Answer:
\(y=3x-15\)
Step-by-step explanation:
Slope intercept form: \(y=mx+b\) where \(m\) is the slope and \(b\) is the y-intercept (the value of y when the line crosses the y-axis)
1) Find the slope of the line (\(m\))
When it comes to parallel lines, they will always have the same slope but different y-intercepts. The given equation is \(y=3x-5\). Because 3 is in the place of m, we know that the slope of the line is 3. Therefore, the slope of the line parallel to it will also be 3. So far, this is what our equation looks like:
\(y=3x+b\)
2) Find the y-intercept (\(b\))
To find the y-intercept, we plug the given point (4,-3) into the equation we currently have and solve for b.
\(y=3x+b\\-3=3(4)+b\\-3=12+b\)
Subtract both sides by 12
\(-3-12=12+b-12\\-15=b\)
Therefore the y-intercept of our line is -15. Plug -15 back into the original equation as b.
\(y=3x+(-15)\\y=3x-15\)
I hope this helps!
PLEASE HELP 20 POINTS
Answer:
\(x^7\sqrt{x}\)
Explanation:
\(\sqrt{x^{15}}\)
apply exponent rule:
\(\sqrt{x^{14}x}\)
apply radical rule:
\(\sqrt{x^{14}}\sqrt{x}\)
simplify more:
\(\sqrt{x^{7*2}}\sqrt{x}\)
final answer:
\(x^7\sqrt{x}\)
Answer:
\(x^7\sqrt{x}\)
Step-by-step explanation:
\(\sqrt{x^{15}} =\sqrt{x^{(14+1)}}\)
Apply the exponent rule \(a^{b+c}=a^b \cdot a^c\)
\(\implies \sqrt{x^{(14+1)}}=\sqrt{x^{14}x^1}=\sqrt{x^{14}x}\)
Apply the radical rule \(\sqrt{ab} =\sqrt{a}\sqrt{b}\):
\(\implies \sqrt{x^{14}x}=\sqrt{x^{14}} \sqrt{x}\)
Apply the radical rule \(\sqrt[a]{x^b} =x^{\frac{b}{a}}\):
\(\implies \sqrt{x^{14}} \sqrt{x}=x^{\frac{14}{2}}\sqrt{x}=x^7\sqrt{x}\)
can't get this rule answer. I got it wrong...
Answer:
Asymptotes can be defined as lines that the curve approaches but never touches or crosses.
5(x+6)+3x=2(1+4x)+1
I need help solving for x (9th grade pre ap algebra)
Answer:
-29
Step-by-step explanation:
5x +30 +3x =2+8x+1
x= -29
What is the answer please
Answer:
I think it should be (C)
Answer:
B
Step-by-step explanation:
The fastest way to solve this would to plug in a number for x such as 1 in both equations to find which 2 are equivalent.
When you plug 1 into the top equation it equals 3.5, so now we need to find the correct equation below that equals 3.5 when 1 is plugged in for x.
When you plug 1 into equation B you are also left with 3.5.
900*500/600+5+1-100+10
Answer:
666
Step-by-step explanation:
= 900*500/600+5+1-100+10
= 666
plz follow me
Answer:
so the answer is 666 omg I hate that number
7+7 please help me i need help quick right away
Answer:
very funny and 14
Step-by-step explanation:
Answer:
14
Step-by-step explanation:
7 plus 7? how old are you?
Find the missing angles. will give brainliest if done correctly.
Answer:
x = 69 v = 103
Step-by-step explanation:
Angles in a triangle add up to 180 degrees:
34 + 77 + x = 180
x = 69
Angles on a straight line add up to 180:
77 + v = 180
v = 103
Answer:
x = 69°V = 103°Step-by-step explanation:
the sum of the interior angles in a triangles is 180°, take away from 180 the know angles (34° and 77°) and you will have your answer
180 - 34 - 77 = 69°
Now we find angle V
The angle V and the angle of 77 ° are on a straight line, so the sum is 180°, from 180° you subtract 77 ° and you have the value of V
180 - 77 = 103 °
To solve 2x+9=21, what is the first step?
