Answers
The temperature of the ideal gas is 264.5°C while the temperature of the van der Waals gas is 260.1°C
What is Adiabatic ProcessAn adiabatic process is a thermodynamic process in which no heat is transferred to or from the working fluid. This process occurs when the change in the internal energy of the system is equal to the work done. Examples of adiabatic processes include the compression and expansion of gases, the compression of liquids, and the cooling and heating of a gas.
(a) Final temperature (T2) of the ideal gas =
T2 = T1(P2/P1)^((γ-1)/γ)
T2 = 200(3/1)^((1.4-1)/1.4)
T2 = 264.5°C
(b) Final temperature (T2) of the van der Waals gas =
T2 = T1(P2/P1)^((γ-1)/γ) - (a/V2)(P2 + b)
Where, a = 3.567 kJ/molK and b = 0.0427 L/mol
T2 = 200(3/1)^((1.4-1)/1.4) - (3.567/1)(3 + 0.0427)
T2 = 260.1°C
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Related Questions
A laser positioned on a ship is used to communicate with a small two man research submarine resting on the bottom of a lake. The laser is positioned 12 m above the surface of the water, and it strikes the water 20 m from the side of the ship. The water is 76 m deep and has an index of refraction of 1.33. How far is the submarine from the side of the ship
Answers
Answer:
84.1 m
Explanation:
Given :
The distance from the ship to submarine :
20 + y
Using Pythagoras :
Tan θ = opposite / Adjacent
Tan θ = 20 / 12
12 tan θ = 20
θ = tan^-1(20/12)
20
θ = 59.036°
The angle phi;
n1sinθ1 = n2sin θ
Sin 59.036 = 1.33 * sin phi
Sin phi = sinsin(59.04) ÷1.33
0.8574907 = 1.33 * sin phi
Sin phi = 0.8574907 / 1.33
Sin phi = 0.6447298
phi = sin(0.6447298
Phi = 40.15°
From Pythagoras :
y = 76tan40.15°
y = 76 * 0.8435707
y = 64.11
20 + y
20 + 64.11 = 84.11
If you drive 2 hours at 50mph and then drive 4 hours at 65mph, how far did you drive in all?
Answers
Answer:
i think its 400 miles driven
Explanation:
attempted to do it...
A scientist heated a tank containing 50 g of water. The specific heat of water is 4.18 J/gºC. The temperature of the water increased from 25ºC to 37ºC. How much heat energy did the water absorb?
1: 2,508 joules
2: -2,508 joules
3: 5,225 joules
4: 7,733 joules
Answers
Answer: a) 2,508
Explanation:
A radar antenna is rotating and makes one revolution every 24 s, as measured on earth. However, instruments on a spaceship moving with respect to the earth at a speed v measure that the antenna makes one revolution every 44 s. What is the ratio v/c of the speed v to the speed c of light in a vacuum
Answers
Answer:
0.838
Explanation:
The ratio v/c of the speed v to the speed c of light in a vacuum is shown below:
Given that
\(\triangle t_0 = 24\ seconds\) = time interval for one revolution
\(\triangle t = 44\ seconds\) = time interval measured with speed v
based on the given information, the ratio v/c of the speed v to the speed c of light in a vacuum is
\(\triangle t = \frac{\triangle t_0}{\sqrt{1 - \frac{v^2}{c^2}}}\)
\({\sqrt{1 - \frac{v^2}{c^2}}} = \frac{\triangle t_0}{\triangle t}\)
Now squaring both the sides
\(\frac{v^2}{c^2} = 1 - \frac{(\triangle t_0)^2}{(\triangle t)^2}\)
Now remove the squaring root from both the sides and putting the values
\(\frac{v}{c} = {\sqrt{1 - \frac{(\triangle t_0)^2}{(\triangle t)^2}\)
\(= {\sqrt{1 - \frac{(24)^2}{(44)^2}\)
= 0.838
A body rolls over a horizontal, smooth surface without slipping with a translational
kinetic energy E. Show that the kinetic energy of the body is E=(1+K 2 /R 2 )
where K is the radius of gyration and R is the radius of the body. Using the above relation, find the
total kinetic energy of a circular disc.
b) A wheel of mass 1000 kg and radius 1 m is rotating at the rate of 420 r.p.m. What is the
constant torque required to stop the wheel in 14 rotations, assuming the mass to be
concentrated at the rim of the wheel?
