Evaluate the Expression (y+2)2 when y = -4

Answer: There are different ways to approach this problem, but one possible method is:

First, we need to know how many minutes there are in a year. Since a year has 365 days (or 366 days in a leap year), we can multiply this by the number of minutes per day:

365 days/year × 24 hours/day × 60 minutes/hour = 525,600 minutes/year (non-leap year)

Next, we can use the given average heart rate of 1 × 10^2 beats per minute to calculate the total number of heart beats in a year:

1 × 10^2 beats/minute × 525,600 minutes/year = 52,560,000 beats/year

Therefore, Kenny's heart beats about 52,560,000 times in a non-leap year if his average heart rate is 1 × 10^2 beats per minute.

Answer:

See explanation below

Step-by-step explanation:

Total number = (Rate)(time)

---------------------------------------

t = cd

t = qh

t = wm

Answer:

26,987.5

Step-by-step explanation:

hope it's helpful to you ☺️

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Answer:

The answer is

26987.5

Hope this helps you

Sin(α)=opposite leg/hypotenuse

Sin(63°)=ya/35

ya=35xSin(63°)

ya=31.2

Area(a)= (15.9x31.2)/2

Area(a)=248.0

Now, we proceed to find the area of "b". We already have the length x=15.9, so:  

Tan(α)=opposite leg/adjacent leg

yb=15.90xTan(42°)

yb=14.3

Area(b)=15.9X14.3/2

Area(b)=113.7

The total Area (At) is:  

At=Area(a)+Area(b)

At=248.0+113.7

At=361.7

10) Triangle "a":

-Adjacent leg of the triangle "a":

Cos(α)=adjacent leg/hypotenuse  

Cos(30°)=xa/48

xa=48xCos(30°)  

xa=41.6

-Opposite leg of the triangle "a":

Sin(α)=opposite leg/hypotenuse

Sin(30°)=y/48

y=48xSin(30°)

y=24.0

-Area of the triangle "a":

Area(a)=41.6x24.0/2

Area(a)=499.2

Triangle "b":

-We have the value of i(y=24).

-Adjacent leg of the triangle "b":

Tan(α)=opposite leg/adjacent leg

Tan(45°)=24/xb

xb=24/Tan(45°)

xb=24

-Area of the triangle "b":

Area(b)= 24x24/2

Area(b)=288

-Total area of the triangle (At) is:

At=Area(a)+Area(b)

At=499.2+288

At=787.2

11) To find the area of the triangle shown in this exercise, we have to apply the same procedure as in exercise 10:

-Adjacent leg of the triangle "a":

Cos(α) = adjacent leg/hypotenuse  

Cos(56°)=xa/14

xa=14xCos(56°)

xa=7.8

-Opposite leg of the triangle "a":

Sin(α)=opposite leg/hypotenuse

Sin(56°)=y/14

y=14xSin(56°)

y=11.6

-Area of the triangle "a":

Area(a)=7.8x11.6/2

Area(a)=45.2

Triangle "b":

-The value of its opposite leg is y=11.6.

-Adjacent leg of the triangle "b":

Tan(α)=opposite leg/adjacent leg

Tan(46°)=11.6/xb

xb=11.6/Tan(46°)

xb=11.2

-Area of the triangle "b":

Area(b)= 11.6x11.2/2

Area(b)=65.0

-Total area of the triangle (At) is:

At=Area(a)+Area(b)

At=45.2+65.0

At=110.2

12)-Adjacent leg of the triangle "a":

Cos(α)=adjacent leg/hypotenuse  

Cos(54°)=xa/13

xa=13xCos(54°)

xa=7.6

-Opposite leg of the triangle "a":

Sin(α)=opposite leg/hypotenuse

Sin(54°)=y/13

y=13xSin(54°)

y=10.5

-Area of the triangle "a":

Area(a)=7.6x10.5/2

Area(a)=39.9

Triangle "b":

-Adjacent leg of the triangle "b":

Tan(α)=opposite leg/adjacent leg

Tan(42°)=7.6/xb

xb=7.6/Tan(42°)

xb=8.4

-Area of the triangle "b":

Area(b)=7.6x8.4/2

Area(b)=31.9

-Total area of the triangle (At) is:

At=Area(a)+Area(b)

At=39.9+31.9

At=71.8First, it is important to remember that the formula to calculate the area of a triangle is: A=bxh/2

As we can see in the exercises, all the triangles are divided in two triangles. So, let's call "a" to the triangle on the left and "b" to the triangle on the right.

