The critical numbers are x = π/6 and x = 2π/3, the absolute maximum is 3π/2, and the absolute minimum is π/6 + √3/2.
To find the critical numbers of the function, we first take its derivative
f'(x) = 1 + 2cos(2x)
Then, we set the derivative equal to zero to find any critical numbers
1 + 2cos(2x) = 0
cos(2x) = -1/2
Using the unit circle, we see that the solutions to this equation are
2x = 2π/3 + 2nπ or 2x = 4π/3 + 2nπ
where n is an integer.
Simplifying, we get
x = π/6 + nπ or x = 2π/3 + nπ
for n being an integer.
Now, we need to test the critical numbers and the endpoints of the interval [0, 3π/2] to find the absolute maximum and minimum values of the function.
f(0) = 0 + sin(0) = 0
f(3π/2) = 3π/2 + sin(3π) = 3π/2
f(π/6) = π/6 + sin(π/3) = π/6 + √3/2
f(2π/3) = 2π/3 + sin(4π/3) = 2π/3 - √3/2
We can now use the first and second derivative tests to determine the nature of the critical points
For x = π/6
f''(x) = -4sin(2x)
f''(π/6) = -4sin(π/3) = -2√3 < 0
Therefore, x = π/6 is a local maximum.
For x = 2π/3
f''(x) = -4sin(2x)
f''(2π/3) = -4sin(4π/3) = 2√3 > 0
Therefore, x = 2π/3 is a local minimum.
Finally, we compare the values we obtained to find the absolute maximum and minimum
The absolute maximum is 3π/2 at x = 3π/2.
The absolute minimum is π/6 + √3/2 at x = π/6.
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3. Michelle wants to save at least $3,500. She has already put away
$600 and just got a job making $360 each week.
Which equation represents the scenario given w represents the
number of weeks.
A. 3500 < 360w – 600
C. 3500 > 360w + 600
B. 3500 < 360w + 600
D. 3500 > 360w - 600
The equation that represents the scenario is 3500 < 360w + 600.
What is the equation that represents the scenerio?Here are inequality signs and what they mean:
> means greater than< means less than≥ means greater than or equal to ≤ less than or equal toTotal amount Michelle wishes to save < total amount already saved + (number of weeks x amount made weekly)
$3500 < $600 + ($360w)
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Select all correct answers. one solution to a quadratic equation is . what is true about any remaining solutions? there are at least two more real solutions. there are no other real solutions. there is exactly one complex solution. there are two or more complex solutions. there are no complex solutions. there is exactly one more real solution.
There is exactly one more real solution or there is exactly one more complex solution
Given,
One solution to a quadratic equation is x = -5/3
We have to find the correct statements from the given ones;
A polynomial of degree two is a quadratic equation.
This implies that a polynomial has two solutions.
We already have an answer to the query, which is a true root.
Then, the additional response that we lack can appear in the form of two responses.
It may be a real root or a complicated root, depending on the situation.
The following is the response to this query:
There is exactly one more real solution or there is exactly one more complex solution
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Calculate the vibrational partition function of HCN at 900 K given the wavenumbers 3311/cm (symmetric stretch), 937/cm (bend; two modes), and 2097/cm (asymmetric stretch)
The vibrational partition function of HCN at 900 K is 3.319.
To calculate the vibrational partition function (Qvib) of HCN at 900 K, we first need to calculate the vibrational energies of each mode:
The vibrational energy of each mode is given by:
E(v) = (v + 1/2) × h × nu
where v is the vibrational quantum number, h is Planck's constant (6.626 x 10^-34 J s), and nu is the frequency in cm^-1.
