To check the result by differentiation, we can take the derivative of the expression we obtained and see if it matches the original integrand.
WeWe can start by using the trigonometric identity:
(sec(θ))^2 = 1 + (tan(θ))^2
Substituting this into the integral, we get:
∫ [(sec(θ))^2 − 2sin(θ)] dθ
= ∫ [1 + (tan(θ))^2 − 2sin(θ)] dθ
= ∫ [1 + (tan(θ))^2 − 2tan(θ)cos(θ)] dθ (using the identity sin(θ)/cos(θ) = tan(θ))
= ∫ [1 + (tan(θ) − cos(θ))^2 − cos^2(θ)] dθ
= ∫ [(tan(θ) − cos(θ))^2 + 1 − cos^2(θ)] dθ
= ∫ [(tan(θ) − cos(θ))^2 + sin^2(θ)] dθ
Now, let u = tan(θ) − cos(θ), then du/dθ = sec^2(θ) - sin(θ), and we can rewrite the integral as:
∫ [(tan(θ) − cos(θ))^2 + sin^2(θ)] dθ
= ∫ (u^2 + 1) du/(sec^2(θ) - sin(θ))
= ∫ (u^2 + 1) du/(u + tan(θ))
We can use partiapartiall fractions to separate the integrand into two terms:
(u^2 + 1)/(u + tan(θ)) = u - tan(θ) + (tan(θ)^2 + 1)/(u + tan(θ))
Therefore, the integral becomes:
∫ [(tan(θ) − cos(θ))^2 + sin^2(θ)] dθ
= ∫ [u - tan(θ) + (tan(θ)^2 + 1)/(u + tan(θ))] du
= (1/2) (tan(θ) − cos(θ))^2 + ln|u + tan(θ)| + C
= (1/2) (tan(θ) − cos(θ))^2 + ln|tan(θ) − cos(θ) + tan(θ)| + C
= (1/2) (tan(θ) − cos(θ))^2 + ln|sin(θ)/cos(θ)| + C
= (1= (1/2) (tan(θ) − cos(θ))^2 + ln|sin(θ)/cos(θ)| + C
= (1/2) tan^2(θ) - tan(θ)cos(θ) + ln|sin(θ)/cos(θ)| + C
To check the result by differentiation, we can take the derivative of the expression we obtained and see if it matches the original integrand:
d/dθ [(1/2) tan^2(θ) - tan(θ)cos(θ) + ln|sin(θ)/cos(θ)| + C]
= sec^2(θ)/2 - (sec^2(θ) - 2sin(θ))/2 + sec(θ)/cos(θ)
= (sec^2(θ) - 2sin(θ))/2 + sec(θ)/cos(θ)
Using the trigonometric identity we used before, we can simplify this expression to:
(sec^2(θ) - 2sin(θ))/2 + sec(θ)/cos(θ)
= [(sec(θ))^2 - 2 sin(θ)]/(2cos(θ))
= (sec(θ))^2/2 - sin(θ)
This is indeed the original integrand, so our answer is correct.
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.Independent random samples of business managers and college economics faculty were asked to respond on a scale from 1 (strongly disagree) to 7 (strongly agree) to this statement: Grades in advanced economics are good indicators of students’ analytical skills. For a sample of 70 business managers, the mean response was 4.4 and the sample standard deviation was 1.3. For a sample of 106 economics faculty, the mean response was 5.3 and the sample standard deviation was 1.4.
a) Test, at the 5% level, the null hypothesis that the population mean response for business managers would be at most 4.0. (10marks)
b) Test, at the 5% level, the null hypothesis that the population means are equal against the alternative that the population mean response is higher for economics faculty than for business managers. Assume unequal variance.
Step-by-step explanation:
a) The test statistic is (4.4-4)/(1.3/sqrt(70)) = 2.83. The p-value is 0.0023. Since the p-value is less than 0.05, we reject the null hypothesis.
b) The test statistic is (5.3-4.4)/sqrt((1.4^2/106)+(1.3^2/70)) = 4.09. The p-value is less than 0.0001. Since the p-value is less than 0.05, we reject the null hypothesis.
Sketch curve of the given vector equation. Indicate with an arrow the direction in which t increases
r(t) = < t , 2 - t , 2t >
The curve of the given vector equation is shown below: It can be seen that the arrow points towards the positive x-axis, which is in the direction of increasing t.
