Balance the equation N2 +H20= NH3 + NO

Answer:

Explanation:

From the given information:

Let y(t) be the amount of sugar in tank A at any time.

Then, the rate of change of sugar in the tank is given by:

\(\dfrac{dy}{dt}= (rate \ in ) - ( rate \ out )\)

The rate of the sugar coming into the tank is 0

\(\text{rate of sugar going out }= \dfrac{y(t) \ pound}{100}\times \dfrac{1 }{min} \\ \\ = \dfrac{y}{100} \ pound/min\)

\(So; \\ \\ \\ \dfrac{dy}{dt} = 0 - \dfrac{y}{100} \\ \\ \implies \dfrac{dy}{y }= -\dfrac{dt}{100 } \\ \\ \implies dx|y| = -\dfrac{t}{100}+C \\ \\ \implies e*{In|y|}= e^{-\dfrac{t}{100}+C} \\ \\ \implies y = Ce^{-\dfrac{t}{100}}\)

Initial amount of sugar = 25 Pounds

Now; y(0) = 25

25 = Ce⁰

C = 25

So;  y(t) = 25 \(e^{-\dfrac{t}{100}\)

Thus, the amount of sugar at any time t = \(\mathbf{25 e^{^{-\dfrac{t}{100}}}}\)

B) For tank B :

\(\dfrac{dy}{dt}= 1 - \dfrac{y}{50 } \\ \\ \dfrac{dy}{dt}= \dfrac{50-y}{50} \\ \\ \dfrac{dy}{50-y }= \dfrac{dt}{50}\)

Answer:

Fe3(PO4)2

Explanation:

calculate the molar mass for each of the following compounds 7. PbSO

8. Ca(OH)2

9. Na3PO4

10. (NH4)2CO3

11. C6H12O6

12. Fe3(PO4)2

13. (NH4)2S

14. Zn(C2H3O2)2

In the following experiment, a coffee-cup calorimeter containing 100 mL of \(H_{ 2} O\) is used. The initial temperature of the calorimeter is 23.0 ∘C. If 6.60 g of \(CaCl_{2}\) is added to the calorimeter, Final temperature of the solution in the calorimeter = 11.

The first step in solving this problem is to calculate the number of moles of \(CaCl_{2}\\\) added to the calorimeter.

Moles of \(CaCl_{2}\) = mass of \(CaCl_{2}\) / molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 6.60 g / 110.98 g/mol (molar mass of \(CaCl_{2}\)

Moles of\(CaCl_{2}\) = 0.0594 mol

We can use the equation for heat transfer to find the change in temperature of the solution. q = mCsΔT, where q is the heat transferred, m is the mass of the solution, Cs is the specific heat of the solution, and ΔT is the change in temperature.

We know that the initial temperature of the calorimeter is 23.0 ∘C and the mass of the solution is 100 g (since the density of water is 1 g/mL). We can solve for ΔT: ΔT = q / mCs

To find q, we can use the enthalpy change of solution (ΔHsoln) and the number of moles of\(CaCl_{2}\)added: q = ΔHsoln x moles of\(CaCl_{2}\)

q = -82.8 kJ/mol x 0.0594 mol

q = -4.92 kJ

Now we can solve for ΔT: ΔT = (-4.92 kJ) / (100 g x 4.184 J/g⋅∘C)

ΔT = -11.8 ∘C

We can find the final temperature of the solution by adding the change in temperature to the initial temperature: Final temperature = 23.0 ∘C - 11.8 ∘C =11 ∘C.

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In this case, it can be see that we have a gas mixture wherein hydrogen has a partial pressure of 0.545 bar, nitrogen 0.517 bar and argon 0.107 bar and we are asked to calculate the mole fraction of each gas.

According to the given information, it turns out possible for us to use the Dalton's law in order to calculate the mole fraction of each gas in the mixture. However, we first must calculate the total pressure of the mixture by adding them all together:

\(P_T=0.545bar+0.517bar+0.107bar=1.169bar\)

After so, we proceed to the mole fractions by dividing the pressure of each by the total one:

\(x_{H_2}=\frac{0.545bar}{1.169bar} =0.466\\\\x_{N_2}=\frac{0.517bar}{1.169bar} =0.442\\\\x_{Ar}=\frac{0.107bar}{1.169bar} =0.092\)

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Regards!

Answer:

Sulfur is considered an “impurity” in petroleum. Sulfur in crude oil can corrode metal in the refining process and contribute to air pollution. Petroleum with more than 0.5% sulfur is called “sour,” while petroleum with less than 0.5% sulfur is “sweet.”

Answer: Decreases

Explanation: Electronegativity decreases because the valence electrons are farther from the nucleus.

The genetic variations in the bird population can lead to differences in behavior, physiology and morphology which can impact birds' survival and reproductive success.