For the symmetric stretch mode, nu = 3311 cm^-1:
E(v) = (v + 1/2) × h × nu = (0 + 1/2) × 6.626 x 10^-34 J s × 3311 cm^-1 = 1.096 x 10^-20 J
For the two bend modes, nu = 937 cm^-1:
E(v) = (v + 1/2) × h × nu = (0 + 1/2) × 6.626 x 10^-34 J s × 937 cm^-1 = 3.108 x 10^-21 J
Therefore, the total energy of both bend modes is 2 * E(v) = 6.216 x 10^-21 J
For the asymmetric stretch mode, nu = 2097 cm^-1:
E(v) = (v + 1/2) × h × nu = (0 + 1/2) × 6.626 x 10^-34 J s × 2097 cm^-1 = 6.933 x 10^-21 J
Now we can calculate the vibrational partition function as the sum of the individual contributions:
Qvib = exp(-E(0)/(kT)) + exp(-E(1)/(kT)) + exp(-E(2)/(kT)) + ...
where k is the Boltzmann constant (1.38 x 10^-23 J/K) and T is the temperature in Kelvin.
At 900 K, we have:
Qvib = exp(-E(0)/(kT)) + exp(-E(1)/(kT)) + exp(-E(2)/(kT))
= exp(-(1.096 x 10^-20 J)/(1.38 x 10^-23 J/K × 900 K)) + exp(-(3.108 x 10^-21 J)/(1.38 x 10^-23 J/K × 900 K)) + exp(-(6.933 x 10^-21 J)/(1.38 x 10^-23 J/K × 900 K))
= 1.249 + 1.060 + 1.010
= 3.319
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The circle shown above has a radius of 5 units, and the central angle of the sector that is shaded is 25π radians. Determine the area of the shaded sector, in terms of π. Enter the area of the sector.
Answer:
The answer is below
Step-by-step explanation:
Given that:
The radius of the circle (r) = 5 units
The central angle (θ) = 25π
A sector of a circle is the portion of a circle made up of two of its radii and an arc. The area of a sector that subtends with a central angle (θ) and a radius (r) is given by the formula:
\(Area\ of\ sector=\frac{\theta}{360} *\pi r^2\)
Substituting the radius of the circle and the central angle:
\(Area\ of\ sector=\frac{\theta}{360} *\pi r^2\\\\Area\ of\ sector=\frac{25\pi}{360} *\pi (5)^2\\\\Area\ of\ sector=\frac{125\pi^2}{72}\)
PLEASE HELP! This is one of my lowest average classes.
What is the best way to designate point A on the ruler below?
Answer:
2 1/2 inches
Step-by-step explanation:
Here, we want to give the measurement of point A that is marked on the ruler
We have this as;
As we can see, we have the whole number of inches before it as 2
Now, the small intervals between each of the whole numbers on the ruler is;
1/8
A is at the 4th point
So we have its measure added to 2 as:
2 + (4 * 1/8)
= 2 1/2 inches
help meeeeeeeeeeeee pleaseeee rnnn!!!
It would take about 10 seconds for the object to fall to the ground from the top of the tower
How to determine the time spent by the object from the top of the tower to the ground?From the question, we have the following function equation that can be used in our computation:
s(t) = 16t²
Also, from the question;
The height (h) of the tower is given as
h = 1503 feet
The object would hit the ground when the height of the tower equals the distance travelled
Mathematically, this can be represented as:
s(t) = h
So, we have
s(t) = 1503
Substitute s(t) = 1503 in s(t) = 16t²
16t² = 1503
Divide both sides by 16
This gives
t² = 93.9375
Take the square root of both sides and approximate
t = 10 seconds
Hence, the time taken is about 10 seconds
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Range of g(x)=3 square root of x
The range of the function g(x) is given as follows:
[0, ∞).
How to obtain the domain and range of a function?The domain of a function is obtained as the set containing all the values assumed by the independent variable x of the function, which are also all the input values assumed by the function.The range of a function is obtained as the set containing all the values assumed by the dependent variable y of the function, which are also all the output values assumed by the function.From the graph of the function given in this problem, y assumes all real non-negative values, hence the interval notation representing the range of the function is given as follows:
[0, ∞).
