A security architect is required to deploy to conference rooms some workstations that will allow sensitive data to be displayed on large screens. Due to the nature of the data, it cannot be stored in the conference rooms. The fileshares is located in a local data center. Which of the following should the security architect recommend to BEST meet the requirement?
A. Fog computing and KVMs
B. VDI and thin clients
C. Private cloud and DLP
D. Full drive encryption and thick clients

Answers

Answer 1

Recommend VDI (Virtual Desktop Infrastructure) with thin clients for secure display of sensitive data on large screens in conference rooms, ensuring data stays in a centralized data center without local storage.

VDI (Virtual Desktop Infrastructure) and thin clients would be the best recommendation to meet the requirement of displaying sensitive data on large screens while not storing the data in the conference rooms. With VDI, the sensitive data remains in the local data center's fileshares, and only the virtual desktops are accessed remotely by thin clients in the conference rooms. This ensures that the data is securely stored centrally and not physically present in the conference rooms, minimizing the risk of data exposure or unauthorized access.

Therefore, option B. VDI and thin clients is correct.

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Related Questions

A student is investigating the particles in a glass window, raindrops on the window, and the air around the window. Assume the window, the raindrops, and the air are all at 25 °C.

Answers

The glass is a solid and as such the attraction between its particles is strong enough to make them locked in one place. The raindrop is a liquid and as such the attraction between its particles is strong enough to hold them together, but not strong enough to prevent the particles from sliding past each other. The air is a gas and as such there is very little (minimal) attraction between its particles, thereby, making them to move freely.

What is matter?

Matter can be defined as anything (physical object or body) that has mass and takes up space. Thus, the mass of a physical object measures the amount of matter the object contains.

The states of matter.

In Science, water is an example of matter and it exists in three (3) main states or phases such as the following:

SolidLiquidGas

Based on scientific records and information, we know that all particles have various degrees of attraction to one another and this can be described as follows:

The glass is a solid and as such the attraction between its particles is strong enough to make them locked in one place. The raindrop is a liquid and as such the attraction between its particles is strong enough to hold them together, but not strong enough to prevent the particles from sliding past each other. The air is a gas and as such there is very little (minimal) attraction between its particles, thereby, making them to move freely.

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Complete Question:

A student is investigating the particles in a glass window, raindrops on the window, and the air around the window. Assume the window, raindrops, and the air are all at 25 degrees Celsius. Identify the particle structure in each sample of matter.

it is a probabilistic question

it is a probabilistic question
it is a probabilistic question

Answers

Explanation:

I can't see the whole question... How can I solve it?

solve the following differential equations using laplace transforms dy(t) 2 y(t) = 8 u(t) y(0) = 0 dt

Answers

The solution to the given differential equation using Laplace transforms is \($y(t)=2-2e^{-2t}-t$\)

The given differential equation is solved using Laplace transforms. The solution involves finding the Laplace transform of the differential equation.

The given differential equation is:

\($$\frac{d^2y(t)}{dt^2}+2\frac{dy(t)}{dt}=8u(t),\qquad y(0)=0$$\)

Taking Laplace transform of both sides, we get:

\($$s^2Y(s)-sy(0)-y'(0)+2(sY(s)-y(0))=\frac{8}{s}$$\)

Substituting  \($y(0)=0$\) and  \($y'(0)=0$\), we get:

\($$(s^2+2s)Y(s)=\frac{8}{s}$$\)

Solving for \($Y(s)$\), we get:

\($$Y(s)=\frac{4}{s^2(s+2)}$$\)

Using partial fraction decomposition, we get:

\($$Y(s)=\frac{2}{s}-\frac{2}{s+2}-\frac{1}{s^2}$$\)

Taking the inverse Laplace transform, we get:

\($$y(t)=2-2e^{-2t}-t$$\)

Therefore, the solution to the given differential equation using Laplace transforms is \($y(t)=2-2e^{-2t}-t$\).

