1.
Many cancers have a mutation in their epidermal growth factor
receptors (EGFR). The dissociation constants of the non-mutant
receptor and two mutant receptors for a ligand are given.
EGFR
Kd (nM
Answers
The given problem can be solved by calculating the affinity of each mutant form and then comparing it to the wild-type value. Here, Kd is the equilibrium dissociation constant of the binding reaction between a ligand and its receptor. It represents the concentration of ligand required to achieve half-maximal binding to the receptor at equilibrium.
Most of the time, it is a measure of the strength of binding between the ligand and receptor.
The answer to the given problem is as follows:
Wild-type EGFR Kd = 1.2 nM
Mutant 1 Kd = 1.7 nM
Mutant 2 Kd = 3.0 nM
The higher the dissociation constant, the lower the affinity of the receptor for the ligand. In other words, the mutant forms of EGFR have a lower affinity for the ligand than the wild-type EGFR form.
Therefore, in the given problem, mutant 2 has the lowest affinity for the ligand out of all three forms.
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Related Questions
How does a plant root cell get the energy it needs to power all of its cellular processes??
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I'm not sure, but I would say it gets its energy from the Phloem, which transports nutrients around the plant.
12. Microwaves are one type of
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Are fireworks Biotic, Abiotic or Neither?
Answers
Answer:
fireworks are biotic
Explanation:
hope that helps
t/f during an infection with listeria, an intracellular bacterium, apcs will present antigen on mhc ii molecules.
Answers
During an infection with Listeria, an intracellular bacterium, antigen-presenting cells (APCs) will present antigen on MHC II molecules, the given statement is true because Listeria monocytogenes is a Gram-positive, intracellular bacterium that can cause severe foodborne infections, particularly in immunocompromised individuals.
Once inside the host, Listeria is engulfed by phagocytic cells such as macrophages and dendritic cells, which serve as APCs. APCs process and present the bacterial antigens to the immune system by displaying them on their MHC II molecules. This presentation is crucial for activating the adaptive immune response, specifically T-helper cells. These T-helper cells then interact with the MHC II-antigen complex, promoting the release of cytokines that aid in coordinating the immune response.
In addition to MHC II presentation, Listeria can also be presented on MHC I molecules through a process called cross-presentation. This mechanism allows the activation of cytotoxic T-lymphocytes (CTLs) to target and eliminate Listeria-infected cells. Overall, the presentation of Listeria antigens on MHC II molecules by APCs plays a critical role in the host's immune response against this intracellular bacterium.
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How greenhouse gases can lead to the formation of damaging acid rain
Answers
Explanation:
those gases dissolve with water vapor in the air to form H2SO4 and HNO3
When it rains, these acids dissolve into rainwater and makes the pH of the rainwwater decreases
Which term describes the relationship in which one organism lives inside the other one. Check ih correct answer
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Answer:
The term that describes the relationship in which one organism lives inside the other one is endosymbiosis.
Explanation:
Are carbon compounds and organic compounds the same
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How you complete this
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Answer:
Hi. Can you type the question, it's a bit confused reading it like this thank you!.
1. You have isolated a long hydrophobic molecule that inserts itself within biological membranes. Specifically, it spans
both layers of the lipid bilayer after insertion. Would you expect this molecule to mimic the effect that some general
anesthetics have? Why or why not? Refer to the general anesthetic mechanism outlined in Figure 5 as a resource.
Answers
The hydrophilic heads face the water at each bilayer surface in this energetically most-favorable configuration, while the hydrophobic tails are protected from the water inside.
What kind of lipids have both hydrophilic and hydrophobic ends?Phospholipids are lipids with phosphate groups and are a crucial part of cell membranes. A phospholipid has a hydrophilic (loving water) head and a hydrophobic (hating water) tail (see figure below).
In the body's aqueous environment, what interactions lead to the creation of lipid bilayers?Hydrophobic interactions are the primary mechanism behind the development of the lipid bilayer. A phospholipid's hydrophobic domains are attempting to repel polar hydrophilic water molecules.
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The main regulatory protein of secondary hemostasis and inhibitor of serine protease is:_________
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Answer:
Antithrombin
Explanation:
what type of symbiotic relationship do rhizobium and plants have?
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This image shows a volcanic eruption in Hawaii with lava flowing into the sea.
Which statement best describes this eruption?
Its magma is high in silica.
