An automobile and a truck start from rest at the same time, with the truck initially at some distance ahead of the car. The truck has a constant acceleration of 2.90 m/s, and the automobile an acceleration of 3.00 m/s. The automobile catches up with the truck after the truck moved 240.0 m. a) How much time does it take for the automobile to catch the truck? b) How far ahead was the truck initially?

Answer:

How do static and sliding friction affect the speed of a paperback book, a flat eraser and a key?

Prediction: Which item (paperback book, flat eraser, or key) will have the most static friction and which item will have the most sliding friction?  Make sure your prediction gives an explanation of your reasoning.

Explanation:

Answer:

soccer, football, volleyball, baseball, locress

Explanation:

hope it helps

The equivalent distribution for the magnitude of velocity, g(v), can be defined using the Maxwellian distribution for velocity components.

The Maxwellian distribution describes the statistical distribution of velocity components in a gas. To obtain the equivalent distribution for the magnitude of velocity, g(v), we use the properties of vector addition and vector magnitude.

By considering the velocity components as independent random variables with a Maxwellian distribution, we can calculate the resulting magnitude distribution. This involves applying mathematical operations to determine the probability density function of the magnitude of velocity.

The derived g(v) distribution provides insights into the statistical behavior and characteristics of the velocity magnitudes within the gas system.

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Answer:

High tides and low tides are caused by the Moon.

Explanation:

The Moon's gravitational pull generates something called the tidal force.

Answer:

The moon is one

Explanation:

The moon has a strong gravitational force, and because of that it has certain control on Earth's oceans which can make tides

Answer:

Unbalanced forces can lead to a change in direction, a change in speed, or both a change in direction and in speed.

Explanation:

Answer:

Yep.

Explanation:

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. Gravity will pull the object down. So yes, gravity affects kinetic energy.

Answer:

Kinetic energy is energy an object has because of its motion. A ball held in the air, for example, has gravitational potential energy. If released, as the ball moves faster and faster toward the ground, the force of gravity will transfer the potential energy to kinetic energy.

Explanation:

The box will be in rest due to net force applied on it is zero.

The definition of force in physics is: The push or pull on a massed object changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude.

Given that Bert and Ernie are pushing on opposite sides of the box with force of same magnitude, let it be F.

So, net force acting om the force = F-F = 0.

As that net force acting on the box is zero, the box will be in rest.

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A 60-MSun star will have a shorter lifetime than the Sun. The exact calculation of the lifetime of a 60-MSun star requires complex models and considerations.

The lifetime of a star is primarily determined by its mass. Higher-mass stars have more fuel (hydrogen) available for nuclear fusion, but they also burn through their fuel at a much faster rate. This results in a shorter main-sequence lifetime compared to lower-mass stars like the Sun.

While the precise calculation of the lifetime of a 60-MSun star would require detailed stellar evolution models, it is generally understood that such a massive star would burn through its hydrogen fuel relatively quickly.

Massive stars have intense energy production and high luminosity, leading to a more rapid depletion of their nuclear fuel. Therefore, the lifetime of a 60-MSun star is expected to be significantly shorter than the main-sequence lifetime of the Sun, which is approximately 10¹⁰ years (ten billion years).

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An object's mass remains unchanged everywhere while the weight of an object depends on gravity, it is a measurement of how much gravity has an impact on an object. Therefore, an object’s mass, rather than its weight is used to indicate the amount of matter it contains.

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Seasons are a part of a region's climate, but are not the only part.  hence the Option that best explains the relations between Climate and Seasons is

A. light and heat from the sun.

The Climatic condition of the Earth largely depends on the Solar System. Solar radiation warms the atmosphere and is fundamental to atmospheric composition, while the distribution of solar heating across the planet produces global wind patterns and contributes to the formation of clouds, storms, and rainfall.

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Answer:light and heat from the sun

Explanation:

The circled vector on the diagram below represents the tension on the rope.

The option C is correct

Tension is described as  the force transmitted through a string, rope, cable or wire when it is pulled tight by forces acting from opposite ends.

