A transformer is connected to 2200 V,40 Hz supply. The core-loss is 800 watts out of which 600 watts are due to hysteresis and the remaining eddy current losses. Determine the core-loss f the supply voltage and frequency are 3300 V and 60 Hz. 900 W 1300 W 1200 W 1350 W

Answer:

  0°

Explanation:

The resistor voltage has the same phase as the circuit current. There is no phase difference.

Answer:

Explanation:

To calculate the final grade, create a spreadsheet in Excel, enter assignment names and points, assign weights to exams, and use formulas to calculate grades. Adjusting the exam weight will automatically update the final grades.

To calculate the final grade for a student that allows you to change the weight given to exams, follow these steps:

To change the weight given to exams, change the value in cell C1. The values in column C will be recalculated automatically. The final grades in column G will also be updated.

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Answer:

The answer is "the last choice"

Explanation:

The flowchart to this question can be defined in the attached file.

Answer:

D

Explanation:

Only size 1 arrays can be converted to Python scalars in linear regression when you are trying to make predictions using the model you have built. This means that when you have an array with only one element in it, you can convert that element to a scalar value in Python.

For example, if you have an array with the value [5], you can convert it to a scalar value of 5 in Python using the following code:

```python
import numpy as np

# Create an array with one element
arr = np.array([5])

# Convert the array to a scalar value
scalar = arr.item()

# Print the scalar value
print(scalar)
```

This will output the scalar value 5.

In linear regression, you often need to make predictions using the model you have built. If you have an array with only one element in it, you can convert that element to a scalar value in Python to make a prediction. For example, if you have built a linear regression model and you want to make a prediction for the value 5, you can convert the array [5] to a scalar value and then use that scalar value to make a prediction using the model.

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James’s fixed cost is AUD 73,000 and average fixed cost is AUD 1.3036 per liter. James’s variable cost is AUD 40,000 per month and average variable cost is AUD 0.7143 per liter . There will be no accounting profit and economic profit for the month of January instead there will be loss.

James's fixed costs consist of the rental earnings from his premises, which is AUD 3,000 per month, the cost of the milk truck (AUD 40,000), milk stainless cans (AUD 20,000), and milk cooler (AUD 10,000). Therefore, the total fixed cost is AUD 3,000 + AUD 40,000 + AUD 20,000 + AUD 10,000 = AUD 73,000. The average fixed cost can be calculated by dividing the total fixed cost by the quantity of milk produced per month. In this case, the average fixed cost would be AUD 73,000 / 56,000 liters = AUD 1.3036 per liter.

The variable cost is represented by the expenditure on 2-litre milk packs, which is given as AUD 40,000 per month. The average variable cost can be calculated by dividing the variable cost by the quantity of milk produced per month. In this case, the average variable cost would be AUD 40,000 / 56,000 liters = AUD 0.7143 per liter.

To calculate James's accounting profit for January, the revenue from milk sales needs to be determined. Assuming the price of milk is AUD 2 per liter, the revenue can be calculated by multiplying the quantity of milk produced (56,000 liters) by the selling price (AUD 2). Therefore, the revenue for January would be AUD 2 * 56,000 liters = AUD 112,000.

James's accounting profit can be calculated by subtracting the total cost (fixed cost + variable cost) from the revenue. In this case, the accounting profit would be AUD 112,000 - (AUD 73,000 + AUD 40,000) = AUD -1,000.

To calculate James's economic profit, the opportunity cost of using his own premises needs to be considered. Since James was earning AUD 3,000 per month from rental, this amount needs to be deducted from the fixed cost. Therefore, the economic profit would be AUD -1,000 - AUD 3,000 = AUD -4,000.

Overall, James's accounting profit for January is AUD -1,000, and his economic profit is AUD -4,000. These figures indicate that the business is incurring losses for the month of January.

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Answer:

Gently push the micropipette into the tip box and tag tightly to load the tip.

Explanation:

The recommended practice when putting a tip on a micropipette is ;  Gently push the micropipette into the tip box and tag tightly to load the tip.

Given that it is not advisable to remove tip from rack so as not to contaminate it, if we want to put a tip on a micropipette we should gently push the micropipette into the tip box.

Answer:

Some ways that an operations manager may alter operations to meet customer demand include understanding who the customer is (this could be conducted through surveys and feedback opportunities for the customer) and making stock demand be more efficient to meet customer demand.

Incomplete question. However, I inferred you referring to the online article "How automakers can survive the self-driving era."

Explanation:

According to the article, as a result of the perceived demand for autonomous cars in the next few years, this has led to a heightened desire among commercial carmakers to develop driverless technology.

For example, carmakers such as Audi, Toyota have stated projections about the commercial availability of driverless cars.

The most important characteristic of a systems analyst is being a problem solver.

