A SONET STS-12 Data link has a data rate of 622.08mb/s. A high fidelity voice channel (10 bits/s sample not 8 bits/s sample) by time division multiplexing on this link, sampling at the nyquist rate. How many complete voice channels can the link handle under these circumstances?

Answers

Answer 1

To calculate the number of complete voice channels that a SONET STS-12 data link can handle, we need to consider the data rate and the sample rate of the voice channel.

Given:

Data rate of SONET STS-12 data link: 622.08 Mb/s

Sample rate of the voice channel: 10 bits/s

To determine the number of voice channels, we need to divide the data rate of the link by the data rate of each voice channel.

First, let's convert the data rate of the SONET STS-12 link to bits per second (bps):

622.08 Mb/s = 622.08 * 10^6 bits/s

Now we can calculate the number of voice channels:

Number of voice channels = (Data rate of link) / (Data rate per voice channel)

Number of voice channels = (622.08 * 10^6 bits/s) / (10 bits/s)

Number of voice channels = 622.08 * 10^6 / 10

Number of voice channels = 62.208 * 10^6

Number of voice channels = 62,208,000

Therefore, the SONET STS-12 data link can handle 62,208,000 complete voice channels under these circumstances.

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Related Questions

What is the transfer function of a filter? What is the transfer function of a filter? The transfer function shows how a filter affects the phase of input components as a function of frequency. It is defined as the output phasor divided by the input phasor as a function of frequency. The transfer function shows how a filter affects the amplitude and phase of input components as a function of frequency. It is defined as the input phasor divided by the output phasor as a function of frequency. The transfer function shows how a filter affects the amplitude and phase of input components as a function of frequency. It is defined as the output phasor divided by the input phasor as a function of frequency. The transfer function shows how a filter affects the phase of input components as a function of frequency. It is defined as the input phasor divided by the output phasor as a function of frequency.

Answers

Answer: Provided in the explanation section

Explanation:

A precise explanation is provided here to make it easy for understanding

(a). The transfer option shows how a filter affects the amplitude and phase of input components as a function of frequency. It is defined as the output phasor divided by the input phasor as a functoon of frequency.

H(jw) = V₀ (jw) / Vin(jw)

(b).  To determine the transfunction of a filter, we connect a sinusoidal source to be the input part, measure the amplitude and phases of both the input signal and resulting output signal using voltmeters.

Oscilloscope or other instruments, and divide the Output phasor by the input phasor. This is is repeated for all frequencies.

cheers i hope this helped !!

Simplify the following using K-Map
05
(a) Z (A,B,C,D) = (0,2,3,6,7,8,9,10,11,12,13,14,15)
(b) F(w.x.y.x) = {3,4,5,7,9,13,14,15)
!!

Answers

Answer:

b

Explanation:

I really need help on this!
Which of the following is a term for a comparison between product metrics and values to industry standards and competitions metrics and values?
A: ideal value
B: competitive analysis
C: benchmark
D: marginally accepted value

Answers

C: benchmark because I have done this before
The answer is D!
Plz mark brainliest

If the yield strength of the aluminium is approximately 280MPa(40,000psi). Calculate the load Py at which the beam begins to yield?

Answers

The load Py at which the aluminum beam begins to yield can be calculated using the yield strength of approximately 280 MPa (40,000 psi).

When a material reaches its yield strength, it means that it has reached the point where it starts to deform permanently under load. In this case, the yield strength of the aluminum is given as 280 MPa. To calculate the load Py at which the beam begins to yield, we need to consider the cross-sectional area of the beam.

Assuming the beam has a uniform cross-section, we can use the formula:

Py = Yield strength × Cross-sectional area

To calculate the cross-sectional area, we need to know the dimensions of the beam, such as its width and height. Once we have the cross-sectional area, we can substitute it into the formula to find the load Py.

It's important to note that this calculation assumes the load is applied uniformly across the entire cross-section of the beam. In real-world scenarios, the distribution of the load and other factors might affect the actual yield point.

the mechanical properties of different materials and how they affect structural calculations by exploring textbooks or engineering references that cover topics such as material science and structural analysis.

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What is the result of 10/4? 1) 3 2) 2.5 3) 2.0 4) 2 What is 2
∗∗
3? 1) 3 2) 2 3) 8 4) 6

Answers

1) The result of 10/4 is 2.5.

