The integral of x^2 + 25x^4 with respect to x is (1/3)x^3 + (25/5)x^5 + C. The integral of 4x(5e^(4x) + e^x) with respect to x is e^(4x) + (1/2)e^x + C.
To evaluate the integral of x^2 + 25x^4, we can use the power rule for integration. The power rule states that the integral of x^n with respect to x is (1/(n+1))x^(n+1) + C, where C is the constant of integration.Applying the power rule to x^2, we get (1/3)x^3. Applying the power rule to 25x^4, we get (25/5)x^5. Therefore, the integral of x^2 + 25x^4 with respect to x is (1/3)x^3 + (25/5)x^5 + C, where C is the constant of integration.To evaluate the integral of 4x(5e^(4x) + e^x), we can use the linearity property of integration.
The linearity property states that the integral of a sum of functions is equal to the sum of the integrals of the individual functions.The integral of 4x with respect to x is 2x^2. For the term 5e^(4x), we can apply the power rule for integration with the base e. The integral of e^(kx) with respect to x is (1/k)e^(kx), where k is a constant. Therefore, the integral of 5e^(4x) is (1/4) e^(4x).For the term e^x, the integral of e^x with respect to x is simply e^x.Adding the integrals of the individual terms, we obtain the integral of 4x(5e^(4x) + e^x) as e^(4x) + (1/2)e^x + C, where C is the constant of integration.
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consider the quadratic function y equals short dash x squared plus 6 x minus 5. what do we know about the graph of this quadratic equation, based on its formula?
Based on the formula of the quadratic function y=-x^2+6x-5, we know that its graph is a downward-facing parabola that opens wide, with a vertex at (3,-14), and an axis of symmetry at x=3.
Based on the formula of the quadratic function y=-x^2+6x-5, we can determine several properties of its graph, including its shape, vertex, and axis of symmetry.
First, the negative coefficient of the x-squared term (-1) tells us that the graph will be a downward-facing parabola. The leading coefficient also tells us whether the parabola is narrow or wide. Since the coefficient is -1, the parabola will be wide.
Next, we can find the vertex using the formula:
Vertex = (-b/2a, f(-b/2a))
where a is the coefficient of the x-squared term, b is the coefficient of the x term, and f(x) is the quadratic function. Plugging in the values for our function, we get:
Vertex = (-b/2a, f(-b/2a))
= (-6/(2*-1), f(6/(2*-1)))
= (3, -14)
So the vertex of the parabola is at the point (3,-14).
Finally, we know that the axis of symmetry is a vertical line passing through the vertex. In this case, it is the line x=3.
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NUMBER SENSE
27. Reverse the digits of 432 and subtract the
smaller number from the larger number.
Repeat this procedure five more times.
What is the final difference?
Answer: 99-99=0
Step-by-step explanation:
432,234 432-234=
198,891 891-198 =693
693,396 693-396 =297
297,792 792-297= 495
495,594 594-495=99
99-99=0
Lisa uses her railcard to buy a ticket.
She gets off the normal price of the ticket.
The normal price of the ticket is £24.90
Work out how much Lisa pays for the ticket.
The discount percentage is different, the amount that Lisa pays will also be different.
What exactly is the discounted method?The act of estimating the present value of a future payment or series of cash flows that will be received in the future is referred to as discounting. A discount rate (also known as a discount yield) is the rate at which future cash flows are discounted back to their present value.
We need to know what percentage of the regular ticket price Lisa saves with her railcard. We cannot calculate the exact amount Lisa pays for the ticket without this information.
Assuming Lisa receives a 1/3 discount with her railcard, we can calculate the cost of her ticket as follows:
Discounted price = Regular price minus discount amount
Normal price x Discount percentage = Discount amount
Discount rate = 1/3 = 33.33% (rounded to two decimal places)
Discount amount = £24.90 multiplied by 33.33% = £8.30 (rounded to two decimal places)
Price after discount = £24.90 - £8.30 = £16.60 (rounded to two decimal places)
As a result, if Lisa receives a 1/3 discount with her railcard, she will pay£16.60 for the ticket. However, if the discount percentage is different, Lisa's payment will be different as well.
