do i calculate standard deviation for sample or population

The exact value of the average rate of change of the function f(x) = 4/(-3x+1) on the interval [-3, 0] is 6/5.

To find the average rate of change of the function f(x) = 4/(-3x+1) on the interval [-3, 0], we use the formula:

Average rate of change = (f(b) - f(a))/(b - a),

where a and b are the endpoints of the interval.

In this case, a = -3 and b = 0. Let's calculate the average rate of change:

Average rate of change = (f(0) - f(-3))/(0 - (-3)).

First, let's evaluate f(0):

f(0) = 4/(-3(0)+1) = 4/1 = 4.

Next, let's evaluate f(-3):

f(-3) = 4/(-3(-3)+1) = 4/10 = 2/5.

Now we can substitute these values into the formula:

Average rate of change = (4 - 2/5)/(0 - (-3)) = (20/5 - 2/5)/3 = (18/5)/3 = 18/15 = 6/5.

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Answer:

6

Step-by-step explanation:

its 6

Answer:

Step-by-step explanation:

Geoff is feeling peckish, so he decides to pop into the shop and grab some snacks. He picks up a packet of crisps for 25p, a can of soup for 68p and a watermelon for £1.47. He wonders why the watermelon is so cheap, but he doesn't question it. He goes to the cashier and hands over a £5 note. The customer behind Geoff wonders "how much change does he get back?"

To figure this out, we need to add up the price of the snacks and take it away from the money Geoff gave. We can use a dot to show the pence as parts of a pound. For example, 25p = 0.25 pounds.

The price of the snacks is:

0.25 + 0.68 + 1.47 = 2.40 pounds

The money Geoff gave is:

5.00 pounds

The change is:

5.00 - 2.40 = 2.60 pounds

So, Geoff gets £2.60 in change and a bargain watermelon.

Answer:

Answer:

2.60

Step-by-step explanation:

25+68+147=240

500-240=260

turn into pounds 2.60

Step-by-step explanation:

To find the volume of the smallest cube-shaped box that can contain the pyramid, we need to first determine the length of the smallest edge of the box. Since the base of the pyramid is a square, the smallest edge of the box will be the diagonal of the square base of the pyramid.

Using the Pythagorean theorem, we find that the diagonal is:√(10² + 10²) = √200 = 10√2 inches Thus, the length of each edge of the smallest cube-shaped box that can contain the pyramid will be 10√2 inches. The volume of a cube is given by the formula

V = s³, where s is the length of one of its edges. Therefore, the volume of the box will be:(10√2)³ = 1000√8 cubic inches To simplify this expression, we can use the fact that √8 = √(4 · 2) = 2√2. Thus, the volume of the box is:1000√8 = 1000 · 2√2 = 2000√2 cubic inches Therefore, the volume of the smallest cube-shaped box that can contain Eric's pyramid is 2000√2 cubic inches, or approximately 2827.43 cubic inches to two decimal places.

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Answer:

a=2

Step-by-step explanation:

Let's solve your equation step-by-step.

2(a+1)=6

Step 1: Simplify both sides of the equation.

2(a+1)=6

(2)(a)+(2)(1)=6(Distribute)

2a+2=6

Step 2: Subtract 2 from both sides.

2a+2−2=6−2

2a=4

Step 3: Divide both sides by 2.

2a /2 = 4 /2

a=2

The carnival committee should expect to pay $218.70 for prizes at the booth.

We can start by calculating the expected number of students who win each prize:

Stuffed toy: 22% of 150 students = 0.22 x 150 = 33 students

Jump rope: 16% of 150 students = 0.16 x 150 = 24 students

T-shirt: 6% of 150 students = 0.06 x 150 = 9 students

No prize: 100% - (22% + 16% + 6%) = 56% of 150 students = 0.56 x 150 = 84 students

Next, we can calculate the total amount of money that the carnival committee should expect to pay for prizes at the booth:

Stuffed toy: 33 students x $3.60 per toy = $118.80

Jump rope: 24 students x $1.20 per rope = $28.80

T-shirt: 9 students x $7.90 per shirt = $71.10

Total cost of prizes = $118.80 + $28.80 + $71.10 = $218.70

Therefore, the carnival committee should expect to pay $218.70 for prizes at the booth.

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The following are the zeros for the function h (x) = x2 + 3x - 8: - x= -4 and x=2.