To sketch curve of the given vector equation, r(t) = < t , 2 - t , 2t >, and indicate with an arrow the direction in which t increases, we need to follow some steps.
Step 1: Create a table for the vector. We need to create a table and fill in the values for t, x, y, and z. Let's do it below:
\(tt (time)xx (position)x(t)x(t)(2−t)(2−t)2t2t\)
Step 2: Plotting the points. We can plot the points by simply taking the x, y and z values from the table created above. The curve will pass through these points. The curve will be three-dimensional.
Step 3: Indicate the direction of t. To indicate the direction of t, we use an arrow on the curve. The arrow is drawn such that it starts from the initial point and points in the direction in which the parameter (in this case, t) increases. In this problem, since t increases in a positive direction, we take the arrow pointing towards the positive x-axis.
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A cylinder has base radius x cm and height 2x cm. A cone has base radius x cm and height h cm. The volume of the cylinder and the volume of the cone are equal. Find h in terms of x. Give your answer in its simplest form.
The value of h in terms of x when the volume of cylinder is equal to that of cone is h = 6x²
What is volume of cylinder and cone?Volume' is a mathematical quantity that shows the amount of three-dimensional space occupied by an object or a closed surface. The unit of volume is in cubic units such as m3, cm3, in3 etc. Sometimes, volume is also termed capacity.
The volume of a cone is linked to the volume of a cylinder. A cone is one third of the volume of a cylinder. The volume of a cone is ¹/₃ × π × r² × l. To calculate the volume we multiply these values together.
The volume of cylinder = πr²h
and volume of cone = 1/3 πr²h
since the volume of the cone and cylinder are equal
πr²h = 1/3 πr²h
r in cylinder = x cm and h is 2x
r in cone = x cm
therefore πx²×2x = 1/3πxh
divide both side by πx
π2x³/πx = h/3
2x² = h/3
therefore h = 3×2x²
h = 6x²
therefore the value of h in terms of x is h = 6x²
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2+5x=7x-18+2x
——— ————-
3x 3x
9514 1404 393
Answer:
x = 5
Step-by-step explanation:
Perhaps you want to solve for x the rational equation ...
(2+5x)/(3x) = (7x -18 +2x)/(3x)
Multiplying by 3x and collecting terms, we have ...
2 +5x = 9x -18
20 = 4x . . . . . . add 18-5x to both sides
5 = x . . . . . . . . divide both sides by 4
The solution is x=5.
PLEASE HELP ME
im stuck on it
The completed two-column table used to prove that ΔSUV ≅ ΔTVU, can be completed as follows;
Statements \({}\) Reasons
1. \(\overline{SU}\) ≅ \(\overline{TV}\) Given
2. ∠TSU ≅ ∠STV \({}\) Given
3. \(\overline{UV}\)║\(\overline{ST}\) \({}\) Given
4. ∠TSU ≅ ∠SUV\({}\) Alternate Interior Angles Theorem
5. ∠TVU ≅ ∠STV\({}\) Alternate Interior Angles Theorem
6. ∠STV ≅ ∠SUV \({}\)\({}\) Transitive Property of Congruence
7. ∠TVU ≅ ∠SUV\({}\) Transitive Property of Congruence
8. \(\overline{UV}\) ≅ \(\overline{UV}\) \({}\) Reflexive Property of Congruence
9. ΔSUV ≅ ΔTVU \({}\) SAS
What are congruent triangles?Two triangles such as ΔSUV and ΔTUV are congruent when the three sides of triangle ΔSUV are congruent to the three sides of triangle ΔTUV.
The details of the reasons used to prove the congruency of the triangles are as follows;
Alternate Interior Angles Theorem
The alternate interior angles theorem states that the alternate interior angles formed by two parallel lines, such as \(\overline{UV}\) and \(\overline{ST}\) and their common transversals, \(\overline{TV}\) and \(\overline{SU}\), are congruent.
Transitive Property of Congruence
The transitive property of congruence states that two shapes are congruent to themselves if both shapes are congruent to a third shape.
Reflexive Property of Congruence
The reflexive property of congruence states that a shape, line, or angle is congruent to itself.
