A vapor-compression refrigeration system circulates R−134a at a rate of 10 kg/min. The refrigerant enters the compressor at −10 ∘ C,1.2 bar and exits at 7 bars. The isentropic compressor efficiency is 68%. There are no significant pressure drops as the refrigerant flows through the condenser and evaporator. The refrigerant leaves the condenser at 7 bar and 24 ∘ C. Ignoring the heat transfer between the compressor and its surroundings, determine (a) the coefficient of performance, (b) the refrigerating capacity in tons

Answer:

The yoke is a clamp-type mounting, which is placed over the tank valve and then tightened into place. The DIN is a threaded valve, wherein you screw the regulator into the tank valve

Answer: You make more money

Explanation: A pc is like 2k+ to build so imagine all of the profits coming in from your business/work.

The given statement "The DOM is an abstract interface whose purpose is to provide a language independent way to access the elements of an HTML document" is true because it correctly defines DOM.

The Document Object Model (DOM) is a programming interface for web documents. It represents the page so that programs can change the document structure, style, and content. The DOM is language-independent and allows programming languages such as JavaScript to access and manipulate the content of an HTML document dynamically. It provides a hierarchical tree structure of the HTML document, where each node of the tree represents an HTML element, attribute, or text.

The DOM allows developers to write programs that can update the content of web pages without requiring a page reload, making it a powerful tool for creating dynamic and interactive web applications.

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Micrometer for brake rotors. For air disc brakes, the steering axle brake lining/pad thickness must be at least 3.2 mm (1/8 inch), and for hydraulic disc, drum, and electric brakes, it must be at least 1.6 mm (1/16 inch).

Every 45° (1/8 of a rotation), take a measurement of the brake rotor thickness of 0.40 inches (10mm) inside the outside circumference of the brake rotor. 6. Compare the lowest result obtained to the brake rotor's minimum thickness requirements. Depending on the vehicle, replacement brake pads can range in thickness from roughly 3/8" to 1/2". When the pads are down to around 1/4 inch, some shops advise changing them; others advise doing so at 1/8 or when only 20 to 25 percent of the original thickness remains.

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qué qué qué qué qué qué qué

It is because an isometric sketch is more useful for functional drawings that are used to explain how something works, while one-point perspective drawings are typically used to give a more sensory idea of an object or space.

Isometric Sketch or isometric drawing can be described as a pictorial representation of an object in which all three dimensions are drawn at full scale. It looks like an isometric projection. Isometric sketch is kind of 3D drawing, which is set out using 30-degree angles. It is kind of axonometric drawing so the same scale is used for every axis, resulting in a non-distorted image.

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The volumetric pipette is the most accurate device to measure the volume of a standard solution. Therefore, the correct answer is (c) i.e. volumetric pipette.

The volumetric pipette is the most accurate pipette out of all for measuring volumetric annalysis. Volumetric pipettes are glasswares that are designed to transfer a particular small volume of sample fluid from one container to another in a very stable and controlled manner while preserving an accurate record of each sample drop.

What are pipettes?

In the context of the laboratory, pipettes are used to transfer liquid from one container to another accurately and swiftly.  While there exist several different types of pipettes, it is vital to take into account that some certain pipettes offer more accuracy as a comparison to others.

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Answer:What is Kirchhoff's loops rule?

Image result for What does Kirchhoff's loop rule say for a system that only has a battery and a light bulb attached?

Kirchhoff's loop rule states that the algebraic sum of potential differences, including voltage supplied by the voltage sources and resistive elements, in any loop must be equal to zero. For example, consider a simple loop with no junctions, as in Figure 6.3. 3.

Explanation:

Knowing the mass of the I section's centre of mass is necessary to calculate the moment of inertia of the I section.

A body's geometric centre is known as a centroid. It alludes to the uniform density object's c, or centre of gravity.

A body's centroid is the location where the volume on each side is equal. A solid body made of a single material has its mass at its centroid. The centroid and centre of mass of a body are identical if its mass is dispersed evenly.

The centroid is the object's focal point. The centroid of a triangle is the location where the three medians of the triangle intersect. The intersection of all three medians is another definition for it.

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Answer:

B) SHORT CIRCUIT

Explanation:

Answer:

Explanation:The directive that tells the assembler to recognize 80x86 instructions that use 32-bit operands is:

B) .586

The .586 directive enables the assembler to recognize and support instructions specific to the 586 (Pentium) processor and later versions. This includes instructions that use 32-bit operands, as the 586 processor and subsequent processors introduced the ability to work with 32-bit data.

A) .STACK 4096 is a directive used to allocate stack memory for the program.

C) .MODEL FLAT is a directive that specifies the memory model used for the program, but it does not directly enable recognition of 32-bit operands.

