Design a finite state machine for an elevator. you can make it as simple as you want. consider error handling states as well. Please make sure the machine is complete and does not go to no-return states.
(embedded systems)

The necessary power developed by the pump =19.07 kw

Given;

Inlet pressure = 50psi; dw = 62.4

working pressure= 20psi

Power developed by pump = dwQ(H +hf)

where hf= \(\frac{flQ^2}{2gDla^2}\) + ∑k \(\frac{Q^2}{2gA^2}\)

input the values;

hf= 130.274

Power= dwQ(H +hf) = 62.4 x 1.25 x (50 + 130.274)

= 25.566hp

Therefore,

Power = 25.566 x 0.746= 19.07kW

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The problem at hand deals with calculating various thermodynamic properties of a gas mixture that is being separated by a spiral-wound, nonporous cellulose acetate membrane separator.

The permeate that is produced by the separator contains 95 mol% pure H2, and no ethane, while the relative split ratio (separation factor, SP) for H2 relative to methane is 47. The data that is given in the problem is as follows:FeedPermeateRetentatePhase conditionVaporVaporVaporTemperature, F8036365Pressure, psia36550365Enthalpy, Btu/lbmol855083808890Entropy, Btu/lbmol1.5204.222.742The required calculations are as follows:Calculating the Entropy change:We are required to calculate the irreversible production of entropy in Btu/h-R, the lost work in Btu/h, and the minimum work of separation in Btu/h. For these calculations, we require the entropy change between the Feed and Permeate streams.

From the given data, we have:SFeed = 1.520 Btu/lbmol SPermeate = 4.222 Btu/lbmolΔS = SPermeate - SFeed= 4.222 - 1.520 = 2.702 Btu/lbmol. KCalculating the Irreversible Production of Entropy:The formula for calculating the irreversible production of entropy is given by,  Irreversible Production of Entropy (S dot) = Qrev/Ts  Here, Qrev = - TΔS  Since the temperature difference between the Feed and Permeate streams is negligible, we can assume that the temperature of the surroundings, i.e. 80F = 540 R is the same as that of the streams. Hence, the temperature of the streams can be taken as the temperature of the surroundings.

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Arrows shot from untuned bows are likely to have inconsistent and inaccurate flight paths.

When a bow is not properly tuned, it means that the various components of the bow (limbs, string, and arrow rest) are not working in harmony, leading to imprecise arrow release. Consequently, arrows shot from untuned bows may wobble, drift, or experience "porpoising" is up and down oscillation during flight. These irregularities can cause the arrow to miss the intended target or have unpredictable impact points. Therefore, it is crucial to tune a bow properly to ensure better arrow flight, improved accuracy, and overall enhanced shooting performance.

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Answer:

my friend here justin

Explanation:

hes already taken

Answer:

Industrial Engineers study various types of math including calculus, numerical analysis, statistics, linear algebra, numerical methods, operations research, etc. We do not necessarily use these in our day-to-day activities, but they help to build an analytical mindset that many employers value.

You are surely going to have commercial subjects , honestly when doing engineering every type of math is taught.

Answer:

Objects that float on water have densities less than the density of water; those that do not float on water have densisties greater than the density of water:

Float on water:  d < 0.0361 lb/in³ (where d denotes denisity)

Do not float on water:  d > 0.0361 lb/in³

Explanation:

I don't know if this works for it or not?

Answer:

Explanation: Three-phase power is a three-wire ac power circuit with each phase ac signal 120 electrical degrees apart

Here is a script in python to calculate the distance a projectile would travel for a given firing angle. The formula that can be used for this calculation is distance = (initial_velocity^2 / gravity) * sin(2 * firing angle). Using the inputs mentioned below, the script will calculate the distance that the projectile will travel in meters and miles. The result will be displayed with two decimal places.

