7. An auto's velocity increases uniformly from 3m/s to 25m/s while
covering 90m. Calculate the acceleration. *

Answer: The answer would be option B waxing phase as per the phases of the moon.

Explanation: The moon has a cycle of 30 days in the first fifteen days it starts from a new moon and travels the path upto it reaches a full moon this phase of the moon is called Waxing Phase and in the next phase it travels from a full moon to the new moon again and this phase of the moon is said to be the Waning Phase.

These two phases of the moon are also divided into two subphases where they have Crescent and Gibbous.

As per these explanations, the conclusion could be driven that the moon from a full moon to a new moon is called as Waning phase.

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The net force on particle q₁ is 9.22 × 10^-13 N, and it points to the left.

The net force on particle q₁ due to particles q2 and q3 can be found using Coulomb's law.

Coulomb's law states that the force between two charged particles is given as

F= k * (q₁ * q₂) / r^2

Since q₁ and q₂ have the same charge, the force between them is repulsive, i.e., it points to the left. Using Coulomb's law, we can find the magnitude of this force:

F₁₂ = k * (q₁ * q₂) / r₁₂^2

F₁₂ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2

F₁₂ = -4.61 × 10^-13 N

Here,  the force between q₁ and q₂ points to the left, and its magnitude is 4.61 × 10^-13 N.

The  force between q₂ and q₃ also points to the left, and its magnitude is given as

F₂₃ = k * (q₂ * q₃) / r₂₃^2

F₂₃ = (9 × 10^9 Nm^2/C^2) * (-2.35 × 10^-6 C)^2 / (0.100 m)^2

F₂₃ = -4.61 × 10^-13 N

Here,  the force between q₂ and q₃ also points to the left, and its magnitude is 4.61 × 10^-13 N.

F_net = -F₁₂ - F₂₃

F_net = -(-4.61 × 10^-13 N) - (-4.61 × 10^-13 N)

F_net = 9.22 × 10^-13 N

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Answer:

The net force on the hanging mass is thus

2 T Mg     18 6.6 N 11.4 N

, enough to accelerate it upward at

17 m/s2

. The angular acceleration of the pulley is thus

   

2 2

Explanation:

The tension in the rope on both sides of the pulley 20.21N.

To solve this problem, we'll need to consider the forces acting on both sides of the pulley and apply Newton's second law of motion. Let's break it down step by step:

(a) Is the tension in the rope the same on both sides of the pulley?

No, the tension in the rope is not the same on both sides of the pulley. The side with the greater mass attached will experience a greater tension in the rope.

(b) Find the tension in the rope on both sides of the pulley:

Calculate the gravitational force on each mass:

Gravitational force on the pulley: Fpulley = mpulley * g, where mpulley is the mass of the pulley and g is the acceleration due to gravity (approximately 9.8 m/s²).

Gravitational force on the hanging mass: Fhanging = mhanging * g, where m_hanging is the mass of the hanging mass.

Calculate the net force on the pulley:

Net force on the pulley is the difference between the tension forces on either side: Fnet = TLeft - Tright.

Apply Newton's second law to the pulley:

For the pulley, Fnet = mpulley * a, where a is the acceleration of the pulley. Since the pulley is assumed to be massless, we can use the relationship a = α * r, where α is the angular acceleration and r is the radius of the pulley.

Use the relationship between linear acceleration and angular acceleration:

α = a / r.

Equate the torque due to the tension to the moment of inertia times the angular acceleration:

τ = I * α, where τ is the torque, I is the moment of inertia of the pulley, and α is the angular acceleration.

Substitute the expression for α and solve for the net tension:

Tnet = (τ / r) = (I * α) / r = (1/2 * mpulley * r² * α) / r = (1/2 * mpulley * r * a).

Now, substitute the expression for a from step 3 and solve for the net tension:

Tnet = (1/2 * mpulley * r * α) = (1/2 * mpulley * r * (a / r)) = (1/2 * mpulley * a).

Substitute the expression for a from step 2 (Fnet = mpulley * a) and solve for the net tension:

Tnet = (1/2 * Fnet).