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Lisa uses her railcard to buy a ticket.
She gets off the normal price of the ticket.
The normal price of the ticket is £24.90
Work out how much Lisa pays for the ticket.
I really need help with solving quadratics using the quadratic formula, if anybody could help me with these problems that would be awesome, i would like an explanation on how to do this.
1. Solutions: x = 3.4, 10.6
2. Solutions: \(x = \dfrac{-7}{2} - \dfrac{i\sqrt{15}}{2},\ x = \dfrac{-7}{2} + \dfrac{i\sqrt{15}}{2}\)
3. Solutions: x = -1, 11
Step-by-step explanation:Quadratic formula: \(x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\)
Quadratic equation: ax² + bx + c = 0, where a ≠ 0
1. x² - 14x + 36 = 0
a = 1, b = -14, c = 36
Substitute the given values into the formula:
\(x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-14)\pm\sqrt{(-14)^2-4(1)(36)}}{2(1)}\\\\x = \dfrac{14 \pm \sqrt{196-144}}{2}\\\\x = \dfrac{14\pm\sqrt{52}}{2}\\\\x = \dfrac{14\pm7.21}{2}\)
Separate into two cases:
\(a)\ x = \dfrac{14 - 7.21}{2}\implies x = \dfrac{6.79}{2}\implies x = 3.395\\\textsf{Nearest tenth: 3.4}\\\\ b)\x = \dfrac{14 + 7.21}{2}\implies x = \dfrac{21.21}{2}\implies x=10.605\\\textsf{Nearest tenth: 10.6}\)
2. x² + 7x + 16 = 0
a = 1, b = 7, c = 16
Substitute the given values into the formula:
\(x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-7\pm\sqrt{7^2-4(1)(16)}}{2(1)}\\\\x = \dfrac{-7 \pm \sqrt{49-64}}{2}\\\\x = \dfrac{-7 \pm \sqrt{-15}}{2}\\\\ x = \dfrac{-7 \pm i\sqrt{15}}{2}\)
Imaginary number rule: For any positive real number "k", \(\sqrt{-k} = i\sqrt{k}\)
Note: Two imaginary solutions indicate that the graph will not intersect the x-axis. As a result, it has no real roots.
Separate into two cases:
\(a)\ x = \dfrac{-7 - i\sqrt{15}}{2}\implies x = \dfrac{-7}{2} - \dfrac{i\sqrt{15}}{2}\\\\b)\ x = \dfrac{-7 + i\sqrt{15}}{2}$}\implies x = \dfrac{-7}{2}$} + \dfrac{i\sqrt{15}}{2}\)
3. x² - 10x - 11 = 0
a = 1, b = -10, c = -11
Substitute the given values into the formula:
\(x = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \dfrac{-(-10)\pm\sqrt{(-10)^2-4(1)(-11)}}{2(1)}\\\\x = \dfrac{10\pm\sqrt{100+44}}{2}\\\\x = \dfrac{10\pm\sqrt{144}}{2}\\\\x = \dfrac{10\pm12}{2}\)
Separate into two cases:
\(a)\ x = \dfrac{10 - 12}{2}\implies x = \dfrac{-2}{2}\implies x = -1\\\\ b)\ x = \dfrac{10 + 12}{2}\implies x = \dfrac{22}{2}\implies x = 11\)
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please help! i have no clue if it's equivalent :(
Answer:
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
y+2=y+2
Step 2: Subtract y from both sides.
y+2−y=y+2−y
2=2
Step 3: Subtract 2 from both sides.
2−2=2−2
0=0
Answer:
All real numbers are solutions.
Answer:
Yes
Step-by-step explanation:
First, combine like terms:
\((-\frac{1}{4} y+2\frac{1}{4}y -y)\) + 2
Solve:
y+2
Hope this helps!
