a) The Fracture criterion, on the other hand, explains how material is damaged and under what conditions it will break.
b) r = Pα/(1+α^2)^0.5+1,
r is the ratio of the principal stresses.
c) σ2 = [1-(σa/σy)^2]^0.5 (σy-σa).
d) As stress continues to increase, deformation may continue to occur and may become more severe over time. If the stress continues to increase beyond the yield stress, the material may fail.
(a) In mechanics of materials, yield criterion refers to the factors that dictate when a material will deform permanently while fracture criterion refers to factors that determine when the material will break. The Yield criterion is a theory that describes the relationship between stress and strain in a material. It is utilized to determine the point at which a material begins to deform permanently. The Fracture criterion, on the other hand, explains how material is damaged and under what conditions it will break.
(b) To calculate the maximum stresses the steel can support, the stress distribution in a material under plane stress is given by:
σ1=σ2
= (σx+σy)/2 + (((σx-σy)/2)^2+τxy^2)^0.5,
where
τxy=0
σ1=σ2= (σx+σy)/2 + (((σx-σy)/2)^2+0^2)^0.5
σ1=σ2= (σx+σy)/2 + ((σx-σy)/2)^2
σ1=σ2= (σx+σy)/2 + σx^2-σxσy+σy^2
σ1=σ2 can be written as
σ1=σ2= (σx+σy)/2 + 0.5(σx-σy)^2/[(σx-σy)/2]
Let
r = σx/σy and
α = σy/350,
then substituting these values in the Von Mises criterion yields:
[(r-1)^2+1/α^2]^0.5 - (r-1)/α = 0,
let
P = [(r-1)^2+1/α^2]^0.5 then
P = r/α-1/α,
thus
r = Pα/(1+α^2)^0.5+1,
r is the ratio of the principal stresses.
(c) Assuming σ1=σa, for yield not to occur,
σ2 = k(σy-σa),
where k is a constant that is a function of the yield criterion used, and σy is the yield stress of the steel. Thus,
k = σ2/(σy-σa),
assuming the yield criterion used is the Von Mises criterion, then
k = [1-(σa/σy)^2]^0.5 - σa/σy,
the maximum distance from the hole that the applied stresses σ1 and σ2 can be if yield is not to occur is
σ1 = σa,
σ2 = [1-(σa/σy)^2]^0.5 (σy-σa).
(d) If yield did occur but the stresses applied at distance from the hole continued to increase, the possible consequences could be deformation of the plate, or even failure of the material. This is because the area where yield has occurred would have a residual deformation. As stress continues to increase, deformation may continue to occur and may become more severe over time. If the stress continues to increase beyond the yield stress, the material may fail.
An illustration is shown below:
Illustration showing the consequences of increasing stress on a material after yield has occurred. The yellow region represents the area where yield has occurred. As stress continues to increase, deformation may continue to occur and may become more severe over time. If the stress continues to increase beyond the yield stress, the material may fail.
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how many moles of oxygen atoms are in one mole of the molecule Ca5(PO4)3OH? could you also show work
Answer:
13 moles of oxygen
Explanation:
A mole of a substance is the unit of measuring the number of particles within a chemical substance.
The given compound is:
Ca₅ (PO₄)₃OH
This is a mole of Ca₅ (PO₄)₃OH
In this compound we have:
5 moles of Ca
3 mole of P
13 mole of O
1 mole of H
So,
In 1 mole of Ca₅ (PO₄)₃OH, we have 13 moles of oxygen
Explain how copper conducts electricity?
Answer:
Copper is a metal made up of copper atoms closely packed together. As a result, the electrons can move freely through the metal. For this reason, they are known as free electrons. They are also known as conduction electrons because they help copper be a good conductor of heat and electricity.
Explanation:
explain the advantages of a potentiometric titration over titrations that use colored indicators. 2. could you suggest a potentiometric method for any of the analytes encountered thus far in our experiments? provide a short outline of the suggested procedure.