Now, you can find the tensions on each side of the pulley:

Tleft = Tnet + Fhanging

Tright = Tnet - Fpulle

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Answer:

The Earth’s lithosphere, which includes the crust and upper mantle, is made up of a series of pieces, or tectonic plates, that move slowly over time.

A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth’s mantle to the surface, solidifying to create new oceanic crust. The Mid-Atlantic Ridge and Pacific Ring of Fire are two examples of divergent plate boundaries.

When two plates come together, it is known as a convergent boundary. The impact of the colliding plates can cause the edges of one or both plates to buckle up into a mountain ranges or one of the plates may bend down into a deep seafloor trench. A chain of volcanoes often forms parallel to convergent plate boundaries and powerful earthquakes are common along these boundaries.

At convergent plate boundaries, oceanic crust is often forced down into the mantle where it begins to melt. Magma rises into and through the other plate, solidifying into granite, the rock that makes up the continents. Thus, at convergent boundaries, continental crust is created and oceanic crust is destroyed.

Two plates sliding past each other forms a transform plate boundary. One of the most famous transform plate boundaries occurs at the San Andreas fault zone, which extends underwater. Natural or human-made structures that cross a transform boundary are offset—split into pieces and carried in opposite directions. Rocks that line the boundary are pulverized as the plates grind along, creating a linear fault valley or undersea canyon. Earthquakes are common along these faults. In contrast to convergent and divergent boundaries, crust is cracked and broken at transform margins, but is not created or destroyed.

After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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Answer:

it would take him 3 hours to travel 90 miles

Explanation:

Answer:

Electrons repel one another - they will move "away" from the left side of the leftmost can- (the right can must become more negatively charged than the left can) -

B appears to be the best answer

The electrons move from the left soda can to the right soda can. The answer is (B).

When the negatively charged balloon is moved close to the left soda can, it will repel the negatively charged electrons in the soda can. This will cause the electrons to move away from the balloon and distribute themselves within the soda can.

Since the soda cans are in contact with each other, the excess electrons from the left soda can will be repelled by the negative charge on the balloon and will flow to the adjacent right soda can. The electrons will continue to move until there is no potential difference between the two cans, which means that they will stop flowing when both cans have the same amount of negative charge.

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The displacement of the object after 1 second, is 3 m.

The displacement of the object after 3 seconds, is 9 m.

The displacement of the object after 5 seconds, is 15 m.

The displacement of an object is the change in the position of the object.

The displacement of the object after 1 second, x = 3 m/s x 1 second = 3 m

The displacement of the object after 1 second, x = 3 m/s x 3 s = 9 m

The displacement of the object after 1 second, x = 3 m/s x 5 s = 15 m

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Answer:

C.

Explanation:

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

\(a = \frac{f}{m} \\ \)

where

m is the mass

f is the force

We have

\(a = \frac{275}{18} \\ = 15.277777...\)

We have the final answer as

Hope this helps you

Bohr's work demonstrates the importance of communication in science by making use of works communicated by other scientists.

Bohr's work on atomic structure and the quantization of energy demonstrated the importance of communication in science by highlighting the need for clear and effective communication between scientists from different fields.

Bohr's theory was based on the work of other scientists, including Planck and Einstein, and required collaboration and communication between physicists, chemists, and mathematicians.

By effectively communicating his ideas and working with others, Bohr was able to develop a groundbreaking theory that revolutionized the understanding of atomic structure and paved the way for future advances in physics and chemistry.

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Answer:

8.0 rad/s

Explanation:

I₁ = 1.0 kgm², ω₁ = -20.0 rad/s (clockwise is positive direction)

I₂ = 4.0 kgm², ω₂ = 15.0 rad/s

Angular momentum conservation:

I₁ω₁ + I₂ω₂ = (I₁ + I₂)ω

1.0 x (-20.0) + 4.0 * 15.0 = (1.0 + 4.0)ω

40.0 = 5.0ω

so ω = 8.0 rad/s

Answer:

temperatures is directly proportional to kinetic energy

Explanation:

in increasing the temperature,kinetic energy also increases

hope it helps...

