A box of candy is shaped like a rectangular pyramid. The volume of the candy box measures 120 cubic inches. The area of the base of the candy box is 18 square inches. What is the height of the candy box?

The absolute value of the expression is given by:

\(\[\left| \frac{2z_1 7z_2}{2z_1 - 7z_2} \right| = \frac{|k|\cdot |14i - 49k|\cdot |z_1^3|}{|z_1|\cdot |4 - 28ki + 49k^2|}.\]\)

Let's start by simplifying the expression inside the absolute value:

\(\[\frac{2z_1 \cdot 7z_2}{2z_1 - 7z_2}.\]\)

To make progress, we'll multiply both the numerator and denominator by the conjugate of the denominator:

\(\[\frac{2z_1 \cdot 7z_2}{2z_1 - 7z_2} \cdot \frac{2z_1 + 7z_2}{2z_1 + 7z_2}.\]\)

Expanding the numerator, we have:

\(\[2z_1 \cdot 7z_2 \cdot (2z_1 + 7z_2) = 14z_1^2z_2 + 49z_1z_2^2.\]\)

Expanding the denominator, we have:

\([(2z_1)(2z_1) + (2z_1)(7z_2)] + [(7z_2)(2z_1) + (7z_2)(7z_2)] = 4z_1^2 + 14z_1z_2 + 14z_1z_2 + 49z_2^2 = 4z_1^2 + 28z_1z_2 + 49z_2^2.\)

Putting it all together, the expression becomes:

\(\[\frac{14z_1^2z_2 + 49z_1z_2^2}{4z_1^2 + 28z_1z_2 + 49z_2^2}.\]\)

Now, we can take the absolute value:

\(\[\left| \frac{14z_1^2z_2 + 49z_1z_2^2}{4z_1^2 + 28z_1z_2 + 49z_2^2} \right| = \frac{|14z_1^2z_2 + 49z_1z_2^2|}{|4z_1^2 + 28z_1z_2 + 49z_2^2|}.\]\)

Since\($\frac{z_2}{z_1}$\) is pure imaginary, we have \($z_2 = ki z_1$\) for some real number \($k.$\) Substituting this into the expression, we get:

\(\[\frac{|14z_1^2(ki z_1) + 49z_1(ki z_1)^2|}{|4z_1^2 + 28z_1(ki z_1) + 49(ki z_1)^2|}.\]\)

Simplifying, we have:

\(\[\frac{|14kz_1^3i + 49k^2z_1^3i^2|}{|4z_1^2 + 28kz_1^2i - 49k^2z_1^2|} = \frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2(4 - 28ki + 49k^2)|}.\]\)

Since\($2z_1 \neq 7z_2,$\) we have \($2 \neq 7ki,$\) which implies \($k \neq \frac{2}{7i}.$\)Therefore, \($4 - 28ki + 49k^2 \neq 0,$ so $z_1^2(4 - 28ki +49k^2) \neq 0,$\) which means we can cancel it from the expression:

\(\[\frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2(4 - 28ki + 49k^2)|} = \frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|}.\]\)

Since \($|ab| = |a|\cdot |b|,$\) we have:

\(\[\frac{|14kz_1^3i - 49k^2z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|} = \frac{|14ki - 49k^2|\cdot |z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|}.\]\)

Finally, we can simplify the expression further:

\(\[\frac{|14ki - 49k^2|\cdot |z_1^3|}{|z_1^2|\cdot |4 - 28ki + 49k^2|} = \frac{|k|\cdot |14i - 49k|\cdot |z_1^3|}{|z_1|\cdot |4 - 28ki + 49k^2|}.\]\)

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Answer:

C: \(\frac{1}{8*8*8*8*8*8*8*8}\)

Step-by-step explanation:

\(a^{-n} = \frac{1}{a^n}\)

Since a = \(8^2\) :

\((8^2)^{-n} = \frac{1}{(8^2)^n} =\frac{1}{8^{2n}}\)

Since n = 4 :

\((8^2)^{-4} =\frac{1}{8^{2*4}}=\frac{1}{8^{8}}=\frac{1}{8*8*8*8*8*8*8*8}\)

For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Answer:

B - Her monthly average would have increased by $19.57. ... Katie works as a waitress and records her monthly tips in the table shown below. If Katie decided not to work the month of November, how would her five month average compare to her six month ... Lisa is currently taking physics as one of her electives in school.

