The ball strikes the ground after an interval of approximately 1.48 seconds.
What is gravitational force?Gravitational force is the force of attraction between two objects that is proportional to the mass of the objects and the distance between them. It is the force that causes objects to fall towards the center of the earth and it is the force that holds planets and other celestial bodies in orbit around the sun.
To determine the time interval that the ball strikes the ground, we can use the equation of motion for vertical motion under the influence of gravity:
y = vit + 1/2g*t^2
where y is the vertical displacement (or height), vi is the initial velocity, t is the time interval, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
We know that the initial velocity (vi) is -7.10 m/s (since it is thrown downward), the initial height (y) is 30.8 m, and the final height is 0 m (since it strikes the ground). So,
y = vit + 1/2g*t^2
0 = -7.10t + 1/29.8*t^2
To solve for t, we can divide both sides of the equation by -1/2*g
t = (-2*y/g) / vi
t = (-2*30.8/9.8) / -7.1
t = 1.48 s
So, the ball strikes the ground after an interval of approximately 1.48 seconds.
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a 5 kg object near earth's surface is released from rest such that it falls a distance of 10 m . after the object falls 10 m , it has a speed of 12 m/s . which of the following correctly identifies whether the object-earth system is open or closed and describes the net external force? responses the system is closed, and the net external force is zero. the system is closed, and the net external force is zero. the system is open, and the net external force is zero. the system is open, and the net external force is zero. the system is closed, and the net external force is nonzero. the system is closed, and the net external force is nonzero. the system is open, and the net external force is nonzero.
The correct response is: the system is closed, and the net external force is nonzero.
The object-earth system is closed because there are no external forces acting on the system, as all the forces are internal, i.e., the gravitational force between the object and the earth. However, the net external force is not zero because the object is accelerating due to the force of gravity. The net external force is equal to the weight of the object, which is given by W = mg, where m is the mass of the object and g is the acceleration due to gravity. Therefore, the net external force is F_net = mg = 5 kg x 9.8 m/s^2 = 49 N.
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does anyone know the answer to this ?????
Answer:
as fuel is combusted,the rocket pushes the gas is backward and the gas is pushed the rocket forward
Explanation:
hope this helps :]
Review. On a day that the temperature is 20.0°C, a concrete walk is poured in such a way that the ends of the walk are unable to move. Take Young's modulus for concrete to be 7.00× 10⁹N/m² and the compressive strength to be 2.00× 10⁹ N/m². (b) Does the concrete fracture?
The magnitude of compressive strength (cs) of concrete can be defined as the maximum amount of pressure concrete can bear before failing or fracturing.
Fracture of concrete would occur if the magnitude of tensile stress exceeds the tensile strength of the concrete. Concrete can bear compressive stress up to a specific limit beyond which it will fail and ultimately fracture. Therefore, to find out if the concrete fractures, we need to find the maximum compressive stress that the concrete can bear and compare it with the stress developed in the given case.Let's assume that the cross-sectional area of the concrete is A, and its length is L. In such a case, the change in length of the concrete is given by: ΔL = FL / AY, where F is the force applied, Y is Young's modulus, and A is the cross-sectional area. The magnitude of compressive stress developed in the concrete due to this force is given by:σ = F/AThe force required to produce a change of ΔL is given by:F = (A*Y*ΔL)/LTherefore, the magnitude of compressive stress developed in the concrete is given by:σ = (A*Y*ΔL)/(A*L)σ = YΔLSubstituting the values of Young's modulus and temperature in the formula, we get: Y = 7.00 × 10⁹ N/m²σ = YΔLσ = (7.00 × 10⁹ N/m²) × 0.0002σ = 1400 N/m²
The magnitude of compressive stress developed in the concrete is 1400 N/m², which is much smaller than the compressive strength of concrete, i.e., 2.00 × 10⁹ N/m². Hence, the concrete does not fracture.
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Hi im really confused:
How much energy would be needed to raise the temperature of the air in a room by 5.0°C if the room measures 4.0m x 4.0m x 3.0m? (Density of air = 1.0kg/m³)
Assume that the room has no furniture and that the walls gain no thermal energy.
