Q. Text-styling feature of MS word is
A. WordColor
B. WordFont
C. WordArt
D. WordFill
​

Answer:

Thermal energy is measured using a thermometer denominated in Fahrenheit, Celsius and Kelvin

Energy attenuation system is designed to control the kinetic energy of an object during an impact or collision to reduce the damage caused by the impact. When designing an energy attenuation system for a 1200 kg car traveling at 100 km/hr at impact, there are various factors that need to be considered.

The first factor is the speed of the car, which is 100 km/hr. The energy of the car can be calculated using the formula E = 0.5mv^2, where E is the kinetic energy, m is the mass of the car, and v is the velocity of the car. Therefore, the kinetic energy of the car can be calculated as follows: E = 0.5 x 1200 kg x (100 km/hr)^2= 3,333,333.33 JoulesTo control the energy of the car at impact, the energy attenuation system needs to absorb this energy gradually.

The faster the car is traveling, the higher the kinetic energy, and therefore, the more difficult it is to design a system that can control the energy of the car at impact. A car traveling at a fast speed requires a more advanced energy attenuation system, which can absorb the energy of the car gradually and reduce the force of the impact to safe levels.

In conclusion, designing an energy attenuation system for a car traveling at a fast speed requires a more advanced system than one for a car traveling at a slower speed. The system needs to be designed in such a way that it can absorb the energy of the car gradually, and the force of the impact is reduced to safe levels. The design of the system should ensure that the passengers are safe and are not exposed to any serious injuries.

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Answer:

shear strength = 2682.31 Ib/ft^2

Explanation:

major principal stress = 100 Ib / in2

minor principal stress = 20 Ib/in2

Normal stress = 3000 Ib/ft2

Determine the shear strength when direct shear test is performed

To resolve this we will apply the coulomb failure criteria relationship between major and minor principal stress a

for direct shear test

use Mohr Coulomb criteria relation between normal stress and shear stress

Shear strength when normal strength is 3000 Ib/ft  = 2682.31 Ib/ft^2

attached below is the detailed solution

An engineer would indicate the unit of measurement used in a design in millimeters.

The primary unit of measurement is the stocking unit of measure for a given item in a specific organization. You must define an item attribute that serves as the primary unit of measurement when creating each item.

Because the technical drawings are scaled, engineers, architects, and builders may create the items according to exact specifications.

When understanding scales, the number on the left relates to the measurement of the drawing, while the number on the right represents the actual size of the object.

Therefore, a millimeter is used in a design.

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Answer:

1.4 mL

Explanation:

Given that:

volume of alcohol \(V_0\) = 500

Temperature change ΔT = (30° - 5°)C

=25° C

\(\beta_{ alcohol }= 1.12 \times 10^{-4} / ^0C\)

The increase in volume ΔV =  \(\alpha \times V_o \times \Delta T\)

\(= 500 \times 1.12 \times 10^{-4} / ^0 C\times 25^0 C\)

= 1.4 mL

Tensile strength and yield strength of materials can vary depending on the specifics of the manufacturing process, exact chemical composition, and the treatment of the material. They are usually provided by the manufacturer in a materials property datasheet. I don't have real-time access to such specific databases or proprietary materials databases to provide these values.

However, I can give you a general idea based on typical values for similar materials:

(a) UNS G10200 hot-rolled steel (also known as AISI 1020 steel):

- Tensile Strength: around 420 MPa

- Yield Strength: around 350 MPa

(b) SAE 1050 cold-drawn steel:

- Tensile Strength: around 690 MPa

- Yield Strength: around 600 MPa

(c) AISI 1141 steel quenched and tempered at 540°C:

- Tensile Strength: around 760 MPa

- Yield Strength: around 690 MPa

(d) 2024-T4 aluminum alloy:

- Tensile Strength: around 470 MPa

- Yield Strength: around 325 MPa

(e) Ti-6Al-4V annealed titanium alloy:

- Tensile Strength: around 900 MPa

- Yield Strength: around 880 MPa

These are general values and actual values can vary based on exact processing conditions and slight differences in alloying elements. For precise values, you should refer to the material's datasheet provided by the manufacturer or a reliable materials database.

This happens as a result of a gain in kinetic energy at the expense of a decrease in enthalpy brought on by gas expansion as air passes through the diverging region of the nozzle.