Step-by-step explanation:

Answer:

Nov. ✔ = Feb.

Oct. ✔ < Dec.

Jan. ✔ > Nov.

Step-by-step explanation:

Edge 2022

At the grand opening, al's furniture store, there is offering spin wheel for discount. The probability that a customer gets a 10% or 20% discount is equals to the 0.75.

At the grand opening, al's furniture store, it offered a spin the wheel for a discount to its customers. The wheel is divided into 12 equal slices.

The percentage of discount awarded by 6 slices = 10%

The percentage of discount awarded by 3 slices = 20%

The percentage of discount awarded by 2 slices = 40%

The percentage of discount awarded by 1 slices

= 100%

We have to determine the probability that a customer gets a 10% or 20% discount. As we see all slices are independent to each other so events related to these also independent.

We have total 12 slices. Since, 6 slices awarded for 10% discount i.e. chances of getting 10% discount is equal = 6/12

Similarly, 3 slices awarded for 20% discount i.e. chances of getting 20% discount is 3/12.

Hence chances of getting 10% or 20% discount is

= P( X = 20%) + P( X= 10%)

= 6/12 + 3/12

= 1/2 + 1/4

= 0.50 + 0.25

= 0.75

Hence, required value is 0.75.

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The equation of the line would be y = (-3/4)x + 5.

What is the slope-point form of the line?

For the line having slope "m" and the point (x1, y1) the equation of the line passing through the point (x1, y1) having slope 'm' would be

                      y - y1 = m(x - x1)

The given equation is \(y=-\frac{3}{4}x-17\)

The required line is parallel to the given line.

and we know that the slopes of the parallel lines are equal so the slope of the required line would be m = -3/4

And the required line passes through (8, -1)

so by using slope - point form of the line,

      y - (-1) = (-3/4)(x - 8)

      y + 1 = (-3/4)x - (-3/4)8

       y + 1 = (-3/4)x + 24/4

       y = (-3/4)x + (12/2 - 1)

       y = (-3/4)x + 5

Hence, the equation of the line would be y = (-3/4)x + 5.

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Answer:

45

Step-by-step explanation:

3*3=9*5=45  

your welcome

Therefore , the solution of the given problem of circle comes out to be this statement is true  ∠AOC = 100° .

Each area of a plane with a specific distance from this additional spot forms a circle (center). Thus, it comprises of curved spots that are separated from one another and separated by the surface. Additionally, it rotates evenly around the centre from all sides. Every set of endpoints in a circular, constrained double sphere is uniformly spaced apart from the "centre."

Here,

Given :

AD and EC are diameters as we can see they are passing through centre .

So , there are diameter.

=> ∠AOC = ∠A0B + ∠BOC

=> ∠AOC = 100°

thus , this statement is true  ∠AOC = 100° .

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Answer: can you show us the graph?

Step-by-step explanation:

Answer:

Step-by-step explanation:

We can use algebra to determine how many years it has been since the cost of a box of pencils was $0.00, and therefore calculate how many years the price has been increasing by $1.10 per year.

Let's say that x is the number of years since the cost of a box of pencils was $0.00.

If the price of a box of pencils is increasing by $1.10 per year, then the cost of a box of pencils x years after it cost $0.00 would be:

$0.00 + ($1.10 * x)

We know that the current cost of a box of pencils is $2.19. Setting this equal to the expression above, we can solve for x:

$0.00 + ($1.10 * x) = $2.19

$1.10 * x = $2.19

x = $2.19 / $1.10

x = 1.99

So, it has been approximately 1.99 years (or just under 2 years) since the cost of a box of pencils was $0.00, and the price of a box of pencils has been steadily increasing by $1.10 per year during that time.