Its magma has low viscosity.
Its gases are released in rapid bursts.
Its lava came from an explosive eruption.
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The last one is right answer i think
A plant wilts and becomes floppy if it loses water faster than the roots can absorb water. Explain why a plant is more likely to wilt when the weather is hot and windy, rather than cool and still. :)
Answers
Answer:
Explanation: When the weather is hot and windy plants generally wilt because of the higher rate of transpiration.
Transpiration refers to the mechanism by which water evaporates from a plant's leaves.
The air surrounding the plant generally becomes hot and windy resulting in a faster rate of water loss through the leaves whereas the root struggles to absorb enough water from the soil to balance the water loss through leaves.
As a result, the plant suffers from water deficiency which causes withering and floppiness.
In contrast the rate of transpiration is reduced in cool and quiet weather, lowering the likelihood of water loss exceeding the roots ability to absorb water.
individual organism can adaptTrue, But it has to increase their fitnesssometimes, it depends on where they are located if the adoption is helpful or notfalse, only a population can adapt
Answers
Organisms can adapt to different environments, however, this usually occurs over generations and at the population level. At the level of the individual, an example is mutations, in which the offspring may have different characteristics from the progeny. However, these adaptations of the offspring will either be detrimental or give an advantage depending on the environment in which it is
Because these changes occur gradually over generations, individual organisms cannot increase their fitness on their own. And although there are special cases in which an organism can adapt to environmental changes through a phenomenon called phenotypic plasticity, this is not common in all species and is not due to a genetic change in the individual. Therefore, the answer would be B (sometimes, it depends on where they are located if the adaptation is helpful or not).
what animal eats fiddler crabs?
Answers
Answer:
Predators that feed on fiddler crabs include herons, egrets and raccoons. At one to two years, the fiddler crab reaches sexual maturity.
Explanation:
s bone marrow edema-like signal involving the roof of the left acetabulum and left anterior inferior iliac spine.
Answers
A bone marrow edema-like signal involving the roof of the left acetabulum and left anterior inferior iliac spine indicates an abnormal finding on the MRI suggestive of increased fluid and inflammation within the bone marrow. Further evaluation and diagnostic tests may be needed to determine the underlying cause.
Based on the information provided, it seems like you are describing a bone marrow edema-like signal involving the roof of the left acetabulum and left anterior inferior iliac spine.
In the main part, bone marrow edema-like signal refers to an abnormal MRI finding that indicates increased fluid and inflammation within the bone marrow. This signal can be seen as areas of increased intensity on the MRI images. The involvement of the left acetabulum and left anterior inferior iliac spine suggests that these areas are affected by the edema-like signal.
In the explanation, bone marrow edema-like signal can be caused by various factors such as trauma, infection, inflammation, or stress fractures. It is important to consider the patient's medical history, symptoms, and additional imaging findings to determine the underlying cause. Further evaluation, such as blood tests or additional imaging studies, may be necessary to make a definitive diagnosis.
In conclusion, a bone marrow edema-like signal involving the roof of the left acetabulum and left anterior inferior iliac spine indicates an abnormal finding on the MRI suggestive of increased fluid and inflammation within the bone marrow. Further evaluation and diagnostic tests may be needed to determine the underlying cause.
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Plasma resembles serum but has which additional protein? A. Platelets B. Albumin Nitrogenous C. wastes D. Glucose E. Fibrinogen
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Plasma resembles serum but has fibrinogen as additional protein
What is fibrinogen?Both serum and plasma are derived from the liquid fraction of blood that remains after the cells have been removed, but there is where the similarities end. Serum is the liquid left over after blood clots. Plasma is the liquid that remains after the administration of an anticoagulant prevents clotting.Fibrinogen is a glycoprotein complex that is generated in the liver and circulates in all vertebrate blood. Thrombin converts it enzymatically to fibrin during tissue and vascular injury, and ultimately to a fibrin-based blood clot. Fibrin clots primarily serve to occlude blood arteries in order to stop bleeding.For more information on fibrinogen kindly visit to
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The image shows groundwater zones. Top to bottom: Porous rock or soil, Water, Impermeable rock. Zone 1 is at the top of porous rock. Zone 2 is between porous rock and water. Zone 3 is in the Water. Zone 4 is between the Water and Impermeable rock. Which is the saturated zone?