Answers
Answer:
I am not sure sorry wish I could help
Answer:
I also wish I could help u but am sorry I don't know it
Don't worry you will find a solution
If dx denotes the change in position of an object and dt denotes the corresponding time interval, then instantaneous velocity is given by:
Answers
Answer:
\(Velocity=\frac{dx}{dt}\)
Explanation:
Remember that instantaneous velocity is just a measure to know the velocity that any object has at any point given in time, so we just need to know the distance it has travel, which would be the change in position, and the time it took that change in position to occurr, this means distance by time, so we just divide dx by dt and we have the solution for instantaneous velocity.
If a change in position as denoted by \(dx\) and \(dt\) change in time, the instantaneous velocity will be given by,
\(v = \dfrac {dx}{dt}\)
What is Velocity?It can be defined by the change in position of the object over time. This is a vector quantity. Vector quantity is a quantity that has both magnitude and direction.Instantaneous velocity:The velocity of the object at a point of time is known as instantaneous velocity. Instantaneous velocity can be calculated by the ratio of change in position to the elapsed point of time.
\(v = \dfrac {dx}{dt}\)
Where,
\(v\) - instantaneous velocity
\(dt\) - change in distance (position)
\(dt\)- change in time
Therefore, if a change in position as denoted by \(dx\) and \(dt\)change in time, the instantaneous velocity will be given by,
\(v = \dfrac {dx}{dt}\)
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Explain/Describe how atoms in domains determine whether a material is magnetic or not. (Please help this is due today)
Answers
Answer:
In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.
In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.
The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.
So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.
In hiking, what fitness component is required of you
Answers
(c) Two argon atoms form the molecule Ar2 as a result of a van der Waals interaction with U0= 1.68×10-21 J and R0= 3.82×10-10 m. Find the frequency of small oscillations of one Ar atom about its equilibrium position.
Answers
Answer:
Explanation:
Answer:
\(\mathbf{f_o =1.87 \times 10^{11} \ Hz}\)
Explanation:
The formula for calculating the elastic potential energy is:
\(U_o = \dfrac{1}{2}kR_o^2\)
By rearrangement and using (K) as the subject;
\(K = \dfrac{2 U_o}{R_o^2}\)
\(k = \dfrac{2\times 1.68 \times 10^{-21}}{(3.82\times 10^{-10})^2}\)
k = 2.3 × 10⁻² N/m
Now; the formula used to calculate the frequency of the small oscillation is:
\(f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{k}{m}}\)
where;
m = mass of each atom
assuming
m = 1.66 × 10⁻²⁶ kg
Then:
\(f_o = \dfrac{1}{2 \pi}\sqrt{\dfrac{2.3 \times 10^{-2} N/m}{1.66 \times 10^{-26} \ kg}}\)
\(\mathbf{f_o =1.87 \times 10^{11} \ Hz}\)
A ball is dropped from a height of 78.4 m above the ground. How long does it take to hit the ground?
