To start with, we know that the school allots £1500 for the trip to the theater. Also, we know that the theater tickets have a regular cost of £35, and there's a 1/5 discount. So the actual cost of the ticket is: £35 - (1/5 * £35) = £28.So, the amount of money left for train tickets and other expenses is:£1500 - (3 * £28) = £1416.Now,
we know that a train ticket for the day will cost £12. And since there are 3 teachers, we will deduct £36 from the amount left for students' train tickets and other expenses. Hence, the amount left for students will be: £1416 - £36 = £1380.To find the maximum number of students, we need to find out how many students can go to the theater with the amount we have. We can do this by dividing the amount by the total cost of taking one student to the theater (which includes the theater ticket and the train ticket):£1380 / (£28 + £12) = £1380 / £40 = 34.5.So, the maximum number of students who can go to the theater is 34 (since we can't have half a student!). Therefore, 34 students and 3 teachers can go on the trip. In total, there will be 37 people on the trip.
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Can someone please explain what x is over here? And solve a part with working please :). Eternally grateful
Answer:
\(\frac{1}{9}\) , 3 , 10
Step-by-step explanation:
Using the rules of exponents
\(a^{-m}\) = \(\frac{1}{a^{m} }\)
\(a^{\frac{m}{n} }\) = \(\sqrt[n]{a^m}\)
\(a^{0}\) = 1
(a)
\(6^{-x}\) = \(\frac{1}{6^{x} }\) = \(\frac{1}{9}\)
(b)
\(6^{\frac{x}{2} }\) = \(\sqrt{6^{x} }\) = \(\sqrt{9}\) = 3
(c)
\(6^{0}\) + \(6^{x}\) = 1 + 9 = 10
If the measure of DCE is 28 what is the measure of CED
Answer: Measure of CED is: 212°
The production function is used to examine the relationship between _________.
Select the correct answer below:
supply and demand
producers and consumers
price and cost
inputs and outputs
The production function is used to examine the relationship between inputs and outputs.
The production function is a fundamental concept in economics that represents the relationship between inputs and outputs in the production process. It helps us understand how much output can be produced with a given set of inputs.
In the production process, inputs such as labor, capital, raw materials, and technology are combined to produce goods or services. The production function captures the quantitative relationship between these inputs and the resulting output. It provides a framework to analyze how changes in input levels affect the output level.
The production function typically takes the form of a mathematical equation or a graphical representation. It shows how the quantity of output depends on the quantities of various inputs used in the production process.
By studying the production function, economists can analyze factors such as efficiency, productivity, and technological progress. It helps firms make decisions regarding the optimal combination of inputs to maximize output or minimize costs. Additionally, it allows policymakers to assess the impact of policies on production and economic growth.
Therefore, the production function primarily focuses on examining the relationship between inputs and outputs, rather than supply and demand, producers and consumers, or price and cost.
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Help lssshjwejjwkwkwwkk
61 matchsticks need to make 20 squares.
Given,
From the figure,
Matchsticks are used to make the pattern.
To make these 4 squares, you need 13 matchsticks.
To find the how many matchsticks do you need to make 20 squares?
Now, According to the question:
Let the need matchsticks be 'n'
The number of the squares to make 1 square , you need 4 matchsticks,
and when you need to add one square, you need three more matchsticks .
So , we have to make n no. of squares you need
4 + 3(n - 1) matchsticks (n \(\geq\) )
= 4 + 3n - 3
= 1 + 3n
When, n = 20
1 + 3 x 20
= 61
Hence, 61 matchsticks need to make 20 squares.
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Which operation involving complex numbers requires the use of a conjugate to be carried out?
Answer:
Step-by-step explanation:
Rationalization.
2 + i
For example: " rationalize the denominator of --------- "
-3 + i
a rectangle has a width of 2x + 1 and a length of 6X which expression describes this area
Given parameters:
Width = 2x + 1
Length = 6x
Unknown:
Expression for the area = ?
Solution:
The area of a rectangle is the space it occupies,
Area of rectangle = length x width
Input the parameter and solve;
Area of rectangle = 6x(2x + 1)
= 12x² + 6x
The area of the rectangle is 12x² + 6x
The sum of one and the product of four and a number
How many quarters are there in 17
Answer:
68 quarters
Step-by-step explanation:
How many quarters are there in $17?
Each quarter is equivalent to 0.25 cents, 4 quarters makes up 1 dollar.
