Consider a finite square-well potential well of width 3.00×10−15 m that contains a particle of mass 1.88 GeV/c2. How deep does this potential well need to be to contain three energy levels? (This situation approximates a deuteron inside a nucleus.)

Explanation:

Explanation:

Pressure is defined as a Force over an

Area.

p=F/A

We can rearrange this to make the Force

the subject

F = p *A

The pressure is given as 1200 Pa.

We know a pascal is 1 Newton / Square

metre = N/m²

The area of a cube will be width * breadth

= 1.5 m * 1.5 m= 2.25 m²

So the force the cube is pushing down

with (its weight) is simply

F = p * A = 1200 N/m² * 2.25 m² = 2700 N

Weight is officialy defined as a force

measured in Newtons, but when we

talk about weight we often give it in

Kilograms (a unit of mass).

To get the weight in units of

Kilogram-force you must divide by the

gravitational acceleration =9.81 m/s²

2700 / 9.81 = 275.23 Kg

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Answer:

Frequency = 3 Hz

Explanation:

Frequency is a measure of Hertz. Recall that Hertz is the unit expressing cycles/second, where one second is the denominator of the fraction for simplicity. If there are 12 waves every four seconds, and one wave represents one cycle, dividing 12 waves by 4 seconds will give the answer of 3 waves (or cycles) per one second.

The frequency of these waves is 3 Hz. The correct option is D.

Frequency is the number of cycles or oscillations of a wave that occur in one second, measured in Hertz (Hz). It is a fundamental property of waves and is directly related to the energy and wavelength of the wave. The higher the frequency of a wave, the more energy it carries and the shorter its wavelength.

The formula for frequency (f) is:

f = 1 / T

where f is the frequency in Hertz (Hz) and T is the period of the wave in seconds (s). The period is the time it takes for one complete cycle or oscillation of the wave to occur.

Here in the Question,

The frequency of the waves can be calculated using the formula:

frequency = number of waves/time

In this case, the number of waves is 12 and the time is 4 seconds. Substituting these values into the formula, we get:

frequency = 12 waves / 4 seconds = 3 Hz

Therefore, the frequency of these waves is 3 Hz.

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Answer:

4kg

Explanation:

pressure=50pa

force=200N

Area=?

now,

pressure=force/area

50=200/area

area=200/50

area=4kg

The pressure is the forces acting on a given area. Hence, the area of the surface with a pressure of 50 Pa by a force of 200 N is 4 m².

Force is an external agent acting on a object to deform it or to change its state form motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction. The unit of force is Newton (N).

Pressure is the force applied on unit area. Thus, as the force increases, pressure increases. Pressure can have the units in atm, pa, N/m² etc.

Pressure = Force / area.

Given that force = 200 N

pressure = 50 Pa = 50 N/m²

Therefore, area =  force/pressure

                          = 200 N / 50 Pa

                          = 4 m²

Therefore, the area of the surface is 4 m².

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Answer:

Explanation:

Astronauts face a wide range of dangers when maneuvering in space. Collecting rock samples requires breaking apart rocks on the moon's surface, which requires tools. These tools are sometimes small hammers or other times special drills. All of this process means moving and using force to break these rocks apart and every single movement can cause a mistake which can lead to a piece of the suit ripping or a failure in the machinery. Since there is no oxygen on the moon the tiniest failure in the suit can lead to the death of the astronaut. Therefore, having backup safety precautions, and quick repair scenarios is a must when collecting rock samples on the moon.

Answer:

A. Pu -239

Explanation:

An isotope is an element with the same atomic number but different mass number. most isotope are unstable, having short half life.

Curium-242 is an isotope produced when Plutonium 239 is bombarded by an alpha particle. This reaction between Plutonium 239 and alpha particle gives curium-242, neutron and a high amount of energy as the products.

Curium oxidizes easily, and it is a dangerous metal which can cause cancer initiation when absorbed by biological materials e.g bones or tissue.

Answer:

12

Explanation:

What is the total kinetic energy of a hoop of radius 1 m and mass 2 kg that rolls at an

angular velocity of 1 rad/s?

The bent wire circuit shown in the figure is in a region of space with a uniform magnetic field in the +z direction. Current flows through the circuit in the direction indicated. segments 2 and 5 are oriented parallel to the z-axis; the other pieces are parallel to either the x or y-axis.