Given a collection of inputs X (domain) and a set of potential outputs Y (codomain), a function is more technically defined as a set of ordered pairings (x,y) where xX and yY with the caveat that there can only be one ordered pair with the same value of x. The function notation f:XY can be used to express that f is a function from X to Y.

The function's zero is a value of x that makes it equal to zero. In other words, the equation f(x) = 0 leads to a zero.

By putting h(x) equal to zero and figuring out x, we may determine the zeroes for the function h(x) = x2 + 3x - 8.

h(x) = x² + 3x - 8 = 0

We may factor the left side of the equation to find x:

x² + 3x - 8 = (x-2)(x+4) = 0

We set each factor to zero and solve for x to discover the zeroes:

x-2 = 0 or x+4 = 0

x = 2 or x = -4

Consequently, the function's zeros are x = 2 and x = -4.

So, A is the right response. x = -4 and x = 2

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The complete question is

What are the zeros of the function h (x) = x² + 3x - 8?

A. x = -4 and x = -2

B. x= -8 and x = 2

C. x = -2 and x = 8

D. x = 2 and x = 8

Every quadratic nonresidue of p is a primitive root of p, when p = 2^k + 1 is primeIf p = 2^k + 1 is a prime number, we want to show that every quadratic nonresidue of p is a primitive root of p.

In other words, we aim to prove that if an element x is a quadratic nonresidue modulo p, then it is also a primitive root of p.

Let's assume p = 2^k + 1 is a prime number. To prove that every quadratic nonresidue of p is a primitive root of p, we can use the properties of quadratic residues and quadratic nonresidues.

A quadratic residue modulo p is an element y such that y^((p-1)/2) ≡ 1 (mod p), while a quadratic nonresidue is an element x such that x^((p-1)/2) ≡ -1 (mod p).

Now, let's consider an element x that is a quadratic nonresidue modulo p. We want to show that x is a primitive root of p.

Since x is a quadratic nonresidue, we know that x^((p-1)/2) ≡ -1 (mod p). By Euler's criterion, this implies that x^((p-1)/2) ≡ -1^((p-1)/2) ≡ -1^2 ≡ 1 (mod p).

Since x^((p-1)/2) ≡ 1 (mod p), we can conclude that the order of x modulo p is at least (p-1)/2. However, since p = 2^k + 1 is a prime, the order of x modulo p must be equal to (p-1)/2.

By definition, a primitive root of p has an order of (p-1). Since the order of x modulo p is (p-1)/2, it follows that x is a primitive root of p.

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Answer:

c mystify

Step-by-step explanation:

mystify means

utterly bewilder or perplex (someone).

"maladies that have mystified and alarmed researchers for over a decade"

Answer:

D. $5.00 because when you look at the graph each hour five dollars is being added

The command in Stata would be the most useful is reg when  you want to combine this with a dataset that reports how much each individual sleeps per week.

A collection of data is known as a data set (or dataset). In the case of tabular data, a data set relates to one or more database tables, where each row refers to a specific record in the corresponding data set and each column to a specific variable. The data set includes values for each of the variables, such as the object's height and weight, for each set member. Data sets may also include a group of files or documents.

For data management, visualisation, statistics, and automated reporting, Stata is a general-purpose statistical software programme created by StataCorp. Researchers in a variety of disciplines, such as science, biomedicine, epidemiology, and sociology, use it.

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Answer:

7/5 or 1.4

Step-by-step explanation:

1. Cross multiply. 5(2x-1)= 3(3)

2. Simplify and add 5. 10x -5= 9.     10x = 14

3. Divide by 10. 10x/10 = 14/10

X= 14/10= 7/5 or 1.4

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Our ratio is 5 : 2.

Once we know our ratio, we just have to figure out equivalent ones to fill in the chart. If it helps, feel free to think about this like a fraction! Fractions and ratios are pretty much interchangeable.

5 / 2 = ? / 4 = 10 / 4

10 : 4

5 / 2 = 25 / ? = 25 / 10

25 : 10

5 / 2 = ? / 20 = 50 / 20

50 : 20

Hope this helps!

Answer:

5:2

10:4

25:10

50:20

Step-by-step explanation:

So, this is a 5 to 2 ratio. Which means for every 5 thing there are also 2 other things.

Let's walk through the table:

We see in the second row that there is 4 in the second column. That means the 2 was multiplied by 2 to get 4. So, you would have to multiply 5 by 2 as well. So the ratio would be 10:4.

For the 25 row, 5 x 5 = 25. Because the five was multiplied by another 5, you would have to multiply 2 by 5 as well. This gets the ratio of 25:10.