Potentiometric method provides a more accurate and precise determination of the analyte concentration compared to traditional color indicator-based titrations.
Potentiometric titrations offer several advantages over titrations that use colored indicators. Some of these advantages include:
1. Increased accuracy: Potentiometric titrations directly measure the potential difference between the electrodes instead of relying on the color change, which can be subjective and influenced by factors such as solution color and human error.
2. Greater sensitivity: Potentiometric methods can detect smaller changes in concentration, allowing for more precise determination of the endpoint.
3. Wider range of analytes: Potentiometric titrations can be used for a broader range of analytes, including those that do not have a well-defined color change with conventional indicators.
For a potentiometric method involving an analyte you've encountered in your experiments, I suggest using a pH electrode for an acid-base titration. Here's a short outline of the procedure:
1. Prepare the analyte solution in a beaker and add an appropriate amount of a supporting electrolyte to minimize the liquid junction potential.
2. Place a pH electrode and a reference electrode (e.g., Ag/AgCl) into the solution.
3. Connect the electrodes to a potentiometer or pH meter to measure the potential difference between them.
4. Begin titration by slowly adding the titrant solution (e.g., a strong acid or base) to the analyte solution while continuously monitoring the potential difference.
5. Record the potential difference and the volume of titrant added at regular intervals.
6. Plot the potential difference against the volume of titrant added to construct a titration curve. Identify the inflection point on the curve, which corresponds to the endpoint of the titration.
7. Use the titrant volume at the endpoint to calculate the concentration of the analyte in the solution.
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what are the limiting and excess reactants if 20.0g of C3H8 reacts with 10.0g of O2
Step 1
The reaction must be completed and balanced as follows:
C3H8 + 5 O2 => 3 CO2 + 4 H2O
-------------
Step 2
Information provided:
20.0 g of C3H8
10.0 g of O2
----
Information needed:
1 mole of C3H8 = 44.1 g
1 mole of O2 = 32.0 g
(use your periodic table please)
-------------
Step 3
By stoichiometry,
C3H8 + 5 O2 => 3 CO2 + 4 H2O
44.1 g C3H8 ---------- 5 x 32.0 g O2
20.0 g C3H8 ---------- X
X = 20.0 g C3H8 x 5 x 32.0 g O2/44.1 g C3H8
X = 72.6 g O2
For 20.0 g of C3H8, 72.6 g of O2 is needed, but there is only 10.0 g of O2.
Therefore,
Answer:
The limiting reactant = O2
The excess = C3H8
1.
Which statement correctly describes a major defect of the student model in representing the
structure of a plant cell?
A А
It does not demonstrate the ability to grow and divide over time,
пе
B.
It does not demonstrate the ability to move in response to environmental stimuli,
C
It does not represent the organelles as being submerged in a fluid medium
D. It does not represent multiple types of structure as turning light into food,
Water at 10°C After it was left in a room for 5 min a. Where did the water droplets come from? b. Why did the water droplets appear only after few minutes?
Answer:
a
Explanation:
because the water was left in the room the water vapour from the surroundings air comes into contact with the cooler surface of the water, so its losses heat qnd condense to form water droplet.
please help!!! image attached
Answer:
37E 15-ow
Explanation:
You see the amount of number shown is added up to the theroisicotist which is a hippopotamus
Reactants capable of interacting to form products in a chemical reaction must first overcome a thermodynamic barrier know as the reaction's __________________.
If 12.7 grams of hydrogen reacted with an unknown amount of oxygen, how many grams of water would be produced? (Write a balanced equation and show your work under the equation)
Answer:
2H2 + 1 O2 ------> 2H2O
m = 12.7g m = ?
Get the number of moles for Hydrogen gas (H2) by dividing the mass by the molar mass (1.01g/mol as listed in the periodic table for its atomic mass)
12.7/1.01 = 12.57 mol of H2
Now use the mole to mole ratio of Hydrogen gas (H2) and water (H2O).