A system analyst is charged with the responsibility of analysing and solving problems related to computer systems. Hence, it is required to have a good problem solving skill in other to excel in this domain.

Programming skills are good for analysts but not so important. They can work with programmers for code implementation to solve problems but they do not need to be able to code on their own.

Therefore, a system analyst must have good problem solving skill.

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Answer:

a) Density of the road segment

i) Before bus strike = 23.02 pc/mi/In

ii) after bus strike = 25.76 pc/mi/In

b) Volume to capacity ratio

i) Before bus strike = 0.69

ii) After bus strike = 0.78

C) level of service of the upgrade segment

i) Before bus strike = LOS C

ii) after bus strike = LOS D

Explanation:

a) Density of the road segment

i) before bus strike ( D1 )

 D1 = 1662 / 72.18  = 23.02 pc/mi/In

ii) After bus strike ( D2 )

D1 = 1859 / 72.18 = 25.76 pc/mi/In

b) Volume to capacity ratio

i) Before bus strike ( v 1 )

V1 = 1662 / 2400 = 0.69

ii) After bus strike ( V2 )

V2 = 1859 / 2400 = 0.78

C) level of service of the upgrade segment  ( Gotten from " LOS Criteria for basic freeway segments " )

i) Before bus strike =  ( LOS C )

ii) After bus strike  = LOS D

Attached below is the detailed solution to the question above

Answer:

c. an initial condition specifies the temperature at the start of the problem and a boundary condition provides information about temperatures on the boundaries.

Explanation:

Conduction refers to the transfer of thermal energy or electric charge as a result of the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.

In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.

Any material or object that allow the conduction (transfer) of electric charge or thermal energy is generally referred to as a conductor. Conductors include metal, steel, aluminum, copper, frying pan, pot, spoon etc.

Hence, the difference between an initial condition and a boundary condition for conduction in a solid is that an initial condition specifies the temperature at the start of the problem and a boundary condition provides information about temperatures on the boundaries.

The standard trie for the given set of strings is shown attached.

A typical trie refers to a hierarchical data structure, primarily utilized to house a collection of strings. The trie consists of nodes that symbolize individual characters present in a given string. The offspring of a particular junction signify the viable succeeding characters in a sequence. The trie's foliage embodies the strings that it contains.

The strings in the trie displayed are arranged alphabetically for storage. The starting point of the tree symbolizes a blank character. The initial offshoot of the main node serves as a symbol for the letter "a". The 'c' character is represented by the second offspring of the parent node. The offspring of the character nodes are the sequences that commence with that specific character.

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Answer:

The following description of the problem is provided.

Explanation:

Passive continental margins are characterized by three major features, which are sedimentary deposits, broad continental shelves, and a lack of tectonic activity.

Firstly, sedimentary deposits are a major feature of passive continental margins, as they accumulate over time due to erosion and sedimentation processes.
Secondly, broad continental shelves are another major feature of passive continental margins, as they are typically wide and gently sloping. These shelves are formed by the deposition of sediments, which can be transported from nearby rivers or eroded from the adjacent continental landmass.
Lastly, a lack of tectonic activity is a defining feature of passive continental margins. Unlike active continental margins, which are located at plate boundaries and experience intense tectonic activity, passive margins are located within a single tectonic plate and experience relatively little deformation or seismic activity.

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Answer:

Tradicionalmente, se han distinguido 5 tipos de mantenimiento, que se diferencian entre sí por el carácter de las tareas que incluyen:

Explanation:

Mantenimiento Correctivo: Es el conjunto de tareas destinadas a corregir los defectos que se van presentando en los distintos equipos y que son comunicados al departamento de mantenimiento por los usuarios de los mismos.

Mantenimiento Preventivo: Es el mantenimiento que tiene por misión mantener un nivel de servicio determinado en los equipos, programando las intervencions de sus puntos vulnerables en el momento más oportuno. Suele tener un carácter sistemático, es decir, se interviene aunque el equipo no haya dado ningún síntoma de tener un problema.

Mantenimiento Predictivo: Es el que persigue conocer e informar permanentemente del estado y operatividad de las instalaciones mediante el conocimiento de los valores de determinadas variables, representativas de tal estado y operatividad. Para aplicar este mantenimiento, es necesario identificar variables físicas (temperatura, vibración, consumo de energía, etc.) cuya variación sea indicativa de problemas que puedan estar apareciendo en el equipo. Es el tipo de mantenimiento más tecnológico, pues requiere de medios técnicos avanzados, y en ocasiones, de fuertes conocimientos matemáticos, físicos y/o técnicos.

