Answer:
he magnetic field is greater because the magnetization of the material is added
Explanation:
The magnetic field in a solenoid is given by the relation
B₀o = μ₀ n I
where n is the density of turns and I the current
When we put a magnetic material inside solenoid
the magnetic field is
B = B₀ + μ₀ M
where M is called the magnetization of the material and corresponds to the alignment of the magnetic moments of the atoms with the field, therefore the total field is much greater, it should be noted that the part of Bo increases with the current, but the magnetization has a maximum value.
Consequently the magnetic field is greater because the magnetization of the material is added
at room temperature, what fraction of the nitrogen molecules in the air are moving at less than 300 m/s?
The fraction of nitrogen molecules in the air that are moving at less than 300 m/s is likely to be very high, since this is well below the average speed of nitrogen molecules at room temperature. However, the exact fraction will depend on the specific temperature and pressure conditions.
At room temperature, the majority of nitrogen molecules in the air move at speeds less than 300 m/s. The average speed of nitrogen molecules in the air is around 500 m/s, but the speed distribution follows a bell-shaped curve, with a small fraction of molecules moving much faster and a small fraction moving much slower than the average.
The distribution of molecular speeds is determined by the Maxwell-Boltzmann distribution, which describes how the speeds of gas molecules are related to temperature. The distribution shows that at any given temperature, only a small fraction of molecules have speeds greater than a certain value.
For example, at room temperature (around 25°C or 298 K), only about 2.5% of nitrogen molecules in the air have speeds greater than 500 m/s, while the vast majority (over 97%) have speeds less than this value. Even fewer molecules (less than 0.1%) have speeds greater than 1000 m/s, which is much faster than the speed of sound in air.
Overall, the fraction of nitrogen molecules in the air that are moving at less than 300 m/s is likely to be very high, since this is well below the average speed of nitrogen molecules at room temperature. However, the exact fraction will depend on the specific temperature and pressure conditions.
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what are the main obstacles Gey and his assistants faced in their effort to grow cells.
a physical quantity Z is given by z=ad/g .calculte the relatibe error in z
Answer:
e_{r} = Δa /a + Δd /Δ d + Δg / g
Explanation:
The error or uncertainty of a quantity is given by several factors, the most direct error is the absolute one that is given by the appreciation of the instruments, when some quantities obtained by a mathematical formula we must know how each error is programmed in the total error, we can see this with the relative error
the calculated quantity is Z
its relative error is
\(e_{r}\) = ΔZ/Z = 1/Z (dZ /da Δa + dZ /dd Δd + dZ /dg Δg)
e_{r} = 1 / Z (d /g Δa + a /g Δd + ad !1/g²! Δg)
e_{r} = Δa /a + Δd /Δ d + Δg / g
notice that we take the worst case.
The measured quantities have absolute errors Da, Dd, Dg
A student slides her 80.0-kg desk across the level floor of her dormitory room a distance 2.00 m at constant speed. If the coefficient of kinetic friction between the desk and the floor is 0.400, how much work did she do?
Answer:
628 J
Explanation:
Force of friction x distance = work
force of friction = normal force * coeff
= ( 80 kg * 9.81 m/s^2) * .4 = 313.92 N
3139.2N * 2 m = 627.84 J = ~ 628 J
Compared to a sidereal month, the time from one full moon to the next is:__________
The sidereal month of the moon is approximately 27.321661 days, and the time from one full moon to the next is called a synodic month, which is about 29.5 days.
The time from one full moon to the next is called a synodic month, which is about 29.5 days. The synodic month is longer than the sidereal month because during the time it takes for the moon to return to the same position relative to the stars, the Earth has also moved in its orbit around the sun.
This means that the moon has to travel a little further to get back to the same position relative to the Earth, making the synodic month slightly longer. The difference between the two is only about 0.3 days, but over time it can have significant effects on the moon's position relative to the Earth and the timing of lunar events.
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Question 3 of 5
The gravitational pull of the Moon is much less than the
gravitational pull of Earth.
Which two statements are true for an object with a mass of 20 kilograms that
weighs 44 pounds on Earth?