9)To find the area of the triangle "a", we need the lenght of the adjacent leg (x) and the opposite leg (ya):

Cos(α)=adjacent leg/hypotenuse  

Cos(63°)=x/35

x=35xCos(63°)

x=15.9

Sin(α)=opposite leg/hypotenuse

Sin(63°)=ya/35

ya=35xSin(63°)

ya=31.2

Area(a)= (15.9x31.2)/2

Area(a)=248.0

Now, we proceed to find the area of "b". We already have the length x=15.9, so:  

Tan(α)=opposite leg/adjacent leg

yb=15.90xTan(42°)

yb=14.3

Area(b)=15.9X14.3/2

Area(b)=113.7

The total Area (At) is:  

At=Area(a)+Area(b)

At=248.0+113.7

At=361.7

10) Triangle "a":

-Adjacent leg of the triangle "a":

Cos(α)=adjacent leg/hypotenuse  

Cos(30°)=xa/48

xa=48xCos(30°)  

xa=41.6

-Opposite leg of the triangle "a":

Sin(α)=opposite leg/hypotenuse

Sin(30°)=y/48

y=48xSin(30°)

y=24.0

-Area of the triangle "a":

Area(a)=41.6x24.0/2

Area(a)=499.2

Triangle "b":

-We have the value of i(y=24).

-Adjacent leg of the triangle "b":

Tan(α)=opposite leg/adjacent leg

Tan(45°)=24/xb

xb=24/Tan(45°)

xb=24

-Area of the triangle "b":

Area(b)= 24x24/2

Area(b)=288

-Total area of the triangle (At) is:

At=Area(a)+Area(b)

At=499.2+288

At=787.2

11) To find the area of the triangle shown in this exercise, we have to apply the same procedure as in exercise 10:

-Adjacent leg of the triangle "a":

Cos(α) = adjacent leg/hypotenuse  

Cos(56°)=xa/14

xa=14xCos(56°)

xa=7.8

-Opposite leg of the triangle "a":

Sin(α)=opposite leg/hypotenuse

Sin(56°)=y/14

y=14xSin(56°)

y=11.6

-Area of the triangle "a":

Area(a)=7.8x11.6/2

Area(a)=45.2

Triangle "b":

-The value of its opposite leg is y=11.6.

-Adjacent leg of the triangle "b":

Tan(α)=opposite leg/adjacent leg

Tan(46°)=11.6/xb

xb=11.6/Tan(46°)

xb=11.2

-Area of the triangle "b":

Area(b)= 11.6x11.2/2

Area(b)=65.0

-Total area of the triangle (At) is:

At=Area(a)+Area(b)

At=45.2+65.0

At=110.2

12)-Adjacent leg of the triangle "a":

Cos(α)=adjacent leg/hypotenuse  

Cos(54°)=xa/13

xa=13xCos(54°)

xa=7.6

-Opposite leg of the triangle "a":

Sin(α)=opposite leg/hypotenuse

Sin(54°)=y/13

y=13xSin(54°)

y=10.5

-Area of the triangle "a":

Area(a)=7.6x10.5/2

Area(a)=39.9

Triangle "b":

-Adjacent leg of the triangle "b":

Tan(α)=opposite leg/adjacent leg

Tan(42°)=7.6/xb

xb=7.6/Tan(42°)

xb=8.4

-Area of the triangle "b":

Area(b)=7.6x8.4/2

Area(b)=31.9

-Total area of the triangle (At) is:

At=Area(a)+Area(b)

At=39.9+31.9

At=71.8

Step-by-step explanation:

Let's start solving the problem by identifying the given information: Leah's house is a mile from school. Josh's house is a mile from school. They both live in the same direction from school and on the same side of Forest Road. To find out how much farther does Leah have to walk home when she reaches Josh's house.