Lastly, for the last row, divide 20 by 2. This gets you 10. Now, multiply 10 by 5 to get the final box. The ratio would then be 50:20.

Hope this helps!! Ask questions if you need clarification!

Answer:

$96.

Step-by-step explanation:

5/6  costs 80

Multiply both parts by 6/5:

5/6 * 6/5 ( = 1 ) costs 80 * 6/5

= 16 * 6

= $96.

Using the polyfit function with the given linear function:

a = 5.025 and b = 2.0266.

The eventual concentration C is 4.4695.

To plot the data from the given table, we can first use the built-in MATLAB polyfit function to find the coefficients of the linear function. This will allow us to change the variables such that the law C = a - be-0.2t becomes a linear function.

Using the polyfit function with the given data, we can find that a = 5.025 and b = 2.0266.

Now, we can plot the graph of a - be-02t on the interval (0, 10] (as a solid curve), along with the original data points (using '.'). To do so, we can use the following MATLAB code:

t = 0:8;
C = [3.033 3.306 3.672 3.929 4.123 4.282 4.399 4.527 4.622];
plot(t,a-b*exp(-0.2*t),'b-',t,C,'.');

By doing so, we can plot the graph of a - be-0.2t, along with the original data points. The eventual concentration of the chemical reaction, based on the linear function, is C = 5.025 - 2.0266e-02*10 = 4.4695.

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If a differentiable function f: ℝ³ ⟶ ℝ has an absolute maximum value K ≠ 0 and an absolute minimum m, then the function f must have a critical point where the derivative of the function is zero (or undefined).

Given that, suppose f : ℝ³ ⟶ ℝ is a differentiable function which has an absolute maximum value K ≠ 0 and an absolute minimum m.

Since f is continuous on a compact set, it follows that f has a global maximum and a global minimum. We are given that f has an absolute maximum value K ≠ 0 and an absolute minimum m. Then there exists a point a ∈ ℝ³ such that f(a) = K and a point b ∈ ℝ³ such that f(b) = m.Then f(x) ≤ K and f(x) ≥ m for all x ∈ ℝ³.

Since f(x) ≤ K, it follows that there exists a sequence {x_n} ⊆ ℝ³ such that f(x_n) → K as n → ∞. Similarly, since f(x) ≥ m, it follows that there exists a sequence {y_n} ⊆ ℝ³ such that f(y_n) → m as n → ∞.Since ℝ³ is a compact set, there exists a subsequence {x_nk} and a subsequence {y_nk} that converge to points a' and b' respectively. Since f is continuous, it follows that f(a') = K and f(b') = m.

Since a' is a limit point of {x_nk}, it follows that a' is a critical point of f, i.e., ∇f(a') = 0 (or undefined). Similarly, b' is a critical point of f. Therefore, f has at least two critical points where the derivative of the function is zero (or undefined). Hence, the statement is true.

Therefore, the above explanation is verified that if a differentiable function f: ℝ³ ⟶ ℝ has an absolute maximum value K ≠ 0 and an absolute minimum m, then the function f must have a critical point where the derivative of the function is zero (or undefined).

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Answer:

a^25

Explanation:

a^5*5

Answer:

c. 40

a. 3.5

Step-by-step explanation:

question 2:

2x+3x+4x=180

9x=180

x=180/9

x=20

2x=2(20)=40

question 3:

x/15=4/17

17x=60

x=60/17

x=3.5

Answer:

A. The slope is 7/2, The y-intercept is (0,-3)

Step-by-step explanation:

The slope of a line passing through two points P=(x1,y1) and Q=(x2,y2) is given by m=y2−y1x2−x1.

We have that x1=0, y1=−3, x2=2, and y2=4.

Plug the given values into the formula for a slope: m=4−(−3)/2−0=72.

Now, the y-intercept is b=y1−mx1 (or b=y2−mx2, the result is the same).

b = -3 - (7/2) × (0) = -3

Finally, the equation of the line can be written in the form y=b+mx:

y = 7/2x - 3

Answer:

19x2-7

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answer: 20g−30

i know this bc i know everything

Answer:

Step-by-step explanation:

(4g-6)(5)=0 5times 4g=20g  5 times -6 = -30

20g-30=0

20g=30 30 became positive

20g/20=30/20

g=1.5

The z-scores for the different values of random variable x;