SAS
SAS, is an acronym for Side-Angle-Side congruency postulate, which states that, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
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A grocery store orders 3 large cartons of eggs for every 7 small cartons of eggs. Which ratio could represent the number of large cartons of eggs to small cartons of eggs in an order from the grocery store?
Answer:
3:7
Step-by-step explanation:
-
Hope that helps
Did I graph this equation right?
Equation: P=125+50w
Answer:
yes
Step-by-step explanation:
You want a graph of P = 125 +50W.
Slope-intercept formThe given equation is in slope-intercept form. The independent variable is W, and the dependent variable is P.
Axes assignmentsUsually, the independent variable is graphed on the horizontal axis, which you have done.
The dependent variable is graphed on the vertical axis, which you have done.
The axes are correctly labeled and graduated.
InterceptThe "y-intercept" (P value) when the independent variable is zero is the constant in the equation, 125. You have correctly shown that on the graph.
SlopeThe slope of the line is the coefficient of the independent variable (W) in the equation. You have correctly shown that P increases by 50 when W increases by 1.
Yes, you properly graphed the equation.
<95141404393>
For a certain type of hay fever, Medicine H has a 30% probability of working. In which distributions does the variable X have a binomial distribution?
Select EACH correct answer.
A. When the medicine is tried with two patients, X is the number of patients for whom the medicine worked.
B. When the medicine is tried with six patients, X is the number of patients for whom the medicine does not work.
C. When the medicine is tried with six patients, X is the number of patients for whom the medicine worked.
D. When the medicine is tried with two patients, X is the number of doses each patient needs to take.
The variable X has a binomial distribution in the following distributions:
A. When the medicine is tried with two patients, X is the number of patients for whom the medicine worked.
C. When the medicine is tried with six patients, X is the number of patients for whom the medicine worked.
What is binomial distribution?In a binomial probability distribution, the number of "Successes" in a series of n experiments is represented as either success/yes/true/one (probability p) or failure/no/false/zero (probability q = 1 p), depending on the outcome's boolean value.
In a binomial distribution, we have a fixed number of independent trials (in this case, the number of patients), and each trial has only two possible outcomes (success or failure). The probability of success remains the same for each trial (in this case, the probability of the medicine working is 30%).
Option B does not represent a binomial distribution since it counts the number of patients for whom the medicine does not work, which is the complement of success. Option D is not a binomial distribution as it counts the number of doses each patient needs to take, which is not a success/failure outcome.
So, the correct answers are:
A. When the medicine is tried with two patients, X is the number of patients for whom the medicine worked.
C. When the medicine is tried with six patients, X is the number of patients for whom the medicine worked.
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What is the y-interception of the quadratic function
f(x)=(x - 6) (x-2)?
Answer:
(0, 12)
Step-by-step explanation:
To find the y-intercept of the quadratic function f(x) = (x - 6)(x - 2), we need to substitute x = 0 in the equation and solve for f(0).
f(x) = (x - 6)(x - 2)
f(0) = (0 - 6)(0 - 2) // Substitute x = 0
f(0) = 12
Therefore, the y-intercept of the quadratic function f(x) = (x - 6)(x - 2) is 12, which means the graph of the function intersects the y-axis at the point (0, 12).
Can someone please help?
Answer:
Step-by-step explanation:
8b-4b+8-3=4b+5
4b=-5
b=-5/4=1 1/4
Answer:
4b+5
Step-by-step explanation:
i flip a coin 40 times. what is the expected number of pairs of consecutive tosses that comes up heads?
Answer:
20
Step-by-step explanation:
because you have a 50 % 50% shot of getting either.
Answer:
20
Step-by-step explanation:
Add these fractions, giving your answer
in its simplest form.
6/12 + 2/13 =?
Answer: 0.6 espero haberte ayuado
Step-by-step explanation:
Cara and Beejal make a poster for school. The poster is in the shape of a rectangle. The left side of the poster measures 7 units; the top side of the poster measures 6 units. What is the area in square units of the completed poster?
26 square units
48 square units
42 square units
13 square units
The area of the completed poster is 42 square units.
The answer is (c) 42 square units.
The area of a rectangle:The area of a rectangle is the total amount of space or region enclosed within the boundaries of a rectangle.
It is measured in square units, which is the product of the length and the width of the rectangle.
The formula for calculating the area of a rectangle is:
Area = Length x Width
Here we have
Cara and Beejal make a poster for school.
