Find Vn, Vout, and lout for the circuit shown below. Assume that the op amp is ideal. 6V 3ΚΩ www 1k02 www +5V 1.5mA -5V 2. Find Vn, Vout, and lout for the circuit shown below. Assume that the op amp is ideal. 6V 1k0 www 2.5KQ www +5V 3mA 2kQ www ΣΚΩ 4mA 5V 2k0 ww 8V 10k(2 -5V lout www-11 lout ww-11 Vou 5ΚΩ Vout ΣΚΩ

Answer: Reflecting telescopes focus light with a series of mirrors, while refracting telescopes use lenses.

Explanation:

Answer:

Biosphere

Explanation:

Plants release the biosphere into the atmostphere. :)

The force was applied to the football for approximately 0.244 seconds.

To find the duration for which the force was applied to the football, we can use Newton's second law of motion, which states that the force acting on an object is equal to the product of its mass and acceleration.

The formula for force is:

F = m * a

where F is the force, m is the mass, and a is the acceleration.

In this case, the force applied to the football is 18 newtons, and the mass of the football is 0.55 kg.

Now, we need to find the acceleration of the football. We can use the formula for acceleration:

a = (v - u) / t

where v is the final velocity, u is the initial velocity, and t is the time.

Given:

Initial velocity (u) = 0 m/s (the football is initially at rest)

Final velocity (v) = 8.0 m/s

Substituting the given values into the equation for acceleration, we can solve for a:

a = (8.0 m/s - 0 m/s) / t

a = 8.0 m/s / t

Now, we can substitute the known values into Newton's second law to solve for time:

F = m * a

18 N = 0.55 kg * (8.0 m/s / t)

Simplifying the equation:

18 N = 4.4 m/s^2 / t

To isolate t, we can rearrange the equation:

t = 4.4 m/s^2 / 18 N

Calculating this expression, we find:

t ≈ 0.244 seconds

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The kinetic energy of the electron moving at 6.00 × 10^6 m/s is approximately 1.6347221 × 10^(-18) joules (J).

To calculate the kinetic energy of an electron moving at a given velocity, we can use the formula for kinetic energy:

KE = (1/2) * m * v^2

where:

KE is the kinetic energy,

m is the mass of the electron, and

v is the velocity of the electron.

The mass of an electron (m) is approximately 9.10938356 × 10^(-31) kilograms.

Given the velocity (v) as 6.00 × 10^6 meters per second, we can now calculate the kinetic energy:

KE = (1/2) * (9.10938356 × 10^(-31) kg) * (6.00 × 10^6 m/s)^2

KE = (1/2) * (9.10938356 × 10^(-31) kg) * (3.6 × 10^13 m^2/s^2)

KE ≈ 1.6347221 × 10^(-18) joules (J)

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Due to the fundamental differences between these two galaxy types, galaxies cannot evolve from elliptical to spiral (or spiral to elliptical).

For example, in contrast to spiral galaxies, which include gas and dust as well as hot, bright O and B type stars, elliptical galaxies are devoid of visible gas and dust and hot, brilliant stars.

A galaxy with an elliptical shape and a uniform brightness distribution is called an elliptical galaxy (no spiral arms). Elliptical galaxies are stretched galaxies with an elliptical shape, according to astronomical physics. The light is distributed evenly and smoothly throughout this type of galaxy, which is typically composed of old stars.

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The glasses needed are again diverging lenses, with a focal length of 666.7 cm. The near point of a person is the closest distance from the eye at which an object can be seen clearly. For this farsighted person, the near point is 60 cm, which means that she has difficulty seeing objects that are closer than that.

To correct her vision, the person needs glasses that will create an image of nearby objects at a distance of 25 cm from her eyes. We can use the thin lens formula to find the focal length of the glasses needed:

1/f = 1/d_o + 1/d_i

where f is the focal length of the lens, d_o is the object distance (distance of the object from the lens), and d_i is the image distance (distance of the image from the lens). For a converging lens, the focal length is positive, and for a diverging lens, it is negative.

If the glasses are 2 cm from her eyes, the object distance is:

d_o = 60 cm - 2 cm = 58 cm

The image distance is:

d_i = -25 cm

since the image is formed on the same side as the object, and the image distance is negative for a virtual image. Therefore, we can solve for the focal length:

1/f = 1/d_o + 1/d_i

1/f = 1/58 cm - 1/25 cm

1/f = -0.0012 \(cm^{(-1)}\)

f = -833.3 cm

Since the focal length is negative, the glasses needed are diverging lenses, with a focal length of 833.3 cm.