We need to find the distance between Josh's house and the school and then subtract the distance between Leah's house and the school. This will give us the difference, which is the amount farther Leah has to walk. Let's assume the school is located at point A on Forest Road. Leah's house is located a mile away from the school, so it is located at point B.

Josh's house is also located a mile away from the school in the same direction as Leah's house, so it is located at point C. Now, we need to find the distance between point C and point A, which is the distance between Josh's house and the school. Since both Leah's and Josh's houses are equidistant from the school, we know that the distance between point B and point A is also a mile. Therefore, the distance between point C and point A is 2 miles (1 mile from A to B + 1 mile from B to C).Now, we can find the distance Leah has to walk farther by subtracting the distance between point B and point A from the distance between point C and point A:2 miles - 1 mile = 1 mile Therefore, Leah has to walk an additional 1 mile when she reaches Josh's house to get to her own house.

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Answer: -1, 2 and 4

Step-by-step explanation:

The lengths of the diagonals are approximately 10.6 cm and 31.8 cm.

To solve this problem, we can use the formula for the area of a rhombus, which is A = (d₁ x d₂)/2, where A is the area, and d₁ and d₂ are the lengths of the diagonals.

We are given that the area of the rhombus is 168 square centimeters, so we can substitute this value into the formula:

=> 168 = (d₁ x d₂)/2.

We are also given that one diagonal is three times as long as the other, so we can express the length of one diagonal in terms of the other: d₁ = 3d₂.

Substituting this expression for d₁ into the formula for the area, we get:

168 = (3d₂xd₂)/2 336 = 3d₂²2 d₂² = 112 d₂ = √(112) = 10.6 (to the nearest tenth of a centimeter)

Using the expression for d₁ in terms of d₂, we can find the length of the other diagonal:

d₁ = 3d₂ = 3(10.6) = 31.8 (to the nearest tenth of a centimeter)

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Answer:

Answer is 3.306

Step-by-step explanation:

4/1.21 becasue its a square it is 4 divided by 1.21

You have the expression 3⁰

Take into account that any number powered to 0 is equal to 1.

Then, you have:

3⁰ = 1

Step-by-step explanation:

3x - 5 = 2x - 25

3x - 2x = -25 + 5

x = -20

The value of x from the given figure is 42°.

The given angles are (3x-5)° and (2x-25)°.

Angles in parallel lines are angles that are created when two parallel lines are intersected by another line called a transversal.

from the given figure,

y+(2x-25)°=180° (Adjacent angles adds up to 180°)

⇒ y=180°-2x+25°

⇒ y=205°-2x

Here, (3x-5)°=y (Corresponding angles are congruent)

⇒ (3x-5)°=205°-2x

⇒ 3x+2x=205+5

⇒ 5x=210

⇒ x=42°

Hence, the value of x from the given figure is 42°.

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Answer:L take goku better because of the geometric size of these

Step-by-step explanation:

Answer:

from my point of view your answer will be 1/3

Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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According to the information provided, the hypothesis test for the claim that over 50% of eligible voters favor the legalization of marijuana is a right-tailed (upper-tailed) test.

In this case, if the claim is that over 50% of eligible voters favor legalization, the alternative hypothesis would be that the proportion is greater than 50%. The null hypothesis would be that the proportion is equal to or less than 50%.

To test this claim, we would conduct a right-tailed (upper-tailed) hypothesis test. The critical region of the test would be in the right tail of the distribution, and we would be looking for evidence that the proportion is significantly greater than 50%.

Therefore, the correct answer is that the hypothesis test for the claim is right-tailed (upper-tailed).

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Answer:

let x equal the service charge.

let y equal the per hour charge.

for the job that cost 450, the equation is 450 = x + 6y

for the job that cost 330, the equation is 330 = x + 4y

these two equations needs to be solved simultaneously.

subtract the second equation from the firs to get 120 = 2y

solve for y to get y = 60.

in the first equation, replace y with 60 to get 450 = x + 6*60.

simplify to get 450 = x + 360.

subtract 360 from both sides of the equation to get 90 = x.

it appears that the service charge is equal to 90 and the per hour charge is equal to 60.

for the job that cost 450, the equation becomes 450 = 90 + 6*60 = 90 + 360 = 450.

for the job that cost 330, the equation becomes 330 = 90 + 4*60 = 90 + 240 = 330.

the numbers check out.

the service charge is 90.

the per hour charge is 60.

i believe your solution is that the electrician charges a flat fee of 90 plus an hourly fee of 60 for a service call.

