eastside middle school has 75% student participation in the fall carnival determine which of the simulations below could model the probability of a student participating

Answer:

the answer isn't there; the answer is 2.5

Step-by-step explanation:

Answer:

Pool K cost equation : 30 + 5V , Pool M cost equation : 10 + 10V

Pool K slope & intercept  = 30 & 5 , Pool M slope & intercept = 10 & 10

Step-by-step explanation:

Total cost  [Pool] = Fixed (membership) cost + Variable cost (per visit)

Intercept is part at which equation line intersects x or y axis. In pools case, it is  fixed (membership) cost. Slope is change in y due to change in x. In pools case, it is variable cost (per visit)

Pool K cost equation : 30 + 5V , Pool M cost equation : 10 + 10V

where V = number of visits.

Pool K slope & intercept  = 30 & 5 , Pool M slope & intercept = 10 & 10

Answer:

11

Step-by-step explanation:

4d=44

4d/4=44/4

d=11

the cost is 11$ per dress

Answer:

The correct answer is C \(3\frac{8}{33}\)

Solution by separating the parts:

\(3\frac{8}{33}\) = 3 + \(\frac{8}{33}\)

We know that \(\frac{8}{33}\) is 8 ÷ 33.

Therefore: \(3\frac{8}{33}=\) 3 + (8 ÷ 33)

You then would have to use "Long Division" for 8 divided by 33

= 3 + 0.242 = 3.242424242424...

Hence giving you 3.24 repeated which is C

P.S. the quiz either looks like a PVS exam form, or a virtual school exam/quiz, I'm able to work and help with any other further questions.

99.7% of the students scored between (44.67 , 56.33) i.e.

between 44 and 56.

On Subtracting 1 from your sample size, we get

100 – 1 = 99.

On Subtracting confidence level from 1, and then divide by two.

(1 – .997) / 2 = 0.0015

Now, df = 99 and α = 0.0015

from the table at df = 99 we got 2.262.

Divide your sample standard deviation by the square root of your sample size.

28 / √(100) = 2.8

Now, 2.262 × 2.8 = 6.33

So, the confidence interval be,

(100 - 6.33 , 100 + 6.33) = (44.67 , 56.33)

Hence, 99.7% of the students scored between (44.67 , 56.33) i.e.

between 44 and 56.

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Answer:

an = 4n + 3

Step-by-step explanation:

Answer:

James works on history 6/10 more that English.

Step-by-step explanation:

Since he worked on History for 9/10 of an hour, and worked on English for 3/10 of an hour. He would be working on history 6/10 more than English.

9/10-3/10=6/10.

6/10=3/5

Answer:

James works on history 6/10 of an hour more than on English.

Step-by-step explanation:

This is because 9/10 - 3/10 = 6/10

Expressions 2(-3)(7), -2(27 ÷ 9), and (4 - 10) - (8 ÷ (-2)) all have negative values.

The expressions that have negative values are:

1. 2(-3)(7)
2. -2(27 ÷ 9)
3. (4 - 10) - (8 ÷ (-2))

Let's break down each expression to understand why they have negative values.

1. 2(-3)(7):

  - First, we multiply -3 and 7, which gives us -21.
  - Then, we multiply 2 and -21, which gives us -42.
  - Therefore, the expression 2(-3)(7) has a negative value of -42.

2. -2(27 ÷ 9):

  - We start by calculating 27 ÷ 9, which equals 3.
  - Then, we multiply -2 and 3, which gives us -6.
  - Hence, the expression -2(27 ÷ 9) has a negative value of -6.

3. (4 - 10) - (8 ÷ (-2)):

  - Inside the parentheses, we have 4 - 10, which equals -6.
  - Next, we have 8 ÷ (-2), which equals -4.
  - Finally, we subtract -4 from -6, which gives us -6 - (-4) = -6 + 4 = -2.
  - Thus, the expression (4 - 10) - (8 ÷ (-2)) has a negative value of -2.

To summarize, the expressions 2(-3)(7), -2(27 ÷ 9), and (4 - 10) - (8 ÷ (-2)) all have negative values.

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Answer:

The measure of the angle is 34 deg.

Step-by-step explanation:

Let the angle measure = x

"the supplement of an angle is twenty-four degrees less than five times the angle"

The supplement's measure is 5x - 24

The measures of supplementary angles is 180 deg.

x + 5x - 24 = 180

6x - 24 = 180

6x = 204

x = 34

Answer: The measure of the angle is 34 deg.

Answer:

Step-by-step explanation:

How to Use the Equivalent Expression Calculator?

The procedure to use the equivalent expression calculator is as follows:

Step 1: Enter an algebraic expression in the input field

Step 2: Now click the button “Submit” to get the equivalent expression

Step 3: Finally, the equivalent expression for the given algebraic expression will be displayed in a new window.

