Find the values of x and y.

x=____
(b) y=_____

Answer:

$936.18

Byehave fun k bye

To calculate the cost of shortage (Cs), we need to find the area under the normal distribution curve to the left of the optimal service level. The cost of shortage is the difference between the selling price and the Monday price, multiplied by the probability of shortage.

To calculate the cost of excess (Ce), we find the area under the normal distribution curve to the right of the optimal service level. The cost of excess is the difference between the cost of making the cake and the selling price, multiplied by the probability of excess. The optimal service level is determined by minimizing the total cost, which is the sum of the cost of shortage and the cost of excess. We can find the corresponding z value for the optimal service level using the standard normal distribution table. Once we have the optimal service level (z value), we can find the corresponding demand value. Since demand is normally distributed, we can calculate the optimal number of birthday cakes to make for the weekend by subtracting the expected demand from the optimal service level demand. However, without specific information on the desired service level or target level of shortage/excess, it is not possible to provide numerical answers to the questions. The optimal service level, corresponding z value, and the optimal number of cakes will depend on the specific parameters and objectives of the supermarket bakery.

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Answer:7888

Step-by-step explanation:

Answer:

A.30

Step-by-step explanation:

^ABC = 180⁰-60⁰=120⁰

=> 4x⁰=120⁰

=> x = 30⁰

The correct answer is option (a) $24,852.The initial capital investment for the 2-year capital project with an internal rate of return factor of 1.69 and net annual cash flows of $42,000 is $24,852.

The internal rate of return (IRR) is a measure used to evaluate the profitability of an investment. In this case, we know that the IRR factor is 1.69. The IRR factor is calculated by dividing the net present value (NPV) of the project by the initial capital investment. Since the IRR factor is given as 1.69, we can set up the equation: NPV / Initial capital investment = 1.69.

We also know that the net annual cash flows for the project are $42,000. The NPV can be calculated by multiplying the net annual cash flows by the IRR factor: NPV = Net annual cash flows × IRR factor. Plugging in the values, we get NPV = $42,000 × 1.69 = $70,980.

Now, we can rearrange the equation to solve for the initial capital investment: $70,980 / Initial capital investment = 1.69. Cross-multiplying and solving for the initial capital investment, we get: Initial capital investment = $70,980 / 1.69 = $24,852.

Therefore, the correct answer is option (a) $24,852.

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Answer:

Step-by-step explanation:

Let x be the study time Thursday:

              5 day average \(=\frac{70+45+0+40+x}{5}\)

                                       \(=\frac{155+x}{5}\)

For the average to be 50 minutes:

                 \(50=\frac{155+x}{5}\)

                \(250=155+x\)

                   \(x=95\)

Solution:  Jaxon needs to study for 95 minutes Thursday.

Answer

17

Step-by-step explanation:

Divide 38.25 by 2.25

Answer:17

Step-by-step explanation:

38.25 divided by 2.25

If adding only twelve, you must leave out three of the fifteen, and the number of ways is = 15! / (3! * 12!).

1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12∗13∗14∗15 over

(1∗2∗3)∗(1∗2∗3∗4∗5∗6∗6∗8∗9∗10∗11∗12) =

13∗14∗15 over

(1∗2∗3)

27306 = 455

Answer: If all toppings are distinct, then you have C 4 15 combinations. If there are three distinct toppings, you have 3 ⋅ C 3 15 combinations (because we have C 3 15 choices for toppings and then 3 choices for which of those three toppings is doubled).

Step-by-step explanation:

Answer:

40%

Step-by-step explanation:

20-12 = 8 difference

8/ 20  x100 = the percentage change  = 40%

Answer:

Please check the explanation.

Step-by-step explanation:

Given the decimal number

\(6.05\)

Rewrite as

\(=6+0.05\)

\(=6+\frac{5}{100}\)        ∵ 0.05 = 5/100

\(=6+\frac{1}{20}\)

\(=\:\frac{121}{20}\)

\(=6\frac{1}{20}\)

Given the decimal number

12.346

Rewrite as

\(=12+0.346\)

\(=12+\frac{173}{500}\)              ∵ 0.346 = 346/1000 = 173/500

\(=12\frac{173}{500}\)

Given the decimal number

7.5

Rewrite as

\(=7+0.5\)

\(=7+\frac{1}{2}\)                 ∵ 0.5 = 1/2

\(=7\frac{1}{2}\)

Slope = change in Y over change in x:

Slope = ( 7 - -3) / ( 4 -2)

Slope = (7 +3) / (4-2)

Slope = 10/2

Slope = 5

The answer is 5

The given integral converges to \($\boxed{\frac{1}{4}\ln 3}$\), and it is proved that it converges.