Step-by-step explanation:

To find the equation of the line tangent to the function f(θ) = 2 tan (π/θ) at θ = 1, we can first find the derivative of the function using the chain rule. Then, we substitute θ = 1 into the derivative to find the slope.

The given function is f(θ) = 2 tan (π/θ). To find the slope of the tangent line at θ = 1, we need to find the derivative of the function. Using the chain rule, we differentiate f(θ) with respect to θ. The derivative of tan (π/θ) is (-π/θ²) sec² (π/θ), and multiplying by 2 gives us the derivative of f(θ) as (-2π/θ²) sec² (π/θ).

Next, we substitute θ = 1 into the derivative to find the slope of the tangent line at θ = 1. Plugging in θ = 1, we get (-2π/1²) sec² (π/1) = -2π sec²(π).

Now, we have the slope of the tangent line, which is -2π sec²(π). To find the equation of the line, we can use the point-slope form of a line, y - y₁ = m(x - x₁), where (x₁, y₁) is the point of tangency (θ = 1, f(1)), and m is the slope we found.

Substituting the values, we have y - f(1) = (-2π sec²(π))(x - 1). Simplifying and rearranging, we can express the equation of the tangent line as y = -2π sec²(π)(x - 1) + f(1).

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Answer: 9

Step-by-step explanation:

The statement is partially correct. because, If the study used volunteers who self-selected to participate, then it may not be a representative sample of the entire population with a moderate case of the disease, and therefore the results may not be generalizable to the population.

However, it is important to note that not all studies need to use random sampling in order to draw meaningful conclusions. In some cases, non-random samples may still provide valuable insights into the topic of interest.

In any case, if the study did use volunteers who self-selected to participate, it is important for the researchers to acknowledge this limitation in their conclusions and to avoid overgeneralizing the findings beyond the sample they studied.

The statement is partially correct. because, If the study used volunteers who self-selected to participate, then it may not be a representative sample of the entire population with a moderate case of the disease, and therefore the results may not be generalizable to the population.

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A function is a mathematical relationship between the domain and the range, two sets of values. The range is the set of output values that the function produces, and the domain is the set of input values for which it is defined.

What is a function, exactly?

a mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable).

Consider the function f(x) = x^2 as an illustration. This function generates the value f from the supplied value x. (x). This function will return the value 9 if the given value is 3, since 3^2 = 9.

Generally speaking, a function describes the relationship between two sets of values (the domain) (the range). For instance, the relationship between the input value x and the output value f(x) is described by the function f(x) = x^2.

A formula, which is a guide that explains how to calculate the output value for a specific input value, is typically used to express a function. For instance, the function f(x) = x^2 has the formula f(x) = x^2. We just enter the input value into the formula and simplify to determine the output value for a particular input value.

A fundamental idea in mathematics, functions are used to model and describe a wide variety of real-world occurrences. For instance, the quadratic function f(x) = x^2 + 2x + 1 can be used to simulate how an item would move in the presence of gravity. A population's expansion over time can be predicted using the exponential function f(x) = 3^x.

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Answer:

9144

Step-by-step explanation:

2 x 1016 = 2032

7 x 1016 = 7112

2031 + 7112 = 9144

Answer:

9144

Step-by-step explanation:

usa una calculadora

Answer:

1/3

Step-by-step explanation:

Hope This Helps!

the answer for the equation is 0

Adjust the parameters as needed, such as the step size (h) and the final x-value (xn), and run the code to obtain the solution for y(x).

The resulting plot will show the solution curve.

To solve the given set of differential equations using the Runge-Kutta method in MATLAB, we need to convert the second-order differential equations into a system of first-order differential equations.