Mantenimiento Cero Horas (Overhaul): Es el conjunto de tareas cuyo objetivo es revisar los equipos a intervalos programados bien antes de que aparezca ningún fallo, bien cuando la fiabilidad del equipo ha disminuido apreciablemente de manera que resulta arriesgado hacer previsiones sobre su capacidad productiva. Dicha revisión consiste en dejar el equipo a Cero horas de funcionamiento, es decir, como si el equipo fuera nuevo. En estas revisiones se sustituyen o se reparan todos los elementos sometidos a desgaste. Se pretende asegurar, con gran probabilidad un tiempo de buen funcionamiento fijado de antemano.

Mantenimiento En Uso: es el mantenimiento básico de un equipo realizado por los usuarios del mismo. Consiste en una serie de tareas elementales (tomas de datos, inspecciones visuales, limpieza, lubricación, reapriete de tornillos) para las que no es necesario una gran formación, sino tal solo un entrenamiento breve. Este tipo de mantenimiento es la base del TPM (Total Productive Maintenance, Mantenimiento Productivo Total).

A bend is defined as a change in the shape of the part between the damaged and undamaged area that is smooth and continuous.

What is a kink?

A kink can be defined as a sharp bend with a small radius over a short distance.

So when any part is kinked it must be replaced without any doubt. A part is kinked if it just doesn't work on the repair.

What is a bend?

Unlike a kink, a bend can be restored. That is after a bend also  a part can be bought back to its original position.

When the part is straightened, it is returned to proper shape and state without any areas of permanent deformation.

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Answer:

u do the same thing as part B but only add 100 k, I think, cuz I'm still in middle school but I mean if u see it asks u to do the same thing as B but C says that instead, u do it at half pressure and 100 k is higher temp so what its asking is to repeat b but the twist is u do it at half pressure and 100 k is the higher temp

hope this helps :)  

Option C. Small service desks are effective if the service desk has a broad scope of responsibilities.

Small service desks can be effective if they have a broad scope of responsibilities. This is because having a wide range of responsibilities allows them to provide excellent customer service. They can be more efficient and responsive to customer needs and can manage a larger volume of calls and inquiries. This is especially true if the service desk is well-trained and equipped with the right tools and resources. Furthermore, having a small service desk can be cost-effective since it requires fewer staff and resources. Additionally, small service desks can provide world-class service if they have satisfied customers and have the right processes and procedures in place. By having a broad scope of responsibilities, small service desks are able to offer customers the best possible service, making them an effective and efficient choice.

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Answer:

The goal of the software is to observe the software behavior to meet its requirement expectation. In software engineering, validating software might be harder since client's expectation may be vague or unclear.

Explanation:

Allen made a Venn diagram to compare radiation and conduction. The diagram shows two intersecting circles, with the left circle labeled radiation, the right circle labeled conduction.

The overlapping region between the two circles is labeled "Y."The label that belongs in the area marked Y is "Occurs when molecules are in direct contact."Conduction occurs when molecules are in direct contact with each other. When two objects or substances are in contact, energy flows from the hotter object to the cooler object until both objects are at the same temperature.Radiation, on the other hand, does not require matter to transfer energy.

It involves the transfer of energy in the form of waves or particles through a vacuum or a transparent medium. Radiation is the transfer of heat from one body to another in the form of waves or rays.Most of the time, radiation and conduction occur at the same time. A good example of this is the transfer of heat through a metal pot. In this case, the heat from the burner is transferred to the metal pot through conduction, and then it is transferred to the food inside the pot through radiation.

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Answer:

about half a pound i think

Explanation:

Answer:

The answer is below

Explanation:

Given that:

\(k_t=torque\ constant=0.075\ Nm/A\\\\k_v=voltage\ constant=0.12\ V/(rad/sec)\\\\R_a=armature \ resistance=2.5 \Omega\\\\V_t=terminal\ voltage=24\ V\\\\a)The \ starting\ current\ I_a\ is\ given \ as:\\\\I_a=\frac{V_t}{R_a} =\frac{24}{2.5} =9.6\ A\\\\The \ starting\ torque(T)\ is:\\\\T=k_tI_a=0.075*9.6=0.72\ N.m\)

b) The maximum speed occurs when the terminal voltage and back emf are equal to each other i.e.

\(V_t=e_b=k_v\omega\\\\\omega=\frac{V_t}{k_v}=\frac{24}{0.12} =200\ rad/s\)

c) The load torque is given as:

\(T_L=0.0125\Omega\\\\The\ motor\ torque \ is:\\\\T=k_t(\frac{V_t-k_v\omega}{R_a} )\\\\but\ T = T_L,hence:\\\\0.0125\omega=0.075(\frac{24-0.12\omega}{2.5} )\\\\0.03125\omega=1.8-0.009\omega\\\\0.04025\omega=1.8\\\\\omega=44.72\ rad/sec\\\\N=\frac{60\omega}{2\pi} =\frac{60*44.72}{2\pi} =427\ rpm\)

The correct answer is Susceptibility, Vulnerability, and Recoverability should be used as the three objective criteria for measuring system survivability.

To address society's evolving needs for fire detection, signaling, and emergency communications, NFPA 72 offers the most recent safety regulations. In conclusion, NFPA 72 defines survivability as the capacity of the fire alarm circuit to continue operating effectively even when it is being attacked by fire.According to NFPA 72, the fire alarm system might be the typical system of initiating and notification devices. A voice/alarm emergency communication system must be built in compliance with NFPA 72 Chapter 24 for any Group 3 occupancy of 100 or more.

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Answer:

375 KPa

Explanation:

From the question given above, the following data were obtained:

Initial pressure (P₁) = 125 KPa

Initial temperature (T₁) = 300 K

Final temperature (T₂) = 900 K

Final pressure (P₂) =?

The new (i.e final) pressure of the gas can be obtained as follow:

P₁/T₁ = P₂/T₂

125 / 300 = P₂ / 900

Cross multiply

300 × P₂ = 125 × 900

300 × P₂ = 112500

Divide both side by 300

P₂ = 112500 / 300

P₂ = 375 KPa

Thus, the new pressure of the gas is 375 KPa

When hydraulic fluid is released upon depressing the air valve core of an accumulator, it serves as evidence of a compromised bladder, diaphragm, or piston separating the gas and hydraulic sections within the accumulator.

Accumulators are essential components in hydraulic systems that store energy by compressing a gas, usually nitrogen, to maintain a desired pressure level. They provide various functions such as energy storage, pressure regulation, and shock absorption. The separator, whether a bladder, diaphragm, or piston, ensures that the gas and hydraulic fluid remain isolated from one another.

If the separator becomes damaged or ruptured, the hydraulic fluid may leak into the gas side of the accumulator. Consequently, when the air valve core is depressed, the hydraulic fluid is released instead of the expected gas. This situation indicates that maintenance or replacement of the separator is required to restore the proper functioning of the accumulator and ensure the efficiency and safety of the hydraulic system.

In summary, the release of hydraulic fluid when depressing the air valve core of an accumulator is evidence of a compromised separator, necessitating immediate inspection and corrective measures to maintain optimal system performance.

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The absolute pressure in psia being measured is; 27.228 psia

Formula for absolute Pressure is;

Absolute pressure = Atmospheric pressure + Gauge pressure

P_{abs} = P_{atm} + P_g

We are given;

P_atm = 29.86 (in Hg) = 14.666 psia

Density of mercury at 70 °F; ρ = 13.543 g/cm³

Mercury Manometer reading; h = 25.62 in

Acceleration due to gravity; g = 32.243 ft/s²

Gauge pressure of the mercury = ρgh = 13.543 * 25.62 * 32.243

When we multiply and covert to psia gives; P_g = 12.562 psia

Thus;

P_abs = 14.666 + 12.562

P_abs = 27.228 psia

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scale is used to make a scale drawing. every scale drawing has it's sclae written for proper interpreatation

A Scale is the ratio of a sketched model and the actual measuremnts while a scale drawing is a sketched model that was carefully made such that every measurement in the sketch could be represented to the site or actual mearuement through the scale with very little or no error

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To make a scale drawing, scale is used. For correct interpretation, every scale drawing has its own scale inscribed on it.

A scale drawing is a sketched model that has been meticulously prepared so that every measurement in the sketch may be conveyed to the site or actual measurement through the scale with very little or no mistake.

A weighing apparatus or equipment with two pans of equal weight hung from its ends —usually used in the plural, either pan or tray of a balance scale.

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A V-8 engine that posses a firing order of 18436572 with number 1 cylinder on compression, the cylinder which would be on the exhaust stroke is number: A. 6.

An injector can be defined as a mechanical device that is designed and developed for the introduction of fuel into the internal combustion system of an engine, especially under pressure.

In Engineering, there are two (2) main types of fuel injection system and these include the following:

A sequential fuel injection is typically designed and developed to spray fuel into the internal combustion system of an engine based on the firing order that is configured within it by the manufacturer.

As a general rule, one of the two-paired spark plugs within the internal combustion system of an engine is always designed to have a negative polarity while the other spark plug is designed to have a positive polarity always.

In this context, we can infer and logically deduce that a V-8 engine that posses a firing order of 18436572 with number 1 cylinder on compression, the cylinder which would be on the exhaust stroke is number 6.

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Complete Question:

The coil polarity in a waste-spark system is determined by the direction in which the coil is wound (left-hand rule for conventional current flow) and can't be changed. for example, if a v-8 engine has a firing order of 18436572 and number 1 cylinder is on compression, which cylinder will be on the exhaust stroke?

A. 6

B. 4

C. 8

D. 2

probably in it's chromosomes