The expected value of the hypothesis generated by the learning algorithm is zero.

Assume the learning model consists of all hypotheses of the form h(x) = ax. The question asked to calculate the expected value, ¯g(x), of the hypothesis produced by the learning algorithm (expected value with respect to the data set). We have to express our answer as axˆ and round ˆa to two decimal digits only.

Explanations: Given, the learning model consists of all hypotheses of the form `h(x) = ax`. Expected value of hypothesis generated by the learning algorithm is given by:

¯g(x) = E(h(x))

= E(a x)

Now, E(x) is the expected value of the random variable `x`. If the data set has uniform distribution on [−1,1], then E(x) = 0. Therefore, ¯g(x) = E(h(x))

= E(a x)

= a E(x)

= a * 0

= 0

Thus, the expected value of the hypothesis generated by the learning algorithm is zero. Therefore, the answer is 0x^. The final answer is 0.00.

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Answer:

c > 38.5

Step-by-step explanation:

14c > 600 - 61

14c > 539

c > 38.5

Answer:

82

Step-by-step explanation:

60 - 16/2 + 10(3)

60 - 16/2 + 30              multiplication

60 - 8 + 30                    division

 52 + 30                       addition or subtraction in order from left to right

 82

The fraction which is greater is 3/10. That means there are more flute players than trumpet players in the band.

Perhaps what you meant was "Which is the greater fraction of the bands: flute players or trumpet players?"

First of all, we need to make the denominators of fraction 3/10 and 1/12 the same so we can actually compare the given fractions. To do this, we can take the least common multiple (LCM) of the denominators and multiply the numerator and denominator of each fraction by certain numbers so that the denominators equal to the LCM.

The multiples of 12 are 12, 24, 36, 48, 60 etc. The multiples of 10 are 10, 20, 30, 40, 50, 60 etc. Notice that the first common multiple is 60. That's the LCM of 12 and 10.

3/10 is equal to 18/60 while 1/12 is equal to 5/60. 18 is greater than 5 so the first fraction is greater, which means there are more flute players than there are trumpet players in the band.

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The results of dividing 1 into pieces that are each 1/9 of a whole is 9

1 ÷ 1/9

1 ÷ 1/9

= 1 × 9/1

= (1 × 9) / (1 × 1)

= 9/1

= 9

Complete question:

If 1 is divided into pieces that are each 1/9 of a whole, how many pieces are there

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The equation represents the intersections. The correct option is A:

If we have two functions:

y = f(x) and y = g(x), the equation:

f(x) = g(x) gives the value of x such that the two functions have the same output. So, that equation gives the intersection points between the two graphs.

By looking at the graph, we can see that we have two intersections, one at:

(2, 0) and other at (0, 4).

This means that:

So the correct option is the first one.

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A. The differential equation for the level of nicotine in the body, N, in mg, as a function of time, t, in hours is dN/dt = -0.346N + 2.00, where N(0) = 0.

B. The solution to the differential equation is N(t) = 5.79 - 4.79e^(-0.346t). When t = 16, N(16) = 2.46 mg of nicotine in the blood.

A. The rate at which nicotine enters the body is 5 cigarettes per hour, and 0.4 mg of nicotine is absorbed from each cigarette. Thus, the rate of change of the nicotine level in the body is the rate at which nicotine enters the body minus the rate at which it leaves the body.

Using the constant of proportionality -0.346, the differential equation is dN/dt = -0.346N + 2.00, where N(0) = 0.

B. To solve the differential equation, we first find the general solution by separating variables and integrating both sides. This yields ln|N(t) - 5.79| = -0.346t + C, where C is the constant of integration.

Since N(0) = 0, we can solve for C and get C = ln(5.79). Thus, the solution is N(t) = 5.79 - 4.79e^(-0.346t). Finally, when t = 16, N(16) = 2.46 mg of nicotine in the blood.