(The following passage is an essay published by a British writer in the 1750s.) Pleasure is very seldom found where it is sought. Our brightest blazes of gladness are commonly kindled by unexpected sparks. The flowers which scatter their odors from time to time in the paths of life, grow up without culture from seeds scattered by chance. Nothing is more hopeless than a scheme of merriment. Wits and humorists are brought together from distant quarters by preconcerted invitations; they come attended by their admirers prepared to laugh and to applaud: they gaze a while on each other, ashamed to be silent, and afraid to speak; every man is discontented with himself, grows angry with those that give him pain, and resolves that he will contribute nothing to the merriment of such worthless company. Wine inflames the general malignity, and changes sullenness to petulance, till at last none can bear any longer the presence of the rest. They retire to vent their indignation in safer places, where they are heard with attention, their importance is restored, they recover their good humor, and gladden the night with wit and jocularity. Merriment is always the effect of a sudden impression. The jest which is expected is already destroyed. The most active imagination will be sometimes torpid, under the frigid influence of melancholy, and sometimes occasions will be wanting to tempt the mind, however volatile, to sallies and excursions. Nothing was ever said with uncommon felicity, but by the cooperation of chance; and therefore, wit as well as valor must be content to share its honors with fortune. All other pleasures are equally uncertain, the general remedy of uneasiness is change of place; almost everyone has some journey of pleasure in his mind, with which he flatters his expectation. He that travels in theory has no inconveniences; he has shade and sunshine at his disposal, and wherever he alights finds tables of plenty and looks of gaiety. These ideas are indulged till the day of departure arrives, the chaise is called, and the progress of happiness begins. A few miles teach him the fallacies of imagination. The road is dusty, the air is sultry, the horses are sluggish, and the postilion (21 brutal. He longs for the time of dinner that he may eat and rest. The inn is crowded, his orders are neglected, and nothing remains but that he devour in haste what the cook has spoiled, and drive on in quest of better entertainment. He finds at night a more commodious house, but the best is always worse than he expected. He at last enters his native province, and resolves to feast his mind with the conversation of his old friends, and the recollection of juvenile frolics. He stops at the house of his friend whom he designs to overpower with pleasure by the unexpected interview. He is not known till he tells his name, and revives the memory of himself by a gradual explanation. He is then coldly received, and ceremoniously feasted. He hastes away to another whom his affairs have called to a distant place, and having seen the empty house, goes away disgusted by a disappointment which could not be intended because it could not be foreseen. At the next house he finds every face clouded with misfortune, and is regarded with malevolence as an unreasonable intruder, who comes not to visit but to insult them. It is seldom that we find either men or places such as we expect them. He that has pictured a prospect upon his fancy, will receive little pleasure from his eyes; he that has anticipated the conversation of a wit, will wonder to what prejudice he owes his reputation. Yet it is necessary to hope, though hope should always be deluded, for hope itself is happiness, and its frustrations, however frequent, are yet less dreadful than its extinction. Overall, the style of the passage is best described as conversational digressive cryptic lyrical E intellectual
This is a passage from an essay published by a British writer in the 1750s.
The writer explores the idea that pleasure is rarely found where it is sought and that unexpected sparks can bring the brightest blazes of gladness.
The writer argues that merriment is often hopeless, as pre-planned schemes of humor can lead to discontent and anger.
Instead, true wit and humor come from chance and cooperation with fortune. The writer also explores the idea of travel and how the anticipation of pleasure is often shattered by the reality of dusty roads, bad food, and disappointing encounters.
Overall, the style of the passage is conversational and digressive, with a lyrical quality to the language.
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Jay and kevin are shoveling the snow off a driveway. working together, they can clear the driveway of snow in 14 minutes. working alone, it would take kevin 21 minutes longer to clear the driveway of snow than it would take jay working alone. when j is the number of minutes it would take jay to clear the driveway of snow when working alone, the situation is modeled by this rational equation: how long would it take jay to clear the driveway of snow working alone?
a. 7 minutes
b. 21 minutes
c. 35 minutes
d. 42 minutes
Therefore, As a result, the answer to the given equation problem is Jay would need to work alone for 21 minutes to remove the snow from the driveway.
Define equation .
A number, a variable, or a mix of both plus certain operation symbols make up an expression. An equal sign separates two expressions that make up an equation. Word illustration The product of 8 and 3 is 11.