Answers
Answer: it would take 4 seconds
Explanation:
please help i’ll mark you
Answers
Answer:
What should I do. reply quickly for a quick answer
Answer: put a line across the paper
Explanation:
ntroduction The flow of geophysical fluids (i.e., the Earth’s ocean and atmosphere, and the atmospheres of gas giants planets such as Jupiter and Saturn) is complicated, involving a vast number of processes and interactions among them on scales ranging from centimeters to the planet’s size, and timescales going from seconds to millennia. Two effects mainly constrain the flow of geophysical fluids: the planet’s rotation and stratification. In this lab we will deal with the first of the aforementioned effects. We will learn how the unusual properties of rotating fluids manifest themselves in, and profoundly influence, the circulation of the Earth’s ocean and planetary atmospheres. The planet’s rotation makes these fluids more similar than one might expect. On what scales might the atmosphere, ocean, or our laboratory experiment, “feel” the effect of rotation? Suppose that U is a typical horizontal current speed, and the typical distance over which the currents varies is L. Then the timescale of the motion (Tmotion) is L/U. Compare this with the period of rotation Trot, define a nondimensional number (the Rossby number):
Ro := Trot/Tmotion = Trot × U/L. If Ro is much greater than one, then the timescale of motion is short relative to a rotation period, and rotation will not significantly influence the motion. If Ro is much less than one, then the motion will be aware of rotation. Let us estimate Ro for large-scale flow in the atmosphere and ocean.
• Amosphere: L ∼ 5000 Km, U ∼ 10 m/s, and T = 1 day, giving Ro = 0.2, which suggest the rotation will be important.
• Ocean: L ∼ 1000 Km, U ∼ 0.1 m/s, giving Ro = 0.01, and rotation will be a controlling factor. Pre Lab 1.
It is clear from the Ro estimations above, that rotation is very important in shaping the patterns of air and ocean currents on sufficiently large scales. How can we study this effect on an small rotating tank (L ∼ 30cm)? If we generate a current in the tank of U ∼ 0.1 cm/s, what would be an appropriate rotation period?
Answers
Answer:
Explanation:
To study the effect of rotation on a small rotating tank, we want the Rossby number to be much less than one, so that rotation will be a controlling factor in shaping the patterns of flow.
Based on the given information, the length scale of the tank is L = 30 cm and the current speed is U = 0.1 cm/s. To calculate the timescale of the motion, Tmotion, we can use the formula Tmotion = L/U, which gives us:
Tmotion = 30 cm / 0.1 cm/s = 300 s
Next, we need to estimate an appropriate rotation period, Trot, so that the Rossby number Ro = Trot / Tmotion will be much less than one. We can use the formula Ro = Trot * U / L, rearrange it to solve for Trot:
Trot = Ro * L / U
If we take Ro to be 0.1 (for example), then we have:
Trot = 0.1 * 30 cm / 0.1 cm/s = 30 s
So, with a rotation period of 30 s and a current speed of 0.1 cm/s, we should expect the rotation to have a significant influence on the patterns of flow in the small rotating tank.
A busboy uses a 15N force to push a 25kg cart at constant speed. If the waiter is pushing down at a 37 degree angle, find the normal force and friction
Answers
ANSWER
\(\begin{gathered} N=245N \\ Fr\approx11.98N \end{gathered}\)EXPLANATION
First, let us make a sketch of the problem:
The normal force has the same magnitude as the weight of the cart.
\(N=mg\)where m = mass; g = acceleration due to gravity
Hence, the normal force is:
\(\begin{gathered} N=25\cdot9.8 \\ N=245N \end{gathered}\)Applying Newton's second law of motion in the horizontal direction, the sum of forces acting on the cart is:
\(\sum F_x=ma_x=-Fr+Fp\cos 37_{}\)where Fp = force of the push
Fr = friction force
Since the waiter pushes the cart at a constant speed, it means that the acceleration of the cart (ax) is 0.
This implies that:
\(0=-Fr+15\cos 37\)Solve for Fr:
\(\begin{gathered} \Rightarrow Fr=15\cos 37 \\ \Rightarrow Fr\approx11.98N \end{gathered}\)That is the friction force.
