Draw a self-portrait using this set of instructions:
Draw 5 lines - remember the different types, implied, irregular, directional...
**Think about how a line can express emotion. What would a line conveying happiness look like? What would a line conveying anger look like? maybe you can show your mood by the type of line you create.
Draw 3 shapes - remember there are organic shapes and geometric shapes
Draw in some shading where it's needed- with a regular graphite pencil - notice how you can get light gray to a dark gray by putting different amounts of pressure, or overlapping hatches(lines)
Choose 1 color to add to your drawing that represents your mood.
*Is there any implied motion in your drawing? how can you create implied motion using lines? try to create implied motion or time passing for bonus points.
Post a photo of your final drawing here and talk about how you created it and what you were trying to convey, and respond to at least one of your classmates
Answers
To create a self-portrait using the given instructions, follow these steps: Here is an example of a self-portrait using these instructions:
Step 1: Draw 5 lines, including implied, irregular, and directional lines. These lines should express the emotion you're trying to convey. A happy line may be curved and flowing, whereas an angry line may be sharp and jagged.
Step 2: Draw 3 shapes, including organic and geometric shapes. Use these shapes to create the overall structure of your self-portrait.
Step 3: Shade your self-portrait as necessary using a regular graphite pencil. You can create different shades of gray by varying the pressure or overlapping the lines.
Step 4: Choose one color that represents your mood and add it to your self-portrait. For example, if you're feeling happy, you may want to use a bright yellow color.
Step 5: To create implied motion, use lines to show the movement. For example, if you want to show yourself running, you can use curved lines to indicate the direction of movement. You can also use overlapping lines to show the passing of time.
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Related Questions
will the particle move to the right (in the positive x -direction) or to the left (in the negative x -direction), and why?
Answers
Yes, the particle moves in the positive x-direction (to the right) or the negative x-direction (to the left) due to the forces of attraction and repulsion.
When the particle's velocity is positive, it is travelling to the right. When the velocity is negative, it also moves to the left. A body with a higher mass may have a lower moment of inertia than a body with a lower mass. This relies on the mass distribution and axis with respect to which we are computing the moment of inertia. In real-world situations, we frequently avoid dealing with particles.
The time it takes for a constant force to bring a particle to rest, on the other hand, is represented by its momentum.
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You are moving at 30 km/s with respect to the sun because the Earth ismoving. So is the chair you are sitting in. If you stood up and jumped, thechair wouldn't move out from under you because:A) The inertia of you and the chair carry both of you with the speed of the EarthB)The chair is stuck to the ground because of frictionC) You didn’t jump high enough for that speed to matterD) You have inertia that keeps you gravitationally attracted to the chair
Answers
Given that both the chair and the person are affected by Earth's movement, we can deduct that both have inertia due to Earth's speed.
Therefore, the answer is A.A 38.3 kg girl and a 59.4 kg boy are on the surface of a frozen lake, 12.5 m apart. Using a rope, the girl exerts a horizontal 4.70 N force on the boy, pulling him toward her. Calculate the magnitude of the girl's acceleration.
Answers
The magnitude of the girl's acceleration will be 0.122 m/s².It is denoted by \(\rm a_g\).
What is force?Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Force is defined as the product of mass and acceleration. Its unit is Newton.
Mass of girls, \(\rm m_g=38.3 \ kg\)
Mass of boys,\(\rm m_b=59.4 kg\)
Girl exerts a horizontal force,\(\rm F_{gb}=4.70 N\)
\(\rm F_{gb}=m_g \times a_g \\\\\ a_g=\frac{F_{gb}}{m_g} \\\\ a_g=\frac{4.70}{38.3 } \\\\ a_g= 0.122 \ m/s^2\)
Hence, the magnitude of the girl's acceleration will be 0.122 m/s².
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A yoyo can be approximated as a solid cylinder of mass m, radius R and thickness d. Two identical such yoyos have their strings tied together and are wound so that the two yoyos are touching each other. These stuck together yoyos are ejected into deep space far from any other objects. Shortly after being ejected, the center of mass of the yoyos have an initial velocity ū as indicated in the diagram. At this instant, the stuck together yoyos are rotating about the center of mass counterclockwise with an angular speed Wil. As the yoyos fly through space the strings unwind so that at some later time all of the string has unwound from each yoyo. At this time, the velocity of the center of mass is ū and the distance between the center of the yoyos is d. Determine the unknown angular velocity (magnitude and direction) of the center of mass for the tied together yoyos. You can neglect the mass of the string and you can assume that the yoyos are tied to the string so that the string is not slipping on the axle of the yoyo
Answers
Answer:
I don't understand what your asking
Explanation:
I really don't know
A lawn mower is pushed with a force of 79 N. If 11,099 J of work are done on mowing the lawn, what is the total distance the lawn mower was pushed? Round your answer to a whole number (no decimal places).
