A) What is the ammeter Reading I? Express your answer in terms of E, R, and rint.

B) What is the voltmeter reading V? Express your answer in terms of E, R, and rint.

C) What is the power PR dissipated in the resistor? Express your answer in terms of I and V.

D) Again, what is the power PR dissipated in the resistor? This time, express your answer in terms of one or more of the following variables: I, rint, and R.

E) For the third time, what is the power PR dissipated in the resistor? Express your answer in terms of one or more of the following variables: E, rint, and R.

F) What is the total power Ptotal dissipated in the resistive elements of the circuit? Express your answer in terms of one or more of the following variables: E, rint, and R.

G) What is the total power Ptotal dissipated in the resistive elements of the circuit, in terms of the EMF E of the battery and the current in the circuit? Express your answer in terms of E and the ammeter current I.

Answers

Answer 1

(A) The ammeter reading is \(I = \dfrac{E}{R_{eq}}\)

(B) The voltmeter reading V, \({ E}=I \times(R+r_{int})\)

(C) The power dissipated = VI

(D) The power PR dissipated in the resistor, the power dissipated = I²R

(E) The power PR dissipated in the resistor in terms of the R and E,\(P\ = \dfrac{RE^2}{(R+r_{int})^2}\)

(F) The total power dissipated,

\(P_{T}= \dfrac{E_2}{(R+r_{int})}\)

(A) The current will be calculated by the ratio of the voltage and the equivalent resistance of the circuit. The ammeter reading is calculated by the formula written below for the calculation of the current.

\(I = \dfrac{E}{R_{eq}}\)

Here Req. = R+rint.

When the internal resistance is also taken into consideration the ammeter written is calculated,

\(I =\dfrac{ E}{(R+r_{int})}\)

The voltmeter reading V,

(B) Voltmeter reading is the potential difference across battery or resistance. The voltage is calculated by the product of the resistance and the current.

\({ E}=I \times(R+r_{int})\)

(C) The power is calculated by the product of the voltage and the current flowing in the circuit.

The power dissipated is calculated as,

The power dissipated = VI

(D) The power is calculated by the product of the voltage and the current flowing in the circuit. The value of the voltage V = IR can be substituted in the formula. The power PR dissipated in the resistor,

power dissipated = I²R

(E) The power is calculated by the product of the voltage and the current flowing in the circuit. The power PR dissipated in the resistor in terms of the R and E,

\(P\ = \dfrac{RE^2}{(R+r_{int})^2}\)

(F) The total power \(P_{total}\) dissipated,

\(P_R = \dfrac{RE^2}{(R+r_{int})^2}\)

The total power dissipated,

\(P_{T}= \dfrac{E_2}{(R+r_{int})}\)

(G) The power is the product of the voltage and the current. The total power P total dissipated in the resistive elements of the circuit can be written as,

Power dissipated = EI

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The missing circuit diagram is attached with the answer.

A) What Is The Ammeter Reading I? Express Your Answer In Terms Of E, R, And Rint.B) What Is The Voltmeter

Related Questions

An apple is falling from a tree. Disregarding air resistance, which diagram shows the free-body diagram of the force or forces acting on the apple?
A free body diagram with two vectors of same length but pointing in opposite directions. The force upward is labeled F Subscript N Baseline. The force downward is labeled F Subscript g Baseline.

A free body diagram with one force vector pointing downward labeled F Subscript g Baseline.

A free body diagram with one force vector pointing right labeled F Subscript g Baseline.

A free body diagram with two force vectors, the first pointing downward labeled F Subscript g Baseline, the second pointing right labeled F Subscript p Baseline.

Answers

If an apple is falling from a tree, disregarding air resistance, the diagram that shows the free-body diagram of the force or forces acting on the apple would be: A free-body diagram with one force vector pointing downward labeled F Subscript g Baseline.

What diagram is the best?

The best diagram that represents the scenario painted above would be the one pointing downward and the reason for this is that there are no extra forces acting on the body except the force of gravity that points downward.

So, the best option that describes the narrative above is the selected option.