(a) Z = 2.25

(b) Z = 1.50

(c) Z = -1.75

(d) Z = 3.25

(e) Z = -2.25

(f) Z = 3.50

We are given different values of x which is a random variable along with the values of the mean and the standard deviation. We have to calculate the z-score for the given values of x. We will use the following formula to calculate the z-score.

z = (x - μ)/σ

In all the parts we have;

μ = 23

σ = 4

(a)x = 32

z = (x - μ)/σ

z = (32 - 23)/4

z = 9/4 = 2.25

(b) x = 29

z = (x - μ)/σ

z = (29 - 23)/4

z = 6/4 = 1.50

(c) x = 16

z = (x - μ)/σ

z = (16 - 23)/4

z = 7/4 = -1.75

(d) x = 36

z = (x - μ)/σ

z = (36 - 23)/4

z = 13/4 = 3.25

(e)  x = 14

z = (x - μ)/σ

z = (14 - 23)/4

z = -9/4 = -2.25

(f)  x = 37

z = (x - μ)/σ

z = (37 - 23)/4

z = 14/4 = 3.50

Therefore, the z-scores will be;

(a) Z = 2.25

(b) Z = 1.50

(c) Z = -1.75

(d) Z = 3.25

(e) Z = -2.25

(f) Z = 3.50

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The complete question is "Suppose the random variable x is best described by a normal distribution with μ=23 and σ=4. Find the z-score that corresponds to each of the following x-values.

(a) x=32

z=

(b) x=29

z=

(c) x=16

z=

(d) x=36

z=

(e) x=14

z=

(f) x=37

z=                    "

Answer:

Step-by-step explanation:

Take AC as  x

90° + x +70°= 90°

x = 70 + 90 = 160 - 90 = 70

x = 70

Hope this answer will help you!!!!!

Step-by-step explanation:

90°+?+70°=90°(right angle)

?=70+90=160-90=70

?=70

Answer:

13

Step-by-step explanation:

If Mr. West wants to still go on his trip to China he will need to not be late more than 13 times. How i got this is since he is working and making $2000 over the next 6 weeks and he only needs $10,000 of it we can take $2000 away from the equation. Then, divide 2000 by 150 to get the amount of times he can be late. The answer is 13.3, which rounded is 13.

Answer:

(-6,9)

Step-by-step explanation:

We can use the midpoint formula to find the coordinates of C. The midpoint formula states that the midpoint of a line segment with endpoints (x1, y1) and (x2, y2) is:

((x1 + x2)/2, (y1 + y2)/2)

In this case, we know that the midpoint of CD is M(-1, 7) and one endpoint of CD is D(4, 5). Let C = (x, y) be the coordinates of the other endpoint of CD. Then we can use the midpoint formula to set up two equations:

(x + 4)/2 = -1

(y + 5)/2 = 7

Solving for x and y, we get:

x + 4 = -2

y + 5 = 14

x = -6

y = 9

Therefore, the coordinates of C are (-6, 9).

Answer:

Solve it, you can do it!

Step-by-step explanation:

Multiply 4 2/3 and then divide what you get with 7

Answer:

1.5 or 1 1/2

Step-by-step explanation:

4 2/3 / 7

14/3 / 7

3 * 7 = 21

21/14 =

1.5

edit 1: i changed the / to an or to make it less confusing

Problem 1

Angles A and B are adjacent in parallelogram ABCD. For any parallelogram, adjacent angles are supplementary.

A+B = 180

2x+(x+6) = 180

3x+6 = 180

3x = 180-6

3x = 174

x = 174/3

x = 58

Use this x value to find angles A and B

angle A = 2x = 2*58 = 116 degrees

angle B =  x+6 = 58+6 = 64 degrees

Answer:  64 degrees

================================================

Problem 2

Let y be the measure of the unknown angle that's supplementary to the 42 degree angle. This must mean that,

y+42 = 180

y = 180-42

y = 138 degrees

Answer: D) 138 degrees

The measure of ∠B is 64 degrees.

The angle that is supplement ot the angle 42 degrees is 138 degrees.

Supplementary angles are angles that sum up to 180 degrees. When two angles sum up to 180 degrees, they are supplementary angles.

Therefore,

Adjacent angles of a parallelograms are supplementary.

Hence,

∠A + ∠B = 180

2x + x + 6 = 180

3x + 6 = 180

3x = 180 - 6

3x = 174

x = 174 / 3

x = 58

Therefore,

∠B = 58 + 6 = 64°

The other angle that is supplement to 42 degrees is as follows;

42 + y = 180

y = 180 - 42

y = 138°

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