Answer:
a=3m/s squared
Explanation:
a=v-u/t
where a=acceleration,v=final velocity,u=initial velocity,t=time taken
a=10-4/2-0
a=6/2
a=3m/s squared
A body on the surface of the earth weichs 400 Ib. The radius of the earth is about 4,000 miles. If this same body were placed on a 4,000 mile high tower, its weight would be a. 100 lbs b. 200 lbs c. 400 lbs d. 800 lbs e. 16,000 lbs
Option a is correct.
F=GMm/R²
where F is the gravitational force or weight
G is the universal constant of gravitation
M is the mass of Earth
m is the mass of the object
R is the distance between the center of the earth and the object
Given,
initial distance R =4000miles
weight at surface of the earth F=400lb
Let the force be F' for a distance R' from earth's center.
Here R' = radius+ height of the tower = R+4000 miles = 4000 + 4000 = 8000 miles.
Since the other terms in the formula remain constant, the new weight F' can be calculated as follows:
F'/F = R²/R'(otherwise the inverse square law in gravitation)
F'/400=(4000)²/(8000)²
F' = 100 lb
Thus option a is correct.
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The weight of the body on a 4000-mile high tower would still be 400 lbs.
Explanation:The weight of an object depends on the gravitational acceleration at its location. On the surface of the Earth, the gravitational acceleration is approximately 32 ft/s2. Therefore, a 400 lb body on the Earth's surface would weigh 400 lbs. If the body were placed on a 4000-mile high tower, it would be much farther from the center of the Earth and experience a weaker gravitational pull. The weight of the body would decrease as the square of the ratio of the radii of the tower and the Earth. So, the weight on the tower would be:
Weight on the tower = (400 lb) * (4000 mi/4000 mi)2 = 400 lb * 1 = 400 lb
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Momentum is usually not exactly conserved in a real world demonstration of momentum conservation. What is a possible reason for this fact?
Answer:
For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.
Explanation:
Hope this helps
hi can someone please answer the number 2 question i really need it thank you ❤️
#Batangas
\(\\ \tt\longmapsto d=\dfrac{49.07}{8}\times 100\)
\(\\ \tt\longmapsto d=6.13(100)\)
\(\\ \tt\longmapsto d=613km\)
#Puerto Princesa
\(\\ \tt\longmapsto d=\dfrac{58.10}{8}\times 100\)
\(\\ \tt\longmapsto d=7.26(100)\)
\(\\ \tt\longmapsto d=726km\)
#Davao
\(\\ \tt\longmapsto d=\dfrac{39.47}{8}\times 100\)
\(\\ \tt\longmapsto d=4.93(100)=493km\)
An electric current is transmitted through an aluminum wire that has been coiled several times around a piece of metal.
What the curved and looped arrows represent in the diagram?
a. magnetic field lines created by Earth's gravity acting on the wire
b. magnetic field lines created by Earth's magnetic field acting on the wire
c. magnetic field lines created when the aluminum wire removes the metal's magnetic field
d magnetic field lines created when the metal is inserted into the wire coil
The curved and looped arrows will represent the magnetic field lines created by Earth's magnetic field acting on the wire. Therefore the answer is (b).
Principles behind magnetic fieldsThe Earth's magnetic field can induce a magnetic field in the wire when it carries an electric current. This magnetic field is perpendicular to both the direction of the current flow and the Earth's magnetic field lines. The magnetic field produced by the current flowing through the wire interacts with the Earth's magnetic field, causing the magnetic field lines to loop around the wire in a specific direction. This phenomenon is known as the "right-hand rule" and is commonly used to determine the direction of the magnetic field produced by a current-carrying wire.
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What is one of the most important tips or skills for getting and staying organized? How do you feel this helps?
Answer:
Know what you need and what to discard
Explanation:
Knowing what to do with all your things/information helps declutter and to become more organized.
At t = 0 a rock is projected from ground level with a speed of 15.0 m/s and at an angle of 53.0° above the horizontal. Neglect air resistance
When the rock is projected at an angle of 53.0° above the horizontal with a speed of 15.0 m/s, it will follow a parabolic trajectory due to the influence of gravity. Since air resistance is neglected, the only force acting on the rock is gravity. The trajectory of the rock can be calculated using the equations of projectile motion.
The time taken by the rock to reach its maximum height can be calculated using the formula t = Vsinθ/g, where V is the initial velocity, θ is the angle of projection, and g is the acceleration due to gravity. The maximum height attained by the rock can be calculated using the formula h = V^2sin^2(θ)/2g. The range of the rock can be calculated using the formula R = V^2sin(2θ)/g. Therefore, the trajectory of the rock can be fully determined by these equations, provided air resistance is ignored.
