Consider a T = 0) ideal gas of spin- fermions in a three-dimensional potential that gives single-particle energy levels a €= for vino n=1,2,3,... (a) Find the Fermi energy for such a system with N p

Answers

Answer 1

The formula to find the Fermi energy of such a system is 1.206 × (Np /V)2/3 where V is the volume of the system.

Consider a T = 0) ideal gas of spin-1/2 fermions in a three-dimensional potential that gives single-particle energy levels a€= for vino n=1,2,3,...(a) Find the Fermi energy for such a system with Np. Fermi energy:

The Fermi energy of a system is the highest energy level that is filled by electrons at absolute zero temperature. At T = 0 K, the electrons fill up to the Fermi energy level. Since the Fermi-Dirac distribution function goes from 1/2 to 0 at E = EF and the probability of an electron having energy above the Fermi energy is very small, EF represents the energy of a system at T = 0.0.

For a system of spin-1/2 fermions, the total number of electrons is given by Np and the single-particle energy levels are given by a€= for vino n=1,2,3,...Therefore, the number of electrons at an energy level En is given by the Fermi-Dirac distribution function:f(E) = 1 / [exp(E - EF) / kT + 1]At T = 0 K, the denominator becomes very large for E > EF and very small for E < EF. Therefore, at T = 0, f(E) = 1 if E < EF and 0 if E > EF.

The total number of electrons in the system is given by:

Np = ∑n[2/(exp(En - EF) / kT + 1)]

Since the system is filled up to the Fermi energy, we can rewrite this equation as:

Np = ∑n[2] for En ≤ EF

Therefore, the Fermi energy can be obtained by solving for EF:

Np = ∑n[2/(exp(En - EF) / kT + 1)]≅ ∑n[2] for En ≤ EF2EF3∑n=1(1/n2/3) = Np

Fermi energy for the system with Np of spin-1/2 fermions is 1.206 × (Np /V)2/3

Given, the single-particle energy levels for a system of spin-1/2 fermions are a€= for vino n=1,2,3,...The number of electrons in the system is given by Np.

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Related Questions

Help me please Which of the following statements best describes the atoms and molecules that make up a glass
filled with water?
O The atoms and molecules of the liquid water are moving, while the atoms and molecules of the glass are not
moving.
The atoms and molecules of neither the liquid water nor the glass are moving.
O The atoms and molecules of the liquid water are not moving, while the atoms and molecules of the glass are
moving.
The atoms and molecules of both the liquid water and the glass are moving.

Answers

Answer:

The correct option is;

The atoms and molecules of the liquid water are moving, while the atoms and molecules of the glass are not moving

Explanation:

Matter that exist in the liquid or gaseous state consist of molecules that move freely about in the entire containing medium for gas, while the molecules move freely  in the portion of the container occupied by the fluid in the case of liquid fluids

However, the molecules of a solid are fixed within the current shape of the solid and are only free to vibrate within a fixed location and the allow the passage of subatomic particles such as electrons

As such, the glass cup being a solid, consists of molecules fixed in space, while the liquid water consists of molecules which can translate within the portion of the volume of the glass filled with the water.

A 500,000kg rocket is accelerating straight up. Its engines produce 10,000,000N, what would its acceleration be

Answers

From,

Force = Mass * Acceleration

10000000N = 500000kg * a

Divide by 500000kg both sides

10000000/500000 = 500000a/500000

20m/s^2 = a


Acceleration is 20m/s^2

An athlete running the velocity 3m/s due east is confronted with two trade winds. One wind travelling at 10m/s in a direction north 65degrees east and another wind travelling at 8m/s in a direction south 70degrees east. Find the resultant velocity and direction of the athlete ​

Answers

Answer:

v = 10.09 m / s,   8.78 North of East

Explanation:

The easiest way to solve this exercise is to decompose the velocities into a coordinate system, where the x-axis coincides with the West-East direction and the y-axis coincides with the South-North direction.

in a control system, an accelerometer consists of a 4.47-g object sliding on a calibrated horizontal rail. a low-mass spring attaches the object to a flange at one end of the rail. grease on the rail makes static friction negligible, but rapidly damps out vibrations of the sliding object. when subject to a steady acceleration of 0.720g, the object should be at a location 0.475 cm away from its equilibrium position. find the force constant of the spring required for the calibration to be correct.