The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
U = \(c_{p}\) m ΔT
U = Energy
\(c_{p}\) = Specific heat
m = Mass
ΔT = Change in temperature
ρ = Density
V = Volume
ρ = 1000 g / m³ (Dry air )
\(c_{p}\) = 1 J / g K
ΔT = 5 °C
V = 4 * 4 * 3
V = 48 m³
m = ρ V
m = 1000 * 48
m = 48000 g
U = 1 * 48000 * 7
U = 336000 J
U = 336 kJ
Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ
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One drops a penny from top of the Empire State Building on the ground below. The hight of the Empire State Building is 443m How long will it take for a penny yo strike the ground assuming no air resistance
Answer:
See below
Explanation:
Assuming no resistance
DISTANCE = 1/2 a t^2
443 = 1/2 (9.81)t^2 Shows t = 9.5 seconds
Is the potential energy on the surface of Earth zero?If not,what will be it's value?
Answer:
Potential energy does not have an absolute measurement. It is always relative to some reference point. Gravitational potential always increases when you go up and decreases when you go down. But the choice of a zero point is arbitrary.
If you’re dropping objects onto the ground, then choosing the ground as a zero point makes the calculations easier. But you could just as easily make the zero point the top of Mt. Everest, and all the answers would turn out the same. Up still means more energy and down means less, but now the PE of an object at sea level would have a negative sign, but not as negative as an object ten meters above sea level.
So everything would still work fine.
In fact, planetary astronomers take this idea to extremes. Instead of the top of Mt. Everest, they set the zero point for potential energy as infinitely high—so far “up” that gravity is so weak that going “up” another kilometer doesn’t gain you any energy. Then the value for potential energy everywhere else in the universe anywhere near a planet has a negative sign, but just as before, all the answers in relative terms turn out fine.
Explanation:
PLEASE MARK ME AS BRAINLIEST
8\%) Problem 9: The maximum horizontal distance that Jean can throw a baseball is 58.2 m : D Assuming she can throw with the same initial speed at all launch angles, to what maximum height (measured in meters above the release point) will the ball rise if she throws it straight upward?
The maximum height the ball will rise if Jean throws it straight upward is 0 meters above the release point.
To find the maximum height the ball will rise if Jean throws it straight upward, we can use the concept of projectile motion. The key idea is that the vertical component of the initial velocity is zero at the highest point of the trajectory.
Given that the maximum horizontal distance is 58.2 m, we can assume that the initial speed (also known as the magnitude of the initial velocity) is constant for all launch angles.
Let's denote the maximum height as "h" (measured in meters above the release point). At the highest point of the trajectory, the vertical velocity component will be zero.
Using the equation for the vertical displacement in projectile motion, we have:
Vertical displacement = (Initial vertical velocity * time) + (0.5 * acceleration due to gravity * time^2)
Since the ball is thrown straight upward, the initial vertical velocity is positive (upward). The acceleration due to gravity is negative (downward). Therefore, the equation becomes:
h = (0 * t) + (0.5 * (-9.8 m/s^2) * t^2)
Simplifying the equation, we have:
h = -4.9t^2
To find the time it takes for the ball to reach its highest point, we need to use the equation for the vertical component of the velocity:
Vertical velocity = Initial vertical velocity + (acceleration due to gravity * time)
Since the vertical velocity is zero at the highest point, we have:
0 = 0 + (-9.8 m/s^2) * t
Solving for t, we find:
t = 0
This means that at the highest point of the trajectory, the ball has been in the air for 0 seconds.
Substituting t = 0 into the equation for h, we find:
h = -4.9(0)^2
h = 0
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When Jean throws the ball straight upward, it will not rise to any height above the release point. It will only reach the same level as the release point. To determine the maximum height the ball will reach when thrown straight upward, we need to use the concept of projectile motion. When the ball is thrown straight upward, it experiences a vertical motion under the influence of gravity.
First, we need to find the initial vertical velocity of the ball. Since the ball is thrown straight upward, the initial vertical velocity is equal to zero.
Next, we need to find the time it takes for the ball to reach its maximum height. We can use the equation:
t = (final velocity - initial velocity) / acceleration
The final velocity is zero, the initial velocity is zero, and the acceleration due to gravity is -9.8 m/s^2 (taking downward as negative). Therefore, the time taken to reach the maximum height is zero.
Now, we can use the equation for vertical displacement:
Δy = (initial velocity * t) + (0.5 * acceleration * t^2)
Substituting the values, we get:
Δy = (0 * 0) + (0.5 * -9.8 * 0^2)
=> Δy = 0
This means that the maximum height the ball will rise is 0 meters above the release point. The ball will reach the same level from where it was thrown, but not higher.