Here,
The formula is: 1/j +1/j+ 21 = 11/ 4.
LCM = j+21+j / j(j+21)=1/14
Thus, 2j+21 / j(j+21) = 1/14 is obtained.
14(2j+21) times itself yields j(j+21).
28j+294 expanded to j²+21j
Gather comparable terms
j²+21j-28j-294=0
j²- 7j-294=0
With the use of a graphing calculator, we have:
j = 21 or j= -14
Due to the context,
j's value cannot be negative.
As a result, the answer to the given equation's problem is Jay would need to work alone for 21 minutes to remove the snow from the driveway.
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Consider the elliptic curve group based on the equation y2 = x3 + ax +b mod p where a = 1740, b 592, and p=2687 We will use these values as the parameters for a session of Elliptic Curve Diffie-Hellman Key Exchange. We will use P = (4,908) as a subgroup generator. You may want to use mathematical software to help with the computations, such as the Sage Cell Server (SCS). On the SCS you can construct this group as: G=EllipticCurve(GF(2687),[1740,592]) Here is a working example. (Note that the output on SCS is in the form of homogeneous coordinates. If you do not care about the details simply ignore the 3rd coordinate of output.) Alice selects the private key 33 and Bob selects the private key 9. What is A, the public key of Alice? What is B, the public key of Bob? After exchanging public keys, Alice and Bob both derive the same secret elliptic curve point TAB. The shared secret will be the x-coordinate of TAB. What is it?
Alice selects the private key 33 and Bob selects the private key 9. By evaluating the calculations with the given parameters, the shared secret x-coordinate will be obtained.
To perform the Elliptic Curve Diffie-Hellman Key Exchange, we need to compute the public keys A and B for Alice and Bob, respectively. Given the generator point P = (4,908) and the private keys (secret integers) for Alice and Bob as 33 and 9, respectively, we can compute their corresponding public keys.
First, we define the elliptic curve group using the provided parameters: G = EllipticCurve(GF(2687), [1740, 592]).
To compute the public key A for Alice, we multiply the generator point P by Alice's private key:
A = 33 * P.
Similarly, to compute the public key B for Bob, we multiply P by Bob's private key:
B = 9 * P.
Once the public keys A and B are computed, Alice and Bob exchange them. To derive the shared secret point TAB, both Alice and Bob perform scalar multiplication with their own private key on the received public key. In other words, Alice computes TAB = 33 * B, and Bob computes TAB = 9 * A.
Finally, the shared secret is the x-coordinate of TAB.
By evaluating the calculations with the given parameters, the shared secret x-coordinate will be obtained.
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Pls please help me ASAP!!!
Answer:
z = 0
Step-by-step explanation:
3 (z + 7) = 21
3z + 21 = 21
3z = 0
z = 0
HELP PLS Determine the type of correlation represented in the scatter plot below
Answer:
this is a positive correlation
Step-by-step explanation:
it is going up so its positive
18 = 5p + 3 NEED HELP ASAP
Answer:
\(p=3\)
Step-by-step explanation:
\(5p+3=18\\5p=15\\p=3\)
Hope this helps plz hit the crown :D
Answer:
Are you solving for p , because if you are p = 3
Step-by-step explanation:
18 = 5p + 3
Subtract 3 from both sides
15 = 5p
Divide by 5 in both sides
p = 3
Describe what is happening in this graph.
Roller Skating
Answer:
The skater slows down, then gains speed quickly. The speed begins to slow until it becomes constant .
Step-by-step explanation: answer on edge
Please help I will give brainliest
Answer:
1. ∠YZX = 37°
2. ∠YXZ = 53°
3. XZ = 30 meters
Step-by-step explanation:
1. To solve for an unknown angle, we need to utilize the inverse of a trigonometric function.
⭐What are the inverses of the trigonometric functions?