From the balanced equation, we can see that 2 mol of H2 gives us 2 mol of H2O. Since both of the ratios are equal (2:2), the moles we have for hydrogen gas is the same as the moles we get for water.
12.57 mol of H2O
Now that we have the amount of mol for H2O produced in this reaction, we can convert it to grams by multiplying the moles by the molar mass.
Molar mass of H2O = (1.01 x 2) + (16) = 18.02g/mol
12.57 x 18.02 = 226.5g (rounded)
Therefore 226.5g of water will be produced in this reaction
According to law of conservation of mass and stoichiometry, 114.3 g of water are produced if 12.7 grams of hydrogen reacted with an unknown amount of oxygen.
What is law of conservation of mass?According to law of conservation of mass, it is evident that mass is neither created nor destroyed rather it is restored at the end of a chemical reaction .
Law of conservation of mass and energy are related as mass and energy are directly proportional which is indicated by the equation E=mc².Concept of conservation of mass is widely used in field of chemistry, fluid dynamics.
2 H₂ + O₂\(\rightarrow\) 2 H₂O,according to this equation,4 g hydrogen reacts with 32 g oxygen to give 36 g water, thus 12.7 g of hydrogen will produce 12.7×36/4=114.3 g water and hence for this amount of water to be formed 12.7 g of hydrogen reacts with 101.6 g of oxygen which is obtained as 114.3-12.7=101.6 g
Thus, 114.3 g of water is produced.
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At the summit of Mount Everest, what would happen to the boiling temperature of water? A. it would not change at all B. it would increase (>100 ∘
C) C. it would decrease (<100 ∘
C) D. it would change to 0 ∘
At the summit of Mount Everest, the boiling temperature of water C. would decrease (<100 ∘C).
The lower atmospheric pressure means that the pressure on the surface of the water is reduced, requiring less energy for the water molecules to escape as vapor. Consequently, the boiling point of water decreases to a temperature below 100 °C (212 °F).
At the summit of Mount Everest, the boiling point of water is approximately 68 °C (154 °F).
Therefore, if you were to bring water to a boil on the summit of Mount Everest, it would start to boil at a lower temperature compared to sea level due to the reduced atmospheric pressure.
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I really need help on this it’s a major grade!!
Can some one please write an amazing long essay explaining how life was prior to the invention you selected, how life is different today, and whether the result is
positive or negative.
PLEASE HELP QUICK ITS DUE TODAY 2/26/2021 AT 11:59!
What types of biochemical reactions are primarily reductive in nature?
The types of biochemical reactions that are primarily reductive in nature are known as reduction reactions. Reduction reactions involve the gain of electrons or the decrease in oxidation state of a molecule, resulting in a reduction in its overall energy or the transfer of electrons from a donor to an acceptor molecule.
One prominent example of a reductive biochemical reaction is photosynthesis, where plants and some bacteria use sunlight energy to convert carbon dioxide (CO2) into glucose. In this process, carbon dioxide is reduced to glucose by accepting electrons and hydrogen atoms from water molecules. Another example is cellular respiration, specifically the electron transport chain, where electrons derived from the breakdown of glucose and other fuel molecules are transferred through a series of redox reactions, resulting in the reduction of molecular oxygen (O2) to water (H2O) as the final electron acceptor.
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hydrogen gas is produced by the reaction between metallic aluminum and aqueous hydrochloric acid. 2al(s) 6hcl(aq)⟶2alcl3(aq) 3h2(g) the hydrogen gas produced by this reaction is typically collected via water displacement. during this process, the hydrogen gas becomes saturated with water vapor. if 292.6 ml of gas with a total pressure of 1.44 atm is collected via water displacement at 29.4 ∘c , what is the partial pressure of the hydrogen gas in the sample? the vapor pressure of water at 29.4 ∘c is 30.75 torr. Ph2
(a) - 1.39 atm is the partial pressure of the hydrogen gas in the sample
(b) - 0.219 g many grams of aluminum must have reached to produce this quantity of hydrogen gas.