Please find the code below:-

import mathdef projectile_distance():    print("Please enter the firing angle in degrees (0-81): ")    angle = int(input())    if angle > 81 or angle < 0:        print("Error: Please enter the firing angle between 0 and 81")        projectile_distance()    else:        print("Please enter the initial velocity of the projectile in m/s: ")        velocity = float(input())        gravity = 9.8        distance_m = (velocity ** 2 / gravity) * math.sin(math.radians(2 * angle))        distance_mi = distance_m / 1609.344        print("The projectile will travel a distance of " + str(round(distance_m, 2)) + " meters or " + str(round(distance_mi, 2)) + " miles.")projectile_distance()

This script will ask the user to enter the firing angle in degrees between 0 and 81. If the angle is not within this range, an error message will be displayed, and the user will be asked to enter the angle again. Once a valid angle is entered, the user will be asked to enter the initial velocity of the projectile in meters per second.

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Answer:

the elevation of the water surface over the obstruction is highest at 1.341 m

the maximum height of the obstruction h = 0.159 m

Explanation:

From the given information:

The diagrammatic expression for the water profile showing a rectangular channel  with 3 cm width carrying a 4 m3/s of water at a depth of 1.5 m with an obstruction 15 cm high is placed across the channel can be seen in the diagram attached below.

To calculate the elevation of the water surface over the obstruction, we need to  determine the following:

a. the velocity of the channel

b. the froude number at the upstream of the obstruction

c. the specific energy level

To start with the velocity V of the channel.

\(V_1 = \dfrac{Q}{A} \\ \\ V_1 = \dfrac{4 \ m^3/s}{(3 \times 1.5 ) m^2 } \\ \\ V_1 = \dfrac{4 \ m^3/s}{4.5 \ m^2}\)

\(V_1 = 0.88 \ m/sec\)

The froude number  at the upstream of the obstruction

\(F _{\zeta} = \dfrac{V_1}{\sqrt{gy__1}}\)

\(F _{\zeta} = \dfrac{0.88}{\sqrt{9.81 \times 1.5}}\)

\(F _{\zeta} = \dfrac{0.88}{\sqrt{14.715}}\)

\(F _{\zeta} = \dfrac{0.88}{3.836}\)

\(F _{\zeta} =0.229\)

\(F _{\zeta} \simeq0.3\)  which is less than the subcritical flow.

Similarly, the specific energy level for this process can be expressed as:

\(E_1 = \dfrac{V_1^2}{2g}+y_1\)

\(E_1 = \dfrac{0.88^2}{2 \times 9.81 }+1.5\)

\(E_1 = \dfrac{0.7744}{19.62 }+1.5\)

\(E_1 =0.039469+1.5\)

\(E_1 =1.539469\)

\(E_1 \simeq1.54 \ m\)

\(E_2 + \Delta z = E_1\)

\(E_2= E_1 - \Delta z\)

\(E_2= (1.54 - 0.15) \ m\)

\(E_2=1.39 \ m\)

Suppose ;

\(V_1 y_1 = V_2y_2\\ \\ Then; \ making \ V_2 \ the \ subject \ of \ the \formula\ we \ have: \\ \\ \\V_2 = \dfrac{V_1 y_1}{y_2} ---- (1)\)

From the energy equation:

\(E_2 + \Delta z = E_1\)

we can now substitute the above derived parameter and have :

\(E_2 + \Delta z=y_1 + \dfrac{V_1^2}{2g}\)

\(E_2 =y_1 + \dfrac{V_1^2}{2g} - \Delta z\)

\(E_2 =y_2 + \dfrac{V_2^2}{2g}\)

replace the value of \(V_2\) =\(\dfrac{V_1 y_1}{y_2}\)  in equation (1), we have:

\(E_2 =y_2 + \dfrac{( \dfrac{V_1y_1}{y_2})^2}{2g}\)

\(E_2 =y_2 + \dfrac{ {V_1^2y_1^2}}{2gy_2^2}\)

\(E_2 \times y_2^2 =y^3_2 + \dfrac{ {V_1^2y_1^2}}{2g}\)

\(y^3_2 - E_2y^2_2 + \dfrac{V_1^2y_1^2}{2g}=0\)

Replacing our values now; we have:

\(y^3_2 - 1.39 \times y^2_2 + \dfrac{0.88^2 \times 1.5^2}{2 \times 9.81}=0\)

\(y^3_2 - 1.39 \times y^2_2 + \dfrac{1.7424}{19.62}=0\)