Answer:
The first step is to subtract 9 from each side
Step-by-step explanation:
2x+9=21
The first step is to subtract 9 from each side
2x+9-9 = 21-9
2x = 12
Then divide by 2 on each side
2x/2 = 12/2
x = 6
Answer:
That would be to collect like terms
Step-by-step explanation:
Further explanation
\(2x+9=21\\\\Collect\: like\: terms\\2x = 21-9\\\\Simplify\\2x = 12\\\\Divide\:both\:sides\:of\:the\:equation\:by\:2\\\frac{2x}{2} = \frac{12}{2} \\Simplify\\\\x =6\)
green (g), and one blue (b). when all three dice are rolled at the same time, calculate the probability of the following outcomes: 2.6 you roll a 6 on each of the dice (6 on r, 6 on g, and 6 on b). a. 1/6 b. 1/36 c. 1/108 d. 1/216 e. 1/2 2.7 you roll a 1 on each of the dice (r, g, and b), or a 2 on each of the dice (r, g, and b). a. 1/6 b. 1/36 c. 1/108 d. 1/216 e. 1/2 2.8 you roll no 3s at all. a. 125/216 b. 1/2 c. 1/3 d. 1/6 e. 9/216
According to the given questions the probability are 2.6 - (d) 1/216. 2.7- (d) 1/216. 2.8 - (a) 125/216.
To calculate the probability of the given outcomes, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes.
2.6) To roll a 6 on each of the dice (r, g, and b), the probability is 1/6 * 1/6 * 1/6 = 1/216.
Therefore, the answer is (d) 1/216.
2.7) To roll a 1 on each of the dice (r, g, and b), or a 2 on each of the dice (r, g, and b), we have two possible outcomes. The probability for each outcome is 1/6 * 1/6 * 1/6 = 1/216.
Therefore, the answer is (d) 1/216.
2.8) To roll no 3s at all, we need to determine the number of outcomes without any 3s, which is 5 * 5 * 5 = 125.
The total number of possible outcomes is 6 * 6 * 6 = 216. So, the probability is 125/216.
Therefore, the answer is (a) 125/216.
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what is x to the 2nd power?
Answer:
x2 or x square
Step-by-step explanation:
hope it helps
Write the expression in complete factored
form.
3p(a - 1) - 2(a - 1)
Help!
Answer:
(a - 1)(3p - 2)
Step-by-step explanation:
3p(a - 1) - 2(a - 1) ← factor out (a - 1) from each term
= (a - 1)(3p - 2)
anyone know? plz help any oen
A multiple-choice test has 32 questions, each with
four response choices. If a student is simply guessing
at the answers,
a. What is the probability of guessing correctly for
any individual question?
b. On average, how many questions would a student
answer correctly for the entire test?
c. What is the probability that a student would get
more than 12 answers correct simply by guessing?
Answer:
a. The probability of guessing correctly for any individual question is 1/4, since there are four response choices and only one of them is correct.
b. On average, a student would answer 8 questions correctly for the entire test by guessing. This is because there are 32 questions and each question has a 1/4 chance of being answered correctly, so 32 x 1/4 = 8.
c.To calculate the probability of a student getting more than 12 answers correct simply by guessing, we need to use the binomial distribution formula. The formula is:
P(X > k) = 1 - Σ P(X = i), i = 0 to k
where P(X > k) is the probability of getting more than k correct answers, P(X = i) is the probability of getting exactly i correct answers, and Σ represents the sum from i = 0 to k.
In this case, k = 12, since we want to find the probability of getting more than 12 correct answers. The probability of getting exactly i correct answers can be calculated using the binomial distribution formula:
P(X = i) = C(32, i) * (1/4)^i * (3/4)^(32-i)where C(32, i) is the number of ways to choose i correct answers out of 32 questions.