The direction of the magnetic force along segment 1, which carries current in the -x direction is +y. Therefore, the answer is

b) Determine the direction of the magnetic force along segment 2, which carries current in the -z-direction. The magnetic field lines are at right angles to the direction of the current flow, so the direction of the magnetic field is in the +y direction. The current flow in segment 2 is in the -z direction and so the direction of the magnetic force is in the +x direction. Fleming's left-hand rule can be used to determine the direction of the magnetic force acting on the wire segments. The thumb points in the direction of the current, and the index finger points in the direction of the magnetic field. The direction of the magnetic force along segment 3, which carries current in the +y direction is in the +x direction.

Therefore, the answer is d) Determine the direction of the magnetic force along segment 4, which carries current in the +x direction. The direction of the magnetic force along segment 4, which carries current in the +x direction is in the +y direction.

Therefore, the answer is a) Determine the direction of the magnetic force along segment 1, which carries current in the -x direction is +y. The direction of the magnetic force along segment 6, which carries current in the +x direction is in the +z direction.

Therefore, the answer is e) Determine the direction of the magnetic force along segment 5, which carries current in the +z direction in the -x direction. The direction of the magnetic force along segment 7, which carries current in the -y direction is in the -x direction.

Therefore, the answer is f) Determine the direction of the magnetic force along segment 6, which carries current in the +x direction in the -y direction.

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A Wheatstone bridge is a resistance bridge that has variable resistances that are adjusted so there is equal current flow through the legs of the bridge and zero potential across the bridge.

This configuration is widely used in scientific and engineering applications to precisely measure unknown electrical resistance values. The Wheatstone bridge consists of four resistors connected in a diamond shape, with a galvanometer connected between two opposite corners to detect any potential difference.

When the bridge is balanced, the ratio of the known resistances is equal to the ratio of the unknown resistances, allowing for accurate determination of the unknown resistance value. The Wheatstone bridge has been a fundamental tool in electrical measurements since its invention in the 19th century and continues to be utilized in modern electronics and instrumentation.

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my views

Explanation:

Figure (8) shows a rod made up of copper and wood joined together. The rod is heated at the joint in the centre for about a minute. At which point – A, B, C or D, would it show the lowest temperature? PLEASE GIVE REASONS ALSO(MINIMUM 2)

Answer:

Greta scored high in knowledge and vocabulary on the IQ test.

Explanation:

This statement highlights Greta's strengths in knowledge and vocabulary specifically, indicating that she performed well in these areas during the test. However, it does not provide information about her overall IQ score or her performance in other cognitive domains that may have been assessed in th

Various examples of drag, elastic and tension forces are mentioned.

Elastic force is a type of force that occurs when an object is stretched or compressed, and it resists the deformation of the object. This force is proportional to the amount of stretching or compression, and it causes the object to return to its original shape when the force is removed.

Tension force is a type of force that is transmitted through a string, rope, wire or cable when it is pulled tight by forces acting at either end. This force acts to transmit the tension through the length of the string, keeping it taut and preventing it from breaking.

A person biking into a headwind experiences air resistance, which is a type of drag force.

A stretched rubber band or a compressed spring both exhibit elastic force.

A person pulling a wagon by a rope exerts a tension force on the rope. Another example of tension force can be observed when a weight is hung from a rope or chain, creating tension within the rope or chain.

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Answer:

A.Nitrogen

Explanation:

Because it is belong to non-metal group.

I don't knowwwww

Answer:

D.Beryllium (Be)

Explanation:

Trust

(a) 0.300 A. is the magnitude of the current in the circuit. (b) infinity is the time at which the voltage reaches 8.00 V. (c) The rate at which energy is being stored in the capacitor is 2.40 watts.

(a) To determine the magnitude of the current when the voltage across the capacitor is 8.00 V, Ohm's Law can be applied. The current (I) in the circuit can be calculated as I = ε/R, where ε is the battery voltage and R is the resistance. Substituting the given values, I = 36.0 V / 120 Ω = 0.300 A.

(b) The time it takes for the voltage across the capacitor to reach 8.00 V can be determined by considering the charging time constant of the RC circuit. The charging time constant (τ) is given by the product of the resistance and the capacitance, τ = RC. Substituting the given values, τ = (120 Ω) × (5.00 μF) = 600 μs. To find the time (t) at which the voltage across the capacitor reaches 8.00 V, we can use the formula t = τ × ln(Vf/Vi), where Vf is the final voltage (8.00 V) and Vi is the initial voltage (0 V). Solving the equation, t = 600 μs × ln(8.00/0) = infinity (the voltage across the capacitor never reaches 8.00 V in this circuit configuration).