Answers
Answer:
141m
Explanation:
a cat leaps to try to catch a bird. if the cat's jump was at 60° off the ground and its initial velocity was 2.74 m/s, what is the highest point of its trajectory, neglecting air resistance?
Answers
The projectile launch relations allow to find the results for the maximum height of the jump of the cat is 0,, 287 m
The projectile launch studies the movement of the body near the earth, let's use the relationship
\(v_y^2 = v_o_y - 2 g y\)
Where v_y is the vertical velocity, v_[oy} the initial vertical velocity, g the acceleration of gravity (g = 9.8 m / s²) and t the time
They indicate that the cat jumped with an initial velocity of v₀ = 2.74 m / s and an angle of θ = 60º, let's use trigonometry to find the components of the velocity
v₀ₓ = v₀ cos 60
\(v_o_y\) = v₀ sin 60
\(v_o_y\) = 2.74 sin 60 = 2.37 m / s
In the point highest trajectory the vertical speed must be zero (v_y = 0), in the attached we can see a diagram of the speeds of the cat
0 = \(v_{oy}^2\) - 2g y
y = \(\frac{v_{oy}^2 }{2g}\)
Let's calculate
y = \(\frac{2.37^2}{2 \ 9.8 }\)
y = 0.287 m
In conclusion with the projectile launch relations we can find the results for the maximum height of the cat jump is 0,, 287 m
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What is the cause of change in properties of matter
Answers
Answer:
Chemical changes cause a substance to change into an entirely substance with a new chemical formula.
Explanation:
Chemical changes are also known as chemical reactions. The “ingredients” of a reaction are called reactants, and the end results are called products.
why is it important to calibrate the thermometer with a set of standards having a range of melting points
Answers
Calibrating a thermometer is important to ensure that the temperature readings are accurate.
By using a set of standards with a range of known melting points, the thermometer can be calibrated against known temperatures to ensure it is providing accurate readings.
This ensures that when the thermometer is used in experiments or other applications, the measurements taken are reliable and can be trusted. Calibration also allows any potential errors in the thermometer readings to be identified and corrected.
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Another child is on a swing next to the first. This child has a mass of 48 kg and a maximum kinetic energy of 3800 J. What is the velocity of this child?
Answers
Answer:12.583m/s
Explanation:
\(KE=\frac{1}{2}mv^{2}\)
\(3800=\frac{1}{2}(48)v^{2}\)
\(\frac{3800}{24}=v^{2}\)
\(\sqrt{158.33} = v\\12.583m/s=v\)
Two cars are traveling towards one another. The VW Bug has a mass of 187 kg and its initial velocity is -38 m/s. The compact car has a mass of 702 kg and an initial velocity of 23 m/s. They collide and stick together. How fast does the wreckage move immediately after the collision
Answers
Answer:
10.17 m/s in the direction the compact car was going (+)
Explanation:
Law of conservation of momentum states that total P before the collision must equal total momentum after the collision.
P = mv
solve for v, velocity of the two cars stuck together after the collision:
(187kg)(-38 m/s) + (702kg)(23 m/s) = (187 + 702 kg)v
momentum before = momentum after
-7106 kg·m/s + 16146 kg·m/s = 889 kg(v)
9040 kg·m/s = 889 kg(v)
v = 9040 kg·m/s / 889 kg = 10.17 m/s
if the dipole charges are 700 nc and -700 nc, determine the dipole separation. the dipole separation is much smaller than 15 cm. please answer in millimeters
Answers
The dipole separation is 1 mm. To determine the dipole separation, we need to use the equation:
p = qd
where p is the dipole moment, q is the magnitude of the charges and d is the separation distance between them.