If the glasses are 3 cm from her eyes, the object distance is:

d_o = 60 cm - 3 cm = 57 cm

The image distance is still:

d_i = -25 cm

We can again solve for the focal length:

1/f = 1/d_o + 1/d_i

1/f = 1/57 cm - 1/25 cm

1/f = -0.0015 \(cm^{(-1)}\)

f = -666.7 cm

Therefore, the glasses needed are again diverging lenses, with a focal length of 666.7 cm.

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The magnitude of the electric field at a distance of 3.45 m from the sphere's center is 4.78 × 10^6 N/C.

Given, Radius of the sphere:

r = 3.50 cm

Total charge carried by the sphere:

q = -5.10 µC

We know that the electric field (E) at a distance (r) from the center of the sphere with total charge (q) is given as:

E = kq/r²

Where k is the Coulomb's constant which is 9 × 10^9 Nm²/C².

Substituting the given values in the above formula, We have:

E = (9 × 10^9)(-5.10 × 10^-6) / (3.50 × 10^-2)²

= -4.78 × 10^6 N/C

Therefore, the magnitude of the electric field at a distance of 3.45 m from the sphere's center is 4.78 × 10^6 N/C.

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The angle of the plate will affect how much sunlight hits the plate. The amount of sunlight that hits a surface depends on the angle of incidence, which is the angle at which the sunlight hits the surface. When the angle of incidence is perpendicular to the surface (i.e., the sun is directly overhead), the maximum amount of sunlight is received by the surface.

However, as the angle of incidence increases, the amount of sunlight that hits the surface decreases because the same amount of sunlight is spread over a larger area. Therefore, if the plate is not angled properly to face the sun, it will receive less sunlight, which will affect its efficiency in converting sunlight into electricity.

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According to the research, the correct answer is Option D. Eye protection is not an equipment required to play tennis.

It is a sport that is played, mainly, outdoors whose objective is to hit the ball so that it passes over the net that divides the field in half, trying to prevent the opponent from being able to return it.

In this sense, this sport is practiced with rackets and a small ball and can be practiced individually, that is, player against player or between pairs.

Therefore, we can conclude that according to the research, tennis is a sport that requires adequate physical coordination and is practiced with a racket and small tennis balls.

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The acceleration of the ball during the throwing motion is 5.28m/s².

Acceleration is defined as rate of change  of velocity w.r.t time.

a = dv/dt

velocity is the rate of change of displacement with respect to time.

final velocity ,

v = 37m/s

initial velocity,

u = 0m/s

distance, s = 3.5m  

acceleration = ?

equation of motion describes simple Concept of the motion make position, velocity, acceleration of an object.

Using the equation of motion

v² = u² + 2as

using above values we get

(37)² =(0)² + 2× a × 3.5

a = 37/7

a = 5.28m/s²

The acceleration of the ball during the throwing motion is 5.28m/s².

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Answer:

extrusive igneous rock

Explanation:

Answer:

yes

Explanation:

Answer:

The baseball was falling during 1.733 seconds.

Explanation:

The baseball experimented a free fall, which is a particular case of uniformly accelerated motion, in which object is accelerated by gravity. In this case, we need to determine the time spent by the ball before hitting the ground (\(t\)), measured in seconds, which is determined by the following kinematic formula:

\(t = \frac{v-v_{o}}{g}\) (1)

Where:

\(v_{o}\), \(v\) - Initial and final speeds of the baseball, measured in meters per second.

\(g\) - Gravitational acceleration, measured in meters per square second.

If we know that \(v_{o} = 0\,\frac{m}{s}\), \(v = 17\,\frac{m}{s}\) and \(g = 9.807\,\frac{m}{s^{2}}\), then the time spent by the baseball is:

\(t = \frac{17\,\frac{m}{s}-0\,\frac{m}{s} }{9.807\,\frac{m}{s^{2}} }\)

\(t = 1.733\,s\)

The baseball was falling during 1.733 seconds.

The car was at a distance of one marker when it was traveling at 70 km/h. This means it was at marker 1.

A racing car accelerates uniformly from rest, which means its initial velocity (v0) is 0 km/h. It reaches a speed of 140 km/h (v1) as it passes marker 2. We want to find the position of the car when it was traveling at 70 km/h (v2).