At t=0, a rock is projected from ground level with a speed of 15.0 m/s and at an angle of 53.0° above the horizontal. To determine the maximum height and horizontal range, first split the initial velocity into its horizontal and vertical components.
Step 1: Calculate the horizontal and vertical components of the initial velocity:
Horizontal component (Vx) = 15.0 m/s * cos(53.0°)
Vertical component (Vy) = 15.0 m/s * sin(53.0°)
Step 2: Find the time it takes to reach the maximum height:
t = Vy / g
where g is the acceleration due to gravity, approximately 9.81 m/s².
Step 3: Calculate the maximum height (H) using the following equation:
H = (Vy²) / (2 * g)
Step 4: Find the time it takes to reach the ground (total flight time) using the equation:
t_total = 2 * Vy / g
Step 5: Calculate the horizontal range (R) using the equation:
R = Vx * t_total
By following these steps, you can find the maximum height and horizontal range of the rock's trajectory, neglecting air resistance.
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4
(a) Which arrow shows the amplitude of the wave?
(1 mark)
Answer:
hmmm, where is the image?
but still let me tell you
Explanation:
amplitude of a wave is the maximum displacement of a particle from its rest position
so the arrow should be from the middle of the wave to the top of the crest or to the bottom trough,
from the middle
okay?
hope this helps, but be sure to add the image next time
8× +5+9×+3 how can I solve this
Answer:
collect like terms then add=>8x+9x+5+3
=>8x+9x+5+3=>17x+8
A vector has an x-component of length of 3 and a y-component of length 4. What is the angle of the vector? (Hint: Use the inverse tangent)
Answer:
tan theta = y / x = 4 / 3 = 1.33
arctan 1.33 = 53.1 deg
A 5kg bowling ball is rolling with 75kg*m/s. How fast is it going?
Answer:
you are going 1 mile per hour depending on how fast
Explanation:
300 watts of power is produced over 15 seconds. How much work was done transferring the power?
Answer:
4500
Explanation:
Formula: power x time
300 x 15 = 4500
what are the principal differences between an mhd generator and a conventional generator?
The principal difference between an MHD generator and a conventional generator lies in their operational mechanisms.
While conventional generators work by converting mechanical energy into electrical energy through the use of electromagnetic induction, MHD generators produce electricity by utilizing a combination of magnetic and electric fields to ionize a conductive gas and create a flow of charged particles.
Additionally, MHD generators can operate at higher temperatures and pressures than conventional generators, allowing for more efficient energy production.
However, MHD generators are more complex and expensive to build and maintain than conventional generators, and they require a constant source of high-temperature gas to function.
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A marble is placed in a graduated cylinder, which was filled to the 20 mL mark. The level rises to 40 mL. What happens to the volume of the water?
Answer:
Below
Explanation:
The volume of water remains the same....the new measurement now includes the volume of the marble ( 20 ml)
the diagram below represents the orbits of earth, comet temple-tuttle, and planet x, another planet in out solar system. arrows on each orbit represent the direction of movement. which objects orbit would have and eccentricity close to 1?
Answer:
the most elliptical orbit is that of COMETA
Explanation:
The eccentricity of a curve in defined as the ratio between lacia to the focus, called c and the value of the axis greater than
ε = c / a
if we use Pythagoras' theorem
c = \(\sqrt{a^2 - b^2}\)
substituting
ε = \(\sqrt{1 - (b/a)^2 }\)
if ε = 0 we have a circumference
In the diagram presented the orbit of the comet is an ellipse a> b
ε=\(\sqrt{1- x} \\ x = (\frac{b}{a} )^2\)
if we expand in series
ε = 1 - x/2
ε= \(1 - \frac{1}{2} \ (\frac{ b}{a} )^2\)
if we neglect the non-linear terms
ε = 1
Earth's orbit is a small ellipse
b / a = 149 10⁶ / 151 10⁶
b / a = 0.98675
ε = \(\sqrt{1- 0.98675^2}\)
ε = 0.16
a very small ellipse
Planet X, despite not having data, it seems that the sun is in the scepter of the orbit, so b = a
therefore both the semi-axes of the curve
e = a / b
Consequently, the most elliptical orbit is that of COMETA.
URGENT HELPP
19. A 5 m long wooden pole PQ can be balanced horizontally if pivoted at a point 2 m from the end P, as shown in the diagram. If pivoted at the point 2 m from end Q, a weight of 500 N has to be hung at Q for the pole to remain balanced horizontally, as shown in another diagram. What is the weight of the wooden pole?