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During one month andre used 785 gallons of water at his home. There are approximately 3. 8 liters in 1 gallon. Which measurement is closest to the number of liters andre used during this month?.
Andre used 2983 gallons of liquid all through this month.
Given;
Andre used 785 gallons of water at his house in a single month. In a gallon, there are roughly 3.8 liters.
To get the measurement that is closest to the number of liters Andre used during this month;
The total gallons of water used in a month = 785 gallons
The quantity of water in a single gallon = 3.8 liters
Therefore, the number of liters Andre used during this month;
U = total gallons of water used in a month * quantity of water in a single gallon
U = 785 * 3.8
U = 2983
Hence, the number of liters Andre used during this month is 2983 gallons.
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Question text Level and Trend in a Time Series is estimated by- Select one: a. Moving Average b. Simulation method c. Regression analysis d. Covariance analysis e. Correlation Analysis
(C) Regression analysis is the statistical method commonly used to estimate the level and trend in a time series by modeling the relationship between the data and independent variables.
Regression analysis is the statistical method used to estimate the level and trend in a time series. Time series data represents observations taken at different points in time and is commonly used to analyze trends and patterns over time.
Regression analysis allows us to model the relationship between a dependent variable (in this case, the time series data) and one or more independent variables (such as time or other relevant factors). By using regression analysis, we can identify the underlying trend in the time series and estimate its level.
The regression model captures the relationship between the dependent variable (the time series) and the independent variable(s) by fitting a line or curve that best represents the data. This line or curve helps to identify the overall trend and level of the time series.
While moving average, simulation method, covariance analysis, and correlation analysis are useful techniques in analyzing time series data, they are not specifically designed to estimate the level and trend in a time series. Therefore, (C) regression analysis is the most appropriate method for estimating the level and trend in a time series.
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I need number line answers thanks alot!
Step-by-step explanation:
2X(5)=10
2X(-5)=10
20÷(-4)=5
-2X(5)=10
20÷(4)=5
4X(-5)=20
25÷(-5)=5
-20÷(4)=-5
She selects 150 trees at random from her orchard and uses this fertilizer on those trees and estimates the following regression: Y
^
i
=600+4.93X i
, where Y
^
i
denotes the predicted number of apricots obtained from the I th tree and X i
denotes the number of units of fertilizer used on the I th tree. A. H 0
:β 1
≥5.14 and H 1
:β 1
<5.14. B. H 0
:β 1
>4.93 and H 1
:β 1
≤4.93. C. H 0
:β 1
=5.14 and H 1
:β 1
=5.14. D. H 0
:β 0
=4.93 and H 1
:β 0
=4.93. Suppose the standard error of the estimated slope is 0.74. The t-statistic associated with the test Wendy wishes to conduct is (Round your answer to two decimal places. Enter a minus sign if your answer is negative.1
Given statement solution is :- The t-statistic associated with the test is approximately -0.28.
The t-statistic, which is used in statistics, measures how far a parameter's estimated value deviates from its hypothesised value relative to its standard error. Through the Student's t-test, it is utilised in hypothesis testing. In a t-test, the t-statistic is used to decide whether to accept or reject the null hypothesis.
To find the t-statistic associated with the test, we need to calculate the test statistic using the estimated slope coefficient, the null hypothesis, and the standard error.
The estimated slope coefficient is 4.93.
The null hypothesis is H₀: β₁ ≥ 5.14 (stating that the true slope coefficient is greater than or equal to 5.14).
The predicted slope's standard error is 0.74.
The formula to calculate the t-statistic is:
t = (estimated slope - hypothesized slope) / standard error
Plugging in the values:
t = (4.93 - 5.14) / 0.74
t = -0.21 / 0.74
t ≈ -0.28 (rounded to two decimal places)
Therefore, the t-statistic associated with the test is approximately -0.28.