A nozzle is a tool used to change the characteristics of a fluid flow as it leaves a confined chamber or conduit, particularly to enhance velocity. The reciprocal of the nozzle length, pressure, and the square root of the nozzle diameter all increase air velocity.

A nozzle needs to be made to expand steam from 500 PA at 210 °C to 100 kPa at a rate of 0.1 kg/s.  In order to reach critical or sonic conditions (i.e., choked flow) at its throat, the flow is accelerated when a nozzle is used.

Therefore, The steam's specific volume at the nozzle's exit is determined to be 1.4 m3/kg and its velocity at that point to be 700 m/s.

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Answer:

a. True

Explanation:

The study of fluids in a state of rest or in motion and the forces involved in it is called fluid mechanics. Fluid mechanics has a wide range of applications in the field of mechanical engineering as well as civil engineering.

When we study the flow of fluid between any two flat plates that is indefinitely flat and is parallel, the flow of the fluid is known as plane Poiseulle flow. The profile of a plane Poiseulle flow is parabolic.

The velocity profile of a plane Poiseulle flow is :

\($\frac{u(y)}{U_{max}}=1-\left(\frac{2y}{h}\right)^2$\)

Thus the answer is TRUE.

The correct answer is b. A shock can result if the megger leads are disconnected before the voltage has had a chance to bleed off.

The megger test is used to measure the insulation resistance of electrical wiring or equipment. When the test is completed, the voltage stored in the wiring or equipment needs to be discharged before the leads are disconnected. If the leads are disconnected too quickly, the stored voltage can create a shock hazard, potentially causing injury or even death. It is important to wait for the voltage to bleed off completely before disconnecting the leads to avoid any electrical shock. Additionally, failing to discharge the voltage properly can result in false megger readings or damage to the wire or equipment being tested. It is important to always follow proper safety protocols when performing electrical tests to prevent accidents and ensure accurate results.

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Aluminum is the metal most frequently used in metal-and-glass cladding systems for several reasons.

Firstly, aluminum has excellent corrosion resistance, which is crucial for exterior applications where the cladding is exposed to weather conditions.

Secondly, aluminum is lightweight, making it easier to handle and install. This reduces the overall weight of the cladding system and the load on the building structure. Additionally, aluminum is highly malleable, allowing it to be easily shaped and formed into complex profiles and designs. This versatility makes it suitable for various architectural styles.

Lastly, aluminum is a sustainable material as it can be recycled indefinitely without losing its properties. This aligns with the growing emphasis on environmental considerations in construction.

Overall, these factors make aluminum the preferred choice for metal-and-glass cladding systems.

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In a distributor ignition system, the rotor rotates under the distributor cap to send the high voltage to each spark plug wire.

The rotor is a small, cylindrical component that is typically made of plastic with a conductive metal tip on the end. It is attached to the distributor shaft and rotates at the same speed as the engine's crankshaft. As the rotor rotates, it passes over a series of metal contacts, known as the distributor cap terminals, which are connected to the spark plug wires. When the rotor passes over a terminal, it completes the circuit and sends a high voltage pulse to the corresponding spark plug wire, which ignites the fuel in the engine's cylinders.

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After the auditor completes tests of controls and draws conclusions about control risk, the auditor makes decisions about the nature, timing, and extent of substantive procedures.

Substantive procedures are audit procedures performed to obtain audit evidence about the completeness, accuracy, and validity of the data produced by an entity's accounting system. These procedures include detailed testing of account balances, transactions, and disclosures to determine if there are any material misstatements in the financial statements. The auditor considers the assessed level of control risk and the effectiveness of the entity's internal controls in determining the appropriate scope and extent of substantive procedures to be performed.

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Answer:

thrust washer

can be used to eliminate rubbing friction of wheel touching frame

All of the following are identified in the text as the primary functions of communication EXCEPT for to influence others.

A function is a group of related statements designed to perform a specific task. It is a set of instructions that performs a specific task and returns a result. Functions are an essential part of any programming language as they provide a way to create reusable code. Functions take parameters as input, perform an operation and return the result. Functions can be used to simplify complex tasks and make programs easier to read and understand. By using functions, programmers can reduce code duplication, increase code readability and improve code maintainability. Functions can also make programs more efficient as they can be called multiple times with different parameters.