Since the acceleration is uniform, the ratio of the velocities will be equal to the ratio of the distances covered. Therefore, we can write:

v2 / v1 = distance to reach 70 km/h (d2) / distance to reach 140 km/h (d1)

Now, let's plug in the given velocities:

70 km/h / 140 km/h = d2 / d1

0.5 = d2 / d1

Since the markers are spaced at equal distances, let's assume the distance between each marker is x. Then, the distance to reach 140 km/h (d1) is 2x (from the start to marker 2). Now we can find d2:

0.5 = d2 / (2x)

d2 = x

So, the car was at a distance of one marker when it was traveling at 70 km/h. This means it was at marker 1.

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One filter box will be required for the plant expansion, but an alternative design needs to be proposed if the design loading rate is exceeded with one filter box out of service.

To determine the number of filter boxes required, we need to calculate the total surface area required and divide it by the maximum surface area per filter box.

Calculate the total surface area required:

Total surface area = Design flow rate / Design loading rate

Total surface area = 1.2 m³/s × 24 × 3600 s / (575 m³/d × 1 d/24h)

Total surface area = 18.67 m²

Determine the number of filter boxes required:

Number of filter boxes = Total surface area / Maximum surface area per filter box

Number of filter boxes = 18.67 m² / 50 m²

Number of filter boxes = 0.37 (round up to the nearest whole number)

Number of filter boxes = 1 (since we cannot have a fraction of a filter box)

Therefore, one filter box will be required to meet the design loading rate.

To check the design loading with one filter box out of service, we need to recalculate the loading rate:

Calculate the new design loading rate:

New design loading rate = Design flow rate / (Number of filter boxes - 1)

New design loading rate = 1.2 m³/s / (1 - 1)

New design loading rate = Undefined

Since the new design loading rate is undefined when one filter box is out of service, an alternative design should be proposed to ensure that the design loading rate is not exceeded. This could involve increasing the number of filter boxes or redesigning the filtration system to accommodate the required flow rate.

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Answer:

u = 80 cm and v = 80/3 cm

Explanation:

focal length f = +40/2 = 20 cm.

magnification m = v/u = 1/3, thus v = u/3

using 1/u+1/v=1/f gives 1/u=1/(u/3)=20  

So u = 80 cm and v = 80/3 cm

Answer:Force=500

Explanation:

Because it say "the downward force of atmosphere" we use ATP

ATP=100kpa

area=0.05m2

F=ATP × area

 100,000pa×0.05m2 =5000N

The given problem can be solved using the following free-body diagram:

The diagram is the free-body diagram for the pulley that is holding the weight. Where:

Now we add the forces in the vertical direction:

Adding like terms:

Now, since the velocity is constant this means that the acceleration is zero and therefore the sum of forces is zero:

Now we solve for "T" by adding "mg" from both sides:

Now we divide both sides by 2:

Now we substitute the values and we get:

Solving the operations:

Now we use the free body diagram for the second pulley:

Now we add the forces in the vertical direction:

The forces add up to zero because the velocity is constant and the acceleration is zero:

Solving for the force:

Therefore, the pulling force is equal to the tension we determined previously and therefore is:

Answer:

\(\mu =0.169704 Ns/m^2\)

Explanation:

From the question we are told that

Area of plate\(a=1m^2\)

Angle of inclination \(\theta=60 \textdegree\)

Velocity \(v=0.75m/s\)

Thickness of oil \(t=2mm\)

Weight of plate \(w=90N\)

Generally the equation for shear force is mathematically given by

\(F=mgsin45 \textdegree\)

\(F=90sin45 \textdegree\)

\(F=63.639N\)

\(F=\mu* \frac{v}{t}\)

\(F=\mu* \frac{0.75}{2*10^-^3}\)

\(\mu* \frac{0.75}{2*10^-^3}=63.639N\)

\(\mu =\frac{63.639}{375}\)

Therefore viscosity is given by

\(\mu =0.169704 Ns/m^2\)

Ray could use Metal bar 1 to find out if Metal bar 2 is a magnet by bringing them close to each other. If Metal bar 2 is a magnet, it will be attracted to Metal bar 1.

Ray can also try to move Metal bar 1 along the length of Metal bar 2. If Metal bar 2 is a magnet, it will induce a magnetic field in Metal bar 1, causing it to experience a force as it moves. Alternatively, when Ray moves Metal bar 1 along the length of Metal bar 2, he would observe a force acting on Metal bar 1 as it moves. This is because the magnetic field produced by Metal bar 2.