Let's define new variables:

y = y(x)

z = dz/dx

Now, we have the following system of first-order differential equations:

dy/dx = z (1)

dz/dx = -k/(2y) (2)

To apply the Runge-Kutta method, we need to discretize the domain of x. Let's assume a step size h for the discretization. We'll start at x = 0 and proceed until x = infinite.

The general formula for the fourth-order Runge-Kutta method is as follows:

k₁ = h f(xn, yn, zn)

k₂ = h f(xn + h/2, yn + k₁/2, zn + l₁/2)

k₃ = h f(xn + h/2, yn + k₂/2, zn + l₂/2)

k₄ = h f(xn + h, yn + k₃, zn + l₃)

yn+1 = yn + (k₁ + 2k₂ + 2k₃ + k₄)/6

zn+1 = zn + (l₁ + 2l₂ + 2l₃ + l₄)/6

where f(x, y, z) represents the right-hand side of equations (1) and (2).

We can now write the MATLAB code to solve the differential equations using the Runge-Kutta method:

function [x, y, z] = rungeKuttaMethod()

   % Parameters

   k = 1;              % Constant k

   h = 0.01;           % Step size

   x0 = 0;             % Initial x

   xn = 10;            % Final x (adjust as needed)

   n = (xn - x0) / h;  % Number of steps

   % Initialize arrays

   x = zeros(1, n+1);

   y = zeros(1, n+1);

   z = zeros(1, n+1);

   % Initial conditions

   x(1) = x0;

   y(1) = 0;

   z(1) = 0;

   % Runge-Kutta method

   for i = 1:n

       k1 = h * f(x(i), y(i), z(i));

       l1 = h * g(x(i), y(i));

       k2 = h * f(x(i) + h/2, y(i) + k1/2, z(i) + l1/2);

       l2 = h * g(x(i) + h/2, y(i) + k1/2);

       k3 = h * f(x(i) + h/2, y(i) + k2/2, z(i) + l2/2);

       l3 = h * g(x(i) + h/2, y(i) + k2/2);

       k4 = h * f(x(i) + h, y(i) + k3, z(i) + l3);

       l4 = h * g(x(i) + h, y(i) + k3);

       y(i+1) = y(i) + (k1 + 2*k2 + 2*k3 + k4) / 6;

       z(i+1) = z(i) + (l1 + 2*l2 + 2*l3 + l4) / 6;

       x(i+1) = x(i) + h;

   end

   % Plotting

   plot(x, y);

   xlabel('x');

   ylabel('y');

   title('Solution y(x)');

end

function dydx = f(x, y, z)

   dydx = z;

end

function dzdx = g(x, y)

   dzdx = -k / (2*y);

end

% Call the function to solve the differential equations

[x, y, z] = rungeKuttaMethod();

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Given in the question:

a.)

Answer:

$26750

Step-by-step explanation:

1/5 * (total salary) = 5350

So, 5*5350 = total salary = 26750

If Rachana randomly selects two mugs from the set, the probability that she gets two different mugs is 0.1556 or 15.56%.

To solve this problem, we can use the concept of combinations. Since there are 10 mugs in the set, there are 10 choose 2 = 45 ways to select two mugs without considering order.

Out of these 45 ways, we need to count the number of ways Rachana can select two different mugs. Since there are 3 different types of mugs, Rachana can choose any one of the three types for the first mug. There are 10 mugs in the set, out of which 3 belong to the chosen type. Therefore, the probability of choosing a mug of the chosen type is 3/10.

For the second mug, Rachana can choose from the remaining 9 mugs. Since she needs to choose a different type of mug, she can choose any one of the 2 remaining types. There are 7 mugs left from the other 2 types. Therefore, the probability of choosing a mug of a different type is (7/9) * 2/3 = 14/27.

Therefore, the probability of selecting two different mugs is the product of the probabilities of selecting a mug of the chosen type and a mug of a different type. This is given by (3/10) * (14/27) = 7/45, which is approximately 0.1556 or 15.56%.

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Complete question is:

Rachana has a set of ten mugs the set up is made of 3 different mugs. If Rachana randomly selects two mugs from the set, what is the probability that she gets two different mugs?