Given the integral, \($\int_{1}^{\infty} \frac{1}{x^2-4} \mathrm{d}x$\)

a) The given integral is an improper integral because the upper limit of integration is infinity, and the function has a vertical asymptote at \($x=2$\) and \($x=-2$\).

b)  \($x^2-4$\) can be factored as \($(x+2)(x-2)$\).

Therefore, \($$\int_{1}^{\infty} \frac{1}{x^2-4} \mathrm{d}x = \frac{1}{4} \int_{1}^{\infty} \left( \frac{1}{x-2} - \frac{1}{x+2}\right) \mathrm{d}x$$\)

Now, we can integrate this integral as:

\($$ \frac{1}{4} \int_{1}^{\infty} \left( \frac{1}{x-2} - \frac{1}{x+2}\right) \mathrm{d}x$$\)

Using the following limits,

\($$ \int \frac{1}{x-a} \mathrm{d}x = \ln |x-a| + C$$\)

where \($C$\) is the constant of integration.

Therefore,\($$ \frac{1}{4} \int_{1}^{\infty} \left( \frac{1}{x-2} - \frac{1}{x+2}\right) \mathrm{d}x = \frac{1}{4} \left( \ln |x-2| - \ln |x+2| \right) \Biggr|_{1}^{\infty}$$\)

\($$= \frac{1}{4} \left[ \lim_{x \rightarrow \infty} \ln \left| \frac{x-2}{x+2} \right| - \ln 3 \right]$$\)

Since \($\frac{x-2}{x+2}$\) approaches \($1$\)as x approaches infinity,\($$ \frac{1}{4} \left[ \lim_{x \rightarrow \infty} \ln \left| \frac{x-2}{x+2} \right| - \ln 3 \right] = \boxed{\frac{1}{4}\ln 3}$$\)

Therefore, the given integral converges to \($\boxed{\frac{1}{4}\ln 3}$\), and it is proved that it converges.

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Answer:50x-12

Step-by-step explanation:

We need to get rid of parentheses in this term.

All the negative factors will change sign.

In our example, we have 2 negative factors.

The sign of the term will not change, since there is an even number of negative factors.

Answer:

$3600 * 12

Step-by-step explanation:

To get the minimum amount of money the family must earn to meet the requirements of their budgets for one year, first you have to get their total budget for a month and then multiply it by the number of months in a year.

The monthly budget = Rent + food + child care + transportation + utilities + insurance + savings + taxes

Monthly budget = $870 + $550 + $375 + $480 + $400 + $235 + $400 + $290 = $3600

Minimum requirements for one year = $3600 * 12 months

Answer:

sry i dont no

The actual number of people in 10 years could be 57,000 or 56,000. The equation of the trend line is y=1.9x+21, so for any year x, the population y can be found using this equation. To find the population in 16 years, when the population is 52,900, we can plug in x=16 and solve for y to find y=52,900. To find the population in 10 years, when the population is 2,000 people from what the trend line shows, we can plug in x=10 and solve for y to find y=50,900. Since the population should be 2,000 more, the actual population in 10 years is either 57,000 (50,900 + 2,000) or 56,000 (50,900 + 1,000).

Answer:

Part A is 16

Step-by-step explanation:

a) To maximize its net savings, the company should use the new machine for 7 years.  b) The net savings during the first year of use of the machine are $405 (rounded off to the nearest dollar).  c) The net savings over the period determined in part a are $1,833.33 (rounded off to the nearest cent).

Step-by-step explanation: a) To determine for how many years should the company use the new machine to maximize its net savings, we need to find the value of x that maximizes the difference between the savings and the costs.To do this, we need to first calculate the net savings, N(x), which is given by:S'(x) - C'(x) = 175 - x² - (x² + 11x) = -2x² - 11x + 175To find the maximum value of N(x), we need to find the critical values, which are the values of x that make N'(x) = 0:N'(x) = -4x - 11 = 0 ⇒ x = -11/4The critical value x = -11/4 is not a valid solution because x represents the number of years of operation of the machine, which cannot be negative. (i.e., not use it at all).However, this answer does not make sense because the company would not introduce a new machine that it does not intend to use. Therefore, we need to examine the concavity of N(x) to see if there is a local maximum in the feasible interval.

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A. x and y are both within the same solar system.

7.2 light years= 455336 AU

The value of r that indicates a stronger correlation is option (C) r = -0.912 represents a stronger correlation because |-0.912|>|0.721|

The value of the correlation coefficient, denoted by "r", ranges from -1 to 1. A correlation of -1 indicates a perfect negative correlation, 0 indicates no correlation, and 1 indicates a perfect positive correlation. The absolute value of the correlation coefficient (|r|) represents the strength of the correlation, where the closer |r| is to 1, the stronger the correlation is.

