Can someone help me pls I’m stuck

Answer:

x = ± 10

Step-by-step explanation:

- 5x² = - 500 ( divide both sides by - 5 )

x² = 100 ( take square root of both sides )

x = ± \(\sqrt{100}\) = ± 10

That is x = - 10 or x = 10

Answer:

3932.6N

Step-by-step explanation:

because force = weight

weight = mass × gravity so,

weight = 1060kg×3.71m/s

=3932.6N

The number of players the team can bring to the tournament is 21

From the question, we are to write an equation that can be used to solve the number of players the team can bring to the tournament

From the given information,

The members of the softball team raised $1405.25 and they rented a bus for $822.50

∴ They have $1405.25 - $822.50 left

Also, they budgeted $27.75 per player for meals

Then, x, the number of players the team can bring to the tournament is

x = ($1405.25 - $822.50) ÷ $27.75

x = $582.75 ÷ $27.75

x = 21

Hence, the number of players the team can bring to the tournament is 21.

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Answer:

102 tickets

Step-by-step explanation:

Let's say the total number of tickets sold is n.

7n = 2142

 n = 2142 ÷ 7

 n = 306

They sold 306 tickets in total.

We want to know how much they sold per night. We know they sold the same number of tickets each night for three nights.

306 ÷ 3 = 102

Therefore, they sold 102 tickets each night.

I hope this helps :)

Answer:

f(x), h(x) and k(x) can not be an exponential function.

Step-by-step explanation:

A exponential function can be represented by:

Let's evaluate each function and see which of the functions fit the expression above.

First, let's evaluate x = 0

For x = 0

f(x) = 3

g(x) = 1

h(x) = 1

k(x) = 0

If we substitute x=0 in the expression above, we will find that:

To be consider a exponential function, a can not be zero. Thus, k(x) can not be an exponential function

Now, we already now the value for "a". The next step is to find the value for b:

Let's evaluate x = 1

Now, we can write all the posible exponential functions. Then, we can test the other given points:

As we can see, f(x) in not an exponential function.

All the points are the same as the presented in the table.

As we can see, g(x) can be an exponential function.

As we can see, g(x) can not be an exponential function.

The 0.0035 hr⁻¹ first-order degradation rate constant in the 40 °C, 1.0 mg/ml solution, where R = 1.987 cal/mol/degree and 2,000 cal/mol activation energy indicates;

a. The rate constant for first-order degradation of N₂O₂ at room temperature is approximately 4.12595 × 10⁻² hr⁻¹

A first order reaction is one that has a rate that varies linearly with the concentration of one reactant

The given parameters are;

Temperature of the solution = 40°C

T₁ = 40 °C + 273.15 = 313.15 K

The rate constant, K₁ = 0.00351 hr⁻¹

Concentration of the solution = 1.0 mg/ml

Activation energy, Eₐ = 2000 Cal/mol

R = 1.987 cal/mol/degree

The formula by which the rate constant can be found is presented as follows;

\(log\dfrac{k_2}{k_1} =\dfrac{E_a}{2.303\times R} \times \dfrac{T_2-T_1}{T_1\cdot T_2}\)

a. Room temperature = 25 °C

T₂ = 25 °C + 273.15 = 298.15 K

Therefore;

\(log\dfrac{k_2}{0.00351} =\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\)

\(k_2=0.00351 \times 10^{\left(\dfrac{2000}{2.303\times 1.987} \times \dfrac{313.15-298.15}{313.15 \times 298.15}\right)} \approx 4.12595\times 10^{-2}\)

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Answer:

43) 79 years and 6 months

44)  17 years and 6 months

Step-by-step explanation:

As the account increases by a constant percentage bi-monthly, we can use the compound interest formula to write a function to model the situation.

\(\boxed{\begin{minipage}{8.5 cm}\underline{Compound Interest Formula}\\\\$ A=P\left(1+\frac{r}{n}\right)^{nt}$\\\\where:\\\\ \phantom{ww}$\bullet$ $A =$ final amount \\ \phantom{ww}$\bullet$ $P =$ principal amount \\ \phantom{ww}$\bullet$ $r =$ interest rate (in decimal form) \\ \phantom{ww}$\bullet$ $n =$ number of times interest is applied per year \\ \phantom{ww}$\bullet$ $t =$ time (in years) \\ \end{minipage}}\)

The interest is compounded bi-monthly, which means every 2 months.

Therefore, the interest is applied 6 times per year.

