A uniform ladder rests on a rough horizontal ground leaning against a smoth vertical wall.Weight of a ladder is 300 N and a man weighing 500 N stands on one quarter of its length from the bottom. Ladder makes 30 to the horizontal. Find the reaction at the wall and the total force on the ground.
Answers
The total force of the ground is 800N and the reaction at the wall on the ground is 476.3 N.
From the given,
weight of ladder (W₁) = 300N
weight of man (W₂) = 500N
The angle (θ) = 30°
The reaction at the wall (R) =?
ΣMg =0
-R.l.sin(30°) + 500×1/4×l(cos 30°) + 300×1/2×l(cos 30°) = 0
125×l(cos 30°) + 150×l(cos 30°) = R.l.sin(30°)
(125 + 150)×l(cos 30°) = R.l×sin(30°)
275 ×l(cos 30°) / l×sin(30°) = R
275×0.866/ 0.5 = R
238.15 ×2 =R
R = 476.3 N
The total force, Fg = 300 + 500
Fg = 800 N.
Thus, the total force Fg is 800 N and the reaction at the wall is 476.3 N.
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Related Questions
Does water pressure depend on the total amount of water present?
(Will pick brainliest)
Answers
Answer:
No, because pressure is determined by force and the area over which that force acts.
Explanation:
The noble gas neon is used for filling neon signs. Like other noble elements, it has a full octet (complete outer energy level) of electrons, which makes the gas A. freeze at room temperature. B. react with other gases in the air. C. unlikely to combine with other elements. D. solidify at standard pressure and temperature, chiny pray-colored solid at room
Answers
Answer:
C. unlikely to combine with other elements.
Explanation:
In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.
Noble gases are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.
Hence, the full octet makes the gas (neon) unlikely to combine with other elements.
How much work does a 25-newton force do to lift a potted plant from the floor to a shelf 1.5 meters high?
Answers
Answer:
37.5 N*m
Explanation:
w=fd
w=?
f=25 N
d=1.5 m
w=25N*1.5m=37.5 N*m
25 POINTS 25 POINTS 25 POINTS 25 POINTS 25 POINTS
Assignment: Build an Electromagnet and a Motor Investigation
Electromagnet
1. How many paper clips did the wire wrapped around the nail just a few times pick up?
2. Which electromagnet design was most successful in picking up the most paper clips?
3. Would wrapping the wire more times around the nail make the electromagnet stronger or weaker?
4. What do you think the result would be if an iron nail that was much thicker was used?
5. What do you think would happen if a wooden stick was chosen as the core instead of the iron nail?
Motor
1. Describe the components that are necessary to make a motor run? What do they each provide? (example: battery provides voltage source)
2. Describe how the homemade motor makes mechanical energy from electrical energy.
3. What are three appliances in your house that use a motor that turns electrical energy into mechanical energy?
Answers
All the paper clips, coiled wire with nail and wrapping or coiling the wire more times are the correct answers.
All the paper clips will the wire wrapped around the nail just a few times pick up. A coiled wire with nail in the center is the electromagnet design which is most successful in picking up the most paper clips. Wrapping or coiling the wire more times around the nail make the electromagnet more stronger.
If an iron nail that was much thicker was used, it will make the magnet stronger that leads to strong electromagnetism. There are three main parts that is necessary for making a motor i.e. a rotor, a stator and a commutator.
These three parts use the attractive and repulsive forces of electromagnetism, causing the motor to spin continually as long as it receives a steady flow of electric current. Motors comprise of loops of wire in a magnetic field.
When current is passed through the loops, the magnetic field exerts a torque on the loops, which rotates the shaft that leads to the generation of electricity. Water pump, mixer and washing machine are three appliances in your house that use a motor that turns electrical energy into mechanical energy.
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A 1=2.40 μF
capacitor is first charged by being connected across a battery with voltage b=8.00 V.
