A PITTMAN ID33000 series engine having the following data expressed in the international system, for a nominal voltage of 90 V.
Terminal resistance: 1.33 Ohms;
Inductance: 4.08mH;
Constant Torque (KT): 0.119 N.m/A;
Voltage constant: 0.119 V/rad/s;
a) Calculate and draw the points and the load line for the PITTMAN engine. Express the correct units.
b) A P.M.D.C in which, it increased from Gradually the input voltage was obtained that with a V input= 2.1 V and a current, i=0.12 A, it is managed to start turning the motor shaft. Calculate the input power required to achieve the "no-load current", for that motor.

Answer:

I am not sure it's confusing

Answer:

do the wam wam

Explanation:

The letter "k" in the word "quartile" does not indicate that it is Greek. It is more likely influenced by the Latin origin of the word.

In the English language, the letter "k" is not typically associated with Greek words. Greek words usually use the Greek alphabet, which does not include the letter "k" but has a similar-sounding letter "κ" (kappa). The word "quartile" itself is derived from the Latin word "quartus," meaning "fourth." It is used in statistics to divide a distribution into four equal parts.

Greek words, on the other hand, often use letters like alpha (α), beta (β), gamma (γ), and so on. These letters are distinct from the letter "k." For example, the Greek word for "fourth" is "τέταρτος" (tétartos), which does not have a "k" sound.

Therefore, in the context of the word "quartile," the letter "k" does not indicate that it is Greek. It is more likely influenced by the Latin origin of the word.

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Answer: hello your question is incomplete below is the complete question

An ideal Otto Cycle has a compression ratio of 9.2 and uses air as the working fluid. At the beginning of the compression process, air is at 98kPa and 20C. The pressure is doubled during the constant volume heat addition process. Assuming constant specific heats, determine:the amount of heat transferred to the air

answer : 609.804 kj/kg

Explanation:

Given data:

compression ratio (r)= 9.2

pressure given(p1) = 98 kPa

Initial temperature =  20 + 273 = 293 k

pressure during constant volume heat addition process = 2p1

note : specific heat at constant pressure and specific heat at  constant volume varies with temperature

we use T = 300k because it is closest to T1 = 293 k

hence at T = 300 K ( ideal gas properties of air )

             \(u_{1}\)   = 214.07 Kj/kg

            \(v _{r1}\) = 621.2

To get  \(v_{r2}\) = \(v_{r1} * \frac{v_{2} }{r}\) = 621.2 * 1 / 9.2 = 67.52

ALSO    at \(v_{r2}\) = 67.52 ( from ideal gas properties )

                \(u_{2}\) = 518.9 kj/kg

                T2 = 708.32 k

next we apply the gas equation

\(\frac{p1v1}{T1} = \frac{p2v2}{T2}\)

hence  p2 = (9.2) * \(\frac{708.32}{293} * 98\) = 2179.59 kpa

to determine T3  due to the constant volume heat addition

\(\frac{T3}{T2} = \frac{P3}{P2}\)

Hence T3 = p3/p2 * T2 = 2( 708.32 ) = 1416.64 k

At T3 = 1416.64 k ( from ideal gas properties )

\(u_{3}\) = 1128.704 kj/kg

\(v_{r3}\) = 8.592

Determine the amount of heat transferred to the air

\(q_{in} = ( u_{3} - u_{2} )\)

     = ( 1128.704  - 518.9 )

     = 609.804 kj/kg

Answer:

A, Hazardous Material

Explanation: Because that defines a hazardous material. A Safety Data Sheet isn't a material, so it can cause harm.

Answer:

Explanation:

write each force in terms of magnitude and directions  

Fx = F sin Ф

Fy = F cos Ф

where Ф is to be measured from x axis.