A conducting bar with mass m and length L slides over horizontal rails that are connected to a voltage source. The voltage source maintains a constant current I in the rails and bar, and a constant, uniform, vertical magnetic field B fills the region between the rails . Find the magnitude and direction of the net force on the conducting bar. Ignore friction, air resistance and electrical resistance :
A. v2m / ILB to yhe right
B. 3v2m /2 ILB to yhe left
C. 5v2m/ 2ILB to the right
D. v2m / 2ILB to the left
Answers
Answer:
F = ILB
Explanation:
To find the net force on the conducting bar you take into account the following expression:
\(\vec{F}=I( \vec{L}X \vec{B})\)
I: current in the conducting bar
L: length of the bar
B: magnitude of the magnetic field
In this case the direction of the magnetic field and the motion of the bar are perpendicular between them. The direction of the bar is + i, and the magnetic field poits upward + k. The cross product of these vector give us the direction of the net force:
+i X +k = +j
The direction of the force is to the right and its magnitude is F = ILB
determine the resultant force that water exerts on the overhang sea wall along abc. the wall is 2 m wide.
Answers
The resultant force that water exerts on the overhang sea wall along abc is 179 kN.
What is force?Force is a physical quantity that describes the interaction between two objects, such as a push or a pull. It is defined as any influence that causes an object to undergo a change in motion or deformation. Force is a vector quantity, meaning that it has both magnitude (size or strength) and direction.
Component that is horizontal. Because AB is horizontal, there is no horizontal component. The horizontal component of BC's force is.
(Fbc)h =γwhˉA=(1000kg/m3)(9.81m/s2)(1.5m+21(2m))(2m(2m))=98.1(103)N.
Component that is vertical. The weight of the water contained in blocks Abefa and Bcdeb (shown shaded in Fig. a) is equal to the force on AB and the vertical component of the force on BC. Here,
Aabefa=1.5m(2.5m)=3.75m2and
2Abcdeb=(3.5m)(2m)–4π(2m)2=(7–p)m2. Then,
Fab=γwVabefa=(1000kg/m3)(9.81m/s2)[(3.75m2)(2m)] =73.575(103)N=73.6N (FBC)v=γwVbcdeb=(1000kg/m3)(9.81m/s2)[(7–π)m2(2m)] =75.702(103)N
Therefore,
Fbc=(Fbc)²h2+(Fbc)²v2=√[98.1(10³)N]²+[75.702(10³)N]²=123.91(10³)N=124KN
FR² =(Fbc)²H2+[Fab+(Fbc)v]²
==[98.1(10³)N]² + [(73.6(10³)N)²+75.702(10³)N²]
=178.6(10³)N = 179 kN.
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A man is standing away from the School
Building at a distance of
300m . He claps his hands and hears an echo calculate the time interval of him hearing his echo
Answers
The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
What do you mean by echo?An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.
The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.
To calculate the time interval, we can use the following formula:
time = distance / speed
where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.
distance = 2 x 300m = 600m
speed = 343 m/s
time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)
Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.
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What is the Main impact that tsunamis have on humans? (Science)
Answers
Answer:
Explanation:
Tsunamis can have a devastating impact on human populations. The primary impact of a tsunami is the destruction of coastal communities and infrastructure. The powerful waves can inundate low-lying areas, destroying buildings, homes, and infrastructure such as roads, bridges, and ports. The destruction caused by tsunamis can result in the loss of life, injury, displacement, and economic disruption.
Tsunamis can also have secondary impacts on human populations, such as the disruption of essential services like water and electricity, which can exacerbate the already difficult living conditions in affected areas. The destruction of crops and fisheries can also have long-term economic impacts on affected communities.
It is essential to note that the impact of a tsunami can vary greatly depending on a range of factors, such as the size of the wave, the distance from the epicenter of the earthquake that caused the tsunami, and the preparedness and resilience of the affected communities. Therefore, it is crucial to have effective early warning systems and evacuation plans in place to minimize the impact of a tsunami on human populations.
HELPPPP
A man is trying to push a box across a table. He pushes on the box with 5 N and the
table provides a frictional force of 1 N. What will be the net force on the box?