68 quarters is equivalent to $17.
What is the solution set of inequality 8n<32
Step-by-step explanation:
n < 4
Solution set =]_○○,4[
find dy/dx
5. \( y=10 \bigcap_{4}^{x(x+1)(2 x-1)} \)
The derivative of the given expression `y=10 ∩_4^(x(x+1)(2x-1))` is `dy/dx = 4^(x(x+1)(2x-1)) * ln 4 * [(2x-1)(x+1) + 4x² - x]`.
Given, `y=10 ∩_4^(x(x+1)(2x-1))`
To find the derivative of the above expression, we can use the Chain rule of differentiation.
The Chain rule of differentiation is used to find the derivative of composite functions. This rule is also known as the function of a function rule.
The Chain Rule: If `f` and `g` are both differentiable functions, then the derivative of their composite is given by the product of the derivative of `g` with respect to `x` and the derivative of `f` with respect to `g`.
That is, if `y = f(g(x))`, then
`dy/dx = f'(g(x))g'(x)`
Hence, the derivative of the given expression `y=10 ∩_4^(x(x+1)(2x-1))` is given by:
dy/dx = d/dx [10 ∩_4^(x(x+1)(2x-1))]
dy/dx = 0 + d/dx [4^(x(x+1)(2x-1))] * d/dx [x(x+1)(2x-1)]
Now we need to find the derivative of the two terms separately.
(i) d/dx [4^(x(x+1)(2x-1))] = 4^(x(x+1)(2x-1)) * ln 4 * d/dx [x(x+1)(2x-1)]
(ii) d/dx [x(x+1)(2x-1)] = x'(x+1)(2x-1) + x(x+1)(2x-1)'= 1(x+1)(2x-1) + x(1)(4x-1)
So, dy/dx = 0 + 4^(x(x+1)(2x-1)) * ln 4 * [1(x+1)(2x-1) + x(1)(4x-1)]
Hence, dy/dx = 4^(x(x+1)(2x-1)) * ln 4 * [(2x-1)(x+1) + 4x² - x]
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Which equation describes a line that passes through (-6,8) and is perpendicular to the line described by y=2x-4
Step-by-step explanation:
Hey, there!!
The given is a point (-6,8) through which a line passes. And is perpendicular to the line y = 2x-4
The equation for point (-6,8) is,
(y-8)= m1(x+6)...........(i)
and given equation is y = 2x-4............(ii)
Now, from equation (ii).
slope (m2)= 2 { as equation (ii) is in the form of y= mx+c where m is a slope}.
Now, For perpendicular,
m1×m2= -1
m1×2= -1
\(m1 = \frac{ - 1}{2} \)
Therefore, m1 = -1/2.
Putting, the value of m1 in equation (i).
(y-8) = -1/2×(x+6)
2(y-8)= -1(x+6)
2y - 16 = -x -6
x+2y-10 = 0......... is the required equation.
Hope it helps...
Consider the table that includes the input and output values of a function. Which answer classifies the function using finite differences? The function is quadratic with a constant second difference of –96. The function is quadratic with a constant second difference of 96. The function is cubic with a constant third difference of –96. The function is cubic with a constant third difference of 96.
Answer:
b, quadratic with constant second difference of 96
Step-by-step explanation:
The function is cubic with a constant third difference of 96.
What is Function?A function is defined as a relation between a set of inputs having one output each. In simple words, a function is a relationship between inputs where each input is related to exactly one output.
Using differences:
X f(x) first difference second difference third
3 39 - - -
5 187 (187-39)/2= 74 - -
7 551 (551-187)/7-5 = 182 182 - 74/2 = 54 -
9 1227 (1227-551)/(9-7)=338 338-182/2=78 78-54/2 = 12
11 2311 (2311-1227)/2=542 542-338/2=102 102-78/2 = 12
According to table,
The function is cubic, because the third average change rate is constant of 12.
12>0, so the third difference is >0 then -96 is false.
Thus, the function is cubic with a constant third difference of 96.
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Solve the augmented matrix by elementary row operations. 9. (4 points) Let A and B be 3 by 3 matrices with det (A) = 3 and det (b) = 5. Find the value of det (AB).
The value of determinant of the matrix det (AB) is 15.
Given matrices A and B are 3 by 3 matrices with
det (A) = 3 and
det (b) = 5.