A. The object's mass would be less on the Moon.
B. The object's mass would be the same on the Moon.
C. The object's weight would be the same on the Moon.
D. The object's weight would be less on the Moon.
Answer:
Number b and c are true
B. The object's mass would be the same on the Moon.
C. The object's weight would be the same on the Moon.
a plant that is 4.1 cm tall is 10.3 cm from a converging lens. you observe that the image of this plant is virtual and 6.2 cm tall. what is the focal length of the lens?
Answer:A plant that is 4.1 cm tall is 10.3 cm froma converging lens. You observe that the image of this plant is virtual and 6.2 cm tall.
blocks x and y are attached to each other by a light rope and can slide along a horizontal surface. Mass of block x is 10 kg and that of block y is 5 kg. the magnitude of force of friction on blocks x and y is 8.0 N and 4.0N respectively. Find the action-reaction forces that the blocks exert on each other if an applied force of 40 N(right) acts on block per illustration below.
Blocks x and y exerts action-reaction forces on each other with 146.1 N and 53.1 N respectively.
The given parameters:
mass of block x = 10 kg
mass of block y = 5 kg
magnitude of the frictional force of block x = 8 N
magnitude of the frictional force of block y = 4 N
the applied force to the right = 40 N
To find:
the action-reaction forces that the blocks exert on each otherThe block y pulls block x to the left with the following reaction forces;
Force of block y = force due to its own weight + frictional force
Reaction Force of block y = mg + 4 Nwhere;
g is the acceleration due to gravity = 9.81 m/s²
Reaction Force of block y = (5 x 9.81) + 4Reaction Force of block y = 49.1 + 4Reaction Force of block y = 53.1 NThus, block y reacts on block x with a force of 53.1 N
The block x acts on block y towards the right direction with following forces;
Force of block x on y = force due to its own weight + frictional force + applied force to the right
Force of block x on y = (mg) + (8 N) + (40 N)Force of block x on y = (10 x 9.81) + (48)Force of block x on y = 98.1 + 48Force of block x on y = 146.1 NThus, block x acts on block y with a force of 146.1 N
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Two identical objects, A and B, move along straight, parallel, horizontal tracks. The position – time graph represents the position as a function of time for objects A and B.
a) At approximately which time or times, if any, are the objects moving at the same speed? If the objects are never moving at the same speed during the time interval shown, indicate this directly. Briefly explain your answer.
(b) Describe what is happening to the positions of objects A and B between 3 s and 4 s.
I would appreciate some help with this, thank you!
Part (a)
The position of both objects is increasing, so we can consider when the velocities are the same. The velocity is the rate of change of position with respect to time, so we can see when the slope of the tangents to both graphs is the same. This occurs at about 1 second.
Part (b)
The positions of objects A and B are both increasing. However, the position of object A is increasing at a constant rate, while the same cannot be said for object B.
Ph11_UnitPacket2019
Page 30 of 38
3. A ray of light travels from air into a liquid. The ray is incident upon the liquid at an angle of 30.0 degrees
The angle of refraction is 19.9º.
a. What is the index of refraction for the liquid? 1901
1999
thin liquid could be.
Let's see
Use snells law
\(\\ \rm\Rrightarrow \dfrac{n_1}{n_2}=\dfrac{sini}{sinr}\)
\(\\ \rm\Rrightarrow \mu=\dfrac{sin30}{sin19.9}\)
\(\\ \rm\Rrightarrow \mu=0.5/0.34\)
\(\\ \rm\Rrightarrow \mu=1.47\)
It may be glass
a wrench cm long lies along the positive -axis and grips a bolt at the origin. a force is applied in the direction at the end of the wrench. find the magnitude of the force needed to supply of torque to the bolt.
A 30 cm long wrench is positioned at the origin, along the positive y-axis, and is holding a bolt. Just at end of the wrench, a force is exerted in the direction of "0, 3, and 4"
What does force in physics mean?
You can also use words like extend and squeeze to describe force. Force is described in physics as the pull or push that causes a massed object to change its speed. Force is an outside agent that has the power to alter a body's resting or moving position.
What function does force serve?
For instance, if there is no opposition, force is defined as the interaction that modifies an object's motion. When we look attentively at this sentence, we can see how push-pull plays a part in it. A pull is defined as a force that causes an object to move closer to you. On the other side, it is a shove if it travels away.