Therefore, the correct answer is B) .586.

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Answer:

A. ) 591.7 v

B.) 991.7v

C.) 59.7%

D.) 47.9 Kw

E.) 247925 W

F.) 59.7 %

Explanation:

Given that a simple power system consists of a dc generator connected to a load center via a transmission line. The load power is 100 kW. The transmission line is 100 km copper wire of 3 cm diameter. If the voltage at the load side is 400 V,

Let first calculate the resistance in the wire.

The resistivity (rho) of a copper wire is 1.673×10^-8 ohm metres

Resistance R =( L× rho)/A

Where Area = πr^2 = π × 0.015^2

Area = 0.00071 m^2

R = (100000 × 1.673×10^-8) / 0.00071

Resistance in wire = 2.367 ohms

Then let calculate the resistance in the load.

Also, since Power P = V^2 /R

Make R the subject of formula

R = V^2/ P

R = 400^2/100000

Resistance in load = 1.6 Ohms

Current l = V / R

I = 400/1.6 = 250 Ampere

a.) Voltage drop across the line V line will be achieved by using Ohms law.

V = I R

V = 250 × 2.367

V = 591.7 v

B.) Voltage at the source side Vsource will be

V = V line + V load

V = 400 + 591.7

V = 991.7 v

C.) Percentage of the voltage drop Vline /Vsource

591.7/991.7 × 100 = 59.7%

D.) Line losses

P = I V

P = 250 × 591.7

P = 147925 W

Power loss = 147925 - 100000

Power loss = 47,925 W

Power loss = 47.9 Kw

E.) Power delivered by the source

P = IV

P = 250 × 991.7 = 247925 W

F.) System efficiency

Efficiency = power line / power source × 100

Efficiency = 147925 / 247925 × 100

Efficiency = 59.7 %

In this exercise we have to use the circuit knowledge of an electrical system and calculate the characteristics so we have to:

A. ) 591.7 v

B.) 991.7v

C.) 59.7%

D.) 47.9 Kw

E.) 247925 W

F.) 59.7 %

Organizing the information given in the statement we have that:

Calculating the resistivity we find that:

\(R =( L* \rho)/A\\A= \pi r^2 = 0.00071 m^2\\R = (100000 * 1.673*10^{-8}) / 0.00071\\R = 2.367 ohms\)

Then it becomes simpler to calculate the power and current, we have:

A)  With the above information, we can calculate the voltage as:

\(V = I R\\V = 250 * 2.367\\V = 591.7 v\)

B) Now calculating the source voltage, we find that:

\(V = V line + V load\\V = 400 + 591.7\\V = 991.7 v\)

C.) The percentage will be calculated as the division of the two previous values, like:

\(591.7/991.7 * 100 = 59.7\%\)

D.) Like any imperfect circuit, losses occur, so the loss will be calculated as:

\(Power loss = 147925 - 100000\\Power loss = 47,925 W\\Power loss = 47.9 Kw\)

E.) Power delivered by the source, can be:

\(P = IV\\P = 250 * 991.7 = 247925 W\)

F.) System efficiency, will be:

\(Efficiency = power line / power source *100\\Efficiency = 147925 / 247925 * 100\\Efficiency = 59.7 \%\)

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a. a = 12 is the solution to the given congruence relation. b. the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

(a) The main answer: The integer a that satisfies a ≡ -15 (mod 27) is 12.

To find the value of a, we need to consider the congruence relation a ≡ -15 (mod 27). This means that a and -15 have the same remainder when divided by 27.

To determine the value of a, we can add multiples of 27 to -15 until we find a number that falls within the range of {0, 1,..., 26}. By adding 27 to -15, we get 12. Therefore, a = 12 is the solution to the given congruence relation.

(b) The main answer: The positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

Supporting explanation: Two integers are relatively prime if their greatest common divisor (GCD) is 1. In this case, we are looking for positive integers that have no common factors with 12 other than 1.

To determine which numbers satisfy this condition, we can examine each positive integer less than 12 and calculate its GCD with 12.

For 1, the GCD(1, 12) = 1, which means it is relatively prime to 12.

For 2, the GCD(2, 12) = 2, so it is not relatively prime to 12.

For 3, the GCD(3, 12) = 3, so it is not relatively prime to 12.

For 4, the GCD(4, 12) = 4, so it is not relatively prime to 12.

For 5, the GCD(5, 12) = 1, which means it is relatively prime to 12.

For 6, the GCD(6, 12) = 6, so it is not relatively prime to 12.

For 7, the GCD(7, 12) = 1, which means it is relatively prime to 12.

For 8, the GCD(8, 12) = 4, so it is not relatively prime to 12.