Given values:

Substitute the given values into the formula, and solve for t:

\(\begin{aligned}A&=P\left(1+\dfrac{r}{n}\right)^{nt}\\\\\implies 10000&=2400\left(1+\dfrac{0.018}{6}\right)^{6t}\\\\\implies 10000&=2400\left(1+0.003\right)^{6t}\\\\\dfrac{25}{6}&=\left(1.003\right)^{6t}\\\\\textsf{Take natural logs:} \quad \ln \left(\dfrac{25}{6}\right)&=\ln\left(1.003\right)^{6t}\\\\\ln \left(\dfrac{25}{6}\right)&=6t\ln\left(1.003\right)\\t&=\dfrac{\ln \left(\dfrac{25}{6}\right)}{6\ln\left(1.003\right)}\\\\t&=79.4031089...\end{aligned}\)

The account balance will reach $10,000 during the 79th year (after 79 years and 4.84 months).

As the interest is applied bi-monthly (every 2 months) we need to round up to the nearest 2 month interval. Therefore, the account balance will reach $10,000 after 79 years and 6 months.

Note: After 79 years and 4 months, the account balance will be $9,987.47, and after 79 years and 6 months it will be $10,017.43.

\(\hrulefill\)

As the account increases by a constant percentage quarterly, we can use the compound interest formula to write a function to model the situation.

\(\boxed{\begin{minipage}{8.5 cm}\underline{Compound Interest Formula}\\\\$ A=P\left(1+\frac{r}{n}\right)^{nt}$\\\\where:\\\\ \phantom{ww}$\bullet$ $A =$ final amount \\ \phantom{ww}$\bullet$ $P =$ principal amount \\ \phantom{ww}$\bullet$ $r =$ interest rate (in decimal form) \\ \phantom{ww}$\bullet$ $n =$ number of times interest is applied per year \\ \phantom{ww}$\bullet$ $t =$ time (in years) \\ \end{minipage}}\)

The interest is compounded quarterly, which means every 3 months.

Therefore, the interest is applied 4 times per year.

Given values:

Substitute the given values into the formula, and solve for t:

\(\begin{aligned}A&=P\left(1+\dfrac{r}{n}\right)^{nt}\\\\\implies 60000&=30000\left(1+\dfrac{0.04}{4}\right)^{4t}\\\\\implies 60000&=30000\left(1+0.01\right)^{4t}\\\\2&=\left(1.01\right)^{4t}\\\\\textsf{Take natural logs:} \quad \ln \left(2\right)&=\ln\left(1.01\right)^{4t}\\\\\ln \left(2\right)&=4t\ln\left(1.01\right)\\\\t&=\dfrac{\ln \left(2\right)}{4\ln\left(1.01\right)}\\\\t&=17.4151792...\end{aligned}\)

The value of the investment account will double during the 17th year (after 17 years and 4.98 months).

As the interest is applied quarterly (every 3 months) we need to round up to the nearest 3 month interval. Therefore, the investment account will double by 17 years and 6 months.

Note: After 17 years and 3 months, the account balance will be $59,606.83, and after 17 years and 6 months it will be $60,202.90.

Answer:

3/3

Step-by-step explanation:

-4 + 2/3 eqeuls that because well actaully there is no right answer just that's as close as u can get too a right answer

(i)  The partial fraction decomposition of\(100/(x^7 * (10 - x))\) is\(100/(x^7 * (10 - x)) = 10/x^7 + (1/10^5)/(10 - x).\) (ii) The expression for t in terms of x is t = 10 ± √(100 + 200/x).

(i) To express the rational function 100/(\(x^7\) * (10 - x)) in partial fractions, we need to decompose it into simpler fractions. The general form of partial fractions for a rational function with distinct linear factors in the denominator is:

A/(factor 1) + B/(factor 2) + C/(factor 3) + ...

In this case, we have two factors: \(x^7\) and (10 - x). Therefore, we can express the given rational function as:

100/(\(x^7\) * (10 - x)) = A/\(x^7\) + B/(10 - x)

To determine the values of A and B, we need to find a common denominator for the right-hand side and combine the fractions:

100/(x^7 * (10 - x)) = (A * (10 - x) + B * \(x^7\))/(\(x^7\) * (10 - x))

Now, we can equate the numerators:

100 = (A * (10 - x) + B * \(x^7\))

To solve for A and B, we can substitute appropriate values of x. Let's choose x = 0 and x = 10:

For x = 0:

100 = (A * (10 - 0) + B * \(0^7\))

100 = 10A

A = 10

For x = 10:

100 = (A * (10 - 10) + B *\(10^7\))

100 = B * 10^7

B = 100 / 10^7

B = 1/10^5

Therefore, the partial fraction decomposition of 100/(\(x^7\) * (10 - x)) is:

100/(\(x^7\) * (10 - x)) = 10/\(x^7\) + (1/10^5)/(10 - x)

(ii) Given the differential equation: dx/dt = (1/100) *\(x^2\) * (10 - x)

We are also given x = 1 when t = 0.

