Find the value of x.

68

110°

135

The calculator helps to slove an expression. By putting all elements one by one of the expression to get result.

What is a calculator?

A calculator is a device that performs numerical arithmetic operations. Basic calculators can only perform addition, subtraction, multiplication, and division calculations.

To perform basic operations, use the basic operation symbols. Addition (+), subtraction (-), multiplication (), and division () are examples of these operations.

Don't be concerned about the order of operations. A scientific calculator will perform calculations in the correct order.

Using the parentheses keys, you can change the order of operations. The calculator's order of operations will be overridden.

Correct your errors. If you accidentally press the wrong key, press the DEL key. This will remove the last button you pressed, but it will not remove any calculations you've made.

Make a clean sweep of your work. To clear the line, press the CLEAR button. You can probably scroll up to see previous calculations. You can delete these by pressing delete after each line.

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The school spends $636 each day on lunches and milk cartons for 250 students, assuming each person gets only one lunch and one carton of milk.

Assuming that each person gets only one lunch and one carton of milk:

The total cost for lunches per day = $2.40 x 250 = $<<2.4*250=600>>600

The total cost for milk cartons per day = $0.30 x 120 = $<<0.3*120=36>>36

The total cost for both lunches and milk cartons per day = $600 + $36 = $<<600+36=636>>636.

Therefore, the school spends $636 each day on lunches and milk cartons for 250 students.

This explanation provides a calculation of the total cost spent by a school on lunch and milk cartons for 250 students. It assumes that each student receives only one lunch and one carton of milk. The calculation shows that the school spends $2.40 on each lunch and $0.30 on each carton of milk. Using these values, the total cost for lunches and milk cartons is calculated, resulting in a daily expenditure of $636 for the school.

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Complete question:

A school spends $2.40 on every lunch it serves in the cafeteria and $0.30 for each carton of milk. If there are 250 students at the school, and 120 of them take a carton of milk with their lunch each day, how much does the school spend each day on lunches and milk cartons for these students?

The present value of $425 due in the future under each of the given conditions are as follows 1. $425 due in 5 years, with a 6% nominal rate and semiannual compounding: $314.92

To calculate the present value, we use the formula for the present value of a future amount with compound interest:

\(\[PV = \dfrac{FV}{(1 + r/n)^{nt}}\]\)

Where:

PV = Present Value

FV = Future Value

r = Nominal interest rate (in decimal form)

n = Number of compounding periods per year

t = Number of years

In this case, the future value is $425, the nominal interest rate is 6% (0.06 in decimal form), the compounding is semiannual (n = 2), and the time period is 5 years. Plugging these values into the formula, we get:

\(\[PV = \dfrac{425}{(1 + 0.06/2)^{(2 \times 5)}} = 314.92\]\)

Therefore, the present value of $425 due in 5 years, with a 6% nominal rate and semiannual compounding, is $314.92.

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The increasing the sample size by a factor of 25 will reduce the width of the confidence interval by a factor of 5.

a. Suppose we have a two-sided confidence interval for the population mean with known variance, given by the equation:

Cl is the confidence interval, x is the sample mean, σ is the population standard deviation, n is the sample size, and zα/2 is the z-score corresponding to the desired level of confidence.

The σ are fixed for a given level of confidence, we can achieve this by increasing n by a factor of 4.

Specifically, if we increase the sample size from n to 4n, then the new confidence interval will have half the width of the original interval.

b. If the sample size is increased by a factor of 25, then the term √n in the denominator of the above equation will be replaced.

Therefore, increasing the sample size by a factor of 25 will reduce the width of the confidence interval by a factor of 5.

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Answer:

I think the answer is A. A car remains parked in a parking lot.

Step-by-step explanation:

The graph shows a line increasing in time, but not in distance, therefore the person/vehicle isn't moving, it's just sitting still

Answer:

2

Step-by-step explanation:

because the speed doesent change and he doesent make any turns

The Economic Order Quantity (EOQ) is calculated to be 547.72 units. The number of orders placed per year is 5.84, and the reorder point (ROP) is 32.01.

The total holding cost of lawnmowers is R1369.30, and the total ordering cost of lawnmowers is R876.00. These calculations provide valuable insights for efficient inventory management.

The Economic Order Quantity (EOQ) can be calculated by using the formula: EOQ = √2DS / H,

where D = Total Demand = 3200 units,

S = Ordering cost per order = R150,

and H = Annual holding cost per unit = R5.

Therefore, EOQ = √ (2 x 3200 x 150) / 5 = 547.72 units.