In conclusion, when Jean throws the ball straight upward, it will not rise to any height above the release point. It will only reach the same level as the release point.
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A potato is which part of the plant?
root
stem
leaf
flower
A 2 kg object is released from rest near the surface of a planet such that its gravitational field is considered to be constant. The mass of the planet is unknown. The
object's speed after falling for 3 sis 75 m/s. Air resistance is considered to be negligible, Calculate the weight of the 2 kg object on the planet of unknown mass.
2N
B
25 N
50N
D
75 N
A 3.00 kg box sliding west at 2.00 m/s makes an inelastic collision with a second box sliding 1.50 m/s east. Afterwards, they both come to a stop. What was the mass of the second box?
Let west be the negative direction, and east be positive. Then the total momentum of the system is conserved such that
(3.00 kg) (-2.00 m/s) + m (1.50 m/s) = 0
Solve for m :
m = (3.00 kg) (2.00 m/s) / (1.50 m/s) = 4.00 kg
Which substances are inorganic? Check all that apply.
C6H12O6
K2CO3
C4H10
C27H46O
Fe3O4
The major characteristic an organic compound has which an inorganic
compound doesn't have is the presence of carbon atoms in the molecule.
This helps us to differentiate the compounds into their respective divisions.
Inorganic compounds
K2CO3Fe3O4Organic compounds
C6H12O6C4H10C27H46OWe can observe that inorganic compounds lack carbon atoms which makes
the answer valid.
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Answer:
B and E because yk thats the asnwer
The ballistic pendulum was invented in 1742 by English mathematician Benjamin Robins. It consists of an initially stationary pendulum that moves after being struck by a bullet, and it is used to measure the original velocity of the bullet. The known variables are the bullet's mass m, the Pendulum's mass M, and the height to which the block and bullet swing, determined by the length of the pendulum L and final angle θ.
Two principles of physics are necessary to solve for the bullet's original velocity. What are these principles?
Conservation of Momentum and Newton’s Second Law.
Conservation of Momentum and Newton’s Third Law.
Conservation of Energy and Conservation of Angular Momentum.
Conservation of Momentum and Conservation of Energy.
Newton's Second Law and Conservation of Angular Momentum.
Conservation of Momentum and Conservation of Angular Momentum.
Conservation of Energy and Newton’s Third Law.
Conservation of Energy and Newton's Second Law.
The principles necessary to solve for the bullet's original velocity in the ballistic pendulum are Conservation of Momentum and Conservation of Energy.
Conservation of Momentum: This principle states that the total momentum of a system remains constant if no external forces act on it. In the ballistic pendulum, the momentum before the collision between the bullet and the pendulum is equal to the momentum after the collision.
Conservation of Energy: This principle states that the total energy of a system remains constant if no external forces do work on it. In the ballistic pendulum, the initial kinetic energy of the bullet is transferred to the pendulum as gravitational potential energy when the pendulum swings upward.
Therefore, the correct answer is:
Conservation of Momentum and Conservation of Energy.
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Q2. Fill in the blanks:
North Pole of a magnet will.....
.. North pole of another magnet.
South Pole of a magnet will.
North pole of a another magnet.
Needle of a compass lines up with the......
of a magnet.
You can find the shape of a magnetic field using........
...... and also a plotting.
Answer:
repel , attract,l am sure with these two blanks only
Answer:
Magnetic fields
A magnet creates a magnetic field around it. You cannot see a magnetic field, but you can observe its effects. A force is exerted on a magnetic material brought into a magnetic field. The force is a non-contact force because the magnet and the material do not have to touch each other.
The shortest plane mirror in which you can see your entire image is:.
The shortest plane mirror in which you can see your entire image is typically half your body's height, assuming that the mirror is positioned vertically and you are standing in front of it.
When you stand in front of a plane mirror, the mirror reflects the light rays that hit it, creating a virtual image. The virtual image appears to be behind the mirror and is the same size as the object being reflected.
To see your entire image in the mirror, you need to position yourself in such a way that the top of your head and the bottom of your feet are both within the field of view of the mirror. Therefore, the height of the mirror should be at least equal to your body height.