By plugging in the values into the first formula, we can find that the probability of a student getting more than 12 answers correct simply by guessing is approximately 0.097 or 9.7%. This means that a student has a relatively low chance of getting more than 12 answers correct by simply guessing on the test.
Can someone please help me with math.
Answer:
5: B
6: B
Step-by-step explanation:
For 5 all you have to do is look for the line that has a slope of 2
The only line that has a slope of 2 is line 2 therefore your answer is B
For 6
Slope intercept form - y = mx + b
where y = slope and b = y intercept
first lets find the y intercept
y intercept (b) = y value of the coordinate ( More specifically the coordinate where the line passes the y axis. )
The line passes the y axis at point (0,2)
The y value of that coordinate is 2 so the y intercept is 2, Hence b = 2
now we have y = mx + 2
Now let's find the slope.
Slope = change in y over change in x.
For this line as y goes up 1, x goes up 3
So the slope would equal 1 over 3
We then plug in 1/3 for m in the slope intercept equation
We would be left with \(y=\frac{1}{3} x+2\) which corresponds with answer choice B
Which values of x are solutions to the equation below 15x^2 - 56 = 88 - 6x^2?
a. x = -4, x = 4
b. x = -4, x = -8
c. x = 4, x = 8
d. x = -8, x = 8
A quadratic equation is a polynomial equation of degree 2, which means the highest power of the variable is 2. It is generally written in the form: ax^2 + bx + c = 0. Option (d) x = -8, x = 8 is the correct answer.
The given equation is 15x^2 - 56 = 88 - 6x^2.
We need to find the values of x that are solutions to the given equation.
Solution: We are given an equation 15x² - 56 = 88 - 6x².
Rearrange the equation to form a quadratic equation in standard form as follows: 15x² + 6x² = 88 + 56 21x² = 144
x² = 144/21 = 48/7
Therefore x = ±sqrt(48/7) = ±(4/7)*sqrt(21).
The values of x that are solutions to the given equation are x = -4/7 sqrt(21) and x = 4/7 sqrt(21).
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The given equation is 15x² - 56 = 88 - 6x². Values of x are solutions to the equation below 15x² - 56 = 88 - 6x² are x = -2.62, 2.62 or x ≈ -2.62, 2.62.
Firstly, let's add 6x² to both sides of the equation as shown below.
15x² - 56 + 6x² = 88
15x² + 6x² - 56 = 88
Simplify as shown below.
21x² = 88 + 56
21x² = 144
Now let's divide both sides by 21 as shown below.
x² = 144/21
x² = 6.86
Now we need to solve for x.
To solve for x we need to take the square root of both sides.
Therefore, x = ±√(6.86).
Therefore, the values of x are solutions to the equation below are x = -2.62, 2.62 or x ≈ -2.62, 2.62.
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How do you write greater than 7?.
The greater than sign is '>' . If one value is greater than the other, use greater than. For example, 8 is greater than 7. Therefore, we can write greater than 7 is x >7.
Greater than symbol:
In mathematics, the greater than sign is placed between two values where the first number is greater than the second number. For example, 10 > 5. Here 10 is greater than 5. For inequalities, the greater-than sign always refers to the greater value, and the sign consists of two equal length dashes joined at an acute angle on the right.
As we know math problems don't always end evenly. We may need to include inequalities such as greater than and less than signs. Statements can be expressed as mathematical expressions.
Example: 'x' is the number of students in the class. If she has more than 45 students in her class, and she has 5 students join her class again, then she has more than 50 students in her class. This statement is expressed mathematically as x + 5 > 45. fish . Crocodiles always want to eat more fish, so they can eat more fish, regardless of how many mouths they have open.
One of the best ways to remember the "greater than" and "less than" signs is to think of them as little alligators (or crocodiles). The numbers on either side represent the number of fish. Crocodiles always want to eat more fish, so they can eat more fish, regardless of how many mouths they have open.
