A rectangle has a length that is 4 times the width, w. If the perimeter of the rectangle has a perimeter of 40
feet, what is the length of the rectangle?
Answer: 16cm
Step-by-step explanation:
l = 4w
2l + 2w = p
2(4w) + 2w = 40
8w + 2w = 40
10w = 40
w = 4 cm
l = 4w = 4(4) = 16cm
solve the linear equation 4x-(2x-1)=x+5+x-6
The linear equation doesn't have a solution.
How to compute the value?The linear equation given is illustrated as: 4x-(2x-1) = x+5+x-6
This will be solved thus:
4x - 2x + 1 = x+5+x-6
4x - 2x + 1 = 2x - 1.
2x + 1 = 2x - 1
Collect like terms
2x - 2x = -1 - 1
0 = -2
This illustrates that the equation doesn't have a solution.
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What is the apparent solution to the system in the graph
Answer:
(2, 1)
Step-by-step explanation:
The solution is the point where the two lines intersect. In this case, that is (2, 1)
Given g(x)=-x-4g(x)=−x−4, solve for xx when g(x)=10g(x)=10.
The solution for x in the function when the function g(x) = 10 is 4
How to determine the solution for x in the function?From the question, we have the following equation that can be used in our computation:
g(x)=x-4
To make the equation legible, we need to rewrite it
So, we have the following representation
g(x) = x - 4
Also from the question, we have
g(x) = 10
This means that we calculate x when g(x) = 10
Substitute the known values in the above equation, so, we have the following representation
10 = x - 4
So, we have the following equation
x - 4 = 10
Add 4 to both sides of the equation
So, we have the following representation
x - 4 + 4 = 10 + 4
Evaluate the equation
x = 14
Hence, the solution is 14
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tommy wants to hire a car to drive 850 miles in 8 days how much would it cost him to hire a car from the cheaper side.
Note if Tommy were to hire a car to drive 850 miles in 8 days under the price conditions given, it would cost him £575 to go with the cheaper company which is company B.
To compute the cheaper price, we need to work out how much it comes to if he went with either company.
Company A:
Daily Charge £20
Cost per mile 50p
Given that he goes 850 Miles ;
For 8 days,
His Total cost with Company A is
(20 x 8) + [ (50 *850)/100); recall that 100 pence (p) make 1 British Pound (£)
Thus, 160 + 425
= £585
Thus, to go with Company A, Tommy will spend £585
On the other hand, Tommy's Total cost with Company B is computed as follows;
Daily Charge £40
Cost per mile 30p
Total cost will come to: (40 x 8) + [(30 *850)/100)
= 320 + (25500/100)
= £575
Since Company will charge a total of £585 and Company B will charge a total of £ 575, we can conclude that the cheaper company is company B.
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Full Question:
Tommy wants to hire a car to drive 850 miles in 8 days how much would it cost him to hire a car from the cheaper side. See the attached for the pricing conditions.
how to change a negative exponent to a positive exponent
According to the relative frequency table, which grade had the greatest number of students who preferred one of the toppings?
The most considerable count of students who enjoyed at least one of the toppings was in Grade 7, which had a total of 45 participants.
How to solveTo analyze the number of students in each grade, one must multiply the combined relative frequencies for every row by the absolute amount of students (100).
Grade 6: (0.15 + 0.10 + 0.05) * 100 = 0.3 * 100 = 30 learners
Grade 7: (0.20 + 0.15 + 0.10) * 100 = 0.45 * 100 = 45 pupils
Grade 8: (0.10 + 0.05 + 0.10) * 100 = 0.25 * 100 = 25 scholars
The most considerable count of students who enjoyed at least one of the toppings was in Grade 7, which had a total of 45 participants.
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In a survey, 100 students from grades 6, 7, and 8 were asked about their favorite pizza topping. The relative frequency table below shows the results:
Grade Pepperoni Cheese Veggie
6 0.15 0.10 0.05
7 0.20 0.15 0.10
8 0.10 0.05 0.10
Which grade had the greatest number of students who preferred one of the toppings?
answer please. most accurate gets branliest.
Answer:
m∠U = 36°
m∠V = 75°
m∠T = 69°
Step-by-step explanation:
(2x+14)+(6x+9)+(6x+3)=180
Combine like terms: 14x+26=180
Solve this equation: x=11
Use x=11 to find angles
∠U = 36°
∠V = 75°
∠T = 69°
You can add up all of these measurements to check. =180°
Answer:
The measures of the 3 angles are:Angle T = 69°Angle U = 36°Angle V = 75°Step-by-step explanation:
The Triangle Sum Theorem states that the 3 angles of a triangle must add up to 180°.