However, if you position the mirror at an angle or tilt it, you may be able to see your entire image in a mirror that is shorter than half your body height. The angle and orientation of the mirror will affect the field of view and the visibility of your image.
It's important to note that this measurement assumes an average human body height and a mirror that is positioned vertically. Individual variations in height and the specific arrangement of the mirror can affect the minimum height of the mirror needed to see your entire image.
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A bag of sugar weights 20 N on the earths surface. If you double the distance from the center of the earth, the bag now weighs what
the peak of solar radiation occurs in what part of the electromagnetic spectrum? group of answer choices radiowaves microwaves visible light gamma rays
The peak of solar radiation occurs in part of the electromagnetic spectrum i.e. Visible light. Hence, the correct option is (c).
The peak of solar radiation occurs in the visible light part of the electromagnetic spectrum. The Sun emits energy across a wide range of wavelengths, including radio waves, microwaves, visible light, and gamma rays. However, when we analyze the distribution of this energy, we find that the maximum amount of radiation is emitted in the visible light region.
Visible light consists of various colors, each corresponding to a specific wavelength. The Sun emits the most energy at wavelengths that correspond to the colors green and yellow, which is why we perceive sunlight as being predominantly yellowish. This peak in energy emission in the visible light range is essential for sustaining life on Earth, as it enables photosynthesis in plants and allows us to see.
While other parts of the electromagnetic spectrum, such as radio waves, microwaves, and gamma rays, are also emitted by the Sun, the peak of solar radiation occurs in the visible light range. This peak is significant for various biological processes and plays a crucial role in the functioning of our planet.
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A toy radio-controlled car races around a circular track in a time of 2 MINUTES, with a speed of 5.25 m/s. What is the radius of the
circular track? (will give brainliest)
Answer:
The radius will be "100.31 m". A further solving is given below.
Explanation:
The given values are:
Time,
T = 2 minutes
i.e.,
= 120 seconds
Speed,
V = 5.25 m/s
As we know
⇒ \(T=\frac{2 \pi R}{V}\)
then,
⇒ \(R=\frac{TV}{2 \pi}\)
On substituting the given values, we get
⇒ \(=\frac{120\times 5.25}{2\times 3.14}\)
⇒ \(=\frac{630}{6.28}\)
⇒ \(=100.31 \ m\)
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
\(m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s\)
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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Displacement vectors of 4 km south, 2 km north, 5 km south, and 5 km north combine to a total displacement of: ________
The total displacement of the vectors is 2 km south.
Distance is the total path that an object in motion has traveled. Displacement is a verb that denotes the movement or displacement of an object.
Here, the vector moves 4 km towards the south, then moves 2 km north. The vector again moves 5 km south and moves 5 km north. Draw the diagram, mentioning the 4 km south movement by the black arrow, the 2 km north movement by the blue arrow, the 5 km south movement by the orange arrow, and the 5km north movement by the green arrow.
Also, mark the starting and ending points. These points give the displacement of the diagram. From the diagram, we can tell, the displacement is 2 km south of the starting point.
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question 1 and 2 and maybe get brainlyest
an aluminum wire with a diameter of 0.100 mm has a uni-form electric field of 0.200 v/m imposed along its entire length. the temperature of the wire is 50.08c. assume one free electron per atom. (a) use the information in table 26.2 to determine the resistivity of aluminum at this temperature. (b) what is the current density in the wire? (c) what is the total current in the wire? (d) what is the drift speed of the conduction electrons? (e) what potential difference must exist between the ends of a 2.00-m length of the wire to produce the stated electric field?