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Assume that two stars are in circular orbits about a mutual center of

mass and are separated by a distance a. Assume also that the angle of

inclination i and their stellar radii are r1 and r2.

(a) Find an expression for the smallest angle of inclination that will pro-

duce an eclipse. Hint: Refer to Figure 7. 8 of your text.

(b) If a = 2 AU, r1 = 10 R⊙, and r2 = 1 R⊙, what minimum value of i

will result in an eclipse?

Answers

Eclipsing stars have orbital planes that are parallel to the sky's plane. Since the length of ingress and the length of the eclipse rely on the disparity in the diameters of the stars

The orbital inclination over which eclipses can occur depends on the relative diameters of the stars, but in general, only a tiny percentage of the known binary systems will be observed to experience eclipses. The varying light has two functions. Since the length of ingress and the length of the eclipse rely on the disparity in the diameters of the stars, it enables the estimation of the respective radii of the stars. That is, if Δt1 is the total time between first and last contact, and Δt2 is the period of totality, assuming that the eclipse is annular or total, then.

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What is resonance as in ultrasound waves formation using magnetostriction method​

Answers

Answer:

Resonance is when the frequency of the vibrating quartz rod is equal to the frequency of the LC tank circuit.

a device that transforms electrical energy to mechanical energy is a a) transformer. b) magnet. c) generator. d) motor. e) none of these 7) which formula makes your answer possible?

Answers

A device that transforms electrical energy into mechanical energy is called a (d) motor.

A motor is a device that utilizes electrical energy to get mechanical energy or movements. There is a coil on the magnetic field in a motor device. Since the electrical energy or voltage is applied to the motor, The coil in the motor will rotate and generate mechanical energy.

Usually, the motor device has efficiency on its device. The efficiency of the motor is defined as

η = Eo / Ei

where η is efficiency, Eo is output energy (mechanical energy) and Ei is input energy (electrical energy).

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Gear B supplies 15 kW of power, while gears A, C and D withdraw 6 kW, 4 kW and 5 kW, respectively. If the shaft is made of steel with the allowable shear stress of tau_allow = 75 MPa, and the relative angle of twist between any two gears cannot exceed 0.05 rad. determine the required minimum diameter d of the shaft to the nearest millimeter. The shaft is rotating at 600 rpm.

Gear B supplies 15 kW of power, while gears A, C and D withdraw 6 kW, 4 kW and 5 kW, respectively. If

Answers

Using the formula of shear stress, the minimum required diameter is 0.81mm

What is Shear Stress

Shear stress is a force that causes two objects to slide past each other in opposite directions. It is the force per unit area of the surface on which the force is applied. Shear stress is often caused by two objects rubbing against each other, such as a car tire sliding on the road. It can also be caused by wind, gravity, or other forces.

The shear stress on the shaft can be calculated using the formula:

τ(allow) = P/(2*π*d*J)

where P is the total power transferred by the shaft, d is the diameter of the shaft, and J is the polar moment of inertia.

J = π*d⁴/32

Substituting the given values,

τ(allow) = (15 + 6 + 4 + 5)/(2*π*d*π*d⁴/32)

d = √[32*(15 + 6 + 4 + 5)/(τ(allow)*2*π²)]

d = √[32*(30)/(75*2*π²)]

d = 0.81mm

The minimum required diameter of the shaft is 0.81 mm to the nearest millimeter.

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10. Which is of the following is not used in the
testing/analysis step?
A. Engineering notebooks.
B. Multiview drawings.
C. 3-D modeling software.
D. CNC machines.

Answers

A CNC machine stands for Computer Numerically Controlled Machine, they are used to Machine objects in hence create items, machine parts from prototypes. Hence the CNC machines are not used for testing/Analysis

D. CNC machines.

In Engineering the following items are basically needed for and during test/Analysis

Engineering notebooks: This is used to write down importance observations and findingsMulti-view drawings: This is also needed to visualise prototypes from different perspective or views3-D modelling software: e.g AutoCad , Autodesk Inventor, Revit to mention a few can be used to design and analyse project even before their actual implementation or design

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Which one of the following answer options are your employers responsibility

Answers

Where are your answer options?