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Solve the quadratic equation 6x2 + 1 = 5x. Show your work.
Answer:
Factors = (3x - 1) (2x - 1)values :- x = 1/3 , 1/2Step-by-step explanation:
= > 6x^2 + 1 = 5x
• Bring it in the standard form,
= > 6x^2 - 5x + 1 = 0
= > 6x^2 - (3 + 2)x + 1 = 0
= > 6x^2 - 3x - 2x + 1 = 0
• Take out common
= > 3x (2x - 1) - 1 (2x - 1) = 0
= > (3x - 1) (2x - 1) = 0...factors
= > x = 1/3 and 1/2... values of x
Hope it helps you!!Write an equation in slope-intercept form of the line that passes through the given point and is parallel to the graph of the given equation. (-7,-6); y=-5x+2
Answer:
The equation in the slope-intercept form is
y = -5x - 41
Step-by-step explanation:
The given equation in the question is;
y = -5x + 2
The equation of a straight line graph can be written in the form;
y = mx + c
where m is the slope and c is the intercept
From here, we can see that the slope m is -5
Since the line is parallel to the new line we are trying to write its equation, it means that they have the same value of intercept.
Hence, the slope of the new line is also -5
Now, we can write the equation of the new line as;
y = -5x + c
we need to get the value of c here however
To get the value of c, we need to input the value of x and y
From the graph, x = -7 and y = -6
Substituting these values, we have;
-6 = -5(-7) + c
-6 = 35 + c
c = -6 -35
c = -41
So the equation of the new line will be;
y = -5x - 41
the given set is a basis for a subspace w. use the gram-schmidt process to produce an orthogonal basis for w.
y₁ = [1 -4 0 1] and y₂ = [5 1 -6 -1] is the orthogonal basis for w using Gram-Schmidt process.
Given,
The set;
x₁ = [1 -4 0 1]
x₂ = [7 -7 -6 1]
We have to produce the orthogonal basis for w using the Gram-Schmidt process;
Here,
y₁ = x₁ = [1 -4 0 1]
Now,
Solve for y₂
y₂ = x₂ - [x₂y₁ / y₁y₁] y₁
That is,
y₂ = [7 -7 -6 1] - ( [7 -7 -6 1] [1 -4 0 1] / [1 -4 0 1] [1 -4 0 1] ) × [1 -4 0 1]
y₂ = [7 -7 -6 1] - (7 + 28 - 0 + 1) / (1 + 16 + 0 + 1) × [1 -4 0 1]
y₂ = [7 -7 -6 1] - 36/18 × [1 -4 0 1]
y₂ = [7 -7 -6 1] - 2 × [1 -4 0 1]
y₂ = [7 -7 -6 1] - [2 8 0 2]
y₂ = [5 1 -6 -1]
That is,
The orthogonal basis for w using Gram-Schmidt process is,
y₁ = [1 -4 0 1] and y₂ = [5 1 -6 -1]
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Please answer with everything needed i appreciate everyones help:)
Answer:
at 5 mins Holly traveled 2 miles. At 10 mins Holly traveled 4 miles. from there on she stayed there for 10 mins then went on her way. At 30 mins she traveled 5 1/2 miles. when she hit 35 mins she hit her destination then went back home.
Step-by-step explanation:
pretty simple
PLEASE HELP
The pressure of a gas varies jointly with the amount of the gas (measured in moles) and the temperature and inversely with the volume of the gas.
If the pressure is 1,218 kPa (kilo Pascals) when the number of moles is 8, the temperature is 290* Kelvin, and the volume is 960 cc,
find the pressure when the number of moles is 6, the temperatire is 250° K, and the volume is 360 cc.
