BRAINIEST AWNSER 100 points PLEASE HELP






The number 1 is the identity for multiplication. Do you think
that division has an identity? Explain your reasoning.

Answer:

$7.65 million dollars / $7.55 * 10^6

Step-by-step explanation:

30*1.5=45 seconds

5.1*1.5=7.65

for scientific notation just take the number of zeros and use that for exponent, and make a dot so it is a number less than 10

Answer:

1.

by using Pythagoras theorem

h²=p²+b²

h²=12²+40²

h=√1744

AB=42

2.

x+48°+90°=180°{sum of interior angle of triangle}

x=180°-138°

x=42°

Answer:

f(x) = (x + 4)(x - 4)

Step-by-step explanation:

f(x) = x² - 16

This is the difference of two squares.

f(x) = (x + 4)(x - 4)

The representation that does not change the location of the given point (3, 140°) is option A. (-3, 230°).

The given point is (3, 140°). To determine which representation does not change the location of this point, we need to consider both the magnitude (distance from the origin) and the angle.

Option A, (-3, 230°), changes the sign of the magnitude to -3, which means it is in the opposite direction from the original point. Therefore, option A does not represent the same location as the given point.

Option B, (3, 500°), has an angle of 500°, which is not equivalent to the original angle of 140°. Therefore, option B does not represent the same location as the given point.

Option C, (3, 320°), has an angle of 320°, which is not equivalent to the original angle of 140°. Therefore, option C does not represent the same location as the given point.

Option D, (-3, 500°), changes both the sign of the magnitude and the angle. The sign change in magnitude makes it opposite in direction from the original point, and the angle of 500° is not equivalent to the original angle of 140°. Therefore, option D does not represent the same location as the given point.

Therefore, none of the given options represent the same location as the given point (3, 140°).

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The inequality notation for the given interval is -∞ < x ≤ -11 and -8 ≤ x < ∞

Disclaimer:

Considering the given interval as (-∞, -11] ∪ [-8, ∞).

Given interval is a union of two intervals.

The first interval denotes the set of all real numbers which are less than or equal to -11.

And the second interval denotes the set of all real numbers which are greater than or equal to -8.

The inequalities can be written as below:

(-∞, -11] ⇒ x ≤ -11 (or) -∞ < x ≤ -11

[-8, ∞) ⇒ x ≥ -8 (or) -8 ≤ x < ∞

And there is a union symbol between these two intervals.

So, x should satisfy both inequalities.

x ≤ -11 and x ≥ -8

or the above can be written as

-∞ < x ≤ -11 and -8 ≤ x < ∞

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Answer:

3:8

Step-by-step explanation: :)

Answer:

3 eggs :  8 cups of flour

=3:8

Answer:

um.. ok    the answer is 10 remainder 2

Step-by-step explanation:

5 goes into 52

10 times

Answer:

10.4

Step-by-step explanation:

If three pencils, each measuring one foot in length, are laid end to end touching, the total distance covered by the row would be 3 feet.

Since each pencil is 1 foot long, when three pencils are laid end to end, they form a row that is 3 feet long. The key information here is that the pencils are touching, which means there are no gaps between them. Therefore, the row would extend for a total distance of 3 feet.

In this scenario, the correct answer is option a, 3 ft. The row would not extend beyond 3 feet because there are only three pencils, each measuring one foot in length. If there were more pencils or if they were not touching end to end, the total distance covered by the row would be different. However, based on the given information, the row formed by the three one-foot-long pencils would have a length of 3 feet.

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Estimable functions can be calculated using linear algebra when a design matrix is presented. Thus, the statement is proved.

Suppose E(Y)=Xβ as usual and let x 1, …,x r denote the columns of the matrix X. We have to show that β k is not estimable if and only if x k can be expressed exactly as a linear

combination of the other columns of X.

An estimable function is a linear combination of the parameters in a model that can be estimated. Estimable functions can be calculated using linear algebra when a design matrix is presented.