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Answer:

It's B (Fg pointing down only)

Explanation:

just trust bro

The Si unit of potential difference is a) volt b) JA⁻¹s⁻¹ c)JC⁻¹ d) All the above

Answers

Answer:

a) Volt

Explanation:

The standard metric unit on electric potential difference is the volt.

answer

all of the above

explanation

as we know that the si unit of potential difference is volt

which is equal to j/c and j/c is equal to j/a.s so the correct answer is all of the above

Which is an example of physical weathering?

a- limestone in rock dissolving when acid rain flows across it

b- bits of rock rusting when exposed to oxygen and water

c- wind blowing off bits of a rock over time

d- oxidation of certain metals in rock

Answers

C
I’m pretty sure the answer is C because physical weathering means is when rock is broken down through mechanical processes such as wind, and C is the only one talking about breaking down (not dissolving) the rock.
I could be wrong.?

An example of physical weathering is the wind that is blowing off bits of a rock over time. This results into breaking down of large rocks. Thus, the correct option is C.

What is Physical weathering?

Physical weathering is also called as mechanical weathering. It is a process which causes the disintegration of large rocks, minerals, and large soil particles without any chemical change. The primary process in physical weathering is the abrasion, it is the process by which clasts and other particles are reduced in size and mix up with soil.

Physical weathering occurs when large rocks are broken down through mechanical processes such as wind blowing, water, gravitational force, freeze-thaw cycles, or the growth of roots into the rocks.

Therefore, the correct option is C.

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A wave oscillates with a period of 4.25 X 10-10 s. How many waves will strike a signal detector in 3 seconds?

Answers

Answer:

\(n=7.05\times 10^9\) waves

Explanation:

Given that,

A wave oscillates with a period of \(4.25\times 10^{-10}\ s\)

We need to find the number of waves that will strike a signal detector in 3 seconds.

We know that,

Frequency = (no. of oscillations)/time

Time period = time/(no. of oscillations)

Let there are n waves that will strike

So,

\(n=\dfrac{3}{4.25\times 10^{-10}}\\\\=7.05\times 10^9\)

Hence, \(7.05\times 10^9\) waves will strike in 3 seconds.

A 0.149-kg baseball, initially moving at 15 m/s is brought to rest in 0.050 seconds by a baseball glove on a catcher’s hand. The magnitude of the average force exerted on the ball by the glove is

Answers

The magnitude of the average force exerted on the ball by the glove is

What is the magnitude of the average force exerted on the ball by the glove?

The magnitude of the average force exerted on the ball by the glove is calculated as follows:

Force = Mass × acceleration

Data given:

Mass, m = 0.149 kg

Velocity, v = 15 m/s

Time, t = 0.050 seconds

However,

Acceleration = Δv / t

where;

Δv is the change in velocityt is the time taken

Hence;

Force = Mass ×  Δv / t

Force = 0.149 × (15 - 0) / 0.050

Force = 44.7 N

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define one kilogram mass​

Answers

Answer:

a unit of mass or weight equaling one thousand grams


Describe how the location of the oxygen molecules will change after the divider swings open.

Answers

Find the freezing point of the material and contrast it to that of other metals. Measure the metal's length and contrast it with the lengths of other metals. Also, contrast the metal's shape with those of other metals.

Which of the following best describes how heat energy flows in the concentrated solar layout?

The air within the solar cooker receives energy from the water through the edges of the cook pot. The air outside solar cooker receives energy that is transferred from the gas within the solar cooker through sidewalls of the solar cooker.

What kind of energy is transferred in a solar cooker?

Radiation is utilized to bake the s'mores in the hot cooker that is created in this exercise. When heat is transported without the presence of Sun and s'mores were in close proximity to one another  Electromagnetic waves that are passing through the air convey the heat.

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Because they have an extended structure, elements that are ___________ tend to be in the ___________ state at room temperature.

Answers

Answer:

metal

solid

Explanation:

Mr. Chowder ties an eraser to a string and swings it in a circle with a radius of 0.974 meters. The eraser makes 127 revolutions in a minute. Determine its acceleration (in m/s/s).

Answers

The acceleration of the eraser is 169.19 m/s².

What is centripetal acceleration?

A body travelling in a circle has centripetal acceleration. Due to the fact that velocity is a vector quantity (i.e., it has both a magnitude and a direction), when a body travels in a circle, its direction is continually changing, which causes a change in velocity, which results in an acceleration.

Given that angular velocity of the eraser: ω = 127 rpm

= 126×2π/60 radian/second

= 13.2 radian/second.

radius of the circle: r = 0.974 meter.

Hence, its centripetal acceleration is = ω²r

= 13.2×13.2×0.974 m/s²

=169.19 m/s².

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What is the main difference between a gas and a
plasma?