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An airplane travels for 2.5 hours at an average rate
of 130 miles per hour. Use the distance formula, d=rt, to find how
far the plane travels.
The plane travels a distance of 325 miles if the airplane travels for 2.5 hours at an average speed of 130 miles per hour. Using the distance formula (d = rt), we can calculate the distance.
To find the distance traveled by the airplane, we can use the distance formula, which is represented as d = rt. In this formula, "d" represents the distance, "r" represents the rate or speed at which the object is traveling, and "t" represents the time taken for the travel.
Given that the airplane travels for 2.5 hours at an average rate of 130 miles per hour, we can substitute these values into the formula. The rate of the airplane is 130 miles per hour, and the time taken is 2.5 hours.
Using the formula, we can calculate the distance traveled as follows:
d = rt
d = 130 mph × 2.5 hours
Multiplying the rate (130 mph) by the time (2.5 hours) gives us:
d = 325 miles
Therefore, the airplane travels a distance of 325 miles during the 2.5 hours of travel at an average rate of 130 miles per hour.
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The chart shows the time, initial velocity, and final velocity of three riders.
A 4-column table with 3 rows. The first row labeled rider has entries Gabriella, Franklin, Kendall. The second row labeled time with entries 10 seconds, 8.5 seconds, 6 seconds. The third column labeled initial velocity has entries 55, 50, 53.2. The fourth column labeled final velocity has entries 32, 50, 67.
Which best describes the riders' final velocities ?
The motion of Gabriella is decelerated.
The motion of Franklin is uniform.
The motion of Kendall is accelerated.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
As per the given data after interval of time:
The final velocity of Gabriella decreases and the motion is decelerated.
The final velocity of Franklin remains same and the motion is uniform.
The final velocity of Kendall increases and the motion is accelerated.
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Joe pushes a 12,000 N car, starting from rest, with a force of 310 N for 20 seconds. (a) What is the magnitude of the car's acceleration? (b) How much force would be needed to stop the car in a distance of 30 m?
The acceleration of the car can be obtained as 0.26 m/s^2. The force required to ove it a distance of 30 m is 11760 N.
What is the acceleration?We know that the acceleration is the change in the velocity of the object with time. Now we know from the Newton law that the force is the product of the mass of the object and the acceleration.
Now we have that;
weight = mass * acceleration due to gravity
mass = weight/ acceleration due to gravity
mass = 12,000 N / 10 m/s^2
= 1200 Kg
The we know that;
Force = mass * acceleration
acceleration = Force/mass
= 310 N/1200 Kg
= 0.26 m/s^2
For the force that that is needed to move the car a distance of 30 m we have;
F = ma
= 1200 Kg * 9.8 m/s^2
= 11760 N
This is the force that ca move the object forward.
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On the graph of voltage versus current, which line represents a 2.0 Ω resistor?
Answer:
line BExplanation:
According to ohm's law V = IR where;
V i sthe supply voltage (in volts)
I = supply current (in amperes)
R = resistance (in ohms)
In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.
For line B, R = ΔV/ΔI
R = V₂-V₁/I₂-I₁
R = 14.0-4.0/7.0-2.0
R = 10.0/5.0
R = 2.0ohms
Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.
Answer:
line A
Explanation:
A P E X
A gray kangaroo can bound across a flat stretch of ground with each jump carrying it 8.0 m from the takeoff point.
If the kangaroo leaves the ground at a 22˚ angle, what is its takeoff speed?
What is its horizontal speed?
The kangaroo's horizontal speed will be 9.7 m/s and its departure speed will indeed be 10.65 m/s.
What is the sound's velocity?By observing the pace at which this compressed region moves through the medium, we may determine the sound speed. The sound wave travels at a speed of around 343 meters per second in low humidity at 20 degrees Celsius.
Briefing:The following equation relates the distance to the direction and initial velocity:
d = [v₀²sin2θ]/g, where θ – the angle of the jump.
Thus, v₀² = gd / (sin2θ) = (9.8×8)/0.69 = 113.62
v₀ = 10.65 m/s ( the take off speed).
