2-Methyl-2-butanol reacts with hydrogen bromide via a(n) ___________.Question 8 options:
a) SN1 mechanism
b) SN2 mechanism
c) E1 mechanism
d) E2 mechanism
e) None of these.

The frequency of an x-ray wave with an energy of 2×10^(-17) J in hertz is 3.01 × 10^(16) hz.

We can find the value of frequency of an x ray wave by using the relation between energy and frequency.

As we know that,

Energy is directly proportional to the frequency of the wave.

Mathematically,

E = h. f

Where,

E is the energy in joule

f is the frequency of the wave in hertz

h is the planck's constant

Given,

E = 2 × 10^(-17)J

h = 6.63 × 10^(-34) kg.m2/s

By substituting all the values, we get

2 × 10^(-17)J = 6.63 × 10^(-34) kg.m2/s × f

f = 2 × 10^(-17)J / 6.63 × 10^(-34) kg.m2/s

f = 3.01 × 10^(16) hz.

Thus, we concluded that the frequency of an x-ray wave with an energy of 2×10^(-17) J in hertz is 3.01 × 10^(16) hz.

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Answer:

Fabric is made of cotton.

Explanation:

Hope that helps :)

Answer:

Hey mate your answer is

cotton

hope it helps you

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Answer:

A box

Explanation:

In quantum mechanics, the atom is metaphorically described as a box. In fact, the Schrödinger wave equation is based on the three dimensional box metaphor of the atom.

Thus, a box provides a convenient treatment of the atom as it represents the fundamental components of the problem of atomic structure, hence the answer.

C. A box

Thus, the correct option is C.

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Answer:

if you touch a hot stove, the nerves in your skin shoot a message of pain to your brain. The brain then sends a message back telling the muscles in your hand to pull away.

Explanation:

Answer:

If your students do an exercise and choose the option "send my answers to the teacher", you can check their answers in your mail box. If the students log in with their username and password and do the exercises in their workbooks, you can check their work in your notifications.

Explanation:

may it helpful for you

The value of "n" in the hydrate formula CuSO4 * nH2O is 5.

To determine the value of "n," we need to calculate the molar ratio between the released water and the hydrate copper(II) sulfate.

First, we need to convert the mass of water released to moles. The molar mass of water (H2O) is approximately 18.015 g/mol. Therefore, 5.051 g of water is equal to 5.051 g / 18.015 g/mol ≈ 0.2804 mol.

Next, we calculate the molar ratio between water and copper(II) sulfate. The molar mass of copper(II) sulfate (CuSO4) is approximately 159.609 g/mol. From the balanced chemical equation, we know that one mole of copper(II) sulfate is associated with "n" moles of water.

Assuming that the molar ratio is 1:1 between CuSO4 and H2O, we can set up the following equation:

0.2804 mol H2O = 14.00 g CuSO4 * (1 mol H2O / (159.609 g CuSO4 * n))

By rearranging the equation, we can solve for "n":

n = 14.00 g CuSO4 / (159.609 g CuSO4/mol) = 0.0877 mol

Since "n" represents the number of water molecules, it must be a whole number. Therefore, the closest whole number to 0.0877 is 5.

Therefore, the value of "n" in the hydrate formula CuSO4 * nH2O is 5.

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1. The molarity of the solution is 0.674 M.

2. 47.88 g of CuSO₄ in a small volume of water to make a concentrated solution.

3. 217 mL of 6.00M H₂SO₄ using a graduated cylinder or pipette, and transfer it to a 500 mL volumetric flask.

1. The molar mass of KNO₃ is:

K = 39.10 g/mol

N = 14.01 g/mol

O = 16.00 g/mol (x3)

Molar mass of KNO₃ = 101.10 g/mol

To find the number of moles of KNO₃:

mass = 341 g

moles = mass/molar mass = 341/101.10 = 3.37 mol

The volume of the solution is given as 5.0 L, so the molarity of the solution is:

Molarity = moles of solute/volume of solution

Molarity = 3.37 mol/5.0 L = 0.674 M.