(a) Using the information in table 26.2, we can find the resistivity of aluminum at this temperature. From the table, we find that the resistivity of aluminum at \(50.08°C is 2.83 x 10^-8 Ωm.\)
(b) The current density J in the wire is given by:
\(J = σE\)
where σ is the conductivity of aluminum and E is the electric field. Since σ = 1/ρ, where ρ is the resistivity, we have:
J = (1/ρ)E
Plugging in the values, we get:
\(J = (1/2.83 x 10^-8 Ωm)(0.200 V/m) = 7.06 x 10^6 A/m^2\)
(c) The total current I in the wire is given by:
I = JA
where A is the cross-sectional area of the wire. The cross-sectional area of the wire can be calculated using the formula:
\(A = πr^2\)
where r is the radius of the wire, which is half of the diameter. So, we have:
\(A = π(0.100/2 x 10^-3 m)^2 = 7.85 x 10^-8 m^2\)
Plugging in the values, we get:
\(I = (7.06 x 10^6 A/m^2)(7.85 x 10^-8 m^2) = 0.554 A\)
(d) The drift speed v of the conduction electrons can be calculated using the formula:
\(v = (J/ne)(1/A)\)
where n is the number of free electrons per unit volume of the wire, and e is the charge of an electron. Since there is one free electron per atom and the atomic mass of aluminum is 26.98 g/mol, we can calculate the number density of aluminum atoms using the formula:
\(ρ = (N/V)m\)
where N is Avogadro's number, V is the molar volume of aluminum, and m is the atomic mass of aluminum. Plugging in the values, we get:
\(ρ = (6.022 x 10^23/mol)(10.0 cm^3/mol)(26.98 g/mol)/(1000 g/kg) = 2.699 x 10^22 atoms/m^3\)
Since each atom has one free electron, the number density of free electrons is also 2.699 x 10^22 electrons/m^3. Plugging in the values, we get:
\(v = (J/ne)(1/A) = (7.06 x 10^6 A/m^2)/(2.699 x 10^22/m^3)(1/7.85 x 10^-8 m^2) = 0.054 m/s\)
(e) The potential difference V required to produce the stated electric field along a length L of the wire is given by:
V = EL
Plugging in the values, we get:
\(V = (0.200 V/m)(2.00 m) = 0.400 V\)
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!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
Second choice
Explanation:
I suppose ME is the same as POTENTIAL energy
ME = mgh = 70 * 10 * 12 = 8400j
Half way down, 4200 j is converted to Kinetic Energy
1/2 m v^2 = 4200
1/2 (70) v^2 = 4200 v = 10.95 m/s
Just before impact ALL of the 8400 j is now KE
1/2 (70)v^2 = 8400 v = 15.49 m/s
.A drawing pin is pressed into the notice board. The pointed pin area is 0.25 mm² and the force exerted on the pin is 10 newtons. Compute the pressure.
The pressure exerted is 4 × 10⁷ N/m²
Pressure is the force carried out perpendicular to the surface of an item in step with the unit vicinity over which that force is sent. Gauge pressure is the pressure relative to the ambient strain. numerous units are used for the explicit strain.
Strain is a pressure carried out perpendicular to the surface of an item in keeping with unit location. Mathematically it is P = F/A, in which P is strain, F is force, and A is area. strain is a scalar amount, one that most effectively has value and no directional vector characteristics.
Calculation:-
Given,
area = 0.25 mm2
= 2.5 × 10⁻⁷ m²
Force = 10 N
Pressure = force/area
= 10 / 2.5 × 10⁻⁷
= 4 × 10⁷ N/m²
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height 5. An inclined plane is 100 m long and at an angle of 20° to the horizontal. The AMA of the slope is two. Calculate: a) the effort required to push a 7200 N block up the slope b) the ideal mechanical advantage c) the efficiency of the slope.
(a) The effort required to push the block up the slope is 3600 N.
(b) the ideal mechanical advantage of the slope is 2.92
(c) The efficiency of the slope is 68.5%.
What is the effort required?a) To calculate the effort required to push the block up the slope, we can use the formula:
Effort = Load / AMA
where;
Load is the weight of the block, and AMA is the actual mechanical advantage of the slope.Load = 7200 N
AMA = 2
Effort = 7200 N / 2
Effort = 3600 N
b) The ideal mechanical advantage (IMA) of an inclined plane is given by the formula:
IMA = Length of slope / Height of slope
Length of slope = 100 m
Angle of slope = 20°
We can use trigonometry to find the height of the slope:
Height of slope = Length of slope x sin(angle of slope)
Height of slope = 100 m x sin(20°)
Height of slope = 34.2 m (rounded to one decimal place)
Therefore, the ideal mechanical advantage of the slope is:
IMA = 100 m / 34.2 m
IMA = 2.92 (rounded to two decimal places)
c) The efficiency of the slope is given by the formula:
Efficiency = AMA / IMA x 100%
AMA = 2
IMA = 2.92
Efficiency = 2 / 2.92 x 100%
Efficiency = 68.5% (rounded to one decimal place)
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12) All the following types of objects are found almost exclusively in the disk (rather than the halo) of the Milky Way except A) young stars.