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HELP PLEASE!! Please don't give me sites or links, those won't work since the site is blocked
Answer:
z=-5
Step-by-step explanation:
-4z=20
divide both sides of the equation by -4
-4z/-4=20/-4
z=-5
Sketch the region enclosed by the graphs of the given functions. Determine whether it is more natural to integrate with respect to x or to y to find the area of the region. Draw a typical approximating rectangle and label the height and width. y=e*, y=x² -1, x=-1, x = 1 10 Find the area of the region. G
The region enclosed by the graphs of y = e^x, y = x^2 - 1, x = -1, and x = 1 is more naturally integrated with respect to y. The area of the region is approximately 1.24 square units.
To sketch the region enclosed by the graphs of the functions y = e^x, y = x^2 - 1, x = -1, and x = 1, we can plot these functions on a coordinate plane. The region is bounded by the curves of the two functions and the vertical lines x = -1 and x = 1. To determine whether it is more natural to integrate with respect to x or y, we can look at the shape of the region. In this case, it is more natural to integrate with respect to y because the region is horizontally oriented.
To find the area of the region, we integrate with respect to y. The height of the approximating rectangle is the difference between the y-values of the functions e^x and x^2 - 1. The width is the difference between the x-values, which is 2.
Integrating y = e^x - (x^2 - 1) with respect to y from e to 0 gives the area of the region. Evaluating the integral, we get the area as approximately 1.24 square units.
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Find the remainder of 2338when divided by 55. b) What is the inverse of 23 modulo 55 i.e. which number a has the property that 23*a has the remainder 1 when divided by 55?
a) 2338 ≡ 42 • 55 + 28 ≡ 28 (mod 55)
b) We want to find a such that
23a ≡ 1 (mod 55)
Use the Euclidean algorithm:
55 = 2 • 23 + 9
23 = 2 • 9 + 4
9 = 2 • 4 + 1
⇒ 1 = 9 - 2 • 4
⇒ 1 = 9 - 2 • (23 - 2 • 9) = 5 • 9 - 2 • 23
⇒ 1 = 5 • (55 - 2 • 23) - 2 • 23 = 5 • 55 - 12 • 23
Solve for a :
5 • 55 - 12 • 23 ≡ 1 (mod 55)
⇒ -12 • 23 ≡ 1 (mod 55)
⇒ a ≡ -12 ≡ 43 (mod 55)
i've asked 55 students on monday whether they did their homework over the weekend. 17 of them said they did. find a 67% confidence interval for the proportion of students who will tell me that they did their homework over the weekend.
We are 67% confident that the proportion of students who are tell me that they did their homework over the weekend.0.087 with a margin of error of 0.0175
Find the confidence interval ?In statistics, a confidence interval describes the likelihood that a population parameter would fall between a set of values for a given percentage of the time.
Confidence ranges that include 95% or 99% of anticipated observations are frequently used by analysts.
87/1000 = 0.087
We have a 67% confidence level that the percentage of left-handed students is 0.087, with a 0.0175 margin of error.