Answer:

Implement a hazard communication program

Explanation: i took the quiz

table saws you can use with __ or __ but not both at the same time

Answers

Answer:

wood or metal

Explanation:

sorry if incorrect

What is the difference between a.c and d.c​

Answers

Answer:

Alternating Current (a.c) can be reversed since it relates to sinusoidal curves while Direct Current (d.c) can not be reversed.

Explanation:

\(.\)

Difference between AC and DC

Electric current flows in two ways as an alternating current (AC) or direct current (DC). In alternating current, current keeps switching directions periodically – forward and backward. While in the direct current it flows in a single direction steadily. The main difference between AC and DC lies in the direction in which the electrons flow. In DC, the electrons flow steadily in a single direction while electrons keep switching directions, going forward and then backwards in AC. Let us learn more differences between them in the next few sections.

What types of materials are best for preventing heat transfer through convection?.

Answers

The types of materials are best for preventing heat transfer through convection include the following:

FiberglassWoolCottonPaper (wood cellulose)StrawFoams

What are the types of energy transmission?

In Science, there are three (3) main types of heat energy transmission and these include the following:

ConvectionRadiationConduction

What is convection?

Convection can be defined as a heat energy transfer process which typically involves the transfer of heat, as a result of the movement of mass.

Based on scientific research and experiments, convection is generally considered to be a more effective and efficient means of heat transport on planet Earth when compared to conduction.

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The phase sequence of a 3-phase system for which VAN = 120 /90o V and VBN = 120 /210o V is:_______
a) bca
b) abc
c) cab
d) acb

Answers

Answer:

b. abc

Explanation:

The phase rotation and its sequence is order in which voltage is reached to their respective sources. The wave forms of a polyphase flow through AC source to the panel. The three phase system has two possible sequence which can be a-b-c or c-b-a. The correct answer is therefore b.

Calculate the energy conumed by each individual node if:
a. The node tranmit their temperature reading directly to the Sink
b. The node are organied in a cluter with node 3 a cluter-head. Let the network lifetime be defined a the time interval between the tart of t

Answers

The cluster head directs data transmission between clusters and controls the actions of its individual nodes.

What does a scientific energy mean?

The definition of power as the "capacity to accomplish work" refers to the capability to exert a force that compels an object to move. Even if the word is vague, it is clear what energy actually means: it is the force that causes objects to move. Kinetic energy and potential energy are the two categories of power.

From where does energy come?

Fossil fuels (coal, gas, and oil), nuclear energy, or renewable energy sources are the main energy sources. A secondary source of energy that is produced from fundamental energy sources is electricity.

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We are given a trained classifier. We add an additional data point to the data set and find that the decision boundary did not change at all. Which classifier could we have used? a. 1-nearest neighbor b. Logistic regression

Answers

Classifier could we have used based on data point to the data set is:  a. 1-nearest neighbor classifier.

When adding an additional data point and the decision boundary remains unchanged, which is a characteristic of the 1-nearest neighbor method. Logistic regression is a supervised learning algorithm that is used for binary classification used to analyzing from data point.

The probability of occurrence of a binary target variable based on one or more independent variables. One advantage of the nearest neighbor classifier is that it can capture complex decision boundaries and can be applied to a wide range of classification problems.

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Select the correct answer.
Which chemical can you use to assist with your motor fuel needs?
O A.
ethylene glycol
OB.
ethanol
O c.
butanol
OD.
pentanol
O E.
propranolol
Reset
Next

Answers

The answer is either b or e search it up and you will know the answer by definition

Answer: Ethanol

Explanation:

Which method do you use to test if an element is in a set or list named x?

A. (element instanceof List) || (element instanceof Set)
B. x.in(element)
C. x.contain(element)
D. x.contains(element)
E. x.include(element)

Answers

To test if an element is in a set or list named x, you should use the method "D. x.contains(element)".