1) 4 N
2) 5 N
3) 6 N
4) Not enough information has been given
Answers
Answer:
4 Newton
Explanation:
because you minus 1 Newton from 5 newton
The net force on the box is equal to 4N. Therefore, option (1) is correct.
What is the net force?The net force can be described as the vector sum of forces acting on a particle or object. The net force can be defined as a single force showing same the effect of the original forces on the particle's motion. Net force gives the same acceleration as all those actual forces together.
The net force becomes the resultant force. It has the same effect on the rotational motion as all actual forces taken together by the object. Force is a vector quantity as it has a magnitude and a direction.
In the given problem, the applied force is in the opposite direction of the frictional force so we can find the net force by subtracting these two forces.
Given, the applied force to push the box = 5N
The frictional force on the box, = 1 N
The net force on the box = 5N + (-1N) = 4N
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A radio-controlled car powered by an electric motor accelerates from rest to 0.800 m/s in 23.0 ms. The total mass of the car is 675 g. What is the average power (in W) delivered to the car by the motor during its acceleration
Answers
Answer:
9.39Watts
Explanation:
The work done by the car is converted to kinetic energy. Hence;
Work done = Kinetic energy =1/2mv²
Time t = 23ms =23×10^-3s
Mass = 675g = 0.675kg
v = 0.8m/s
Work done = 1/2(0.675)0.8²
Work done = 0.216Joules
Average power = Work done/Time
Average power = 0.216/0.023
Average power = 9.39Watts
Hence the average power (in W) delivered to the car by the motor during its acceleration is 9.39Watts
When a ball is thrown straight up with no air Resistance, the acceleration is in what direction ?
Answers
Answer:
The ball has a velocity upwards but the acceleration is downwards. Gravity is giving the ball a downwards acceleration from the moment the ball leaves the hands.
Reginald Esuke from Cameroon ran down a mountain slope in just 62.25 min. How much work was done if the power developed during Esuke’s descent was 585.0 W?
Answers
The amount of work which was done if the power developed during Esuke’s descent was 585.0 W is equal to 2,184,975 Joules.
What is work done?The work done (W) by an object can be calculated by multiplying the force acting on it by the perpendicular distance covered by the physical object over a specific period of time. This ultimately implies that, work done (W) and energy (E) have the same unit i.e Joules (J).
Mathematically, the work done (W) by an object can be calculated by using the following formula:
Work done = power × time
Additionally, we would convert the unit of time in minutes to seconds by multiplying by 60 seconds.
Substituting the given parameters into the work done (W) formula, we have the following;
Work done = 585.0 × 62.25 × 60
Work done = 2,184,975 Joules.
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Why is drinking water good for the brain?
Answers
Answer:
water is good fort he brain becuase it increases blood circulation and provides more oxygen to the brain
Answer:
It helps regulate blood and and oxygen.
Explanation:
helps also with cleaning and purifing the blood stream
Warm air is more dense than cool air. Warm air is less dense than cool air Warm air and cool air have the same density
Answers
Answer:
You are exactly right. The molecules in hot air are moving faster than the molecules in cold air. Because of this, the molecules in hot air tend to be further apart on average, giving hot air a lower density. That means, for the same volume of air, hot air has fewer molecules and so it weighs less
(b) The graph display a load against extension plot for a metal wire of diameter 1.5 mm and original length
1m. When the load reached the value at a point A, the wire broke. From the graph deduce values of
i)force constant
ii)the youngs modulus for the metal of the wire
Answers
From Hooke's law, the force constant of the wire is 3.0 * 10^5 N/m while the Young Modulus is 6.4 * 10^7 .
What is Hookes law?According to Hooke's law, the force is directly proportional to the extension of the wire.