A. 500 N
B. 670 N
C. 800 N
D. 1000 N
The weight of the wooden pole is 500 N. The correct answer is option A.
To determine the weight of the wooden pole, we can use the principle of moments. The pole is balanced horizontally when the sum of the clockwise moments is equal to the sum of the counter clockwise moments.
When pivoted at a point 2 m from end P, the weight of the pole can be balanced by the moment created by the weight of the pole itself. Let's denote the weight of the pole as W_pole. The clockwise moment created by the weight of the pole is W_pole * 2 Nm.
When pivoted at a point 2 m from end Q, a weight of 500 N is needed to balance the pole horizontally. The counterclockwise moment created by the weight of 500 N is 500 N * 2 Nm.
Since the pole is balanced horizontally in both cases, the clockwise moment and the counter clockwise moment must be equal.
W_pole * 2 Nm = 500 N * 2 Nm
Simplifying the equation:
W_pole = 500 N
Therefore, the weight of the wooden pole is 500 N. The correct answer is option A.
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Atruck with a mass of 5280 Kg has an acceleration of 45 m/s/s what is the force acting on the truck?
in which phase is the solution defined?
A solution is defined as the homogeneous mixture which has the same composition throughout. A solution can exist in any phase.
What is binary solution?A solution which is made up of two constituents or components is defined as the binary solution. The term solute is commonly used to refer to the constituent that dissolves and the term solvent is one in which the dissolution takes place.
There can be three physical states in which the solutions may exist, there can be three types of solutions: solid solutions, liquid solutions and gaseous solutions. There are solid solutions, liquid solutions and gaseous solutions.
Thus the solution can exist in any phase.
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One particle has a charge of 2.15 x 10^ -9 while another particle has a charge of 3.22 x 10^ -9 If the two particles are separated by 0.015 m, what is the electromagnetic force between them? A. 4.31 x 10^ -7 N B. 2.77 x 10^ -4 N C. 4.15 x 10^ -6 N D. 6.22 x 10^ -4 N
Answer:
B. 2.77 x \(10^{-4}\) N
Explanation:
The required force can be calculated by:
F = \(\frac{Kq_{1}q_{2} }{d^{2} }\)
Where F is the force between the particles, K is the coulomb's constant (9 x \(10^{9}\) \(Nm^{2}/C^{2}\)), \(q_{1}\) is the charge on the first particle, \(q_{2}\) is the charge on the second particle and \(d^{2}\) is the distance between the particles.
So that:
F = \(\frac{9*10^{9}*2.15*10^{-9} *3.22*10^{-9} }{(0.015)^{2} }\)
= \(\frac{6.2307*10^{-8} }{(2.25*10^{-4} }\)
= 2.7692 x \(10^{-4}\)
The force between the particles is 2.77 x \(10^{-4}\) N.
Answer:
b
Explanation:
a pex
*100 points*
A blue and a green billiard ball, each with a mass of 0.15 kg, collide directly. Before the collision, the blue ball had a speed of 3 m/s while the green ball had a speed of 2 m/s. After the collision, the blue ball stays in place while the green ball continues in motion.
In 3-4 sentences, represent the situation before and after the collision and calculate the speed of the green ball after the collision. Be sure to discuss direction.
The speed of the green ball after the collision will be "1 m/s".
According to the question,
Before collision,
Mass,
\(m_1=m_2 = 0.15 \ kg\)Speed,
\(u_1 = 3 \ m/s\)\(u_2 = -2 \ m/s\)Let,
Blue ball moving in (+) axis.Green ball moving in (-) axis.After collision, the final velocity of blue ball be "\(v_1\)".then, \(v_2 =0\)
The momentum conversion will be:
→ \(m_1 u_1 +m_2 u_2 = m_1 v_1\)
→ \(v_1 = u_1 +u_2...(m_1=m_2)\)
→ \(v_1 = 3 -2\)
→ \(v_1 = 1 \ m/s\) (Speed of green ball)
Thus the above answer is correct.
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Answer: The speed of the green billiard ball after the collision is 1 m/s
Explanation:
Mass (Before the collision) m1 and m2 - 0.15 kg
Speed (Before the collision) - u1 = 3 m/s and u2 = -2 m/s
Velocity (After the collision) v1 - final velocity of the blue ball
v2 = 0
m1u1 + m2u2 = m1v1 (momentum conversion)
v1 = u1 + u2 (m1 = m2)
v1 = 3 - 2
v1 = 1 m/s
Let's say the blue billiard ball is going north and the green billiard ball is going west. They would collide directly into each other with the same mass of 0.15 kg. Since the blue billiard ball has the speed of 3 m/s and the green billiard ball has a speed of 2 m/s, you would subtract them to get the velocity after the collision (v1) of the green ball since we already have the velocity before the collision (v2) which equaled zero. The speed of the green billiard ball after the collision is 1 m/s.
All sound waves are produced by vibrating particles ?
If a vehicle's speed doubles from 20 mph to 40 mph, the distance needed to stop the vehicle increases by ___ times. a) 2 b) 3 c) 4 d) 8. c) 4
The average reaction distance is around 1 second at 20 mph. Let's say that the distance covered by the vehicle in 1 second is 8 meters. Therefore, the reaction distance is 8 meters.
Braking distance is the distance the vehicle travels from the time the driver applies the brakes until the time the vehicle comes to a complete stop. This distance is affected by many factors such as road conditions, tire conditions, and the condition of the brakes. On dry roads, the average braking distance is around 4 times the speed of the vehicle in meters.
Let's say the vehicle weighs 1,000 kg and has good brakes and tires. In this case, the braking distance would be around 24 meters (4 x 20 x 0.25).
Therefore,Stopping Distance = Perception Distance + Reaction Distance + Braking Distance= 7.5 + 8 + 24= 39.5 meters.
Now, let's calculate the distance required to stop a vehicle traveling at a speed of 40 mph.
Stopping Distance = Perception Distance + Reaction Distance + Braking Distance.
As the length of the vehicle and the reaction time of the driver do not change, the only variable that changes in this equation is the braking distance.
Therefore, Stopping Distance = Perception Distance + Reaction Distance + Braking Distance= 7.5 + 8 + (4 x 40 x 0.25)= 79 meters.
Therefore, if the speed of a vehicle doubles from 20 mph to 40 mph, the distance required to stop the vehicle increases by 4 times.
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what is the energy (in j) of a photon required to excite an electron from n = 2 to n = 8 in a he⁺ ion? submit an answer to three signficant figures.
Answer:
Approximately \(5.11 \times 10^{-19}\; {\rm J}\).
Explanation:
Since the result needs to be accurate to three significant figures, keep at least four significant figures in the calculations.
Look up the Rydberg constant for hydrogen: \(R_{\text{H}} \approx 1.0968\times 10^{7}\; {\rm m^{-1}\).
Look up the speed of light in vacuum: \(c \approx 2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}\).
Look up Planck's constant: \(h \approx 6.6261 \times 10^{-34}\; {\rm J \cdot s}\).
Apply the Rydberg formula to find the wavelength \(\lambda\) (in vacuum) of the photon in question:
\(\begin{aligned}\frac{1}{\lambda} &= R_{\text{H}} \, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\end{aligned}\).
The frequency of that photon would be:
\(\begin{aligned}f &= \frac{c}{\lambda}\end{aligned}\).
Combine this expression with the Rydberg formula to find the frequency of this photon:
\(\begin{aligned}f &= \frac{c}{\lambda} \\ &= c\, \left(\frac{1}{\lambda}\right) \\ &= c\, \left(R_{\text{H}}\, \left(\frac{1}{{n_{1}}^{2}} - \frac{1}{{n_{2}}^{2}}\right)\right) \\ &\approx (2.9979 \times 10^{8}\; {\rm m \cdot s^{-1}}) \\ &\quad \times (1.0968 \times 10^{7}\; {\rm m^{-1}}) \times \left(\frac{1}{2^{2}} - \frac{1}{8^{2}}\right)\\ &\approx 7.7065 \times 10^{14}\; {\rm s^{-1}} \end{aligned}\).
Apply the Einstein-Planck equation to find the energy of this photon:
\(\begin{aligned}E &= h\, f \\ &\approx (6.6261 \times 10^{-34}\; {\rm J \cdot s}) \times (7.7065 \times 10^{14}\; {\rm s^{-1}) \\ &\approx 5.11 \times 10^{-19}\; {\rm J}\end{aligned}\).
(Rounded to three significant figures.)
Where does the first stage of cellular respiration occur?
O w
O x
OY
O Z
8. An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120
specific heat capacity of the liquid in this temperature range. Assume that negligible h
O
O
O
2.51 x 10³ J/(kg. C°)
1.67 x 106 J/(kg C°)
2.02 x 104 J/(kg. C°)
The specific heat capacity of the liquid is 2.51 x 10³ J/kg⁰C.