In this case, r = 0.721 indicates a moderate positive correlation, while r = -0.912 indicates a strong negative correlation. The absolute value of -0.912 is greater than the absolute value of 0.721, indicating that the strength of the negative correlation is stronger than the strength of the positive correlation.

Therefore, the correct option is (C) r = -0.912 represents a stronger correlation because |-0.912|>|0.721|

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If λ is an eigenvalue of matrix A and x is the corresponding eigenvector, then for any positive integer m, λ^m is an eigenvalue of A^m, and x is the corresponding eigenvector of A^m.

Let λ be an eigenvalue of matrix A with eigenvector x. This means that Ax = λx. Now, consider the matrix A^m, where m is a positive integer. By multiplying both sides of the eigenvector equation by A^(m-1), we have A^(m-1)Ax = A^(m-1)(λx), which simplifies to A^mx = λA^(m-1)x.

Since A^mx = (A^m)x and A^(m-1)x = λ^(m-1)x, we can rewrite the equation as (A^m)x = λ^(m-1)(Ax). Using the initial eigenvector equation Ax = λx, we have (A^m)x = λ^(m-1)(λx), which further simplifies to (A^m)x = λ^m x.

Therefore, we have shown that if λ is an eigenvalue of A with eigenvector x, then for any positive integer m, λ^m is an eigenvalue of A^m with the same eigenvector x. This result demonstrates the relationship between eigenvalues and matrix powers, illustrating that raising the matrix to a power corresponds to raising the eigenvalue to the same power while keeping the eigenvector unchanged.

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the largest positive representable number in 32-bit IEEE 754 single precision floating point format is approximately \(3.4028235 * 10^{38\)., the largest positive representable number in 64-bit IEEE 754 double precision floating point format is approximately \(1.7976931348623157 * 10^{308.\)

What is floting point?

A floating-point is a numerical representation used in computing to approximate real numbers.

In IEEE 754 floating-point representation, the largest positive representable numbers in 32-bit single precision and 64-bit double precision formats have specific bit encodings and corresponding values in base 10.

32-bit IEEE 754 Single Precision Floating-Point:

The bit encoding for a single precision floating-point number consists of 32 bits divided into three parts: the sign bit, the exponent bits, and the fraction bits.

Sign bit: 1 bit

Exponent bits: 8 bits

Fraction bits: 23 bits

The largest positive representable number in single precision format occurs when the exponent bits are set to their maximum value (all 1s) and the fraction bits are set to their maximum value (all 1s). The sign bit is 0, indicating a positive number.

Bit Encoding:

0 11111110 11111111111111111111111

Value in Base 10:

To determine the value in base 10, we need to interpret the bit encoding according to the IEEE 754 standard. The exponent bits are biased by 127 in single precision format.

Sign: Positive (+)

Exponent: 11111110 (254 - bias = 127)

Fraction: 1.11111111111111111111111 (interpreted as 1 + 1/2 + 1/4 + ... + \(1/2^{23\))

Value = (+1) * \(2^{(127)\) * 1.11111111111111111111111

Value ≈ 3.4028235 × \(10^{38\)

Therefore, the largest positive representable number in 32-bit IEEE 754 single precision floating point format is approximately 3.4028235 × \(10^{38\).

64-bit IEEE 754 Double Precision Floating-Point:

The bit encoding for a double precision floating-point number consists of 64 bits divided into three parts: the sign bit, the exponent bits, and the fraction bits.

Sign bit: 1 bit

Exponent bits: 11 bits

Fraction bits: 52 bits

Similar to the single precision format, the largest positive representable number in double precision format occurs when the exponent bits are set to their maximum value (all 1s) and the fraction bits are set to their maximum value (all 1s). The sign bit is 0, indicating a positive number.

Bit Encoding:

0 11111111110 1111111111111111111111111111111111111111111111111111

Value in Base 10:

Again, we interpret the bit encoding according to the IEEE 754 standard. The exponent bits are biased by 1023 in double precision format.

Sign: Positive (+)

Exponent: 11111111110 (2046 - bias = 1023)

Fraction: 1.1111111111111111111111111111111111111111111111111 (interpreted as 1 + 1/2 + 1/4 + ... + \(1/2^{52\))

Value = (+1) * \(2^{(1023)\) * 1.1111111111111111111111111111111111111111111111111

Value ≈ 1.7976931348623157 × \(10^{308\)

Therefore, the largest positive representable number in 64-bit IEEE 754 double precision floating point format is approximately 1.7976931348623157 × \(10^{308\).

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Answer:

\(3y + 3y - 12\)

Step-by-step explanation:

This is because if you were to combine like terms, the two beginning values would add up to 6y since adding two y's is just y & 3+3 is 6. & 12 is common sense lol.