Given that;
F = Ke
F = 240N
e = 0.8 mm or 0.0008m
K = F/e
K = 240N/0.0008m
K = 3.0 * 10^5 N/m
Now;
Young Modulus = 240N/(3.14 * (1.5 * 10^-3)^2)/0.0008m/1.5 * 10^-3
= 6.4 * 10^7
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PLEASE HELP ME!!! LOOK AT THE SCREENSHOTS
Answers
Answer:
Question 19: 4. -2
Question 20: 1. -1
Explanation:
Protons always have a positive (+) charge.
Neutrons always are a neutral (0) charge, or no charge.
Electrons always have a negative (-) charge.
Question 19:
We have 8 protons, so a +8 charge.
We also have 10 electrons, so a -10 charge.
-10 + 8 = -2, or a -2 charge.
Question 20:
We have 1 proton, so a +1 charge.
We also have 2 electrons, so a -2 charge.
1 - 2 = -1, or a -1 charge.
PLEASE HELP
Suri, a scientist at NASA, created models of each planet. The models contain the same properties as the actual planets, but at a smaller scale. The first property being tested is the density of the planets. Suri places each planet into a container of water. Which planet will float on top of the water?
A) Mercury
B) Venus
C) Neptune
D) Saturn
Answers
Answer:
Explanation:
Let's turn to the table of planetary densities:
Saturn will float in the water ( 0.7 g/cm³ < 1.0 g/cm³)
do humans have the right to alter and colonize unique environments on another planet? explain your answer.
Answers
Answer:
We may have people making habitats on asteroids ... I know that humans will colonize the solar system and one day go beyond. Richard Gott has estimated that the human race could survive for another 7.8 million years, but it is not likely to ever colonize other planets.
To be sure there are many daunting challenges facing prospective space colonists such as protection from exposure to deadly radiation levels, the impact on the human body while living and working in cramped, low-gravity environments for extended periods of time and the psychological toll of isolation and confinement.
According to me we can't colonize other planets which is against humanity
Difference between corpuscular theory and wave theory
Answers
Answer:
Explanation:
Isaac Newton argued that the geometric nature of reflection and refraction of light could only be explained if light were made of particles, referred to as corpuscles, because waves do not tend to travel in straight lines.
You have 150 W/m^2 hitting your roof each day. You can convert 13% of it into
usable energy, and you need 3.5 kW to run your house for a day. Show the MATH,
answer and units, to determine the size solar panel you will need to succeed.
Answers
Answer:
Energy = .13 W / m^2 energy of incident energy
N = 3500 Watts / day power needed
N = 3500 Watts (3600 * 24 sec) = .0405 Watts/sec
The problem must mean that one needs 3.5 Kw-days
3.5 Kw-days = 3500 watts * 86400 sec = 3.02E8 joules
150 J/sec-m^2 * .13 = 19.5 J / sec-m^2 usable energy
In one day 19.5 J/sec-m^2 = 1.68E6 J/m^2 usable energy received
Area = 3.028E8 J / 1.68E6 J/m2 = 180 m^2
One would need 180 m^2 of solar panels
That's quite a lot of energy
A 1100 watt microwave oven uses 1.1 kW while running so 3.5 kW for 24 hours seems to be quite a lot.
Suppose that you exert 500 N horizontally on a 40kg crate on a factory floor. The friction between the floor and the crate is 200 N. What is the acceleration of the crate?
Answers
Answer:
The acceleration of the crate is 7.5 m/s²
Explanation:
Given;
force exerted on the crate, F₁ = 500 N
mass of the crate, m = 40 kg
frictional force between the floor and the crate, F₂ = 200 N
The net horizontal force is given by;
∑Fₓ = F₁ - F₂
∑Fₓ = 500 N - 200 N
∑Fₓ = 300 N
Apply Newton's second law of motion to determine the acceleration of the crate;
∑Fₓ = ma
a = ∑Fₓ / m
a = 300 N / 40 kg
a = 7.5 m/s²
Therefore, the acceleration of the crate is 7.5 m/s²