It is then disconnected from the battery and connected across an uncharged capacitor with capacitance 2=5.60 μF.
Calculate the final charge 1,f
and 2,f
on 1
and 2,
respectively.
Answers
The final charge on the first capacitor is 7.20 μC and the final charge on the second capacitor is 12.00 μC.
What do you mean by charge ?When placed in an electromagnetic field, the physical property of matter known as electric charge causes it to experience a force.
Positive and negative electric charges are the two types of charges that charge carriers, protons and electrons, commonly carry. The movement of charges produces energy.
The initial charge on the first capacitor, 1, can be calculated using the formula as follows:
Q = C × V
where,
Q is the charge,
C is the capacitance, and
V is the voltage.
By substituting the values, we get:
Q = 2.40 μF × 8.00 V
= 19.2 μC
Let's call the final charge on the first capacitor 1,f and the final charge on the second capacitor 2,f.
So, the two capacitors are now connected in parallel, their equivalent capacitance is C_eq :
C_eq = C1 + C2
C_eq = 2.40 μF + 5.60 μF
= 8.00 μF
The final charge on the equivalent capacitance is equal to the initial charge on the first capacitor,
Q_eq = Q1,f = 19.2 μC
From this, we can calculate the final charge on each capacitor:
Q1,f = (C1 / C_eq) × Q_eq
Q1,f = (2.40 μF / 8.00 μF) × 19.2 μC
= 7.20 μC
Q2,f = (C2 / C_eq) × Q_eq
Q2,f = (5.60 μF / 8.00 μF) × 19.2 μC
= 12.00 μC
Thus, The final charge on the first capacitor is 7.20 μC and the final charge on the second capacitor is 12.00 μC.
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The following table was given to Candoe by her teacher. She couldn't find answer to some questions. Help her in completing the table.
Layer name Horizon name
1. Organic layer 1. Horizon O
2. Top soil 2. Horizon A
3. Sub soil 3. Horizon B
4. Weathered rock particles 4. Horizon C
5. Bed rock 5. Horizon R
Answers
Here is the completed soil horizon table:
Layer name Horizon name
Organic layer 1. Horizon O
Top soil 2. Horizon A
Sub soil 3. Horizon B
4.Weathered rock particles 4. Horizon C
Bed rock 5. Horizon R
The soil horizon names are:
O horizon: This is the organic layer consisting of accumulating plant litter and decomposing organic matter.
A horizon: This is the top soil consisting of mineral material mixed with organic matter. It has the highest concentration of organic matter.
B horizon: This is the subsoil consisting of predominantly mineral material. It has less organic matter than the A horizon.
C horizon: This consists of weathered bedrock with accumulated mineral material. It contains few organic materials.
R horizon: This is the unweathered bedrock material beneath the soil layers.
So each soil layer is named according to its composition and properties using horizon names from O to R
If you travel 450 meters in 40 seconds, what is your average speed in meters per
second?
A)11.25
B)40
C)450
D)18000
Answers
Answer:
The answer is a 11.25m/s
An object of mass 10 kg, initially at rest, experiences a constant horizontal acceleration of 4 m/s2 due to the action of a resultant force applied for 20 s. Determine the total amount of energy transfer by work, in kj.
Answers
So, the total energy value that has been transferred by work is 32 kJ.
IntroductionHi ! In this question, I will help you. Work is the amount of force exerted to cause an object to move a certain distance from its starting point. In physics, the amount of work will be proportional to the increase in force and increase in displacement. Amount of work can be calculated by this equation :
\( \boxed{\sf{\bold{W = F \times s}}} \)
With the following condition :
W = work (J)F = force (N)s = shift or displacement (m)Now, because in this question, the "s" is not directly known, whereas it is known that the initial velocity is zero, the object has an acceleration, and is moving in certain time intervals. Then, use this formula to find the value of "s" !