4.2 Number of orders placed per year: No of orders per year = D / Q,

where D = Total Demand = 3200 units and Q = EOQ = 547.72 units.

Therefore, No of orders per year = D / Q = 3200 / 547.72 = 5.84 orders.

4.4 Total holding cost of lawnmowers:

Total holding cost of lawnmowers = (Average inventory level) x (Annual holding cost per unit),

where (Average inventory level) = EOQ / 2 = 547.72 / 2 = 273.86 units and Annual holding cost per unit = R5.

Thus, the Total holding cost of lawnmowers = 273.86 x R5 = R1369.30.

4.1 Reorder Point (ROP): ROP can be calculated by using the formula:

ROP = dL, where d = Daily demand = D / Number of working days

= 3200 / 300 = 10.67 and L = Lead time = 3 days.

Hence, ROP = dL = 10.67 x 3 = 32.01.

4.5 Total ordering cost of lawnmowers:

Total ordering cost of lawnmowers = (Number of orders placed per year) x (Ordering cost per order),

where (Number of orders placed per year) = 5.84 orders and Ordering cost per order = R150.

Therefore, the Total ordering cost of lawnmowers = 5.84 x R150 = R876.00.

The Economic Order Quantity (EOQ) is calculated to be 547.72 units.

The number of orders placed per year is 5.84, and the reorder point (ROP) is 32.01.

The total holding cost of lawnmowers is R1369.30, and the total ordering cost of lawnmowers is R876.00.

These calculations provide valuable insights for efficient inventory management.

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\(\textit{area of a semicircle}\\\\ A=\cfrac{\pi r^2}{2} ~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ A=0.1413 \end{cases}\implies 0.1413=\cfrac{\pi r^2}{2}\implies 0.2826=\pi r^2 \\\\\\ \cfrac{0.2826}{\pi }=r^2\implies \sqrt{\cfrac{0.2826}{\pi }}=r\implies 0.30\approx r\)

Thus, the graph of f is concave up on the intervals (-infinity,0) and (2,infinity). Therefore, the answer is (A).

To determine where the graph of f is concave up, we need to find the intervals where the second derivative of f is positive. Taking the derivative of f(x), we get f'(x)=12x^2-4x^3. Then taking the derivative of f'(x), we get f''(x)=24x-12x^2. To find where f''(x) is positive, we need to find the roots of f''(x)=0, which are x=0 and x=2. We can then use a test point in each of the intervals (-infinity,0), (0,2), and (2,infinity) to see if f''(x) is positive or negative. For example, plugging in x=-1, we get f''(-1)=24-12(-1)^2=12, which is positive.

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the only student that is correct is Stepheh. "The vertex is at (–4, –1)."

Here we have the quadratic equation:

f(x) = (x + 3)*(x + 5)

The first claim is: "The y-intercept is at (15, 0)."

This is clearly false, as the y-intercept is at x = 0, and in that point we have x = 15.

The second claim is:

"The x-intercepts are at (–3, 0) and (5, 0)"

This is false, in the factored equation we can see that the x-intercepts are x =-3 and x = -5.

Third claim:

"The vertex is at (-4, -1)"

The middle value between the zeros is:

(-3 + (-5))/2 = -4

Evaluating the function in x = -4 we get the y-value of the vertex:

f(-4) = (-4 + 3)*(-4 + 5) = -1*1 = -1

So the vertex is at (-4, -1), this claim is true.

The fourth claim is:

"The midpoint between the x-intercepts is at (4, 0)."

Which is false, we already saw that the midpoint between the x-intercepts is at x = -4

Then the only student that is correct is Stepheh. "The vertex is at (–4, –1)."

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Answer:

x> -12/5

Step-by-step explanation:

Divide both sides (5x and 12) and re write

5x ÷ 5 > -12 ÷ 5

Thus the solution given above

Answer : x> -  12  

                       5

divide both side by 5

x + ( 12/5 ) > 0

Answer:

area = 277 units²

Step-by-step explanation:

area = (25 x 5) + (8 x 13) + (8 x 6) = 277 units²

Step-by-step explanation:

Step 2: Using the order of operations, evaluate the expression with the substituted variable values.

The area of the rectangular-shaped building is 2448 square feet.

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the rectangle in a two-dimensional plane is called the area of the rectangle.

Given that a rectangular-shaped building that is 34 feet wide and 72 feet long. The area of the rectangle will be calculated as below:-

Area of rectangle = Length x width

Area of rectangle = 34 x 72

Area of rectangle = 2448 square feet

Therefore, the area of the rectangular-shaped building is 2448 square feet.