2. To prepare 250 mL of 1.2M CuSO₄ solution:

1.2 mol/L x 0.250 L = 0.30 mol CuSO₄

Then, calculate the mass of CuSO₄ needed using its molar mass:

0.30 mol x 159.61 g/mol = 47.88 g CuSO₄

3. To prepare 500 mL of 2.6M H₂SO₄ solution:

2.6 mol/L x 0.500 L = 1.3 mol H₂SO₄

Then, calculate the volume of 6.00M H₂SO₄ needed to contain 1.3 mol of H₂SO₄:

1.3 mol / 6.00 mol/L = 0.217 L = 217 mL

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The question you have asked is related to an experiment on pressure and volume of propane for each volume of water added to the flask.

1. Volume of Water Added (ml) - The volume of water added to the flask should be measured in milliliters.

2. Volume of Gas (mL) - The volume of gas should be measured in milliliters.

3. Pressure (atm) - The pressure should be measured in atmospheres.

4. Once the water and gas volumes have been measured, record them along with the pressure in the table provided.

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Answer:

469N

Explanation:

adding all mass i hope you got

Approximately 6.02 x 1025 mole of sand particles would be present in the truck.

A substance's mole is equivalent to 6.022 x 1023 of that substance. (such as atoms, molecules, or ions). The number 6.022 1023 is referred to as "Avogadro's number" or "Avogadro's constant." To translate between particle mass and number, use the mole idea.

Yes, if we know how many moles of sand are in the truck, we can calculate how many sand particles are there.

Avogadro's number, which is the quantity of particles (atoms, molecules, or ions) in one mole of a substance, can be used to calculate the number of particles in a substance. The equivalent of 6.02 x 1023 particles/mol is Avogadro's number.

Number of particles = Avogadro's number x the number of moles

The quantity of sand particles can be determined as follows if the truck contains 100 moles of sand:

100 moles times 6.02 x 1023 particles/mol equals the number of particles.

6.02 x 1025 particles make up the total.

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Answer:

New volume V2 = 96 ml

Explanation:

Given:

Old volume V1 = 100 ml

Old pressure P1 = 1.92 atm

New pressure P2 = 2 atm

Find:

New volume V2

Computation:

Using Boyle's Law

P1V1 = P2V2

(1.92)(100) = (2)(V2)

V2 = 96

New volume V2 = 96 ml

Outgoing shortwave radiation depends on factors such as the angle of the Sun's rays, albedo, cloud cover, and atmospheric gases. These factors collectively determine the amount of solar radiation that is reflected, absorbed, and re-emitted by the Earth's surface, influencing the outgoing shortwave radiation.

Outgoing shortwave radiation depends on several factors. Firstly, it is influenced by the solar radiation received by the Earth's surface. The amount of solar radiation reaching the Earth is determined by the angle of the Sun's rays, which changes throughout the day and across different seasons. This means that outgoing shortwave radiation will vary depending on the time of day and the time of year.

Another important factor is the albedo, which refers to the reflectivity of different surfaces on Earth. Surfaces with high albedo, such as ice and snow, reflect more solar radiation back into space, resulting in lower outgoing shortwave radiation. Conversely, surfaces with low albedo, such as dark soil and vegetation, absorb more solar radiation, leading to higher outgoing shortwave radiation.

The presence of clouds also plays a role in outgoing shortwave radiation. Clouds can either reflect incoming solar radiation back into space or absorb and re-emit it as longwave radiation. The type and thickness of clouds, as well as their altitude, can affect the amount of outgoing shortwave radiation.

Finally, atmospheric gases such as water vapor, carbon dioxide, and ozone can also influence outgoing shortwave radiation. These gases absorb and re-emit some of the incoming solar radiation, impacting the amount of radiation that escapes back into space.

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The molar solubility of the salt with the generic formula AB2, given a solubility product constant (Ksp) of \(2.56 \times 10^2\), is 4 M. Here option B is the correct answer.