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Find the power set for the following sets (Write 3 examples of each)
a) Two sets A & B both having any 2 elements
b) Two sets A & B both having any 3 elements
c) Two sets A & B both having any 4 elements
Given statement solution is :- a) Power set for two sets A and B with any 2 elements:
Set A: {1, 2}, Set B: {3, 4}
Power set of A: {{}, {1}, {2}, {1, 2}}
Power set of B: {{}, {3}, {4}, {3, 4}}
b) Power set for two sets A and B with any 3 elements:
Set A: {1, 2, 3}, Set B: {4, 5, 6}
Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}
Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}
c) Power set for two sets A and B with any 4 elements:
Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}
Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}
Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},
a) Power set for two sets A and B with any 2 elements:
Set A: {1, 2}, Set B: {3, 4}
Power set of A: {{}, {1}, {2}, {1, 2}}
Power set of B: {{}, {3}, {4}, {3, 4}}
Set A: {apple, banana}, Set B: {cat, dog}
Power set of A: {{}, {apple}, {banana}, {apple, banana}}
Power set of B: {{}, {cat}, {dog}, {cat, dog}}
Set A: {red, blue}, Set B: {circle, square}
Power set of A: {{}, {red}, {blue}, {red, blue}}
Power set of B: {{}, {circle}, {square}, {circle, square}}
b) Power set for two sets A and B with any 3 elements:
Set A: {1, 2, 3}, Set B: {4, 5, 6}
Power set of A: {{}, {1}, {2}, {3}, {1, 2}, {1, 3}, {2, 3}, {1, 2, 3}}
Power set of B: {{}, {4}, {5}, {6}, {4, 5}, {4, 6}, {5, 6}, {4, 5, 6}}
Set A: {apple, banana, orange}, Set B: {cat, dog, elephant}
Power set of A: {{}, {apple}, {banana}, {orange}, {apple, banana}, {apple, orange}, {banana, orange}, {apple, banana, orange}}
Power set of B: {{}, {cat}, {dog}, {elephant}, {cat, dog}, {cat, elephant}, {dog, elephant}, {cat, dog, elephant}}
Set A: {red, blue, green}, Set B: {circle, square, triangle}
Power set of A: {{}, {red}, {blue}, {green}, {red, blue}, {red, green}, {blue, green}, {red, blue, green}}
Power set of B: {{}, {circle}, {square}, {triangle}, {circle, square}, {circle, triangle}, {square, triangle}, {circle, square, triangle}}
c) Power set for two sets A and B with any 4 elements:
Set A: {1, 2, 3, 4}, Set B: {5, 6, 7, 8}
Power set of A: {{}, {1}, {2}, {3}, {4}, {1, 2}, {1, 3}, {1, 4}, {2, 3}, {2, 4}, {3, 4}, {1, 2, 3}, {1, 2, 4}, {1, 3, 4}, {2, 3, 4}, {1, 2, 3, 4}}
Power set of B: {{}, {5}, {6}, {7}, {8}, {5, 6}, {5, 7}, {5, 8}, {6, 7}, {6, 8}, {7, 8}, {5, 6, 7}, {5, 6, 8}, {5, 7, 8}, {6, 7, 8},
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Find a value of c so that P(Z ? c) = 0.71. a) -1.11 b) 0.75 c) -0.55 d) 0.55 e) 1.55
Among the provided answer options, the closest value to -0.555 is -0.55, which is option c. Therefore, option c (-0.55) is the value of c that satisfies P(Z ? c) = 0.71.
The notation P(Z ? c) represents the probability that a standard normal random variable Z is less than or equal to c. To find the value of c that corresponds to P(Z ? c) = 0.71, we need to determine the Z-score associated with this probability.
Using a standard normal distribution table or a calculator, we can find that a Z-score of approximately 0.555 corresponds to a cumulative probability of 0.71. However, since we are looking for the value of c in P(Z ? c), we need to consider the opposite inequality.
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Which ordered pair is a solution to the system of linear equations? x + 2y = 1 y = −2x − 1 (1, 1) (1, −1) (−1, 1) (−1, −1)
(-1, 1) is the ordered pair is a solution to the system of linear equations
The system of equations are x+2y=1
y=-2x-1
Substitute y value in equation 1
x+2(-2x-1)=1
x-4x-2=1
-3x=3
Divide both sides by 3
x=-1
Substitute the value of x in the equation
-1+2y=1
2y=2
Divide both sides by 2
y=1
Hence, the ordered pair is a solution to the system of linear equations is (-1, 1)
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how to find the third side of an isosceles triangle with only 2 sides known
Answer:
To obtain the third side of an isosceles triangle with two sides known, use the Pythagorean theorem if it is a right triangle or provide additional information if it is no
Step-by-step explanation:
You can follow these steps:
Identify the two sides that are known. In an isosceles triangle, these will be the two equal sides, often referred to as the legs of the triangle.
