A 75.0-kg man is riding an escalator in a shopping mall. The escalator moves the man at
a constant velocity from ground level to the floor above, a vertical height of 4.60 m. What
is the work done on the man by (a) the gravitational force and (b) the escalator?

(A)

Explanation:

The number of atoms for each element on the left side must equal that on the right side. Only (A) satisfies that condition. The other other choices have mismatching number of atoms on either side.

Answer A

Explanation:  because u need to make sure you know the difference between a need and a want

Answer:

a

Explanation:

Hi there!

Recall the equation for work given a potential difference and charge:
\(\large\boxed{W = qV}\)

W = Work (J)
q = charge (C)
V = Potential difference (V)

The work is equivalent to the change in KINETIC ENERGY, and only depends on the particle's charge and the potential difference that it experiences. Mass has no impact on this.

Thus:

\(W' = (2Q)(V) = 2W\)

This is equivalent to:

\(\large\boxed{2W = \text{ d) } 2K}}\)

The water flow rate from the faucet, assuming a steady flow, is approximately 0.0001608 cubic meters per second.

The phenomenon of a water stream "necking down" as it falls can be explained by the principle of conservation of mass. According to this principle, the flow rate of water remains constant throughout the system.

In the given figure, the water stream emerges from a faucet with an initial cross-sectional area of 1.8 cm² (Area one). As the water falls, it narrows down to a smaller cross-sectional area of 0.3 cm² (Area two) at a height of 25 cm.

To calculate the water flow rate assuming steady flow, we can use the formula:

Flow rate = A₁√(2gh) / A₁² - A₂²

Where A₁ and A₂ are the initial and final cross-sectional areas, respectively, g is the acceleration due to gravity, and h is the height of the water column.

Plugging in the given values, we have:

Flow rate = 1.8 cm² √(2 × 9.8 m/s² × 25 cm) / (1.8 cm²)² - (0.3 cm²)²

Converting the units to match, we get:

Flow rate = 0.018 m² √(2 × 9.8 m/s² × 0.25 m) / (0.018 m²)² - (0.003 m²)²

Simplifying the expression, we find:

Flow rate ≈ 0.0001608 m³/s

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Based on the mass of the liquid and the mass of the cylinder, the reading shown on the balance is 1.593 kg.

To calculate the reading shown on the digital balance, we need to first find the mass of the liquid in the cylinder, and then add it to the weight of the empty cylinder.

The volume of the liquid can be found using the formula for the volume of a cylinder:

V = πr²h

where;

r is the radius of the cylinder, and h is the depth of the liquid.

Substituting the given values, we get:

V = π x (3.5 cm)² x 12.0 cm

= 1486.96 cm³

We need to convert the volume from cubic centimeters to cubic meters to use the density of the liquid in kilograms per cubic meter:

V = 1.48696 x 10⁻³ m^3

The mass of the liquid can be found using the formula:

mass = density x volume

Substituting the given values, we get:

mass = 900 kg/m³ x 1.48696 x 10⁻³ m³

= 1.33826 kg

Therefore, the reading shown on the digital balance is:

mass of empty cylinder + mass of liquid

mass of empty cylinder = 2.5/9.81

mass of empty cylinder = 0.2548 kg

reading shown on the digital balance =  0.2548 kg + 1.33826 kg

reading shown on the digital balance = 1.593 kg

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Answer:

The Saffir-Simpson Hurricane Wind Scale is a 1 to 5 rating based only on a hurricane's maximum sustained wind speed. This scale does not take into account other potentially deadly hazards such as storm surge, rainfall flooding, and tornadoes.

The Saffir-Simpson Hurricane Wind Scale estimates potential property damage. While all hurricanes produce life-threatening winds, hurricanes rated Category 3 and higher are known as major hurricanes*. Major hurricanes can cause devastating to catastrophic wind damage and significant loss of life simply due to the strength of their winds. Hurricanes of all categories can produce deadly storm surge, rain-induced floods, and tornadoes. These hazards require people to take protective action, including evacuating from areas vulnerable to storm surge.

Explanation:

pls mark as branlist.

Tropical hurricanes or cyclones are usually destructive with great wind speeds of 3 and above according to the Saffir Simpson Hurricane Wind Scale with huge amounts of rainfall resulting in flooding.

The Saffir Simpson Hurricane Wind Scale is scale that classifies wind based on wind speed using a scale of 1-5.

This scale does not take into account wind surge, amount of rainfall and other characteristics of storms.

Storms rated 3 and above are particularly strong and destructive.