Answers

The main difference is that in a gas, the atoms remain intact and generally linked into molecules, but in plasma, at least part of the electrons have completely separated from their atoms. In other words, plasma particles are charged, whereas gas particles are largely uncharged.

The drawing shows a horizontal ray of white light incident perpendicularly on the vertical face of a prism made of crown glass. The ray enters the prism, and part of the light undergoes refraction at the slanted face and emerges into the surrounding material. The rest of the light is totally internally reflected and exits through the horizontal base of the prism. The colors of light that emerge from the slanted face of the prism may be chosen by altering the index of refraction of the material surrounding the prism. Find the required index of refraction of the surrounding material so that (a) only red light and (b) all colors except violet emerge from the slanted face of the prism. Take n

Answers

Answer:

The answer is "1.0748 and 1.0875".

Explanation:

Please find the complete question in the attachment file.

The incidence angle is \(i=45^{\circ}\) for all colors When the angle is r, then use \(\frac{\sin{i}}{\sin{r}}=\frac{n_{o}}{n}\) . Snell's rule Where \(n_{o}\) is an outside material reflectance (same hue index) or n seems to be the crown glass index of the refraction, That index of inclination is \(90^{\circ}\) as the light in color shifted behaver from complete inner diffraction to diffraction.

Whenever the external channel has a thermal conductivity for the red light, that's also

\(n_{o}=\frac{n_{r}\sin{45^{\circ}}}{\sin{90^{\circ}}}=\frac{1.520\times\sin{45^{\circ}}}{\sin{90^{\circ}}}=1.0748\)

When outside the material has a refractive index, this happens with violet light.

\(n_{o}=\frac{n_{r}\sin{45^{\circ}}}{\sin{90^{\circ}}}=\frac{1.538\times\sin{45^{\circ}}}{\sin{90^{\circ}}}=1.0875\)

In point a, The only red light flows out from the leaned face and the residual colors are mirrored mostly on prism for the primary benefits \(n_{o}=1.0748\) (and slightly larger than that).

In point b, The only violet light is shown in the prism with the majority of the colors coming out from the sloping face for a scale similar to \(n_{o}= 1.0875\) (and slightly smaller than this).

A gazelle is running in a straight line with a constant velocity of 1340 m/min. A cheetah can accelerate from 0 m/min to 1820 m/min in 3 seconds. What is the average acceleration of the gazelle? What is the average acceleration of the cheetah?

Answers

The gazelle has zero average acceleration because it's moving at a constant speed. Constant speed means no change in speed means zero acceleration.

The cheetah, on the other hand, changes its speed from 0 m/min to 1820 m/min in a matter of 3 seconds, so its average acceleration is

a[ave] = (1820 m/min - 0 m/min) / (3 s)

… = (1820 m/min) / (3/60 min)

… = 36,400 m/min²

… = (36,400 m) / (60 s)²

… = 91/9 m/s² ≈ 10.1 m/s²

Name:
9. A ball is thrown vertically in the air from rest and soars for 4.2 seconds.
If the acceleration due to gravity is 9.8 m/s², what is the final velocity
of the ball when it is caught?

Answers

The final velocity of the ball when it is caught is 20.58 m/s

What is velocity?

Velocity is the rate of change of displacement.

To calculate the final velocity of the ball when it is caught, we use the formula below.

Formula:

v = u+gt............ Equation 1

Where:

v = Final velocityu = Initial velocityg = Acceleration due to gravityt = Time

From the question,

Given:

u = 0 m/sg = 9.8 m/s²t = 4.2/2 = 2.1s

SUbstitute these values into equation 1

v = 0+9.8×2.1v = 20.58 m/s

Hence, the  final velocity of the ball when it is caught is 20.58 m/s

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Determine the pressure P of a 450K Oxygen gas in a gas chamber when its initial pressure is 175Pa has a temp 300K

Answers

Answer:

262.5Pa

Explanation:

Given parameters:

P1  = 175Pa

T1  = 300K

T2  = 450K

Unknown:

P2  = ?

Solution:

To solve this problem, we are going to use an adaptation of the combined gas law.

           \(\frac{P1}{T1}\)    = \(\frac{P2}{T2}\)  

  Insert the parameters and solve;

           \(\frac{175}{300}\)    = \(\frac{P2}{450}\)  

          P2 = 262.5Pa

To heat the house, the boiler transfers 15 MJ of energy in 10 minutes.
Calculate the power of the boiler.

Answers

The power supplied by the boiler to heat the house is 25000 Watts(W) or 25 Kilowatts (KW).