For 9, the GCD(9, 12) = 3, so it is not relatively prime to 12.

For 10, the GCD(10, 12) = 2, so it is not relatively prime to 12.

For 11, the GCD(11, 12) = 1, which means it is relatively prime to 12.

Therefore, the positive integers less than 12 that are relatively prime to 12 are 1, 5, 7, and 11.

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Answer:

Executive Summary

Explanation:

It is Executive Summary because I used process of elimination. Constraints are set backs. Project objectives are the goals that you want to achieve. Project development cycle are basically the steps that will be used.

The altitude ensures acceptable navigational signal coverage only within 22 NM of a VOR.

Altitude or height exists as distance measurement, usually in the vertical or "up" approach, between a reference datum and a point or object. The exact meaning and reference datum change according to the context.

The MOCA exists in the lower published altitude in effect between fixes on VOR airways, off-airway routes, or route segments that satisfy obstacle support conditions for the whole route segment. This altitude also ensures acceptable navigational signal coverage only within 22 NM of a VOR.

The altitude ensures acceptable navigational signal coverage only within 22 NM of a VOR.

Therefore, the correct answer is 22 NM of a VOR.

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Answer:

A tax is a monetary payment without the right to individual consideration, which a public law imposes on all taxable persons - including both natural and legal persons - in order to generate income. This means that taxes are public-law levies that everyone must pay to cover general financial needs who meet the criteria of tax liability, whereby the generation of income should at least be an auxiliary purpose. Taxes are usually the main source of income of a modern state. Due to the financial implications for all citizens and the complex tax legislation, taxes and other charges are an ongoing political and social issue.

I dont know I asked this to

Explanation:

Answer:

\(\triangle h=4.935m\)

Explanation:

From the question we are told that:

Liquid density \(\rho=800\)

Diameter of pipe \(d=4cm \approx 0.004m\)

Diameter of venture \(d=10cm \approx 0.010m\)

Specific weight of mercury P_mg \(133 kN/m^3\)

Flow rate \(r=0.05 m^3/s\)

Area A:

            \(A_1=\frac{\pi}{4}0.1^2\\A_1=0.00785m^2\\A_2=\frac{\pi}{4}0.04^2\\A_2=0.001256m^2\\\)

Generally the Bernoulli's equation is mathematically given by

\(\frac{P_1}{\rho_1g}+\frac{V_1^2}{2g}=\frac{P_2}{\rho g}+\frac{V_2^2}{2g}\\\)

Where

\(V_1=\frac{r}{A_1} \\\\ &V_1=\frac{r}{A_2}\)

Therefore

\(P_1-P_2=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

Generally the equation for pressure difference b/w manometer fluid is given as

\(P_1-P_2=(p_mg-pg)\triangle h\)

Therefore

\((p_mg-pg)\triangle h=\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})\)

\(\triangle h=\frac{\frac{Pr^2}{2}(\frac{A_1^2-A_2^2}{A_1^2A_2^2})}{(p_mg-pg)}\)

\(\triangle h=\frac{\frac{(800)(0.05)^2}{2}(\frac{(0.1)^2-(0.4)^2}{(0.1)^2(0.04)^2})}{(1.33*10^3-800*9.81)}\)

\(\triangle h=4.935m\)

Therefore elevation change is mathematically given by

\(\triangle h=4.935m\)

To replace a uniformly distributed loading with a single force, we need to find the static equivalent force that produces the same effect as the distributed loading.

The magnitude of the equivalent force can be found by calculating the area under the load curve and multiplying it by the length of the loaded beam. This gives us the total load on the beam.

Once we have the total load, we can find the location of the equivalent force by calculating the centroid of the loaded area. The centroid is the point where the load is effectively concentrated.

The direction of the equivalent force is perpendicular to the plane of the loaded beam and acts at the location of the centroid.

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Explanation:

The main sources of error in the collection of data are as follows : Due to direct personal interview. Due to indirect oral interviews. Information from correspondents may be misleading. Mailed questionnaire may not be properly answered. Schedules sent through enumerators, may give wrong information.

It doesn't really matter whether your adapters are clean as long as they're not worn is a true statement.

An adapter is said to be a kind of a physical device that gives room for a single hardware or electronic interface to be plugged in(accommodated without loss of function) to another hardware or electronic interface.

An adapter is known to be an electronic device tht is often used in regards to electrical connections.

Note that an adapter can work even if they are dirty. Hence, It doesn't really matter whether your adapters are clean as long as they're not worn is a true statement.