Those rated below 3 are mild and less destructive.

Tropical hurricanes or cyclones are usually destructive with great wind speeds of 3 and above according to the Saffir Simpson Hurricane Wind Scale with huge amounts of rainfall resulting in flooding.

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Answer:

the floor deforms very slightly under your weight

Explanation:

A trampoline is made up of a large piece of strong cloth held by springs on which you jump up and down as a sport. So, If you stand on a trampoline, it depresses under your weight.  However, the floor does not deform under your weight as it is too stiff.

Therefore,

when you stand on a hard stone floor, the floor deforms very slightly under your weight.

Speed of the drop will be 15.4919m/s

Given :- g =10m/s²

u=0

s=12

v²-u²=2as is the formula to be used.

v²=u²+2as

v²=2 x 10 x 12

=240

v=√240 m/s

=15.4919m/s

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To push a box up an inclined plane, the force required is smaller if you push parallel to the incline.

This is also referred to as a ramp and is a flat surface which is tilted at an angle.

Pushing parallel to the plane doesn't generate friction which means a smaller amount of force will be required.

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Answer:

The centripetal acceleration of the car will be 12.32 m/s² .

Explanation:

Given that

radius ,R= 57 m

Velocity , V=26.5 m/s

We know that centripetal acceleration given as follows

\(a_c=\dfrac{V^2}{R}\)

Now by putting the values in the above equation we get

\(a_c=\dfrac{26.5^2}{57}=12.32\ m/s^2\)

Therefore the centripetal acceleration of the car will be 12.32 m/s² .

Answer:  a stretch of 2

Explanation: because it 2 (x) - 3

The total volume of the piece of wood is 1.33\(cm^3\).

To calculate the total volume of the piece of wood, we can use the principle of displacement.

1. First, we need to find the difference in volume between the two water levels. The initial volume is 17.7 \(cm^3\), and the final volume is 18.5 cm^3. The difference is 18.5 \(cm^3\) - 17.7 \(cm^3\) = 0.8 \(cm^3\).

2. Now, we need to find the volume of water displaced by the piece of wood. Since the relative density of the wood is 0.60, it means that the wood is 0.60 times denser than water.

3. The volume of water displaced by the wood is equal to the difference in volume divided by the relative density of the wood. So, the volume of water displaced is 0.8 cm^3 / 0.60 = 1.33 \(cm^3\).

4. Finally, the total volume of the piece of wood is equal to the volume of water displaced. Therefore, the total volume of the piece of wood is 1.33 \(cm^3\).

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Answer:

i have this qustion and i am in middle school you in

Explanation:

Answer:

to see how it affects the planes and to obsereve the damage the birds have taken

Explanation:

Answer:

I will use (a / R) for alpha the angular acceleration

T R = I a / R     torque equals angular acceleration for cylinder

M g - T = M a    linear acceleration of center of mass

T = M (g - a) = I a / R^2 from first equation

If I = 1/2 M R^2 then M ( g - a) = M a / 2    from above

or g = 3 a / 2  and a = 2 g / 3

Also we have T = M (g - a) = M (g - 2 g / 3) = g / 3

Substitute I = M R^2 for the hollow cylinder

Looks like a = g/2 for hollow cylinder

The multiplication of the given decimals in kg*cm/s and kg*m/s to 3 significant figures are 60.7kg.cm/s  and 0.607kg.m/s respectively.

Given that;

a × b = ?

2.594kg × 23.4cm/s

= 60.6996kg.cm/s

= 60.7kg.cm/s ( 3 significant figures )

a × b = ?

2.594kg × 0.234m/s

= 0.606996kg.m/s

= 0.607kg.m/s ( 3 significant figures )

The multiplication of the given decimals in kg*cm/s and kg*m/s to 3 significant figures are 60.7kg.cm/s  and 0.607kg.m/s respectively.

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So the speed of object of mass 4 Kg and kinetic energy of 32 j at 10 second is 4 m/s.

Kinetic energy is the energy that an object has when it moves or changes its position. As long as an object is moving at the same speed, it maintains the same kinetic energy.

The kinetic energy of an object is calculated from the object's velocity and mass. As can be seen from the equation below, velocity is quadratic and can have a large effect on kinetic energy.

KE = ¹/₂ mv²

v = √(2KE/m)

Where, v = velocity

M = Mass of object (4.0 Kg)

KE = Kinetic energy (32 j)

v = √(2 × 32/4)

v = √16

v = 4 m/s

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A father and son push a 500 kg car for 5 minutes using a force of 50 N, but the car does not move.