\(sin^-1 (opposite/hypotenuse)\)\(cos^-1 (adjacent/hypotenuse)\)\(tan^-1(opposite/adjacent)\)To know which inverse of the trigonometric functions we use, we have to see the type of side lengths we are given (opposite, adjacent, or hypotenuse)
We are given side length XY, which is opposite of ∠YZX, and we are given side length YZ, which is adjacent to ∠YZX. Therefore, we will use \(tan^-1 (opposite/adjacent) =\)
Substitute the values we are given into the function:
\(tan^-1 (18/24) =\)
Compute this equation using a scientific calculator. I recommend using the Desmos Scientific Calculator:
\(= 37\)
∴ ∠YZX = 37°
2. We already know 2 angles (∠YZX = 37°, and ∠ZYX = 90°) Therefore, to find ∠YXZ, we have to utilize the triangle sum theorem.
⭐ What is the triangle sum theorem?
\(angle_1 + angle_2 +angle_3 = 180\)The sum of all angles in a triangle is 180°Substitute the angles we know already (∠YZX and ∠ZYX), and solve for ∠YXZ.
\(< YZX + < ZYX + < YXZ = 180\)
\(37 + 90 + YXZ = 180\)
\(127 + YXZ = 180\)
\(< YXZ = 53\)
∴ ∠YXZ = 53°
3. We already know 2 side lengths (ZY = 24 meters, and XY = 18). Therefore, to find XZ, we have to utilize the Pythagoras' theorem.
⭐ What is the Pythagoras' theorem?
\((C)^2 = (A)^2 + (B)^2\)C is the hypotenuse of the triangle, A is a leg of the triangle, and B is another leg of the trianglePythagoras' theorem can only be used on right trianglesSubstitute the values of the side lengths into the formula:
\((XZ)^2 = (XY)^2 + (ZY)^2\)
\((XZ)^2 = 18^2 + 24^2\)
Solve for XZ:
\((XZ)^2 = 324 + 576\)
\((XZ)^2 = 900\)
\(\sqrt{(XZ)^2} = \sqrt{900}\)
\(XZ = 30\)
∴ XZ = 30 meters
Examine the computation formula for r, the sample correlation coefficient.
In the formula for r, if we exchange the symbols x and y, do we get a different result or do we get the same (equivalent) result? Explain your answer.
a. The result is the same because the formula is dependent on the symbols.
b. The result is different because the formula is dependent on the symbols.
c. The result is the same because the formula is not dependent on the symbols.
d. The result is different because the formula is not dependent on the symbols.
c. The result is the same because the formula is not dependent on the symbols.
The sample correlation coefficient (r) measures the strength and direction of the linear relationship between two variables, x and y. The formula for r is:
r = [ Σ(xy) - n(¯x)(¯y) ] / [ √(Σ(x²) - n(¯x)²) * √(Σ(y²) - n(¯y)²) ]
If we exchange the symbols x and y, the formula remains the same because it calculates the correlation based on the product of deviations, which is symmetric in nature. Exchanging x and y will not alter the correlation value, as the formula itself is not dependent on the specific symbols used. In the computation formula for the sample correlation coefficient, the symbols x and y represent the two variables being analyzed. The formula calculates the correlation between these two variables based on their individual data points.
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what does the highest point on a bell-shaped curve represent?
The highest point on a bell-shaped curve represents the peak or maximum value of the distribution. This point is known as the mode of the distribution.
In a bell-shaped curve, also known as a normal distribution or Gaussian distribution, the data is symmetrically distributed around the mean. The curve is characterized by a central peak, and the highest point on this peak corresponds to the mode.
The mode represents the most frequently occurring value or the value that has the highest frequency in the dataset. It is the point of highest density in the distribution.
The bell-shaped curve is often used to model naturally occurring phenomena and is widely applied in statistics and probability theory. The mode provides information about the most common or typical value in the dataset and is useful for understanding the central tendency of the distribution.
While the mean and median also have significance in a normal distribution, the highest point on the bell-shaped curve specifically represents the mode, indicating the value with the highest occurrence in the dataset.
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!help!
what is the common factor for the two fractional terms 5/8x and 11/8xy?
The terms can be writen as (5) (1/8) (x) and (11) (1/8) (x) (y)
○ 5
○ 1/8x
○ 5/8
○ y
The common factor of given terms is x/8, which is given in option B.