Answer:

b

Explanation:

Using the formula for the Doppler effect:

f' = (v + vr) / (v + vs) * f

Given:

Source frequency (horn): f = 625 Hz

Speed of sound: v = 343 m/s (approximate value at room temperature)

The velocity of the receiver, vr, is zero because the person waiting at the crosswalk is stationary.

The velocity of the source, vs, is the speed of the car, which is given as 9.0 m/s.

Thus:

f' = (v + vr) / (v + vs) * f

= (343 m/s + 0) / (343 m/s + 9.0 m/s) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

Therefore, the person waiting at the crosswalk hears a frequency of approximately 609 Hz.

(2)Using the same Doppler effect formula:

f' = (v - vr) / (v - vs) * f

In this case, the velocity of the receiver, vr, is still zero because the person remains stationary.

The velocity of the source, vs, is now negative, indicating that the car is moving away from the person.

Thus:

f' = (v - vr) / (v - vs) * f

= (343 m/s + 0) / (343 m/s - (-9.0 m/s)) * 625 Hz

= (343 m/s) / (352 m/s) * 625 Hz

≈ 609 Hz

In other words, as the car moves away from the person, they would still hear a frequency of approximately 609 Hz.

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The pressure after the temperature has risen to 40.0 °C, assuming that there are no appreciable leaks or changes in volume is 4.35×10⁵ Pa

From the question given above, the following data were obtained:

The pressure the temperature has risen to 40 °C can be obtained as follow:

P₁V₁ / T₁ = P₂V₂ / T₂

Volume = contant

P₁ / T₁ = P₂ / T₂

4.00×10⁵ / 288 = P₂ / 313

Cross multiply

P₂ × 288 = 4.00×10⁵ × 313

Divide both sides by 288

P₂ = (4.00×10⁵ × 313) / 288

P₂ = 4.35×10⁵ Pa

Thus, the pressure at 40 °C is 4.35×10⁵ Pa

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Answer:

The below diagram shows pure spectrum with white light

Explanation:

Answer:

B

Explanation:

Let T be the orbit period and a be the radius of orbit.

For T^2= k× a^3 (k is a constant)

there seems to be an indirect relationship between two variables.

Answer:

Those cruise rpm's are normal.

Explanation:

Answer:

3.35 seconds

Explanation:

Use one of the equations of accelerated motion:

Δd = v1Δt+1/2aΔt^2

and rearrange for Δt which is time

Δt = √(2Δd)/a

now we can substitute in the values

a= 9.8 (acceleration due to gravity) and Δd= 55 as that is the height of the building

Δt = √(2*55)/9.8

Δt = 3.3503s

Answer: 9.42

Explanation: yes

The new distance of the 3.78 nC particle when the electrostatic force is doubled is 0.049 m.

The magnitude of the electrostatic force experienced by the 3.78 n C particle when it is 0.069 m from the 2.15 nC particle is calculated as follows;

F = kq₁q₂ / r²

where;

F = ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 0.069² )

F = 1.536  x 10⁻⁵ N

When this electrostatic force is doubled, the new distance of 3.78 nC particle from the 2.15 nC is calculated as;

r² = kq₁q₂ / 2F

r = √ ( kq₁q₂ / 2F )

r = √ [ ( 9 x 10⁹ x 2.15 x 10⁻⁹ x 3.78 x 10⁻⁹ ) / ( 2 x 1.536  x 10⁻⁵ ) ]

r = 0.049 m

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Answer:

V=?

S=400m

t=80s

V=S/t

V=400/80

V=5m/sec

The average velocity of the runner for the given displacement and time of motion  is 5 m/s.

The given parameters:

The average velocity of the runner is determined by dividing the total displacement by the time of motion as shown below;

\(v= \frac{Displacement }{time} \\\\v = \frac{400}{80 } \\\\v = 5 \ m/s\)

Thus, the average velocity of the runner for the given displacement and time of motion  is 5 m/s.