\( \boxed{\sf{\bold{s = \frac{1}{2} \times a \times t^2}}} \)
With the following condition :
s = shift or displacement (m)a = acceleration (m/s²)t = interval of the time (s)Problem SolvingWe know that :
a = acceleration = 4 m/s²t = interval of the time = 20 sm = mass = 10 kgWhat was asked :
W = work = ... kJStep by Step :
Calculate value of force by multiple m and a\( \sf{F = m \times a} \)
\( \sf{F = 10 \times 4} \)
\( \sf{\bold{F = 40 \: N}} \)
Calculate value of shift or displacement\( \sf{s = \frac{1}{2} \times a \times t^2} \)
\( \sf{s = \frac{1}{\cancel 2} \times \cancel 4 \:_2 \times 20^2} \)
\( \sf{s = 2 \times 400} \)
\( \sf{\bold{s = 800 \: m}} \)
Last, calculate the value of work\( \sf{W = F \times s} \)
\( \sf{W = 40 \times 800} \)
\( \boxed{\sf{W = 32,000 \: J = 32 \: kJ}} \)
So, the total energy value that has been transferred by work is 32 kJ.
Hello,Plz Help Which conditions are necessary for rain to form?
The temperature of the air below the cloud is above freezing.
The temperature of the air below the cloud is below freezing.
The sky has no clouds, and the temperature of the air is cold.
There is a warm layer of air and a cold layer of air closer to the ground.
Answers
The third one makes no since because the clouds carry the rain. It isn’t always cold when it’s going to rain
The fourth one is a good one
The second one again it’s not always cold when it’s raining
The first one could be it also
Hmmm I would go with the last one
Sorry if it’s wrong
The option There is a warm layer of air and a cold layer of air closer to the ground. is the correct answer
How would the motion of the book change if there was MORE friction as it moved across the table?
Answers
Answer:
The force of friction opposes the motion of an object, causing moving objects to lose energy and slow down.
Explanation:
A fast Humvee drove from Desert A to Desert B. for the first 12 hours and traveled at an average speed of 185 km/h. For the next 13 hours, it travelled at an average speed of 160 km/h. What was the average speed of the whole journey?
Answers
Answer:
The value is \(v_t = 172 \ km/h\)
Explanation:
From the question we are told that
The average speed for the first 12 hours is \(u = 185 km/h\)
The average speed for the next 13 hours is \(v = 160 \ km/h\)
Generally the total time taken is mathematically represented as
\(t_t = 12 + 13\)
=> \(t_t = 25 \ h\)
The distance covered in the first movement is
\(D = u * 12\)
\(D = 185 * 12\)
\(D = 2220 \ km\)
The distance covered in the first movement is
\(d= v * 13\)
\(d = 160 * 13\)
\(d = 2080 \ km\)
The total distance traveled is
\(D_t = D + d\)
\(D_t = 2220 +2080\)
\(D_t = 4300 \ km\)
The average of the whole journey is
\(v_t = \frac{D_t}{t_t}\)
\(v_t = \frac{4300}{25}\)
\(v_t = \frac{4300}{25}\)
\(v_t = 172 \ km/h\)
an electromagnetic wave travels in a straight line through a vacuum. The wave has a frequency of 6.0THz. What is the number of wavelengths in a distance of 1.0m along the wave?
Answers
Answer:
i think it is 123
Calculate the angular momentum of a ballet dancer who is spinning at 1.5 rev/sec. Model the dancer as a cylinder (I = MR 2) with a mass of 62 kg, a height of 1.6 m and a radius of 0.16 m.
Answers
The angular momentum of the ballet dancer is 14.98 kgm²/s.
What is the angular momentum of the ballet dancer?The angular momentum of the ballet dancer is calculated by applying the following formula as show below.