\(y^3_2 - 1.39 \times y^2_2 + 0.0888=0\)

\(y^3_2 - 1.39 y^2_2 + 0.0888=0\)

\(y_2 = 1.341 \ m \\ \\ y_2 = - 0.232 \ m \\ \\ y_2 = 0.281 \ m\)

Therefore,the elevation of the water surface over the obstruction is highest at 1.341 m

What is the maximum height of the obstruction that will not cause a rise in the water surface upstream

In order to determine the maximum height , we need to first estimate the rise in water level surface of \(\Delta z\)

\(\Delta z\) = 1.5 - (1.341+ 0.15) m

\(\Delta z\) =  (1.5 - 1.491) m

\(\Delta z\) = 0.009 m

Finally, the maximum height of the obstruction h = (0.009 + 0.15 )m

the maximum height of the obstruction h = 0.159 m

The statement which is not true is z is available to code that is written outside the circle class.

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The given code snippet declares a global variable named "foo" in a C-style language. It does not provide any information about the type or initial value of the variable.

The code does not include any function definitions or statements that utilize the variable. Therefore, the primary purpose of this code seems to be the declaration of the global variable "foo."

In C-style languages, global variables are declared outside of any function and can be accessed by any part of the program. They have a global scope and are accessible across different functions. However, relying heavily on global variables can make the code harder to understand and maintain. It is generally considered a good practice to limit the use of global variables and instead use local variables within functions, passing necessary values as parameters.

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A manufacturer of circuit cards aims to develop an apparatus for subjecting them to rapid thermal transients using forced convection, characterized by the relation Nuj = CRemPr^m, where m = 0.8 and n = 0.33.

To achieve rapid thermal cycling and minimize disruption to production schedules, the manufacturer needs an apparatus that can impose controlled thermal stresses on the circuit cards. Forced convection, which involves the movement of fluid (air or liquid) over the surface of the cards, is an effective method for achieving rapid heat transfer.

The relation Nuj = CRemPr^m is a dimensionless correlation equation known as the Nusselt number correlation. It relates the Nusselt number (Nu) to the Reynolds number (Re) and the Prandtl number (Pr). The Nusselt number represents the convective heat transfer coefficient, which determines the rate of heat transfer between the fluid and the surface. The Reynolds number characterizes the flow regime, indicating whether the flow is laminar or turbulent, while the Prandtl number represents the ratio of momentum diffusivity to thermal diffusivity of the fluid.

In the given relation, the values of m = 0.8 and n = 0.33 determine the correlation exponents. These values have been determined through experimental data and are specific to the system being studied. The manufacturer needs to determine the appropriate values of the constant C based on the specific conditions and characteristics of their apparatus and circuit cards.

By using the Nuj = CRemPr^m relation, the manufacturer can design and optimize their thermal cycling apparatus to achieve the desired rapid thermal transients. This will allow them to perform accelerated thermal stress tests on the circuit cards, identifying any defective joints or potential failure points before the product is released to the customer. Implementing such tests in the manufacturing process will help ensure the reliability and quality of the electronic modules, reducing the risk of failures caused by thermal cycling-induced stresses.

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Answer:

When two fair dice are rolled, 6×6=36 observations are obtained.

P(X=2)=P(1,1)=

36

1

​

P(X=3)=P(1,2)+P(2,1)=

36

2

​

=

18

1

​

P(X=4)=P(1,3)+P(2,2)+P(3,1)=

36

3

​

=

12

1

​

P(X=5)=P(1,4)+P(2,3)+P(3,2)+P(4,1)=

36

4

​

=

9

1

​

P(X=6)=P(1,5)+P(2,4)+P(3,3)+P(4,2)+P(5,1)=

36

5

​

P(X=7)=P(1,6)+P(2,5)+P(3,4)+P(4,3)+P(5,2)+P(6,1)=

36

6

​

=

6

1

​

P(X=8)=P(2,6)+P(3,5)+P(4,4)+P(5,3)+P(6,2)=

36

5

​

P(X=9)=P(3,6)+P(4,5)+P(5,4)+P(6,3)=

36

4

​

=

9

1

​

P(X=10)=P(4,6)+P(5,5)+P(6,4)=

36

3

​

=

12

1

​

P(X=11)=P(5,6)+P(6,5)=

36

2

​

=

18

1

​

P(X=12)=P(6,6)=

36

1

​

Therefore, the required probability distribution is as follows.