A design matrix is a table that displays the explanatory variables for the dependent variables in a statistical model. Let us prove the above statement by splitting it into two parts:

(i) β k is not estimable ⇒ x k can be expressed exactly as a linear combination of the other columns of X. Suppose that β k is not estimable, which implies that Xβ = Pβ, where P is an n x n symmetric, idempotent matrix of rank r-1, and β has r components. Because P is idempotent, it follows that X is in the null space of (I-P), and thus any column of X can be represented as a linear combination of the other columns of X.

(ii) x k can be expressed exactly as a linear combination of the other columns of X ⇒ β k is not estimable. Suppose x k can be expressed exactly as a linear combination of the other columns of X, say x k = Σa i x i, where i ≠ k and a i are scalars. Then, it follows that the jth element of Pβ is Σ a i β i if j ≠ k and P jj β k if j = k. Since x k can be expressed as a linear combination of the other columns, it follows that P kk = 0, which means that β k is not estimable.

Thus, the above statement is proved.

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Control limits are based on multiples of the sample statistic's standard deviation, hence the assertion is false that "control limits are based on multiples of the process standard deviation".

A control chart is made up of many different parts. There are two control limitations. The top dashed line represents the upper control limit (UCL), and the bottom dashed line represents the lower control limit (LCL).The solid middle line denotes the statistic's average for the plot.

The horizontal lines known as control limits in a control chart show the upper and lower limits of the acceptable range of results for a process. When plotted data goes over a control limit, a process is out of control and requires management action. The control limits are defined as three standard deviations on either side of the mean.

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Answer:

she is 15. 15 plus 15 is 30 and that leaves u with 6

Answer:

Aryan is 14 years old

Step-by-step explanation:

If we let "A" represent Aryan's age, and "S" would represent Sarah's age, then we can make the following equations...

S = 2A - 6

S + A = 36

Now we sub in the value of S in terms of A and get...

S + A = 36

(2A - 6) + A = 36

2A - 6 + A = 36

3A = 36 + 6

3A = 42

A = 14

We are to use the power reducing formula to rewrite cos⁴x in terms of the first power of cosine.

Here,

we have

cos⁴x

We can rewrite

cos⁴x as cos²x * cos²x

This is so because of the formula

(cos (A + B))(cos (A - B)) = cos²A - sin²BCos² x = (1 + cos 2x)/2 and cos 2x = 2cos²x - 1

Hence,

(cos⁴x) = (cos²x * cos²x) = (cos²x)(1 + cos 2x)/2

Again,

cos 2x = 2cos²x - 1

Therefore

(cos⁴x) = (cos²x * cos²x) = (cos²x)(1 + cos 2x)/2= (cos²x)(1 + 2cos²x - 1)/2= (cos²x)(2cos²x)/2= cos²x(cos²x)

This is in terms of the first power of cosine and is the required answer.

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Answer:

x = 58

Step-by-step

d is parallel to m => (2x-26) °  and 90 ° are Alternate interior angles

2x - 26 = 90

2x = 90 + 26

2x = 116

x = 58

Given that the surface integral is ∫∫(S) [x²dy / dz + y²dz / dx + z²dx Ady] and S is the outside surface of the solid 0. 2 ∫₀²π [1/3 (cos θ)]ⁿπ₀ dφ= 2 [sin φ]²π₀= 0Therefore, the value of the given surface integral is zero.

We have to evaluate this surface integral using the Gauss formula. The Gauss formula is given by ∫∫(S) F.n ds = ∫∫(V) div F dvWhere, F is the vector field, S is the boundary of the solid V, n is the unit outward normal to S and ds is the surface element, and div F is the divergence of F.