2) The result of 2**3 is 8.

1) When dividing 10 by 4, we obtain a decimal result of 2.5. This is because 10 divided by 4 equals 2 with a remainder of 2. The remainder, expressed as a fraction, is 2/4, which simplifies to 0.5. Adding the whole number part (2) and the fractional part (0.5) together gives us the result of 2.5.

2) In the expression 2**3, the double asterisks represent the exponentiation operation. Therefore, 2 raised to the power of 3 is calculated as 2 * 2 * 2, which equals 8. The exponentiation operation denotes repeated multiplication of the base number (2 in this case) by itself, according to the power (3 in this case).

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A 1.5 m x1.5 m square footing is supported by a soil deposit that contains a 16.5 m thick saturated clay layer followed by the bedrock. The clay has μs = 0.50 and Es = 5,000 kN/m2 . The footing base is at 1.5 m below the ground surface. Determine the maximum vertical central column load so that the elastic settlement of the footing will not exceed 50.0 mm. If the square footing is replaced by a 1.2 m wide wall footing with all other conditions remaining the same.

Required:
What will be the elastic settlement under the same footing pressure?

Answers

Answer:

somewhere around 34.2223 meters thick but that's what I am estimating.

Is the impedance of the capacitor purely reactive, and how does it compare to the nominal value of the ideal capacitor? Why or why not is it purely reactive?

Answers

In an electric field, a capacitor is a device that stores electrical energy. It has two terminals and is a passive electrical component. Capacitance refers to a capacitor's effect.

What is the impedance of an ideal capacitor?An perfect capacitor has an infinite resistance. For all frequencies and capacitance levels, the reactance of a perfect capacitor, and consequently its impedance, is negative.A capacitor that has no resistance and therefore doesn't lose any energy while it's operating is the ideal capacitor. It just possesses capacitance. There is no dielectric loss in a perfect capacitor. High temperature stability characterizes the ideal capacitor.As capacitance and frequency increase, capacitive reactance falls. Impedance is the complete opposition that reactance and resistance give.Similar to inductors, the ideal capacitor is a totally reactive device with no resistive (power dissipative) effects whatsoever. Of course, nothing is so flawless in the actual world. Capacitors, however, have the advantage of often being more pure reactive components

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Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit length) that the water exerts on the pier. Assume that the flow can be approximated as an potential fluid flow around the front half of the cylinder, but due to flow seperation, the average pressure on the rea half is constant and approximately equal to 1/2 the pressure at point A.

Answers

Answer: hello the diagram related to your question is missing please the third image is the missing part of the question

Fx = 977.76 Ib/ft

Explanation:

Estimate the force that water exerts on the pier

V = 12 ft/s

D( diameter ) = 6 ft

first express the force  on the first half of the cylinder  as

Fx1 =  - \(-2\int\limits^\pi _\frac{\pi }{2} {Ps*cos\beta *a} \, d\beta\)   ---------------- ( 1 )

where ; Fy = 0

Ps = Po + 1/2 Pv^2 ( 1 - 4 sin^2β )  ------------- ( 2 )

Input equation (2)  into equation ( 1 )         (note :  assuming Po = 0 )

attached below is the remaining part of the solution

Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit
Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit
Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit
Water flows around a 6-ft diameter bridge pier with a velocity of 12 ft/s. Estimate the force (per unit

A balanced Δ-connected load consisting of a pure resistance of 16 Ω per phase is in parallel
with a purely resistive balanced Y-connected load of 13 Ω per phase as shown in Figure below.
The combination is connected to a three-phase balanced supply of 346.41-V rms (line-to-line)
via a three-phase line having an inductive reactance of j3 Ω per phase. Taking the phase
voltage Van as reference, determine
a) The current, real power, and reactive power drawn from the supply.
b) The line-to-neutral and the line-to-line voltage of phase a at the combined load terminals.

Answers

The three-phase line voltage is given as 346.41 Vms

The real power drawn from the supply is given as 19.2kW

What is Line Voltage?

"Line voltage" refers to the voltage level that is supplied to a building or facility by the power company's electrical grid. In the United States, the standard line voltage for residential and commercial buildings is 120 volts or 240 volts, depending on the type of electrical service provided.