∑F at y = o

FAy + FBy + FCy + FDy + FEy + FGy = 0

∑F at x = o

FAx + FBx + FCx + FDx + FEx + FGx = 0

Let  

FA = FA sin (110)   +   FA cos (110)

FB = 20 sin (270)  +  20 cos (270)

FC = 16 sin (140)    +  16 cos (140)

FD = 9 sin (40)       +  9 cos (40)

FE = 20 sin (270)    +  20 cos (270)

FG = FG sin (50)     +  FG cos (50)

add x and y forces:

FAx + FBx + FCx + FDx + FEx + FGx = 0

FAy + FBy + FCy + FDy + FEy + FGy = 0

FA sin (110)  + 0  + 16 sin (140)  + 9 sin (40)  + 0   + FG sin (50) = 0

FA cos (110) - 20 + 16 cos (140) + 9 cos (40) - 20 + FG cos (50 = 0

FA sin (110)  + 0  + 10.285  + 5.785  + 0   + FG sin (50) = 0

FA cos (110) - 20 - 12.257 + 6.894 - 20 + FG cos (50) = 0

FA sin (110)  + 16.070 + FG sin (50) = 0        

FA cos (110) - 45.363 + FG cos (50) = 0

solving for FA, and FG

FA = 13 kN

FG = 15.3 kN

From the given information, we can say that the sum of the upward forces is equivalent to the sum of the downward forces.

From the diagram, equating the component of the upward forces and the downward forces, we have:

\(\mathbf{-F_a sin 70 +F_c sin 40+F_d sin 40 + F_g sin50= F_b+F_e}\) --- (1)

Also, the sum of the horizontal positive x-axis as well as the horizontal negative x-axis can be computed as:

\(\mathbf{F_g cos 50 +F_d cos 40 = F_c cos 40 +F_a cos 70 --- (2)}\)

If:

\(F_B = F_E = 20 \ kN \\ \\ F_c = 16 \ kN \\ \\ F_D= 9\ kN\)

Then, from equation (1), we can have the following:

\(\mathbf{F_a sin 70 + 16 sin 40 + 9 sin40 + F_gsin 50 = (20 + 20 )kN}\)

collecting like terms;

\(\mathbf{F_a sin 70 + F_gsin 50 = 40 - 16 sin 40 - 9 sin40 }\)

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

From equation (2);

\(\mathbf{F_g cos 50 + 9cos 40 = 16 cos 40 + F_a cos 70}\)

collecting like terms:

\(\mathbf{F_g cos 50 -F_a cos 70 =16cos 40 -9cos 40}\)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 ----- (let \ this \ be \ equation (4))}\)

Suppose we equate (3) and (4) together using the elimination method;

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\) --- (3)

\(\mathbf{-F_a cos 70 +F_g cos 50 =5.36 --- (4)}\)

Let's multiply (3) with ( cos 70 ) and (4) with (sin 70);

Then, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

Adding both previous equations together, we have:

\(\mathbf{F_a sin 70 cos 70 + F_gsin 50 cos 70 =23.93 cos 70}\)

\(\mathbf{-F_a cos 70 sin 70 +F_g cos 50 sin 70 =5.36 sin 70}\)

\(\mathbf{(0 + F_g(sin 50 cos 70 + sin70 cos50) = 23.93 cos 70 + 5.36 sin 70)}\)

\(\mathbf{( F_g(0.262 + 0.604)) =(8.19 + 5.04)}\)

\(\mathbf{( F_g(0.866)) =(13.23)}\)

\(\mathbf{ F_g =\dfrac{(13.23)}{(0.866)}}\)

\(\mathbf{ F_g =15.28 \ N}\)

Replacing the value of \(\mathbf{F_g}\) into equation (3), to solve for \(\mathbf{F_a}\), we have:

\(\mathbf{F_a sin 70 + F_gsin 50 =23.93}\)

\(\mathbf{F_a sin 70 + 15.28sin 50 =23.93} \\ \\ \mathbf{F_a sin 70 +11.71 =23.93} \\ \\ \mathbf{F_a sin 70 =23.93-11.71 } \\ \\ \mathbf{F_a sin 70 =12.22 } \\ \\ \mathbf{F_a =\dfrac{12.22 }{sin 70}} \\ \\\)

\(\mathbf{F_a =13.01 \ N}\)

Therefore, we can conclude that the magnitudes of \(\mathbf{F_a}\) and \(\mathbf{F_g}\) are 13.0 N and 15.28 N respectively.

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Machined parts can be classified as rotational or nonrotational. The two examples of operations that create nonrotational geometries are option (a) boring and option (d) planing.