To determine the molar solubility of a salt with the generic formula AB2, given the value of its solubility product constant (Ksp = \(2.56 \times 10^2\)), we need to set up an equilibrium expression and solve for the concentration of the salt.

The generic formula AB2 indicates that one mole of the salt dissolves to form one mole of \(A^2+\) ions and two moles of \(B^-\) ions in the solution. Let's assume that the molar solubility of AB2 is x M.

The solubility product constant (Ksp) expression for the salt AB2 can be written as:

\(K_{sp} = [\mathrm{A}^{2+}][\mathrm{B}^{-}]^{2}\)

Substituting the concentrations in terms of x, we get:

\(K_{sp} = (x)(2x)^{2}\)

\(K_{sp} = 4x^{3}\)

Now, we can solve for x:

\(4x^3 = 2.56 \times 10^2\)

\(x^3 = 2.56 \times 10^2 / 4\)

\(x^3 = 64 \times 10^1\)

\(x^3 = 64 \times 10\)

\(x = \left(64 \times 10\right)^{\frac{1}{3}}\)

x = 4

Therefore, the molar solubility of the salt AB2 is 4 M, which corresponds to option b) in the given choices.

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The saturated vapor pressure of methanol in the vessel is 125.9 mmHg (rounded off to 3 significant figures). The volume percent concentration of methanol in the vapor is 73.2% (rounded off to 3 significant figures).

a. Saturated vapor pressure of methanol in the vessel in mmHg: The vapor pressure of methanol (MeOH) in the vessel can be determined using Dalton's law of partial pressures. MetOH psat = MetOH Pabs

Here, MetOH Pabs is the pressure exerted by the vapor of methanol in the vessel. It is equal to the total pressure in the vessel minus the partial pressure of the inert gas (nitrogen). Pabs = 2 inch of water gauge = 2 x 25.4 mm of water gauge / 1 inch of water gauge = 50.8 mm of water gauge

Total pressure in mmHg = Pabs x 760 mmHg / 406.8 inch of water gauge = 94.8 mmHg

Partial pressure of nitrogen = 2 inch of water gauge = 50.8 mm of water gauge

Partial pressure of methanol = MetOH Pabs MetOH psat = 126 mmHg (at 25°C)

Therefore, the saturated vapor pressure of methanol in the vessel is 125.9 mmHg (rounded off to 3 significant figures).

b. Volume percent concentration of methanol in the vapor: The volume percent concentration of methanol in the vapor can be determined using the ideal gas law and the Dalton's law of partial pressures. V = nRT / PV = volume of the vapor (L)n = number of moles of methanol gas R = gas constant T = temperature (K)P = pressure (atm)

Let's assume that the total volume of the vapor in the vessel is 1 L and the temperature is 25°C (298 K).

The number of moles of nitrogen gas (N2) in the vapor can be determined using the Dalton's law of partial pressures. N2 Pabs = Pabs - MetOH PabsN2 Pabs = 50.8 mm of water gaugeN2 Pabs = 50.8 mm of water gauge x 1 atm / 760 mmHg = 0.067 atmN2 V = nRT / PN2N2 V = (0.067 atm x 1 L) / (0.082 L atm/K mol x 298 K)N2 V = 0.0022 mol

The number of moles of methanol gas (MeOH) in the vapor can be determined using the ideal gas law. MetOH Pabs = MetOH psatMetOH Pabs = 125.9 mm Hg MetOH Pabs = 125.9 mmHg x 1 atm / 760 mmHg = 0.165 atmMetOH V = nRT / PMetOH V = (0.165 atm x 1 L) / (0.082 L atm/K mol x 298 K)MetOH V = 0.006 mol

The volume percent concentration of methanol in the vapor can be determined using the following equation.

Volume percent concentration of MeOH = MetOH V / (N2 V + MetOH V) x 100%

Volume percent concentration of MeOH = 0.006 mol / (0.0022 mol + 0.006 mol) x 100%

Therefore, the volume percent concentration of methanol in the vapor is 73.2% (rounded off to 3 significant figures).