We don't know the angles of the triangle, but we do know that the sum of all three unknown angles is 180°.
We set the three expressions together as equal to 180°.
6x + 3 + 6x + 9 + 2x + 14 = 180
Simplify
14x + 26 = 180
Subtract 26
14x = 154
x = 11
Now, we check our answer for x.
6(11) + 3 + 6(11) + 9 + 2(11) + 14 = 180
69 (measure of angle T) + 75 (measure of angle V) + 36 (measure of angle U) = 180
180 = 180 ✅
Note that once we found x, would substitute it in and get the needed measures. Since the needed measures add up to 180°, we know that our answer is correct.
The measures of the 3 angles are:Angle T = 69°Angle U = 36°Angle V = 75°find the absolute maximum and absolute minimum values of f on the given interval. f(x) = x x^2 − x 25 , [0, 15]
absolute minimum value 8+4π
absolute maximum value 15
The absolute minimum value of f on the given interval is 8+4π and the absolute maximum value of f on the given interval is 15.
To find the absolute maximum and absolute minimum values of f on the given interval [0,15], we need to first find the critical points of the function and then evaluate the function at those critical points as well as at the endpoints of the interval.
To find the critical points of f, we need to find the values of x where f'(x) = 0 or f'(x) does not exist.
f'(x) = 3x^2 - 1 - 25 = 3x^2 - 26
Setting f'(x) = 0, we get:
3x^2 - 26 = 0
x^2 = 26/3
x = ± √(26/3)
Since √(26/3) is not in the interval [0,15], we only need to consider x = - √(26/3) as a critical point.
Next, we evaluate the function f at the critical point and at the endpoints of the interval:
f(0) = 0(0)^2 - 0 - 25 = -25
f(15) = 15(15)^2 - 15 - 25 = 3375 - 15 - 25 = 3335
f(-√(26/3)) = (-√(26/3))(√(26/3))^2 - (-√(26/3)) - 25
= 26/3 + √(26/3) - 25
To compare these values and find the absolute maximum and minimum, we can use the following observations:
- If the critical point or an endpoint gives the largest value of f, then that is the absolute maximum.
- If the critical point or an endpoint gives the smallest value of f, then that is the absolute minimum.
Comparing the values we found, we can see that:
- The absolute minimum value of f on [0,15] is 26/3 + √(26/3) - 25 ≈ 8 + 4π
- The absolute maximum value of f on [0,15] is 15
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Two firms producing identical products engage in price competition. Cost of firm 1 is $20 per unit produced and cost of firm 2 is $15 per unit produced. There are no fixed costs. Firms produce only after they learn the quantity demanded. Each firm can choose any real number in the interval [15,25] as its price.
For tie-breaking we will assume that if both firms set the same price, all consumers purchase from firm 2.
The payoff/profit function of firm 1 is:
(p1 - 20)(100 - p1) if p1 is less than or equal to p2,
0 if p1 is greater than p2
The payoff/profit function of firm 2 is:
(p2 - 15)(100 - p2) if p2 is less than p1,
0 if p2 is greater than or equal to p1
Given all of this information, solve the following parts of the problem:
a) is p1 = 20, p2 = 19.50 a Nash Equilibrium?
b) is there a Nash Equilibrium in which Firm 2 makes a positive profit?
c) How many strategies does player 1 have?
d) is p1 = 15, p2 = 15 a Nash Equilibrium?
e) is p1 = 21, p2 = 21 a Nash Equilibrium?
a) No, p1 = 20, p2 = 19.50 is not a Nash Equilibrium.
b) Yes, there is a Nash Equilibrium in which Firm 2 makes a positive profit.
c) Player 1 has infinitely many strategies.
d) Yes, p1 = 15, p2 = 15 is a Nash Equilibrium.
e) No, p1 = 21, p2 = 21 is not a Nash Equilibrium.
What is Nash Equilibrium?Nash Equilibrium is a state of a strategic game where no player has an incentive to deviate from his or her chosen strategy after considering the strategies of other players. A game has more than one Nash equilibrium if players are unable to agree on a cooperative strategy to play.