The poster is in the shape of a rectangle. The left side of the poster measures 7 units; the top side of the poster measures 6 units.
The area of a rectangle is found by multiplying its length by its width.
In this case, the length of the poster is 7 units and the width is 6 units, so the area is:
Area = length × width
Area = 7 × 6
Area = 42 square units
Therefore,
The area of the completed poster is 42 square units.
The answer is (c) 42 square units.
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After the expression above is simplified, what is the coefficient of x expressed as a decimal?
Answer:
-0.8
Step-by-step explanation:
3/5 × (2x + 5) - 2x =
= 3/5 × 2x + 3/5 × 5 - 2x
= 1.2x + 3 - 2x
= -0.8x + 3
Answer:
-0.8
Step-by-step explanation:
The question asks for the expression to be simplified, so we can start with that. I will put fractions in parentheses for easier readability.
The first step is to distribute the (3/5) to the terms in the parentheses. (3/5) * 2x is (6/5)x, and (3/5) * 5 is 3. The expression we're then left with is (6/5)x + 3 - 2x.
I'm going to convert (6/5) here into a decimal, because it'll, in my opinion, make the later calculations easier, but you don't need to. (6/5) now becomes 1.2.
The second step is to combine like terms, meaning combining the two terms with "x". 1.2x - 2x is -0.8x, giving the final expression of -0.8x + 3.
This is as far as we can go with the simplification. Therefore, the final answer must be the coefficient of x, or the number x is being multiplied by. As it is already a decimal, there's no need to convert.
The coefficient of x here is -0.8, so that is the final answer.
Hope this helps! Let me know if you have any questions.
In which shapes does the measure of
∠
K
=
40
°
∠
K
=
40
°
?
Select the shapes you want to choose.
Answer:
Step-by-step explanation:
Write the slope-intercept form of the linear equation that is parallel to y = -3x + 5 and passes through (-4,5)
Answer:
y = -3x - 7
Step-by-step explanation:
slope: -3
point: (-4,5)
slope formula: y = mx + b
m = slope
b = y-intercept
First, substitute in slope
y = -3x + b
Then, substitute the point (x,y) to solve for b
5 = -3(-4) + b
5 = 12 + b
5 - 12 = 12 - 12 + b (Subtract 12 on both sides to balance equation)
-7 = b
Now, plug in whole equation without the point
y = -3x - 7
what is the value of X
-9(x+6)=-207
Answer:
x=17
It just is. I don't know how to explain it.
the opera theater manager calculates that 20% of the opera tickets for tonight's show have been sold. if the manager is right, what is the probability that the proportion of tickets sold in a sample of 865 tickets would differ from the population proportion by greater than 3% ? round your answer to four decimal places.
The probability that the proportion of tickets sold in a sample of 865 tickets would differ from the population proportion by greater than 3% would be 0.0456, rounded to four decimal places.
By using the following formula, we can find the standard error in the population:
SE = √(p(1-p)/n),
where p is population proportion and n is sample size.
Since p = 0.2 and n = 865 in this instance, Therefore,
SE = √(0.2 × 0.8 / 865) = 0.015.
The z-score is then determined by dividing (0.03 - 0) by 0.015, which is 2.
We can determine that the likelihood of receiving a z-score larger than 2 or less than -2 is around 0.0456 using a conventional normal distribution table.
So, the likelihood that the proportion of tickets sold in a sample of 865 tickets would deviate from the general proportion by more than 3% is roughly 0.0456, rounded to four decimal places.
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60=-5(x-6)
Please answer this with how you got the answer.
Answer:
x = -6
Step-by-step explanation:
» Solution
Step 1: Distribute -5 to the terms inside the parantheses.
\((-5)(x)+(-5)(-6)=60\) \(-5x+30=60\)Step 2: Subtract 30 from both sides.
\(-5x+30-30=60-30\) \(-5x=30\)Step 3: Divide both sides by -5.
\(-5x/-5=30/-5\) \(x=-6\)Therefore, x = -6.
If the semi-circle and the parabola are the respective graphs of fx= square root of 9-x2,gx=b- 1/4 x2, find the value of b.
The value of b is 2.
To find the value of b, we need to equate the equations of the semi-circle and the parabola.