What is factor?A factor is a number that divides another number, leaving no remainder.
Here, given terms are:
\(\frac{5}{8}x\) and \(\frac{11}{8} x\)
Now, factors of 5x/8 = 5 X 1/8 X (x)
factors of 11x/8 = 11 X 1/8 X (x)
So, common factors are 1/8 and x
Thus, the common factor of given terms is x/8, which is given in option B.
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Find the length of the segment indicated below
The calculated value of the side length in the triangle is 144
How to find the length of the indicated segmentFrom the question, we have the following parameters that can be used in our computation:
The simiar triangles
Using the theorem of corresponding sides, we hav
GH = 2JK
So, we have
10x - 36 = 2 * 4x
Multiply
So, we have
10x - 36 = 8x
Evaluate
2x = 36
So, we have
x = 18
This means that
GK = 4 * 18
GK = 144
Hence, the indicated side length in the triangle is 144
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A histogram of the sale price of (a subset of) homes in Ames, and a scatterplot of first floor area vs. sale price of the same homes are given below. 400 300 6e+05 200 4e+05 count Sale Price (dollars) 100 - 2e+05 Oe+00 - Oe+00 2e+05 8e+C 1000 3000 4e+05 6e+05 Sale Price (dollars) 2000 First Floor Area (sq. feet) (a) Describe the shape of the histogram of sale price of houses. (Where are the majority of sale prices located? Where are the minority of sale prices located?) (b) Are exponential, normal, or gamma distributions reasonable as the population distribution for the sale price of homes? Justify your answer. (c) Describe the relationship between first floor sq footage and sale price. (What happens to price as the area increases? What happens to the variability as area increases?)
The histogram of the sale price of houses appears to be skewed to the right, indicating that the majority of sale prices are located on the lower end of the price range. The majority of sale prices seem to be located between $100,000 and $400,000, with very few sale prices above $600,000.
An exponential distribution would not be a reasonable fit for the sale price of homes because it assumes a continuous variable with a constant rate of change. The sale price of homes is not a continuous variable, as it is determined by factors such as location, condition, and size. A normal distribution could potentially be a reasonable fit if the data was centered around a mean and did not have any significant outliers. However, as the histogram shows a skewed distribution, a gamma distribution may be a more appropriate fit as it allows for skewness in the data.
The scatterplot of first floor area vs. sale price shows a positive relationship between the two variables. As the first floor area increases, the sale price tends to increase as well. However, there appears to be a lot of variability in the sale price as the area increases. This suggests that other factors may be influencing the sale price of homes, in addition to the size of the first floor area.
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HELP PLSSS (LOOK AT THE PICTURE)
Answer:
Step-by-step explanation:
1. Get the amount of rocks in tons that the company used in the second month. To do this, you must subtract the amount they used in the first month by the total amount used.
Rocks used in first month: 3 1/2 tons
Total amount used : 7 1/4 tons
7 1/4 tons - 3 1/2 tons
To subtract, convert into improper fractions
((7*4)+1)/4 tons - ((3*2)+1)/2 tons
29/4 tons - 7/2 tons
then convert the denominator into the same number. To do this just multiply 2/2 onto the second fraction
7/2 * 2/2 = 14/4
subtract
29/4 - 14/4 = 15/4 tons used on the second project.
2. Now that we know that 15/4 or 3 3/4 tons where used on the second month we just simply divide by the 5 projects that used the same amount of rocks.
To divide, we can just multiply 5 to the denominator of our improper fraction
15/4 * 1/5 = 15/20
Then we simplify
3/4 tons of rock were used for each project.
IF |X+5| = 14, THEN X =? PLEASE HURRY DUE BY 11:00
Answer:
x=9,−19
hope this is fast enough
Answer:
I think X=9
Hope this helps :)
monique and tara each make an ice-cream sundae. monique gets 3 scoops of cherry ice-cream and 1 scoop of mint chocolate chunk ice-cream for a total of 84g of fat. tara has 1 scoop of cherry and 3 scoops of mint chocolate chunk for a total of 60g of fat. how many grams of fat does 1 scoop of each type of ice cream have?