Power is the rate of doing work. It is the energy supplied to the body per unit of time. It is of two types, instantaneous power which is calculated for a particular instant, and average power which is calculated over an interval of time Its S.I. unit is watts (W).

One watt is equal to one joule of energy transfered per second.

Given in the question

Energy transferred = 15 MJ

Time interval = 10 minutes

Before calculating the power, We need to convert the given values into their S.I. unit

1MJ = 1000000 J

So 15 MJ = 15 × 1000000 J

15 MJ = 15000000 J

Similarly,  1 minute = 60 seconds

So 10 minutes = 10 × 60 seconds

10 minutes = 600 seconds

Now,

Power =  Energy transferred/ Time Interval

Power = 15000000 / 600

Power = 150000/6

Power = 25000 Watts or W

Power = 25 kilowatts or KW

Therefore, the power supplied by the boiler to heat the house is 25000 Watts(W) or 25 Kilowatts (KW).

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The potential energy for a particle that can move along the x-axis is U=Ax2+Bsin(πx/L), where A, B, and L are constants.
A) What is the force on the particle at x=0?
B) What is the force on the particle at x=L/2?
C) What is the force on the particle at x=L?

Answers

A) The force on a particle can be found by taking the negative of the derivative of the potential energy function with respect to x. For U = Ax^2 + Bsin(πx/L), let's find the derivative:

dU/dx = d(Ax^2)/dx + d(Bsin(πx/L))/dx = 2Ax + B(π/L)cos(πx/L)
Now let's find the force at x=0:
F(x=0) = -dU/dx(0) = -[2A(0) + B(π/L)cos(π(0)/L)] = -[0 + B(π/L)] = -B(π/L)
B) The force on the particle at x=L/2:
F(x=L/2) = -dU/dx(L/2) = -[2A(L/2) + B(π/L)cos(π(L/2)/L)] = -[AL + B(π/L)cos(π/2)] = -[AL + 0] = -AL
C) The force on the particle at x=L:
F(x=L) = -dU/dx(L) = -[2A(L) + B(π/L)cos(π(L)/L)] = -[2AL + B(π/L)cos(π)] = -[2AL - B(π/L)]
To summarize:
A) The force at x=0 is -B(π/L).
B) The force at x=L/2 is -AL.
C) The force at x=L is -2AL + B(π/L).

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If an object's surface area is smaller does it create more or less pressure?

Answers

Answer:

When the surface area is less the pressure exerted by the object is more. However, when the surface area is large, the points of contact between the object and the pressure. Thus, less pressure is exerted by the body on the surface.

Explanation:

hope it helps

If the surface area of an object is smaller, it will create more pressure

An object's surface area is inversely proportional to its pressure.

This can be demonstrated from the formula below

Pressure:

The can be defined as the perpendicular force acting per unit area. the S.I  unit of pressure is N/m².

Formula:P = F/A.................. Equation 1

Where: P = Pressure of the objectF = Force acting on the objectA = Surface area of the object.

In View of the above equation, It can be seen that as the surface area of an object reduces the pressure created by the object will increase.

Hence, If the surface area of an object is smaller, it will create more pressure

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2. A roller coaster is at the top of a 72 m hill and weighs 150 kg. The coaster (at this moment) has
energy
anarov

Answers

Answer:

it is going down down down down the hill it goes so the roller coaster will then be down to a 0 m

A 5kg traveling at 4 m/s slams into a 1kg object and sticks to it. What will the final velocity of the two objects be?

Answers

Answer:

Below

Explanation:

Using conservation of momentum

mv = mv

5(4)  + 1(0)   = (4+1) v    

                ( this assumes the 1 kg mass was not moving before being struck)

20  = 5 v

v = 4 m/s          

0.53-kg billiard ball initially at rest is given a speed of 12 m>s during a time interval of 4.0 ms. what average force acted on the ball during this time?

Answers

The average force acting on the billiard ball during the 4.0 ms time interval is 1590 Newtons.

To calculate the average force acting on the billiard ball during the given time interval, we can use Newton's second law of motion:

F = m * Δv / Δt

Where:

F is the average force,

m is the mass of the ball (0.53 kg),

Δv is the change in velocity (final velocity - initial velocity),

Δt is the time interval (4.0 ms).