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The number of hectares of each crop he should plant are; 250 hectares of Corn, 500 hectares of Wheat and 450 hectares of soybeans

He grows corn, wheat and soya beans on the farm of 1200 hectares. Thus;

C + W + S = 12   ----(1)

It costs $45 per hectare to grow corn, $60 to grow wheat, and $50 to grow soybeans. Thus;

45C + 60W + 50S = 63750  -----(2)

He will grow twice as many hectares of wheat as corn. Thus;

W = 2C    ------(3)

Put 2C for W in eq 1 and eq 2 to get;

C + 2C + S = 1200

3C + S = 1200     -----(4)

45C + 60(2C) + 50S = 63750

45C + 120C + 50S = 63750

165C + 50S = 63750    ------(5)

Solving eq 4 and 5 simultaneosly gives;

C = 250 and W = 500

Thus; S = 1200 - 3(250)

S = 450

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The student exerts the greatest force on the floor of the elevator when the elevator is at rest, either starting from the first floor or stopping at the tenth floor. When the elevator is in motion, the student is being acted upon by two forces: their weight, which is acting vertically downward, and the normal force from the floor of the elevator, which is acting vertically upward.

The normal force is equal in magnitude to the weight of the student but acts in the opposite direction. As a result, the net force acting on the student is zero and the student does not exert any significant force on the floor of the elevator.

However, when the elevator comes to a stop, the normal force changes. The sudden change in velocity means that there is a non-zero net force acting on the student, which results in the student exerting a force on the floor of the elevator. The magnitude of this force is equal to the student's weight, which is determined by their mass and the acceleration due to gravity.

In conclusion, the student exerts the greatest force on the floor of the elevator when the elevator is at rest, either starting from the first floor or stopping at the tenth floor. This is because the normal force changes when the elevator comes to a stop, resulting in a non-zero net force acting on the student and a corresponding force being exerted on the floor of the elevator.

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Add the difference between the EDD and the delivery date to 280 days (280 days - 8 days = 272 days, for example). By multiplying the total days from step 3 by 7, you can get 38.9 weeks.

Menstrual history, clinical examination, and ultrasound are the three fundamental techniques used to estimate gestational age (GA). We also show that birth weight can be calculated more accurately than gestational age. A larger mother's size, superior nutritional reserves as measured by her arm fat and muscle area during pregnancy, a higher birth order, quitting smoking, and her age between 20 and 35 all had a significant impact on FFGC.

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The relationship between density, pipe average velocity, and cross-sectional area perpendicular to the velocity can be used to calculate mass flow rate.

The quantity of mass flowing across a cross-section per unit of time is known as the mass flow rate. The volume of the fluid moving through a cross-section per unit time is referred to as a volume flow rate. By multiplying the fluid's density, the average pipe velocity, and the cross-sectional area of the pipe normal to the velocity, one can compute the mass flow rate, which is a measurement of the amount of mass flowing through a particular cross-section per unit time. Contrarily, volume flow rate is defined as the amount of fluid moving across a specific cross-section in a unit of time. The mass flow rate into a control volume is proportional to the velocity component parallel to the cross-sectional area for fluid flow in a pipe, when the velocity is constant across the pipe's cross-section.

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To calculate the power radiated by a half-wave dipole, we need to use the expression for the power radiated per unit solid angle:

P = (1/2) * (η * c * r^2) * |Hϕ|^2

where P is the power radiated, η is the impedance of free space (approximately 377 ohms), c is the speed of light (approximately 3 x 10^8 m/s), r is the distance from the antenna, and |Hϕ| is the magnitude of the magnetic field strength.

Given: Magnetic field strength |Hϕ| = 60 * I0 * cos(π/2) * cos(θ) * Z0 * sin(θ)

|Hϕ| = 10μA/m

θ = π/4

r = 10 km = 10,000 m

First, we need to convert the magnetic field strength to amperes (A):

|Hϕ| = 10μA/m = 10 * 10^(-6) A/m

Substituting the given values into the power equation:

P = (1/2) * (377 * 3 * 10^8 * (10,000)^2) * (10 * 10^(-6))^2

Simplifying the equation:

P ≈ 1.3 watts

Therefore, the power radiated by the half-wave dipole is approximately 1.3 watts.

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The amount of total current draw that will occur if the strip heat comes on while the compressor is operating is 53.778 A.

We have the following details

Pe = 10 Kw

compressor current = 34A

Power factor = 70%

The voltage applied = 240 V

frequency f = 60 Hz

P = ER² / R

= 240² / 10 x 10

= 57600 / 10000

= 5.76Ω

We have El = Lr = Et

El = Lr = 240

The true power P

10 x 10³ / 240

= 41.667 A

The total current is solved by

√41.667² + 34³

= √1736.138 + 1156

= √2892.138

= 53.778 A

Hence the amount of total current draw that will occur if the strip heat comes on while the compressor is operating is 53.778 A.

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