Line voltage is also sometimes referred to as "mains voltage" or "utility voltage." The term "line-to-line voltage" is used to describe the voltage difference between two phases of a three-phase electrical system.

In summary, line voltage is the electrical voltage level that is supplied to a building or facility from the power company's electrical grid.

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A balanced -connected load consisting of a pure resistance of 16 per phase is in parallelwith a purely

Using the correlation for the second virial coefficient (Pitzer correlation), find the molar volume of acetylene vapour at 247.1 K and 13.5 bar, giving your answer to the nearest cm3/mol. The critical temperature is 308.3 K and the critical pressure of acetylene is 61.39 bar. Take R = 8.314 J/mol-K and the acentric factor for acetylene is 0.187.

Answers

The molar volume of acetylene vapor at 247.1 K and 13.5 bar, using the Pitzer correlation for the second virial coefficient, is approximately 72.5 cm3/mol.

Explanation:

The Pitzer correlation can be used to estimate the second virial coefficient of a gas. The equation is given by B = (RTc)/(Pc) * (1 + m(1 - (T/Tc)^(0.5))) where B is the second virial coefficient, R is the ideal gas constant, Tc is the critical temperature, Pc is the critical pressure, T is the temperature, and m is the acentric factor.

Plugging in the given values and solving for B, we get B = -0.009413 m3/mol. Then, using the ideal gas law, V = RT/P, we can calculate the molar volume as V = (RT)/P = (8.314 J/mol-K * 247.1 K) / (13.5 bar * 10^5 Pa/bar) ≈ 0.0725 m3/mol ≈ 72.5 cm3/mol.

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A rectangular channel 3 m wide carries 4 m3/s of water at a depth of 1.5 m. If an obstruction 15 cm high is placed across the channel, calculate the elevation of the water surface over the obstruction. What is the maximum height of the obstruction that will not cause a rise in the water surface upstream

Answers

Answer:

the elevation of the water surface over the obstruction is highest at 1.341 m

the maximum height of the obstruction h = 0.159 m

Explanation:

From the given information:

The diagrammatic expression for the water profile showing a rectangular channel  with 3 cm width carrying a 4 m3/s of water at a depth of 1.5 m with an obstruction 15 cm high is placed across the channel can be seen in the diagram attached below.

To calculate the elevation of the water surface over the obstruction, we need to  determine the following:

a. the velocity of the channel

b. the froude number at the upstream of the obstruction

c. the specific energy level

To start with the velocity V of the channel.

\(V_1 = \dfrac{Q}{A} \\ \\ V_1 = \dfrac{4 \ m^3/s}{(3 \times 1.5 ) m^2 } \\ \\ V_1 = \dfrac{4 \ m^3/s}{4.5 \ m^2}\)

\(V_1 = 0.88 \ m/sec\)

The froude number  at the upstream of the obstruction

\(F _{\zeta} = \dfrac{V_1}{\sqrt{gy__1}}\)

\(F _{\zeta} = \dfrac{0.88}{\sqrt{9.81 \times 1.5}}\)

\(F _{\zeta} = \dfrac{0.88}{\sqrt{14.715}}\)

\(F _{\zeta} = \dfrac{0.88}{3.836}\)

\(F _{\zeta} =0.229\)

\(F _{\zeta} \simeq0.3\)  which is less than the subcritical flow.

Similarly, the specific energy level for this process can be expressed as:

\(E_1 = \dfrac{V_1^2}{2g}+y_1\)

\(E_1 = \dfrac{0.88^2}{2 \times 9.81 }+1.5\)

\(E_1 = \dfrac{0.7744}{19.62 }+1.5\)

\(E_1 =0.039469+1.5\)

\(E_1 =1.539469\)

\(E_1 \simeq1.54 \ m\)

\(E_2 + \Delta z = E_1\)

\(E_2= E_1 - \Delta z\)

\(E_2= (1.54 - 0.15) \ m\)

\(E_2=1.39 \ m\)

Suppose ;

\(V_1 y_1 = V_2y_2\\ \\ Then; \ making \ V_2 \ the \ subject \ of \ the \formula\ we \ have: \\ \\ \\V_2 = \dfrac{V_1 y_1}{y_2} ---- (1)\)