Let's begin with evaluating the surface integral using the Gauss formula;

For the given vector field, F = [x², y², z²], so div \(F = ∂Fx / ∂x + ∂Fy / ∂y + ∂Fz / ∂z\)

Here, Fx = x², Fy = y², Fz = z²

Therefore, \(∂Fx / ∂x = 2x, ∂Fy / ∂y = 2y, ∂Fz / ∂z = 2zdiv F = 2x + 2y + 2z\)

Now applying Gauss formula,\(∫∫(S) [x²dy / dz + y²dz / dx + z²dx Ady] = ∫∫(V) (2x + 2y + 2z) dv\)

Since the surface S is the outside surface of the solid, the volume enclosed by the surface S is given by V = {(x, y, z) : x² + y² + z² ≤ 1}

Now, using spherical coordinates,x = r sin θ cos φ, y = r sin θ sin φ and z = r cos θwhere 0 ≤ r ≤ 1, 0 ≤ θ ≤ π, 0 ≤ φ ≤ 2π

Now, we can calculate the Jacobian of transformation as follows;∂x / ∂r = sin θ cos φ, ∂x / ∂θ = r cos θ cos φ, ∂x / ∂φ = -r sin θ sin φ∂y / ∂r = sin θ sin φ, ∂y / ∂θ = r cos θ sin φ,

\(∂y / ∂φ = r sin θ cos φ∂z / ∂r = cos θ, ∂z / ∂θ = -r sin θ, ∂z / ∂φ = 0\)

Therefore, the Jacobian of transformation is given by,|J| = ∂(x, y, z) / ∂(r, θ, φ) = r² sin θ

Now, the integral becomes∫∫(V) (2x + 2y + 2z) dv = ∫∫∫(V) 2x + 2y + 2z r² sin θ dr dθ dφ

Now, we can express x, y and z in terms of r, θ and φ;x = r sin θ cos φ, y = r sin θ sin φ and z = r cos θ, so the integral becomes∫∫(V) (2r sin θ cos φ + 2r sin θ sin φ + 2r cos θ) r² sin θ dr dθ dφ

= ∫₀²π ∫₀ⁿπ ∫₀¹ (2r³ sin⁴θ cos φ + 2r³ sin⁴θ sin φ + 2r³ sin²θ cos θ) dr dθ dφ

= 2 ∫₀²π ∫₀ⁿπ [∫₀¹ r³ sin⁴θ cos φ + r³ sin⁴θ sin φ + r³ sin²θ cos θ dr] dθ dφ

= 2 ∫₀²π ∫₀ⁿπ [1/4 sin⁴θ (cos φ + sin φ) + 1/4 sin⁴θ (sin φ - cos φ) + 1/3 sin³θ cos θ] dθ dφ

= 2 ∫₀²π [∫₀ⁿπ 1/2 sin⁴θ (sin φ) + 1/6 sin³θ (cos θ) dθ] dφ

= 2 ∫₀²π [1/3 (cos θ)]ⁿπ₀ dφ= 2 [sin φ]²π₀= 0Therefore, the value of the given surface integral is zero.

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Answer:

Step-by-step explanation:

You want to identify the lines among those listed that will intersect the line y = 4.

The line y = 4 is a horizontal line. Any line of the form y = c, for some constant c (not 4), will be parallel and will not intersect y = 4.

All of the other lines listed will intersect y = 4.

The intersecting lines are ...

<95141404393>

Answer:

j + 5 = 80

Step-by-step explanation:

i think thats right

Therefore , the solution of the given problem of expressions comes out to be choice D is the correct response: 200 • (1.02)24.

It is preferable to use moving numbers, which can be growing decreasing, or variable, rather than generating estimates at random. They could only assist one another by exchanging resources, knowledge, or answers to problems. A truth statement may contain strategies, components, and notations against mathematical processes such as additional denial, synthesis, and mixture.

Here,

The number of paintings in the library is increasing by 2% each month, so the growth rate for one month is 2/100 = 0.02.

Therefore, multiplying the starting number of paintings (200) by the growth factor

=>  (1 + 0.02)24,

where 24 is the number of months in 2 years, will give the number of paintings the art museum will own after two years (24 months).

Thus, the expression that denotes the number of paintings the art institution owns after two years is as follows:

=>  D) 200 • (1.02)^24

Therefore, choice D is the correct response: 200 • (1.02)24.