In Java, the most appropriate method to check if an element is present in a list or set is the "contains()" method. The correct syntax for using this method is "x.contains(element)", where 'x' represents the list or set and 'element' represents the item you want to check for. The method returns a boolean value, i.e., 'true' if the element is present and 'false' if it's not.

The other options (A, B, C, and E) mentioned in your question are not valid methods in Java for checking the presence of an element in a list or set.

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The rate or speed at which work is performed is called what?
Select one:


Answers

Answer:

What are you talking about? pls explain and then maybe I can help.

Why should the administrator (or the superuser) account never be locked regardless of how many incorrect login attempts are made? What should be done instead to alert the staff to the attempted intrusion, and how could the chances of such an attack succeeding be minimized?

Answers

The answer to question is given in brief

The administrator (or superuser) account should never be locked regardless of how many incorrect login attempts are made because the administrator is the one who controls access to the system. If the account is locked, it will be impossible to regain access to the system in the event of an intrusion. It is important to note that the administrator account is often targeted by hackers because it provides the highest level of access to the system. Instead of locking the account, the staff should be alerted to the attempted intrusion.

This can be done by setting up an intrusion detection system (IDS) or an intrusion prevention system (IPS) that can detect and block suspicious activity.

In addition, the staff should be trained on how to recognize and respond to potential intrusions. The chances of such an attack succeeding can be minimized by implementing best practices such as regularly updating software, limiting access to the administrator account, and using strong passwords and two-factor authentication.

It is also important to regularly monitor the system for any signs of suspicious activity.

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Consider pressurized water, engine oil (unused), and NaK (22%/78%) flowing in a 20-mm-diameter tube.

(a) Determine the mean velocity, the hydrodynamic entry length, and the thermal entry length for each of the fluids when the fluid temperature is 366 K and the flow rate is 0. 01 kg/s.

(b) Determine the mass flow rate, the hydrodynamic entry length, and the thermal entry length for water and engine oil at 300 and 400 K and a mean velocity of 0. 02 m/s

Answers

Answer:

To solve this problem, we need to use the Reynolds number, the Prandtl number, and the Darcy friction factor. The Reynolds number is a dimensionless number that describes the flow regime of the fluid, the Prandtl number characterizes the ratio of momentum diffusivity to thermal diffusivity, and the Darcy friction factor describes the frictional losses in the pipe.

(a)

For pressurized water at 366 K and a flow rate of 0.01 kg/s, we can calculate the mean velocity as follows:

v = m_dot / (rho * A), where

m_dot = 0.01 kg/s (mass flow rate)

rho = 997 kg/m^3 (density of water at 366 K)

A = pi * (0.02 m)^2 / 4 = 0.000314 m^2 (cross-sectional area of the tube)

v = 0.01 / (997 * 0.000314) = 3.18 m/s

The Reynolds number for water is:

Re = (rho * v * D) / mu, where

D = 0.02 m (diameter of the tube)

mu = 0.000283 Pa s (dynamic viscosity of water at 366 K)

Re = (997 * 3.18 * 0.02) / 0.000283 = 2.24e5

Using the Reynolds number, we can estimate the hydrodynamic entry length using the following equation:

L_hyd = 0.05 * Re * D

L_hyd = 0.05 * 2.24e5 * 0.02 = 224 m

For the thermal entry length, we use the following equation:

L_th = 0.05 * Re * Pr * D / Nu

where Pr is the Prandtl number and Nu is the Nusselt number. For water at 366 K, Pr = 5.5 and we can estimate Nu using the Dittus-Boelter correlation:

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Nu = 0.023 * (2.24e5)^(4/5) * 5.5^(0.4) = 244

L_th = 0.05 * 2.24e5 * 5.5 * 0.02 / 244 = 3.6 m

For engine oil (unused) at 366 K and a flow rate of 0.01 kg/s, we can calculate the mean velocity as follows:

v = m_dot / (rho * A), where

m_dot = 0.01 kg/s (mass flow rate)

rho = 890 kg/m^3 (density of engine oil at 366 K)