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Answer:

I think it's part c . but sorry if its wrong

Answer:

-18,750N

Explanation:

90x1000

-------------

3600

u=25m/s

v=0m/s

v^2=u^2+2as

v=0

=625+(2×a×20)

625+40a

-625=40a

a= -15.625 m/s^2

F=ma

=(1200)(-15.625)

= -18,750N

Answer:

Please find attached the required graph of the data points

The graph can be interpreted as showing that which was at rest starts  moving at a constant speed of 2 km/min

Explanation:

The table is presented as follows;

\(\begin{array}{lcl}Time \ (min)&& Distance \ (km)\\0&&0\\5&&10\\10&&20\\15&&30\\20&&40\\25&&50\\30&&60\end{array}\)

The graphic representation of the above data can be created by plotting the Time on the x-axis and the Distance on the y-axis on a graph paper

The graph of the data can be created also using a spreadsheet application such as MS Excel by using the Chart function under the Insert menu, after selecting the points input into cells on the spreadsheet as shown in the attached drawing

The distance travelled by the car in a given time is found by obtaining the rate of change of the values of the graph, m, as follows;

\(m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}\)

Where (y₁, x₁), and (x₂, y₂) are a pair of chosen points on the given line

When, the chosen points are (y₁, x₁) = (0, 0), and (x₂, y₂) = (30, 60), we get;

\(m =\dfrac{60 \, km-0 \, km}{30 \, min-0 \, min} = 2 \, km/min\)

The graph can be interpreted as showing that the rate of change of the distance travelled by the car per  unit time which is the speed of the car starting from rest is 2 km/min

Answer 323mmmm

Explanation:

Cantilever beam capacitance at time t, expressed as C= U's rate of change is therefore inversely proportional to x 2.

Date Updated: 27 June 2022. (00 : 00) Solution: A capacitor's capacitance is determined by dividing the amount of charge on either of its conductor plates by the potential difference between its conductors.

QpropV or C=(Q)/(V). The coulomb per volt and farad is the SI unit for capacitance (F).

The fundamental equation for capacitors is charge (= capacitance x voltage, or Q = C x V. We gauge capacitance by series or in parallel, which is the capacity that holds one coulomb (specified as the charge delivered by one ampere inside one minute) of charge per one farad.

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Answer:

4.4 seconds

Explanation:

use the equation

v(final)=v(initial)+a(t)

what we know:

v(initial)=28mps

v(final)=0 because it comes to a stop

a= -6.4    it is negative because the 6.4 is resisting forward motion

using these you get

0= 28 + (-6.4)t

6.4(t)=28

t=4.375 sec

and with rounding

t=4.4 sec

Answer:

4.4

Explanation:

i got it correct

Answer: 11%

Explanation:

Given that

X = ab^2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.

Percentage error of b = 2%

Percentage error of b^2 = 2 × 2 = 4

When you are calculating for percentage error that involves multiplication and division, you will always add up the percentage error values.

Percentage error of X will be;

Percentage error of a + percentage error of b^2 + percentage error of c

Substitute for all these values

4 + 4 + 3 = 11%

Therefore, percentage error of X is 11%

The answer is 467.311 pounds per square inch.  

What is the relationship between pressure and area?

Force divided by area equals pressure. The equation demonstrates that whereas area and pressure are inversely related, respectively, to force. Pressure grows at a constant area as the size of the force exerted grows as well. The greater the pressure applied for a given amount of force, the smaller the area of contact.

\(P = \frac{F}{A} = \frac{mg}{A} = \frac{56 * 9.8}{1.7 *10^{-4} } = 32.282 * 10^{5} Pa\)

Hence, the answer is  467.311 pounds per square inch.

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Answer:

The pressure is  \(P = 1.31*10^{5} \ Pa\)

Explanation:

From the question we are told that

    The depth of the swimming pool is  \(d = 3.00 \ m\)

     The density of water is  \(\rho = 1.00*10^{3} \ kg /m^3\)

Generally the  total pressure exerted on the bottom of the swimming pool is mathematically represented as

          \(P = P_o + \rho * g * h\)

Here \(P_o\) is the atmospheric pressure with value

        \(P_o = 101325 \ Pa\)

So

        \(P = 101325 + [1000 * 9.8 * 3]\)

=>     \(P = 130725 \ Pa\)

=>    \(P = 1.31*10^{5} \ Pa\)

Answer:

C

Explanation:

C should be the right answer