L = Iω
where;
I is the moment of inertia of the dancerω is the angular speed of the dancer = 1.5 rev/sec = 9.42 rad/sThe moment of inertia of the dancer, I = MR²
I = 62 kg x (0.16 m )²
I = 1.59 kgm²
The angular momentum of the ballet dancer is calculated as;
L = 1.59 x 9.42
L = 14.98 kgm²/s
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help me with the question b.
Answers
Answer:
a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.
b) Liquid P - \(Q = 3840\,J\), Liquid Q - \(Q = 5500\,J\), Liquid R - \(Q = 7800\,J\), Liquid S - \(Q = 2856\,J\)
Explanation:
a) The specific heat capacity means the amount of heat needed by a unit mass of a material to increase its temperature in one unit.
b) Let suppose that heat transfer rates between liquids and surroundings are stable. The quantity of the heat released is determined by the following expression:
\(Q = m\cdot c\cdot (T_{r} - T_{f})\) (1)
Where:
\(m\) - Mass of the liquid, in kilograms.
\(c\) - Specific heat capacity, in joules per kilogram-degree Celsius.
\(T_{r}\) - Initial temperature of the sample, in degrees Celsius.
\(T_{f}\) - Freezing point, in degrees Celsius.
Liquid P (\(m = 1\,kg\), \(c = 160\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 6\,^{\circ}C\))
\(Q = (1\,kg)\cdot \left(160\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 6\,^{\circ}C)\)
\(Q = 3840\,J\)
Liquid Q (\(m = 1\,kg\), \(c = 220\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 5\,^{\circ}C\))
\(Q = (1\,kg)\cdot \left(220\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 5\,^{\circ}C)\)
\(Q = 5500\,J\)
Liquid R (\(m = 1\,kg\), \(c = 300\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 4\,^{\circ}C\))
\(Q = (1\,kg)\cdot \left(300\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 4\,^{\circ}C)\)
\(Q = 7800\,J\)
Liquid S (\(m = 1\,kg\), \(c = 102\,\frac{J}{kg\cdot ^{\circ}C}\), \(T_{r} = 30\,^{\circ}C\), \(T_{f} = 2\,^{\circ}C\))
\(Q = (1\,kg)\cdot \left(102\,\frac{J}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C - 2\,^{\circ}C)\)
\(Q = 2856\,J\)
if Sarah melts 10g of tin. What mass of melted tin would she have at the end of the experiment?
Answers
Answer:
10g
Explanation:
As the Law of Conservation of Mass states that " Mass can neither be created nor be destroyed in a chemical reaction".
Though melting of tin isn't a chemical change, the same logic is applied here...
Hence,
The mass of tin will be 10 g itself...
Answer:
10g
Explanation:
The experiment is about melting of tin. When solid tin is melted, it retains the amount of substance it originally has and we expect it to still be 10g.
Mass is the quantity or amount of matter contained in a substance. For most chemical processes, the law of conservation of matter is always succinctly observed.
The law states that "matter is neither created nor destroyed in a chemical reaction or process". Although melting is a phase change, we can adapt this law to the process. Owning to no loss of matter in the melting procedure, the amount of substance remains the same.
Therefore, we are left with about the same mass of substance we started with which is 10g.
With what speed would a rock of mass 115g
have to be thrown if it were to have a
wavelength of 2.03 × 10−34 m?
Planck’s constant is 6.63 × 10−34 J · s.
Answer in units of m/s.
Answers
The speed of the rock is 56.8 m/s.
Wavelength, λ = 2.03 x 10⁻³⁴m
Mass of the rock, m = 115 x 10⁻³kg
So, the kinetic energy,
1/2 mv² = hc/λ
v = √(2hc/mλ)
v = √(2 x 6.63 x 10⁻³⁴/115 x 10⁻³x2.03 x 10⁻³⁴)
v = 56.8 m/s
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Distance divided by time is known as
Answers
Distance divided by time is known as the speed of the given body or the object the result we get out by dividing the distance from the time is a scalar quantity as it does not depend on the direction of the moving object.