Answer:

I believe the median is 6.5

Step-by-step explanation:

The relationship that is normally expressed as the quotient of one quantity divided by another is called a ratio

The relationship that is normally expressed as the quotient of one quantity divided by another is called a ratio. A ratio is a comparison of two numbers or measurements, and it can be written in different ways.

For example, if we have two quantities A and B, the ratio of A to B can be written as

A/B

A:B

"A is to B"

The ratio of A to B tells us how many times A is contained within B, or how many units of A we would need to have to match the amount of B.

Ratios are useful in many fields, such as finance, engineering, and science, where they are used to compare and analyze different quantities and their relationships.

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The particular solution to the differential equation with the initial condition y(7) = 0 is:

(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x - 7.

To solve the given differential equation, we can use the method of separation of variables. Here's the step-by-step solution:

Step 1: Write the given differential equation in the form dy/dx = f(x, y).

  In this case, dy/dx = y² - 4.

Step 2: Separate the variables by moving terms involving y to one side and terms involving x to the other side:

  dy / (y² - 4) = dx.

Step 3: Integrate both sides of the equation:

  ∫ dy / (y² - 4) = ∫ dx.

Let's solve each integral separately:

For the left-hand side integral:

Let's express the denominator as the difference of squares: y² - 4 = (y - 2)(y + 2).

Using partial fractions, we can decompose the left-hand side integral:

1 / (y² - 4) = A / (y - 2) + B / (y + 2).

Multiply both sides by (y - 2)(y + 2):

1 = A(y + 2) + B(y - 2).

Expanding the equation:

1 = (A + B)y + 2A - 2B.

By equating the coefficients of the like terms on both sides:

A + B = 0, and

2A - 2B = 1.

Solving these equations simultaneously:

From the first equation, A = -B.

Substituting A = -B in the second equation:

2(-B) - 2B = 1,

-4B = 1,

B = -1/4.

Substituting the value of B in the first equation:

A + (-1/4) = 0,

A = 1/4.

Therefore, the decomposition of the left-hand side integral becomes:

1 / (y² - 4) = 1/4 * (1 / (y - 2)) - 1/4 * (1 / (y + 2)).

Integrating both sides:

∫ (1 / (y² - 4)) dy = ∫ (1/4 * (1 / (y - 2)) - 1/4 * (1 / (y + 2))) dy.

Integrating the right-hand side:

∫ (1/4 * (1 / (y - 2)) - 1/4 * (1 / (y + 2))) dy

= (1/4) * ln|y - 2| - (1/4) * ln|y + 2| + C₁,

where C₁ is the constant of integration.

For the right-hand side integral:

∫ dx = x + C₂,

where C₂ is the constant of integration.

Combining the results:

(1/4) * ln|y - 2| - (1/4) * ln|y + 2| + C₁ = x + C₂.

Simplifying the equation:

(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x + (C₂ - C₁).

Combining the constants of integration:

C = C₂ - C₁, where C is a new constant.

Finally, we have the solution to the differential equation that satisfies the initial condition:

(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x + C.

To find the value of the constant C, we use the initial condition y(7) = 0:

(1/4) * ln|0 - 2| - (1/4) * ln|0 + 2| = 7 + C.

Simplifying the equation:

(1/4) * ln|-2| - (1/4) * ln|2| = 7 + C,

(1/4) * ln(2) - (1/4) * ln(2) = 7 + C,

0 = 7 + C,

C = -7.

Therefore, the differential equation with the initial condition y(7) = 0 has the following specific solution:

(1/4) * ln|y - 2| - (1/4) * ln|y + 2| = x - 7.

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a. The probability that the current component has been in operation for at least 50 hours is 0.5

b. The probability that the current component will last for at least 50 more hours is also 0.5.

(a) The probability that the current component has been in operation for at least 50 hours is given by the cumulative distribution function (CDF) of the uniform distribution on [100, 200] evaluated at 50.

The CDF of a uniform distribution on [a, b] is given by:

F(x) = (x - a) / (b - a) for a <= x <= b

F(x) = 0 for x < a

F(x) = 1 for x > b

Therefore, in this case, the CDF is:

F(x) = (x - 100) / 100 for 100 <= x <= 200

F(x) = 0 for x < 100

F(x) = 1 for x > 200

So the probability that the current component has been in operation for at least 50 hours is:

P(ti >= 50) = 1 - F(50) = 1 - ((50 - 100) / 100) = 0.5

(b) The probability that the current component will last for at least 50 more hours is also given by the CDF of the uniform distribution on [100, 200], but evaluated at 150 instead of 50.

That is,

P(ti >= 150) = F(150) = (150 - 100) / 100 = 0.5.

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Answer:

B

Step-by-step explanation:

Distance = rate x  time

The rate is 3/15

distance = (3/15) (50)

distance = 10 miles