Given that the magnitude of the charges is 700 nc and they are opposite in sign, the dipole moment is:
p = qd = (700 nc)(d)
Since the dipole separation is much smaller than 15 cm, we can assume that it is less than 150 mm. Therefore, we can rewrite the equation as:
p = qd = (0.7 µC)(d)
where 1 µC = 1000 nc.
To solve for d, we can rearrange the equation as:
d = p/q = (0.7 µC)/(700 nc) = 1 mm
Therefore, the dipole separation is 1 mm.
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The work done by an ideal monatomic gas undergoing one complete Carnot cycle is 9936 J. The Carnot engine operates between TH=2990 K and TL=1140 K. The high temperature expansion happens between V1=301 L and V2=899 L. How many mol of gas participate in this process?
Answers
The number of moles of gas participating in the Carnot cycle can be determined by calculating the net work done and using the ideal gas law. In this case, the number of moles is approximately 11.94.
The net work done by an ideal gas in a Carnot cycle can be calculated using the formula:
\(W_{net} = nRT_{H}ln(V2/V1)\)
where \(W_{net\) is the net work done, n is the number of moles of gas, R is the gas constant, \(T_H\) is the high temperature in Kelvin, V1 is the initial volume, and V2 is the final volume.
In this case, the net work done is given as 9936 J. The gas constant R is a constant value. The high temperature \(T_H\) is given as 2990 K, and the initial and final volumes V1 and V2 are given as 301 L and 899 L, respectively.
By rearranging the formula, we can solve for the number of moles:
\(n = W_{net} / RT_{H}ln(V2/V1)\)
Substituting the given values, we can calculate the number of moles of gas participating in the process, which is approximately 11.94 moles.
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A brick, milk, and ice cubes are all examples of matter.
Answers
true because
brick: solid
milk: liquid
ice cube: solid
What is the volume of the water in the graduated cylinder gizmo Student Volume Lab Sheet (cm3 and mL)
Answers
Answer:
The volume of water in the graduated cylinder will be equal to the calculated volume of the sphere.
Explanation:
The volume of solid objects can be measured by completely immersing these solids in an overflow faucet filled to brim with a liquid in which the solid does not dissolve. This is known as the displacement method. When water is used, it is known as water displacement method.
In the Volume Lab Sheet, a sphere whose volume has been pre-calculated is immersed in the overflow faucet containing water. The displaced water is collected in a beaker and the volume is obtained using a 50 mL measuring cylinder.
The volume of a sphere is calculated using the following formula:
Vsphere = 4πr³/ 3
The symbol π represents the number pi, which is about 3.14. The letter r stands for the radius of the sphere, which is the distance from the center of a sphere to its surface. The radius is exactly half of the diameter, which is the distance across the sphere through its center.
The volume of the water in the measuring cylinder is found to be equal to the calculated volume of the sphere. This is because an object immersed completely in a liquid displaces a volume of liquid equal to its own volume.
can anyone help me please
Answers
Answer:
Gravity.
Rocket ships.
Ball.
Basketball.
Explanation:
Gravity has to do a lot with air. It puts the planets in there area.
Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.
A ball gets throwed in the air, which gravity comes into place.
Basketball is also a similar example to a ball.
Cars already on the freeway do not have the right-of-way to cars merging onto the freeway.
A. true
B. false
Answers
The statement Cars already on the freeway do not have the right-of-way to cars merging onto the freeway is False.
What is the right-of-way?
The right-of-way is the right of a pedestrian, vehicle, or ship has to move ahead or proceed with precedence over others in a particular situation or place.
The right-of-way of car already on the freeway precedes those of other cars merging onto the freeway.
In conclusion, the right-of-way is a legal right as to who has precedence in a particular situation or place.
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Answer:
false
Explanation:
Which is the most accurate description of how the coolant works in an engine?
Coolant absorbs thermal energy.
Combustion absorbs thermal energy.
Coolant absorbs chemical energy.
Combustion absorbs chemical energy.
Answers
Answer:
Coolant absorbs thermal energy
Explanation:
Since the coolant is used to refrigerate the engine, it have to absorb the thermal energy
1. How much heat must be absorbed by 375 grams of water to raise its
temperature by 25° C?(Cp of water is 4.184)
Answers
Answer:
39225J
Explanation:
Given parameters:
Mass of water = 375grams of water
Change in temperature = 25°C
Specific heat capacity of water = 4.184J/g°C
Unknown:
Amount of heat absorbed = ?