(c) The rate at which energy is being stored in the capacitor when the voltage across it is 8.00 V can be calculated by multiplying the current flowing through the capacitor by the voltage. Using the previously calculated current value (0.300 A) and the voltage (8.00 V), the rate of energy storage is P = IV = 0.300 A × 8.00 V = 2.40 W. Therefore, when the voltage across the capacitor is 8.00 V, the rate of energy being stored in the capacitor is 2.40 watts.

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Answer:

(i) El coche recorre 180 kilómetros.

(ii) El coche decelera a razón de 2.5 metros por segundo al cuadrado.

Explanation:

El problema se divide en dos partes. La primera es el coche viajando a velocidad constante y la segunda consiste en una decelaración hasta alcanzar el reposo.

Primera parte - Viaje a velocidad constante

La distancia recorrida por el coche se calcula mediante la siguiente ecuación cinemática:

\(x = v\cdot t\) (1)

Donde:

\(x\) - Distancia recorrida, en kilómetros.

\(v\) - Velocidad, en kilómetros por hora.

\(t\) - Tiempo, en horas.

Si sabemos que \(v = 90\,\frac{km}{h}\) y \(t = 2\,h\), entonces la distancia recorrida por el coche es:

\(x = v\cdot t\)

\(x = 180\,km\)

El coche recorre 180 kilómetros.

Segunda parte - Deceleración

Asumiendo que la deceleración del coche es constante, se determina mediante la siguiente ecuación cinemática:

\(a = \frac{v-v_{o}}{t}\) (2)

Donde:

\(v_{o}\) - Velocidad inicial, en metros por segundo.

\(v\) - Velocidad final, en metros por segundo.

\(t\) - Tiempo, en segundos.

Si sabemos que \(v_{o} = 25\,\frac{m}{s}\), \(v = 0\,\frac{m}{s}\) y \(t = 10\,s\), entonces la deceleración experimentada por el coche es:

\(a = -2.5\,\frac{m}{s^{2}}\)

El coche decelera a razón de 2.5 metros por segundo al cuadrado.

Answer:20Hz to 20000Hz

Explanation:

Humans can detect sounds in a frequency range from about 20 Hz to 20 kHz.

During exercise, the breakdown of ATP into ADP and inorganic phosphate provides the energy needed for muscle movement. This process exemplifies the transformation of chemical energy into mechanical energy. ATP stands for adenosine triphosphate, and it is often referred to as the "energy currency" of cells.

During exercise, the human body breaks down ATP, an energy molecule, to provide the energy needed for muscle movement. This process is an example of the transformation of chemical energy.
ATP stands for adenosine triphosphate, and it is often referred to as the "energy currency" of cells. It stores and releases energy in its high-energy phosphate bonds. When the body needs energy for muscle movement during exercise, ATP is broken down into ADP (adenosine diphosphate) and inorganic phosphate through a process called hydrolysis. This reaction releases energy that can be used for muscle contraction.
The transformation of chemical energy refers to the conversion of energy stored in chemical compounds, like ATP, into a different form of energy. In this case, the chemical energy stored in ATP is transformed into mechanical energy, which allows muscles to move.
In summary, during exercise, the breakdown of ATP into ADP and inorganic phosphate provides the energy needed for muscle movement. This process exemplifies the transformation of chemical energy into mechanical energy.

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Answer:

True

Explanation:

The volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.

To determine the volume of helium in the balloon, the combined gas law must be applied. The formula for the combined gas law is given by:

PV/T = constant

where P is pressure, V is volume, and T is temperature. Since the temperature and the amount of helium remains unchanged, the combined gas law can be written as P1V1 = P2V2 where P1 is the initial pressure, V1 is the initial volume, P2 is the final pressure, and V2 is the final volume.

Given that the initial pressure P1 = 760 mmHg and the final pressure P2 = 380 mmHg, the final volume V2 can be determined using:

P1V1 = P2V2

V2 = (P1V1)/P2

V2 = (760 mL)(760 mmHg)/(380 mmHg)

V2 = 1520 mL

Hence, the volume of the helium in the balloon when the atmospheric pressure is 380 mmHg is 1520 mL.