We need to find the value of det (AB).
Writing the given matrices into the augmented matrix form gives [A | I] and [B | I] respectively.
By multiplying A and B, we get AB. Similarly, by multiplying I and I, we get I. We can then write AB into an augmented matrix form as [AB | I].
Therefore, we can solve the augmented matrix [AB | I] by row reducing [A | I] and [B | I] simultaneously using elementary row operations as shown below.

The determinant of AB can be calculated as det(AB) = det(A) × det(B)
= 3 × 5
= 15.
Conclusion: The value of det (AB) is 15.
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We need to find the value of determinant det(AB), using the formula: det(AB) = det(A)det(B)
=> det(AB) = 3 × 5
=> det(AB) = 15.
Hence, the value of det(AB) is 15.
The given matrices are A and B. Here, we need to determine the value of det(AB). To calculate the determinant of the product of two matrices, we can follow this rule:
det(AB) = det(A)det(B).
Given that: det(A) = 3
det(B) = 5
Now, let C = AB be the matrix product. Then,
det(C) = det(AB).
To evaluate det(C), we have to compute C first. We can use the following method to solve the augmented matrix by elementary row operations.
Given matrices A and B are: Matrix A and B:
[A|B] = [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0][A|B]
= [3 0 0|1 0 1] [0 3 0|0 1 1] [0 0 3|1 1 0].
We can see that the coefficient matrix is an identity matrix. So, we can directly evaluate the determinant of A to be 3.
det(A) = 3.
Therefore, det(AB) = det(A)det(B)
= 3 × 5
= 15.
Conclusion: Therefore, the value of det(AB) is 15.
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I need some help please
Answer:
x+2
hope this helps ;)
and cute pfp
Answer:
Step-by-step explanation:
x-1, because 3 fits the criteria, x>=1
Hi, can you help me answer this question please, thank you
We are asked to determine the p-values for a proportion that is greater than 0.51. Since we are asked about the hypothesis being greater then the p-value is given by:
\(p-\text{value}=P(z>3.065)\)This is a right-tailed test. To determine this probability we need to use the fact that:
\(P(z>3.065)=P(z<-3.065)\)replacing we get:
\(p-\text{value}=P(z<-3.065)\)Now, from the tables for z-scores in the normal distribution we get:
\(p-\text{value}=0.0011\)Therefore, the p-value is 0.0011
This is an online ACT prep guide problem that I’m having trouble on.Below, is the answer options to this problem.A. -4B. 1C. 6D. The limit does not exist.
Step 1
Given; A graph
Required; To find f(-4)
Step 2
The graph at x=-4 has a removable discontinuity. Therefore we can then conclude that f(-4) is undefined.
Hence, f(-4) is undefined
A removable discontinuity is a point on the graph that is undefined or does not fit into the rest of the graph.
Using suitable identity, find the value of 87^3+ 13^3/
87^2 −87 ×13 + 13^2
The value of the given expression [\(87^3+ 13^3/87^2 -87 * 13 + 13^2\)] by simplifying the numerator and denominator using suitable identities is 100.
We will first calculate the numerator:
As (\(a^3\) + \(b^3\)) = (a + b)(\(a^2\) - ab + \(b^2\)) :
\(87^3\) + \(13^3\) = (87 + 13)(\(87^2\) - \(87 * 13\) + \(13^2\))
= 100(\(87^2\) - 87 * 13 + \(13^2\))
Now, calculate the denominator:
\(87^2 - 87 * 13 + 13^2\)
As,(\(a^2 -2ab +b^2\)) =\((a - b)^2\):
\(87^2 - 87 * 13 + 13^2 = (87 - 13)^2\)
\(= 74^2\)
So by solving the equation further:
\((87^3+13^3) / (87^2- 87 * 13+13^2) = 100*(87^2- 87 *13 + 13^2)/(87^2 - 87 * 13 + 13^2)\)
As we can see the numerator and denominator are the same expressions (\(87^2 - 87 * 13 + 13^2\)). so, they cancel each other:
\((87^3 + 13^3) / (87^2 - 87 * 13 + 13^2) = 100\)
So, the value of the given expression is 100.
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-7(1-10)
Giving brainlist out again
Answer:
Step-by-step explanation:
-7(1-10)
10-1=9
9 – -7=2
a batter hits the ball and runs toward first base at a speed of 28 ft/s. at what rate (in ft/s) does the distance between the runner and second base change when the runner has run 20 ft? (round your answer to two decimal places.)
The rate at which the distance between the runner and second base changes is 28.71 ft/s.
Given, a batter hits the ball and runs toward first base at a speed of 28 ft/s. we have to find the rate (in ft/s) at which the distance between the runner and second base change when the runner has run 20 ft.
As, distance = speed × time
d = st
On differentiating both the sides
d' = s't + s
d' = 20/28 + 28
d' = 0.71 + 28
d' = 28.71
Hence, the rate at which the distance between the runner and second base changes is 28.71 ft/s.
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(2/3)³×(-3/4)²×(-1)²⁰⁰³
(2/5)²×(-5/12)³
Answer:
Step-by-step explanation:
\((-1)^{n} = -1 , if \ n \ is \ a \ odd \ integer\\\\\\\\(-1)^{2003} =-1 \\\\(\dfrac{-3}{4)}^{2}=\dfrac{3}{4}, \ as \ 2 \ is \ even \ number.\\\\(\dfrac{2}{3})^{3}*(\dfrac{-3}{4})^{2}*(-1)^{2003}=\dfrac{2^{3}}{3^{3}}*\dfrac{3^{2}}{4^{2}}*(-1)\\\\\\=\dfrac{2^{3}}{3^{3}}*\dfrac{3^{2}}{2^{4}}*(-1)\\\\\\=\dfrac{-1}{3^{3-2}*2^{4-3}}\\\\\\=\dfrac{-1}{3^{1}*2^{1}}\\\\=\dfrac{-1}{6}\)
\((\dfrac{2}{5})^{2}*(\dfrac{-5}{12})^{3}=\dfrac{2^{2}}{5^{2}}*\dfrac{(-5)^{3}}{(2^{2}*3)^{3}}\\\\\\=\dfrac{2^{2}}{5^{2}}*\dfrac{- 5^{3}}{2^{6}*3^{3}}\\\\\\= -\dfrac{5^{3-2}}{2^{6-2}*3^{3}}\\\\\\= -\dfrac{5}{2^{4}3^{3}}\\\\= -\dfrac{5}{16*3}\\\\\\= \dfrac{-5}{48}\)\(HINT: \dfrac{a^{m}}{a^{n}}=a^{m-n}, m >n\\\\\\\dfrac{a^{m}}{a^{n}}=\dfrac{1}{a^{n-m}}, n >m\\\\\\(a^{m})^{n}=a^{m*n}\)
What is the area of a regular decagon if the length of each side is 20 units?
Answer:
Area ≈ 3077.68
Explanation:
See attached image for equation
please solve :( i can’t figure it out whatsoever
Answer:
a) see attached
b) 15015 meters
Step-by-step explanation:
You want the voltage, current, resistance, and power for each component of the circuit shown in the diagram.
Voltage and current lawsThe relevant circuit relations are ...
Kirchoff's voltage law: the sum of voltages around a loop is zeroKirchoff's current law: the sum of currents into a node is zeroOhm's law: voltage is the product of current and resistanceSeries: elements in series have the same currentParallel: elements in parallel have the same voltageVoltageGiven current and resistance for element 1, we immediately know its voltage is ...
V = IR = (4)(10) = 40 . . . . volts
Given the voltage on element 3, we know that parallel element 2 has the same voltage: 30 volts.
Given the voltage at T is 90 volts, the sum of voltages on elements 1, 2, and 4 must be 90 volts. That means the voltage on element 4 is ...
90 -(40 +30) = 20
CurrentThe current in elements 1, 4, and T are all the same, because these elements are in series. They are all 4 amperes.
That 4 ampere current is split between elements 2 and 3. The table tells us that element 2 has a current of 1 ampere, so element 3 must have a current of ...
4 - 1 = 3 . . . . amperes
ResistanceThe resistance of each element is the ratio of voltage to current:
R = V/I
Dividing the V column by the I column gives the values in the R column.
Note that power source T does not have a resistance of 22.5 ohms. Rather, it is supplying power to a circuit with an equivalent resistance of 22.5 ohms.
PowerPower is the product of voltage and current. Multiplying the V and I columns gives the value in the P column.
Note that the power supplied by the source T is the sum of the powers in the load elements.
b) WavelengthWe found that the transmitter is receiving a power of 90 watts, so its operating frequency is ...
(90 W)×(222 Hz/W) = 19980 Hz
Then the wavelength is ...
λ = c/f
λ = (3×10⁸ m/s)/(19980 cycles/s) ≈ 15015 m/cycle
The wavelength of the broadcast is about 15015 meters.
__
Additional comment
The voltage and current relations are "real" and used by circuit analysts everywhere. The relationship of frequency and power is "made up" specifically for this problem. You will likely never see such a relationship again, and certainly not in "real life."
Kirchoff's voltage law (KVL) means the sum of voltage rises (as at T) will be the sum of voltage drops (across elements 1, 2, 4).
Kirchoff's current law (KCL) means the sum of currents into a node is equal to the sum of currents out of the node. At the node between elements 1 and 2, this means the 4 amps from element 1 into the node is equal to the sum of the currents out of the node: 1 amp into element 2 and the 3 amps into element 3.
As with much of math and physics, there are a number of relations that can come into play in any given problem. You are expected to remember them all (or have a ready reference).
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which expression is equivalent to f(x)=3x+2
Mr. Joseph bought 9 pounds of fertilizer for his lawn. He uses 2 2/3 pounds for his backyard and 1 2/9 for his front yard. How much fertilizer is ;eft?
what is -2(3x+12y-5-17x-16y+4) simplifyed
Answer: 28x+8y+2 .
= -2 (-14x-4y-1)
= 28x + 8y + 2
Step-by-step explanation:
Answer: 28x + 8y + 2
Step-by-step explanation:
-2(3x+12y-5-17x-16y+4)
= -2(3x-17x+12y-16y-5+4)
= -2(-14x-4y-1)
= -2(-14x) -2(-4y) -2(-1)
= 28x+8y+2
what is the scale factor pls help
Answer:
im pretty sure its 2
Step-by-step explanation:
Answer:
4
Step-by-step explanaiton:
B is 4x bigger than A
If Karis can run 1 mile in 10 minutes, how many
miles could he run in 1 hour at this same rate?
Answer:
6 miles per hour or 6 miles
Step-by-step explanation:
If Karis can run 1 mile in 10 minutes, how many miles could he run in 1 hour at this same rate?
1 mile = 10 minutes
there are 60 minutes in 1 hour
10 minutes × 60 minutes = 6
6 × 1 mile = 6 miles so the answer is 6 mile per hour
the larger circle has center $o$ and passes through $d$. the smaller circle has diameter $od$. what percent of the larger circle's area is gray?
25% is the larger circle area is gray.
Area of a Circle: The area of a circle is pi times the radius squared.
To calculate the area of the circle we have the formula:
A = π r²-----(1)
where
A=area
r=radius.
First, we have to analyze the given data, the large circle center o passes through d, so
Gray circle area=π*(radius)^2----(2)
The radius of the smaller circle = OD/2 substitute in (2)
Gray circle area=π*(OD/2)^2
Gray circle area=π*OD^2/4
Larger circle area=π*(radius)2
radius of the larger circle = OD
larger circle area=π*OD^2
To know the percentage of a large circle we have a small formula:
gray circle area/large circle area--------(3)
=π*OD^2/4/π*OD^2
=π*OD^2/4*1/π*OD^2=1/4
=25/100
=25%
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Which of these values for P and a will cause the function f(x) = Pa* to be an
exponential growth function?
A. P= 8; a = 1
P= 1²;
gia
OC. P=;a=
OD. P= 8; a = 9
OB. P=
SUBMIT
Among the given options, the values P = 8 and a = 9 will cause the function f(x) = Pa^x to be an exponential growth function. Option D
Answer to the aforementioned questionTo determine which values of P and a will cause the function f(x) = Pa^x to be an exponential growth function, we need to consider the properties of exponential growth.
In an exponential growth function, the base (a) must be greater than 1. This is because the exponential function will continuously increase as x increases when a > 1.
Therefore, among the given options, the values P = 8 and a = 9 will cause the function f(x) = Pa^x to be an exponential growth function.
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Margie is 4.25 feet tall . The maple tree in her backyard is 5.5 times taller than her. How tall is the maple tree?
Answer:
Given that,
Margie is 4.25 feet tall
The maple tree in her backyard is 5.5 times taller than her.
To find the height of the maple tree.
we get,
Height of the maple tree is,
\(=4.25\times5.5\)\(=23.375\)Maple tree is 23.375 feet tall.