Boring is a machining process that enlarges an existing hole to a desired diameter, and the resulting geometry is a straight cylindrical shape with parallel walls. Planing, on the other hand, is a process that produces flat surfaces by removing material in a linear motion. The resulting geometry is a flat surface with straight edges.

Drilling and turning are examples of operations that create rotational geometries. Drilling involves creating a hole by removing material in a rotary motion, resulting in a cylindrical shape with a circular cross-section. Turning, on the other hand, is a process that creates round geometries by removing material with a rotating cutting tool.

Milling is an operation that can create both rotational and nonrotational geometries, depending on the type of milling process used. Some milling processes involve rotating the workpiece, resulting in rotational geometries, while others involve moving the cutting tool in a linear motion, resulting in nonrotational geometries.

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Answer:

or is the strongest evenger she hulk

Explanation:

?????????

Answer:

Thor!

Explanation:

In Thor: Ragnarok he beat the Hulk in order for Hulk to win thor had to be electrocuted and in Avengers: Endgame Thor is seen holding open the  "Floodgates" and withstanding the radiation from a dying star, also the fact that Thor is a god means that he is all powerful and the rightful heir to the throne to Asgard, plus the fact that he has defeated Loki multiple times a feat that not even the Hulk has done.

The factors that  you need to consider when preparing to move gondolas are:

In choosing gondola one need to look at some  factor in decisions such as height.

Know that it is good to  consider the construction material and also the center wall configuration for its building also.

The factors that  you need to consider when preparing to move gondolas are:

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A flexible manufacturing system is typically built into machine and routing.

A flexible manufacturing system (FMS) is a type of manufacturing system that is designed to be easily adaptable to changes in the product being manufactured or the production process itself. An FMS typically consists of a group of automated machines that are connected by a material-handling system and controlled by a central computer system.

This allows for the production of a wide variety of products in small to medium batches with minimal setup time and labor costs. FMSs are often used in industries such as automotive, electronics, and aerospace.

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If a pilot-operated check valve (POC) does not check flow, you will see a. erratic actuator movement.

Pilot operated test valves paintings through permitting loose float from the inlet port via the opening port. Supplying a pilot strain to the pilot port permits float withinside the contrary direction. Air strain on pinnacle of the poppet meeting opens the seal permitting air to float freely.

An actuator fault is a form of failure affecting the machine inputs. Due to strange operation or fabric aging, actuator faults might also additionally arise withinside the machine. An actuator may be represented through additive and/or multiplicative fault.

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The biggest challenge in cracking pre-shared keys is obtaining the encrypted passwords in the first place. If the password hashes are not obtainable, cracking becomes infeasible.

Pre-shared key password cracking entails making an effort to identify the original password or key that was used to encrypt data or safeguard a system. To guess the original password, different strategies like brute-force, dictionary attacks, or hybrid assaults are generally used after getting the encrypted password hashes, which are mathematical representations of the original password.

The sheer volume of potential password combinations that must be examined presents the biggest obstacle to breaking pre-shared keys. The quantity of possible password combinations and the computing power at hand directly influence how long it takes to crack a password. Therefore, even with powerful computers, breaking strong passwords that are lengthy and contain a combination of letters, numbers, and symbols might take a while.

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Answer:

It is true that the sampling distribution of the proportions is approximately a normal distribution.

Explanation:

Solution

Given that:

N = 50

P= 0.8

Thus

p ^ =√p(1-p)/n

p ^=√0.8 (1-0.8)/50

p ^= 0.0566

Therefore,we conclude that the sampling distribution of the proportions is approximately a normal distribution.

False.A parallel-in, serial-out (PISO) shift register accepts the data bits in parallel and transfers them out one bit at a time in a serial fashion.

In a PISO shift register, the data bits are loaded simultaneously into the parallel inputs of the register. These parallel inputs are typically represented as D0, D1, D2, ..., Dn, where n is the number of parallel inputs. Once the data is loaded, the shift register sequentially outputs the bits in a serial manner, starting from the most significant bit (MSB) to the least significant bit (LSB).

The serial output is typically obtained from a single output pin, often labeled as Q or Q0. With each clock pulse, the shift register shifts the bits internally, and the next bit in the sequence is made available at the serial output.Therefore, the statement is false as a parallel-in, serial-out shift register accepts the data bits in parallel but transfers them out one bit at a time in a serial manner.