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The amount of solar radiation that the Earth intercepts from the Sun varies depending on several factors, including the distance between the Earth and the Sun, the Earth's orbital eccentricity, and atmospheric conditions.

On average, the Earth intercepts about 1,366 watts per square meter (W/m²) of solar radiation outside of the Earth's atmosphere. This value is known as the solar constant. However, due to various factors, including the Earth's atmosphere, not all of this solar radiation reaches the surface. The atmosphere absorbs, scatters, and reflects a portion of the incoming solar radiation. The actual amount of solar radiation that reaches the Earth's surface depends on factors such as the angle of incidence, cloud cover, aerosols, and the specific location and time of year.

On average, about 70% of the solar radiation that reaches the top of the Earth's atmosphere makes it through the atmosphere and reaches the surface. Therefore, the average amount of solar radiation that reaches the Earth's surface is approximately 957 W/m². It's important to note that these values are averages and can vary depending on various factors and geographical locations.

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Answer:

1. Competition and prediction

Commensalism

Parasitism

Mutualism

Amensalism

2. As the population of wolves has declined the population of the moose increase

3.

Answer:

option C

Explanation:

Final velocity of the object is 114 m / s. Hence, final velocity of the object is 114 m / s.

The frequency change, in accordance with the presented description, is 636 Hz.

The quantity of occurrences of a recurring event per unit of time is its frequency. It is distinct from angular frequency, and for clarification, it is sometimes referred to as sampling rate. One occurrence per second, or hertz (Hz), is the unit of frequency.

Speed (v1) = 36 m/s

Speed (v2) = 45 m/s

Frequency (f) = 500 Hz

Speed of sound (s) = 343 m/s

We are aware of the modification of frequency formula, which

Frequency = s+v1/ s+v2(f) -------(1)

Put a value here and apply equation (1).

We'll use v2 = -45 since it's the other way.

Frequency = s+v1/ s-v2(f)

Frequency = 343+36 / 343-45(500)

Frequency = 636

Thus, the frequency shift is 636 Hz.

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The complete question is-

A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren relative to the police car is 500 Hz, what is the frequency heard by an observer in the truck after the police car passes the truck? (The speed of sound in air is 343 m/s.)

a). 396 Hz

b). 636 Hz

c). 361 Hz

d). 393 Hz

e). 617 Hz

The object that has potential energy is the can of gasoline.

Potential energy is described as the energy held by an object because of its position relative to other objects, stresses within itself, its electric charge, or other factors.

The forms of potential energy includes:

Potential energy is described as the energy a system has due to position, shape, or configuration.

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Answer:true

Explanation:

The final velocity of the horse is 22.5 m/s [W]. Velocity is a vector quantity that describes the rate at which an object changes its position. It includes both magnitude (speed) and direction.

To find the final velocity of the horse, we can use the formula for calculating velocity:

v = u + at

where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Given:

Initial velocity (u) = 10 m/s [W]

Acceleration (a) = 6.25 m/s^2 [W]

Time (t) = 2 sec

Substituting the given values into the formula, we can calculate the final velocity:

v = 10 m/s + (6.25 m/s^2)(2 sec)

v = 10 m/s + 12.5 m/s

v = 22.5 m/s

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The tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described is -6.61 ft/s². Weight of car = 2820 lbSpeed of cars = 58.5 ft/s. Coefficient of friction,μs = 0.855μk = 0.715.

Radius of the dip, r = 775 ft.a) What is the tangential acceleration (i.e., the acceleration parallel to the road) of each car as it slides on the road at the positions described?Now, we need to find the tangential acceleration of each car during sliding.Let F be the frictional force exerted by the road on the car.Using, the following formula we can find the force exerted on the cars.

F=μs N = μs m g = 0.855 × 2820 × 32.2 lb = 80445.6 lb.a = F/ma = 80445.6 lb/2820 lba = 28.54 ft/s²The total tangential acceleration is the acceleration due to gravity subtracted by the frictional force, which is as follows,a = -g sinθ - μs g cosθa = -32.2 sin(0) - 0.855 × 32.2 cos(0)a = -27.53 ft/s²The tangential acceleration is,-6.61 ft/s².b) What is the magnitude of the total force that the road exerts on each car?The force acting on the cars can be found by,Force = mass × acceleration (F = ma)Force, F = 2820 × 6.61 lbForce, F = 18,601.4 lb.The force exerted on each car is 18,601.4 lb.

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