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a. The differential equation for the level of nicotine in the body is dN/dt = 2 - 0.346N

b. The differentiation equation can be solve as N = (2 + e^(-0.346t + C')) / 0.346

c. The amount of nicotine in the blood when the person goes to sleep at 11 pm is approximately 0.34 mg

A) To write a differential equation for the level of nicotine in the body, N, as a function of time, t, we need to consider the rate at which nicotine enters and leaves the body.

The rate at which nicotine enters the body is given by the number of cigarettes smoked per hour multiplied by the amount of nicotine absorbed from each cigarette. In this case, it is 5 cigarettes per hour multiplied by 0.4 mg per cigarette, which is 2 mg per hour.

The rate at which nicotine leaves the body is proportional to the amount of nicotine present, with a constant of proportionality of -0.346.

Therefore, the differential equation for the level of nicotine in the body is:

dN/dt = 2 - 0.346N

B) To solve the differential equation, we can separate variables and integrate. Rearranging the equation:

dN/(2 - 0.346N) = dt

Integrating both sides:

∫dN/(2 - 0.346N) = ∫dt

Using a substitution u = 2 - 0.346N and du = -0.346dN:

∫(-1/0.346) du/u = ∫dt

(-1/0.346) ln|u| = t + C

Substituting back u = 2 - 0.346N:

(-1/0.346) ln|2 - 0.346N| = t + C

Simplifying and rearranging:

ln|2 - 0.346N| = -0.346t + C'

Taking the exponential of both sides:

|2 - 0.346N| = e^(-0.346t + C')

Since the absolute value can be positive or negative, we consider two cases:

2 - 0.346N = e^(-0.346t + C') (positive)

-(2 - 0.346N) = e^(-0.346t + C') (negative)

Solving each case separately:

2 - 0.346N = e^(-0.346t + C')

N = (2 - e^(-0.346t + C')) / 0.346

-(2 - 0.346N) = e^(-0.346t + C')

N = (2 + e^(-0.346t + C')) / 0.346

C) Given that the person wakes up at 7 am and goes to sleep at 11 pm, the duration is 16 hours. We can substitute t = 16 into the equation to find the nicotine level N at that time:

N = (2 - e^(-0.346*16 + C')) / 0.346

Since initially there is no nicotine in the blood, N(0) = 0, we can solve for C' by substituting N = 0 and t = 0:

0 = (2 - e^(-0.346*0 + C')) / 0.346

0 = (2 - e^C') / 0.346

e^C' = 2

C' = ln(2)

Substituting the value of C' into the equation:

N = (2 - e^(-0.346*16 + ln(2))) / 0.346

Calculating this expression, we find that the amount of nicotine in the blood when the person goes to sleep at 11 pm is approximately 0.34 mg (rounded to two decimal places).

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Answer:

q1 (1,-3)

r1 (3,3)

s1 (0,2)

t1 (-2,-1)

Step-by-step explanation:

When a shape is reflected, it must be reflected across a line

The vertices for \(\mathbf{rx-axis}\) of qrst are:

The given parameters are:

\(\mathbf{q = (1,3)}\)

\(\mathbf{r = (3,-3)}\)

\(\mathbf{s = (0,-2)}\)

\(\mathbf{s = (-2,1)}\)

The transformation rule is given as:

\(\mathbf{rx-axis}\)

The above rule means that the vertices are reflected over the x-axis

The rule of the transformation is:

\(\mathbf{(x,y) \to (x,-y)}\)

So, we have:

\(\mathbf{q(1,3) \to q'(1,-3)}\)

\(\mathbf{r(3,-3) \to r'(3,3)}\)

\(\mathbf{s(0,-2) \to s'(0,2)}\)

\(\mathbf{t(-2,1) \to t'(-2,-1)}\)

Hence, the vertices for \(\mathbf{rx-axis}\) of qrst are:

\(\mathbf{q'(1,-3)}\)

\(\mathbf{ r'(3,3)}\)

\(\mathbf{ s'(0,2)}\)

\(\mathbf{t'(-2,-1)}\)

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If your train travels at 65 miles per hour for 3.5 hours, it go 227.5 miles.