Answers

The force constant of the spring needed for the calibration to be correct is 0.092 N/m.

A control system is being designed, and an accelerometer contains a 4.47-g object sliding on a calibrated horizontal rail. A low-mass spring is used to connect the object to a flange at one end of the rail. Static friction is negligible on the rail due to grease, but the rapid damping of the sliding object's vibrations occurs. If subjected to a constant acceleration of 0.720g, the object should be 0.475 cm away from its equilibrium position. To make the calibration precise, determine the force constant of the spring.

The solution to the problem is as follows: Formula for the spring constant, k = mg / where, m = mass of the object = acceleration due to gravity = displacement of the object = spring constant. Substitute the values given in the problem statement

m = 4.47 g = 0.00447 kg = 9.8 m/s²x = 0.475 cm = 0.00475

force constant, k = 0.00447 kg × 9.8 m/s² / 0.00475 m= 0.092 N/m.

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name the types of forces​

Answers

Answer:

Frictional Force

Gravitational Force

Tension Force

Electrical Force

Normal Force

Magnetic Force

Air Resistance Force

Consider n moles of a gas, initially confined within a volume V

and held at temperature T. The gas is expanded to a total volume αV

, where α is a constant, by (a) a reversible isothermal expansion,

(14. 7) Consider n moles of a gas, initially confined within a volume V and held at temperature T. The gas is expanded to a total volume aV, where a is a constant, by (a) a reversible isothermal expans

Answers

The negative sign in the equation indicates that work is done on the system during the expansion process.

The reversible isothermal expansion of a gas is a process in which the gas expands or contracts gradually and slowly to maintain the temperature constant throughout the process. The gas is initially confined within a volume V and held at temperature T. The gas is expanded to a total volume αV, where α is a constant, by (a) a reversible isothermal expansion, according to the given problem.

In an isothermal process, the temperature remains constant. Therefore, if a reversible isothermal expansion takes place, then we can say that the gas is expanded or contracted slowly, so that the temperature remains constant throughout the process.

The work done by the gas during reversible isothermal expansion is given by:

W = -nRT ln (α)

Where,
n = Number of moles of gas
R = Universal gas constant
T = Temperature
α = Ratio of final volume to initial volume

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If a car traveled 60 m in 30 s, what is the velocity?*

Answers

Answer:

6.56168

Explanation:

Help: The diagram below illustrates a light ray bouncing off a surface. Fill in the boxes with the correct terms.

Help: The diagram below illustrates a light ray bouncing off a surface. Fill in the boxes with the correct

Answers

The correct terms that fills the box are;

(i) The incident ray

(ii) The normal

(iii) The reflected ray

(iv) The angle of incident

(v) The reflected angle

What is the terms of the ray diagram?

The terms of the ray diagram is illustrated as follows;

(i) This arrow indicates the incident ray, which is known as the incoming ray.

(ii) This arrow indicates the normal, a perpendicular line to the plane of incidence.

(iii) This arrow indicates the reflected ray; the out going arrow.

(iv) This the angle of incident or incident angle.

(v) This is the reflected angle or angle of reflection.

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A turntable must spin at 33.3 rev/min (3.49 rad/s) to play an old-fashioned vinyl record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 1.70 revolutions, starting from rest? The turntable is a uniform disk of diameter 30.5 cm and mass 0.220 kg.

Answers

ANSWER:

0.00145 J

STEP-BY-STEP EXPLANATION:

Using the rotational form of the kinematic equation to find α:

\(\omega^2_f=\omega^2_i+2\alpha\theta\)

It started form rest:

\(\begin{gathered} \omega^{}_i=0\text{ rad/s} \\ \theta=1.7\text{ rev }=3.4\pi\text{rad} \end{gathered}\)

Solving for α:

\(\begin{gathered} \alpha=\frac{\omega^2_f}{2\theta} \\ \alpha=\frac{3.49^2}{2\cdot3.4\pi} \\ \alpha=0.57rad/s^2 \end{gathered}\)

The torque is given by the formula,

\(\begin{gathered} \tau=I\alpha \\ \text{for a uniform disk} \\ I=m\cdot\frac{r^2}{2},\text{ along the vertical a}\xi s\text{ in the center.} \\ \text{Therefore,} \\ \tau=m\cdot\frac{r^2}{2}\cdot\alpha,r=\frac{0.305}{2}=0.1525 \\ \text{ replacing} \\ \tau=0.22\cdot\frac{0.1525^2}{2}\cdot0.57 \\ \tau=0.00145\text{ J} \end{gathered}\)

The speed, v, of an object moving along a straight line can be given in terms of time, t by v = at +b/(t-c)where a, b, c are constants. Assume, the expression is physically correct. If the dimensions of v are L/T, determine the dimensions of the terms a, b and c. Carefully layout your procedure.