Answers
Answer:
zone 3
Explanation:
Answer:
C
Explanation:
the importance of stem cells is that they are differentiated and can become..
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The importance of stem cells is that they are differentiated and can become daughter cells.
Why are stem cells important in differentiation?Stem cells have the potential to serve as the foundation of treatments for a wide range of illnesses due to their capacity to develop into almost any type of cell in the body. Standardized methods for stem cell cultivation and differentiation will be created as research advances.
In the body, stem cells have the capacity to differentiate into a wide variety of cell types. They act as the body's system for repairs. Adult stem cells and embryonic stem cells are the two primary categories of stem cells.
Therefore, one can say that daughter cells are created when stem cells divide properly in the body or a lab to create more cells. These daughter cells either differentiate into more stem cells or into cells with a more focused purpose.
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I need help pls...
If a man has red-green color blindness, a sex-linked dominant trait, what is a possible genotype of his father? I. XR Y II. Xr Y III. XR XR IV XR Xr A. Only III B. I and III C. I and II D. I, III, and IV
Answers
Answer:
C
Explanation:
The possible genotype of his father is \(X^RY\) and \(X^rY\).
For sex-linked traits, an affected man always inherit the affected allele from the mother. The other chromosome, which is the Y chromosome is always from the father and this confers maleness on individuals.
The father of a man affected for a sex-linked trait can be affected for the same trait or otherwise. It does not have any bearing on the male child since the father only donates the Y chromosome to the male child.
Hence, in this case, the father can either be affected for the same trait (\(X^RY\)) or be free from it (\(X^rY\)).
The correct option is C.
What is the difference between Carbonia and Insularia Peppered moths?
Answers
Carbonia and Insularia Peppered moths are two distinct forms or subspecies of the peppered moth (Biston betularia). The main difference between these forms lies in their geographic distribution and coloration.
Carbonia Peppered Moth: Carbonia is a form of peppered moth that is predominantly found in industrial areas where pollution and soot are prevalent.
These moths have dark or melanic coloration, which provides them with camouflage against the darkened tree trunks that were common in industrialized regions. The dark coloration of Carbonia moths helped them evade predators and increased their survival rates in polluted environments.
Insularia Peppered Moth: Insularia is another form of peppered moth that is primarily found in non-polluted or rural areas.
These moths have lighter or speckled coloration, which allows them to blend in with lichen-covered tree trunks that are common in unpolluted habitats.
The light coloration of Insularia moths provided them with camouflage against their natural background, reducing predation risk.
The difference in coloration between Carbonia and Insularia Peppered moths is an example of industrial melanism, where moth populations adapted to their changing environment due to human industrial activities.
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naturally occuring tn5 transposons contain:question 9 options:tnpatranscriptional terminatorsa kanamycin resistance genetwo is50 elements
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Naturally occurring tn5 transposons contain a kanamycin resistance gene, two is50 elements, and tnpatranscriptional terminators.
Transposons are genetic elements that can move from one location to another within the genome of an organism. The tn5 transposon is a naturally occurring transposon that has been extensively studied due to its ability to confer antibiotic resistance to bacteria. The tn5 transposon contains several important genetic elements, including a kanamycin resistance gene, two is50 elements, and tnpatranscriptional terminators.
The kanamycin resistance gene allows bacteria that contain the tn5 transposon to resist the effects of the antibiotic kanamycin. The is50 elements are short DNA sequences that flank the tn5 transposon and help to facilitate its movement within the bacterial genome. Finally, the tnpatranscriptional terminators are DNA sequences that help to regulate the expression of genes within the tn5 transposon.
Overall, the tn5 transposon is an important genetic element that contains several key genetic components. Understanding the structure and function of the tn5 transposon is important for researchers studying antibiotic resistance and other aspects of bacterial genetics.
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2. In a population of king snakes the banded pattern (B) is dominant to no banding
(b). If 12% of the population shows no banding, what percentage of the population,
to the nearest tenth, is heterozygous for banding?
Answers
Answer:
If 12% of the population shows no banding, this means that the frequency of the recessive allele (b) is 0.12^(1/2) or 0.3464 (assuming the population is in Hardy-Weinberg equilibrium). We take the square root because the recessive phenotype occurs only in individuals who are homozygous recessive (bb), and the frequency of homozygous recessive individuals is equal to the square of the frequency of the recessive allele.