Finding Nash Equilibrium
a) Is p1 = 20, p2 = 19.50 a Nash Equilibrium?No. Firm 1 has an incentive to decrease the price to 19.49, thus breaking the tie in its favour. So p1=20, p2=19.5 is not a Nash equilibrium.b) Is there a Nash Equilibrium in which Firm 2 makes a positive profit?Yes. There are several equilibria in which Firm 2 makes a positive profit. One such equilibrium is when both firms charge the same price of 15, at which both firms earn a profit of 375.c) How many strategies does player 1 have?Player 1 has infinitely many strategies to choose from as they can choose any real number in the interval [15,25] as their price.d) Is p1 = 15, p2 = 15 a Nash Equilibrium?Yes. This is a Nash Equilibrium because neither firm has an incentive to change their strategy as they are earning non-zero profits. Both firms earn a profit of 375.e) Is p1 = 21, p2 = 21 Nash Equilibrium?No. If Firm 1 changes its price to 20.99, its profit increases from 405 to 407.99. Therefore, p1=21 and p2=21 is not a Nash Equilibrium.Learn more about Nash equilibrium at
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What number is 0.519 more than 0.356?
Given that3x:8=7:2Calculate the value ofx.Give your answer in its simplest form
The answer is 28/3, and in simplest form its 9 1/3
La o fabrica de jucarii sau produs 8424 de masinute albastre si de trei ori mai putine masinute rosii masinutele sau ambalat cate 12 intr o cutie cate cutii sau folosit
Answer:
936 boxes
Step-by-step explanation:
The computation is shown below:
The red cars is
= 8,424 ÷ 3
= 2,808
The first method for the number of boxes is
= 8,424 ÷ 12 + 2,808 ÷ 12
= 702 + 234
= 936 boxes
And, the other method to solve the number of boxes is
= (8,424 + 2,808) ÷ 12
= 936 boxes
Hence, in this way it could be solved in these two ways
in the time series design, if a researcher notes that every time that sampled inviduals are observed on the DV that the average score increases. can the researcher attribute variation on the DV to treatment
In a time series design, a researcher collects data on a dependent variable (DV) at multiple time points before and after the implementation of a treatment. If the researcher notes that every time sampled individuals are observed on the DV, the average score increases, it may be tempting to attribute this variation to the treatment.
However, caution should be exercised when making such conclusions. While the observed trend in the DV may be associated with the treatment, it's essential to consider alternative explanations, such as maturation, history, or regression to the mean. Maturation refers to the natural developmental processes that occur in participants over time, which might contribute to the observed changes. History refers to external events that could impact the DV, unrelated to the treatment. Regression to the mean occurs when extreme scores naturally become closer to the average over time, which might be mistaken as a treatment effect.
To confidently attribute variation in the DV to the treatment, the researcher should consider using a control group and a comparison group design. This allows for the comparison of changes in the DV between those who received the treatment and those who did not, reducing the likelihood of confounding variables.
In summary, although the increasing average scores in a time series design may suggest a relationship between the treatment and the DV, the researcher should be cautious when attributing this variation solely to the treatment. Other factors and potential confounding variables must be considered before making any definitive conclusions.
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NEED HELP! The wind-speed, in miles per hour (mph), was measured every six hours during a day on the Isles od Scilly.
Answer:
That’s not a lot of info...
Step-by-step explanation:
Joules and calories are two different units of energy. The equation j=0. 239c relates the measures, where c stands for calories and j stands for joules. Complete the table
To complete the table, we can simply multiply the number of calories by 0.239 to find the equivalent amount of Joules.
The equation relates Joules to calories as j = 0.239c, where c stands for calories and j stands for joules. For example, 1 calorie is equal to 0.239 Joules, 2 calories is equal to 0.478 Joules, and so on.
Joules (j) Calories (c)
0.239c 1
0.478c 2
0.717c 3
0.956c 4
1.195c 5
1.434c 6
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Please help!! What is the answer? What is the square rout of 88 rounded to the nearest 100th?
9.38
please don't trust this answer
Solve the system using elimination
Answer:
(3, 2)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASEquality PropertiesAlgebra I
Solving systems of equations using substitution/eliminationStep-by-step explanation:
Step 1: Define systems
2x + 5y = 16
3x - 5y = -1
Step 2: Solve for x
Eliminate y (add equations): 5x = 15Divide 5 on both sides: x = 3Step 3: Solve for y
Define equation: 2x + 5y = 16Substitute in x: 2(3) + 5y = 16Multiply: 6 + 5y = 16Subtract 6 on both sides: 5y = 10Divide 5 on both sides: y = 2Answer:
(3, 2)
Step-by-step explanation:
2x + 5y = 16 ........ (1)
3x - 5y = - 1 ......... (2)
(1) + (2)
( 2x + 3x ) + [ 5y + ( - 5y)] = 16 + (- 1)
5x = 15 ⇒ x = 3
2(3) + 5y = 16 ⇒ y = 2
(3, 2)
Elliot’s dad bought a new car for $31,000 in 2012. Elliot read that a new car loses about 13% of its value each year. What is the multiplier for this situation?