What is speed?The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.
Let us suppose an ant is moving and it covers a total distance of 2.5 meters in 25 seconds, then if we divide the time taken by the ant by the distance traveled by the ant we would get the speed of the ant.
Thus, distance divided by time is known as speed.
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Sonya pushes his friend down the road on his new wagon. Which two terms accurately describe the net force acting on the sled?
Group of answer choices
balanced and contact
unbalanced and noncontact
balanced and noncontact force
unbalanced and contact
Answers
Answer:
unbalanced and contact
Explanation:
The two terms that bests describes the net force acting on the sled is an unbalanced and contact force.
Force is a pull or push on a body. We have two main types of forces. Contact forces acts on a body and they must be in touch with it. An example is frictional force.
Non - contact forces acts based on force field and they are not in contact with the body. An example is gravitational force.
Since the sled is sliding down the road, it is changing velocity and so, unbalanced forces are acting on it.Therefore, the force on the wagon is an unbalanced and contact force.
What is the wavelength of a wave moving at 450 m/s with a frequency of 464 Hz?
Answers
The wavelength of a wave moving at 450m/s with a frequency of 464Hz is 0.97m.
We know that wavelength of a wave is calculated by
\(\lambda=\frac{v}{f}\) ...(i)
where λ ⇒ wavelength
v ⇒ velocity of a wave
f ⇒ frequency
Now, as per the question:
Velocity of wave, v = 450 m/s
Frequency, f = 464 Hz
Putting the values in equation (i),
λ = 450/464
λ = 0.97 m
Therefore, wavelength of a wave moving at 450m/s with a frequency of 464Hz is 0.97m.
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A rightward force is applied to a 8.35 kg object
to accelerate it to the right at 10.6 m/s/s. The
coefficient of friction for the object and the
surface is 0.375. Determine the force of gravity.
the normal force, the force of friction, the
applied force, and the net force,
Answers
Force of gravity = mg = 8.35 * 9.8 = 81.83 N
normal force (N) = 81.83 N
force of friction = 30.69 N
Applied force = 119.2 N
net force = 88.51 N
given
mass = 8.35 kg
acceleration = 10.6 \(m/s^{2}\)
coefficient of friction (mu) = 0.375
force of gravity = mg = 8.35 * 9.8 = 81.83 N
normal force (N) = 81.83 N ( as mg = N )
force of friction = mu * normal = 0.375 * 81.83 = 30.69 N
F net = 0
applied force - force of friction = mass * acceleration
F - fr = ma
F = ma + fr
= 8.35 * 10.6 + 30.69
= 119.2 N
net force = F - fr = ma = 8.35 * 10.6
= 88.51 N
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4. Apply Scientific Reasoning The solar
system formed when gravity began collapsing
a cloud of gas, rock, ice, and other materials.
Where did the gravity come from to initiate
this collapse? Explain.
Answers
Answer:
The gravity that initiated the collapse of the cloud of gas, rock, ice, and other materials that formed the solar system came from the accumulation of mass within the cloud itself. Over time, the force of gravity grew strong enough to overcome the outward pressure of the gas and dust in the cloud, causing it to collapse inward and eventually form the Sun and the planets.
Explanation:
The gravity that initiated the collapse of the cloud of gas, rock, ice, and other materials that formed the solar system came from the accumulation of mass within the cloud itself. The cloud of gas and dust that formed the solar system was made up of tiny particles, some of which had a slightly greater mass than others. As these particles moved around and collided with one another, their gravitational forces began to accumulate and become stronger. The more particles that came together, the greater the force of gravity became.
Over time, the force of gravity grew strong enough to overcome the outward pressure of the gas and dust in the cloud, causing it to collapse inward. As the cloud continued to collapse, it became denser and denser, and the force of gravity continued to increase. Eventually, the pressure and temperature at the center of the cloud became high enough to initiate nuclear fusion reactions, leading to the formation of the Sun and the protoplanetary disk that eventually formed the planets.