To solve this equation and obtain an expression for t in terms of x, we can separate the variables and integrate both sides:

∫(1/\(x^2\)) dx = ∫((1/100) * (10 - x)) dt

Integrating both sides:

-1/x = (1/100) * (10t - (1/2)\(t^2\)) + C

Where C is the constant of integration.

Now, we can substitute the initial condition x = 1 and t = 0 into the equation to find the value of C:

-1/1 = (1/100) * (10*0 - (1/2)*\(0^2\)) + C

-1 = 0 + C

C = -1

Plugging in the value of C, we have:

-1/x = (1/100) * (10t - (1/2)\(t^2\)) - 1

To solve for t in terms of x, we can rearrange the equation:

1/x = -(1/100) * (10t - (1/2)\(t^2\)) + 1

Multiplying both sides by -1, we get:

-1/x = (1/100) * (10t - (1/2)\(t^2\)) - 1

Simplifying further:

1/x = -(1/100) * (10t - (1/2)\(t^2\)) + 1

Now, we can isolate t on one side of the equation:

(1/100) * (10t - (1/2)t^2) = 1 - 1/x

10t - (1/2)t^2 = 100 - 100/x

Simplifying the equation:

(1/2)\(t^2\) - 10t + (100 - 100/x) = 0

At this point, we have a quadratic equation in terms of t. To solve for t, we can use the quadratic formula:

t = (-(-10) ± √((-10)^2 - 4*(1/2)(100 - 100/x))) / (2(1/2))

Simplifying further:

t = (10 ± √(100 + 200/x)) / 1

t = 10 ± √(100 + 200/x)

Therefore, the expression for t in terms of x is t = 10 ± √(100 + 200/x).

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Answer:

32/5

Step-by-step explanation:

Convert the mixed number 6 2/5 into an improper fraction by multiplying the denominator by the whole number and then add the numerator.

Ex: 6 2/5 = 5 x 6 +3  

The completed list of numbers would be: 1, 1, 1, 2, 1, 4, 1, 2

By examining the given list of numbers 1, 1, 1, 2, 1, 4, 1, we can observe a pattern emerging.

The pattern seems to involve alternating sequences. The first sequence is the number 1 repeated three times (1, 1, 1). The second sequence is a number that follows the pattern of increasing by 1 each time (2). The third sequence is the number 1 repeated once (1). The fourth sequence is a number that follows the pattern of doubling each time (4). This pattern of alternating sequences continues.

Based on this pattern, we can predict that the next number in the sequence will follow the alternating sequence pattern. Since the last number in the sequence is 1, the next sequence will involve a number that follows the pattern of increasing by 1. Therefore, the next number in the sequence would be:

1 + 1 = 2

Hence, based on the observed pattern, the next number in the sequence is 2.

Therefore, the completed list of numbers would be:

1, 1, 1, 2, 1, 4, 1, 2

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Group of answer choices:

A) 0.56 to 0.68

B) 0.52 to 0.72

C) 0.53 to 0.71

D) 0.55 to 0.69

Answer:

Option  B) 0.52 to 0.72

Step-by-step explanation:

This is a very trivial exercise. A very good point that is required to solve this question is that the wider the Confidence level, the wider the Confidence Interval.

Let us consider the options one after the other for the width of interval:

Option A) 0.56 to 0.68

Width of Interval = 0.68 - 0.56 = 0.12

Option  B) 0.52 to 0.72

Width of Interval = 0.72 - 0.52 = 0.20

Option  C) 0.53 to 0.71

Width of Interval = 0.71 - 0.53 = 0.18

Option D) 0.55 to 0.69

Width of Interval = 0.69 - 0.55 = 0.14

Assigning the confidence level based on the width of the confidence intervals:

Option A) 0.56 to 0.68 = 90%

Option D) 0.55 to 0.69 = 95%

Option  C) 0.53 to 0.71  = 98%

Option  B) 0.52 to 0.72  = 99%

The condition probability of a given b must be smaller than the intersection of the same two events a and b:

This statement is False.

The condition probability of event "b" given event "a" (P(b|a)) must be less than or equal to the probability of event "b" (P(b)). This is because the occurrence of event "a" restricts the sample space to only those outcomes that belong to event "a", and thus the probability of event "b" given event "a" cannot be greater than the unconditional probability of event "b".