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Answer:

y - 3 = \(\frac{1}{2}\)(x - 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 4 = - 2(x + 3) ← is in point- slope form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

\(m_{perpendicular}\) = - \(\frac{1}{m}\) = - \(\frac{1}{-2}\) = \(\frac{1}{2}\)

passing through (2, 3 ), then

y - 3 = \(\frac{1}{2}\)(x - 2) ← equation of perpendicular line

7a) The area of the base of the monument would be = 400m²

To calculate the base of the monument the area of a square is used. That is;

= Length×width.

Where;

Length = 20m

width = 20m

area = 20×20 = 400m²

Therefore, the area of the base of the monument = 400m²

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Answer:

202.40

Step-by-step explanation:

In the given question, the rocket will hit the ground in 7 seconds. The width of the rectangle is 3 cm. Kirk makes the wall in 5.5 hours. The student needs 97 marks.

The relation between the height and the time of the toy rocket has been given in the question as,

h = -4.9t²+33.6t + 4.9

where,

h= height of the rocket after getting launched

t= time after which the rocket has been launched

So, if we have to calculate how much time the rocket takes to reach the ground,

we have to take h=0 (at ground).

So, the equation becomes

0 = -4.9t²+33.6t + 4.9

Now, the roots of this equation will give the time at which the rocket will hit the ground.

So, after calculating we get

t = -0.1428 sec

or

t = 7 sec

since negative time is not possible,

the time at which the rocket will hit the ground is 7 seconds.

The length of the rectangle is = 5b-7 cm

Hence, the area is = b(5b-7) = 24

Hence, the width comes out to be = 3 cm

Kirk would be able to make the wall in 5.5 hours. This is because Jeff can make it one hour earlier than him i.e., K-1 hours. So, we get -

= (K-1) + K = 10

= 2K = 11

= K = 5.5 hours

The student already has 87 + 85 + 91 = 263 marks. He needs at least -

= (263 + x) / 4 = 90

= 97 marks

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Answer:

R'=(-3,6)

Q'=(-3,-3)

S'=(7,6)

T'=(7,-3)

Answer:

see explanation

Step-by-step explanation:

A translation of 7 units right means adding 7 to the x- coordinate. The y- coordinate remains unchanged, then

Q (- 10, - 3 ) → Q' (- 10 + 7, - 3 ) → Q' (- 3, - 3 )

R (- 10, 6 ) → R' (- 10 + 7, 6 ) → R' (- 3, 6 )

S (0, 6 ) → S' (0 + 7, 6 ) → S' (7, 6 )

T (0, - 3 ) → T' (0 + 7, - 3 ) → T' (7, - 3 )

Answer:

\( = \frac{1}{2} \times 56 \degree \\ = 28 \degree\)

(i) To analyze the linear programming problem using the two-phase simplex method, we need to convert the problem into standard form by introducing slack variables. The problem can be expressed as:

Minimize z = x1 + x2

subject to:

3x1 + x2 + x3 = 1

7x1 + 3x2 - x4 = 4

x1, x2, x3, x4 ≥ 0

The two-phase simplex method involves two phases: the first phase identifies an initial feasible solution, and the second phase optimizes the objective function.

In this case, we start with the artificial variables x3 and x4. In the first phase, we maximize the sum of artificial variables while minimizing the objective function. After the first phase, we check if the optimal solution is feasible (i.e., if the value of the objective function is zero).

Once a feasible solution is obtained, we move to the second phase and proceed with the standard simplex method to optimize the objective function. The optimal solution will be obtained when all artificial variables are eliminated, and the objective function reaches its minimum value.

(ii) Yes, this problem can be solved using the dual simplex method. The dual simplex method is used to solve linear programming problems by analyzing the dual problem. However, to apply the dual simplex method, the problem must satisfy certain conditions, such as having a feasible solution and a bounded feasible region.