What exactly is the partial pressure law?According to Dalton's Law, often known as the Legislation of Partial Pressures, the combined pressure of a mix of gas is equal to the product of their individual partial pressures.
Briefing:(a)The partial pressure of hydrogen gas and the vapour pressure of water are added to determine the total pressure of the gas mixture.
PT = Pw + PH
Water has a vapour pressure of atm.
Pw = (30.75 torr)(1.00 atm) / 760 torr
Pw = 0.0405 atm
The hydrogen gas pressure is
PH = PT - Pw
PH = 1.44 atm - 0.0405 atm
PH = 1.39 atm
(b) The amount of hydrogen gas in moles is
n = PV / RT
n = (1.39 atm) (0.2384 L) / 0.82057 atm L / mol K (302.6 K)
n=0.0122 mol
Aluminum metal and hydrogen gas have a 3:2 molar ratio. The required amount of aluminum metal in moles is
n=0.0122 mol * 2 / 3
n = 0.00813 mol
Aluminum has a molar mass of 26.981538 g/mol. The quantity of aluminum needed is
m = 0.00813 * 26.981538 g/mol
m = 0.219 g
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The complete question is -
Hydrogen gas is produced by the reaction between metallic aluminum and aqueous hydrochloric acid. 2al(s) 6hcl(aq)⟶2alcl3(aq) 3h2(g)
(a)the hydrogen gas produced by this reaction is typically collected via water displacement. during this process, the hydrogen gas becomes saturated with water vapor. if 292.6 ml of gas with a total pressure of 1.44 atm is collected via water displacement at 29.4 ∘c , what is the partial pressure of the hydrogen gas in the sample?
(b)How many grams of aluminum must have reached to produce this quantity of hydrogen gas ? The vapor pressure of water at 29.4 ∘c is 30.75 torr.
issued this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your etext. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon.
The atomic ratio of carbon to oxygen in carbon monoxide (CO) is 1:1, and the atomic ratio of carbon to oxygen in carbon dioxide (CO₂) is 2:1.
Firstly, we can analyze the decomposition of carbon monoxide (CO) and carbon dioxide (CO₂) to determine the atomic ratios involved.
Let's denote the atomic ratio of carbon to oxygen in carbon monoxide as x, and the atomic ratio of carbon to oxygen in carbon dioxide as y.
According to the given data;
Decomposition of carbon monoxide (CO);
Oxygen produced = 3.36 g
Carbon produced = 2.52 g
We know that the atomic mass of carbon is 12 g/mol, and the atomic mass of oxygen is 16 g/mol. Using these values, we can calculate the number of moles for each element;
Number of moles of oxygen = mass / atomic mass = 3.36 g / 16 g/mol = 0.21 mol
Number of moles of carbon = mass / atomic mass = 2.52 g / 12 g/mol = 0.21 mol
Since the atomic ratio of carbon to oxygen in carbon monoxide is x, we can write the following equation;
0.21 mol C / (0.21 mol O) = x
Simplifying the equation, we have;
x = 1
Therefore, the atomic ratio of carbon to oxygen in carbon monoxide is 1:1.
Decomposition of carbon dioxide (CO₂);
Oxygen produced = 9.92 g
Carbon produced = 3.72 g
Following the same calculations as before;
Number of moles of oxygen = mass / atomic mass = 9.92 g / 16 g/mol = 0.62 mol
Number of moles of carbon = mass / atomic mass = 3.72 g / 12 g/mol = 0.31 mol
Since the atomic ratio of carbon to oxygen in carbon dioxide is y, we can write the following equation;
0.31 mol C / (0.62 mol O) = y
Simplifying the equation, we have;
y = 0.5
Therefore, the atomic ratio of carbon to oxygen in carbon dioxide is 1:0.5, which can be simplified to 2:1.