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noun. : the ratio of the maximum demand in the course of an assigned length upon an electric-power system to the load absolutely linked all through that time expressed usually in per cent.

Generally, the fee of demand factor is much less than 1. It is due to the fact the most demand on the power station is normally much less than the related load to the power station. The understanding of demand issue is important in deciding the capability of tools of the power plant.

Demand Factor = Maximum demand / Total related load = 1.5 Kw / 12 Kw = 0.125.

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Power delivered to the resistor in watts is 2.5 watts

Given:

Energy absorbed by resistor = 540 J

Time taken by resistor = 3.6 min

Find:

Power delivered to the resistor in watts

Computation:

Time taken by resistor = 3.6 min

Time taken by resistor = 3.6 × 60

Time taken by resistor = 216 sec

We know that;

Energy = Power × Time

So,

540 = Power × 216

Power = 540 / 216

Power = 2.5 watts

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Answer:

89375 N

Explanation:

Rearrange the formula for normal stress for F:

\(\sigma=\frac{F}{A}\)

\(F=\sigma*A\)

Convert given values to base units:

275 MPa = \(275*10^{6}\) Pa

325 \(mm^{2}\) = 0.000325 \(m^{2}\)

Substituting in given values:

F = \((275*10^{6})*(0.000325)=89375\) N

The advantage of the Floyd algorithm is its versatility. Numerous problems can be resolved with the algorithm. A disadvantage is the algorithm is quite complex and can be difficult to understand.

Only two pointers—each moving through the succession at a different speed—are used in Floyd's method, which is a pointer-based algorithm. In reference to Aesop's story The Tortoises and the Hare, it is also known as the "turtle and the hare algorithm."

The Floyd algorithm is applied to find that shortest route via the weighted graph between each vertex. Both direct and undirected graphs can be used with this approach, but the graph having negative cycles cannot be used. Its space complexity is O, and its time complexity is O(N-L), where N represents the number of nodes in the linked list and L is the length of the loop (1).

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Answer:2%

When the voltages between the three phases are not equal, the current increases dramatically in the motor winding's, and if allowed to continue, the motor will be damaged.

Explanation:

Answer:

a c 1 museum is a patient who by think and pay the the price

Note that the resilient component that defines a set of activities that are triggered when specific conditions are met is: Rules (Option B)

A Rule is a component in the Resilient framework that defines a set of activities that are triggered automatically when specific conditions are met.

Rules are used to automate repetitive or time-sensitive tasks and can be based on various inputs, such as events, incidents, or changes in data. Rules allow organizations to streamline their operations, increase efficiency, and respond to incidents more quickly.

They also help to ensure that standard processes are followed consistently, reducing the risk of human error.

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Full Question:

What is the Resilient component that defines a set of activities that are triggered when specific conditions are met?

Select one:

Tasks

Rules

Phases

Functions

Answer:

Explanation:

The 7 Habits of Highly Effective People, is a book written and first published in 1989. It is a business and self-help book that was written by Stephen Covey. The seven habits include

Being proactive

Starting anything with the end in mind

First things first

Always thinking towards a win-win situation

Seeking initially to understand, then going on to want to be understood

Synergize, and lastly

Growing

Answer:

they were updated rather than being created

Answer:

Invention is about creating something new, while innovation introduces the concept of “use” of an idea or method.

According to the HST data, very distant (and early) galaxies tend to be smaller, bluer, and more irregular than modern ones.

The Hubble Space Telescope (HST) has allowed astronomers to observe galaxies at great distances and thus look back in time to see what galaxies were like in the early universe. The observations show that distant galaxies tend to be smaller, bluer, and more irregular than modern galaxies. This is because galaxies have evolved over time, with smaller galaxies merging to form larger ones and the formation of new stars slowing down over time. The blue color of distant galaxies is due to the fact that they are forming new stars at a much higher rate than modern galaxies. The irregular shape of distant galaxies is due to the fact that they have not yet formed into the well-defined spiral and elliptical shapes that are more common in modern galaxies.