What is an Algebraic Expression?

An algebraic expression is an expression that consists of variables, coefficients, constants, and mathematical operators such as addition, subtraction, multiplication, and division. Generally, if two things are the same, then it is called equivalent. Similarly, in mathematics, the equivalent expressions are the expressions that are the same, even though the expression looks different. But if the values are plugged into the expression, both expressions give the same result.

Example

Question:

Write the equivalent expression for the given expression: 3x+9

Solution:

Given expression: 3x+9

Take 3 outside from the expression, and we get,

= 3(x+3), which is called the equivalent expression

5 meters/ 1 second because if you 40 and 8 you will get 5 and divided 8 by 8 and you get 1, you just divide the denominator by both numerator and denominator.

Answer:

5

Step-by-step explanation:

distance over time you divide

Answer:

1 and 0

Step-by-step explanation:

Zero is an integer

1) The amplitude c+ is c+l

2) The expectation value is 0

3) The uncertainty ΔSX is √(3/7) c+.

Now, we know that any wave function can be written as a linear combination of two spin states (up and down), which can be written as:

Ψ = c+ |+> + c- |->

where c+ and c- are complex constants, and |+> and |-> are the two orthogonal spin states such that Sx|+> = +1/2|+> and Sx|-> = -1/2|->.

Hence, we can write the given wave function as:Ψ = c+|+> + i/√7|->

Now, we know that the given wave function has been defined in Sx basis, and not in the basis of |+> and |->.

Therefore, we need to write |+> and |-> in terms of |l> and |r> (where |l> and |r> are two orthogonal spin states such that Sy|l> = i/2|l> and Sy|r> = -i/2|r>).

Now, |+> can be written as:|+> = 1/√2(|l> + |r>)

Similarly, |-> can be written as:|-> = 1/√2(|l> - |r>)

Therefore, the given wave function can be written as:Ψ = (c+/√2)(|l> + |r>) + i/(√7√2)(|l> - |r>)

Therefore, we can write:c+|l> + i/(√7)|r> = (c+/√2)|+> + i/(√7√2)|->

Comparing the coefficients of |+> and |-> on both sides of the above equation, we get:

c+/√2 = c+l/√2 + i/(√7√2)

Therefore, c+ = c+l

The amplitude c+ is a real number and is equal to c+l

The expectation value of the operator Sx is given by: = <Ψ|Sx|Ψ>

Now, Sx|l> = 1/2|r> and Sx|r> = -1/2|l>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= -i/√7(c+l*) + i/√7(c+l)= 2i/√7 Im(c+)

As c+ is a real number, Im(c+) = 0

Therefore, = 0

The uncertainty ΔSX in the state |Ψ> is given by:

ΔSX = √( - 2)

where = <Ψ|Sx2|Ψ>and2 = (<Ψ|Sx|Ψ>)2

Now, Sx2|l> = 1/4|l> and Sx2|r> = 1/4|r>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= 1/4(c+l* + c+l) + 1/4(c+l + c+l*) + i/(2√7)(c+l* - c+l) - i/(2√7)(c+l - c+l*)= = 1/4(c+l + c+l*)

Now,2 = (2i/√7)2= 4/7ΔSX = √( - 2)= √(1/4(c+l + c+l*) - 4/7)= √(3/14(c+l + c+l*))= √(3/14 * 2c+)= √(3/7) c+

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Answer:  -2x + 5y = 8

Step-by-step explanation:

Since the lines must be parallel, the slopes must be the same, so keep the coefficients of x and y

Substitute the values of x and y from the given coordinate  (6,4) to find the new constant, b, the y-intercept.

-2x + 5y = b

-2(6) + 5(4) = b

-12 + 20 = b

8 = b

Rewrite the original equation substituting the new b for the original -15

-2x + 5y = 8

Answer:

Step-by-step explanation:

Slope - intercept form

Given line

Converting the equation into slope-intercept form

Parallel lines have same slope of 2/5

Using point (6, 4) lets find it's y-intercept (b)

So the line is

Answer:

57

Step-by-step explanation:

Straight line value=180

Given Value=123

Value of ∆TKL

=180-123

=57(Ans)

Answer:

57

Step-by-step explanation:

ANSWER :

The answer is A.

EXPLANATION :

From the problem, we have :

The exclusion is when the denominator is equal to 0.

So equate the denominator to 0.

Factor completely using the difference of two cubes :

So that will be :

Answer:

2x - 1 = 0, 4x^2 + 2x + 1 = 0

Step-by-step explanation:

Option A is correct on Odyssey

The equation of the line with a slope of 1/4 and a y-intercept of 11 is y = (1/4)x + 11 in slope-intercept form and x - 4y = -44 in standard form.

To write the equation of a line in slope-intercept form, we use the formula y = mx + b, where m represents the slope and b represents the y-intercept. In this case, the slope (m) is 1/4 and the y-intercept (b) is 11.

So, the equation in slope-intercept form would be y = (1/4)x + 11.

To rewrite the equation in standard form, we need to eliminate any fractions. We can do this by multiplying the entire equation by 4:

4y = x + 44.

Now, we can rearrange the terms to get the equation in standard form, which is Ax + By = C, where A, B, and C are constants. In this case, we can rewrite the equation as:

x - 4y = -44.

Thus, the equation of the line with a slope of 1/4 and a y-intercept of 11 is y = (1/4)x + 11 in slope-intercept form and x - 4y = -44 in standard form.

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Answer:

Step-by-step explanation:

We know that:

Solution:

Since the slope of the line is un-defined, the line is vertical. Please look at my graph to understand better.

Answer:

the second one.... ( 8,9 )

Step-by-step explanation:

the zero-product system is rlly easy to use....

it basically means to take each term and equal it to zero....

so for your equation it is....

( x - 9 ) ( x - 8 ) = 0

so you would write it as....

( x - 9 ) = 0

and

( x - 8 ) = 0

and then you solve them like this...

( x - 9 ) = 0

add 9 to both sides to get the variable by itself...

x= 9

( x - 8 ) = 0

add 8 to both sides to get the variable by itself....

x = 8

False. The minimum of two independent exponential random variables is not necessarily exponential.

For two independent exponential random variables X and Y, with rate parameters λ1 and λ2 respectively, the minimum of X and Y is a random variable Z with the cumulative distribution function (CDF) given by

\(F_Z(z) = 1 - e^(-(λ1+λ2)z)\).

The survival function of Z is given by

\(S_Z(z) = e^(-(λ1+λ2)z)\).

Therefore, the probability density function of Z is

\(f_Z(z) = (λ1 + λ2)e^(-(λ1+λ2)z)\).

This is not an exponential distribution because the form of the probability density function is not of the form \(f(z) = λe^(-λz)\).

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Answer:

4

Step-by-step explanation:

Answer:x=4

Step-by-step explanation:

Divide 9 by both sides

False.

The given statement "If a sample of n=5 scores has EX= 10 and EX2 = 100, then SS= 80" is a true statement.

Here is how we can prove it:

To calculate SS, we can use the formula below:

SS = \sum_{i=1}^{n}x_{i}^{2} - \frac{(\sum_{i=1}^{n}x_{i})^2}{n}

Given n = 5, EX = 10, and EX2 = 100

We know that:

EX = \frac{\sum_{i=1}^{n}x_{i}}{n}

Putting the given value of EX = 10, we can find out the value of sum of all n scores.

sum = EX \times n sum = 10 \times 5 sum = 50

Now,

we can use EX2 to find the value of sum of squares of all n scores.

EX2 = \frac{\sum_{i=1}^{n}x_{i}^{2}}{n}

Putting the given value of EX2 = 100, we can find out the value of sum of squares of all n scores.

sum of\;squares = EX2 \times n sum of\;squares = 100 \times 5

sum of\;squares = 500

Now, we can substitute the values of sum and sum of squares in the formula of SS.  

SS = \sum_{i=1}^{n}x_{i}^{2} - \frac{(\sum_{i=1}^{n}x_{i})^2}{n}

SS = 500 - \frac{50^2}{5}

SS = 500 - 500

SS = 0

Therefore, the value of SS is 0 which is not equal to 80.

Hence, the statement "If a sample of n=5 scores has EX= 10 and EX2 = 100, then SS= 80" is false.

False.

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Length of the rectangle is 41m, width of the rectangle is 41m and maximum area of the rectangle is 1681 \(m^{2}\).

Let l and w denote the length and width of the rectangle.

Its perimeter is 2(l + w) which is given 164.

∴ l + w = \(\frac{164}{2}\) = 82 ----------------  (1)

Now area A of the rectangle is given by

A = lw.

from equation (1),

A = l(82 - l)

A = 82l - \(l^{2}\)

⇒ A(l) = 82l - \(l^{2}\)--------------------- (2)

We are required to maximize A.

We know that, for Amax,

A'(l) = 0 and A''(l) < 0

equation (2)⇒

A'(l) = 0

82 - 2l = 0

         l = \(\frac{82}{2}\)

         l = 41.

Further, A''(l) = -2 < 0 ∀ l

Thus l = 41 gives Amax.

Hence the required dimension of the rectangle for maximum area are

l = 41 m

and w = 82 - l

          = 82 - 41

      w = 41 m

Therefore

A = lw = (41)(41)

A = 1681 \(m^{2}\)

Therefore the maximum area of rectangle is 1681 \(m^{2}\).

Given question is incomplete. Here I consider perimeter = 164m.

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Answer:

Assuming the number is 1/(y^(-1/4)):  y^(1/4)

Step-by-step explanation:

1/(y^(-1/4))

Bring the y^(-1/4) by subtracting it's exponent:

1*y^-(-1/4)

y^(1/4)

Fg(x) = g(x-1)*1 + g(x-2)*4 + g(x-3)*6 + g(x-4)*8 + g(x-5)*7 + g(x-6)*5 + g(x-7)*3, where g(x) is defined as follows: g(x) = 1 - |x|^2 - 2|x|³    + 10|x|²   - 16|x| + 80 if |x| ≤ 1

The given function g(x) is defined piecewise based on the absolute value of x. For |x| ≤ 1, g(x) is equal to 1 - |x|^2 - 2|x|³ + 10|x|²   - 16|x| + 80.

For 1 < |x| ≤ 2, g(x) is defined differently, and for |x| > 2, g(x) has another definition.

The function Fg(x) is defined as the sum of g(x-i) multiplied by the corresponding values in the list f=[1, 4, 6, 8, 7, 5, 3], where i ranges from 1 to 7.

This means that for each point i, the function g(x-i) is evaluated and multiplied by the corresponding value in f, and the results are summed together.

In essence, Fg(x) combines the contributions of g(x) at different shifted positions (x-i) using the values in f.

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Answer:

10.2 units

Step-by-step explanation:

Check the attachment.

Hope this helps! :D

A diagonal matrix can only be orthogonal if all of its diagonal entries are either 1 or -1.

For a matrix to be orthogonal, it must satisfy the condition that its transpose is equal to its inverse. For a diagonal matrix, the transpose is simply the matrix itself, since all off-diagonal entries are zero. Therefore, for a diagonal matrix to be orthogonal, its inverse must also be equal to itself. This means that the diagonal entries must be either 1 or -1, since those are the only values that are their own inverses. Any other diagonal entry would result in a different value when its inverse is taken, and thus the matrix would not be orthogonal. It's worth noting that not all diagonal matrices are orthogonal. For example, a diagonal matrix with all positive diagonal entries would not be orthogonal, since its inverse would have different diagonal entries. The only way for a diagonal matrix to be orthogonal is if all of its diagonal entries are either 1 or -1.

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Answer:

how many of these you got lol?

2 is same as 68 because isosceles triangle

1 is 90-68 = 22

3=2

4= 90

Answer:

\(\angle 1=22, \angle\ 2=68, \angle 3=68, \angle 4=90\)

Step-by-step explanation:

\(We\ are\ given:\\The\ quadrilateral\ is\ a\ rhombus.\\We\ know\ that,\\A\ rhombus\ is\ a\ parallelogram\ with\ all\ sides\ equal.\\As\ it\ is\ a\ parallelogram,\ the\ opposite\ sides\ are\ parallel\ too.\\Hence,\\\angle 3\ and\ \angle68\ form\ alternate\ interior\ angles\ to\ one\ pair\ of\\ opposite\ parallel\ sides\ in\ the\ rhombus,\ and\ are\ equal\ in\ measure.\\Hence,\\\angle 3=68\\\)

\(As\ we\ know\ that\ the\ diagonals\ of\ a\ rhombus\ are\ perpendicular\\ bisectors\ to\ each\ other:\\\angle 4\ forms\ a\ 90.\\Hence,\\\angle 4=90\)

\(Now,\ lets\ consider\ the\ isosceles\ triangle\ created\ by\ two\ equal\ sides\ of\\ the\ rhombus\ with\ one\ of\ its\ base\ angles\ \angle 2.\\Now,\\We\ know\ that,\\Base\ angles\ opposite\ to\ equal\ sides\ are\ equal\ too.\\Hence,\\As\ the\ two\ sides\ are\ equal,\\Base\ angles\ \angle 68\ and\ \angle 2\ are\ equal\ too.\\Hence,\\\angle 2=68\)

\(Now,\ lets\ consider\ the\ triangle\ made\ up\ of\ \angle 1\ and\ \angle 2:\\We\ know\ that,\\\angle 2=68 [Proven]\\The\ third\ angle\ is\ 90\ as\ the\ diagonals\ of\ a\ rhombus\ are\ perpendicular\\ bisectors.\\Hence,\\\angle 1+ \angle 2 +90=180 [Angle\ Sum\ Property\ Of\ A\ Triangle]\\Hence,\\\angle 1+ \angle 2=90\\\angle 1+68=90\\\angle 1=90-68\\\angle 1=22\)

\(By\ putting\ it\ all\ together\ we\ have:\\\angle 1=22, \angle\ 2=68, \angle 3=68, \angle 4=90\)