In this case, since the problem is a minimization problem and has a feasible solution, the dual simplex method can be applied. It involves analyzing the dual problem, constructing a dual tableau, and performing iterations to improve the objective function value.

By applying the dual simplex method, we can find the optimal solution and determine if any additional iterations are required to reach the minimum value of the objective function while satisfying the constraints.

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0.368 .

The probability that a random variable x is exponentially distributed and less than 45 minutes,

given that the average value is 45 minutes, is 0.368.

This can be calculated by taking the negative of the natural logarithm of 1/2 (i.e. -ln(0.5)) and dividing it by the average value of 45 minutes.

The result, -ln(0.5)/45, equals 0.368, rounded to three decimal places.

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The correct option that represents the electric field is:

Option D: E = 4πε₀Q(x² + y² + z²)^(3/2)x^ + y^ + z^

The electric field is given by the formula:

E = -∇V

where:

∇ is the del operator, which in Cartesian coordinates is represented as:

∇ = (∂/∂x)x^ + (∂/∂y)y^ + (∂/∂z)z^

Taking the negative gradient of V gives us:

E = -∇V = -[(∂V/∂x)x^ + (∂V/∂y)y^ + (∂V/∂z)z^]

First, let's calculate the partial derivatives of V with respect to x, y, and z:

(∂V/∂x) = (∂/∂x)[4πε₀(Q/√(x² + y² + z²))]

= -4πε₀(Qx/√(x² + y² + z²)³)

(∂V/∂y) = (∂/∂y) [4πε₀(Q/√(x² + y² + z²))]

= -4πε₀(Qy/√(x² + y² + z²)³)

(∂V/∂z) = (∂/∂z) [4πε₀(Q/√(x² + y² + z²))]

= -4πε₀(Qz/√(x² + y² + z²)³)

Now, substituting these derivatives into the expression for E:

E = -[(-4πε₀(Qx/√(x² + y² + z²)³))x^ + (-4πε₀(Qy/√(x² + y² + z²)³))y^ + (-4πε₀(Qz/√(x² + y² + z²)³))z^]

Simplifying, we have:

E = 4πε₀Q(x/√(x² + y² + z²)³)x^ + 4πε₀Q(y/√(x² + y² + z²)³)y^ + 4πε₀Q(z/√(x² + y² + z²)³) z^

Therefore, the correct option is:

(d) E = 4πε₀Q(x² + y² + z²)^(3/2)x^ + y^ + z^

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If 1200 square centimeters of material is available to make a box with a square base and an open top,

The largest possible volume of the box is V = 4000cm^3.

We have 1200 cm^2 worth of material. This represents the surface area of a box with a square base and an open top.

the dimensions of the box.

Square base implies the length and width are the same.

Let x = length/width.

The box has a height as well.

Let h = height

the surface area ; S.

S = (area of base) + (area of 4 walls)

The area of the base is x^2

The area of one of the walls is length times height, or xh. Since there are 4 of them, it would be 4 times xh, or 4xh.

S = x^2 + 4xh

And we know that S = 1200cm^2, so

x^2 + 4xh = 1200

Let's solve for h.

4xh = 1200 - x^2

h = (1200 - x^2) / (4x)

we require the volume formula.

V = (length) x (width) x (height)

And we know all of these.

V = (x)(x)(h)

V = (x^2) h

putting h = (1200 - x^2) / (4x) in the formula

V = (x^2) ( 1200 - x^2)/(4x)

We get a cancellation,

V = x(1200 - x^2)/4

V = (1/4)x (1200 - x^2)

This will be our volume function, V(x).

V(x) = (1/4)(x)(1200 - x^2)

To maximize V(x), we must first take the derivative and then make it 0. Using the product rule (and ignoring the constant 1/4), we have

V'(x) = (1/4) [ (1200 - x^2) + (x)(-2x) ]

Simplify,

V'(x) = (1/4) [ 1200 - x^2 - 2x^2 ]

V'(x) = (1/4) [ 1200 - 3x^2 ]

V'(x) = (1/4) [ 3(400 - x^2) ]

V'(x) = (3/4) [ 400 - x^2 ]

To maximize, make V'(x) = 0, and solve for x.