Answers

Given

\(v=at+\frac{b}{t-c}\)

Procedure

Dimensions of v are L/T

The answer would be:

\(LT^{-2},L\text{ and T}\)

The letter a is multiplying to one dimension in time, so it must be a value of distance over two of time. LT^(-2)

The letter b is in the numerator so it must be a distance dimension. L

The letter c is being operated as a subtraction in the denominator so it must be time T

a gas is enclosed in a container fitted with a piston of cross-sectional area 0.150 m2. the pressure of the gas is maintained at 7,200 pa as the piston moves inward 19.5 cm. (a) calculate the work done by the gas. j (b) if the internal energy of the gas decreases by 6.40 j, find the amount of heat removed from the system by heat during the compression.

Answers


The amount of heat removed from the system by heat during the compression is 204.8 J.


(a) To calculate the work done by the gas, we need to use the formula:
W = F * d
F = P * A
where P is the pressure of the gas and A is the cross-sectional area of the piston
F = 7,200 Pa * 0.150 m^2
F = 1,080 N
W = F * d
W = 1,080 N * 0.195 m
W = 211.2 J



(b)  We can use the First Law of Thermodynamics, which states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
-6.40 J = Q - 211.2 J
Q = -6.40 J + 211.2 J
Q = 204.8 J

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24. 3 A young's double slit experiment is performed with three different colors of light: red, green, and blue. Rank the colors by distance between adjacent bright fringes from smallest to largest. (a) red, green, blue, (b) green, blue, red, (c) blue, green, red

Answers

(a) red, green, blue. the distance between adjacent bright fringes, also known as the fringe spacing, is inversely proportional to the wavelength of light. Red light has the longest wavelength, followed by green and then blue. Therefore, the fringe spacing is smallest for red light and largest for blue light.

In a Young's double slit experiment, when light passes through two narrow slits and forms an interference pattern on a screen, the fringe spacing is determined by the wavelength of the light. The fringe spacing is given by the equation:

s = λD / d,

where s is the fringe spacing, λ is the wavelength of light, D is the distance between the screen and the double slits, and d is the distance between the slits.

Since the distance D and the distance between the slits d are constant in this experiment, the fringe spacing is solely determined by the wavelength. The longer the wavelength, the smaller the fringe spacing, and vice versa.

Therefore, since red light has the longest wavelength, followed by green and then blue light, the fringe spacing is smallest for red light and largest for blue light. Thus, the correct ranking of the colors by the distance between adjacent bright fringes is (a) red, green, blue.

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Find the x and y components of each of the following vectors.

hyp = 15 m/s
theta = 150°
x = ?
y = ?

Find the x and y components of each of the following vectors.hyp = 15 m/stheta = 150x = ?y = ?

Answers

Answer:

x =

\( - 15 \times \frac{ \sqrt{3} }{2} \frac{m}{s} \)

y = 7.5m/s

a car cruising at 30 m/s (about 68 mph). if the kinetic friction coefficient between the tires and the road is 0.70 (when the road is dry), when the driver hits the brake, how far (approximately) will the car slide before it comes to a full stop? (g

Answers

The distance travelled by the car before it comes to a full stop is 65.59m if its initial velocity is 30m/sec.

Now, we need to find the distance of a car travelled, so we can use third equation of motion which is

v² - u² =2aS

where v is final velocity ,

u is the initial velocity

a is the acceleration

and S is the displacement of object

Since, final velocity of object is zero because car comes to rest

=>v=0,u=30m/sec, a=?,S=?