T = mg + ma

We know that the force of tension is calculated using the formula T = mg + ma.

In other terms, the pulling force that runs the length of a flexible connector, such a rope or cable, is known as tension. It is always pointed away from the force-applying object and along the length of the connector.

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The height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

In an ellipse, the sum of the distances from any point on the ellipse to its two foci is constant. In this case, the two foci are located 25 feet from the center of the hall.

Given that the hall is 100 feet in length, the distance from one end to the center is 50 feet. We can consider this as the semi-major axis (a) of the ellipse.

The sum of the distances from any point on the ellipse to its two foci is equal to 2a. Thus, the sum of the distances from the ceiling at the center of the hall to the two foci is also 2a.

Since the foci are located 25 feet from the center, the sum of the distances is 2a = 50 feet.

To find the height of the ceiling at the center, we need to determine the semi-minor axis (b) of the ellipse. The semi-minor axis can be calculated using the formula:

b = √(a² - c²)

where c represents the distance from the center to each focus. In this case, c = 25 feet.

Substituting the values into the formula:

b = √(50² - 25²)

b = √(2500 - 625)

b = √(1875)

b = 43.3 feet

Therefore, the height of the ceiling at the center of the whispering gallery is approximately 43.3 feet.

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Answer:

17.6 m/s²

Explanation:

Given:

\(v_{f}\) = 90 m/s (final velocity)

\(v_{i}\) = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

\(a_{avg}\) = Δv / Δt

We can find Δv by doing

Δv = \(v_{f}\) - \(v_{i}\)

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

\(a_{avg}\) = Δv / Δt

\(a_{avg}\) = \(\frac{88m/s}{5/s}\)

acceleration = 17.6 \(m/s^{2}\)

The element of their chemical structure that differentiates one amino acid from another is the side chain, also known as the R-group.

the R-group is what makes each amino acid unique. The R-group can vary in size, shape, and chemical properties, which in turn determines the specific characteristics and functions of each amino acid.

The R-group can consist of different elements such as hydrogen, carbon, oxygen, nitrogen, and sulfur, as well as various functional groups. This variation in the R-group contributes to the diversity and complexity of proteins.

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The truck applies the same force to the car that the car applies to the truck. The truck applies the same force to the car that the car applies to the truck. According to Newton's third law, action and reaction have the same magnitude and move in the opposite direction.

Force is an external agent that can change the state of rest or motion of a body. It has a magnitude as well as a direction.

The direction of the force is the point where force is applied, and the application of force is the point where force is applied.

The concept of force is commonly explained in terms of Isaac Newton's three laws of motion, which are laid out in his Principia Mathematica.

The truck exerts the very same force on the car as the car exerts on the truck. The truck exerts this very same force on the car as the car exerts on the truck.

Action and reaction have the same amplitude and move in the opposite direction, according to Newton's third law.

Thus, this can be the comparison in the given scenario.

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Your question seems incomplete, the complete question is:

Consider the collision between a car and a

light truck whose weights are equal (M = m). If they are moving at the same speed when they collide, compare the size (or magnitude) of the forces between the car and the truck. Friction is so small that it can be ignored.

Compare the forces if the light truck is standing

still when the car hits it.

Answer:

I think the answer is thermal radiation

Together, the two cars are traveling at a speed of 29.11 m/s.

As a result,

The car's mass is 1 m = 1250 kg.

Initially, the car's speed was 1, u = 32 m/s.

Car 2 mass, m' = 875 kg

The starting speed of vehicle 2 is 25 m/s.

both vehicles stick together. An inelastic collision is a situation here. The pace is maintained. Let V be the combined speed of the two vehicles.

Using conV = 29.11 m/s, it is determined.

Thus, the combined speed of the two cars is 29.11 m/s. Therefore, this is the necessary solution. momentum preservation as:

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Answer and Explanation:Option A->The innermost layer of the earth is known as the core. It is divided into inner core and outer core. It comprises of a high concentration of nickel and iron.

Answer:

The kinetic energy of an object is directly proportional to the square of its speed. That means that for a twofold increase in speed, the kinetic energy will increase by a factor of four.