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--The given question is incomplete, the complete question is
"Missed this? watch kcv: atomic theory; read section 2.3. you can click on the review link to access the section in your text. carbon and oxygen form both carbon monoxide and carbon dioxide. when samples of these are decomposed, the carbon monoxide produces 3.36 g of oxygen and 2.52 g of carbon, while the carbon dioxide produces 9.92 g of oxygen and 3.72 g of carbon. Calculate the atomic ratio of carbon to oxygen in carbon monoxide, and carbon dioxide."--
¿Qué bacterias existen según su
nutrición?
Answer:
autotrofas estrictas son aquellas bacterias incapaces de crecer usando materia orgánica como fuente de carbono. Mixotrofas son aquellas bacterias con metabolismo energético litotrofo (obtienen energía de compuestos inorgánicos), pero requieren sustancias orgánicas como nutrientes para su metabolismo biosintético.
40 units of regular Humulin insulin in 100 mL 0.9% NS were to infuse at 10 mL/hr. How many units per hour will be delivered
When infusing 40 units of regular Humulin insulin in 100 mL of 0.9% NS at a rate of 10 mL/hr, 4 units of insulin will be delivered per hour.
To determine the number of units per hour that will be delivered when infusing 40 units of regular Humulin insulin in 100 mL of 0.9% NS (normal saline) at a rate of 10 mL/hr, we can set up a proportion.
Given that 40 units of insulin are diluted in 100 mL of solution, we can calculate the concentration of insulin in units per milliliter (units/mL) as:
Concentration of insulin = 40 units / 100 mL = 0.4 units/mL
Next, we need to determine the number of units delivered per hour. Since the infusion rate is 10 mL/hr, we can multiply the concentration of insulin by the infusion rate to find the units delivered per hour:
Units per hour = Concentration of insulin * Infusion rate
= 0.4 units/mL * 10 mL/hr
= 4 units/hr
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Which table correctly describes the uses of aldehydes?
table A
table B
table C
table D
Answer:
Correct answer is table A i might be wrong
Answer:
It's A - table A
Explanation:
On Edge 2021
write the name and the formula of the compound formed Potassium and oxygen, and Aluminum and nitrogen.
Answer:
K2O Potassium oxide
Explanation:
A toy top has a mass of 32.0 g cu. how many atoms cu are in this spinning top, given that the average atomic mass of copper is 63.55 g/mol cu?
Answer:
3.03 x 10²³ atoms Cu
Explanation:
To find the amount of copper atoms, you need to (1) convert grams to moles (via average atomic mass) and then (2) convert moles to atoms (via Avogadro's number). The final answer should have 3 sig figs because the given value with the lowest amount of sig figs (32.0) also has 3 sig figs.
Avogadro's Number:
6.022 x 10²³ atoms = 1 mole
32.0 g Cu 1 mole 6.022 x 10²³ atoms
---------------- x ---------------- x -------------------------------- = 3.03 x 10²³ atoms Cu
63.55 g 1 mole
Which compound is composed of calcium and chlorine?
CO
CaCl2
CaF2
CsF
The compound that is composed of calcium and chlorine is CaCl₂
How do I determine the compound that contains calcium and chlorine?To know which of the compound that contains calcium and chlorine, we must know the symbol of calcium and chlorine. This is shown below:
Calcium is a group 2 element with atomic number of 20 and a symbol of Ca
Chlorine is a group 17 element with atomic number of 17 and a symbol of Cl
With the above information, we can determine the compound that contains calcium and chlorine as follow:
The compound that contains calcium and chlorine must have Ca and Cl in it.
Thus, the compound that contains calcium and chlorine is CaCl₂
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aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is mixed with 13.9 g of oxygen. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction. Round your answer to significant digits.