Now, we know that force applied by kinetic friction on car is given by =μmg where μ is coefficient of kinetic friction, m is the mass and g is the acceleration due to gravity

=>F=μmg ------eq1

Now,μ=0.70,m=?,g=9.8m/sec²

We also know that F=ma------eq2

Comparing eq1 and eq2

=>μmg=ma

=>a=μg

=>a=0.70ˣ9.8

=>a=6.86m/sec²

Now, 0² - (30)² = 2ˣ(-6.86)ˣS

=>900=2ˣ6.86ˣS

=>S=900/13.72

=>S=65.59m

Hence, car will travel 65.59m before coming to rest

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The change in the momentum of an object is represented by the following formula:
Impulse = (Force)(time) = change in momentum
I = F • t = pfinal – pinitial
A 1.0 kg rabbit traveling east at 10 m/s spots a predator, turns around, and then begins to travel west at 21 m/s.
What is the change in momentum of the rabbit, and what is another term for this concept?

The rabbits change of momentum is

A. 31 kg•m/s east

B. 31 kg•m/s west

C. 15.5 kg•m/s, west

D. 15.5 kg•m/s, east

This value can also be referred to as

E. Collisions

F. Potential energy

G. Kinetic energy

H. Impulse

Please help will mark brainliest

Answers

Hi there!

Recall that:

Change in momentum = mass × change in velocity

Or:

Δp = mΔv = m(vf - vi)

Plug in the given values. We can assign east to be positive and west to be negative in this instance (Velocity is a vector with direction).

Thus:

Δp = (1)(-21 - 10) = -31 kgm/s OR 31 kgm/s WEST.

The correct answer is B.

Change in momentum is EQUIVALENT to the quantity of IMPULSE.

The correct answer is H.

Compare how radiowaves and gamma rays are produced ( 6 marks )

Answers

When compared to each other, radio waves are produced by the movement of negatively-charged electrons whereas gamma rays are produced in nuclear reactions.

How are radio waves and gamma rays produced?

The back-and-forth movement of negatively charged electrons inside an antenna produces radio waves.

Radio waves have the longest wavelengths of all the waves in the electromagnetic spectrum. Radio waves are typically found at frequencies of 300 gigahertz and below.

On the other hand, nuclear explosions, lightning, and radioactive decay generate gamma rays.

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The potential of the electric field produced by point charge at any point (x,y,z) is given by V=3x2+5, where x, y are in metres and V is in volts. The intensity of the electric field at (−2,1,0) is:
A) +17Vm^-1
B) -17m^-1
C) +12 Vm^-1
D) -12 Vm^-1

Answers

V = 3 x 2 + 5 gives the potential of the electric field created by a point charge at any point (x, y, z), where x and y are measured in meters and V is measured in volts. At (2, 1, 0), the electric field has a strength of +12 Vm-1. Here the correct answer is option C.

The electric field E at any point in space is given by the negative gradient of the potential V at that point. That is,

E = -∇V

where ∇ is the gradient operator.

In this case, the potential is given by V = 3x^2 + 5, so the gradient of V is

∇V = ( ∂V/∂x, ∂V/∂y, ∂V/∂z )

= ( 6x, 0, 0 )

Evaluating this at the point (-2, 1, 0) gives

E = (6x, 0, 0)

= (-12, 0, 0)

The magnitude of the electric field intensity is given by

|E| = √(Ex^2 + Ey^2 + Ez^2)

= √((-12)^2 + 0^2 + 0^2)

= 12 Vm^-1

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what is the process of subduction

Answers

Answer:

Subduction is a geological process that takes place at convergent boundaries of tectonic plates where one plate moves under another and is forced to sink due to high gravitational potential energy into the mantle. Regions where this process occurs are known as subduction zones.

Given the equation describing the displacement of an object undergoing simple harmonic motion, Find the maximum acceleration of the object.

Answers

The maximum acceleration of the object is 10.94 x 10² m/s².

The equation of displacement is given as,

y(t) = 4.8 cos(15.1 t)

It is in the form, y(t) = A cos(ωt)

So, the amplitude of the SHM, A = 4.8 m

Angular frequency, ω = 15.1 s⁻¹

The maximum acceleration,

a(max) = -Aω²

the -ve sign indicates that the acceleration is acting towards the mean position.

a(max) = 4.8 x 15.1²

a(max) = 10.94 x 10² m/s²

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An object has a mass of 156 g and a volume of 233 cm³. What is its density? (Give your answer in
g/cm³ to 2 decimal places).
g/cm³
Reduce contrast
Show lin
12✔ 86%

Answers

An object has mass of 156 g and volume of 233 cm³. it's density is 0.67g/\(cm^{3}\)

What do you mean by density?