Step-by-step explanation:
this means, when you put more gas into the same volume at the same temperature, the pressure goes up linearly. and it goes down linearly, when you remove gas.
when you increase the temperature of the same amount of gas in the same volume, the pressure goes up linearly. and it goes down linearly when you decrease the temperature.
when you decrease the volume for the same amount of gas at the same temperature, the pressure goes up linearly. and it goes down linearly, if you increase the volume.
now, all 3 attributes are changed.
and so, the pressure changes as a combination of all 3 factors.
the moles decrease from 8 to 6. that is a factor of 6/8 = 3/4.
the temperature decreases from 290°K to 250°K. that is a factor of 250/290 = 25/29.
the volume decreases from 960 cc to 360 cc. this is an (inverse) factor of 960/360 = 16/6 = 8/3.
so, the pressure is
1,218 × 3/4 × 25/29 × 8/3 = 1,218 × 25/29 × 2 =
= 2,100 kPa
Answer:
2100 kPa
Step-by-step explanation:
The pressure of a gas varies jointly with the amount of the gas and the temperature and inversely with the volume:
\(\implies P \propto \dfrac{nT}{V}\)
where:
P = pressure (measured in kilo Pascals, kPa).n = number of moles.T = temperature (measured in kelvins, K).V = volume (measured in cubic centimeters, cc).\(\textsf{If }a \propto b, \textsf{ then } a=kb \textsf{ for some constant } k:\)
\(\implies P =\dfrac{knT}{V}\)
Given:
P = 1218 kPan = 8 molT = 290 KV = 960 ccSubstitute the given values into the derived equation to find the constant of variation (k):
\(\implies 1218 =\dfrac{k(8)(290)}{960}\)
\(\implies 1218 =\dfrac{2320k}{960}\)
\(\implies 1169280=2320k\)
\(\implies k=\dfrac{1169280}{2320}\)
\(\implies k=504\)
Substitute the found value of k into the equation:
\(\implies P =\dfrac{504nT}{V}\)
To find the pressure (P) when:
n = 6 molT = 250 Kv = 360 ccsubstitute the given values into the equation and solve for P:
\(\implies P =\dfrac{504(6)(250)}{360}\)
\(\implies P=\dfrac{756000}{360}\)
\(\implies P=2100\:\: \sf kPa\)
g 6. if you had to hike up the top of stone mountain which side would you choose to climb? why? (remember your rules about contour intervals! use the cardinal direction in your description.) 7. you do not have enough information from this map to calculate the slope. what are you missing?
I would choose the western side to climb because it is less steep then others.
What is steepness?In mathematics, a line's steepness is determined by its slope (or gradient). The slope is the ratio of any two points on a line's vertical and horizontal distances. A line's steepness can be determined by looking at its slope. Slope is calculated mathematically as "rise over run" (change in y divided by change in x). The slope's absolute value serves as a gauge for a line's steepness, incline, or grade. A steeper line is indicated by a slope with a higher absolute value. A line can be drawn with one of four directions: upward, downward, horizontal, or vertical. If a line rises from left to right, it is said to be increasing.
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the height of a cylindrical container of radius r is 15 cm. what is the height of this quantity of water if it is poured into a cylindrical container of 2r?
Step 1: Calculate the volume of the water in the first container.
The volume of a cylinder is V = πr^2h, where r is the radius of the cylinder and h is the height of the cylinder.
Therefore, the volume of the water in the first container is V = πr^2 x 15 cm, where r is the given radius of the container.
Step 2: Calculate the height of the water in the second container.
The volume of the water in the second container is the same as the volume of the water in the first container, since the same quantity of water is being poured from one container to the other.
Therefore, the volume of the water in the second container is also V = πr^2 x 15 cm, where r is now 2r, the radius of the second container.
To find the height of the water in the second container, we can substitute the value of the radius into the equation for the volume and solve for h. This gives us h = (15 cm) / (π(2r)^2), which simplifies to h = 15 cm / 4πr^2.
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The product of double the number four
!!!Translate the following sentence into a variable expression!!!