What is Speed ?

Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.

Given:

Speed S = 65 miles per hour

Time T = 3.5 hours

We know that,

S= D/T  Where D is the distance traveled.

Therefore,

65 miles per hour = D/ 3.5 hours

D = 65 x 3.5 miles

=227.5 miles

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For the figure 7, the measure of each angle is:

a) m ∠1=131°

b) m ∠2=49°

c) m ∠3=92°

d) m ∠4=88°

e) m ∠5=92°

f) m ∠6=88°

g)  m ∠8=49°

h) m∠9=92°

i) m ∠10=88°

j) m ∠11=131°

k) m ∠12=49°

l) m ∠13=131°

m) m ∠14=49°

n) m ∠15=92°

For the figure 8,

a) m ∠1=12°

b) m ∠3=105°

c) m ∠4=12°

d) m ∠5= 63°

e) m ∠6=105°

f) m∠7=105°

g) m ∠8=105°

h) m ∠11=12°

i) m ∠12=168°

j) m ∠13=12°

k) m ∠14=168°

An angle in Euclidean geometry is the figure produced by two rays, called the sides of the angle, that have a common termination, called the vertex of the angle. Angles formed by two rays lie in the plane containing the rays. Angles are also generated by the intersection of two planes. These are referred to as dihedral angles. Two intersecting curves can also define an angle, which is the angle of the rays lying tangent to the respective curves at their point of intersection.

7) From the figure,

m ∠7=131°

m ∠7=m ∠1

m ∠1=131°

m ∠1+m ∠7+m ∠2+m ∠8=360°

131°+131°+ m ∠2+m ∠8=360°

m ∠2+m ∠8=360°-262°

m ∠2+m ∠8=98°

m ∠2=m ∠8

2m ∠2=98°

m ∠2=49°

m ∠8=49°

And also given that,

m ∠16= 88°

m ∠10=88°

m ∠10+m ∠16+m ∠9+m ∠15=360°

m ∠9+m ∠15=360°-176°

=184°

m ∠9=92°

m ∠15= 92°

m ∠11=m ∠7

m ∠11=131°

m ∠11=m ∠13

m ∠12= m ∠14=m ∠2= m ∠8=49°

m ∠10= m ∠16= m ∠6=m ∠4=88°

m ∠3=m ∠5= m∠9=m ∠15=92°

a) m ∠1=131°

b) m ∠2=49°

c) m ∠3=92°

d) m ∠4=88°

e) m ∠5=92°

f) m ∠6=88°

g)  m ∠8=49°

h) m∠9=92°

i) m ∠10=88°

j) m ∠11=131°

k) m ∠12=49°

l) m ∠13=131°

m) m ∠14=49°

n) m ∠15=92°

8) From the figure,

m ∠2=63°, m ∠9=105°

m ∠2=m ∠5= 63°

m ∠6+ m ∠5+m ∠4=180°

m ∠9= m∠7=m ∠6=m ∠3=105°

m ∠4=180°-63°-105°

m ∠4=12°

m ∠4=m ∠1= m ∠13=m ∠11=12°

m ∠11+m ∠13+m ∠12+m ∠14=360°

m ∠12=m ∠14

2m ∠12=360°-24°=336°

m ∠12=168°

m ∠12=m ∠14=168°

m ∠3=m ∠10=m ∠8=105°

a) m ∠1=12°

b) m ∠3=105°

c) m ∠4=12°

d) m ∠5= 63°

e) m ∠6=105°

f) m∠7=105°

g) m ∠8=105°

h) m ∠11=12°

i) m ∠12=168°

j) m ∠13=12°

k) m ∠14=168°

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The numbers are approximately 2 + 0.5√14 and 2 - 0.5√14.

Let's assume the two numbers as x and y.

According to the problem statement:

The sum of the two numbers is 4: x + y = 4.

The sum of their reciprocals is 8: 1/x + 1/y = 8.