PLEASE SHOW ALL WORK!
The multiplier that would be used to calculate the depreciation of the car is 0.83^y.
What does depreciation mean?Depreciation is when the value of an asset declines due to wear and tear.
The equation that can be used to represent depreciation is:
Value of the asset x (1 - rate of depreciation)^years
$31,000 x 0.83^y.
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A radioactive substance has an initial mass of 475 grams and a half-life of 20 days. What equation is used to determine the number of days, x, required for the substance to decay to 63 grams?
The equation used to determine the number of days, x, required for the substance to decay to 63 grams is: x ≈ 83.60
To determine the number of days, x, required for a radioactive substance to decay to 63 grams, we can use the exponential decay formula. The equation that represents the decay of a radioactive substance over time is:
N(t) = N₀ * (1/2)^(t/h)
Where:
N(t) is the remaining mass of the substance at time t
N₀ is the initial mass of the substance
t is the time elapsed
h is the half-life of the substance
In this case, we have an initial mass of 475 grams, and we want to find the number of days required for the substance to decay to 63 grams. We can set up the equation as follows:
63 = 475 * (1/2)^(x/20)
To solve for x, we can isolate the exponential term on one side of the equation:
(1/2)^(x/20) = 63/475
Next, we can take the logarithm (base 1/2) of both sides to eliminate the exponential term:
log(base 1/2) [(1/2)^(x/20)] = log(base 1/2) (63/475)
By applying the logarithmic property log(base b) (b^x) = x, the equation simplifies to:
x/20 = log(base 1/2) (63/475)
Finally, we can solve for x by multiplying both sides of the equation by 20:
x = 20 * log(base 1/2) (63/475)
Using a calculator to evaluate log(base 1/2) (63/475) ≈ 4.1802, we find:
x ≈ 20 * 4.1802
x ≈ 83.60
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Use the drop-down menus to complete each equation so the statement about its solution is true.
No Solutions
5−4+7x+1=
x +
One Solution
5−4+7x+1=
x +
Infinitely Many Solutions
5−4+7x+1=
x +
No Solutions
5−4+7x+1 =
x + 2
One Solution
5−4+7x+1 =
x - 2
please help!! i need this for a quiz and i am struggling
The surface area of the composite figure is 190 square inches.
What is a composite figures?
Composite geometric figures are made from two or more geometric figures. The composite figure below is made from parts of a rectangle and a circle. Composite figure = 3 sides of a rectangle + ½ the circumference of a circle.
The Box:
Length that equals 11 in
Width that equals 8 in
Height that equals 5 in
The surface area of 4 faces is given by
A=2H(L+W)
A=2×5(11+8)
A=10(11+8)
A=10×90
A=190
Hence , The surface area of the composite figure is 190 square inches.
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Helloooo please give the right answer :)
Answer:
9 feet
Step-by-step explanation:
3X3=9 feet therefore 3 yards is equal to 9 feet
From a table of integrals, we know that for ,≠0a,b≠0,
∫cos()=⋅cos()+sin()2+2+.∫eatcos(bt)dt=eat⋅acos(bt)+bsin(bt)a2+b2+C.
Use this antiderivative to compute the following improper integral:
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if ≠1s≠1
or
∫[infinity]01cos(3)− = limT→[infinity]∫0[infinity]e1tcos(3t)e−stdt = limT→[infinity] if =1.s=1. help (formulas)
For which values of s do the limits above exist? In other words, what is the domain of the Laplace transform of 1cos(3)e1tcos(3t)?
help (inequalities)
Evaluate the existing limit to compute the Laplace transform of 1cos(3)e1tcos(3t) on the domain you determined in the previous part:
()=L{e^1t cos(3)}=
"From a table of integrals, we know that for \(\(a \neq 0\)\) and \(\(b \neq 0\):\)
\(\[\int \cos(at) \, dt = \frac{1}{a} \cdot \cos(at) + \frac{1}{b} \cdot \sin(bt) + C\]\)
and
\(\[\int e^a t \cos(bt) \, dt = \frac{e^{at}}{a} \cdot \cos(bt) + \frac{b}{a^2 + b^2} \cdot \sin(bt) + C\]\)
Use this antiderivative to compute the following improper integral:
\(\[\int_{-\infty}^{0} \cos(3t) \, dt = \lim_{{T \to \infty}} \int_{0}^{T} e^t \cos(3t) \, e^{-st} \, dt = \lim_{{T \to \infty}} \text{ if } s \neq 1, \, \text{ or } \lim_{{T \to \infty}} \text{ if } s = 1.\]\)
For which values of \(\(s\)\) do the limits above exist? In other words, what is the domain of the Laplace transform of \(\(\frac{1}{\cos(3)} \cdot e^t \cos(3t)\)\)?