At the beginning of the third term in a primary school, the head teacher of a school informs parents that their children's promotion to the next class will be based on their final scores which is weighted as follows: homework-10\%; quizzes- 20% and end of term exam-70\%. The headteacher further explains that any student who obtains a weighted score of 75% will be promoted to the next class. Using the above information, calculate: a. The weighted score of Kwame, who obtains 70% in his homework; 40% in his quizzes and 50% in his final exam. (5 marks) b. The weighted score of Akuyoo who obtains 75% in her homework; 78% in her quizzes and 80% in her final exam c. Calculate the Variance and Standard deviation of their weighted scores.
The variance of the weighted scores is approximately 211.68, and the standard deviation is approximately 14.55.
To calculate the weighted scores, we'll multiply the individual scores by their respective weightings and then sum them up.
a. Weighted score of Kwame:
Homework: 70% (score) * 10% (weighting) = 7
Quizzes: 40% (score) * 20% (weighting) = 8
Final exam: 50% (score) * 70% (weighting) = 35
Weighted score = 7 + 8 + 35 = 50
b. Weighted score of Akuyoo:
Homework: 75% (score) * 10% (weighting) = 7.5
Quizzes: 78% (score) * 20% (weighting) = 15.6
Final exam: 80% (score) * 70% (weighting) = 56
Weighted score = 7.5 + 15.6 + 56 = 79.1
c. To calculate the variance and standard deviation of the weighted scores, we'll need the individual scores of Kwame and Akuyoo.
Kwame's scores: Homework = 70, Quizzes = 40, Final exam = 50
Akuyoo's scores: Homework = 75, Quizzes = 78, Final exam = 80
First, we'll calculate the mean of the weighted scores for Kwame and Akuyoo:
Mean = (Weighted score of Kwame + Weighted score of Akuyoo) / 2
Variance:
Variance = [(Weighted score of Kwame - Mean)² + (Weighted score of Akuyoo - Mean)²] / 2
Standard Deviation:
Standard Deviation = √Variance
Using the given data, let's calculate the variance and standard deviation:
Kwame's mean weighted score: (50 + 79.1) / 2 = 64.55
Akuyoo's mean weighted score: (50 + 79.1) / 2 = 64.55
Variance:
Variance = [(50 - 64.55)² + (79.1 - 64.55)²] / 2
= [(-14.55)² + (14.55)²] / 2
= (211.6803 + 211.6803) / 2
= 423.3606 / 2
= 211.6803
Standard Deviation:
Standard Deviation = √Variance
= √211.6803
≈ 14.55
Therefore, the variance of the weighted scores is approximately 211.68, and the standard deviation is approximately 14.55.
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One day at football practice, Darrell, the kicker, punted the ball so that its height in feet above the ground was given by the following function, where t is the number of seconds since the ball was punted.
\(h(t)=-16t^{2} +75\)
When will the football be 81 feet high?
When the football is 81 feet high, it will be √ 3 / 8 seconds
FunctionFunction relates input to output. Therefore,
h(t) = - 16t² + 75Therefore,
t = number of seconds
h(t) = - 16t² + 75
h(t) = 81 ft
Therefore,
81 = - 16t² + 75
- 16t² = 81 - 75
- 16t² = 6
divide both sides by -16
t² = 6 / -16
t² = - 3 / 8
square root both sides
t = √ 3 / 8 seconds
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Answer:
It'll be that high a 1.69 and 3
Step-by-step explanation:
It counts 1.69 as 81 even though it's more like 81.1, so 1.69 and 3 is the answer.
What is the slope of the line through (-7,-8)(−7,−8)
Answer:
the slope would be 0
Step-by-step explanation:
this is because those are the same 2 points
If n(x)=4x-7, m(x) must be equal to which expression?
Step-by-step explanation:
the question is not understood plz clarify it
Answer:is 2 over 4|/x
Step-by-step explanation:
let d be the solid region bounded by the paraboloids and . write six different triple iterated integrals for the volume of d. evaluate one of the integrals.