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The arithmetic mean is 59.

What is arithmetic mean?

It is the sum of collection of numbers divided by the count of the numbers.

Conider AB is the nuber satisfying the condition. Hence,

\(10A+B=A+B+A\times B\\9A=A\times B\\\)

Since AB is a two digit number hence, \(A\neq 0\\\). Hence, divide both sides by \(A\).

\(9=B\)

Hence, B is 9 and A can take any value from 1 to 9.

Hence, numbers are 19, 29, 39, 49, 59, 69, 79, 89,99.

Now, calculate arithmetic mean as follows:

\(AM=\frac{Sum \ of \ numbes}{Count \ of \ numbers}\\=\frac{19+29+39+49+59+69+79+89+99}{9}\\=59\)

Hence, arithmetic mean of numbers is 59.

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Answer:

There are 2 solutions to square root x = 9

They are 3, and -3

Step-by-step explanation:

The square root of x=9 has 2 solutions,

The square root means, for a given number, (in our case 9) what number times itself equals the given number,

Or, squaring (i.e multiplying with itself) what number would give the given number,

so, we have to find the solutions to \(\sqrt{9}\)

since we know that,

\((3)(3) = 9\\and,\\(-3)(-3) = 9\)

hence if we square either 3 or -3, we get 9

Hence the solutions are 3, and -3

The last column evaluates to "T" in all rows. Therefore, the argument is valid since the conclusion always follows from the premises.

Let's assign symbols to represent the statements in the argument:

P: The boss snaps at you.

Q: You make a mistake.

R: The boss is irritable.

The argument can be symbolically represented as follows:

[(P ∧ Q) → R] ∧ ¬P → ¬R

To determine the validity of the argument, we can construct a truth table:

P | Q | R | (P ∧ Q) → R | ¬P | ¬R | [(P ∧ Q) → R] ∧ ¬P → ¬R

---------------------------------------------------------

T | T | T |      T      |  F |  F |          T          |

T | T | F |      F      |  F |  T |          T          |

T | F | T |      T      |  F |  F |          T          |

T | F | F |      F      |  F |  T |          T          |

F | T | T |      T      |  T |  F |          F          |

F | T | F |      T      |  T |  T |          T          |

F | F | T |      T      |  T |  F |          F          |

F | F | F |      T      |  T |  T |          T          |

The last column represents the evaluation of the entire argument. If it is always true (T), the argument is valid; otherwise, it is invalid.

Looking at the truth table, we can see that the last column evaluates to "T" in all rows. Therefore, the argument is valid since the conclusion always follows from the premises.

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Answer: 4y (4y^2-2y-5)

Step-by-step explanation:

Answer:

this is what to do

Step-by-step explanation:

The formula for calculating the sales tax on a good or service is selling price x sales tax rate, and when calculating the total cost of a purchase, the formula is total sale amount = selling price + sales tax.

Answer:

B.

Step-by-step explanation:

Hope it was Right.

Answer: the answer is c

The angle bisector that was constructed incorrectly is Example fiqure  2 , this was a result of not dividing the angle into equal parts.

An angle bisector can be described as a line which is used in dividing a  a given angle usually into  two equal degrees.

It should be noted that the the bisector in the second example was incorrectly constructed as a result of the  bisector not dividing <ABC into two equal parts it doe not matter if it passes intersection of the arcs and point B.

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Final Answer:   The small change in x and corresponding change in y  is             \(dy = (6x^2-2)dx\)

                           dy = ((sec^211x)*11) dx

f(x) =  \(2x^3-2x\)

Here we can consider y as function of x so y=f(x).

Derivative is nothing but rate of change i.e. small change in y with respect to x when y is function of x.  

\((dy/dx )= 6x^2-2\)

\(dy = (6x^2-2)dx\)

Second function here is f(x) = tan11x

Here also we will consider y as function of x

here we need to apply chain rule multiple of x is there.

so \((dy/dx) = (sec^211x)*11\)

\(dy = ((sec^211x)*11) dx\)

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Answer:

47.3 degrees

Step-by-step explanation:

The sum of all the angles in a triangle is 180 degrees.

180 - 42.7 - 90 = N

N = 47.3 degrees

Leave a like if this answered your question

Answer:  Exactly one solution

Step-by-step explanation:

The reason for is because if we were to graph these two lines, we discover that they only intersect at one point, at (6,7). Therefore, if we were to plug those points in respectively, we see that it is true.