In the population of bird species, there may be genetic variations such as difference in feather color, beak size and shape, and wing shape. Some birds may have brown feathers and others may have black or white feathers.

Beak size and shape may vary, with some birds having longer or shorter beaks, and some having curved or straight beaks. Wing shapes may also differ with some birds having longer, narrower wings and others having shorter and wider wings.

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When hydrogen bromide is added to 2-methylbut-2-ene, two products are expected to be produced: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product).

The addition of HBr to 2-methylbut-2-ene follows the Markovnikov addition rule. This means that the hydrogen atom and the bromine atom will add to the carbon atoms in the double bond, such that the hydrogen atom adds to the carbon with the greater number of hydrogen atoms, and the bromine atom adds to the carbon with the lesser number of hydrogen atoms.

In this case, the hydrogen atom will attach to the second carbon atom, which has three hydrogen atoms, while the bromine atom will attach to the third carbon atom, which has only one hydrogen atom. This produces the major product, 2-bromo-2-methylbutane.

The formation of the minor product, 3-bromo-2-methylbutane, occurs due to the rearrangement of the carbocation intermediate formed during the addition reaction. The carbocation can rearrange either by shifting a methyl group from the second to the third carbon, or by shifting a hydrogen atom from the third to the second carbon. This rearrangement produces the minor product, 3-bromo-2-methylbutane.

In conclusion, the addition of HBr to 2-methylbut-2-ene produces two products: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product). The major product forms due to Markovnikov addition rule, while the minor product forms due to carbocation rearrangement.

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Answer:

All elements of period 7 are radioactive. This period contains the actinides, which includes plutonium, the naturally occurring element with the heaviest nucleus; subsequent elements must be created artificially.

Explanation:

hope u understand :)

7th period elements are from 87 to 118, and they are all radioactive elements and unstable. They are produced by nuclear transmutation and have short life in earth.

Some atoms undergo nuclear decay by emitting charged particles alpha or beta particles. Hence, they are unstable and produce other stable isotopes or atoms through radioactive decay process.

Periods in a periodic table are horizontal rows where from left to right the atomic number increases. There are 7 periods and 18 groups in periodic table. Alog a period electronegativity and ionization energy increases.

Elements of 7th period are called actinides includes, uranium, actinium, thorium, plutonium etc. They are all radioactive and are thus unstable. Some of them such as uranium and plutonium  are used as nuclear fuel in power generation.

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The pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.

Ideal gas equation is defined as the state equation for a fictitious perfect gas. Although it has significant drawbacks, it is a decent approximation of the behavior of many gases under various conditions.

Ideal gas equation is expressed as

PV = nRT

By using Ideal gas equation

P x 0.016773 = 1 x 81.49 x 483

P = 1.861 MPa

By using generalized compressibility chart

For r134a

Temperature = 374.2 K

Pressure = 4.06 MPa

vR = V / R x Tc / Pc

    = 0.016773 / 81.49 x ( 374.2 / 4.06 x 10⁶ )

    = 2.2332

Tr = T/Tc = 383 / 374.2 = 1.024

Therefore from the chart Z = 0.85

So, P = Z mRT / V

      P = 0.85 x 1 x 81.49 x 383 / 0.016773

         = 1.582 MPa

By using refrigerant tables

T = 110 C and v = 0.0167763

So, P = 1.6 MPa

Thus, the pressure of the refrigerant using the ideal-gas equation is 1.861 MPa, the generalized compressibility chart is 1.583 MPa and the refrigerant tables is 1.6 MPa.

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HCN, Na2SO4: Combination of compounds.

Mg3N2: Chemical compound.

CO2, H2O: Dissolution or hydration reaction.

Cu, Zn(NO3)2: Single-replacement reaction.

Na, N2: Combination of elements.

Let's analyze each chemical combination to determine the type of reaction involved:

HCN, Na2SO4:

The combination of hydrogen cyanide (HCN) and sodium sulfate (Na2SO4) does not represent a specific chemical reaction. It is simply the combination of two compounds.

Mg3N2:

Mg3N2 represents a chemical compound, magnesium nitride. It does not indicate a specific reaction.

CO2, H2O:

The combination of carbon dioxide (CO2) and water (H2O) represents a chemical reaction known as hydration or dissolution. When carbon dioxide dissolves in water, it forms carbonic acid (H2CO3), which can further dissociate into hydrogen ions (H+) and bicarbonate ions (HCO3-).

Cu, Zn(NO3)2:

The combination of copper (Cu) and zinc nitrate (Zn(NO3)2) represents a single-replacement reaction. Copper displaces zinc from the compound, resulting in the formation of copper nitrate (Cu(NO3)2) and zinc metal (Zn).