The horizontal velocity equals:
vₓ = v₀cos 22° = 10.65 m/s × 0.92 = 9.7 m/s
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If the radius of an electron's orbit around a nucleus doubles but the wavelength remains unchanged, what happens to the number of electron wavelengths that can fit in the orbit?
Answer:
Number of electron wavelength will Double
Explanation:
let the radius = r and wavelength = λ
when R doubles and λ ( wavelength ) remains the same
The number of electron electron wavelengths will double as well
Using Bohr's angular momentum quantization to show this
attached below
How are cactus adapted to survive in deserts?
1. They have evolved their leaves into spikes for minimum water loss through transpiration.
2. They have a waxy layer for minimum water loss.
3. They have thick walls for minimum water loss.
4. They can take water from atmosphere.
5. They change the photo energy from Sun into an intermediate stage and store it, so that they can make food even in night.
Do you believe the media portrays substance abuse as a positive or negative behavior? Explain.
Be sure to include examples to support your position.
If you add something, you are being positive; if you subtract something, you are being negative.
How are individuals portrayed in the media?Whatever is shown in the media should be properly understood by the audience. The connection between the audience and the message is referred to as "meaning" in communication terminology. This point of view asserts that what ultimately determines how people act are their inner perceptions.
What do media portrayals include?Media representations refer to the ways in which the media presents particular communities, experiences, ideas, or topics from a particular ideological or value perspective.
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If the average kinetic energy of the molecules in an ideal gas initially at 20 degrees Celsius doubles, what is the final temperature of the gas?
The final temperature of the gas will be 40 degrees Celsius.
The average kinetic energy of gas particles is proportional to the absolute temperature of the gas, and all gases at the same temperature have the same average kinetic energy.
The temperature of a substance is directly related to its kinetic energy. Kinetic energy is the energy that a substance has because its molecules are in motion, so when a substance absorbs heat, the molecules move faster and the kinetic energy of the substance increases.
As the average kinetic energy of its particles increases, the thermal energy of the object increases. Therefore, the thermal energy of an object increases as its temperature increases. Since the average Kinetic Energy has doubled, so has the absolute temperature.
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the combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, what source strength is required to simulate flow around the body?
The combination of a uniform flow and a source can be used to describe flow around a streamlined body called a half- body. (see video v6.5.) assume that a certain body has the shape of a half-body with a thickness of 0.5 m. if this body is placed in an airstream moving at 15 m/s, The source strength is required to simulate flow around the body is (m)= 94.2 kg.
What is force?Force is a physical appearance that happen on a object of some amount of masses and then it changes it form and move a bit that called the force. It is a vector quantity. It can be measured in Newton, Dyne.
How can we calculate the source strength is required to simulate flow around the body?To calculate the source strength is required to simulate flow around the body we are using the formula here is,
v= m/2*π*b
Or, m= 2*π*b*v
Here we are given,
b= The thickness of a certain body has the shape of a half-body = 2*r = 2* 0.5 = 1 m
v = The velocity of the object. = 15 m/s.
We have to calculate the values of the source strength is required to simulate flow around the body = m kg
Now we put the values in above equation we get,
m= 2*π*b*v
Or, m= 2*π*1*15
Or, m= 94.2 kg
so we can say that , The source strength is required to simulate flow around the body is (m)= 94.2 kg
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Two electrons (-1.6 x 10-1°c) in an atom are separated by 3.4 x 10-11 m. what is the electrostatic force
between them? is it attractive or repulsive?
The electrostatic force between the electrons is approximately 2.31 x 10⁻²⁸ N, acting in a repulsive manner.
To find the electrostatic force between the two electrons, we will use Coulomb's Law, which states that the electrostatic force (F) between two charged particles is directly proportional to the product of their charges (q1 and q2) and inversely proportional to the square of the distance (r) between them. Mathematically, this is represented as:
F = (k * q1 * q2) / r²
Where k is Coulomb's constant, approximately equal to 8.99 x 10⁹ Nm²/C². In this problem, both electrons have a charge of -1.6 x 10⁻¹⁹ C, and they are separated by a distance of 3.4 x 10⁻¹¹ m. Plugging these values into the equation, we get:
F = (8.99 x 10⁹ Nm²/C² * (-1.6 x 10⁻¹⁹ C) * (-1.6 x 10⁻¹⁹ C)) / (3.4 x 10⁻¹¹ m)²
Calculating the force:
F ≈ 2.31 x 10⁻²⁸ N
Since both electrons have negative charges, the electrostatic force between them is repulsive. This is because like charges repel each other, while opposite charges attract. In this case, the two electrons have the same negative charge, which causes them to repel one another.