0 = (3/4) [ 400 - x^2 ]

0 = 400 - x^2

x^2 = 400

x = +/- 20

Therefore,

x = { 20, -20 }

However, since x represents a dimension, it can never be negative, and we must discard the negative solution. That means

x = 20.

This tells us that the maximum volume occurs when x = 20. However, the question is asking WHAT the largest volume of the box is. Solving this is as simple as plugging x = 20 into our volume function, V(x).

V(x) = (1/4)(x)(1200 - x^2)

Therefore,

V(20) = (1/4) (20) (1200 - 20^2)

V(20) = (1/4) (20) (1200 - 400)

V(20) = (1/4) (20) (800)

V(20) = (20/4)(800)

V(20) = 5(800)

V = 4000cm^3

Hence the answer is, the largest possible volume of the box is V = 4000cm^3.

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A. The raw score for a percentile rank of 80 is approximately 82.4.

B. The raw score that falls at the 93rd percentile is 114.324.
C. The score that falls at the 11th percentile is 30.93.

D. The raw score that would be equivalent to a percentile rank of 29 is 79.20.

E. The raw score that falls at the 95th percentile is 99.75.

F. The value of the equivalent raw score is 74.17.

A. To calculate the raw score for a percentile rank of 80 first convert percentile rank to a z-score using the standard normal distribution table or a calculator.

The z-score corresponding to a percentile rank of 80 is approximately 0.84.

Then use the z-score formula to find the corresponding raw score.

z = (x - μ) / σ where, x is the raw score, μ is the mean, and σ is the standard deviation.

Plugging in the given values, we get:

0.84 = (x - 75) / 10

Solving for x, we get:

x = (0.84)(10) + 75 = 82.4

Therefore, the raw score for a percentile rank of 80 is approximately 82.4.

B. We can calculate the z-score from the percentile rank:

PR = 93

=> area to the left of z-score is 0.93.

Using the standard normal distribution table, the corresponding z-score is 1.48.
z = (x - μ) / σ

=> 1.48 = (x - 105) / 6.30

=> x = 105 + 1.48 * 6.30 = 114.324.
Therefore, the raw score that falls at the 93rd percentile is 114.324.

C. Similar to part A, we can calculate the z-score from the percentile rank:

PR = 11

=> area to the left of z-score is 0.11.

Using the standard normal distribution table, the corresponding z-score is -1.23.

z = (x - μ) / σ

=> -1.23 = (x - 38.70) / 6.31

=> x = 38.70 - 1.23 * 6.31 = 30.93.
Therefore, the score that falls at the 11th percentile is 30.93.

D. We can calculate the z-score from the percentile rank:

PR = 29

=> area to the left of z-score is 0.29.

Using the standard normal distribution table, the corresponding z-score is -0.54.
z = (x - μ) / σ

=> -0.54 = (x - 90) / 20

=> x = 90 - 0.54 * 20 = 79.20.
Therefore, the raw score that would be equivalent to a percentile rank of 29 is 79.20.

E. Similar to part A and C, we can calculate the z-score from the percentile rank:

PR = 95

=> area to the left of z-score is 0.95.

Using the standard normal distribution table, the corresponding z-score is 1.65.

z = (x - μ) / σ

=> 1.65 = (x - 75) / 15

=> x = 75 + 1.65 * 15 = 99.75.

Therefore, the raw score that falls at the 95th percentile is 99.75.

F. T-score is calculated as:

T = 10z + 50, where z is the z-score corresponding to the raw score.

26 = 10z + 50 => z = (26 - 50) / 10 = -2.4.

z = (x - μ) / σ => -2.4 = (x - 110) / 14.93 => x = 110 - 2.4 * 14.93 = 74.17.

Therefore, the value of the equivalent raw score is 74.17.

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