Evaluate the existing limit to compute the Laplace transform of on the domain you determined in the previous part:
\(\[L\{e^t \cos(3t)\\).
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Use the euclidean algorithm to find integers $x$ and $y$ such that $164x + 37y = 1,$ with the smallest possible positive value of $x$. state your answer as a list with $x$ first and $y$ second, separated by a comma.
Well, let's use the Euclidean algorithm:
164 = 4×37 + 16
37 = 2×16 + 5
16 = 3×5 + 1
Then working backwards,
1 = 16 - 3×5
1 = 16 - 3×(37 - 2×16) = 7×16 - 3×37
1 = 7×(164 - 4×37) - 3×37 = 7×164 - 31×37
so that x = 7 and y = -31.
The volume of a sphere is 36 cubic inches. What is the radius of the sphere?
Answer:
2.05 inches
Step-by-step explanation:
V = 4/3 x πr³
36=4πr³/3
36x3= 4πr³
108= 4πr³
108/4 = πr³
27= πr^3
27/π =r³
r=
\( \sqrt[3]{27 \div \pi} \)
r= 2.048in
round off to 2.05in
PROOF
V = 4÷3 x πr³
V= 4/3 x π(2.05)³
V=4/3 x π8.6
V=4×π×8.6/3
V=108/3
V=36in³
Therefore: radius= 2.05 inches
Can you guys please help me!!
Answer:
a. 32
b. 32
Step-by-step explanation:
a. 12 + 4y
They gave us the value of "y" which is "5", and substitute that into the expression.
12 + 4y
12 + 4(5)
12 + 20
32
b. 4 (y + 3)
They gave us the value of "y" which is "5", and substitute that into the expression.
4 ( y + 3 )
4 ( 5 + 3)
Distributive property (multiply what is in the parenthesis by what is out of it (4))
4 * 5 + 4 * 3
20 + 12
32
Hope this helped!
Have a supercalifragilisticexpialidocious day!
1
Multiply. Show your work on the visual model.
0.7 x 0.4
Answer:
The answer to your question is, 0.28
Step-by-step explanation:
First you can think of decimals as a whole number for easier multipaction.
The problem written out in whole number form:
7 x 4 = ?
So lets find out the answer, 7 x 4 =
28.
Since it is in the tenths form divde it by 100, Because it is also in regular tencths form as well so we have to go down 3 times.
28 / 100 =
0.28.
Thus the answer to your question is, 0.28
Answer: 7/25. (or). 0.28
Step-by-step explanation: 7 x 4 = 28, so 0.4 x 0.7 basically mean the same as 7 x 4.
which of the following are correctly configured two-tailed tests?
In hypothesis testing, the two-tailed test is a statistical test used to determine if there is a significant difference between the mean of the sample data and the population mean.
The null hypothesis and the alternative hypothesis are included in two-tailed testing. The null hypothesis asserts that the sample population is equal to the population mean. The alternative hypothesis, on the other hand, states that the sample mean is not equal to the population mean. In this case, the rejection region is divided into two equal sections of 0.025 in each tail.
The correct answer that includes "150" is not provided in the question. Therefore, it is impossible to state which of the following are correctly configured two-tailed tests. Please, provide the complete question and additional information so I can better understand and provide an accurate answer.
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Write a number sentence showing one way to decompose the fraction of the day 27 over 6
One way to decompose the fraction of the day 27 over 6 is: 27/6 = 4 + 3/6.
This means that there are four whole parts of the day, plus an additional three-sixths of a part.
To understand this, we can think of the day as being divided into six equal parts, such as hours. Each part would be 1/6 of the day, so 27/6 would represent 4 and a half hours.
We can simplify this further by recognizing that 4 hours is equivalent to 4 times 1/6, or 4/6. So, we can subtract 4/6 from 27/6 to get the remaining fraction of a part, which is 3/6.
The fraction sentence 27/6 = 4 + 3/6 means that there are four whole parts of the day plus three-sixths of another part, which is equivalent to 4 and a half hours. Decomposing fractions like this can help us better understand the value and relationship between different parts of a whole.
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