Given that the initial velocity (vᵢ) is 0 m/s (since the ball is initially at rest) and the final velocity (v) is 12 m/s, we can calculate the change in velocity:

Δv = v - vᵢ = 12 m/s - 0 m/s = 12 m/s

Δt = 4.0 ms = 4.0 x 10⁻³ s

Now, we can substitute the values into the formula to calculate the average force:

F = (0.53 kg * 12 m/s) / (4.0 x 10⁻³ s)

F = (6.36 kg·m/s) / (4.0 x 10⁻³ s)

F ≈ 1590 N

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one type of supersonic wind tunnel is a blow-down tunnel, where air is stored in a high-pressure reservoir, and then, upon the opening of a valve, exhausted through the tunnel into a vacuum tank or simply into the open atmosphere at the downstream end of the tunnel. for this example, we consider just the high-pressure reservoir as a storage tank that is being charged with air by a high-pressure pump. as air is being pumped into the constant-volume reservoir, the air pressure inside the reservoir increases. the pump continues to charge the reservoir until the desired pressure is achieved. consider a reservoir with an internal volume of 30 m3. as air is pumped into the reservoir, the air pressure inside the reservoir continually increases with time. consider the instant during the charging process when the reservoir pressure is 10 atm. assume the air temperature inside the reservoir is held constant at 300 k by means of a heat exchanger. air is pumped into the reservoir at the rate of 1 kg/s. calculate the time rate of increase of pressure in the reservoir at this instant.

Answers

The time rate of increase of pressure in the reservoir at this instant is approximately 9.56 Pa/s.

To calculate the time rate of increase of pressure in the reservoir, we can use the Ideal Gas Law:
PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature. We can rearrange this equation to find n:
n = PV / RT

Since air is being pumped into the reservoir at a rate of 1 kg/s, we can convert this mass flow rate to a molar flow rate using the molar mass of air (M_air = 28.97 g/mol or 0.02897 kg/mol):

Molar flow rate = mass flow rate / molar mass

Molar flow rate = 1 kg/s / 0.02897 kg/mol

Molar flow rate ≈ 34.51 mol/s

Now, we can find the time rate of increase of moles in the reservoir:
dn/dt = 34.51 mol/s

Next, let's differentiate the Ideal Gas Law with respect to time:
d(PV)/dt = R * d(nT)/dt
Since V and T are constants, we get:
dP/dt = R * dn/dt / V

Substituting the values:
dP/dt = (8.314 J/mol*K) * (34.51 mol/s) / (30 m³)
dP/dt ≈ 9.56 Pa/s
At this instant, the time rate of increase of pressure in the reservoir is approximately 9.56 Pa/s.

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A rock is dropped from a height of 2.7m. How fast is it going when it hits the ground?
PLEASE HELP ME!!!

Answers

Use the formula Vf^2 = Vi^2 + 2a(d)


A father pushes his child in a cart. The cart starts to move.



Scientists can use many physical quantities to describe what is happening.

The car is placed on a ramp, which is 20 meters high. The mass of the car and the child is 100kg.



Calculate the potential energy the car will have before it is let go and the velocity the car will travel at down the ramp assuming no frictional forces.



Acceleration due to gravity (g) = 10 m/s2

Answers

The potential energy of the car when it let go is 20,000 J.

The speed of the car at the bottom of the ramp is 20 m/s.

The given parameters;

mass of the car, m = 100 kgheight of the car, h = 20 m

The potential energy of the car is calculated as follows;

P.E = mgh

P.E = 100 x 10 x 20

P.E = 20,000 J

The speed of the car at the bottom of the ramp is calculated as follows;

\(K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v = \sqrt{2gh} \\\\v = \sqrt{2 \times 10 \times 20} \\\\v = 20 \ m/s\)

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A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. What is the momentum of the rocket?

Answers

A fuel-filled rocket is at rest. It burns its fuel and expels hot gas. The gas has a momentum of 1,500 kg m/s backward. So, The momentum of the rocket is -1500 kg m/s.

According to the law of conservation of momentum, in a closed system, the total momentum before and after a process remains constant.

A fuel-filled rocket that is initially at rest expels hot gas as it burns its fuel. The gas has a momentum of 1500 kg m/s backward.

We are required to determine the momentum of the rocket.

Consider the fuel-filled rocket as a system.

We have: Momentum before the burn = 0 kg m/s (since the rocket was at rest initially)Momentum after the burn = momentum of the expelled gas

We can therefore say that the initial momentum of the system was zero (0), and after the burn, the total momentum of the system remains the same as the momentum of the expelled gas.