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The tension in the string holding the tassel and the vertical will the tension in the string

Generally, the equation for Tension is  mathematically given as

\(TCos\theta = mg\)

Therefore

\(TCos6.58^{o} = 19.8*10^{-3}*9.8\)

T = 0.1953 N

b).

Where

\(T* sin \theta = ma\)

\(0.1953*Sin6.58 \textdegree = 19.8*10^{-3}*a\)

a = 1.13 m/s^2

In conclusion

T* sinФ = ma

2msinФ = ma

2sinФ = a

\(sin\theta = \frac{a}{2}\)

\(\theta = sin^{-1}\frac{a}{2} \\\\\theta= sin^{-1}\frac{1.13}{2}\)

Ф = 34.4 °

In conclusion, The tension in the string holding the tassel and the vertical will the tension in the string

T = 0.1953 N

Ф = 34.4 °

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K1Answer:

s= 6.5cm

Explanation:

Point 1: just right before the block leaves the spring

Point 2: the block has v2=0 (stops moving)

Apply Kinetic-Work Theorem:

K1 + U1 + Wother = K2 + U2

K1=0

U1= 1/2×k×x² (k= 1.81e+3 N/m and x= -0.172 m)

Wother = F×s= 1.79×s

K2=0

U2=0

=> s= 6.5cm

This is my attempt to solve. Let me know if this isn't right

Answer:

A

Explanation:

The final velocity of the truck can be calculated using the law of conservation of momentum. The law states that the total momentum of a closed system (the car and truck) remains constant unless an external force acts on the system.

Let's call the final velocity of the system (car + truck) after the collision vf.

The initial momentum of the car before the collision is equal to m1 * v1 = 1500 kg * 20 m/s = 30000 kg m/s, where m1 is the mass of the car and v1 is its initial velocity.

The initial momentum of the truck before the collision is equal to m2 * v2 = 2500 kg * -30 m/s = -75000 kg m/s, where m2 is the mass of the truck and v2 is its initial velocity.

The total initial momentum of the system before the collision is equal to the sum of the initial momenta of the car and truck:

p_initial = m1 * v1 + m2 * v2 = 30000 kg m/s + (-75000 kg m/s) = -45000 kg m/s.

After the collision, the final momentum of the system is equal to the sum of the final momenta of the car and truck:

p_final = m1 * vf + m2 * vf = (1500 kg + 2500 kg) * vf = 4000 kg * vf.

Since the total momentum of the system is conserved, we can set the initial and final momenta equal to each other:

-45000 kg m/s = 4000 kg * vf

Finally, we can solve for the final velocity of the system (truck):

vf = -45000 kg m/s / 4000 kg = -11.25 m/s

Since the truck was moving west before the collision, the final velocity is 11.25 m/s west, so the answer is A. 11.25 m/s west.

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Explanation:

Of the options listed, the only effect that can be caused by exposure to infrared light is overheating (option a).

Infrared light is a form of electromagnetic radiation that is invisible to the human eye but can be detected as heat. When exposed to high levels of infrared light, such as in close proximity to a powerful infrared source, it can lead to overheating of the body or objects. Skin cancer (option b) is not directly caused by infrared light. It is primarily associated with overexposure to ultraviolet (UV) radiation from the sun or artificial sources like tanning beds. UV radiation falls in the higher energy range of the electromagnetic spectrum, while infrared radiation has lower energy. Radiation sickness (option c) is caused by exposure to high-energy ionizing radiation, such as gamma rays or X-rays. Infrared light does not possess enough energy to cause ionization and is therefore not capable of inducing radiation sickness. Memory loss (option d) is not a known effect of exposure to infrared light. Memory loss can be attributed to various factors, such as neurological conditions, head injuries, or aging, but not specifically to infrared light exposure. In summary, while exposure to high levels of infrared light can lead to overheating, it does not cause skin cancer, radiation sickness, or memory loss.

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Answer:

Explanation:

26 - 18 + 12 = 20 m south