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The required belt width is approximately 18.86 mm.

v = π * D * N / 60

where:

D = Diameter of the pulley (300 mm or 0.3 m)

N = Speed of the pulley (1600 r.p.m)

v = π * 0.3 * 1600 / 60 ≈ 25.13 m/s

Next, we need to find the slack side tension (T2) using the following formula:

T2 = T1 * e^(-μ * θ)

where:

e = Euler's number (approximately 2.718)

θ needs to be converted to radians:

θ_rad = θ * (π / 180)

θ_rad = 210 * (π / 180) ≈ 3.665 radians

Now we can calculate T2:

T2 = 8 * e^(-0.22 * 3.665) ≈ 4.55 N/mm

Now, we can solve the equation for the belt width (w):

P = (T1 - T2) * v * μ * θ / (9.81 * 1000)

7.5 * 1000 = (8w - 4.55w) * 25.13 * 0.22 * 3.665 / (9.81 * 1000)

w = (7.5 * 1000 * 9.81) / ((8 - 4.55) * 25.13 * 0.22 * 3.665)

w ≈ 18.86 mm

So, the required belt width is approximately 18.86 mm.

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A) The frequency of v is 500 Hz (to three significant figures). B) The correct expression for v is: v = 93.4 * sin(167πt + 30.0°) V

A) To determine the frequency of the sinusoidal voltage, we need to find the time period between two consecutive zero crossings. Given that the voltage is zero at t = -2 ms and next zero at t ms, the time period (T) can be calculated as:

T = (t - (-2 ms)) = t + 2 ms

Since the voltage is periodic, the time period is the reciprocal of the frequency (f), so we can express the frequency as:

f = 1 / T = 1 / (t + 2 ms)

To express the answer in hertz (Hz) to three significant figures, we can substitute the given value of t into the equation.

Answer: The frequency of v is 500 Hz (to three significant figures).

B) The expression for v can be determined by analyzing the given information. We know that the voltage is 80.9 V at t = 0 and that it is a sinusoidal waveform. We can express it in the form:

v = A * sin(ωt + φ)

where A is the amplitude, ω is the angular frequency, t is time, and φ is the phase angle.

Since the voltage is going positive at t = -2 ms, we can deduce that the phase angle is positive. Moreover, the phase angle determines whether the waveform is a sine or cosine function. If the waveform is zero at t = -2 ms and going positive, the expression should be a sine function.

Therefore, the correct expression for v is: v = 93.4 * sin(167πt + 30.0°) V

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Answer:

  A accountant

  D teacher

  B cook

  C beautician

Explanation:

C is on the right of the accountant, so D (opposite C) is the teacher. The accountant is to the right of the teacher, so cannot be B, and must be A. Then B (opposite A) is the cook, and C (left of B) is the beautician.

__

Clockwise from A:

  A accountant

  D teacher

  B cook

  C beautician

The effective impedance (per phase) of the system seen by the source, assuming an ideal transmission line, would be:

Z_src = j0.5 + (50/14) + (18/14)(0.463 + j0.0772 + (-j0.324)) = j0.5 + 3.571 + 0.848 = 4.419 + j0.5

The effective impedance (per phase) of the system seen by the source for the given setup would be 4.419 + j0.5 Ω, when a capacitor bank of -j0.324 Ω is added parallel to the load.

This is calculated by taking the total impedance of the load side (50 Ω) and the transmission line (j0.5 Ω) referred to the primary side of the step-up transformer (1:14 turn ratio) and then adding the parallel capacitor (-j0.324 Ω).

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Answer: Your welcome!

Explanation:

Current I = 200/√(10^2 + (2π × 50 × 0.1)^2) = 200/√1000 = 14.14 A

Power P = I2R = 14.142 × 10 = 141.4 W

Power factor PF = cos φ = R/√(R2 + X2) = 10/√(102 + (2π × 50 × 0.1)2) = 0.99

Voltage drop across resistance VR = I × R = 14.14 × 10 = 141.4 V

Voltage drop across condenser VC = I × X = 14.14 × 2π × 50 × 0.1 = 44.18 V

The phasor diagram is shown below:

Phasor Diagram

V = 200 V at 0°

I = 14.14 A at -90°

VR = 141.4 V at 0°

VC = 44.18 V at +90°