Then, E(X)=∑X

i

​

⋅P(X

i

​

)

=2×

36

1

​

+3×

18

1

​

+4×

12

1

​

+5×

9

1

​

+6×

36

5

​

+7×

6

1

​

+8×

36

5

​

+9×

9

1

​

+10×

12

1

​

+11×

18

1

​

+12×

36

1

​

=

18

1

​

+

6

1

​

+

3

1

​

+

9

5

​

+

6

5

​

+

6

7

​

+

9

10

​

+1+

6

5

​

+

18

11

​

+

3

1

​

=7

E(X

2

)=∑X

i

2

​

⋅P(X

i

​

)

=4×

36

1

​

+9×

18

1

​

+16×

12

1

​

+25×

9

1

​

+36×

36

5

​

+49×

6

1

​

+64×

36

5

​

+81×

9

1

​

+100×

12

1

​

+121×

18

1

​

+144×

36

1

​

=

9

1

​

+

2

1

​

+

3

4

​

+

9

25

​

+5+

6

49

​

+

9

80

​

+9+

3

25

​

+

18

121

​

+4

=

18

987

​

=

6

329

​

=54.833

Then, Var(X)=E(X

2

)−[E(X)]

2

=54.833−(7)

2

=54.833−49

=5.833

∴ Standard deviation =

Var(X)

​

=

5.833

​

=2.415

Answer:

A. $28

Explanation:

We have the load to be 240V

6000W will be converted to kilowatts

6000/1000 = 6kW

Time heater runs for 36 hours

Cost of electricity = $0.13/Kwh

The question needs us to find cost of running this electric heater

Total kilowatts

= 6kw x 36 hours

= 216kwh

Then the total cost = 216 x $0.13

= 28.08

= $28

Put your printer through a hard reset. Try turning off both the printer and your computer, then restarting both if that doesn't fix the problem. Then try to remove and reinstall your printer's driver.

A problem with the printer itself may exist if the status of your printer reads "Printer in error state." Check to see if the printer is on and wired or wirelessly linked to your computer. Make sure the cover is closed and the paper isn't jammed, and check if there isn't enough paper or ink.

Of all printer errors, paper jams are arguably the most dreadful. There are a few problems that might be present when it comes to smudges, faded lettering, and poor image quality.

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Formation damage control is crucial in petroleum engineering to maintain well productivity. It involves mitigating factors that hinder fluid flow, such as solids deposition, clay swelling, and fluid incompatibility.

Formation damage control is essential in petroleum engineering to prevent or minimize the impairment of well productivity caused by various mechanisms. It involves identifying and addressing factors that can hinder fluid flow within the reservoir formation. Formation damage can occur due to factors such as solids deposition, clay swelling, emulsion formation, fluid incompatibility, and organic/inorganic scale precipitation. These issues can restrict the flow of hydrocarbons from the reservoir to the wellbore, reducing production rates and overall recovery. Basic principles of formation damage control include implementing effective drilling and completion practices, utilizing suitable drilling fluids and additives, optimizing well stimulation techniques, and conducting thorough reservoir characterization and analysis. Proper formation damage control strategies aim to maximize reservoir permeability, minimize the impact of drilling and production operations on the formation, and enhance overall well productivity and hydrocarbon recovery.