Answer:
There is 9.6 grams of CO2 produced
Explanation:
Step 1: Data given
Mass of methane = 5.50 grams
Molar mass of methane = 16.04 g/mol
Mass of oxygen = 13.9 grams
Molar mass of oxygen = 32.0 g/mol
Step 2: The reaction
CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)
Step 3: Calculate number of moles
Moles = mass / molar mass
Moles methane = 5.50 grams / 16.04 g/mol
Moles methane = 0.343 moles
Moles oxygen = 13.9 grams / 32.0 g/mol
Moles oxygen = 0.434 moles
For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O
O2 is the limiting reactant. It will completely react (0.434 moles).
There will react 0.434/2 = 0.217 moles CH4
There will remain 0.343-0.217 = 0.126 moles CH4
There will be produced 0.434 moles of H2O and
0.434/2 =0.217 moles of CO2
Step 4: Calculate mass of products
Mass = moles * molar mass
Mass CO2 = 0.217 moles ¨44.01 g/mol
Mass CO2 = 9.6 grams
Mass H2O = 0.434 moles * 18.02
Mass H2O = 7.8 grams
arrange this isoelectronic series in order of decreasing radius: f−, n3−, o2−, mg2+, na+.
The arrangement of the given isoelectronic series in order of their decreasing radius is N³⁻ > O²⁻ > F⁻ > Na⁺ > Mg²⁺.
We are aware that, on the periodic table, the atomic radius of an element drops as one moves to the right and increases as one moves downward.
As the protons now exert a stronger force on the remaining electrons, the atomic radius of elements reduces when an electron is removed from the atom. The radius gets smaller as more electrons are taken out. The radius of an isoelectronic species will therefore be smaller the more positive charge it possesses.
When electrons are added to an atom, the force of attraction between the protons weakens due to the more protons present, and the electrons experience greater self-repulsion as a result of being packed closer together. To counteract this, the atomic radius of the ion is increased in order to reduce self-repulsion. As a result, the radius of the isoelectronic species increases as negative charge increases.
We can see from this that the atomic radius reduces as the positive charge rises.
As a result, the species are arranged in order of decreasing atomic radius as follows:
N³⁻ > O²⁻ > F⁻ > Na⁺ > Mg²⁺
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suggest two gases in the air that will react with zinc to make zinc carbonate
Answer:
See explanation
Explanation:
Zinc is a metal and as such can undergo corrosion when exposed to moisture.
Two gases in the atmosphere that can react with Zinc metal and covert it to Zinc carbonate are carbon dioxide and water vapour.
Zinc is oxidized to ZnO in the atmosphere by water vapour. This ZnO subsequently reacts with CO2 to yield ZnCO3.
Use the activity series below the predict the products of each of the following reactions. Do not worry about balancing the equations, CCl4 + Br2--? no reaction, CBr4 + Cl2
Answer:
1. a
2.b
Explanation:
Select the correct answer. what type of creation story describes how earth originated from water? a. ex nihilo b. emergence c. world parents d. earth diver
Earth diver story type of creation story describes how earth originated from water.
A creation myth or cosmogonic myth is a symbolic narrative of how the world began and how people first came to inhabit it. earth diver is a common character in various traditional creation myths who is sent by a supreme being into the primal waters to find substance (often sand or mud) with which to build habitable land. earth diver featured character are the on who dives into water and bring up a small amount of mud and sand and that's why according to this theory supreme being is responsible for sending animals inside the water to find little bit of mud and sand.
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What is the activation energy for the isomerization of methyl isocyanide? Rate Constant Temperature 472 K 4.30 X 10-3 min-1 503 K 5.54 x 10-2 min-1
The activation energy for the isomerization of methyl isocyanide is 77.6 kJ/mol.
The activation energy for the isomerization of methyl isocyanide can be determined using the Arrhenius equation. The equation relates the rate constant, activation energy, and temperature.