Na, N2:

The combination of sodium (Na) and nitrogen gas (N2) does not represent a specific reaction. It is simply the combination of two elements.

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Answer: In gases the particles move rapidly in all directions, frequently colliding with each other and the side of the container. With an increase in temperature, the particles gain kinetic energy and move faster. The actual average speed of the particles depends on their mass as well as the temperature – heavier particles move more slowly than lighter ones at the same temperature. The oxygen and nitrogen molecules in air at normal room temperature are moving rapidly at between 300 to 400 metres per second. Unlike collisions between macroscopic objects, collisions between particles are perfectly elastic with no loss of kinetic energy.

Explanation:  This is very different to most other collisions where some kinetic energy is transformed into other forms such as heat and sound. It is the perfectly elastic nature of the collisions that enables the gas particles to continue rebounding after each collision with no loss of speed. Particles are still subject to gravity and hit the bottom of a container with greater force than the top, and giving gases weight. Hope this helps with your problem! Byeeee :DDD

It's sad seeing people actually helping you lol.

and then you dont give brainliest. like ever.

the maximum amount of product that can be formed is 124.39 g SO₃, and there will be 36.8 g of excess O₂ left over.

To find the amount of excess reagent, you need to first determine which reactant is limiting and which is in excess.

Determine the limiting reagent:

Use stoichiometry to determine how much product can be formed from each reactant:

mol SO2:

2 SO₂ + O₂ -> 2 SO₃

2 mol SO₃/2 mol SO₂ = 1 mol SO₃/mol SO₂

1 mol SO₃ = 80.06 g SO₍₃₎

From 2.7 mol O₂

2 SO₂ + O₂ -> 2 SO₃

1 mol SO₃/1 mol O₂ = 1 mol SO₃/mol O₂

1 mol SO₃ = 80.06 g SO₃

2.7 mol O₂ x (1 mol SO₂/1 mol O₂) x (80.06 g SO₂/mol SO₂) = 216.45 g SO₂

Since the amount of SO₂ produced from 3.1 mol of SO₂ is less than the amount produced from 2.7 mol of O₂, SO₂ is the limiting reagent.

Calculate the amount of excess reagent:

To find the amount of excess O₂, use the balanced equation to determine how much O₂ is required to react with all of the SO₂:

2 SO₂ + O₂ -> 2 SO

3.1 mol SO2 x (1 mol O₂/2 mol SO2) = 1.55 mol O₂

Subtract the amount of O₂ used from the initial amount of O₂:

2.7 mol O₂ - 1.55 mol O2 = 1.15 mol O₂

Finally, convert the excess O₂ to mass:

1.15 mol O₂ x 32.00 g/mol = 36.8 g O₂

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Moles of iron = 7.30

Given

mass of iron = 408.67 g

Required

moles of atoms

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

mol iron-Fe (Ar = 56 g/mol)

mol = mass : MW

mol = 408.67 g : 56

mol = 7.30

Answer:

\(N_2~+~3H_2~+~4O_2~->~2HNO_3~+~2H_2O\)

Explanation:

We can start with the reaction of hydrogen and nitrogen to produce ammonia, so:

\(N_2~+~H_2~->~NH_3\)

When we balance the reaction we will obtain:

\(N_2~+~3H_2~->~2NH_3\)

Now, the production of nitric acid with oxygen would be:

\(NH_3~+~O_2~->~HNO_3~+~H_2O\)

If we balance the reaction we will obtain:

\(NH_3~+~2O_2~->~HNO_3~+~H_2O\)

Now, if we put the reactions together we will obtain:

\(N_2~+~3H_2~->~2NH_3\)

\(NH_3~+~2O_2~->~HNO_3~+~H_2O\)

We can multiply the second reaction by "2":

\(N_2~+~3H_2~->~2NH_3\)

\(2NH_3~+~4O_2~->~2HNO_3~+~2H_2O\)

We have "\(2NH_3\)" on both sides. In the first reaction is in the right in the second reaction is on the left. Therefore we can cancel out this compound and we will obtain:

\(N_2~+~3H_2~+~4O_2~->~2HNO_3~+~2H_2O\)

On this reaction, we will have 2 nitrogen atoms on both sides, 6 hydrogen atoms on both sides, and 8 oxygen atoms on both sides. So, this would be the net reaction for the production of nitric acid.

Answer:

Explanation:

Here, we want to get what would be equal on both sides of the chemical equation

For the balancing, the number of atoms of each of the element is what we are balancing

Thus, what we have equal on both sides of the reaction is the total number of elements

Answer:

What would be the formal charge of N in NO2?

Explanation:

The nitrogen gets two electrons for the double bond, one from the single bond and one from the half-filled orbital associated with it. That's a total of 4 and gives N a +1 formal charge since itneeds 5 to be neutral. The Rules for Writing Lewis Structures has some discussion of formal charge in it.