Found it on the internet

Explanation:

Hope this helps dude

Answer:

\(60^{\circ}\) (assuming that air resistance is negligible.)

Explanation:

Let \(g\) denote the gravitational field strength. If air resistance on the projectile is negligible:

Let \(\theta\) denote the angle at which the projectile is launched. Let \(v\) denote the initial velocity of the projectile:

Also because air resistance is negligible, vertical velocity of the projectile will be \(v_{y} = (-u_{y}) = (-v\, \sin(\theta))\) right before the projectile lands. In other words, while the projectile was in the air, the change in vertical velocity would be \((-v\, \sin(\theta)) - (v\, \sin(\theta)) = (-2\, v\, \sin(\theta))\).

Divide the change in velocity by acceleration to find the duration of the flight:

\(\begin{aligned}t &= \frac{v_{y} - u_{y}}{a_{y}} \\ &= \frac{(-v\, \sin(\theta)) - (v\, \sin(\theta))}{(-g)} \\ &= \frac{(-2\, v\, \sin(\theta))}{(-g)} \\ &= \frac{2\, v\, \sin(\theta)}{g}\end{aligned}\).

Range measures the horizontal distance that this projectile has travelled. At a constant horizontal velocity of \(u_{x} = v\, \cos(\theta)\), this projectile would travel a distance of:

\(\begin{aligned}(\text{range}) &= u_{x}\, t \\ &= (v\, \cos(\theta))\left(\frac{2\, v\, \sin(\theta)}{g}\right) \\ &= \frac{2\, v^{2}\, \sin(\theta)\, \cos(\theta)}{g}\end{aligned}\).

Apply the double angle identity \(2\, \sin(\theta) \, \cos(\theta) = \sin(2\, \theta)\) to further simplify this expression:

\(\begin{aligned}(\text{range}) &= \cdots \\ &= \frac{2\, v^{2}\, \sin(\theta)\, \cos(\theta)}{g} \\ &= \frac{v^{2}\, (2\, \sin(\theta)\, \cos(\theta))}{g} \\ &= \frac{v^{2}\, \sin(2\, \theta)}{g}\end{aligned}\).

Note that in this question, \(v^{2}\) and \(g\) are both constant. Hence, for another angle of elevation \(\hat{\theta}\), the range of the projectile will be the same as long as \(\sin(2\, \hat{\theta}) = \sin(2\, \theta)\).

\(\sin(2\, \hat{\theta}) = \sin(2\, (30^{\circ}))\).

Since \(0^{\circ} \le \hat{\theta} \le 90^{\circ}\), \(0^{\circ} \le 2\, \hat{\theta} \le 180^{\circ}\):

\(\sin(2\, \hat{\theta}) = \sin(180^{\circ} - 2\, \hat{\theta}) = \sin(2\, (90^{\circ} - \hat{\theta}))\).

Therefore, \(\hat{\theta} = 90^{\circ} - \theta = 90^{\circ} - 30^{\circ} = 60^{\circ}\) will ensure that \(\sin(2\, \hat{\theta}) = \sin(2\, \theta)\). Launching the projectile at \(60^{\circ}\) will reach the same range.

\(\begin{aligned}(\text{new range}) &= \frac{v^{2}\, \sin(2\, (60^{\circ}))}{g} \\ &= \frac{v^{2}\, \sin(2\, (30^{\circ}))}{g} = (\text{original range})\end{aligned}\).

An object with greater charge will exert a greater force on an object than an object with smaller charge would. However, if you consider two charges that exert a force on each other, regardless of the magnitude of charge, both charges will exert an equal force on each other because of Newton's third law.

Answer:

Consider a satellite with mass Msat orbiting a central body with a mass of mass MCentral. The central body could be a planet, the sun or some other large mass capable of causing sufficient acceleration on a less massive nearby object. If the satellite moves in circular motion, then the net centripetal force acting upon this orbiting satellite is given by the relationship

Fnet = ( Msat • v2 ) / R

Explanation:

The acceleration of the satellite released from a spacecraft orbiting a planet at an altitude of 120 km and the planet has a mass of 5.2 x 10^23 kg and a radius of 2800 km is 4.426 *  \(10^6\)  \(m/s^2\).