In summary, the gravity that initiated the collapse of the cloud of gas, rock, ice, and other materials that formed the solar system came from the accumulation of mass within the cloud itself, and as the cloud continued to collapse, the force of gravity continued to increase.
a horizontal spring with stiffness 0.5 n/m has a relaxed length of 15 cm. a mass of 20 g is attached and you stretch the spring to a total length of 25 cm. the mass is then released from rest and moves with little friction. what is the speed of the mass at the moment when the spring returns to its relaxed length of 15 cm?
Answers
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
1. First, we need to find the spring constant (k) and the mass (m). We are given k = 0.5 N/m and m = 20 g (which we need to convert to kg): m = 20/1000 = 0.02 kg.
2. Next, we need to determine the elongation (x) of the spring. We are given the initial length (25 cm) and the relaxed length (15 cm):
x = 25 cm - 15 cm = 10 cm (which we need to convert to meters):
x = 10/100 = 0.1 m.
3. Now, we can calculate the potential energy (PE) stored in the spring when it's stretched: PE = (1/2) * k * x^2 = (1/2) * 0.5 N/m * (0.1 m)^2 = 0.0025 J.
4. When the spring returns to its relaxed length, the potential energy will be converted into kinetic energy (KE): KE = (1/2) * m * v^2.
5. Since PE = KE, we can solve for the velocity (v) of the mass: 0.0025 J = (1/2) * 0.02 kg * v^2.
6. Solve for v: v^2 = (0.0025 J * 2) / 0.02 kg
v^2 = 0.25
v = √0.25 = 0.5 m/s.
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
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need helping getting the answer
Answers
A 55 kg packing crate is pulled with a constant speed across a rough floor with a rope that is at an angle of 40.8 degrees above horizontal. If the tension in rope is 145 N, how much work is done to move crate 4.0 m?
Answers
If the tension in rope is 145 N, work done to move crate 4.0 m is 442.4 J.
To solve this problem, we first need to find the force acting on the crate in the horizontal direction. This force is equal to the tension in the rope multiplied by the cosine of the angle between the rope and the horizontal:
F_horizontal = Tension * cos(angle) = 145 N * cos(40.8 degrees) = 110.6 N
Next, we can calculate the work done to move the crate using the formula:
Work = Force * Distance * cos(theta)
where theta is the angle between the force and the direction of motion. Since the crate is moving with a constant speed, we know that the net force on it is zero. Therefore, the force of friction acting on the crate must be equal in magnitude to the force we calculated above:
F_friction = F_horizontal = 110.6 N
The angle between the force of friction and the direction of motion is 180 degrees, so we have:
Work = F_friction * Distance * cos(180 degrees) = - 110.6 N * 4.0 m * cos(180 degrees) = - 442.4 J
The negative sign indicates that the work done is in the opposite direction to the displacement of the crate. In other words, the work done by the force of friction is negative because it acts against the motion of the crate. Therefore, the work done to move the crate 4.0 m is -442.4 J.
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An ideal spring with a spring constant of 200 N/m is compressed 15 cm. A 300 g block is placed in front of the spring and the spring is released so that the block is launched to the right as shown. The initial height of the spring and block above the ground is 1.0 m. The height of the end of the ramp is 1.5 m above the ground. (Ignore friction)
a) At what speed does the block leave the spring?
b) How fast is the block moving when it first becomes airborne?
c) How fast is the block moving when it hits the ground?
d) What is the largest mass of the block that will still allow it to reach the ground? (Find where it just barely gets over the top of the ramp)
Answers
(a) The speed of the block when it leaves the spring is 3.87 m/s.
(b) The speed of the block the moment it first become airborne is 2.28 m/s.
(c) The speed of the block when it hits the ground is 5.88 m/s.
(d) The largest mass of the block that will still allow it to reach the ground is 459.3 g.