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Answer:

Hence the magnitude of the pure moment m will be \(2\times 10^5.\)

Explanation:

Now,

We know that,

\(\frac{M}{I} = \frac{E}{R}\)

Thus, \(M =\frac{EI}{R}\)

Here

R = 10000 mm  

\(I=\frac{1}{12}\times 120\times 10^{3}\\= 10^{4} mm^{4}\)

\(E=2\times 10^{5}n/mm^{2}\\\\E=2\times 10^{5}n/mm^{2}\\\\M={(2\times 10^{5}\times 10^{4})/{10000}}\\\\M=2\times 10^{5}\)

Hence, the magnitude of the pure moment m will be \(2\times 10^5.\)

Answer:

speed(0)

square_length = int(input("What is the length of the square?"))

def draw_square():

   pendown()

   for i in range(4):

       forward(square_length)

       left(90)

   penup()

penup()

setposition(-200, -200)

draw_square()

penup()

setposition(-200, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, 200 - square_length)

draw_square()

penup()

setposition(200 - square_length, -200)

draw_square()Explanation:

An unethical action can harm the reputation of all the entities mentioned. Let's examine each one: The person who committed the act: When someone engages in unethical behavior, their personal reputation can be severely damaged.


Their actions reflect poorly on their character and integrity, leading to a loss of trust and respect from others.The company where the act took place: If an unethical action occurs within a company, it can tarnish the company's reputation. Customers, clients, and stakeholders may lose trust in the company's ethics and question its values. This can result in a decline in business, negative publicity, legal consequences, and damage to the overall brand image.The entire automotive aftermarket: If the unethical action within a company or individual spreads to the broader automotive aftermarket industry, it can have negative consequences for the reputation of the entire sector. It may lead to a loss of confidence among customers, suppliers, and other industry stakeholders. Such incidents can create skepticism about the industry's ethics and impact its credibility as a whole.Therefore, an unethical action can have far-reaching repercussions, affecting the reputation of the individual involved.

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Explanation:

print() has a variable number of parameters. this is the answer.

hope this helps you

have a nice day

Answer:

4

Explanation:

Answer:

No matter what u post on a football page, some fatherless dude will either say "pessi" or "penaldo"

The quality control engineer at a petrochemical refinery is in a matrix position.

An engineer can be defined as a person who solves technical problems which are related to a product or a good. These are also engaged in developing new products full of the improvement of the efficiency and quality of the product.

A matrix's profile is determined by the object's row and column numbers, in that order.

Petrochemicals are indeed the chemical byproducts of the processing of gasoline. Some petroleum-derived chemical compounds can also be produced from these other oil and coal.

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Using the concept of equation and fractions, the capacity of the mug is 7/6

To find the capacity of the mug, we can calculate the remaining space in the mug, which is 5/7 (2/7 full) of the total capacity.

Given:

Water in the mug = 1/3 cup

Remaining space in the mug = 5/7 of the total capacity

Let's denote the total capacity of the mug as x.

According to the given information, the water in the mug (1/3 cup) and the remaining space (5/7 of x) should add up to the total capacity (x).

(1/3) + (5/7)x = x

To solve this equation, we can eliminate the fractions by finding a common denominator.

Solving the equation;

x = 7/6

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Phishing, spear phishing, whaling, vishing, dumpster diving, and piggybacking are all types of social engineering attacks that are designed to manipulate people into divulging confidential information or taking actions that benefit the attacker.

Phishing is a type of social engineering attack where the attacker sends fraudulent emails or messages that appear to be from a legitimate source, in order to trick the victim into giving away sensitive information or clicking on a malicious link.

Spear phishing is a more targeted form of phishing where the attacker researches the victim and sends customized messages that appear to be from a trusted source, making it more likely for the victim to fall for the scam.

Whaling is a type of spear phishing that specifically targets high-level executives or individuals with access to sensitive information. The attacker uses social engineering tactics to convince the victim to take a specific action, such as wire transfer of funds or revealing confidential information.

Vishing (voice phishing) is a social engineering attack that uses voice calls or voice messages to trick the victim into giving away sensitive information. The attacker may impersonate a trusted source, such as a bank or government agency, to gain the victim's trust.

Dumpster diving involves searching through a person's trash or recycling to find confidential information, such as account numbers or passwords.

Piggybacking is a physical social engineering attack where the attacker gains unauthorized access to a restricted area by following closely behind an authorized individual, taking advantage of their access privileges.

Overall, social engineering attacks are a growing concern for individuals and organizations, as attackers continue to find new and creative ways to manipulate people into giving away sensitive information or taking actions that benefit them. It is important to be aware of these attack types and to take steps to protect yourself and your organization from these types of threats.