The equation of the semi-circle is given as fx = √(9 - x²).
The equation of the parabola is given as gx = b - (1/4)x².
Since both graphs represent the same function, we can equate them and solve for the value of x:
√(9 - x²) = b - (1/4)x²
To simplify the equation, let's square both sides:
9 - x² = (b - (1/4)x²)²
Expanding the right side of the equation:
9 - x² = b² - 2b(1/4)x² + (1/16)x⁴
Combining like terms:
9 - x² = b² - (1/2)bx² + (1/16)x⁴
Since the two sides of the equation are equal for all values of x, the coefficients of each power of x must be equal. Comparing the coefficients, we have:
-1 = -b/2 (coefficient of x² term)
0 = 1/16 (coefficient of x⁴ term)
From the coefficient of the x² term, we can solve for b:
-b/2 = -1
b/2 = 1
b = 2
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what is an equivalent expression
Answer:
1st option
Step-by-step explanation:
using the rules of logarithms
• log x + log y = log xy
• n logx ⇔\(x^{n}\)
given
2\(log_{2}\) 3 + \(log_{2}\) 3
= \(log_{2}\) 3² + \(log_{2}\) 3
= \(log_{2}\) 9 + \(log_{2}\) 3
= \(log_{2}\) (9 × 3)
= \(log_{2}\) 27
43.87 + what = 58.92
Answer:
15.05
Step-by-step explanation:
:) :0
Juana borrowed $10,686.00 from her parents to finance a vacabion. H interest was charged on the loan at 5.79% p.a., how much interest would she have to pay in 20 days?
Juana would have to pay approximately $29.40 in interest for the $10,686.00 loan over a 20-day period, assuming an annual interest rate of 5.79%.
The interest Juana would have to pay in 20 days can be calculated using the formula:
Interest = Principal × Interest Rate × Time
In this case, the principal amount is $10,686.00 and the interest rate is 5.79% per annum. To calculate the interest for 20 days, we need to convert the time to a fraction of a year. Since there are 365 days in a year, the time in years would be 20/365.
Using the formula and substituting the values:
Interest = $10,686.00 × 0.0579 × (20/365)
Calculating this expression, we find that the interest amount Juana would have to pay in 20 days is approximately $29.40.
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Pls solve the screenshot
Scores on an exam follow an approximately Normal distribution with a mean of 76.4 and a standard deviation of 6.1 points. What is the minimum score you would need to be in the top 7%? 0.93 1.48 85.4 81.4
the minimum score needed to be in the top 7% is 85.48, which can be rounded to 85.4. To determine the minimum score needed to be in the top 7%, we need to use the properties of the normal distribution and the corresponding z-score.
First, we need to find the z-score that corresponds to the top 7%. This can be done by using the standard normal distribution table or a calculator with a normal distribution function. The z-score that corresponds to the top 7% is approximately 1.48.
Next, we can use the formula for transforming a z-score to a raw score:
raw score = z-score * standard deviation + mean
Substituting the values given in the problem, we get:
raw score = 1.48 * 6.1 + 76.4
raw score = 85.48
Therefore, the minimum score needed to be in the top 7% is 85.48, which can be rounded to 85.4.
In conclusion, the minimum score needed to be in the top 7% is 85.4. This calculation was performed by finding the z-score that corresponds to the top 7%, and then transforming the z-score to a raw score using the mean and standard deviation of the distribution.
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An expression is given: (3x−1)−2.75(x+2)
0.25x - 3
0.25x - 6.5
0.25x + 1
0.25x + 4.5
(c) A non-uniform but spherically symmetric charge distribution has a charge density: rho(r)=rho 0
(1−r/R)
rho(r)=0
for r≤R
for r>R
where rho 0
=3Q/πR 3
is a positive constant. Show that the total charge contained in this charge distribution is Q. [4] Show that the electric field in the region r>R is identical to that created by a point charge Q at r=0 [2] Derive an expression for the electric field in the region r≤R. [5]
To show that the total charge contained in the charge distribution is Q, we integrate the charge density over the entire volume. The charge density is given by:
ρ(r) = ρ₀(1 - r/R) for r ≤ R,
ρ(r) = 0 for r > R,
where ρ₀ = 3Q/πR³.
To find the total charge, we integrate ρ(r) over the volume:
Q = ∫ρ(r) dV,
where dV represents the volume element.