Therefore: Momentum of rocket = - momentum of expelled gas

The negative sign signifies that the rocket's momentum is in the opposite direction of the expelled gas.

Hence, the momentum of the rocket is -1500 kg m/s.

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Diego buys a shirt that has a regular price of $15. It is on sale for 10% off. How much money does Diego save?

Answers

Answer:

$1.5

Explanation:

Which of the following wiring methods is NOT permitted for service-entrance conductors rated 1000 - PVC- Type NM Cable- Type MC Cable- ENT

Answers

The following wiring method is NOT permitted for service-entrance conductors rated 1000 - ENT type.

What are service-entrance conductors?

Service-entrance conductors are conductors between the service point and the primary disconnect of a structure or power source conduit system. The service point refers to the point of the property where the utility's system ends and the customer's electrical system begins. Service-entrance conductors are commonly seen in residential homes or commercial buildings.

Service-entrance conductors that are rated 1000 are those that can handle a current capacity of 1000 amperes. These service-entrance conductors are important as they transmit electric power from the utility's point of connection to the primary electrical panel, where it is then distributed throughout the building or house. PVC, Type NM Cable, and Type MC Cable are permitted wiring methods for service-entrance conductors rated 1000.

ENT, on the other hand, is not allowed as a wiring method for service-entrance conductors rated 1000.ENT or Electrical Non-Metallic Tubing is a flexible plastic conduit made of polyvinyl chloride, which is used for indoor and outdoor applications.

However, it's not used as a service-entrance conductor for ratings above 600V or for service conductors to a building or structure. Therefore, the correct answer is ENT.

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PLS HELP MEH!!!!


Sound travels fastest in

a) air
b) water
c) glass
d) diamond

WILL MARK BRAINLIEST IF ANSWER

Answers

My answer has to be 20 characters but it’s a) air

Answer:

hope this helps

Explanation:

Of the three phases of matter (gas, liquid, and solid), sound waves travel the slowest through gases, faster through liquids, and fastest through solids

so your answer would be B.

You want to push a 71-kg box up a 16° ramp. The coefficient of kinetic friction between the ramp and the box is 0.23. With what magnitude force parallel to the ramp should you push on the box so that it moves up the ramp at a constant speed?

Answers

Answer:

345.60N

Explanation:

The magnitude of the force parallel to the ramp that will push the box up the ramp are the frictional force(Ff) and the moving force Fm

Total force = Ff + Fm

Ff = ηR

Ff = ηmgcosθ

Fm = Wsinθ

Fm = mgsinθ

Total force = ηmgcosθ + mgsinθ

Total force = mg(ηcosθ + sinθ)

Given

mass m = 71kg

acceleration due to gravity g = 9.8m/s²

angle of inclination θ = 16°

coefficient of friction η = 0.23

Substitute into the formula;

Total force = 71(9.8)(0.23cos16 + sin16)

Total force = 695.8(0.2211+0.2756)

Total force = 695.8(0.4967)

Total force = 345.60N

Hence the magnitude force parallel to the ramp that you should push on the box so that it moves up the ramp at a constant speed is 345.60N

What is the period of a wave definition?

Answers

A wave's period is the amount of time it takes for two crests to pass one wavelength apart at a certain location.

The formula for wave period is wavelength divided by velocity since the periods indicate that a wave's period is the inverse of its frequency. The frequency of a wave is measured in 1/s, often known as Hertz, whereas the period of a wave is measured in seconds (s) (Hz).

Each wave, period is typically expressed in seconds. Speed (V) divided by wavelength (V) yields the period (T) (S). Divide the length by the speed, for instance, 12 m divided by 6 m/s = 2 s to determine the period of a wave with a speed of 6 m/s and a wavelength of 12 m.

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how fast must the rotor of the generator rotate if it is to generate a maximum induced emf of 50 v ?

Answers

The rotor of the generator must rotate at a speed that will produce the maximum induced emf of 50 V.

However, to explain this in detail, the speed required depends on the design of the generator and the number of poles it has. The formula for the induced emf is given by E = 2πfNACos(θ), where E is the induced emf, f is the frequency of the alternating current, N is the number of turns in the coil, A is the area of the coil, and θ is the angle between the magnetic field and the normal to the coil. From this equation, we can see that the speed required to generate a certain emf is dependent on the frequency and the number of turns in the coil.

Therefore, the specific speed required to generate a maximum induced emf of 50 V will depend on the specific generator in question.

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