Hence, the correct option is A.

The work done is equal to the force applied multiplied by the distance moved in the direction of the force.

In this case, the car does not move, so the distance moved is zero. Therefore, the work done by the father and son pushing the car is

Work = Force x Distance

Work = 50 N x 0 m

Work = 0 Joules (J)

Work = 0 J

Hence, the correct option is A.

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The government started allowing reservations for Native Americans to use federal monies in 1954, but stopped by 1962.

The earliest phase of Indian encounters with Europeans is when the word "exclusive" originally appeared. A sizable portion of the Indians' country was "reserved" for their exclusive use through treaties. Indians were intended to live on reserves, which are frequently sparsely populated areas of land.

Displacement to reservations had two purposes for the United States. Native Americans were originally removed from the area to create room for westward territories. Second, it made it possible for the US to carry out a strategy to transform tribal villages into modest farming settlements.

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Answer:

Explanation:

Voltage and Current relation is given by V=IR
I=9A

R=4Ohm

V=IR
V=9x4=36Volts

Resistance = 4 Ohm

Current = 9 Ampere

Voltage = 36 Volts

Answer:

power

Explanation:

Answer:

power

Explanation:

Answer:

0.5 m/s²

Explanation:

F=ma
F is force
m is mass
a is acceleration

F=ma
5 =  10 x a
a = 5/10
a = 0.5 m/s²

Answer:

the tension in the part of the cord attached to the textbook is 7.4989 N

Explanation:

Given the data in the question;

As illustrated in the image below;

first we determine the value of the acceleration,

along vertical direction; we use the second equation of motion;

y = ut + \(\frac{1}{2}\)a\(_y\)t²

we substitute;

0 m/s for u, 1.29 m for y, 0.850 s for t,

1.29 = 0×0.850  + \(\frac{1}{2}\)×a\(_y\)×(0.850)²

1.29 = 0.36125a\(_y\)

a\(_y\) = 1.29 / 0.36125

a\(_y\) = 3.5709 m/s²

Now when the text book is moving with acceleration , the dynamic equation will be;

T₁ = m₁a\(_y\)

where m₁ is the mass of the text book ( 2.10 kg )

a\(_y\) is the vertical acceleration ( 3.5709 m/s² )

so we substitute

T₁ = 2.10 × 3.5709

T₁ = 7.4989 N

Therefore, the tension in the part of the cord attached to the textbook is 7.4989 N

If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Answer:

2 in front of water and 1 in front of oxygen

Explanation:

Answer:

the correct answer is D

Explanation:

The specific latent heat of fusion of ice obtained from this experiment is approximately 583.33 J/g.

To determine the specific latent heat of fusion of ice using the given experiment, we need to consider the energy transferred during the process.First, we need to calculate the energy lost by the water to cool down from 25 °C to 0 °C. The energy lost is given by:

Q1 = m1 * c * ΔT1

Where:

m1 = mass of water = 100 g

c = specific heat capacity of water = 4.2 J/g °C

ΔT1 = change in temperature = (0 °C - 25 °C) = -25 °C

Q1 = 100 g * 4.2 J/g °C * (-25 °C) = -10,500 J

Next, we calculate the energy released by the water to freeze and cool the remaining ice. The energy released is given by:

Q2 = m2 * Lf

Where:

m2 = mass of ice = 18 g

Lf = specific latent heat of fusion of ice (to be determined)

Q2 = 18 g * Lf

Since energy is conserved in the system, the energy lost by the water (Q1) is equal to the energy released by the water (Q2):

-10,500 J = 18 g * Lf

Solving for Lf:

Lf = -10,500 J / 18 g = -583.33 J/g

The negative sign indicates that energy is being released during the process of freezing.

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Answer: C

Explanation: 60 divided by 4 =15

Velocity can be defined as the rate of change of distance with time

Given data

Acceleration = 4/ms^2

Distance = 60m

Initial Velocity U= 0

Final Velocity V= ?

The expression for velocity is given by

V^2= U^2+2as

Let us substitute our given data into the expression

V^2 = 0^2 + 2*4*60

V^2 = 480

Square both sides

V= √480

V= 21.9 meters/second

V= 22 meters/seconds Approx.

The correct answer is option B

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If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

Geology is the study of the Earth that involves the process at Earth, materials of which it is made, and its history.

Geologists combine both laboratory and field data to illustrate the results of their research. Some observations that can the geologist make by working outdoors instead of in a lab are as follows: