Due to the formation of hydrogen bonds, _____ is highly soluble in water. group of answer choices

The electric field is found as 5.76 * 10^-17 Volts.

Now we know that the electric field is the region in space where the influence of the charge is felt. We are told that the magnitude of the charge is about 40 e.

Reacll that;

E = Kq/r^2

K = electric constant

q = magnitude of charge

r = distance

Thus;

E = 9 * 10^9 * 40 * 1.6 * 10^-19/1^2

E = 5.76 * 10^-17 Volts

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Answer:

The gravitational force between Saturn and it's moon is 1.62 m/s ^2

Explanation:

google it

Answer:

Explanation:

C bro

Answer:

An atomic nucleus is positively charged because it is composed of protons.

Explanation:

define protons, match it up.

Answer:

mass 3.67 kg, density 600 kg/m3) is fitted

with lead (density 1.14 * 10^4 kg/m3) so that it floats in water with

0.900 of its volume submerged. Find the lead mass if the lead is fitted

to the block’s (a) top and (b) bottom.

Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

Explanation:

Answer:

C

Explanation:

So im not saying this is 100% the answer but from what i read everything else was an inference and watching bubbles form when mixing chemicals made more sense as a observation to me

The full three-dimensional strain tensor at the point

\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)

To calculate the full three-dimensional strain at the point \(p = e_1 + 2e_2 + 10e_3\), we need to find the components of the strain tensor \(\epsilon_m_n\).

The strain tensor εₘₙ can be calculated using the formula:

εₘₙ = (0.5) * (∂uₘ/∂xₙ + ∂uₙ/∂xₘ)

Given the displacement field u(x, t) with components:

u₁ = 0.1x₁x₂

u₂ = 0.1x₂ + 5

u₃ = 500

We can calculate the components of the strain tensor as follows:

\(\epsilon_1_1 = (1/2) * (\delta u_1/\delta x_1 + \delta u_1/\delta x_1)\\= (1/2) * (0.1x_2 + 0)\\= 0.05x_2\)

\(\epsilon_1_2 = (1/2) * (\delta u_1/\delta x_2 + \delta u_2/\delta x_1)\\= 0.05x_1\)

\(\epsilon _1_3 = (1/2) * (\delta u_1/∂x_3 + \delta u_3/\delta x_1)\\= (1/2) * (0 + 0)\\= 0\)

\(\epsilon_2_1 = (1/2) * (\delta u_2/\delta x_1 + \delta u_1/\delta x_2)\\= (1/2) * (0 + 0.1)\\= 0.05\)

ε₂₃ = (1/2) * (∂u₂/∂x₃ + ∂u₃/∂x₂)

= (1/2) * (0 + 0)

= 0

ε₃₁ = (1/2) * (∂u₃/∂x₁ + ∂u₁/∂x₃)

= (1/2) * (0 + 0)

= 0

ε₃₂ = (1/2) * (∂u₃/∂x₂ + ∂u₂/∂x₃)

= (1/2) * (0 + 0)

= 0

ε₃₃ = (1/2) * (∂u₃/∂x₃ + ∂u₃/∂x₃)

= (1/2) * (0 + 0)

= 0

Therefore, the full three-dimensional strain tensor at the point

\(p = e_1 + 2e_2 + 10e_3\: is\: :\\epsilon =\left[\begin{array}{ccc}0.05x_2&0.05x_1&0\\0.05&0&0\\0&0&0\end{array}\right]\)

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Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.

ANSWER:

1.757 mm

STEP-BY-STEP EXPLANATION:

The coefficient of linear expansion is given by the following formula:

Where α = coefficiente of linear expasion, ΔL = change in lenght, ΔT = change in tempetature

Solving for ΔL:

Replacing and we calculate the change in lenght:

The change in length is 1.757 mm

Answer:

p=1

Explanation:

Well me know that v=m/s

and that a=m/s^2

so

\((m/s)^{2} = (m/s^2)(x^p)\\\\(m^2/s^2)/(m/s^2)=x^p\\\\m^2s^2/ms^2=x^p\\\\(m^2/m)(s^2/s^2)=x^p\\\\m=x^p\\\\p=1\)

Note: We don't take into account 2 because it's a scalar, it doesn't have units so it doesn't add anything to the equation.

Answer:

Explanation:

The first diagram (by the left) is an endothermic reaction. In this reaction, the products are higher in energy than the reactants. Heat/Energy is absorbed in this reaction and enthalpy is positive. In second diagram (by the right) is an exothermic reaction. In this reaction, the reactants are higher in energy than the products. In this reaction, heat/energy is released.

Answer:

The mass of the apple is 0.49kg

Explanation:

Potential energy=mgh

P=mgh

6=m×1.22×10

6=12.2m

divide both sides by 12.2

m=6/12.2

m=0.49kg

The parametric equations for the line are:Hence, the vector equation and parametric equations for the line are: The vector equation for the line can be written as: Comparing the above equation with \(x = −1 3t, y = 6 − 3t, z = 3 7t\)

The vector equation and parametric equations for the line that goes through the point (0, 12, −12) and is parallel to the line x = −1 3t,

y = 6 − 3t,

z = 3 7t are as follows.

Vector equation for the line:

We know that the given line is parallel to x = −1 3t, y = 6 − 3t, z = 3 7t. Hence, the direction vector of the given line will be the same as the direction vector of x = −1 3t,

y = 6 − 3t,

z = 3 7t.

Direction vector of x = −1 3t, y = 6 − 3t, z = 3 7t is given by the following vector:

Therefore, the vector equation of the line that passes through (0, 12, −12) and is parallel to x = −1 3t, y = 6 − 3t, z = 3 7t is:

Parametric equations for the line:

The vector equation for the line can be written as:

Comparing the above equation with x = −1 3t, y = 6 − 3t, z = 3 7t,

Therefore, the parametric equations for the line are:

Hence, the vector equation and parametric equations for the line are:

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The surface of Venus emits about 58.2 times more radiation per square meter than the surface of Earth, assuming they both behave as black bodies.

Stefan's law states that the energy radiated per unit area per unit time, or the radiant emittance, of a black body is proportional to the fourth power of its absolute temperature. Mathematically, this can be written as:

E = \(σT^4\)

where E is the radiant emittance, σ is the Stefan-Boltzmann constant (\(5.67 x 10^-8 W/m^2K^4\)), and T is the absolute temperature.

Using this formula, we can calculate the ratio of the radiant emittance of Venus's surface at 730 K to that of Earth's surface at 300 K:

(\(E_venus / E_earth) = (σT_venus^4 / σT_earth^4\))

(\(E_venus / E_earth) = (T_venus / T_earth\))\(^4\)

(\(E_venus / E_earth) = (730 / 300)^4\)

(\(E_venus / E_earth) ≈ 58.2\)

Therefore, the surface of Venus emits about 58.2 times more radiation per square meter than the surface of Earth, assuming they both behave as black bodies.

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Light rays first pass through the transparent layer called the cornea and then refracted again as they pass through the transparent lens.

How do light rays flow in the eyes?

The first factor in the journey of light via the eye is the objects being seen and how they produce, reflect, or change the light in various ways.

The visual cortex of the brain's occipital lobe serves as the destination of the light pathway, which starts with photoreceptors in the retina. Rod and cone cells are two different types of photoreceptors. When it comes to eyesight in low light and in peripheral vision, rods can be especially helpful.

The cornea is where most of the refraction occurs as light enters the eye's curved, transparent front surface. The natural or crystalline lens of the eye also distorts light rays. When an item passes in front of the eye, its rays pass through the transparent cornea and enter the eye.

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Answer:

A. 4.5 x 10^-5 kg.m2

B. 108 x 10^-3 kg.m2

C. 54 x 10^-5

Explanation:

A. I = m(r^2)

point mass m = 0.005 g = 5 x 10^-6 kg

I = (5 x 10^-6 kg) x (3 m)^2 = (5 x 10^-6 kg) x 9 m^2 = 4.5 x 10^-5 kg.m2

B. I = m(r^2)

point mass m = 0.3 kg = 3 x 10^-1 kg

I = (3 x 10^-1 kg) x (0.6 m)^2 = (3 x 10^-1 kg) x 0.36 m^2 = 108 x 10^-3 kg.m2

C. KE = 1/2I(w^2)

KE = 1/2(3 x 10^-2 kg.m^2)(0.6 rad/s)^2 = 54 x 10^-5

The work done by the boy is 0 N

The work done by the girl is 72 N

The Net force is 6 N

The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.

There are various kinds of friction such as dry and fluid friction.

Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.

Work done = force * distance

The work done by the boy = 12 * 0

The work done by the boy = 0 N

The work done by the girl = 18 * 4

The work done by the girl = 72 N

Net force = 18 - 12

Net force = 6 N

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Answer:

F = 2(50 N) - (50 N) = 50 N

Explanation:

The direction of F is the direction in which the two students are pushing.

The diameter of the tube needed for the water level to rise one tube diameter due to surface tension is approximately 1/12 inch, calculated using the formula d = 2T cos(θ) / (ρgh) where T, θ, ρ, and g are given values.

The rise of the water level in the tube due to surface tension is given by the formula:

h = 2T cos(θ) / (ρgd)

where h is the rise in the water level, T is the surface tension of water, θ is the contact angle (in this case, θ = 0°), ρ is the density of water, g is the acceleration due to gravity, and d is the diameter of the tube.

We can rearrange this formula to solve for d:

d = 2T cos(θ) / (ρgh)

where we have used g = 32.2 ft/s^2 as the acceleration due to gravity and ρ = 62.4 lb/ft^3 as the density of water at 60 °F.

The surface tension of water at 60 °F is approximately T = 5.11 x 10^-2 lb/ft.

Substituting the given values into the formula for d, we get:

d = 2 * 5.11 x 10^-2 lb/ft * cos(0°) / (62.4 lb/ft^3 * 32.2 ft/s^2 * 1 ft) ≈ 0.001 ft

Therefore, the diameter of the tube needed for the water level to rise one tube diameter due to surface tension is approximately 0.001 ft or 1/12 inch.

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Answer: Friction that acts on a sliding object

Explanation:

Answer:

The answer is "26.208 km"

Explanation:

Given value:

\(\to S= 2.6 \ \frac{m}{s}\\\\\to t= 2.8 \ hours\)

Formula:

\(d= st\\\\d= 2.6 \times 2.8 \times \frac{60 \times 60}{1000}\\\\d= 26.208\ km\)

Answer: c because our solar system is called the milky way

Explanation:

The spot size at the film will depend on the size of the source and the distance between the source and the film. Without knowing the size of the source, we cannot accurately determine the spot size. However, we can use the concept of geometric optics to make a rough estimate.

If we assume that the source is a point source and that the light from the source is diverging uniformly in all directions, then we can use the thin lens equation to estimate the spot size at the film. The thin lens equation is given by:

1/f = 1/di + 1/do

where f is the focal length of the lens, di is the distance from the lens to the image plane (the film), and do is the distance from the lens to the object (the source).

If we assume that the film is the image plane and that the source is at infinity, then do is effectively infinite, and we can simplify the equation to:

1/f = 1/di

Solving for di, we get:

di = f

Therefore, the distance from the lens to the film should be equal to the focal length of the lens.

If we assume that the size of the source is small compared to the distance between the source and the film, then the spot size at the film can be approximated by the formula:

spot size = (source size) x (distance between source and film) / (distance between source and lens)

Without knowing the size of the source, we cannot determine the spot size accurately, but this formula can provide a rough estimate.

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Answer:

The answer is

Explanation:

The velocity or speed of an object can be found by using the formula

\(velocity \: = \frac{distance}{time} \)

From the question

time taken to travel = 10 hours

distance covered = 550 miles

Substitute the values into the above formula and solve for the velocity

That's

\(velocity = \frac{550}{10} \)

We have the final answer as

Hope this helps you

So, 2200 metres were travelled, and 200 metres were moved.

The athlete will be in the exact opposite posture after his motion is finished. That is, 200 m equals 200 x diameter.

Multiplying the circle's diameter by (pi) yields the circumference of the circle. Additionally, the circumference may be determined by multiplying the 2radius by pi (=3.14).

Simply draw a vector from your beginning point to your destination location, solve for the length of this line, and you can determine displacement. If your beginning and finishing positions are identical, as they are if you are running a circular 5K course, your displacement is 0. Displacement in physics is symbolised by the symbol s.

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