From the energy equation:

\(E_2 + \Delta z = E_1\)

we can now substitute the above derived parameter and have :

\(E_2 + \Delta z=y_1 + \dfrac{V_1^2}{2g}\)

\(E_2 =y_1 + \dfrac{V_1^2}{2g} - \Delta z\)

\(E_2 =y_2 + \dfrac{V_2^2}{2g}\)

replace the value of \(V_2\) =\(\dfrac{V_1 y_1}{y_2}\)  in equation (1), we have:

\(E_2 =y_2 + \dfrac{( \dfrac{V_1y_1}{y_2})^2}{2g}\)

\(E_2 =y_2 + \dfrac{ {V_1^2y_1^2}}{2gy_2^2}\)

\(E_2 \times y_2^2 =y^3_2 + \dfrac{ {V_1^2y_1^2}}{2g}\)

\(y^3_2 - E_2y^2_2 + \dfrac{V_1^2y_1^2}{2g}=0\)

Replacing our values now; we have:

\(y^3_2 - 1.39 \times y^2_2 + \dfrac{0.88^2 \times 1.5^2}{2 \times 9.81}=0\)

\(y^3_2 - 1.39 \times y^2_2 + \dfrac{1.7424}{19.62}=0\)

\(y^3_2 - 1.39 \times y^2_2 + 0.0888=0\)

\(y^3_2 - 1.39 y^2_2 + 0.0888=0\)

\(y_2 = 1.341 \ m \\ \\ y_2 = - 0.232 \ m \\ \\ y_2 = 0.281 \ m\)

Therefore,the elevation of the water surface over the obstruction is highest at 1.341 m

What is the maximum height of the obstruction that will not cause a rise in the water surface upstream

In order to determine the maximum height , we need to first estimate the rise in water level surface of \(\Delta z\)

\(\Delta z\) = 1.5 - (1.341+ 0.15) m

\(\Delta z\) =  (1.5 - 1.491) m

\(\Delta z\) = 0.009 m

Finally, the maximum height of the obstruction h = (0.009 + 0.15 )m

the maximum height of the obstruction h = 0.159 m

A rectangular channel 3 m wide carries 4 m3/s of water at a depth of 1.5 m. If an obstruction 15 cm high

A part made from 1040 hot-rolled steel is to be heat treated to increase its strength to approximately 107 kpsi. What Brinell hardness number should be expected from the heat-treated part? The Brinell hardness number for the heat-treated part is

Answers

The expected Brinell hardness number for the heat-treated part made from 1040 hot-rolled steel should be approximately 31.01 BHN.

How to calculate the value

The Brinell hardness number (BHN) is a measure of a material's resistance to indentation. While there is no direct conversion between tensile strength and Brinell hardness, a general correlation can be used to estimate the expected BHN.

Tensile Strength (ksi) = 3.45 × Brinell Hardness Number (BHN)

In order to find the Brinell hardness number, we rearrange the equation:

BHN = Tensile Strength (ksi) / 3.45

Substituting the given tensile strength of 107 kpsi into the equation:

BHN = 107 kpsi / 3.45 ≈ 31.01

Therefore, the expected Brinell hardness number for the heat-treated part made from 1040 hot-rolled steel should be approximately 31.01 BHN.

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All of the following are types of * assertions in Selenium IDE EXCEPTa. Wait b. WaitForc. Assert d. Verity

Answers

Hi! To answer your question, all of the following are types of * assertions in Selenium IDE EXCEPT: Wait.

The other options, WaitFor, Assert, and Verify, are valid types of * assertions in Selenium IDE.

Wait is used for managing time delays but is not considered an assertion type.

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B/ Evaluate e^(πi/2)

Answers

You get a result immediately from Euler's formula:

e ^(i π/2) = cos(π/2) + i sin(π/2) = 0 + i * 1 = i

The cutting plane line indicates where the section is located with relation to the
view.

Answers

Diagonal lines drawn that are placed on section view to indicate the areas of thr object that came on contact with the cutting plane.

When a licensed engineer or land surveyor testifies as an expert in an iowa court, the licensee's testimony cannot be challenged by the opposing attorney

Answers

In Iowa courts, the testimony of a licensed engineer or land surveyor, when presented as an expert witness, can be challenged by the opposing attorney.