The amount of fat in Cherry ice-cream is 24 grams.
The amount of fat in the Mint Chocolate Chunk ice-cream is 12 grams.
Writing data into equations using Algebra,3C + M = 84...(1)C + 3M = 60...(2)
Multiplying equation (2) by 3 and then subtracting equation (1) from
the result gives, 3 * (C +3M) = 3 × 603C + 9M = 180...(3)(3C + 9M = 180) - (3C + M = 84) = 8M =96M= 12
The amount of fat in the Mint Chocolate Chunk ice-cream, M = 12
grams C + 12*3 = 60C = 60-36 = 24
The amount of fat in Cherry ice-cream C = 24 grams As a result, Cherry ice cream contains 24 grams of fat and Mint Chocolate Chunk ice cream contains 12 grams of fat.
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How many cg are in g?
Answer:
there are 100 centigrams in a gram
Step-by-step explanation:
What is the general solution to the trigonometric equation? −3√cscθ=2 Drag the solutions to the box to correctly complete the table.
The general solution to the trigonometric equation −√3cscθ =2 is ,
θ = 2nπ ± 4π/3, where n is a whole number.
The given trigonometric function is
−√3cscθ =2
Since we know that
The values of all trigonometric functions depending on the ratio of sides of a right-angled triangle are defined as trigonometric ratios.
The trigonometric ratios of any acute angle are the ratios of the sides of a right-angled triangle with respect to that acute angle.
The right triangle has three sides:
hypotenuse
Perpendicular
Base
The right triangle has three sides:
Now we we can write it as
⇒ cscθ = -2/√3
Now we also know that
⇒ cscθ = csc(4π/3)
Take cosec inverse both sides we get
⇒ θ = 2nπ ± 4π/3
Thus, this is the general solution of the given trigonometric function.
Where n is a whole number.
The table for this is attached below.
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The image below showcases a right triangle .
My questions:
What is a c, what does that represent
What is this problem asking for me
How do I solve this problem? Are there any formulas in place?
The perimeter of triangle is 66.24 units.
What is triangle?
In Euclidean geometry, any 3 points, once non-collinear, verify a unique triangle and at the same time, a unique plane
Main body:
according to question :
c = 28
let the vertices be A,B,C
∠A= 30°
by using trigonometric ratios,
BC/ AB = sin30°
AB = C = 28
BC/28 = sin30°
BC = 28*sin30°
BC= 28*(1/2)
BC = 14
similarly
AB /CA = cos 30°
28/CA = √3/2
CA = 28*√3/2
CA = 14/√3
CA = 24.24
Hence , perimeter = AB +BC +CA = 28+14+24.24
=66.24 units
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The Little Twelve Football Conference has two
divisions, with ten teams in each division. Each team
plays each of the other teams in its own division twice
and every team in the other division once. How many
conference games are scheduled?
The number of conference games scheduled is 280.
What is a combination?A combination is a selection of all or a portion of a group of items, regardless of the sequence in which the items are chosen.
Given:
The Little Twelve Football Conference has two divisions,
with ten teams in each division.
Each team plays each of the other teams in its own division twice, and every team in the other division once.
The number of conference games scheduled,
= ¹⁰C₂ x 2 + 10 x 10
= 90 x 2 + 100
= 280 games.
Therefore, 280 games are scheduled.
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Show that the line integral -(1,-1) + + re") dy (0,0) is independent of the path in the entire r, y plane, then calculate the value of the line integral.
The line integral is independent of the path in the entire r, y plane and the value of the line integral is -2.
To show that the line integral is independent of the path in the entire r, y plane, we need to evaluate the line integral along two different paths and show that the results are the same.
Let's consider two different paths: Path 1 and Path 2.
Path 1:
Parameterize Path 1 as r(t) = t i + t^2 j, where t ranges from 0 to 1.
Path 2:
Parameterize Path 2 as r(t) = t^2 i + t j, where t ranges from 0 to 1.