Solution:
To solve this problem, we use the expression below:
H = m c Ф
H is the heat absorbed
m is the mass
c is the specific heat capacity
Ф is the change in temperature
Insert the parameters and solve;
H = 375 x 4.184 x (25) = 39225J
3. Gravitational potential energy depends on the ____ and _____ of the object
Answers
Throwing a ball with more force to increase acceleration is an example of which of Newton’s Laws?
Answers
Answer:
Its the 2nd law of motion
Explanation:
Because it talks about force and acceleration
Throwing a ball with more force to increase acceleration is an example of Newton’s 2nd law of motion.
What is Newton's second law of motion?The acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object. The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body. This means that as the force acting upon an object is increased, the acceleration of the object is increased. Likewise, as the mass of an object is increased, the acceleration of the object is decreased.To learn more about Newton’s second law, refer to: https://brainly.com/question/19030143
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For the purification of hydrogen gas by diffusion through a palladium sheet? Compute the number of kilograms of hydrogen that pass per hour through a 6-mm thick sheet of palladium having an area of 0.25 m2 at 600oC. Assume a diffusion coefficient of 1.7x10-8 m2/s, that the respective concentrations at the high- and low-pressure sides of the plate are 2.0 and 0.4 kg of hydrogen per cubic meter of palladium, and that steady-state conditions have been attained.
Answers
The number of kilograms of hydrogen that pass per hour through a 6-mm thick sheet of palladium having an area of 0.25 m2 at 600 C = 4.08 × 10^-3 kg/h
Given details in the question:
Thickness of the sheet of palladium = 6mm
Area of the sheet = 0.25 m2
Temperature = 600oC
Diffusion coefficient= 1.7x10-8 m2/s
Low pressure sides = 2.0
High pressure sides = 2.0
Explanation;
This problem calls for the mass of hydrogen, per hour, that diffuses through a Pd sheet.
M = JAt = -DAt (ΔC/Δx)
Where D = 1.7 × 10^–8 m2/s, A is area; 0.25 m², t =3600s/h
ΔC =( 0.4 - 2.0) kg/m³, Δx = 6 mm or 6 × 10^-3 m
Therefore;
= -(1.7 × 10^–8 m2/s)(0.25 m²)(3600 s/h) [(0.4 - 2.0) kg/m³)/6 × 10^-3]
= 4.08 × 10^-3 kg/h
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The electric current through a wire varies with time as shown
The total charge flown across any cross section of the wire in time interval 0-T is
Answers
The total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.
option (2) is the correct answer.
What is the total current flowing in the wire?The total charge flown across any cross section of the wire in time interval 0-T is calculated as follows;
The total charge flowing = area under the curve
area under the curve = ¹/₂ x base of the triangle x height of the triangle
area under the curve = ¹/₂ x T x i₀
area under the curve = ¹/₂i₀T
Thus, the total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.
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It was found that ice cream sales decrease significantly as the temperature outside decreases; a very strong relationship was found. What is the most likely correlation coefficient from this hypothetical study
Answers
Answer:
Value closest to 1
Explanation:
It is described from the scenario above that ice cream sales decreases as the outside temperature increases, hence showing a strong relationship between both variables (icream sales and temperature). The correlation Coefficient is a metric used in regression modeling to depict the strength of relationship between two variables, (The dependent and independent variables). Correlation Coefficient ranges from (-1 to +1). With values close to 1 or - 1. Also the positive and negative signs are used to show the type of relationship between the variables. If an increase in variable A leads to a decrease in variable B, then we have negative correlation (-) ; while an increase or decrease in both variables depicts a positive correlation. The most likely correlation Coefficient for the study above will be a positive value which is close to 1 since the relationship is described as strong.
Question 10 of 10
Two particles are separated by 0.38 m and have charges of 1.25 x 10-9C and
1.92 * 10-°C. Use Coulomb's law to predict the force between the particles if
the distance is doubled. The equation for Coulomb's law is F = kouse, and
the constant, k equals 9.00 x 109 Nm²/C2
A. -1,50x10-7N
B. -3.74 x 10-8N
C. 1,50 x 10-7N
D. 3.74 x 10-8N
SUBMIT
Answers
Answer:
Its d 3.74 x 10-8N
Explanation:
Answer: 3.74 x 10-8 N
Explanation:
How much work is done when 0.0042C is moved through a potential difference of 12.0V? Use W = qV
A. 2900J
B. 12J
C. 0.00035J
D. 0.050J
Answers
Work done by charge (W) = 0.050 (Approx)
Explanation:
Given:
Charge (q) = 0.0042 C
Potential difference(V) = 12.0 V
Find:
Work done by charge
Computation:
Work done(W) = qV
Work done by charge (W) = (0.0042)(12)
Work done by charge (W) = 0.0504
An elevator accelerates upward at 1.2 m/s 2 . the acceleration of gravity is 9.8 m/s 2 . what is the upward force exerted by the floor of the elevator on a(n) 62 kg passenger? answer in units of n.