The concept of conditional probability is used to describe the probability of an event given that another event has already occurred.

The formula for conditional probability is

where P(b|a) represents the probability of event "b" given that event "a" has already occurred.

In order for this to be meaningful, it is required that P(b|a) <= P(b). This means that the probability of event "b" given that event "a" has already occurred cannot be greater than the unconditional probability of event "b".

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Answer:

104.8cm³(1 decimal place)

Step-by-step explanation:

Volume of a cone is given by the formula

V=1/3πr²h

we are given a radius of 5 and a height of 4 so we will just substitute for the values and we will give our pie as 22/7

V=1/3× 22/7×5²×4

V=1/3 × 22/7 ×25 ×4

V=2200/21

V=104.76190476

V=104.8cm³(1decimal place)

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Answer:

A, B, and E. Hope this helps!

The slope intercept formula is given by the expression below:

Where "m" is the slope and b is the y-intercept of the graph.

The first step to solve this problem is to rewrite the given expression in it's slope-intercept form. This is done below:

From the expression we know that the y-intercept is "3". We need another point to graph the equation correctly. To find it we will make y=0 and find the value of x.

We can finally graph the equation. It crosses the y-axis at "3" and the x-axis at "5".

Answer:

39 - n

Step-by-step explanation:

subtract  the number that the family ate from the amount baked

39 - n

This is because when n tends to infinity, the compounding period becomes infinitesimally small, and the interest rate becomes continuous. Hence, the value of V is given by the continuous compounding formula, V = Vo e^(rt).

Value is a concept that is highly relative and subjective, as it is based on subjective preferences and beliefs. Generally, value refers to the importance, worth, or usefulness of something. For example, the value of a car depends on its make and model, age, condition, and features. In the economic sense, value is the exchange value of a good or service. In terms of personal values, it is the importance that an individual places on a certain belief or idea.

(a) The indeterminate form is 0/0, which is known as a form of L'Hôpital's Rule.

(b) The limit of V as n approaches infinity is given by:

lim V = Vo e^(rt),

where e is Euler's number (approximately 2.718).

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Answer:

£ 550

Step-by-step explanation:

C = p(t + 30)

C = 2(245 + 30)

C = 2 (275)                         [using order of operations]

C = 550

Hope this helps!

Answer:

C = £550

Step-by-step explanation:

Given the Cost formula, C = p(t + 30), and p = 2 and t = 245:

Plug in the values of p and t into the formula:

C = p(t + 30)

C = 2(245 + 30)

C = 2(275)

C = 550

Therefore, the total cost is £550.

The solution of the given problem of equation comes out to be total cost for 942 minutes is $1044.

The similar symbol (=) is used in arithmetic equations to signify equality between two statements. It is shown that it is possible to compare various numerical factors by applying mathematical algorithms, which have served as expressions of reality. For instance, the equal sign divides the number 12 or even the solution y + 6 = 12 into two separate variables many characters are on either side of this symbol can be calculated. Conflicting meanings for symbols are quite prevalent.

Part A:

Given:

To find an equation,

Where x is number of monthly minutes.

and y is total monthly of splint plan.

So, equation is:

\(\rightarrow \text{y} =\text{mx} +\text{b}\)

For the first case:

\(\rightarrow\bold{173 = 380x + b}\)

Second case:

\(\rightarrow\bold{249= 570x + b}\)

Solve for x:

\(\rightarrow{173 - 380\text{x}=249- 570\text{x}\)

\(\rightarrow{-207=-321\)

\(\rightarrow \text{x} =\dfrac{321}{207}\)

\(\rightarrow \text{x} =\dfrac{107}{69}\)

\(\rightarrow \text{x} \thickapprox1.55\)

For value of b

\(\rightarrow 173 = 380(1.55) + \text{b}\)

\(\rightarrow 173 - 589 = \text{b}\)

\(\rightarrow -416 = \text{b}\)

Part B:

\(\rightarrow \text{y} = 942(1.55) - 416\)

\(\rightarrow \text{y} = 1460.1 - 416\)

\(\rightarrow \text{y} \thickapprox1044\)

Therefore, the solution of the given problem of equation comes out to be total cost for 942 minutes is $1044.

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a) A negative number on the x-axis (-a, b) would move in the left direction by one unit.

To find out why, check point (0, b) on the y-axis and point (-a, b) on the x-axis.

The distance between these two points is a unit, meaning that the point (-a, b) is one unit to the left of the point (0, b).

b) A positive number on the x-axis (+a, b) would move in the right direction by a unit.

Again, let's look at the point (0, b) on the y-axis and the point (+a, b) on the x-axis.