Now, calculate the line integral along Path 1:
∫ F · dr = ∫ -(1, -1) · (r'(t) dt
= ∫ -(1, -1) · (i + 2t j) dt
= ∫ -(1 - 2t) dt
= -t + t^2 from 0 to 1
= 1 - 1
= 0
Next, calculate the line integral along Path 2:
∫ F · dr = ∫ -(1, -1) · (r'(t) dt
= ∫ -(1, -1) · (2t i + j) dt
= ∫ -(2t + 1) dt
= -t^2 - t from 0 to 1
= -(1^2 + 1) - (0^2 + 0)
= -2
Since the line integral evaluates to 0 along Path 1 and -2 along Path 2, we can conclude that the line integral is independent of the path in the entire r, y plane.
Now, let's calculate the value of the line integral.
Since it is independent of the path, we can choose any convenient path to evaluate it.
Let's choose a straight-line path from (0,0) to (1,1).
Parameterize this path as r(t) = ti + tj, where t ranges from 0 to 1.
Now, calculate the line integral along this path:
∫ F · dr = ∫ -(1, -1) · (r'(t) dt
= ∫ -(1, -1) · (i + j) dt
= ∫ -2 dt
= -2t from 0 to 1
= -2(1) - (-2(0))
= -2
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What is an advantage of using a stem-and-leaf plot instead of a histogram? What is a disadvantage? O A. Stem-and-leaf plots show data clusters where histograms do not O B. Stem-and-leaf plots contain original data values where histograms do not. O C. Stem-and-leaf plots.easily organize data of all sizes where histograms do not O D. Stem-and-leaf plots graph qualitative data where histograms do not.
Stem-and-leaf plots contain original data values where histograms do not. Therefore, option B is the correct answer.
What is stem and leaf?The "stem" values are listed down, and the "leaf" values go right (or left) from the stem values.
The "stem" is used to group the scores and each "leaf" shows the individual scores within each group.
The advantage of a stem leaf diagram is it gives a concise representation of data. The advantage of a frequency histogram is, that it is visually strong. Histograms are usually preferable to stem and leaf diagrams in large data sets. The disadvantage of a stem leaf diagram is not visual.
Therefore, option B is the correct answer.
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What’s this?i don’t know please tell me?
Answer:
Fractions in roman numerals
Step-by-step explanation:
To work this out go to hogwards and ask Harry
Answer:
٠ You must know Arabic numerals to solve this:
• Follow this interpretation:
Arabic → English
١ → 1 ٢ → 2 ٣ → 3 ٤ → 4 ٥ → 5 ٦ → 6 ٧ → 7 ٨ → 8 ٩ → 9 ٠ → 0• So, let's first interprete, solve then we reverse :
\({ \rm{ - 1 \frac{13}{15} + 2 \frac{1}{17} - 3 \frac{2}{19} }} \\ \\ = { \rm{ - \frac{28}{15} + \frac{35}{17} - \frac{59}{19} }} \\ \\ \approx { \rm{ - 3}}\)
Answer: -٣
I’m not sure I need help
Answer:
D) \(1 < x\leq 4\)
Step-by-step explanation:
1 is not included, but 4 is included, so we can say \(1 < x\leq 4\)
a college team plays ten football games during the season and how many ways can the season and with five wins for
The number of ways that the college team can end the season with five wins in ten football games can be calculated using the combination formula.
The formula for a combination is as follows: `C(n,r) = n! / r!(n-r)!` where n is the total number of games played in a season, and r is the number of games won by the team.
The symbol ! is a factorial notation, meaning that the product of all the positive integers up to that number is multiplied. In other words, 5! is equal to 5 x 4 x 3 x 2 x 1, which equals 120.
In this way, the combination formula can be calculated as: C(10,5) = 10! / 5!(10-5)! = (10 x 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) / ((5 x 4 x 3 x 2 x 1) x (5 x 4 x 3 x 2 x 1))= (10 x 9 x 8 x 7 x 6) / (5 x 4 x 3 x 2 x 1) = 252. Therefore, there are 252 ways in which the college team can end the season with five wins in ten football games.
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