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Answer: B. 15 feet

Explanation:

Answer:

Explanation:

To determine the required size of standard schedule 40 steel pipe to carry 192 m³/hour of water with a minimum velocity of 6.0 m/sec, we can use the following formula:

Q = A × v

where Q is the volumetric flow rate of water, A is the cross-sectional area of the pipe, and v is the velocity of water.

First, we need to convert the volumetric flow rate from m³/hour to m³/sec.

192 m³/hour = 0.0533 m³/sec

Next, we can rearrange the formula to solve for the cross-sectional area:

A = Q / v

A = 0.0533 m³/sec / 6.0 m/sec

A = 0.0089 m²

The cross-sectional area of the pipe is 0.0089 m².

Standard schedule 40 steel pipe has a nominal inside diameter (ID) of 1.049 inches, which is approximately 0.0266 meters. The cross-sectional area of the pipe can be calculated using the formula for the area of a circle:

A = π × (ID/2)²

A = 3.14 × (0.0266/2)²

A = 5.58×10^-4 m²

To determine the required size of the pipe, we can rearrange the formula for the area of a circle to solve for the diameter:

ID = 2 × √(A/π)

ID = 2 × √(0.0089/π)

ID = 0.106 meters

Therefore, the required size of standard schedule 40 steel pipe to carry 192 m³/hour of water with a minimum velocity of 6.0 m/sec is a nominal size of 4 inches, with an inside diameter of 0.102 meters (or 102 millimeters).

Answer:

41.67amps

Explanation:

v*a=w

120*a=5000

5000/12=41.67

Using α = 0.4, the forecasted sales for 2011, 2012, and 2013 would all be $48,000, which is the same as the actual sales in 2009.

Using α = 0.8, the forecasted sales for 2011, 2012, and 2013 would also be $48,000.

In both cases, the forecasts for 2011, 2012, and 2013 remain the same as the actual sales in 2009 due to the zero difference between the actual and forecasted sales values.

To forecast sales for 2011, 2012, and 2013 using exponential smoothing, we need to apply the formula:

Forecast for the next period = Previous period's forecast + α * (Actual value - Previous period's forecast)

Given that the actual 2009 sales are $48,000 and are considered the forecast for 2010, we can calculate the forecasts for subsequent years using different values of α.

(a) For α = 0.4:

- Forecast for 2011 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000

- Forecast for 2012 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000

- Forecast for 2013 = $48,000 + 0.4 * ($48,000 - $48,000) = $48,000

Using α = 0.4, the forecasted sales for 2011, 2012, and 2013 would all be $48,000, which is the same as the actual sales in 2009.

(b) For α = 0.8:

- Forecast for 2011 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000

- Forecast for 2012 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000

- Forecast for 2013 = $48,000 + 0.8 * ($48,000 - $48,000) = $48,000

Using α = 0.8, the forecasted sales for 2011, 2012, and 2013 would also be $48,000.

In both cases, the forecasts for 2011, 2012, and 2013 remain the same as the actual sales in 2009 due to the zero difference between the actual and forecasted sales values.

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Answer:

the percentage of light that gets through this combination is 9.38

Explanation:

Given the data in the question;

Let us represent the incident unpolarized light with \(I_0\).

So, the amount of light intensity passing through the first polarizer will be;

\(I_1\) = \(I_0\) / 2 ------ let this be equation 1

An the amount of light intensity passing through the second polarizer will be;

\(I_2\) = \(I_1\)cos²θ

given that; the second one has its transmission axis at 30°

so, we substitute;

\(I_2\) = \(I_1\) × cos²( 30° )

\(I_2\) = \(I_1\) × 0.75

\(I_2\) = 0.75\(I_1\)

from equation; \(I_1\) = \(I_0\) / 2

\(I_2\) = 0.75( \(I_0\) / 2 )

\(I_2\) = 0.375\(I_0\) .

Now, the amount of light intensity passing through the third polarizer will be;

\(I_3\) = \(I_2\)cos² ( 90° - 30° )

\(I_3\) = \(I_2\) × cos²( 60° )

\(I_3\) = \(I_2\)  × 0.25

we substitute

\(I_3\) = 0.375\(I_0\)  × 0.25

\(I_3\) = 0.09375\(I_0\)

∴ \(I_3\)/\(I_0\) × 100 = 0.09375 × 100

⇒ 9.38%

Therefore, the percentage of light that gets through this combination is 9.38

The values based on the information given will be Ra = 1000N and Rc= 90N

Weight refers to the measure of the force of gravity on an object, and is typically measured in units of mass, such as kilograms or pounds. Weight is influenced by the mass of the object and the strength of the gravitational field it is in.

