A random sample of 10 recent college graduates found that starting salaries for accountants in new york city had a mean of $47,589 and a standard deviation of $11,364. There are no outliers in the sample data set. Construct a 95% confidence interval for the average starting salary of all accountants in the city.

Answer:

21 1/3

Step-by-step explanation:

First, make fractions into decimals:

1/2 = 0.5

1/4 = 0.25

0.5x + 0.25x = 16

0.75x = 16

--------   -------

0.75      0.75

     x = 21 1/3

Hope this helped.

It took 1700 J of work to stretch a spring from its natural length of 2 m to a length of 6 m. The spring constant k will be 212.5 N/m.

The potential energy stored in a spring is given by the formula:

PE = (1/2) kx^2

where k is the spring constant, x is the displacement from the equilibrium position, and PE is the potential energy.

In this problem, the spring is stretched from its natural length of 2 m to a length of 6 m, so the displacement is x = 6 m - 2 m = 4 m.

The work done on the spring is equal to the change in potential energy, so:

Work = PE final - PE initial

1700 J = (1/2) k(4² - (1/2) k(0)²

1700 J = 8k

k = 212.5 N/m

Therefore, the spring constant is 212.5 N/m.

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Answer:

1 over 4

Step-by-step explanation:

Answer:

the answer is \(\frac{1}{-4\\}\)

Step-by-step explanation:

slope= \(y_{2}\)-\(y_{1}\)

           \(x_{2}\)-\(x_{1}\)   so 3-2=1 and then 3-7=-4

Answer:

x=3

Step-by-step explanation:

The whole line (DF) equals 9x - 39. So you need to make that equal to 47+3x+10 and work out like so. I hope this helps!

The values of x and y the triangles to the fight congruent are x = 3 and

y = 1.

What is congruent triangles?

Triangles with the same size and shape are said to be congruent. This implies that the corresponding sides and angles are both equal. Without comparing every angle and side of the two triangles, we can determine whether two triangles are congruent.

If given these triangles are congruent then all corresponding side must be equal

As we can see that both triangle are right triangle

Therefore hypotenuse of one triangle equal to another

x+1  = 4y   ..... (A)

And lenght ( height)  of one  must equal to another triangle

x = y +2          .... (B)

therefore

Plug the value of x = y + 2 in equation A

y + 2 + 1 = 4y

        3y = 3

          y = 1

and x = y+2

x = 1 + 2

x = 3

Hence, the values of x and y the triangles to the fight congruent are

x = 3 and y = 1.

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Complete question:

Complete question is attached below.

Answer:

Step-by-step explanation:

Answer:

the answer to this question is b

Answer:

A

Step-by-step explanation:

if (x1,y1) and (x2,y2) are the extremities of diameter,then eq. of circle is

(x-x1)(x-x2)+(y-y1)(y-y2)=0

reqd. eq. is (x+1)(x-5)+(y+9)(y-1)=0

\(x^{2} +x-5x-5+y^2+9y-y-9=0\\x^{2} -4x+y^2+8y-14=0\\compare with x^2+y^2+2gx+2fy+c=0\\center (-g,-f) \\radius r=\sqrt{g^2+f^2-c}\)

center is (2,-4)

r=√(2²+(-4)²-(-14))

=√(4+16+14)

=√(34)

eq. of circle is (x-2)²+(y+4)²=34

or

(x²-4x)+(y²+8y)=14

(x²-4x+4)+(y²+8y+16)=14+4+16

(x-2)²+(y+4)²=34

Using strong induction, we can prove that the square root of -2 is irrational by showing that it cannot be expressed as a fraction of coprime odd integers.

To prove that √-2 is irrational using strong induction, we need to show that for any natural number n, if the square root of -2 can be expressed as a fraction a/b, where a and b are coprime integers, then a and b must be odd.

We can start by using the base case, n = 1. Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers.

Now, let's assume that for all n ≤ k, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. We want to prove that this also holds for n = k+1.

Assume that √-2 can be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Then, we have

√-2 = a/b

Squaring both sides gives

-2 = a^2/b^2

Multiplying both sides by b^2 gives

-2b^2 = a^2

This implies that a^2 is even, and therefore a is also even. We can express a as 2k for some integer k, which means

-2b^2 = (2k)^2

Simplifying, we get

-2b^2 = 4k^2

Dividing both sides by -2 gives

b^2 = -2k^2

This implies that b^2 is even, which means that b is also even. However, this contradicts our assumption that a and b are coprime integers with a and b odd. Therefore, √-2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd.

By strong induction, we have proven that for any natural number n, the square root of -2 cannot be expressed as a fraction a/b where a and b are coprime integers with a and b odd. Therefore, √-2 is irrational.

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Answer:

false

Step-by-step explanation:

False.

Access supports a wide range of built-in functions and operators that can be used to create calculated fields. These functions and operators include mathematical functions (such as multiplication, division, exponentiation), string functions (such as concatenation, trimming, and formatting), date and time functions, aggregate functions (such as sum, average, count), and more.

In addition, Access also allows you to create user-defined functions using VBA (Visual Basic for Applications), which can be used to perform custom calculations on your data.

Therefore, the statement "the only calculated fields you can create in Access are those involving addition and subtraction" is false.

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Answer:

39

Step-by-step explanation:

i think

Answer:

C

Step-by-step explanation:

Answer:

Step-by-step explanation:

C on ed 2020

The congruency statement which is true among the answer choices is;

According to the task content, the initial transformation is; Triangle GHI is rotated 90Degrees clockwise and then reflected over the y-axis.

On this note, the congruency which are true regarding the transformation are;

This follows from the fact that the transformation.does not involved dilation by means of a scale factor and hence, size remains equal and all angle measures remain the same.

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Answer:

7/12

Step-by-step explanation:

You need to get -7 to be a positive number so that its zero

-7+7=0

Then just add the denominator!!!

0/12=0

I hope this helps!!!!

The graph of the parametric equations x = -2cos(t) and y = -sin(t) within the range 0 ≤ t < 2π is an ellipse centered at the origin, with the major axis along the x-axis and a minor axis along the y-axis.

To sketch the graph of the parametric equations x = -2cos(t) and y = -sin(t), where 0 ≤ t < 2π, we need to plot the coordinates (x, y) for each value of t within the given range.

1. Start by choosing values of t within the given range, such as t = 0, π/4, π/2, π, 3π/4, and 2π.

2. Substitute each value of t into the equations to find the corresponding values of x and y. For example, when t = 0, x = -2cos(0) = -2 and y = -sin(0) = 0.

3. Plot the obtained coordinates (x, y) on a graph, using a coordinate system with the x-axis and y-axis. Repeat this step for each value of t.

4. Connect the plotted points with a smooth curve to obtain the graph of the parametric equations.

The graph will be an ellipse centered at the origin, with the major axis along the x-axis and a minor axis along the y-axis. It will have a vertical compression and a horizontal stretch due to the coefficients -2 and -1 in the equations.

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The speed of the current is 3 miles per hour. Answer: The speed of the current is 3 miles per hour.

.Let "t" be the time taken to travel 78 miles downstream and "t" be the time taken to travel 42 miles upstream.

The distance traveled downstream is 78 miles, so we can write:78 = (10 + x)t ... equation (1)

The distance traveled upstream is 42 miles, so we can write:42 = (10 - x)t ... equation (2)

Solving equations (1) and (2) for "t", we get:t = 78 / (10 + x) ... equation (3)

t = 42 / (10 - x) ... equation (4)

We can equate the value of "t" from equations (3) and (4) since the time is the same.

We get:78 / (10 + x) = 42 / (10 - x)

Multiplying both sides by (10 + x)(10 - x), we get:78(10 - x) = 42(10 + x)

Simplifying, we get:780 - 78x = 420 + 42x

Adding 78x and subtracting 420 from both sides, we get:120x = 360x = 3

Therefore, the speed of the current is 3 miles per hour. Answer: The speed of the current is 3 miles per hour.

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Answer:

3.93700787402, almost  4

Step-by-step explanation:

10 ÷ 2.54

3 × 2.50 = 7.50

3 × 0.04 = 0.12

7.50 + 0.12 = 7.65

7.65 + 2.54 = 10.19

The precise number is use calculator.

Answer:

z=53

Step-by-step explanation:

Answer:

Step-by-step explanation:

The measure of each individual exterior angle in a polygon can be found using the following formula:

Exterior angle measure = 360° / number of sides

This formula assumes that the polygon is a regular polygon, meaning that all sides are of equal length and all interior angles are congruent. For an irregular polygon, the exterior angle measures will vary.

The only value of k that makes Ax=0 have non-trivial solutions is k=0. Option (C) is the correct answer.

To determine the values of k such that Ax=0 has non-trivial solutions, we need to find the values of k that make the determinant of the matrix A equal to zero.

This is because the determinant of A is equal to the product of its eigenvalues, and a non-trivial solution exists when at least one of these eigenvalues is zero.
Using the formula for the determinant of a 3x3 matrix, we have:
det(A) = 1 x (-20k) - 0 x (-8k) + 4 x (-2)(-2k) = -20k + 16k = -4k
Setting det(A) equal to zero, we get:
-4k = 0
Solving for k, we get:
k = 0
To find the values of k, if any, such that Ax=0 has non-trivial solutions, we need to find the values of k that make the matrix A singular, i.e., that make the determinant of A equal to 0.

If the determinant of A is not 0, then the only solution to Ax=0 is the trivial solution (x=0).

Using the formula for a 3x3 determinant, we have:

det(A) = 1 x  (1 x (-10k) - 4 x (-2k)) - 0 x (0 x (-10k) - 4 x (-2))) + 4 x  (0 x (-2k) - 1 x (-2)))

det(A) = 10k - 8k

det(A) = 2k

So, the determinant of A is equal to 2k.

If 2k = 0, then det(A) = 0 and the matrix A is singular.

This occurs when k = 0.
Therefore, the only value of k that makes Ax = 0 have non-trivial solutions is k=0. Option (C) is the correct answer.

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Answer:

6.5

Step-by-step explanation:

all you have to do is substitute x with 2.5 in the equation and you can find y.

To arrive at the same location, the person would have to walk 25 km due north and 6.2 km due west.

This can be calculated using the Pythagorean theorem: c² = a² + b², where c is the total distance and a and b are the distance traveled due north and due west, respectively.
In this case, c = 11.2 km and a = 35 km. Therefore, a² + b² = 11.2² and b = √(11.2² - 35²) = 6.2 km.
Therefore, the person must travel 25 km due north and 6.2 km due west to arrive at the same location.

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Answer:

2/5 mile

Step-by-step explanation:

Let's give the total distance the variable x.

1/4x = 1/10

x = 4/10

x = 2/5

The hash of the given message is 135.

In computing, a message digest is a fixed-sized string of bytes that represents the original data's cryptographic hash. This hash is used to authenticate a message, guaranteeing the integrity of the data in the message.

Here, it is given the message m = 23  

The formula to calculate hash is him) - (m*7;2 MOD 7793.

So, let's calculate the hash : him) - (m*7;2 MOD 7793(him) - (23*7;2 MOD 7793

⇒ (8*23) - (49 MOD 7793)

⇒ 184 - 49= 135.

So, the hash of the given message is 135.

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Answer:

B. 3.2

Step-by-step explanation:

5 companies have 0 computers.

10 companies have 1 computer.

10 companies have 2 computers.

30 companies have 3 computers.

25 companies have 4 computers.

20 companies have 5 computers.

To find mean:

0 x 5 = 0

10 x 1 = 10

10 x 2 = 20

30 x 3 = 90

25 x 4 = 100

20 x 5 = 100

100 + 100 + 90 + 20 + 10 + 0 = 320

20 + 25 + 30 + 10 + 10 + 5 = 100

100 companies were surveyed.

100 companies use 320 computers in total.

320 / 100 = 3.2