Determine the length of the base. The base is the third side of the triangle, and it is the side that is not equal to the other two sides.
If the isosceles triangle is also a right triangle, you can use the Pythagorean theorem to find the length of the base. The Pythagorean theorem states that in a right triangle, the square of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. So, you can use the formula:
base^2 = (leg1)^2 + (leg2)^2
Take the square root of both sides to solve for the base:
base = √((leg1)^2 + (leg2)^2)
If the isosceles triangle is not a right triangle, you need additional information to determine the length of the base. This could be the measure of an angle or another side length.
Remember that the lengths of the two equal sides (legs) in an isosceles triangle are always equal, while the length of the base is different.
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These two figures are similar. Find the missing side, X. -GEOMETRY
The value of the missing side, x, is 12 cm
Similar FiguresFrom the question, we are to determine the value of the side labeled x
From the given information,
The two figures are similar
Thus, by similarity rule, we can write that
8²/52 = x²/117
64/52 = x²/117
x² = (117×64)/52
x² = 7488/52
x² = 144
x = √144
x = 12 cm
Hence, the value of the missing side, x, is 12 cm
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Decide whether the triangles can be proven congruent by the given postulate or theorem. If not, state what information is needed. 11. AFLWAYLW by SAS
On this problem we have two triangles FLW and YLW. We know that the sides FL and LY are congruent and the side LW is shared between the two triangles. Therefore we know that two sides are congruent, we don't know however if the angles F and Y are congruents, there is no indication of that, so we can't prove that it is congruent, because we need to know if the angles are congruents.
6/in a study investigating the effect of car speed on accident severity, the reports of fatal automobile accidents were examined, and the vehicle speed at impact was recorded for each one. the average speed was 48 mph and standard deviation was 15 mph, respectively. a histogram revealed that the vehicle speed at impact distribution was approximately normal. (a) roughly what proportion of vehicle speeds were between 33 and 63 mph? (b) roughly what proportion of 18 vehicles of average speed exceeded 51 mph?
(a) Roughly 68% of the vehicle speeds were between 33 and 63 mph.
(b) Roughly 50% of the 18 vehicles of average speed exceeded 51 mph.
(a) Since the distribution of vehicle speed at impact is approximately normal and we know the mean and standard deviation, we can use the empirical rule, also known as the 68-95-99.7 rule, to estimate the proportion of vehicle speeds between 33 and 63 mph.
According to this rule, approximately 68% of the data falls within one standard deviation of the mean.
Given that the mean speed is 48 mph and the standard deviation is 15 mph, the range of one standard deviation below and above the mean is from 48 - 15 = 33 mph to 48 + 15 = 63 mph.
Therefore, roughly 68% of the vehicle speeds fall between 33 and 63 mph.
(b) If we assume that the distribution of speeds of the 18 vehicles of average speed is also approximately normal, we can again use the empirical rule to estimate the proportion of vehicles exceeding 51 mph.
Since the mean speed is the same as the average speed of 48 mph, and we know that roughly 50% of the data falls above and below the mean, we can estimate that approximately 50% of the 18 vehicles would exceed 51 mph.
It is important to note that these estimates are based on the assumption of normality and the use of the empirical rule, which provides approximate values.
For more accurate estimates, further statistical analysis using the actual data and distribution would be required.
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Determine the range of f(x) equals |X |+3
Answer:
3;+∞
Step-by-step explanation:
round off To the nearest hundredths 39.63222
Answer:
39.63
Step-by-step explanation:
If the number after the place you are rounding to is 4 or lower, then you round down. If it is 5 or higher round up.
Answer:
the answer is: 39.63 and that is the answer
ummmm can i get help
Answer:
Answer is D
Step-by-step explanation:
Answer:
d
Step-by-step explanation: