a spring has a natural length of 16 cm. if a 23 n force is required to keep it stretched to a length of 28 cm, how much work w (in j) is required to stretch it from 16 cm to 22 cm? (round your answer to two decimal places.)

Answer:

h = 200 m

Explanation:

Given that,

A chocolate bar has a nutritional energy content of 100 kJ.

Mass of a mountain climber, m = 50 kg

He eats this chocolate bar and converts it all to potential energy. Using the conservation of energy.

\(E=mgh\\\\h=\dfrac{E}{mg}\\\\h=\dfrac{100\times 10^3}{50\times 10}\\\\h=200\ m\)

So, she can climb from a height of 200 m.

Answer:

Temperature is also a condition that affects the speed of sound. Heat, like sound, is a form of kinetic energy. Molecules at higher temperatures have more energy, thus they can vibrate faster. Since the molecules vibrate faster, sound waves can travel more quickly.

Option-1,3 1. Not monochromatic sources. - interference is due to two monochromatic sources,3. observed from a distance similar to or smaller than the separation between the sources. -

Monochromatic radiation is electromagnetic radiation having a single, fixed frequency in physics. The term monochromatic light is frequently used when that frequency is a component of (or close to) the visible spectrum. The human eye recognizes spectral color in monochromatic light.

Monochromatic radiation has a single wavelength that never changes when it moves through a vacuum or a uniform transparent medium.

Because of the Fourier transform's localization property, no radiation can be completely monochromatic because that would need a wave with an endless length (cf. spectral coherence). Even from lasers or spectral lines, "monochromatic" radiation in reality always consists of components with a range of frequencies of non-zero breadth.

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There is a total of 4 rock bands playing simultaneously at this level to have a pain threshold of (120dB).

The decibel (dB) is a logarithmic unit used to measure sound intensity. Each 10 dB increase in sound intensity corresponds to a 10-fold increase in sound power. Therefore, since the pain threshold is 120 dB, a 10 dB increase from 106 dB is equal to a 10-fold increase in sound power.

Since each individual band is already producing 106 dB, the 10 dB increase would require 4 bands (a 10-fold increase) to reach the pain threshold.

This is because a 10 dB increase from 106 dB would bring the total sound intensity to 116 dB, and a further 4 dB would be required to reach the pain threshold of 120 dB.

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Answer:

(a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Explanation:

Given that,

Top speed = 415 km/h

1 miles = 1609 m

(a). We need to calculate the speed in m/s

Using conversion of km/h to m/s

\(v=415\ km/h\)

\(v=415\times\dfrac{5}{18}\)

\(v=115.28\ m/s\)

(b). We need to calculate the distance from London to Edinburgh in km

Using conversion for distance

\(d=403\ miles\)

Distance in meter,

\(d=403\times1609\)

\(d=648427\ m\)

\(d=648.427\ km\)

We need to calculate the time

Using formula of time

\(t=\dfrac{d}{v}\)

Put the value into the formula

\(t=\dfrac{648.427}{415}\)

\(t=1.56\ h\)

\(t=1\ hours 34\ min\)

\(t= 94\ min\)

(c). Speed v' =7.66 km/s

v'=7660 m/s

In the time it takes the car to travel from London to Edinburgh,

We need to calculate the distance

Using formula of distance

\(d'=v'\times t\)

Put the value into the formula

\(d'=7660\times94\times60\)

\(d'=43202400\ m\)

\(d'=43202.400\ km\)

(d). Speed :

Speed is equal to the distance divided by time.

It is scalar quantity.

Velocity :

Velocity is equal to the displacement divided by time.

It is vector quantity.

Hence, (a). The speed is 115.28 m/s.

(b). The time is 94 min.

(c). The International Space Station travels 43202.400 km.

(d). Speed is scalar quantity.

Velocity is vector quantity.

Answer:

but for which activity donu need the answer and mention the question clearly

The heat output per cycle of the engine of efficiency 0.52 that performs a useful work of 780 J is 1500 J.

Heat Output means the total useful heat energy recovered from the combustion turbine as heat.

To calculate the heat output of the engine, we use the Carnot law formula.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for Q'

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Answer:

\(f_n_e_t=0\)

Explanation:

\(f_1+f_2=f_n_e_t\)

because there are two different forces in different directions (left: negative, right: positive, down: negative, up: positive) so 60N left will be negative, and 60N right will be positive:

\(60+(-60)=0\)

when two same forces apllied then the net force is zero.

The probability density function of X is plotted for a=1/2 and a=2.

The expected value of X (E[X]) is determined.

The expected value of 1/X (E[1/X]) is determined.

The variance of X (V[X]) is determined.

The median of X is determined.

When a=1/2, the probability density function of X is given by p(X=x∣a)=((1/2)+1)x(1/2)^0=(3/2)x for x∈[0,1]. When a=2, the probability density function becomes p(X=x∣a)=(2+1)x^2=3x^2 for x∈[0,1]. To plot the probability density function, we can assign different values of x within the range [0,1], calculate the corresponding probabilities using the given formulas, and plot the points on a graph.

The expected value of X (E[X]) is calculated by integrating the product of X and its probability density function over the range [0,1]. For a=1/2, E[X] = ∫(x * (3/2)x) dx from 0 to 1. For a=2, E[X] = ∫(x * 3x^2) dx from 0 to 1. By evaluating these integrals, we can determine the expected values.

The expected value of 1/X (E[1/X]) is calculated similarly to E[X], but instead of integrating X, we integrate 1/X using the respective probability density functions for different values of a.

The variance of X (V[X]) can be computed by taking the second moment of X (E[X^2]) minus the square of the first moment (E[X]) squared. V[X] = E[X^2] - (E[X])^2. By calculating E[X^2] using the probability density function and the expected values obtained in step 2, we can determine the variances for different values of a.

The median of X is the value of X such that the cumulative distribution function (CDF) is equal to 0.5. To find the median, we integrate the probability density function from 0 to the median value and set it equal to 0.5. Solving for the median provides its value in terms of the parameter a.

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The height reached by the two carts after collision is determined as 5.34 m.

Apply the principle of conservation of mechanical energy.

K.E = P.E

v = √2gh

v = √(2 x 9.8 x 12)

v = 15.34 m/s

Apply the principle of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

8(15.34) + 4(0) = v(8 + 4)

122.72 = 12v

v = 10.23 m/s

Apply the principle of conservation of mechanical energy.

P.E = K.E

mgh = ¹/₂mv²

h = v²/(2g)

h = (10.23²) / (2 x 9.8)

h = 5.34 m

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The voltage drop along the length of the metal bar, when it carries a 4000 A current, is 0.134 V.

The voltage drop (ΔV) along a conductor can be calculated using Ohm's law, which states that the voltage drop is equal to the product of the current (I) and the resistance (R):

ΔV = I * R

In this case, the current (I) is 4000 A. To calculate the resistance (R), we need to use the formula:

R = (ρ * L) / A

where ρ is the resistivity of the metal, L is the length of the bar, and A is the cross-sectional area of the bar.

Given that the resistivity (ρ) is 1.68 × 10⁻⁸ Ω ∙ m, the length (L) of the bar is 20 cm or 0.2 m, and the cross-sectional area (A) is (1.0 cm) * (2.0 cm) = 2.0 cm² or 2.0 × 10⁻⁴ m².

Substituting the values into the resistance formula, we have:

R = (1.68 × 10⁻⁸ Ω ∙ m * 0.2 m) / (2.0 × 10⁻⁴ m²)

R = 1.68 × 10⁻⁴ Ω

Now, we can calculate the voltage drop

ΔV = (4000 A) * (1.68 × 10⁻⁴ Ω)

ΔV = 0.134 V.

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Answer:

15 m/s

Explanation:

Given:

F = 0.7N   m = 0.25g = 0.0025kg   x = 40cm = 0.4m \(v_{0}\) = 0

Since F = ma, a = F/m = 0.7N/0.0025kg = 280m/\(s^{2}\)

Using the Big Five, \(v ^{2} = v_0^{2} + 2ax\), \(v = \sqrt{0 + 2*280m/s^2*0.4m} = \sqrt{216} m/s= 15m/s\)

We have that for the Question it can be said that  the speed of the marshmallow as it leaves the pipe is most nearly

v=15m/s

From the question we are told

A 2.5 g marshmallow is placed in one end of a 40 cm pipe, as shown in the figure above. A person blows into the left end of the pipe to eject the marshmallow from the right end. The average net force exerted on the marshmallow while it is in the pipe is 0.7 N. The speed of the marshmallow as it leaves the pipe is most nearly

Generally the equation for the acceleration  is mathematically given as

\(a=\frac{Force}{mass}\\\\a=\frac{F}{m}\\\\Therefore\\\\a=\frac{0.75}{0.0025}\\\\a=280m/s^2\\\\\)

Using Newtons

V^2=u^2+2as

V^2=2(280)*0.4

v=15m/s

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Answer:

Potential energy

Explanation:

Potential energy is stored energy and the energy of position––gravitational energy. There are several forms of potential energy. Electrical Energy is the movement of electrical charges. Everything is made of tiny particles called atoms.

- Scientific Forms of Energy_ Stored Energy, Kinetic Energy ...ei.lehigh.edu › learners › energy › readings › energy_basics

First, find the weight of the object.

W = m g = 900 x 9.8 = 8,820 N

T2x = -t2 cos 20

t1 x = t1cos 40

mgx= 0

T2y= t2 sin 20

t1y= t1 sin 40

mgy= - mg

X and y components of resultant (R)

Rx = t1x -t2x + mgx

Rx= -t2 cos 20 + t1cos 40 (3)

Ry = t2 sin 20 + t1 sin 40 - mg(2)

Rx, and Ry = 0

0 = -t2 cos 20 + t1cos 40 (3)

0= t2 sin 20 + t1 sin 40 - mg (4)

Solve (3)

0 = -t2 cos 20 + t1cos 40

t2 cos 20 = t1 cos 40

t2 = t1 cos40/cos20

t2 = 0.815 t1

Substitute t2 in 4

0 = t2 sin 20 + t1 sin 40 - mg

0 = (0.815 t1) sin 20 + t1 sin 40 - 8,820

0= t1 ( 0.815 sin 20 + sin 40 ) -8820

0 = 0.921 t1 -8820

8820 = .921 t1

t1 = 8820/0.921

t1= 9570.261N (option D)

Answer:

2,200

Explanation:

truck=35800,car=33600

Hi there!

Because of Newton's Third Law, the force exerted by the sprinter on the track is equal and opposite to the force exerted by the track on the sprinter.

We can begin by calculating the sprinter's acceleration. Use the equation:

vf² = vi² + 2ad

Rearrange for acceleration:

(vf² - vi²)/2d = a

Plug in values:

(8² - 2²)/2(2.5) = 60/5 = 12 m/s²

Calculate the force:

∑F = ma

∑F = 60 × 12 = 720 N. This is the amount of force exerted by the track on the sprinter in causing him to accelerate forward.

Thus, the backward force exerted by the sprinter on the track is the opposite, or -720 N.

Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.

There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.

Part 2: Determining whether the circuit is series or parallel requires more information.

In a series circuit, components are connected in a single path, and the current flows through each component sequentially.

If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.

However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.

To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.

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The final speeds of both cars relative to the ground after the collision are V₁ = 6 m/s and V₂ = 5.6 m/s respectively.

An elastic collision is a collision in which there is no internet loss in kinetic energy within the gadget because of the collision. each momentum and kinetic electricity are conserved portions in elastic collisions.

Given;

m₁ = m₂ = 400 kg

v₁ = 5.6 m/s

v₂ = 6 m/s

According to the law of conservation of momentum,

m₁v₁ + m₂v₂ = m₁v₁ + m₁v₂

According to the law of conservation of energy,

m(v₁)²/2 + m(v₁)²/2 = m(v₁)²/2 + m(v₁)²/2

Now, applying the law to momentum and law of conservation of energy,

m₁v₁ + m₂v₂ = m₁v₁ + m₁v₂

5.6 + 6 = v₁ + v₂ ----------------(1)

m(v₁)²/2 + m(v₁)²/2 = m(v₁)²/2 + m(v₁)²/2

(5.6)² + (6)² = (v₁)² + (v₂)²

67.36 =   (v₁)² + (v₂)² ---------------(2)

From equation 1 and 2

V₁ = 6 m/s and V₂ = 5.6 m/s

An elastic collision is a come between two bodies in which the full kinetic energy of the two bodies remains equal. In an ideal, perfectly elastic collision, there may be no internet conversion of kinetic strength into other kinds which includes heat, noise, or capacity electricity.

Elastic collisions arise whilst both the momentum and kinetic energy are conserved, just like how billiard balls bounce off each different and move at the same speeds as earlier. Inelastic collisions appear whilst simplest the momentum is conserved but not the kinetic power.

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Answer:

D. OJ

Explanation:

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

E = kq/r²

where;

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

F = Eq

where;

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

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The displacement of 20 miles is the straight-line distance in the Southwest direction from the starting point whereas the distance of 70 m is the total distance along the path of travel.

Distance is the actual distance that a body travels. Additionally known as path length. As an illustration, the path length for an object going from point O to point A will be distance OA = 30 m. It is a scalar quantity, the distance.

Displacement is the change in an object's position in relation to a reference frame. It is a vector quantity with both magnitude and direction.

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The luminosity or absolute brightness of a star depends on its size, temperature, and age. A larger star will have a greater luminosity than a smaller one, as it has more surface area to emit light from.

Similarly, a hotter star will have a greater luminosity than a cooler one, as hotter stars emit more light per unit surface area. The age of a star also affects its luminosity, as younger stars are brighter than older stars. This is because younger stars are still fusing hydrogen into helium in their cores, producing energy and generating a greater luminosity. As a star ages, it exhausts its fuel and becomes less luminous.

Understanding the factors that affect a star's luminosity is crucial in astronomy, as it can provide valuable information about the star's properties and evolutionary stage. By studying a star's luminosity, scientists can learn about its size, temperature, and age, and gain insight into the complex processes that govern the lives of stars.

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Answer:

1500 J

Explanation:

Work = force * distance   =  50 N * 30 M = 1500 J

When a Carnot heat engine is operated in reverse as a Carnot refrigerator, the roles of heat input and heat output are reversed.

In other words, instead of converting heat into work, the Carnot refrigerator uses work to transfer heat from a low-temperature reservoir to a high-temperature reservoir. The thermal efficiency of a Carnot refrigerator is given by the equation: Efficiency = (Heat extracted from the low-temperature reservoir) / (Work input)

Since the Carnot heat engine and the Carnot refrigerator are reversible and operate between the same temperature reservoirs, the efficiencies of both processes are equal. Therefore, if the Carnot heat engine has a thermal efficiency of 1717, the Carnot refrigerator also has the same thermal efficiency of 1717. This means that for every unit of work input, the Carnot refrigerator can extract 1717 units of heat from the low-temperature reservoir.

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Answer:

melt

Explanation:

hope it helps you plz mark me brilliantest

Answer:

i think E hola

Explanation:

I dont know

The statement that describes the mass-energy equivalence is that mass-energy can be created or destroyed. Thus, option B is correct.

The mass-energy equivalence gives the relation between mass and energy in the rest frame. This relation was given by Albert Einstein. Energy and mass are directly proportional to each other. Energy can be converted into mass and the mass of the body is converted into energy. Thus, the mass and energy can either be created or destroyed.

The mass-energy equivalence, E = mc², where E is the energy, m is the mass and c is the speed of light. Thus, the mass-energy equivalence states that mass energy can be created or destroyed.

Thus, the ideal solution is option B.

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L, the number of samples, is 8, The frequency spacing in Hz is 31.25 Hz, (a) L² = 64 multiplications  using the definition of the DFT, (b) L log₂(L) = 24 multiplications, (c) 256 log₂(256) = 4096 multiplications

To find the value of L, we divide the duration of the portion of the analog signal (128 ms) by the sampling rate (8 kHz). L = (128 ms) × (8 kHz) = 8.

The frequency spacing in Hz of the computed DFT values is calculated by dividing the sampling rate by the number of points in the DFT. In this case, the DFT is a 256-point DFT, so the frequency spacing is (8 kHz) / 256 = 31.25 Hz.

The total number of required multiplications depends on the method used to compute the DFT.

(a) If the computations are done directly using the definition of the DFT, each sample needs to be multiplied by every other sample, resulting in L² multiplications. In this case, L = 8, so L² = 64 multiplications.

(b) If the L samples are first wrapped modulo 256 and then the 256-point DFT is computed, the total number of multiplications can be reduced. The wrapped samples result in periodicity, allowing for a more efficient computation. The total number of multiplications is given by L log₂(L), where L = 8. Therefore, L log₂(L) = 8 log₂(8) = 24 multiplications.

(c) If a 256-point FFT is computed of the wrapped signal, the number of multiplications is further reduced. The total number of multiplications for an FFT of size N is given by N log₂(N). In this case, N = 256, so the total number of multiplications is 256 log₂(256) = 4096 multiplications.

Therefore, the total number of required multiplications is 64 for direct computation using the DFT definition, 24 if the samples are first wrapped modulo 256 and then computed, and 4096 for a 256-point FFT of the wrapped signal.

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The tension on the left wire 642N and the tension on right wire is 208N

Given that the force of scaffold is 200- N and the length of the scaffold is 18m

We need to find the tension in each wire

Tension Force is the force that is transmitted through a cable, rope, wire or string when it is pulled tight by forces acting from opposite ends

Here

∑ \(T_b=0\)

∴ \(W_B(15m)+W_S(9m)-T_L(18m) = 0\)

∴ \(T_L = \frac{W_B(15m)+W_S (9m)}{18m}\\ T_L = \frac{650(15)+200(9)}{18}\\ T_L = 642 N\)

Hence the tension on the left side is 642N

∑\(T_a\) = 0

\(T_R(18m)-W_B(3m)-W_S(9m)=0\)

∴\(T_R =\frac{W_B(3m)+W_S(9m)}{18m}\)

∴\(T_R = \frac{650(3)+200(+9)}{18}\\\)

∴\(T_R = 208N\)

Hence the tension on the right side is 208N

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The diagram is best showing the process of photosynthesis.

During photosynthesis, plants absorb light energy and carbon dioxide and use these to produce glucose (a type of sugar) and oxygen. The diagram shows the inputs and outputs of this process, with carbon dioxide and water being converted into glucose and oxygen, and light energy being absorbed to drive this process.

Photosynthesis is the process by which plants and some other organisms convert light energy into chemical energy in the form of glucose. The steps of photosynthesis can be summarized as follows:

Light absorption: Chlorophyll and other pigments in the chloroplasts of plant cells absorb light energy from the sun.

Conversion of light energy: The absorbed light energy is converted into chemical energy, which is used to power the next steps of photosynthesis.

Water splitting: Water molecules are split into oxygen gas (O2) and hydrogen ions (H+), releasing electrons in the process.

Electron transport: The released electrons are transferred through a series of protein complexes in the thylakoid membrane of the chloroplast, creating a proton gradient across the membrane.

ATP synthesis: The proton gradient is used to generate ATP (adenosine triphosphate), a molecule that stores energy.

Carbon fixation: Carbon dioxide (CO2) from the atmosphere is fixed into an organic molecule, usually through the Calvin cycle, which uses ATP and the hydrogen ions generated in step 3.

Glucose synthesis: The fixed carbon is used to synthesize glucose, a type of sugar that can be used by the plant for energy or stored for later use.

Oxygen release: The oxygen gas produced in step 3 is released into the atmosphere as a byproduct of photosynthesis.

Overall, the process of photosynthesis can be summarized by the equation:

6 CO2 + 6 H2O + light energy → C6H12O6 + 6 O2

where CO2 is carbon dioxide, H2O is water, C6H12O6 is glucose, and O2 is oxygen.

Hence, The diagram is showing the process of photosynthesis.

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