A = pi * (0.02 m)^2 / 4 = 0.000314 m^2 (cross-sectional area of the tube)

v = 0.01 / (890 * 0.000314) = 3.79 m/s

The Reynolds number for engine oil is:

Re = (rho * v * D) / mu, where

D = 0.02 m (diameter of the tube)

mu = 0.0003 Pa s (dynamic viscosity of engine oil at 366 K)

Re = (890 * 3.79 * 0.02) / 0.0003 = 4.72e5

Using the Reynolds number, we can estimate the hydrodynamic entry length using the following equation:

L_hyd = 0.05 * Re * D

L_hyd = 0.05 * 4.72e5 * 0.02 = 472 m

For the thermal entry length, we use the following equation:

L_th = 0.05 * Re * Pr * D / Nu

where Pr is the Prandtl number and Nu is the Nusselt number. For engine oil at 366 K, Pr = 130 and we can estimate Nu using the Dittus-Boelter correlation:

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Nu = 0.023 * (4.72e5)^(4/5) * 130^(0.4) = 2600

L_th = 0.05 * 4.72e5 * 130 * 0.02 / 2600 = 7.2 m

For NaK (22%/78%) at 366 K and a flow rate of 0.01 kg/s, we can calculate the mean velocity as follows:

v = m_dot / (rho * A), where

m_dot = 0.01 kg/s (mass flow rate)

rho = 1100 kg/m^3 (density of NaK at 366 K)

A = pi * (0.02 m)^2 / 4 = 0.000314 m^2 (cross-sectional area of the tube)

v = 0.01 / (1100 * 0.000314) = 2.87 m/s

The Reynolds number for NaK is:

Re = (rho * v * D) / mu, where

D = 0.02 m (diameter of the tube)

mu = 0.0018 Pa s (dynamic viscosity of NaK at 366 K)

Re = (1100 * 2.87 * 0.02) / 0.0018 = 3.48e5

Using the Reynolds number, we can estimate the hydrodynamic entry length using the following equation:

L_hyd = 0.05 * Re * D

L_hyd = 0.05 * 3.48e5 * 0.02 = 348 m

For the thermal entry length, we use the following equation:

L_th = 0.05 * Re * Pr * D / Nu

where Pr is the Prandtl number and Nu is the Nusselt number. For NaK at 366 K, Pr = 0.013 and we can estimate Nu using the Sieder-Tate correlation:

Nu = 0.027 * Re^(4/5) * Pr^(0.43)

Nu = 0.027 * (3.48e5)^(4/5) * 0.013^(0.43) = 67.3

L_th = 0.05 * 3.48e5 * 0.013 * 0.02 / 67.3 = 0.008 m

(b)

For water and engine oil, the mass flow rate is given as 0.01 kg/s, and the mean velocity is given as 0.02 m/s.

For water at 300 K:

rho = 996.6 kg/m^3 (density of water at 300 K)

mu = 0.000547 Pa s (dynamic viscosity of water at 300 K)

Pr = 7.02 (Prandtl number of water at 300 K)

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Re = (rho * v * D) / mu = (996.6 * 0.02 * 0.02) / 0.000547 = 1445

Nu = 0.023 * Re^(4/5) * Pr^(0.4) = 0.023 * (1445)^(4/5) * 7.02^(0.4) = 426.5

L_hyd = 0.05 * Re * D = 0.05 * 1445 * 0.02 = 14.45 m

L_th = 0.05 * Re * Pr * D / Nu = 0.05 * 1445 * 7.02 * 0.02 / 426.5 = 0.021 m

For water at 400 K:

rho = 958.4 kg/m^3 (density of water at 400 K)

mu = 0.000294 Pa s (dynamic viscosity of water at 400 K)

Pr = 4.41 (Prandtl number of water at 400 K)

Nu = 0.023 * Re^(4/5) * Pr^(0.4)

Explanation:

In your own words, explain the typical environmental and conservation challenges, and associated solutions, facing the surface mining industry today. 1.2 [10] Relative to a comparable underground mine, the capital and operational costs of the surface are generally lower than that of the underground mine. Comment on the reasonableness or unreasonableness of the statement. Typically, which aspects of an operational mine would justify the reasonableness or unreasonableness (correctness or incorrectness) of the statement?

Answers

The typical environmental and conservation challenges facing the surface mining industry today include land degradation, deforestation, water pollution, air pollution, and wildlife habitat destruction.

Solutions to these challenges may include implementing reclamation and restoration programs, using sustainable mining practices, reducing water and energy consumption, and developing efficient waste management systems.

The statement that surface mining has lower capital and operational costs than underground mining is generally reasonable. This is because surface mining typically involves extracting minerals from near the earth's surface, which requires less drilling and blasting than underground mining.

Additionally, surface mines often have larger production capacities and can use larger equipment, resulting in economies of scale. However, the costs associated with land reclamation and restoration, as well as environmental compliance and mitigation, can offset some of the savings.

The aspects of an operational mine that would justify the reasonableness or unreasonableness of the statement include the geology of the ore deposit, the size of the deposit, the depth of the ore, the type of minerals being extracted, and the environmental regulations in place.

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Anyone got a pc that can run 240 fps? Around like 1,300 dollars that can run 240 fps on fortnite whoever answers and gives me a good pc I will give brainliest

Answers

Answer:

What do u need it for just gaming or for streaming and other things

I’ve said this several times before but it bears repeating: Gaming PCs are bottomless pits.

. explain the effect of increasing the right flow tube radius on the flow rate, resistance, and pump rate.

Answers

Answer:

Increasing the flow tube radius caused flow rate to increase and resistance to decrease. To maintain the same pressure, the pump rate had to increase as well.

an aerial photograph taken at 3000m above ground surface, the top and bottom distances of a telecommunication tower are 4.65cm and 4.5cm from the principal point, the bottom of the tower is 2700 above mean sea level.
determine tower height.

Answers

Respuesta: h= 2.22f

Explicación : x/h​= 4.65-4.5-4.5=0.15/4.5=0.0333

3000-2700/x=4.5/f

x= h/0.0333
300/h/0.0033= 4.5/f

h= 300*0.0333/4.5

The trolley travels at the constant speed of 40 mi/h along a parabolic track described by y = x2/500, where x and y are measured in feet. Compute the acceleration of the trolley when it is (1) at point O; and (2) at point A.

Answers

To compute the acceleration of the trolley, we need to first find its velocity vector, and then take the derivative of the velocity vector with respect to time to find the acceleration vector.

At point O, the trolley is at the bottom of the parabolic track, where y = 0. Therefore, the position vector of the trolley is given by r = xi, where i is the unit vector in the x-direction. The velocity vector of the trolley is given by the derivative of the position vector with respect to time:
v = dr/dt = (d/dt)(xi) = (dx/dt)i

Since the trolley is traveling at a constant speed of 40 mi/h, its velocity vector has a magnitude of 40 mi/h. To find the x-component of the velocity vector, we can use the fact that the speed is constant:

40 mi/h = |v| = sqrt[(dx/dt)^2]

Solving for dx/dt, we get:

dx/dt = 40/sqrt(mi^2/h^2) = 40/5280 ft/s

Therefore, the velocity vector of the trolley at point O is given by:

v = (40/5280)i ft/s

Taking the derivative of the velocity vector with respect to time, we get the acceleration vector:

a = dv/dt = (d/dt)(40/5280)i = 0

Therefore, the acceleration of the trolley at point O is zero.

At point A, the position vector of the trolley is given by:
r = xi + (x^2/500)j

where j is the unit vector in the y-direction. To find the velocity vector of the trolley, we need to take the derivative of the position vector with respect to time:

v = dr/dt = (d/dt)(xi) + (d/dt)((x^2/500)j)

The x-component of the velocity vector is given by:

dx/dt = 40 mi/h = 40/5280 ft/s

The y-component of the velocity vector is given by:

(dy/dt)j = (d/dt)((x^2/500)j) = (2x/500)(dx/dt)j

At point A, x = 200 ft (since y = x^2/500 = 40000/500 = 80 ft at point A), so we can compute the y-component of the velocity vector:

(dy/dt)j = (2x/500)(dx/dt)j = (2*200/500)(40/5280)j = (16/1320)j ft/s

Therefore, the velocity vector of the trolley at point A is given by:

v = (40/5280)i + (16/1320)j ft/s

Taking the derivative of the velocity vector with respect to time, we get the acceleration vector:

a = dv/dt = (d/dt)((40/5280)i) + (d/dt)((16/1320)j)

The x-component of the acceleration vector is zero, since the speed of the trolley is constant:

(d/dt)((40/5280)i) = 0

The y-component of the acceleration vector is given by:

(d/dt)((16/1320)j) = (d/dt)((2x/500)(dx/dt)j) = [(2/500)(d^2x/dt^2) + (2/500)(dx/dt)^2]j

To find the second derivative of x with respect to time, we can use the fact that the speed is constant:

What signal propagation phenomena causes the diffusion, or the reflection in multiple different directions, of a signal?

Answers

In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.

Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.

Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.

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If a sky diver decides to jump off a jet in Arkansas
with the intention of floating through Tennessee to
North Carolina, then completing his journey in a
likely manner back to Arkansas by drifting North
from his last point. What state would be the third t
be drifted over and what is the estimated distance
between the zone and then drop point?​

Answers

Answer:

The answer to this question can be defined as follows:

Explanation:

The sky driver began his sky journey from Arkansas, drove across the Tennessee River then landed in North Carolina. He returned to both the north in the very same direction. He began with NC, traveled through Tennessee, eventually lands in Arkansas. But North Carolina has been in the third state on which skydiver was traveling over, and It's also more than 700 miles from Arkansas to the NC.

Sadie is the props manager for a small community theater. Because she does not have a part onstage, Sadie is not part of the Performing Arts pathway of the Arts, AV Technology and Communication cluster.


True


False

Answers

Answer:

I think it is false!

Explanation:

Answer: I think it's true

Explanation:

Because if you were part of a play, you would have a part but if you work on props, you don't have a part onstage.

n order to test whether camshafts are being manufactured to specification a sample of n = 35 camshafts are selected at random. The average value of the sample is calculated to be 4.44 mm and the depths of the camshafts in the sample vary by a standard deviation of s = 0.34 mm. Test the hypotheses selected previously, by filling in the blanks in the following: An estimate of the population mean is 4.44 . The standard error is 0.06 . The distribution is normal (examples: normal / t12 / chisquare4 / F5,6). The test statistic has value TS= . Testing at significance level α = 0.01, the rejection region is: less than and greater than (2 dec places). Since the test statistic (is in/is not in) the rejection region, there (is evidence/is no evidence) to reject the null hypothesis, H0. There (is sufficient/is insufficient) evidence to suggest that the average hardness depth, μ, is different to 4.5 mm. Were any assumptions required in order for this inference to be valid? a: No - the Central Limit Theorem applies, which states the sampling distribution is normal for any population distribution. b: Yes - the population distribution must be normally distributed.

Answers

D46533
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How does the span of a truss relate to load-carrying capacity and when a truss fails, how much area is involved?

Answers

Answer:

For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span

For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss

When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span

Explanation:

The load-carrying capacity of a truss on the span  is basically based on the type of truss ,

For a deeper material truss, increase in distance between the top chord and bottom chord will cause the truss to bear more load with increase in Span

For Cantilever Truss ; increase in span will result in decrease in load bearing capacity of the truss

When a truss fails the areas that are affected are the supports of the truss and its corresponding spam. i.e. 4 crossbars at quarter of the span

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