To find the volume of the solid region bounded by the paraboloids y = x^2 and z = 4 - x^2, we need to set up triple iterated integrals in terms of x, y, and z.
One way to do this is to integrate over x first, then y, then z, or vice versa. Here are six different triple iterated integrals we can use:
1. ∫∫∫d dz dy dx
2. ∫∫∫d dx dy dz
3. ∫∫∫d dx dz dy
4. ∫∫∫d dy dx dz
5. ∫∫∫d dy dz dx
6. ∫∫∫d dz dx dy
Let's evaluate the first integral:
∫∫∫d dz dy dx
We start by finding the limits of integration for z. The paraboloid z = 4 - x^2 is above the paraboloid y = x^2, so the lower limit for z is y - x^2, and the upper limit is 4 - x^2.
Next, we find the limits of integration for y. The paraboloid y = x^2 is a function of x, so the limits are given by the x-values that bound the region d. Since the paraboloids intersect at x = -2 and x = 2, the limits for y are x^2 and 4 - x^2.
Finally, we find the limits of integration for x. The region d is symmetric about the yz-plane, so we can integrate over x from 0 to 2 and multiply by 2 to get the full volume. Therefore, the limits for x are 0 and 2.
Putting it all together, we have:
∫∫∫d dz dy dx = ∫0^2 ∫x^2^(4-x^2) ∫y-x^2^(4-x^2) dz dy dx
Evaluating this integral is a bit messy, but it can be done with some algebraic manipulation and trigonometric substitutions. The answer turns out to be: 64/15
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(1/512)^1/3
I know the answer is 1/8 but how do I get to that?
Answer:
See explanation below
Answer is 1/8
Step-by-step explanation:
The expression is:
\(\left(\dfrac{1}{512}\right)^{\dfrac{1}{3}}\)
A number x raised to the power \(\dfrac{1}{3}\) means it is the cube root of that number or \(\mbox{\large \sqrt[3]{x} }\)
Also \(\left(\dfrac{1}{x}\right)^a = \dfrac{(1)^a}{x^a}\)
Combining these two facts we get
\(\left(\dfrac{1}{512}\right)^{\frac{1}{3}} = \dfrac{1^{\frac{1}{3}}}{512^\frac{1}{3}}= \dfrac{\sqrt[3]{1} }{\sqrt[3]{512} } = \dfrac{1}{\sqrt[3]{512} }\)
\(\sqrt[3]{512} = 8\)
So
\(\left(\dfrac{1}{512}\right)^{\dfrac{1}{3}} = \dfrac{1}{8}\)
2 1/4+2/5÷(−1/2)−1/4
Answer:
i believe its 1.2
Step-by-step explanation:
hopethishelpsya:)
The answer is 6/5.
When the numerator is always higher than or equal to the denominator, the fraction is said to be an improper fraction. When a fraction contains a whole number and a proper fraction is said to be a mixed fraction.
Write the given equation with mixed fraction to an improper fraction,
\(2\frac{1}{4}+\frac{2}{5}\div \left(\frac{-1}{2}\right)-\frac{1}{4}=\frac{9}{4}+\frac{2}{5}\div \left(\frac{-1}{2}\right)-\frac{1}{4}\)
When we divide a fraction, we convert division into multiplication by turning the fraction upside down. Here, we convert the division sign before (-1/2) into multiplication by changing this fraction upside down as (-2/1).
Therefore,
\(2\frac{1}{4}+\frac{2}{5}\div \left(\frac{-1}{2}\right)-\frac{1}{4}=\frac{9}{4}+\left(\frac{2}{5}\times\left(\frac{-2}{1}\right)\right)-\frac{1}{4}\)
Now using the BODMAS rule, solve the bracket first. Followed by multiplication, addition, and subtraction.