B) globular clusters.
C) X-ray binaries.
D) high-mass, red supergiant stars.
B) Globular clusters. Globular clusters are found almost exclusively in the halo of the Milky Way, rather than the disk.
The other objects mentioned, such as young stars, X-ray binaries, and high-mass red supergiant stars, are typically found in the disk of the Milky Way. Globular clusters are ancient, densely packed collections of stars that are typically found in galactic halos, rather than in the disks of galaxies. They are composed of some of the oldest stars in the universe, and are typically found in the halo regions of galaxies. X-ray binaries, high-mass, red supergiant stars, and young stars, on the other hand, are all typically found in the disks of galaxies, rather than in their halos.
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Which geologic events occur most often at this mid-oceanic ridge plate
boundary? *
2 points
Mid-oceanic ridge
plate boundary
Shelf
Sea level
Patella
Plate 2
Continental
crust
Rigid mantle
Asthenosphere
magnetic pole reversals and cooling of ocean water
hydrospheric pollution and adiabatic heating
earthquakes and volcanic eruptions
Answer: Earthquakes and Volcanic eruptions
Explanation:
You did not attach a picture however, this should be the correct answer.
Mid-oceanic ridge plate boundaries such as the Mid-Atlantic Ridge form as a result of plate separating at the boundary. This leads to earthquakes due to the forces of tension acting on the plates.
When this happens, the mantle is exposed and therefore there will be volcanic eruptions as the lava comes to the surface as magma. When this magma cools it creates new seafloors and underwater mountains.
What is the resultant?
1400 N
643 N
how much work is needed for a 68-kg runner to accelerate from rest to 7.5 m/s?
To calculate the work needed for a 68-kg runner to accelerate from rest to 7.5 m/s, we can use the equation: work = 1/2 * mass * velocity^2 Plugging in the values we have: work = 1/2 * 68 kg * (7.5 m/s)^2 work = 1906.25 joules Therefore, the amount of work needed for the runner to accelerate from rest to 7.5 m/s is 1906.25 joules.
To calculate the work needed for a 68-kg runner to accelerate from rest to 7.5 m/s, we'll use the work-energy principle, which states that work equals the change in kinetic energy. The formula for kinetic energy is KE = 0.5 * m * v^2, where m is mass and v is velocity.
Initial kinetic energy (rest): KE_initial = 0.5 * 68 kg * 0 m/s^2 = 0 J (joules)
Final kinetic energy: KE_final = 0.5 * 68 kg * (7.5 m/s)^2 = 1912.5 J
Now, we find the work done by calculating the change in kinetic energy:
Work = KE_final - KE_initial = 1912.5 J - 0 J = 1912.5 J
So, the work needed for a 68-kg runner to accelerate from rest to 7.5 m/s is 1912.5 Joules.
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very dense material when heated will give off a ____ spectrum.
When very dense material is heated, it produces a continuous spectrum. A continuous spectrum is an electromagnetic radiation that displays a continuous range of wavelengths or colors.
The spectrum has no gaps or breaks and is seen as a smooth, unbroken band of colors that blend into each other.A continuous spectrum is created by solids, liquids, and dense gases when heated. The molecules in these materials begin to move around more quickly when they absorb thermal energy.
As a result of this motion, the electrons in the atoms within the material are excited to higher energy levels.This means that the electrons move from lower energy levels, which are closer to the atomic nucleus, to higher energy levels, which are further away from the nucleus. When the electrons transition back to their lower energy states, they release energy in the form of electromagnetic radiation.
The radiation that is released includes a continuous range of wavelengths, which produce a continuous spectrum.Continuous spectra are important in astronomy because they help scientists learn about the temperatures of the objects producing the radiation. By analyzing the spectrum, they can determine the temperature of the object.
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A laser produces light at 5.32x10-7 m.
What is the frequency of the light?
A. 1.77x10-6 Hz
B. 1.60x1011 Hz
C. 1.88x107 Hz
D. 5.64x1014 Hz
Answer:
D
Explanation:
speed = frequency x wavelength
speed of light in vacuum is 3.0 x 10^8
wavelength = 5.32 x10 ^-7
3.0 x 10 ^ 8 = 5.32 x 10^-7 x frequency
frequency = 5.63909 x 10^14
round it off = 5.64 x 10^14 Hz
thus the answer is D
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