Specific heat capacity of the liquidThe specific heat capacity of the liquid is calculated as follows;
Q = mcΔФ
where;
Q is quantity of heat c is specific heat capacitym is mass of the liquidΔФ is change in temperature = 22.54 - 18.55 = 3.99 ⁰Cc = Q/mΔФ
c = (65 x 120)/(0.78 x 3.99)
c = 2.51 x 10³ J/kg⁰C
The complete question is below:
An electrical resistor immersed in a liquid produces 65.0 W of electrical energy for 120 s. The mass of the liquid is 0.780 kg and its temperature increases from 18.55°C to 22.54°C. a) Find the average specific heat capacity of the liquid in this temperature range.
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If you were on a rocket traveling at 99.9% of the speed of light: if someone felt like 1 year had passed on earth how much time would have passed for you in the rocket?
An electron moving at 4.10 ✕ 103 m/s in a 1.45 T magnetic field experiences a magnetic force of 1.40 ✕ 10−16 N. What angle does the velocity of the electron make with the magnetic field? There are two answers between 0° and 180°. ° (smaller value) ° (larger value)
ANSWER
\(8.46\degree;\text{ }171.54\operatorname{\degree}\)EXPLANATION
Parameters given:
Speed of electron, v = 4.10 * 10^3 m/s
Magnetic field, B = 1.45 T
Magnetic force, F = 1.40 * 10^(-16) N
To find the angle that the velocity of the electron makes with the magnetic field, apply the formula for magnetic force:
\(F=qvB\sin\theta\)where θ = angle
q = electric charge = 1.6 * 10^(-19) C
Make θ the subject of the formula:
\(\begin{gathered} \sin\theta=\frac{F}{qvB} \\ \\ \theta=\sin^{-1}(\frac{F}{qvB}) \end{gathered}\)Therefore, the angle that the velocity makes is:
\(\begin{gathered} \theta=\sin^{-1}(\frac{1.4*10^{-16}}{1.6*10^{-19}*4.1*10^3*1.45}) \\ \\ \theta=\sin^{-1}(0.1472) \\ \\ \theta=8.46\degree \end{gathered}\)To find the second angle, subtract the angle from 180 degrees:
\(\begin{gathered} 180-8.46 \\ \\ 171.54\degree \end{gathered}\)The angles are:
\(8.46\operatorname{\degree};\text{ }171.54\operatorname{\degree}\)how do different types of motion affect forces?
Answer:
A force is a push or pull on an object. Forces usually cannot be seen but their effects can.
Nothing moves, changes speed, stops or changes direction without force. Heavier objects need more
force to get them to move or change direction.
Explanation:
A balloonist drops his camera from a height of 100 m while his balloon is ascending at 5 m/s. How
long did it take to reach the ground?
1. If the dielectric becomes damaged it can 'break down' like the air does when lightning strikes. What would happen to the charge on the plates?
2. Here are some statements about how an image is produced and processed in a digital camera.
A) Starting in one corner the charge on each square is moved off the CCD.
B) Light enters the camera.
C) That signal can be stored or sent to a computer or other device.
D) The charges on each square are converted into a digital signal.
E) When the light hits a square on the CCD charge is produced.
a. They are in the wrong order. Write the letters for the statements in the correct order.
b. Explain why there is a delay between taking one photograph with a digital camera and taking the next photograph.
Answer:
Explanation:
A) E) When the light hits a square on the CCD charge is produced
B) A) Starting in one corner the charge on each square is moved off the CCD
C) D) The charges on each square are converted into a digital signal
D) B) Light enters the camera
E) C) That signal can be stored or sent to a computer or other device
b. The delay between taking one photograph with a digital camera and taking the next photograph is due to the time it takes to capture the image and process it into a digital signal. This process includes the capturing of the light entering the camera, the conversion of the charges on each square of the CCD into a digital signal, and the storage or sending of the signal to a computer or other device.
which action will give you more momentum toward the north: throwing one shoe southward at 10 m/s or two shoes southward at 5 m/s?
Throwing one shoe southward at 10 m/s will give you more momentum toward the north.
Momentum is defined as the product of an object's mass and its velocity. The momentum of an object can be determined using the equation:
Momentum = mass × velocity
In this case, both scenarios involve throwing shoes southward, which means the velocity is directed to the south. The key difference is the magnitude of the velocity.
When throwing one shoe southward at 10 m/s, the velocity is higher compared to throwing two shoes southward at 5 m/s. Since momentum depends on velocity, the higher velocity of the single shoe results in a greater momentum.
The mass of the shoes does not play a role in determining which action gives more momentum toward the north since the mass is the same in both scenarios. Therefore, throwing one shoe southward at 10 m/s will give you more momentum toward the north compared to throwing two shoes southward at 5 m/s.
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