The mass per unit of volume of a substance is known as its density (volumetric mass density or specific mass). Although Latin letter D may also be used, the sign most frequently used for density is (the lower case Greek letter rho). The formula for the density is mass divided by volume:

ρ \(=\frac{m}{v}\)

where m is mass, V is volume, and ρ is the density. Density is sometimes roughly characterized as the weight per unit volume, while this is incorrect scientifically; this quantity is more precisely known as specific weight.

For a pure substance the density has same numerical value as its mass concentration. Different materials usually have the different densities, and density may be relevant to buoyancy, purity and packaging. Osmium and iridium are the densest known elements at the standard conditions for temperature and pressure.

given,

The mass=156 g

The volume= 233\(cm^{3}\)

so,

The density = mass/volume

                    = 156/ 233

                     = 0.6695g/\(cm^{3}\)

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A typical value for the dielectric constant of rubber is a minimum of 2. Give one reason why your experimental value was less than two!
What are the dependent and independent variables in thid experiment?

Answers

The independent variable in this experiment is the dielectric constant of rubber, and the dependent variable is the measured value. The typical value for the dielectric constant of rubber is a minimum of 2, but your experimental value could have been lower than two.

The dependent and independent variables in this experiment are not specified. Therefore, it is impossible to answer the question accurately. A typical value for the dielectric constant of rubber is a minimum of 2.

The dielectric constant is defined as the ratio of the electric flux density produced in a substance to that produced in a vacuum by the same electric field.

The dielectric constant is a measure of a substance's ability to store charge in an electric field. The dielectric constant of a substance indicates how easily it can be polarized in response to an applied electric field.

It varies with temperature, frequency, and pressure, among other factors.

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Which is directly proportional PLS HURRY
Which is directly proportional to your weight on a planet's surface?
A. Only your mass
B. Only the mass of the planet
C. Your mass and the mass of the planet
D. The distance from the surface to the center of the planet

Answers

Answer: B. Only the mass of the planet

Explanation:

the confusion on the concepts of mass and weight arises from the fact that the acceleration due to gravity is more or less constant in any place on the Earth's surface, thus the weight of an object is directly proportional to its mass. hope it helps <3

A subject is given a sugar pill and is told it may treat anxiety. This person may experience:

Answers

The answer is the answe

if the string breaks when its tension exceeds 22.5n, what is the maximum speed the object can have at the bottom of the path

Answers

If the string is at the breaking point at the bottom of the circle, then the speed of the object at this point is 7.82m/s.

The force transferred through a rope, string, or wire when pushed by forces acting from opposite sides is referred to as tension. The tension force is applied along the entire length of the wire and exerts an equal amount of strain on the bodies at each end. Every physical object that comes into contact with another one applies some sort of force.

At the bottom of the circle,

Let the maximum speed will be V.

It is given when the string breaks its tension exceeds 22.5N

it means, T=22.5N

now, we know,

In a Circular path,

⇒ \(\frac{mV^2}{r} = T-mg\)

⇒ \(V^{2}=\frac{r}{m}(T-mg)\)

⇒ \(V^{2}=r(\frac{T}{m} -g)\)

⇒ \(V=\sqrt{r(\frac{T}{m} -g)}\)

According to the question,

m = 0.275KG, r = 0.850m and T = 22.5N

Putting the values, We get,

⇒ \(V=\sqrt{(0.850)(\frac{22.5}{0.275}-9.80 )}\)

⇒ \(V=7.82m/s\)

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The complete question is:

A 0.275 Kg ball wings in a vertical circular path on a string L=0.850m long. If the string breaks when its tension exceeds 22.5N, what is the maximum speed the ball can have at the bottom before that happens?

a 180.00 kg roller-coaster car is pressed against a spring of constant 1,350 n/m and compresses it 2.50 meters. it is then released and rolls up an inclined portion of the track. how high up the incline will car roll before coming to a stop?

Answers

To determine how high up the incline the 180.00 kg roller-coaster car will roll before coming to a stop,

1. Calculate the potential energy stored in the compressed spring:
Potential energy (PE_ spring) = 0.5 × spring constant (k) × compression distance (x)^2
PE_ spring = 0.5 × 1,350 N/m × (2.50 m)^2
PE_ spring = 0.5 × 1,350 N/m × 6.25 m^2
PE_ spring = 4,218.75 J (joules)

2. Assume that all the potential energy in the spring is converted into gravitational potential energy when the car reaches its highest point on the incline:
PE_spring = PE_gravitational

3. Calculate the gravitational potential energy:
PE_gravitational = mass (m) × gravitational acceleration (g) × height (h)
Since we know PE_spring and m, and g is approximately 9.81 m/s^2, we can solve for h:
h = PE_spring / (m × g)

4. Plug in the values and solve for h:
h = 4,218.75 J / (180.00 kg × 9.81 m/s^2)
h ≈ 2.33 m

So, the roller-coaster car will roll approximately 2.33 meters high up the incline before coming to a stop.

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consider a planet whose rotation axis is not tilted with respect to its orbital plane. what are the seasons like on this planet?

Answers

As the planet orbits the sun, the angle at which the sunlight hits the planet's surface may change slightly, but this does not result in significant changes in the amount of sunlight that the planet receives.

On a planet whose rotation axis is not tilted with respect to its orbital plane, the seasons are not pronounced. This is because the amount of sunlight that the planet receives does not change significantly throughout the year.

In contrast, on a planet with a tilted rotation axis, the seasons are much more pronounced. As the planet orbits the sun, the angle at which the sunlight hits the planet's surface changes significantly, resulting in longer periods of sunlight in certain parts of the planet and shorter periods of sunlight in other parts. This leads to significant differences in temperature and weather patterns, resulting in the four distinct seasons that we experience on Earth.

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The earliest stethoscope was simply a wooden pipe open at both ends. The fundamental frequency of a 0.25-m stethoscope will cause resonance at approximately what distance along the basilar membrane from its base? (Note: Use 350 m/s for the speed of sound in air.)A.7 mm (14%)

Answers

Resonance will occur at approximately 125 mm (or 12.5 cm) along the basilar membrane from the base of the stethoscope.

To determine the approximate distance along the basilar membrane from the base where resonance will occur, we need to use the formula for the fundamental frequency of a closed pipe:

f = v/4L

Where f is the frequency, v is the speed of sound in air (which is given as 350 m/s), and L is the length of the pipe.

However, the stethoscope in question is open at both ends, which means that the formula for the fundamental frequency of an open pipe should be used instead:

f = v/2L

Where f, v, and L are defined as before.

Since the stethoscope is 0.25 m in length, we can plug in the values for f and v and solve for L:

f = v/2L

f = 350/2(0.25)

f = 700/0.5

f = 1400 Hz

Therefore, the fundamental frequency of the stethoscope is 1400 Hz.

To determine the distance along the basilar membrane from the base where resonance will occur, we need to use the formula:

d = v/2f

Where d is the distance, v is the speed of sound in air, and f is the fundamental frequency of the stethoscope.

Plugging in the values, we get:

d = 350/(2*1400)

d = 350/2800

d = 0.125 m = 125 mm

Therefore, resonance will occur at approximately 125 mm (or 12.5 cm) along the basilar membrane from the base of the stethoscope.

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The volume of a piece of wood (which floats in water) can be measured as shown. Write a brier paragraph to describe the procedure. State the volume of the wood.

Answers

When an item sinks under force, its volume can be calculated. For this reason, the item is fastened to another readily sinkable object. Since the floating object will sink in the water, its volume may be determined.

How can the volume of a piece of wood, an irregular solid that floats on water, be calculated?

One method to determine the volume of a floating object is to weigh it down using a heavy object. It's crucial to figure out the water's depth both with the heavy object submerged and with it pulling the floating object down into the water.

An object floats when the water's upward push balances the weight force acting on it. Untainted by water depth, the amount of the object immersed increases the water is probably upward push.

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how to calculate light year, minute and second?

Answers

Answer:

A light-year is the distance light travels in one year. How far is that? Multiply the number of seconds in one year by the number of miles or kilometers that light travels in one second, and there you have it: one light-year. It's about 5.88 trillion miles (9.5 trillion km).

Explanation:

which is the best definition of pitch

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Answer:

a black or dark viscous substance obtained as a residue in the distillation of organic materials and especially tars

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