To find the frequency of the dominant allele (B), we subtract the frequency of the recessive allele from 1:
Frequency of B = 1 - Frequency of b = 1 - 0.3464 = 0.6536
Since the banded pattern (B) is dominant to no banding (b), we can use the Hardy-Weinberg equation to calculate the frequency of heterozygous individuals:
2pq = 2 x 0.6536 x 0.3464 = 0.4529
Therefore, approximately 45.3% (to the nearest tenth) of the population is heterozygous for banding.
Explanation:
Protein Requirements The weekly question today involves calculating the protein requirement for several adult examples and yourself. The requirements calculated here are the RDA recommendation for good health. RDA for Protein is .8 grams/ kg body weight. Calculation example for adult weighing 125 lbs. 1. Convert weight from pound to kilograms. 125 lbs. + 2.2 lbs./kg = 56.8 kg (round to tenths) 2. Multiply weight by the constant. 56.8 kg x .8 grams/kg body weight = 45.4 grams protein per day Requirements to solve 1. Adult weighing 185 lbs. 2. Adult weighing 150 lbs. 3. Adult weighing 205 lbs. 4. Calculate your own protein requirement.
Answers
RDA protein requirement for good health is 0.8 grams/kg body weight. To calculate protein requirement, multiply body weight in kg by 0.8.
RDA (Recommended Dietary Allowance) for Protein is 0.8 grams/kg body weight to maintain good health. To calculate the protein requirement for an adult weighing 185 lbs:
Step 1: Convert weight from pound to kilograms: 185 lbs ÷ 2.2 lbs/kg = 84.09 kg (round to tenths)
Step 2: Multiply weight by the constant: 84.09 kg x 0.8 grams/kg body weight = 67.27 grams protein per day. Thus, the protein requirement for an adult weighing 185 lbs is 67.27 grams per day.
Similarly, for an adult weighing 150 lbs, it is 54.54 grams per day and for an adult weighing 205 lbs, it is 82.73 grams per day.
To calculate your own protein requirement, use the formula RDA protein requirement = 0.8 grams/kg body weight. Find your weight in kg and multiply it by 0.8. The result will be your protein requirement for good health.
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The Geologic Time Scale is a record of what?
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Answer:
the geologic time scale (gts) is a system of chronological dating that classifies geological strata in time. it is used by geologists to describe the timing and relationships of events in geologic history
Which axis should be used to represent the
dependent variable?
DONE
Intro
Answers
Answer:
y-axis because it changes frequently
Answer:
y-axis
Explanation:
independent variable goes on the x-axis , and dependent variable goes on the y-axis .
You used yeast to make beer. Under ideal condition, how many ATP molecules a yeast will gain from one molecule of glucose?a. 2b. 4 c. 38 d. 36 e. 0 30
Answers
Yeast is a microorganism that is commonly used in the process of making beer. Under ideal conditions, one molecule of glucose can produce 38 ATP molecules in yeast.
Yeast is a microorganism that is commonly used in the process of making beer. When yeast ferments glucose during beer production, it generates ATP molecules as an energy source. Under ideal conditions, one molecule of glucose can produce 38 ATP molecules in yeast. Actually, yeast is a kind of fungus linked to mushrooms. Although there are more than 1,000 types of yeast, Saccharomyces cerevisiae is typically the one utilized for baking. In fact, there are many yeast species in our bodies that coexist harmoniously with us. The yeast will become active if they are given warm water and something to eat (in the form of sugar). Therefore, the correct answer is 38.
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Plants and animals have adaptations that allow them to survive in their specific biome. Which explanation below is most accurate regarding animal and plant adaptations for survival in a desert biome?
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Answer:
animals in the biome have scaly skin to save water and stay cool : plants have thick tissues and shallow roots that capture water
sorry if I am wrong
Explanation:
How can you prevent a city from polluting a lake?
Best answer gets brainly, thanks, and 5 star vote!^^
Answers
Answer:
Use reusable water bottles, not disposable.
Don't wash your car in the driveway, wash it on the lawn.
Dispose of hazardous chemicals properly.
Recycle used motor oil.
Reduce, Reuse, Recycle.
Reduce auto emissions.
Explanation:
- wash your car in the grass instead of the road/ driveway for less chemicals going into the storm drain
- recycle, have a compost pile to decompose leaves, food, yard clippings etc and use for soil
Explain how an element is different from a compound or a mixture.