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12) Driving home from school one day, you spot a ball rolling out into the street (FIGURE 5-27). You brake for 1.20 s, slowing your 950-kg car from 16.0 m>s to 9.50 m>s. What was the average forceexerted on your car during braking and How far did you travel while braking?
We are given the following information
Mass of car = 950 kg
Initial speed of car = 16.0 m/s
Final speed of car = 9.50 m/s
Time = 1.20 s
The average force exerted on the car during braking can be found using Newton's 2nd law of motion
\(F=m\cdot a\)Where m is the mass of the car and a is the acceleration of the car.
The acceleration of the car is given by
\(\begin{gathered} a=\frac{v_f-v_i}{t} \\ a=\frac{9.50-16.0}{1.20} \\ a=-5.4167\; \; \frac{m}{s^2} \end{gathered}\)The negative sign indicates deacceleration since the car is stopping.
So, the force is
\(\begin{gathered} F=m\cdot a \\ F=950\cdot5.4167 \\ F=5145.865\; \; N \end{gathered}\)Therefore, an average force of 5145.865 N was exerted on your car during braking.
The distance traveled by the car while braking can be found as
\(s=v_i\cdot t+\frac{1}{2}\cdot a\cdot t^2\)Let us substitute the given values
\(\begin{gathered} s=16.0\cdot1.20+\frac{1}{2}\cdot(-5.4167)\cdot(1.20)^2 \\ s=19.20-3.90 \\ s=15.3\; m \end{gathered}\)Therefore, the car traveled a distance of 15.3 m while braking.
2) the earth is 1.49x1011 m from the sun. if the earth requires 365.25 days to go once around the sun, what is the centripetal force on the earth
The centripetal force on the earth is 352.8x 10^20N if the earth is 1.49x10^11 m from the sun and requires 365.25 days to go once around the sun.
Given the distance of earth from sun is (r) = 1.49x10^11 m
Number of days the earth requires to complete one revolution (T) = 365.25
The mass of the earth (m) = 5.98x10^24 kg
We know the centripetal force = Fc = mrω^2 where ω is the angular velocity of earth to travel around the sun.
Also we know that ω = 2π/T where T is the time required for the Earth to complete one revolution around the Sun.
Fc = m x r x (2π/T)^2
T = 365.25days x 24 hrs x 60 min x 60 s
Fc = (5.98x10^24 x 1.49x10^11 x 4π^2) / (365.25 x 24 x 60 x 60)^2
Fc = 351.4 x 10^35/(31557600)^2
Fc = 111.35 x 10^28/31557600
Fc = 352.8x 10^20N
Hence the centripetal force on the earth is 352.8x 10^20N.
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a tortoise is walking in the desert. it walks for 4 minutes at a speed of 15 meters per minute. for how many meters does it walk
The tortoise walks for 60 meters in the desert.
In the given scenario, the tortoise walks in the desert for a duration of 4 minutes at a constant speed of 15 meters per minute. To calculate the total distance covered by the tortoise, we can use the formula: distance = time × speed.
Applying this formula, the distance covered by the tortoise can be determined by multiplying the time (4 minutes) by the speed (15 meters per minute).
A tortoise walks in the desert for 4 minutes at a speed of 15 meters per minute. To find the total distance it covers, you can use the formula: distance = time × speed.
In this case, the distance is equal to 4 minutes × 15 meters per minute, which equals 60 meters. So, the tortoise walks for 60 meters in the desert.
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An engineering team has come to the stage in the engineering design process in which it is iterating to improve the solution. hat is one thing the team might be doing ?