The opposing attorney has the right to cross-examine the expert witness and challenge their testimony through questioning and presenting counterarguments or conflicting evidence. This is a fundamental aspect of the legal process that allows for the exploration of different perspectives and the evaluation of the credibility and accuracy of expert testimony. By challenging the testimony, the opposing attorney aims to test the expert's qualifications, methods, reasoning, and conclusions to present a comprehensive and well-rounded view to the court. It is through the adversarial process that the court can weigh the evidence and make an informed decision. Therefore, in Iowa courts, the testimony of a licensed engineer or land surveyor, like any other expert witness, can be subject to challenge by the opposing attorney.

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A hole drilled into a manufactured part is specified to have a diameter of 1.50 cm. Ten parts are sampled from a production run. The hole diameters of the parts range in size from 1.43 cm to 1.55 cm. Is the range of measurements a better indicator of the accuracy or precision of the drilling process? ____________

Answers

Answer:

Precision

Explanation

You know the answer is precision because it uses the word range and plus because I just answered this question and got it correct.

.

a steel cylinder whose capacity is 71.2 cubic feet at 2475 psi and an aluminum cylinder whose capacity is 80 cubic feet at 3000 psi are both filled to 2000 psi. which cylinder contains more air?

Answers

The steel Cylinder . you need to compare how much capacity each psi accounts for in a steel cylinder.

71.2cf divided by 2475 psi gives a value of.0287cf for each psi.

If you divide 80cf by 3000psi, you get.0266cf per psi in an aluminum cylinder.

Steel .0287cf per psi X 3000=57.4cf.

Aluminum .0266cf per psi X 2000psi = 53.2cf.

What is a cylinder?

In geometry, a cylinder is one of the basic 3d shapes with two parallel circular bases at a distance. A curved surface connects the two circular bases at a fixed distance from the center. The axis of the cylinder is the line segment connecting the centers of two circular bases. The height of the cylinder is defined as the distance between the two circular bases. One real-world example of a cylinder is an LPG gas-cylinder.

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About college level
Which class is easier english 103 or 102, which class do u suggest me?

Answers

I would say 102 was easier
103 is better is only all about business writing

A 50-mm cube of the graphite fiber reinforced polymer matrix composite material is subjected to 125-kN uniformly distributed compressive force in the direction 2, which is perpendicular to the fiber direction (direction 1). The cube is constrained against expansion in direction 3. Determine:

a. changes in the 50-mm dimensions.
b. stresses required to provide constraints.

Answers

Answer:

hello some parts of your question is missing attached below is the missing part

answer :

A) Determine changes in the 50-mm dimensions

The changes are : 0.006mm compression  in y-direction

                               0.002 mm expansion in x and z directions

B) the stress required are evenly distributed

Explanation:

Given data :

50-mm cube of graphite fiber reinforced polymer matrix

subjected to 125-KN force in direction 2,

direction 2 is perpendicular to fiber direction ( direction 1 ) and cube is constrained against expansion in direction 3

A) Determine changes in the 50-mm dimensions

The changes are : 0.006mm compression  in y-direction

                               0.002 mm expansion in x and z directions

B) the stress required are evenly distributed

attached below is the detailed solution

A 50-mm cube of the graphite fiber reinforced polymer matrix composite material is subjected to 125-kN
A 50-mm cube of the graphite fiber reinforced polymer matrix composite material is subjected to 125-kN
A 50-mm cube of the graphite fiber reinforced polymer matrix composite material is subjected to 125-kN

an ideal gas at high pressure expands through an adiabatic turbine to a lower pressure in a steady-state, steady-flow process. does the entropy of the gas always increase for an irreversible process (yes or no)?

Answers

The relationship between entropy and energy in an irreversible process of a gas expanding is that as the gas expands, some energy is lost as heat to the surroundings and cannot be recovered.

What is the relationship between entropy and energy in an irreversible process of a gas expanding?

Yes, the entropy of the gas always increases for an irreversible process. This is due to the fact that during the expansion process, some energy is lost as heat to the surroundings, which cannot be recovered.

This leads to an increase in the randomness and disorder of the system, which is reflected by an increase in entropy.Entropy is a measure of the degree of randomness or disorder in a system.

In the case of a gas undergoing an irreversible expansion process, the system loses some energy as heat to the surroundings.

This energy cannot be recovered, and as a result, the randomness and disorder of the system increase. The increase in randomness and disorder is reflected by an increase in the system's entropy.

This is a natural consequence of the second law of thermodynamics, which states that the total entropy of an isolated system always increases over time.

Thus, irreversible processes always result in an increase in entropy, and the irreversible expansion of a gas is no exception.

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Discuss two (2) points related to the importance of Health and
Safety Standards in the wood processing industry.

Answers

Health and safety standards in the wood processing industry are crucial for the safety and protection of workers in the industry. They must follow strict procedures to ensure that they are not exposed to harmful elements, and that their health and well-being are not compromised.

Following are the two points related to the importance of Health and Safety Standards in the wood processing industry.

Employee Safety: Wood processing can be dangerous work, and the workers involved are at risk of injury or illness if the proper health and safety precautions are not taken. Employee safety is a top priority in the industry, and the introduction of health and safety standards helps to ensure that workers are protected from potential hazards such as chemical exposure, dust inhalation, and fire hazards. By following these standards, employers can reduce the likelihood of accidents occurring and minimize the risk of injuries or illnesses to their workers.Compliance: Another important aspect of health and safety standards is compliance. Employers who do not follow these standards can face legal action, fines, and even criminal charges in some cases. Compliance ensures that companies are held accountable for their actions and that they take the necessary steps to protect their workers. In addition, companies that follow health and safety standards are seen as more reputable and trustworthy, which can help to attract and retain employees, and maintain good relationships with clients and customers.

In conclusion, health and safety standards in the wood processing industry are essential for the protection of workers and the success of companies in the industry. By prioritizing employee safety and compliance with regulations, employers can minimize the risks associated with wood processing and maintain a safe and healthy work environment.

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ShopKey Pro presents repair information in a/an _______________________ format or layout.

Answers

ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

What is the Repair Information?

In regards to auto repair information tools, the solution that is known to be made available is the use of ShopKey® Pro with 1Search.

This is know  to be a kind of an exclusive auto repair software that helps to streamlines the search acts to bring closer a special  combination of OEM data as well as experience-based Real Fixes.

Therefore, based on the above, one can say that ShopKey Pro presents repair information in a customized email template as well as auto repair software format or layout.

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What are the indications that Cece is having problems
with her computer hardware? Check all that apply
-losing the Internet connection
-waiting for five minutes
-computer going blank
-mouse pointer freezing
-keyboard getting stuck

Answers

Answer:

-Computer going blank .

-Mouse pointer freezing.

-Keyboard getting stuck.

Explanation:

Any problems with the computer related to its hardware will consist of issues directly related to the physical components of the PC or computer. So any problem involving the physical component of the computer, then it can be termed as a hardware problem.

Based on the problems given in the option, the hardware issues will be problems with the computer, mouse, and keyboard. These form the physical parts of the computer so they will be a hardware issue.

Thus, the correct answers are the third, fourth, and fifth options.

Answer:

c d e

Explanation:

+
Vi
v (t)
V
-37/2T-T/2
8 ΚΩ
ww
-V
m
T/2
1. For the above, derive the Fourier series representation of the waveform.
3T/2
10 mH
t
10 nF
Vo
2. The waveform above is applied to Vi. Using the Fourier series derived in part 1, determine the
magnitude of Vo in terms of Vm if T is equal to for the first 3 non-zero terms of the series.
2πT
50,000
3. If the waveform is applied across a 9-ohm resistor, and Vm =27V calculate the exact amount of
average power absorbed by the resistor.
4. Calculate the power absorbed by the 9-ohm resistor from the first 3 non-zero terms from the
Fourier series.
5. Determine the percentage error in the calculation from part 4 compared with the exact value of
part 3.

+Viv (t)V-37/2T-T/28 ww-VmT/21. For the above, derive the Fourier series representation of the waveform.3T/210

Answers

The sine term 27r 131,= 1 —f v(t)sin (nt)dt 7r

27r1 7 = — (f sin tsin (nt)dt f 0

7r2n (1( —1)n)

How to solve

Step 1 ..

We can express the waveform as a function of time as shown below.

v(t) = sin t; 0 < t < 7F = —sin t; 7F < t < 27r

In order to get the Fourier transform of the function, we have to calculate the sine and cosine terms.

The cosine term is 1 27r a 0 v(t)dt fo 1 ( 27 271 u sin tdt — sin tdil 1=0

1 27r an = —f v(t)cos (nt)dt 71 0 27r

= (f sin tcos (nt)dt —

71 0 = 7111 (1 — cos n7r)/

Now, we can find the sine term 27r 131,= 1 —f v(t)sin (nt)dt 7r

27r1 7 = — (f sin tsin (nt)dt f 0

7r2n (1( —1)n)

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Using a paged memory allocation system with a page size of 2,048 bytes and an identical page frame size, and assuming the incoming data file is 20,992, calculate how many pages will be created by the file. calculate the size of any resulting fragmentation. explain whether this situation will result in internal fragmentation, external fragmentation, or both.

Answers

A process of 72,766 bytes will require 35 pages and an additional 1,086 bytes because a page is 2,048 bytes. It will get 36 frames, which means that 2,048 - 1,086 = 962 bytes will be internally fragmented. A process would require 11 pages + 1 byte in the worst-case scenario.

How is fragmentation size determined?

The distance between the farthest two points in a single fragment that has been removed from the clustering results can be used to determine the size of the fragment.

What is the calculation method for file size?

The resolution (the picture width times the image height) times the bit depth can be used to calculate file size (the number of bits needed to store colours).

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The surface of an object is the
texture value appearance or function

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Texture value appearance

Which one of the following would appear as a thin line on a drawing?
A. Centerline
B. Cutting plane line
C. Short break line
D. Outline

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Answer:

try b

Explanation:

Write a statement that assignsall elements in the arrayatomicWeights the value 1.003,independent of the size of thearray.atomicWeights(:) = 1.0032

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A statement that assigns all elements in the array atomic Weights the value 1.003,independent of the size of the array is atomicWeights(:) = 1.0032.

An array is a grouping of identically typed components that are stored in adjacent memory locations and can each be individually referred to using an index to a special identifier. There is no need to declare five distinct variables when declaring an array of five int values (each with its own identifier). are by default not set. This indicates that none of the components in the array have any specific values assigned to them; rather, their contents are unknown at the time the array is declared.

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Steam flowing through a long, thin walled pipe maintains the pipe wall at a uniform temperature of 500 K. The pipe is covered with an insulation blanket comprised of two different materials, A and B. The interface between the two materials may be assumed to have an infinite contact resistance, and the entire outer surface is exposed to air for which T? = 300 K and h = 25 W/m2K. A. Sketch the thermal circuit of the system. Label all pertinent nodes and resistancesb. For the prescribed conditions, what is the total heat loss from the pipe? What are the outer surface temperatures Ts,2(A) and Ts,2(B)?

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Answer: The heat loss from insulated pipes or tubes to surrounding air depends on several factors such as insulation thickness, ambient temperature, wind speed etc.

Explanation:  The heat loss can be calculated using the following formula: Q = 2 π L (ti - to) / [ (ln (ro / ri) / k) + (ln (rs / ro) / KS)] (2).

Where:

Q = heat loss per unit length of pipe (W/m)L = length of pipe (m)ti = temperature inside pipe (K)to = temperature outside pipe (K)ro = outside radius of pipe (m)ri = inside radius of pipe (m)rs = outside radius of insulation (m)k = thermal conductivity of pipe material (W/mK or W/m oC, Btu/ (hr oF ft2/ft))ks = thermal conductivity of insulation material (W/mK or W/m oC, Btu/ (hr oF ft2/ft))

The total heat loss from the pipe can be calculated by multiplying Q with the length of the pipe. The outer surface temperatures Ts,2(A) and Ts,2(B) can be calculated using the following formula3:

Ts,2(A) = T? + Q/(hA) Ts,2(B) = T? + Q/(hB)

Where:

T? = ambient temperature outside insulation blankethA and hB are convective heat transfer coefficients for materials A and B respectively.

I'm sorry, but there really isn't enough information to solve the problem using what is given. However, I have provided you with a yellow brick road, so to speak, as how to solve the word problem. Hope this helps and have a great day!

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