What is the speed of the block when it leaves the spring?
The speed of the block when it leaves the spring is calculated by applying the principle of conservation of energy.
¹/₂mv² = ¹/₂kx²
mv² = kx²
v² = kx²/m
v = √(kx²/m)
where;
k is the spring constantx is the extension of the springm is the mass of the blockv = √(200 x 0.15²/0.3)
v = 3.87 m/s
The moment the block moves upwards, gravity will set in. The speed of the block the moment it first become airborne is calculated as follows;
v² = u² - 2gh
where;
v is the speed of the block when it first become airborneu is the initial velocity of the block = 3.87 m/sh is the height above the ground = 1.5 m - 1 m = 0.5 mv² = 3.87² - 2(9.8 x 0.5)
v² = 5.18
v = √5.18
v = 2.28 m/s
The speed of the block when it hits the ground is calculated as follows;
v² = u² + 2gh
where;
v is the final speed of the blocku is the initial speed of block when it first become airborne = 2.28 m/sh is the height of fall of the block = 1.5 mv² = 2.28² + 2(9.8)(1.5)
v² = 34.598
v = √34.598
v = 5.88 m/s
The maximum potential energy of the spring is calculated as;
U(max) = ¹/₂kx²
U(max) = ¹/₂ x 200 x 0.15²
U(max) = 2.25 J
The minimum speed required to cross the 1.5 m of the ramp from a height of 1 m.
height difference, Δh = 1.5 m - 1 m = 0.5 mv = √2gΔh
v = √(2 x 9.8 x 0.5)
v = 3.13 m/s
Apply the principle of conservation of energy and determine the largest mass required to cross the 1.5 m ramp from a height of 1 m.
¹/₂mv² = U(max)
m = 2U/v²
m = (2 x 2.25) / (3.13²)
m = 0.4593 kg
m = 459.3 g
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Jenny is going to California. Her trip will be a total distance of 4,698.5 Km. How many meters is that in total?
Answers
Answer:
ytytyt
Explanation:ytytytyt
There are 1000m in 1km. In order to turn meters in kilometers, you need to multiply km by 1000.
A 12-lb mass attaches to a spring and stretches it 6 inches. After it comes to rest, it is stretched an additional 4 inches above equilibrium and released from rest.
Find the equation of motion. Graph the equation of motion. Find the period, amplitude, and frequency. What’s the velocity when it crosses the equilibrium position?
Answers
The equation of motion is \(x(t) = A * cos(2\pi ft)\), the period is \(T = 1 / f = \frac{1}{\frac{\omega}{2\pi } } = \frac{2\pi }{\omega}\), amplitude is A = 4 inches and frequency is \(\frac{\omega}{2\pi }\) and velocity when it crosses the equilibrium position is \(v(0) = -4{\omega} * sin(0) = 0\)
To find the equation of motion, let's start by determining the spring constant k.
Given:
Mass (m) = 12 lb
Initial displacement (x1) = 6 inches
Additional displacement (x2) = 4 inches
The force exerted by the spring is given by Hooke's Law: F = -kx, where x is the displacement from the equilibrium position.
When the mass is at rest, the net force acting on it is zero, so the force due to gravity (mg) is balanced by the force exerted by the spring (kx1):
\(mg = kx_1\)
We can calculate the spring constant k:
\(k = mg / x_1 = \frac{(12 lb * 32.2 ft/s^2)}{ (6 inches / 12 inches/ft) } = 64.4 lb/ft\)
Now, let's determine the equation of motion for the mass-spring system.