When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:
Prototyping: This involves building a physical or digital prototype that can be tested and refined based on feedback from stakeholders. The team can then use this prototype to identify any design flaws and make the necessary changes.Simulation: Simulation involves creating a virtual model of the solution and testing it under various conditions. The team can use simulation to identify potential problems with the solution before it is built.User testing: User testing involves testing the solution with real users to get feedback on how well it works and how it can be improved. The team can use this feedback to make changes to the design and improve the user experience.Feedback analysis: This involves analyzing feedback from stakeholders, including users, customers, and other members of the team. The team can use this feedback to identify areas for improvement and make changes to the design.The key to iterating to improve the solution is to be open to feedback and willing to make changes. By continuously testing and refining the design, the engineering team can create a solution that meets the needs of stakeholders and achieves the desired outcomes.For such more question on stakeholders
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Activity 1 MATCH IT
Directions: Match Column A to Column B. Write your answer on the space provided before the number.
COLUMN A
__1. Hiking
__2. Orienteering
__3. Zumba
__4. Volleyball
__5.badminton
COLUMN B
A. It is an outdoor navigational recreational activity using specially drawn and detailed maps.
B. Created through on-the –spot aerobics class using the non- traditional music.
C.Going on an extended walk for the purpose of pleasure and exercise.
D. Can be traced from the ingenuity of William J. Morgan in 1895 at Holyoke Massachusetts.
E. Games are held inside the gym to avoid the effect of air in the flight of the shuttle.
Answer:
1. A hiking
2. C
3. B
4. D
5. E
Kenneth ran a marathon (26.2 miles) in 5.5 hours. What was Kenneth's average speed? (Round your answer to the nearest tenth.) 0.2 mph 4.8 mph 5.5 mph 144.1 mph
Answer:
4.8 mph
Explanation:
From the question,
Average speed = total distance/total time
V = d/t....................... Equation 1
Where d = distance, t = time
Given: d = 26.2 miles, t = 5.5 hours.
Substitute these values into equation 1
V = 26.2/5.5
V = 4.76 mph
V ≈ 4.8 mph
Answer:
4.8mph
Explanation:
Doing it now on EDG
For those doing the exam on EDG science rn, i wish you luck~
Have a good day!~ :D
If a stream drops 45 meters in 15 kilometers, what is its gradient? a) 333.3
meters per kilometer b) 0.33 meters per kilometer c) 3 meters per kilometer d) 0.003 meters per kilometer
To calculate the gradient of the stream, we need to determine the change in elevation per unit of horizontal distance.
In this case, the stream drops 45 meters over a horizontal distance of 15 kilometers. To find the gradient, we divide the vertical drop (45 meters) by the horizontal distance (15 kilometers). However, to ensure consistent units, we convert the 15 kilometers to meters by multiplying it by 1,000 (since there are 1,000 meters in a kilometer).
So, the calculation becomes:
Gradient = Vertical drop / Horizontal distance
= 45 meters / (15,000 meters)
= 0.003 meters per meter
This means that for every meter of horizontal distance, the stream drops by 0.003 meters vertically. Simplifying the expression, we can also express it as 3 millimeters (mm) per meter.
Therefore, the correct answer is d) 0.003 meters per kilometer.
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The percentage errors in the measurement of mass and speed are 1% and 2% respectively. what is the percentage error in the kinetic energy?
Given a 1% error in the measurement of mass and a 2% error in the measurement of speed, the percentage error in the calculation of kinetic energy can be determined.
Kinetic energy (KE) is calculated using the formula KE = 0.5 * m * v^2, where m represents mass and v represents speed. To determine the percentage error in the kinetic energy, we need to consider the effect of the percentage errors in mass and speed.
For mass, with a 1% error, we can assume that the measured mass (m) is actually (1 ± 0.01) times the true mass. Similarly, for speed, with a 2% error, the measured speed (v) is (1 ± 0.02) times the true speed.
To calculate the percentage error in the kinetic energy, we can propagate these errors by substituting the adjusted values of mass and speed into the kinetic energy formula. By simplifying the expression, we find that the percentage error in kinetic energy is the sum of the percentage errors in mass and speed.
In this case, the percentage error in the kinetic energy would be 1% (from the mass) + 2% (from the speed), resulting in a total percentage error of 3%. Therefore, the kinetic energy measurement is expected to have a 3% error based on the given 1% and 2% errors in the measurements of mass and speed, respectively.
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