Looking at the question, I'm assuming it has a mistake.

However, I will first attempt to solve it normally:

Simply combine like terms to get 5x = 180, and thus x = 36, and y = 72

The first mistake possibility is that the first equation should be 3x + 2y = 180

If that is the case, simply substitute in 2x for y, turning the equation into

3x + 2 (2x) = 180

3x + 4x = 180

7x = 180

Thus, x = 25.715 and y = 51.43

Another possible mistake is that the first equation should be 3y + 2x = 180

Solve similar to the first mistake

3 (2x) + 2x = 180

6x + 2x = 180

8x = 180

Thus, x = 22.5, and y = 45

Hope it helps :)

Step-by-step explanation:

hope it helps you

Answer:

The distribution of y, the number of mints that weigh less than 20.86 grams, follows a binomial distribution. In this case, each mint is either a success (weighs less than 20.86 grams) or a failure (weighs 20.86 grams or more). The probability of success, denoted as p, is the probability that a randomly selected mint weighs less than 20.86 grams.To determine the distribution, we need to know the probability of success, p, and the number of trials, which is 10 in this case. Since you haven't provided the probability, I'll assume it's a known value. Let's denote it as p.Therefore, the distribution of y, the number of mints that weigh less than 20.86 grams, follows a binomial distribution with parameters n = 10 (number of trials) and p (probability of success).

Step-by-step explanation:

The distribution of the number of mints weighing less than 20.86 grams follows a binomial distribution. In this scenario, we have 10 mints that are independently selected and weighed.

Let's define the random variable Y as the number of mints that weigh less than 20.86 grams. Since each mint can be considered a Bernoulli trial (either weighing less than 20.86 grams or not), and there are a fixed number of trials (10 mints), the distribution of Y can be described by a binomial distribution.

The binomial distribution is characterized by two parameters: the probability of success in a single trial (p) and the number of trials (n). In this case, the probability of a mint weighing less than 20.86 grams is not provided, so we would need that information to fully determine the distribution. Assuming the probability of success is constant for each trial, we can calculate the probability mass function of Y using the binomial distribution formula:

P(Y = k) = C(n, k) * p^k * (1-p)^(n-k)

where C(n, k) represents the binomial coefficient, which is the number of ways to choose k successes out of n trials.

To obtain a complete distribution, we would need to know the value of p, the probability of a mint weighing less than 20.86 grams. With that information, we could calculate the probabilities for different values of Y, providing a comprehensive description of the distribution of Y.

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The correct answer is (b) all real numbers except odd multiples of π/2. The domain of validity for cscθ (cosecant) is restricted because cosecant is undefined when the sine of an angle is zero.

In the trigonometric identity cscθ = 1/sinθ, the denominator sinθ becomes zero at odd multiples of π/2 (such as π/2, 3π/2, 5π/2, etc.), resulting in a division by zero error. Therefore, the cosecant function is not defined for these values of θ.

For all other real numbers θ, the sine function is non-zero and well-defined, allowing us to calculate the reciprocal of the sine and determine the value of the cosecant. Hence, the domain of validity for cscθ is all real numbers except odd multiples of π/2, as stated in option (b).

It's important to note that in trigonometry, the domain of validity is determined by avoiding any values that would lead to undefined expressions or division by zero errors.

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The domain of validity for csc θ = 1/sin θ is all real numbers except multiples of π, because at these points the sine function equals zero, and division by zero is undefined.

In mathematics, the cosecant function (csc), is defined as the reciprocal of the sine function, or 1/sinθ. The domain of a function are all the possible input values that will yield real numbers (output). For the csc function, its domain includes all real numbers except where the denominator is zero because division by zero is undefined.

In the unit circle context, sine equals zero at 0, π, 2π, ..., and the negative counterparts. Basically, these are the multiples of π. Thus, for the csc function, the domain is all real numbers except multiples of π, which matches option d in your choices.

The domain of validity for csc θ = 1/sin θ is all real numbers except multiples of π.

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Answer:

118.0 in^3

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

18%of 50

18/100×50

0.18×50= 9

Answer:

9

Step-by-step explanation:

18% of 50

We can rewrite it as,

> 18/100 * 50

Solving,

Hence,18% of 50 = 9

Answer: Its B.) −5 ≤ y ≤ 2

Step-by-step explanation: The graph shows one part of the interval increasing which is the y value and stops at 3. The X interval which is the decreasing interval stops at -5. So this would be -5 greater then or equal to y greater then or equal to 2.

Sorry if wrong! Have a nice day :)