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"lithosphere" (land), "hydrosphere" (water), "biosphere" (living things), and "atmosphere" (air)

A pure liquid has a constant boiling point because it is composed of only one type of molecule while a liquid with a constant boiling point may or may not be pure depending on the type and amount of molecules it contains.

A pure liquid refers to a liquid that contains only one type of molecule, while a liquid with a constant boiling point means that the temperature at which the liquid boils remains the same, even if the pressure changes.

Pure liquids have fixed boiling points that are equal to the liquid's vapor pressure. The vapor pressure is determined by the liquid's molecular structure and the temperature at which it is exposed. It is the pressure exerted by the gas molecules that are in equilibrium with the liquid surface.

As such, these molecules all have the same amount of energy, which means the liquid requires the same amount of energy to reach its boiling point. On the other hand, a liquid with a constant boiling point is not necessarily pure because it may be composed of a mixture of molecules with different boiling points. The molecules with the lowest boiling point will start to evaporate first, leading to a decrease in the overall boiling point of the mixture. The decrease in boiling point will be slower if the molecules in the mixture have a similar boiling point.

In conclusion, a pure liquid has a constant boiling point because all of its molecules have the same amount of energy, while a liquid with a constant boiling point may or may not be pure depending on the type and amount of molecules it contains.

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Answer:

6NO2+3H2O-------->3HNO2+3HNO3

Answer:

Van de Waal forces are intermolecular forces (London Dispersion forces, Dipole-Dipole forces, and Hydrogen Bonds). It was discovered by a Dutch scientist called Johannes Diderik van der Waals. Intermolecular forces are the attraction and strength of bonds between molecules, with London Dispersion Forces being the weakest and Hydrogen Bonds being the strongest.

Explanation:

The correct answer is:

A) 1 > 3 > 4 > 2

(Aromatic 1 is the most reactive towards electrophilic substitution, while aromatic 2 is the least reactive.)

The relative reactivity of aromatic compounds towards electrophilic substitution is determined by their ability to stabilize the positive charge that is formed during the reaction. This stability is influenced by several factors, including the number and position of electron-donating or electron-withdrawing substituents on the ring, as well as the overall aromaticity of the ring.

Aromatic 1 has an electron-donating -NH2 group, which increases the electron density on the ring and makes it more reactive towards electrophiles. Aromatic 3 has an electron-withdrawing -NO2 group, which decreases the electron density on the ring and makes it less reactive towards electrophiles than Aromatic 1, but still more reactive than Aromatics 2 and 4. Aromatic 4 has an electron-withdrawing -COOH group, which also decreases the electron density on the ring and makes it less reactive towards electrophiles than Aromatics 1 and 3. Aromatic 2 has no substituents and is the least reactive of the four.

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Lowering the flame can result in the tip overheating.

An overheating plasma system will wear out torch parts quickly and eventually may burn out the torch and leads.

What is an oxy-acetylene torch set?

A gas torch that burns a mixture of acetylene and oxygen to produce a high-temperature flame (3,000°C or 5,400°F) that can weld or cut metal.

Can an oxy-acetylene torch explode?

Thus, lowering the flame's size may result in the tip overheating.

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Answer:

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

The amount of heat absorbed or produced by the combustion of 39.8 g of CH₄ is 2214 kJ.

The reaction of combustion of methane(CH₄) is as follows:

CH₄ + 2O₂ ⇒ CO₂ + 2H₂O

The ΔH for combustion of methane is given to be -890.1 kJ/mol.

This is the value of heat released when the combustion of 1 mole of CH₄ occurs.

The molar mass of methane is 16 g.

As the heat released by 16g of CH₄ is 890 kJ.

The heat released by 39.8 g of CH₄ is 890/16 x 39.8 = 2214 kJ.

Thus, the amount of heat absorbed or produced by the combustion of 39.8 g of CH₄ is 2214 kJ.

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a. False. In the same OSM (Operating System Memory), it is not necessary for all pages to have the same size. Different pages can have varying sizes depending on the memory allocation requirements of the system.

b. False. In the same OSM, all segments do not need to have the same size.

Segments can have different sizes based on the specific needs of the programs or processes running in the system.

Segmentation allows for flexible memory allocation by dividing the memory into logical segments.

c. True. Internal fragmentation occurs when memory is divided into smaller areas to accommodate smaller data blocks, but the remaining memory within each block is too small to be utilized for another block.

As a result, these small unused portions of memory remain empty, leading to inefficient memory utilization.

This is a disadvantage of the paging architecture employed in a computer's memory management system. It can result in wasted memory space and lower overall system performance.

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The child needs 1,569.25 mg of amoxicillin per day, with 784.63 mg of amoxicillin per dose.

Streptococcus infections are commonly treated with amoxicillin, a broad-spectrum antibiotic.

Amoxicillin is effective against many different types of bacteria, including Streptococcus bacteria.

When a child has a streptococcus infection, amoxicillin may be prescribed at a dosage of 45 mg per kg of body weight per day given b.i.d.

In this case, a 76.8 lb child would be given 1,385.28 mg of amoxicillin per day, divided into two equal doses, for a total of 692.64 mg per dose.

Amoxicillin is a penicillin antibiotic used to treat infections caused by bacteria.

It is effective against many different types of bacteria, including streptococcus bacteria.

The required dosage of amoxicillin for a child is determined by their body weight and the extent of the infection they are experiencing.

In this case, the child weighs 76.8 lbs, which is equivalent to 34.85 kg.

The dosage of amoxicillin is 45 mg per kg of body weight per day, so the child needs 1,569.25 mg of amoxicillin per day.

This dosage is divided into two equal doses, so the child needs 784.63 mg of amoxicillin per dose.

Since amoxicillin is often taken orally, this dosage can be provided in the form of a tablet, suspension, or chewable tablet.

The duration of amoxicillin treatment will depend on the severity of the infection and the response of the child to the treatment. Generally, amoxicillin treatment lasts for 10 to 14 days.

The child should continue taking amoxicillin for the full prescribed course, even if they start feeling better before the treatment is completed.

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When NH3 reacts with BF3, the nitrogen lone pair donates a pair of electrons to the boron atom. This forms a new bond between the nitrogen and boron atoms, and the boron atom gains a full octet of electrons:

 F                 H         H

/ \                /         /

B   F  +      N       /

\ /                \   /

 F                   H

NH3 acts as the Lewis base because it donates a pair of electrons to BF3, which acts as the Lewis acid. The electron pair being donated is the lone pair on the nitrogen atom in NH3.

The reaction between NH3 and BF3 can be modeled using electron dot structures.

First, let's draw the Lewis structure for each molecule:

NH3:

H         H

\        /

 N

/        \

H         H

BF3:

 F

/ \

B   F

\ /

 F

In NH3, nitrogen has five valence electrons and each hydrogen has one valence electron. The electrons are shared to form three covalent bonds between the nitrogen and hydrogen atoms, and there is one lone pair of electrons on the nitrogen atom.

In BF3, boron has three valence electrons, and each fluorine has seven valence electrons. The electrons are shared to form three covalent bonds between the boron and fluorine atoms.

In this reaction, NH3 acts as the Lewis base because it donates a pair of electrons to BF3, which acts as the Lewis acid. The electron pair being donated is the lone pair on the nitrogen atom in NH3.

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Answer:

Explanation:

h

Answer:

Explanation

7 tonnes-8.5 ammonia

1 ton will be 8.5/7=1.21

we now know what 1 ton of nitrogen is equal to

so now,34/28 that is equal to 1.21

1.21=1.21

So the answer would be C. 28 tonnes

Thanks!

Answered by: FieryAnswererGT

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Answer:

a)to make sure it is thoroughly stirred

b)to get the accurate answer

c)to avoid parallax error