\(\begin{aligned}2\frac{1}{4}+\frac{2}{5}\div \left(\frac{-1}{2}\right)-\frac{1}{4}&=\frac{9}{4}-{\frac{4}{5}-\frac{1}{4}\\&=\frac{8}{4}-\frac{4}{5}\\&=\frac{40-16}{20}\\&=\frac{24}{20}\\&=\frac{6}{5}\end{aligned}\)
Therefore, the answer is 6/5.
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The complete question is -
Simply the given expression 2 1/4+2/5÷(−1/2)−1/4
a group of 17,000 people are tested for a gene called ifi202 that has been found to increase the risk for lupus. the random variable is the number of people who carry the gene. determine the range (possible values) of the random variable.
The range of the random variable is from 0 to 17,000.
The range of the random variable is the set of all possible values that the variable can take on. In this case, the variable is the number of people who carry the gene ifi202. Since 17,000 people are being tested, the range of the variable is from 0 to 17,000.
This is because it is possible that none of the people tested carry the gene, or that all 17,000 people tested carry the gene. Any number of people between 0 and 17,000 could also carry the gene, so the range of the variable is 0 to 17,000.
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What is the value of xº?
Answer:
show image
Step-by-step explanation:
4. Compute the flux of the vector field
F(x,y,z) = (yz, —xz, yz)
through the part of the sphere x² + y² + z² 4 which is inside the cylinder x² + z² = 1 and = for which y ≥ 1. The direction of the flux is outwards though the surface.
Evaluating this triple integral will give the flux of the vector field F through the specified surface.
To compute the flux of the vector field F(x, y, z) = (yz, -xz, yz) through the specified surface, we need to calculate the surface integral.
The surface consists of the part of the sphere x² + y² + z² = 4 that is inside the cylinder x² + z² = 1 and y ≥ 1.
To compute the flux, we can use the divergence theorem, which states that the flux of a vector field through a closed surface is equal to the triple integral of the divergence of the vector field over the region enclosed by the surface.
The divergence of the vector field F(x, y, z) = (yz, -xz, yz) is given by:
div(F) = ∂x(yz) + ∂y(-xz) + ∂z(yz)
= z + y - x
Now, we need to find the limits of integration for the triple integral. Since we are only considering the part of the sphere that is inside the cylinder and y ≥ 1, the limits of integration are as follows:
-1 ≤ x ≤ 1
1 ≤ y ≤ √(4 - x²)
-√(1 - x²) ≤ z ≤ √(1 - x²)
The flux integral can be written as:
Flux = ∬S F · dS
Using the divergence theorem, this becomes:
Flux = ∭V div(F) dV
Substituting the divergence and limits of integration:
Flux = ∫∫∫V (z + y - x) dV
Now, we can perform the integration. The order of integration can be chosen as dx dy dz:
Flux = ∫[-1,1] ∫[1,√(4 - x²)] ∫[-√(1 - x²),√(1 - x²)] (z + y - x) dz dy dx
Evaluating this triple integral will give the flux of the vector field F through the specified surface.
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Evaluate the expression if m = −4, n = 1, p = 2, q = −6, r = 5, and t = −2.
|12+2t|
Answer:
8
Step-by-step explanation:
it goes to 12-8 which equals 8
The value of the expression |12 + 2t| at m = −4, n = 1, p = 2, q = −6, r = 5, and t = −2 will be 8.
What is the value of the expression?When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.
The absolute function is also known as the mode function. The value of the absolute function is always positive.
The absolute expression is given below.
⇒ |12 + 2t|
Then the value of the expression |12 + 2t| at m = −4, n = 1, p = 2, q = −6, r = 5, and t = −2 will be
⇒ |12 + 2(-2)|
⇒ |12 - 4|
⇒ |8|
⇒ 8
The value of the expression |12 + 2t| at m = −4, n = 1, p = 2, q = −6, r = 5, and t = −2 will be 8.
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