The equation of motion for a mass-spring system is given by:
\(m * d^2x/dt^2 + k * x = 0\)
Substituting the values, we have:
\(12 lb * d^2x/dt^2 + 64.4 * x = 0\)
Dividing both sides by 12 lb to simplify, we get:
\(d^2x/dt^2 + (64.4/12) * x = 0\)
\(d^2x/dt^2 + 5.37 * x = 0\)
This is a second-order linear homogeneous differential equation. The general solution is of the form:
\(x(t) = A * cos(\omega t) + B * sin(\omega t)\)
To determine the values of A and B, we need initial conditions. At t = 0, the mass is at rest and has an additional 4 inches of displacement above equilibrium:
\(x(0) = A * cos(0) + B * sin(0) = A = 4\)
\(v(0) = -A * \omega* sin(0) + B * \omega * cos(0) = B * \omega = 0\) (since the mass is at rest)
Therefore, A = 4 inches and B = 0.
The equation of motion for the mass-spring system is:
\(x(t) = 4 * cos(\omega t )\)
To find the period (T), amplitude (A), and frequency (f), we can compare the equation of motion to the standard form:
\(x(t) = A * cos(2\pi ft)\)
Comparing the equations, we can see that:
A = 4 inches (amplitude)
ω = 2πf
The period T is the time it takes for one complete cycle, which is the reciprocal of the frequency:
\(T = 1 / f = \frac{1}{\frac{\omega}{2\pi } } = \frac{2\pi }{\omega}\)
The velocity when the mass crosses the equilibrium position (x = 0) can be found by taking the derivative of the equation of motion with respect to time:
\(v(t) = dx/dt = -4{\omega} * sin({\omega}t)\)
At t = 0, the velocity is:
\(v(0) = -4{\omega} * sin(0) = 0\)
Therefore, the velocity when it crosses the equilibrium position is 0.
To graph the equation of motion, we can plot\(x(t) = 4 * cos({\omega}t)\) . The graph will be a cosine function oscillating around the equilibrium position (x = 0) with an amplitude of 4 inches.
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10. pushing force whose direction and point of application would tend to shorten or squeeze an object along the dimension coinciding with the line of action of the force.
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The pushing force described in the question is called compressive force. It is a force that acts in the opposite direction of tension, meaning it tends to squeeze or shorten an object along the dimension coinciding with the line of action of the force.
Compressive force is a type of contact force that acts perpendicular to the surface of an object.
It applies pressure on the object, causing it to deform or compress along the direction of the force.
The magnitude of the compressive force depends on various factors, such as the applied load and the properties of the object, like its elasticity.
Compressive forces can be found in various situations, such as when you push down on a spring or when you squeeze a sponge.
In engineering and architecture, compressive forces are crucial to consider when designing structures that need to support weight or withstand external pressure.
Compressive forces can cause objects to buckle, collapse, or undergo structural failure if they exceed the object's capacity to withstand compression.
A compressive force is a pushing force that tends to squeeze or shorten an object along the direction of the force. It is important to consider compressive forces in various fields to ensure the stability and integrity of objects and structures.
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There is a 5mA flowing through an 18k register. What is the voltage drop?
Answers
The voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
To calculate the voltage drop across a resistor, Ohm's Law can be applied. Ohm's Law states that the voltage (V) across a resistor is equal to the product of the current (I) flowing through it and the resistance (R) of the resistor. The formula for Ohm's Law is V = I * R.
Given:
Current (I) = 5 mA = 5 * 10^(-3) A
Resistance (R) = 18 kΩ = 18 * 10^(3) Ω
Using Ohm's Law, we can calculate the voltage drop (V):
V = I * R
= (5 * 10^(-3) A) * (18 * 10^(3) Ω)
= 90 V
Therefore, the voltage drop across the 18 kΩ resistor is 90 volts. This means that when a current of 5 mA flows through an 18 kΩ resistor, there is a potential difference of 90 volts across the resistor.
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Mxcbccbhf chucklingbdbfbfndbfnf
Answers
Answer:
4 seconds
Explanation:
On the Y axis - you go to 12. Go directly horizontally till you hit the line. Then go directly down. If you do this correctly, you should hit 4 seconds on the X axis.