The term "acceleration" refers to the rate and direction at which velocity varies over time. Acceleration is the change in direction or speed of an object or points moving ahead. The frequent change in direction causes motion on a circle to rise even when the speed remains constant.

For all other motions, these effects increase the acceleration. A vector quantity, acceleration, is something that has both a magnitude and a direction. Velocity is a vector quantity as well.

Given:

The altitude of the spacecraft, h = 120 km,

The mass of the planet, m = \(5.2 * 10^{23}\) kg,

The radius of the planet, r = 2800 km.

Calculate the acceleration by the formula given below,

A = \(G* m /r^2\)

Here, A is the acceleration, G is the gravitational constant,

Substitute the values,

A = 6.674 * \(10^{-11}\) *5.2 * \(10^{23}\) / \(2800^2\)

A = 4.426 *  \(10^6\)  \(m/s^2\)

Therefore, the acceleration of the satellite is 4.426 *  \(10^6\)  \(m/s^2\)

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Answer:

1 N

Explanation:

First the equation is momentum = Force / distance

20 cm = 0.2 m

5 N/m = F / 0.2 m

F = 1 N

Answer:

check explanation

Explanation:

Whenever we talk about velocity ,it means that we r telling them the speed of the object+the direction of the motion of object but here direction isn't mentioned. That's the fault in the statement

The radius of the cylindrical barrel is 0.78 m.

The circular area of the cylindrical barrel is calculated as follows;

P = F/A

A = F/P

where;

A = mg/P

A = (50 x 9.8) / (260)

A = 1.885 m²

A = πr²

r² = A/π

r = √(A/π)

r = √(1.885/π)

r = 0.78 m

Thus, the radius of the cylindrical barrel is 0.78 m.

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Answer:

A. loses an electron, it becomes positively charged.

Answer:

loses electrons

Explanation:

The equations for final velocities is:

v1,f = [(m1-m2)/(m1+m2)]*v1,i v2,f = [(2*m1)/(m1+m2)]*v1,i

An elastic collision is one where both momentum and kinetic energy are conserved. Let m1 and m2 be the masses of two objects with initial velocities v1,i and v2,i=0 (second object is stationary). After the collision, their final velocities are v1,f and v2,f.

Applying conservation of momentum and kinetic energy, we have:

1) m1*v1,i + m2*v2,i = m1*v1,f + m2*v2,f

2) 0.5*m1*v1,i² + 0.5*m2*v2,i² = 0.5*m1*v1,f² + 0.5*m2*v2,f²

Solving these equations for final velocities, we get:

v1,f = [(m1-m2)/(m1+m2)]*v1,i v2,f = [(2*m1)/(m1+m2)]*v1,i

These are the equations for the final velocities of two objects after an elastic collision with the given initial conditions.

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Answer:

4E

Explanation:

From the question given above, the following data were obtained:

Initial elongation (e₁) = 4 cm = 4/100 = 0.04 m

Initial energy (E₁) = E

Final elongation (e₂) = 0.04 + 0.04 = 0.08 m

Final energy (E₂) =?

The energy stored in a s spring is given by:

E = ½Ke²

Where

E => is the energy

K => is the spring constant

e => is the elongation

From:

E = ½Ke²

Energy is directly proportional to the elongation. Thus,

E₁/e₁² = E₂/e₂²

With the above formula, we can obtain the final energy as follow:

Initial elongation (e₁) = 0.04 m

Initial energy (E₁) = E

Final elongation (e₂) = 0.08 m

Final energy (E₂) =?

E₁/e₁² = E₂/e₂²

E / 0.04² = E₂ / 0.08²

E / 0.0016 = E₂ / 0.0064

Cross multiply

0.0016 × E₂ = 0.0064E

Divide both side by 0.0016

E₂ = 0.0064E / 0.0016

E₂ = 4E

Therefore, the final energy is 4 times the initial energy i.e 4E