The Arrhenius equation is given by:
k = Ae^(-Ea/RT)
wherek = rate constant
A = pre-exponential factor (frequency factor)
Ea = activation energy
R = universal gas constant
T = temperature
R = 8.314 J/mol.
KEa = (-R ln(k2/k1))/(1/T2 - 1/T1)
Where k2 and k1 are the rate constants at temperatures T2 and T1, respectively.
For the given data,T1 = 472 K, T2 = 503 K, k1 = 4.30 × 10-3 min-1, k2 = 5.54 × 10-2 min-1.
Substituting these values in the equation for Ea:
Activation energy (Ea) = (-8.314 J/mol.K) ln (5.54 × 10-2 min-1 / 4.30 × 10-3 min-1) / (1/503 K - 1/472 K) = 77,600 J/mol = 77.6 kJ/mol
Therefore, the activation energy is 77.6 kJ/mol.
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What is the formula for Water?
Name full name element's name
Answer:
2 Hydrogen atoms and 1 Oxygen atoms makes water
Explanation:
Hope this helps^^
Answer: Its chemical formula H2O, indicates that each of its molecules contains one oxygen and two hydrogen atoms,
Explanation: i hopes it helps :)
Kim dissolves 70.13 g of solid sodium chloride (NaCl) in enough distilled water to make 400 mL of stock solution. What volumes of stock solution and distilled water (DI) are needed to make a 150 mL solution of 1.2 M NaCl?
This problem is providing us with the mass of solid sodium chloride and the volume of water it was dissolved in. Thus, after diluting it, the volume of the stock solution was required and found to be 60. mL according to:
Diluted solutionsIn chemistry, when we are given a stock solution with specified volume and concentration, one is able to dilute it in order to use it for a specific purpose. This, by holding the number of moles constant, one can write:
\(C_1V_1=C_2V_2\)
Where the subscript 1 stands for the stock solution and 2 for the diluted one. Thus, one first calculate the initial concentration with the mass and volume:
\(M=\frac{70.13g/(58.44 g/mol)}{0.400L}=3.00M\)
Next, we solve for the volume of the stock solution, V1, as follows:
\(V_1=\frac{C_2V_2}{C_1}\)
Finally, we plug in the given data to obtain the result:
\(V_1=\frac{1.2M*150mL}{3.00M}\\ \\V_1=60.mL\)
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What is the molarity of 15.0 milliliters of an unknown acid that is titrated
with a 1.25 M NaOH solution and required 24.65 milliliters of base to
complete the titration?
Answer:
~2.054M
Explanation:
In this question ,I am going to assume that the acid is monoprotic acid(contains only one hydrogen) which I'll represent by HA.
Chemical equation:
NaOH(aq) + HA(aq)----->NaA(aq) + H2O(l)
The mole ratio of NaOH:HA is 1:1
1.25M NaOH=1.25 Moles/L or 1.25 moles /1000ml of NaOH
(1.25 moles /1000ml) x (24.65ml)=0.0308125 moles NaOH
Mole ratio is 1:1
So, moles of HA are also 0.0308125 moles
volume of HA =15ml
To find molarity of HA:
=(0.0308125 moles x 1000ml)/(15ml)
~2.054M of HA
~Hope it helps:)
Direct Combination and the product
Cobalt (III) + nitrogen -> ??
The chemical equation for Direct Combination of Cobalt (III) and nitrogen, with the product given can be represented as given : Cobalt (III) + nitrogen → Cobalt nitride (Co3N2)When Cobalt (III) and nitrogen are combined using direct combination method, the product formed is Cobalt nitride (Co3N2).
The balanced chemical equation for this reaction is shown below.2 Co (III) + 3 N2 → Co3N2.Cobalt nitride is a blackish gray powder with a melting point of 1750 °C and a density of 6.5 g/cm3. Cobalt nitride is an important metal nitride that is used in the preparation of cobalt metal catalysts, magnetic alloys, and other materials.
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