Answers
Answer:
Explanation:
Fr= Fn-P
ma=Fn-mg
Fn= m(a+g)
Fn=62(1.2+9.8)
Fn= 682N
One exciting fairground ride acts like a gaint catapuit. The capsule which the 'rider' is strapped in is fired high into the sky by rubber straps Explain the erengy changes taking place in the ride.
Answers
Elastic energy of rubber straps is converted into the kinetic energy of the capsule which is converted into gravitational potential energy as capsule.
What is energy transformation?In accordance with the law of energy conservation, energy is neither created nor destroyed but can be converted from one form to another. This implies that energy is not lost and continues to exist.
The energy conversion that takes place as the 'rider' is strapped in is fired high into the sky by rubber straps is elastic energy of rubber straps is converted into the kinetic energy of the capsule which is converted into gravitational potential energy as capsule.
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What is the potential energy of a 2 kg bowling ball resting at the top of a 5 m high hill? Show all of your work and include the correct units to receive full credit.
Answers
Answer:
\(\boxed {\boxed {\sf 98 \ J}}\)
Explanation:
We are asked to find the potential energy of a bowling ball.
Potential energy is the energy an object possesses due to its position. It is calculated using the following formula.
\(E_p= mgh\)
In this formula, m is the mass, g is the acceleration due to gravity, and h is the height.
The bowling ball has a mass of 2 kilograms. The hill is 5 meters high. Assuming this situation is occurring on Earth, the acceleration due to gravity is 9.8 meters per second squared.
m= 2 kg g= 9.8 m/s²h= 5 mSubstitute the values into the formula.
\(E_p= (2 \ kg )(9.8 \ m/s^2)(5 \ m)\)
Multiply the numbers together.
\(E_p=19.6 \ kg*m/s^2(5 \ m)\)
\(E_p=98 \ kg*m^2/s^2\)
Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule. Our answer of 98 kg*m²/s² is equal to 98 Joules.
\(E_p= 98 \ J\)
The bowling ball has 98 Joules of potential energy.
Water is being sprayed from a nozzle at the end of a garden hose of diameter 2. 5 cm. If the nozzle has an opening of diameter 1. 0 cm, and if the water leaves the nozzle at a speed of 14 m/s, what is the speed of the water inside the hose?.
Answers
The speed of the water inside a garden hose is 12.6 m.
If the nozzle has an opening of diameter 1.0 cm and the water is leaving the nozzle at a speed of 14 m/s, then the speed of the water inside the hose can be calculated.
To find the speed of the water inside the hose, the Bernoulli equation can be used. The Bernoulli equation states that for an ideal, inviscid flow:
P1/ρ + (V1^2)/2 + gz1 = P2/ρ + (V2^2)/2 + gz2
The speed of the water inside the hose is Where P1 and P2 are the pressures at 1 and 2, V1 and V2 are the velocities at 1 and 2, g is the acceleration due to gravity, and z1 and z2 are the heights at 1 and 2.
The pressure inside the hose will remain constant, so the Bernoulli equation can be simplified to:
(V1^2)/2 = (V2^2)/2
The velocity of the water inside the hose can then be calculated by rearranging the equation:
V2 = √(V1^2 - 2g (z1 - z2))
Therefore, the speed of the water inside the hose can be calculated by substituting in the known values for V1, g, z1, and z2.
Using the given values, the speed of the water inside the hose is calculated to be 12.6 m/s.
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Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x Distance 0 J 15 J 30 J 60 J.
Answers
Answer:
15 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 30 × 0.5 = 15
We have the final answer as
15 JHope this helps you
The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
WORK DONE:The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;
Work done = force (F) × distance (m)
According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:
Work done = 30N × 0.5m
Work done = 15J
Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
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