Thickness, on the other hand, refers to the measure of how thick an object is, or the distance between opposite surfaces of an object. Thickness is typically measured in units of length, such as millimeters or inches.

While weight and thickness are not directly related to each other, they can both play important roles in determining the properties and uses of an object. For example, a thin piece of metal may be lightweight, but may not be strong enough to support heavy loads. Conversely, a thicker piece of metal may be heavier, but may be able to support heavier loads due to its increased strength.

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Answer:

try settings and go to updates?

Explanation:

Resistors limit the amount of current flow in the circuit. For devices connected to the circuit, some currents can damage their integrity. Therefore, resistors are often used to protect devices connected to the circuit that follow it.

The accelerations possible for a ball on an inclined plane is b. range from zero to g.

Why acceleration will be zero to g?

The acceleration of a ball rolling down an inclined plane depends on the angle of the plane and the gravitational force acting on the ball.

When a ball is rolling down an inclined plane, it is subject to two types of acceleration:

Since the angle of the incline can range from 0 to 90 degrees, the acceleration due to gravity acting down the slope can range from 0 to g. In other words, the range of possible accelerations is from zero to g.

So, in conclusion, the range of accelerations for a ball rolling down an inclined plane is from zero to g.

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Answer:

the answer I know is A. different substances. hope this helps :).

Explanation:

just always study hard and God bless.

With a three-wire control system, the motor would not re-start in the event of a power interruption: True.

In Electrical Engineering, a synchronous motor simply refers to an alternating current (AC) electric motor in which the rotational speed of the shaft is directly proportional (equal) to the frequency of the supply current, especially at steady state.

Generally speaking, a three-wire control system is designed and developed to prevent the automatic restarting of a machinery or electric motor when power is restored, after a power interruption.

In this context, we can logically deduce that the above statement is completely true.

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By using a small current in the relay winding, the contacts in the relay controls a larger current.

When a small current is passed through the relay winding, it serves as an electromagnet generating a magnetic field. This magnetic field attracts or repels the relay contacts causing them to close or open, respectively.

The purpose of the relay is to control a larger current circuit, typically in the range of amps or even higher. By using the small current in the relay winding to control the movement of the contacts, the relay can effectively switch or regulate the flow of a larger current.

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Answer:

there's no photo? but I'm willing to help

The peak-to-peak swing on the output voltage of the cascade amplifier is 4.8 Vpp.

To calculate the peak-to-peak swing on the output voltage, we need to consider the gain of the cascade amplifier. The gain determines the amplification of the input signal. In this case, since the input voltage swing is given as 0.2 Vpp, we can assume that the input signal swings symmetrically around a reference voltage.

Step 1: Determine the gain of the cascade amplifier.

The gain of the cascade amplifier can be calculated by dividing the peak-to-peak output voltage by the peak-to-peak input voltage. Since the input voltage swing is 0.2 Vpp, we can use this information to find the gain.

Step 2: Calculate the gain.

Let's assume the gain of the cascade amplifier is "A." Using the formula A = Vout_pp / Vin_pp, where Vin_pp is the peak-to-peak input voltage and Vout_pp is the peak-to-peak output voltage, we can substitute the given values. Thus, A = Vout_pp / 0.2 Vpp.

Step 3: Calculate the peak-to-peak output voltage.

To find the peak-to-peak output voltage, we rearrange the formula as Vout_pp = A * Vin_pp. Substituting the value of A and Vin_pp, we have Vout_pp = 4.8 Vpp.

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Answer:

The correct response is "821.88". A further explanation is given below.

Explanation:

According to the question,

The largest amount unresolved after five years would have been:

= \(35000\times (\frac{F}{P}, 4 \ percent,5 )\)

= \(35000\times 1.216 7\)

= \(42584.50\)

Now,

time (t) will be:

= \(5\times 12\)

= \(60 \ monthly \ payments\)

So, monthly payment will be:

= \(42582.85\times (\frac{A}{P}, 0.5 \ percent,60 )\)

= \(42584.50\times 0.0193\)

= \(821.88\)