To solve this system of equations, we can use the substitution method.

From the first equation, we can express y in terms of x: y = 4 - x.

Substituting this value into the second equation:

1/x + 1/(4 - x) = 8

To simplify the equation, we can find a common denominator:

[(4 - x) + x]/(x(4 - x)) = 8

\(4/(4x - x^2) = 8\)

Now, we can cross-multiply and simplify:

\(4 = 8(4x - x^2)\)

\(4 = 32x - 8x^2\)

\(8x^2 - 32x + 4 = 0\)

Dividing the equation by 4, we get:

\(2x^2 - 8x + 1 = 0\)

Now, we can solve this quadratic equation using the quadratic formula:

\(x = (-b \pm \sqrt{(b^2 - 4ac)} )/(2a)\)

Substituting a = 2, b = -8, and c = 1 into the formula, we get:

\(x = (-(-8) \pm \sqrt{((-8)^2 - 4 \times 2 \times 1))} /(2 \times 2)\)

x = (8 ± √(64 - 8))/4

x = (8 ± √56)/4

x = (8 ± 2√14)/4

x = 2 ± 0.5√14

Therefore, the two numbers are approximately:

x ≈ 2 + 0.5√14

y ≈ 4 - (2 + 0.5√14) = 2 - 0.5√14

The numbers are approximately 2 + 0.5√14 and 2 - 0.5√14.

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Answer:

AAS

Step-by-step explanation:

Angle K is congruent to Angle N (given), Angle H is congruent to itself (reflexive property), and side JH is congruent to side MH (given).

the binary representation of 63.25 as 111111.01.

To convert the decimal number 63.25 to binary, we need to convert the integer part (63) and the fractional part (0.25) separately.

1. Converting the integer part (63):

  Divide 63 by 2, and keep track of the remainders:

  63 ÷ 2 = 31 (remainder 1)

  31 ÷ 2 = 15 (remainder 1)

  15 ÷ 2 = 7 (remainder 1)

  7 ÷ 2 = 3 (remainder 1)

  3 ÷ 2 = 1 (remainder 1)

  1 ÷ 2 = 0 (remainder 1)

  The remainders in reverse order give us the binary representation of the integer part: 111111.

2. Converting the fractional part (0.25):

  Multiply 0.25 by 2 and record the whole number part:

  0.25 × 2 = 0.5 (0)

  0.5 × 2 = 1.0 (1)

  The whole number parts give us the binary representation of the fractional part: 01.

Putting the integer and fractional parts together, we have the binary representation of 63.25 as 111111.01.

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The binary representation of the decimal number 63.25 is 111111.01.

To convert the decimal number 63.25 to binary, we need to separate the whole number part and the fractional part.

Whole Number Part:

Divide the whole number part (63) by 2:

Divide the quotient (31) by 2:

Divide the quotient (15) by 2:

Divide the quotient (7) by 2:

Divide the quotient (3) by 2:

Divide the quotient (1) by 2:

Reading the remainders in reverse order, the binary representation of the whole number part is 111111.

Fractional Part:

To convert the fractional part (0.25) to binary, we multiply the fractional part by 2 and note the whole number part of the result. Repeat this process until the fractional part becomes 0 or until the desired precision is achieved.

Multiply the fractional part (0.25) by 2:

Multiply the fractional part (0.5) by 2:

Since the fractional part becomes 0, we stop the process.

Reading the whole number parts in order, the binary representation of the fractional part is 01.

Combining the binary representation of the whole number part and the fractional part, the binary representation of the decimal number 63.25 is 111111.01.

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Answer:

$771 is your answer rounded

Step-by-step explanation:

771.258

Answer:

895+ 78.25 + 9.12 + 4.5 will equal  986.87 just add all the numberes together and you will get 986.87

Step-by-step explanation:

so therefor your answer will be 986.87 but if you round it to the nearest hundred it would be a thousand

Answer:

your camera is too close, i don't understand

Step-by-step explanation:

Answer:

What is the question?