The distance between the two points is also one unit, which means the point (+a, b) is one unit to the right of the point (0, b).

c) A negative number on the y-axis (a, -b) would move in the downward direction by b units.

Assume that point (a, 0) is on the x-axis and point (a, -b) is on the y-axis. The distance between them is b units, which means that the point (a, -b) is b units below the point (a, 0).

d) A positive number on the y-axis (a, +b) would move in the upward direction by b units.

Also, check the point (a, 0) on the x-axis and point (a, +b) on the y-axis. The distance between these two points is b units, which means that the point (a, +b) is b units above the point (a, 0).

A number is a mathematical term used to show the quantity or value of a thing. It can be depicted using numerals, symbols, or words.

Examples include 30, hundred, -8, 6x, "5", 0.67, etc.

Numbers can be Positive - numbers greater than zero, or negative - numbers less than zero.

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The value of R(A) = 4, N(AT ) = 3, R(AT ) = 4, and N (A) = 3.

Given that

Dimension of matrix  = 7×5

Rank of matrix = 4

The range space of A,

Which is a subspace of R, is known as R(A).

It is made up of all conceivable linear combinations of A's columns.

The dimension of R(A) =  rank of A,

Which is 4 in this case.

The null space of the transpose of A,

Which is also a subspace of R, is designated as N(AT).

All potential answers to the equation ATx = 0,

Where x is a R column vector, are included in it.

N(AT) has a dimension = nullity of A,

which in this case is 3 in this example.

The range space of the transposition of A, is designated as R(AT).

The rows of A are arranged in all conceivable linear configurations.

The rank of A = 4

Thus it equal to dimension of R(AT).

N(A) is the null space of A.

Axe = 0, where x is a column vector in R, are included in it.

The nullity of AT, which is three, is likewise equivalent to the dimension of N(A).

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The mean is approximately 1.67 units of rainfall. The median is 2 units of rainfall.

In statistics, the median is a measure of central tendency that represents the middle value of a set of data. Specifically, it is the value that separates the upper half of the data from the lower half when the data is arranged in order from smallest to largest (or vice versa).

Looking at the line plot, we can see that there are two values marked with a single asterisk and four values marked with two asterisks. Since each asterisk represents a certain amount of rainfall, we can interpret this as follows:

The two values marked with a single asterisk are each 1 unit of rainfall.

The four values marked with two asterisks are each 2 units of rainfall.

Therefore, the data represented in this line plot is as follows:

1, 1, 2, 2, 2, 2

To find the center of this data, we can calculate the mean and median.

The mean is calculated by adding up all the values and dividing by the total number of values. In this case, we have:

(1 + 1 + 2 + 2 + 2 + 2) / 6 = 10 / 6 = 1.67

So the mean is approximately 1.67 units of rainfall.

The median is the middle value when the data is arranged in order. In this case, the data is already in order, so we just need to find the middle value:

The middle value is the average of the two middle numbers:

(2 + 2) / 2 = 2

So the median is 2 units of rainfall.

Based on these calculations, we can conclude that the BEST way to describe the center of the data represented in this line plot is by the median, which is 2 units of rainfall. Therefore, the correct option to complete the statement is:

"The median is 2 inches."

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Answer:

Step-by-step explanation:

The Answer is 9 units away, just start at the Q and count up intill you get to the T on the number line shown.

Hoped this helped!! :D

In the given argument and condition, (D) there are several observations, which strengthen the argument.

An argument is a statement or set of claims, known as premises, that seeks to evaluate the plausibility or acceptability of a conclusion.

The logical, dialectical, and rhetorical perspectives are the three basic areas of study for arguments.

Giving an argument entails offering a group of premises as justifications for believing the conclusion.

It's not always necessary to criticize or insult someone when making an argument.

Arguments can also be employed to back up the beliefs of others.

An example of an argument is as follows:

You should put in a lot of effort if you want to find a decent career.

So, in the given argument and condition, (D) there are several observations, which strengthen the argument.

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Complete question:
Consider the following argument:

Observation: Here in Nashville, the sun has risen every morning. Conclusion: The sun is going to rise in Nashville tomorrow.

a. The argument is weak because there is only one specific case.

b. The argument is strong because the premise includes scientific evidence.

c. The argument is weak because the observation does not consider other cities.

d. The argument is strong because there are a large number of observations.

Answer:

2/3 ft= 8 in   2/5 m= 40 cm   5/6 yr= 10 months

Step-by-step explanation:

Answer:

x=22/5

Step-by-step explanation:

4:x = 10:11

4/x=10/11

x=11*4/10

x=22/5