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Answer:

Yes it is possible. Grain size is often determined by the rate so Firstly reduce the average grain diameter of an undeformed alloy specimen form 0.040 mm to 0.10mm

Answer:

There are a few key benefits to a pre-construction and design specialist taking an interdisciplinary approach:

To maximize employability options. Having exposure to different fields and skills makes a specialist a more versatile and attractive job candidate. They can work across multiple areas of design, planning, architecture and construction.

To draw on a varied creative tool set. Exposure to fields like architecture, engineering, economics, sustainability and more provides many perspectives and solutions to tapping into. This leads to more innovative and well-rounded design thinking.

To integrate well with other team members. Understanding the methods, priorities, constraints and languages of fields like architecture, engineering, planning, and construction allows a specialist to collaborate more effectively. They can translate across disciplines and facilitate joined-up thinking.

To understand constraints and optimally balance priorities. No design or pre-construction problem has limitless options. An interdisciplinary approach helps gain insights into the constraints each field operates under and how to optimize solutions across ecological, economic, functional and other priorities.

To consider impacts holistically. Many impacts, like environmental sustainability, cost efficiency and user experience, span multiple disciplines. An interdisciplinary mindset is needed to evaluate options based on overall impact, not just impacts within one area of focus.

Of these options, I believe "To integrate well with other team members" is the strongest summary of why an interdisciplinary approach is so valuable for this type of specialist role. Understanding other fields in depth helps in collaborating, communicating clearly, addressing concerns proactively and finding optimal compromise - all of which are key to successfully interweaving different areas of expertise on a team.

Explanation:

The combination of a 3200 ω resistor, a 250.0 mh inductor, and a 5.0 nf capacitor in parallel results in a complex impedance. , the total impedance of the circuit is: Ztotal = 1304.5 - j242.8 Ω


The impedance of the resistor is simply its resistance, which is 3200 ω. The impedance of the inductor can be calculated using the formula: Zl = jωL where ω is the angular frequency (in radians per second) and L is the inductance in henries. In this case, ω can be calculated using the formula: ω = 2πf.


Using this value and the inductance of 250.0 mh (0.25 H), we get: Zl = j(6283.2)(0.25) = j1570.8 Ω The impedance of the capacitor can be calculated using the formula: Zc = 1/(jωC) where C is the capacitance in farads. In this case, the capacitance is 5.0 nf (5.0 x 10^-9 F), so we get: Zc = 1/(j(6283.2)(5.0 x 10^-9)) = -j31.83 Ω.

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a. The farthest horizontal distance the jet will strike the ground is calculated using the formula:

D = √[(2gh)/C], where g = 9.81 m/s² is the acceleration due to gravity and C = 0.9 is the coefficient of discharge.

By substituting h = 4 - H (where H is the depth of water above the orifice) and d = 1.5 m into the formula, we can find:

D = √[(2g(4 - H))/C].

Therefore, the farthest horizontal distance the jet will strike the ground is given by:

D = √[(2 × 9.81 × 4)/0.9] = 8.22 meters (rounded off to 2 decimal places).

b. To find the value of "h" for the jet to strike the farthest point on the ground, we can use the formula:

D = √[(2gh)/C], where g = 9.81 m/s² is the acceleration due to gravity and C = 0.9 is the coefficient of discharge.

By substituting d = 8.22 meters and solving for H, we get:

H = 4 - (D²C/2g) = 4 - (8.22² × 0.9/(2 × 9.81)) = 0.653 meters (rounded off to 3 decimal places).

Therefore, the value of "h" for the jet to strike the farthest point on the ground is 4 - 0.653 = 3.347 meters (rounded off to 3 decimal places).

c. The velocity of the water as it goes out of the orifice for it to strike the farthest point on the ground can be calculated using the formula:

V = √[2gh].

By substituting d = 8.22 meters and h = 3.347 meters into the formula, we can find:

V = √[2g × 3.347] = 6.514 meters/second (rounded off to 3 decimal places).

The velocity of the water as it goes out of the orifice for it to strike the farthest point on the ground is 6.514 m/s.

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