Since the charge density is spherically symmetric, we can express dV as dV = 4πr² dr, where r is the radial distance.
The integral becomes:
Q = ∫₀ᴿ ρ₀(1 - r/R) * 4πr² dr.
Evaluating this integral gives:
Q = ρ₀ * 4π * [r³/3 - r⁴/(4R)] from 0 to R.
Simplifying further, we get:
Q = ρ₀ * 4π * [(R³/3) - (R⁴/4R)].
Simplifying the expression inside the parentheses:
Q = ρ₀ * 4π * [(4R³/12) - (R³/4)].
Simplifying once more:
Q = ρ₀ * π * (R³ - R³/3),
Q = ρ₀ * π * (2R³/3),
Q = (3Q/πR³) * π * (2R³/3),
Q = 2Q.
Therefore, the total charge contained in the charge distribution is Q.
To show that the electric field in the region r > R is identical to that created by a point charge Q at r = 0, we can use Gauss's law. Since the charge distribution is spherically symmetric, the electric field outside the distribution can be obtained by considering a Gaussian surface of radius r > R.
By Gauss's law, the electric field through a closed surface is given by:
∮E · dA = (1/ε₀) * Qenc,
where ε₀ is the permittivity of free space, Qenc is the enclosed charge, and the integral is taken over the closed surface.
Since the charge distribution is spherically symmetric, the enclosed charge within the Gaussian surface of radius r is Qenc = Q.
For the Gaussian surface outside the distribution, the electric field is radially directed, and its magnitude is constant on the surface. Hence, E · dA = E * 4πr².
Plugging these values into Gauss's law:
E * 4πr² = (1/ε₀) * Q,
Simplifying:
E = Q / (4πε₀r²).
This is the same expression as the electric field created by a point charge Q at the origin (r = 0).
To derive an expression for the electric field in the region r ≤ R, we can again use Gauss's law. This time we consider a Gaussian surface inside the charge distribution, such that the entire charge Q is enclosed.
The enclosed charge within the Gaussian surface of radius r ≤ R is Qenc = Q.
By Gauss's law, we have:
∮E · dA = (1/ε₀) * Qenc.
Since the charge distribution is spherically symmetric, the electric field is radially directed, and its magnitude is constant on the Gaussian surface. Hence, E · dA = E * 4πr².
Plugging these values into Gauss's law:
E * 4πr² = (1/ε₀) * Q.
Simplifying:
E = Q / (4πε₀r²).
This expression represents the electric field inside the charge distribution for r ≤ R.
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WILL GIVE BRAINLIEST!
If Triangle ABC ≈ Triangle DBE, find the value of x.
Answer:
x = 49
Step-by-step explanation:
The sum of angles in a triangle add up to 180°.
∠CBA = ∠EBD (Vertically opposite angles are equal)
= 52°
Since in the triangle DBE, you already know two of the angles, you can find ∠BDE which is equal to ∠CAB (x + 9)°.
∠BDE = 180° - 70° - 52°
= 58°
∠BDE = ∠CAB
= ∠(x + 9)°
= 58°
x + 9 = 58
x = 58 - 9
x = 49
solve and reduce to the lowest terms: 2/7 times 5/6
Answer:
5/21
Step-by-step explanation:
2/7 * 5/6 = 2 * 5 / 7 * 6 = 10 / 42 = 5/21
Hey there!
2/7 × 5/6
= 2 × 5 / 7 × 6
= 10 / 42
= 10 ÷ 2 / 42 ÷ 2
= 5 / 21
Therefore, your answer should be: 5/21
Good luck on your assignment & enjoy your day!
~Amphitrite1040:)
4 1by8 - 1 3by5 having trouble
Answer:
hope it's helpful. good luck
Answer: 2²¹/₄₀
Step-by-step explanation:
\(\displaystyle\\4\frac{1}{8}-1\frac{3}{5} =\\\\\frac{4*8+1}{8} -\frac{1*5+3}{5}=\\ \frac{32+1}{8} -\frac{5+3}{5} =\\\\\frac{33}{8}-\frac{8}{5} =\\\\ \frac{33*5-8*8}{8*5}=\\\\ \frac{165-64}{40} =\\\\\frac{101}{40}=\\\\ 2\frac{21}{40}\)