Answer:

D. 2:5

Explanation:

It has 5 valency electrons

\(.\)

In the given question, the electronic configuration of nitrogen is 2,5. The correct answer is option D.

The electronic configuration of an atom describes the arrangement of its electrons in different energy levels or orbitals.

Nitrogen has an atomic number of 7, which means it has 7 electrons.

Therefore, the electronic configuration of nitrogen is 2,5, which means it has 2 electrons in its first energy level and 5 electrons in its second energy level. Option D is the correct answer.

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The mass of sulfur dioxide required is approximately 6.36 grams.

To determine the number of grams of sulfur dioxide (SO2) required to exert a pressure of 0.705 atm in a 2.50L tank at 0 °C, we can use the ideal gas law equation: PV = nRT.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15, so the temperature becomes 273.15 K. The ideal gas constant (R) is 0.0821 L·atm/(mol·K).Rearranging the ideal gas law equation to solve for the number of moles (n), we get n = PV / RT.

Plugging in the given values, n = (0.705 atm) * (2.50 L) / [(0.0821 L·atm/(mol·K)) * (273.15 K)]. Calculating this expression, we find that n is approximately 0.0993 moles.The molar mass of sulfur dioxide is 64.06 g/mol (32.06 g/mol for sulfur + 2 * 16.00 g/mol for oxygen).

Finally, we can calculate the mass of sulfur dioxide using the formula: mass = n * molar mass = 0.0993 moles * 64.06 g/mol. Thus, the mass of sulfur dioxide required is approximately 6.36 grams.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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The given reaction releases 906 kJ of heat energy when 4 moles of ammonia react.

So, the amount of heat energy released when 1 mole of ammonia reacts is:

906 kJ ÷ 4 mol = 226.5 kJ/mol

To produce 453 kJ of heat energy, we can use the following proportion:

226.5 kJ/mol = 453 kJ/x

where x is the number of moles of ammonia required.

Solving for x, we get:

x = (453 kJ × 4 mol) ÷ 906 kJ

x ≈ 2 mol

Therefore, 2 moles of ammonia must react to produce 453 kJ of heat energy.

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PO₄ appears in two different places in this chemical equation. PO₃⁻⁴ is a polyatomic ion called phosphate. 2 should be placed in front of Na₃PO₄ to give the same total number of phosphate ions on each side of the equation.

For the reaction -

? Na₃PO₄ + MgCl₂  →  Mg₃(PO₄)₂ + NaCl

There are 2 phosphate ions present on the product side, therefore, 2 phosphate atoms should be present on the reactant side to maintain the equilibrium.

On product side, number of ions of magnesium is 3, so to attain the equilibrium and balance the equation there 3 ions of magnesium should be on the reactant side.

In order to balance the number of ions of phosphate and magnesium in the reaction which is given -

On the reactant side, 6 atoms of chlorine and sodium are formed, in order to balance these 6 atoms of chlorine and sodium, 6 atoms of each should be present on the product side.

Therefore, the balanced chemical equation is -

2 Na₃PO₄ + 3 MgCl₂  →  Mg₃(PO₄)₂ + 6 NaCl

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After 3 half-life, 12 of the 14 of the C-14 = 18 of the C-14 would remain.

Answer:

Explanation:

b. testing the hypothesis

This problem is requiring the empirical formula for CaCO₃, which is its molecular formula, and turns out to be equal, this is A. CaCO3 according to the following:

In chemistry, molecular formulas show both the actual type and number of atoms in a chemical compound, based on the elements across the periodic table and the subscripts standing for the number of atoms in the compound.

However, the empirical formula is a reduced expression of the molecular one, which shows the minimum number of atoms in a compound after simplifying to the smallest whole numbers.

In such a way, since the given compound is CaCO₃ and both Ca and C have a one as their subscript, it is not possible to simplify any further and therefore the empirical formula equals the molecular one this time, making the answer to be A. CaCO3.

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The ratio of the concentrations at equilibrium is as follows:

Chemical equilibrium is the point in a chemical reaction where both the forward and backward processes are occurring at the same rate.

The concentrations of the reactants and products are constant at equilibrium because the forward and reverse speeds are equal.

Considering the given statements based on the reaction equilibrium concentrations, the correct options are:

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Answer:

57.47 grams of sodium is in the sample.

Explanation:

Given that a 100.0-g sample of sodium hydroxide contains sodium, oxygen, and hydrogen, and the sample contains 2.53 g of hydrogen and 40.0 g of oxygen, to determine what mass of sodium is in the sample the following calculation must be performed:

100 - (40 + 2.53) = X

100 - 42.53 = X

57.47 = X

Therefore, 57.47 grams of sodium is in the sample.

Answer: 380 J. Please mark

Explanation: