1. A sphere made of wood has a density of 0.830 g/cm³ and a radius of 8.00 cm. It falls through air of density 1.20 kg/m³ and has a drag coefficient of 0.500. What is its terminal speed (in m/s)?
2. From what height (in m) would the sphere have to be dropped to reach this speed if it fell without air resistance?

Answer:

The water temperature is independent, and the cleanliness of the dishes is dependent.

Explanation:

You can change the independent variable in an experiment, in this case it's the water temperature. The dependent variable is the outcome from the independent variable, in this case being the cleanliness of the dishes. You can't control the cleanliness, but you can control the water temperature.

Hope my explanation isn't too confusing, hope this helps.

N and N2 are not independent after Joint Probability Mass Function

Given that a box of 8 light bulbs contains 2 defective bulbs. The light bulbs are tested one at a time until the defective bulbs are found.

Let N1 be the number of tests done until the first defective bulb is found and

let N2 be the same for the second bulb.

(a) Joint Probability Mass Function of N and N2

The probability of finding the first defective bulb at the nth trial is given by:

P(N1 = n) = P(first defective bulb on nth trial)P(first n − 1 bulbs are not defective)= (2/8) × (6/7) × (5/6) × · · · × [(8 − n + 3)/ (9 − n)]On the nth trial, there are 8 − n + 1 = 9 − n bulbs left, including the defective one, hence (9 - n) bulbs in the denominator.

If the first defective bulb was found on the nth trial, there are 2 defective bulbs left out of 8 bulbs remaining. Therefore, the probability of finding the second defective bulb at the mth trial given that the first was found on the nth trial is:

P(N2 = m | N1 = n) = P(noth defective bulbs in n - 1 trials) × P(defective bulb on mth trial out of 8 - n remaining bulbs)= (6/8) × (5/7) × (4/6) × · · · × [(8 - n - 1 - m + 3)/ (9 - n - m)] × (2/ (8 - n))= (3 - n + m)/ (10 - n - m) × (2/ (8 - n))

For the second defective bulb to be found on the mth trial, there must be no defective bulbs among the first n - 1 bulbs and there are 8 - n bulbs remaining, including one defective one. Therefore, 6 bulbs in the denominator. Also, there are (8 - n - 1) bulbs remaining for the m - 1 non-defective bulbs, giving (8 - n - 1 - m + 3) in the denominator.

Therefore, there are (9 - n - m) bulbs remaining for the mth trial.(b) Are N and N2 independent?

To check if N and N2 are independent, we need to check whether P(N1 = n, N2 = m) = P(N1 = n)P(N2 = m) for all possible n and m. This can be done using the Joint Probability Mass Function of N and N2.

P(N1 = n, N2 = m) = P(N2 = m | N1 = n) × P(N1 = n)= (3 - n + m)/ (10 - n - m) × (2/ (8 - n)) × (2/8) × (6/7) × (5/6) × · · · × [(8 − n + 3)/ (9 − n)]Therefore, N and N2 are not independent.

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Answer: 1.18

Explanation: The formula I used is:

f=1/(2pi) times the square root of k/m

F is the frequency, in this problem, 10 Hz.

K is the spring constant.

M is the mass.

So plugging everything in we would have:

10=1/(2pi)•sqrt x/0.00030

The answer I got was 1.18

Answer:

For number 4: A vector pointing to the right with a magnitude of 2.0

Explanation:

Very simple- just subtract 6-2

I am not sure how to do #2- sorry!

Answer:

Benzene must be kept away from flames.

Explanation:

just took quiz

Answer:

Benzene must be kept away from flames.

Explanation:

Answer:

Within the realm of Newtonian mechanics, an internal frame of reference or internal reference frame, is one in which newton's law of motions is valid

The solution of highest Global Horizontal Irradiance is Arizona.

The state that has highest average daily values of Global Horizontal Irradiance (GHI) is Arizona.

It is important to note that GHI is a measure of the total amount of sunlight that reaches a horizontal surface, and this value is essential for solar energy applications.

GHI is affected by several factors, such as latitude, altitude, cloud cover, and atmospheric conditions. Arizona has a higher average daily value of GHI due to its location, which is closer to the equator.

This factor ensures that Arizona receives more direct sunlight throughout the year, even when compared to the other states mentioned in the question. Therefore, it is safe to say that Arizona is the state with the highest average daily values of Global Horizontal Irradiance (GHI) compared to the other states listed above the states.

Arizona is located closer to the equator, and hence, it receives more direct sunlight throughout the year. Compared to Wisconsin, Florida, and Georgia, Arizona has a higher average daily value of GHI, making it an ideal location for solar power applications. With this high value, solar panels in Arizona are more efficient and produce more electricity compared to the other states.

Therefore, it can be concluded that Arizona has the highest average daily values of Global Horizontal Irradiance (GHI) compared to other states mentioned.

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The maximum value of driving force for the block and spring system is found to be 318N.

The weight of the block is 40N and it is suspended from the spring of spring constant 200N/m. The damping constant B is zero for the oscillation and the system is undamped.

It is subjected to frequency of 10Hz that result in the forced amplitude of 2 cm.

We know,

A = (F/m)/(√w²-w₀²)²

Here,

w = 2πf

f is the frequency,

w = 2 x 3.14 x 10

w = 20π sec ⁻¹

And,

w₀ = k/m

w₀ = 200/(40/9.8)

w₀ = 49 sec⁻²

Putting values in formula,

F = mA(√w²-w₀²)²

F = 40/9.8 x 0.02 x (√(49)²-(20π)²)²

F = 318N.

The maximum driving force is 318N.

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Answer:

The direction of the magnetic force on a moving charge is perpendicular to the plane formed by v and B and follows right hand rule–1 (RHR-1)

Explanation:

hope this helps

Answer:

The direction is into the page. Your thumb is along the velocity vector and your fingers travel along the magnetic-field vector to leave your palm moving into the page

Explanation:

Plato

Answer:

V1/T1 = V2/T2 => V2 = V1/T1 * T2 Using the information given, V1 = 1.9 m3 T1 = 32.0 C T2 = 18.0 C we can get: V2 = 1.9/32 * 18 = 1.06875, the volume that would be taken up by the existing ethanol after the temperature change is 1.07. If the capacity is 1.9 m3, then the amount of additional that can be added is 1.90-1.07 which is 0.83 m3.

Explanation:

Answer:

\(0.027m^{3}\)

Explanation:

First, we write down what we know:

\(\Delta{V}_{ethanol} = Change\; in\; volume\; of\; the\; ethanol.\\\beta_{ethanol} = 75\times{10^{-5}}\;{^\circ{C}^{-1}}\\\beta_{steel} = 36\times{10^{-5}}\;{^\circ{C}^{-1}}\\V_{0} = 2.90m^3\\\Delta{T} = T_1-T_0 = 20 - 33 = -13{^\circ{C}}\)

In order to solve this problem, we have to calculate the final volumes of the ethanol and steel respectively and then find their difference, which will give us the volume of ethanol that we can add once the container in cooled.

\(\Delta{V}_{ethanol}= V_{ethanol}-V_0\\Rearrange\; to\; find\; V_{ethanol}\\ V_{ethanol} = \Delta{V}_{ethanol} +V_0\)

\(\Delta{V}_{steel}= V_{steel}-V_0\\Rearrange\; to\; find\; V_{steel}\\ V_{steel} = \Delta{V}_{steel} +V_0\)

Which gives:

\(V_{steel}-V_{ethanol}=volume\;we\;can\;add=V_{free}\\V_{free} = \beta_{steel}V_0\Delta{T}+V_0-(\beta_{ethanol}V_0\Delta{T}+V_0)\\V_{free} = V_0\Delta{T}( \beta_{steel}-\beta_{ethanol})\\V_{free} = (2.9m^3)( -13{^\circ{C}})(36\times{10^{-5}}\;{^\circ{C}^{-1}}-75\times{10^{-5}}\;{^\circ{C}^{-1}})\\V_{free} = 0.027m^3 = 27l\)

Answer:

D. circumpolar

Explanation:

A circumpolar star is a star, as viewed from a given latitude on Earth, that never sets below the horizon due to its apparent proximity to one of the celestial poles.

-Wikipedia

Answer:

Acceleration, \(a=4\ m/s^2\)

Explanation:

Given that,

Initial velocity, u = 20 m/s

Final velocity, v = 60 m/s

Time, t = 10 s

We need to find the acceleration of the car. It is equal to the change in velocity divided by time.

\(a=\dfrac{v-u}{t}\\\\a=\dfrac{60-20}{10}\\\\a=\dfrac{40}{10}\\\\a=4\ m/s^2\)

So, the acceleration of the car is \(4\ m/s^2\).

When the two magnets are made to move, the energy of the system in the system tends to change potential energy into the kinetic energy

Potential energy is the energy stored in the body while is at rest which would turn into kinetic energy when the object will initiate motion. This conversion of potential energy to kinetic energy is understood by the Work-Energy theorem. The kinetic energy is formulated as,

K.E. = 1/2 mv²

where K.E = Kinetic energy

m = mass of an object

v = velocity of the object

The work-energy theorem is stated as the products of all the forces acting on the system are equal to the difference in kinetic energies.

∑W = ΔK.E

where W = Work done on the system

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Answer:

No

Explanation:

walking requires friction because if friction did not exist we would slide around without stopping

The current of the magnetic field must be flowing counterclockwise around the loop.

To determine the direction of the current, we can use the right-hand rule for the magnetic field around a current-carrying wire.

If you place your right hand around the wire with your thumb pointing in the direction of the current, the direction in which your fingers curl around the wire will be the direction of the magnetic field.

Since the magnetic field is coming out of the page toward you (as indicated by the circle-dot in the center of the loop), we can conclude that the current must be flowing counterclockwise around the loop.

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A white dwarf remains stable in size due to electron degeneracy pressure, which prevents its atoms from collapsing further despite the absence of nuclear fusion reactions.

A white dwarf is a remnant of a low to medium mass star that has exhausted its nuclear fuel and undergone gravitational collapse. As the star's core collapses, its electrons become tightly packed together, leading to electron degeneracy pressure that opposes further compression. This results in a stable size for the white dwarf, where the inward force of gravity is balanced by the outward force of electron degeneracy pressure. Since there are no nuclear fusion reactions to generate heat, the white dwarf eventually cools and dims over time, becoming a cold black dwarf.

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The magnitude of the normal force on the block at point B is 4mg

The correct answer is option a) 4mg

At point A, the block's acceleration is 3mg (where m is the mass and g is the gravitational acceleration), we can find the centripetal acceleration (a_c) at point A:
a_c = 3mg
Since the surface is frictionless, the only force acting on the block at point A is the gravitational force, which can be written as:
Fg = mg
Now, let's consider point B, which is at the top of the circle. The net force (Fnet) acting on the block at point B is the sum of the gravitational force (Fg) and the normal force (Fn):
Fnet = Fn - Fg
Since Fnet at point B is also the centripetal force, we have:
Fn - Fg = m * ac
Now, we can substitute the expressions for Fg and ac that we found earlier:
Fn - mg = m * 3mg
Now, we can solve for the normal force Fn:
Fn = mg + 3mg = 4mg
So the magnitude of the normal force on the block at point B is 4mg, which corresponds to option (a).

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Analyze system dynamics and design compensator to achieve desired response by selecting compensator zero and canceling one pole of GHP(z).

To select a compensator zero to cancel one pole of GHP(z), we need to use the given angle condition:

Zzero - (pole(1) + Zpole(B)) = 180°

Here, Zzero represents the compensator zero, pole(1) represents the first pole of GHP(z), and Zpole(B) represents the compensator pole.

Let's proceed with the solution step by step:

1. First, we need to determine the value of Zzero. The angle condition states that Zzero = Zpole(1), which means the compensator zero is equal to the first pole of GHP(z).

2. Now, we need to find the value of Zpole(B). We can rewrite the angle condition as follows:

Zpole(B) = Zzero - pole(1) + 180°

Since we already know that Zzero = Zpole(1), we can substitute Zzero in the above equation:

Zpole(B) = Zpole(1) - pole(1) + 180°

Simplifying further:

Zpole(B) = 180°

Therefore, the value of Zpole(B) is 180°.

To summarize, we can select the compensator zero (Zzero) to cancel one pole of GHP(z) as Zpole(1), and the compensator pole (Zpole(B)) is determined to be 180° based on the given angle condition.

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Explanation:

Nonmetals tend to gain electrons and become anions. For example, in Fig. 2.22 A, a neutral oxygen atom (O), with eight protons and eight electrons, gains two electrons. This gives it two more negative charges than positive charges and an overall charge of 2–.

Answer:Im doing that same quiz rn and i just put A

Explanation:

this is because EM energy is produced when electrically charged participles vibrate generating an electric filed and a magnetic field which sends out an EM wave.

i hope this helped

The power dissipated in a 141-Ω resistor with a current of 0.40 A can be calculated using the formula P = I^2 * R. The power is equal to 0.064 W.

To calculate the power dissipated in a resistor, we can use the formula P = I^2 * R, where P is the power, I is the current, and R is the resistance.

Given that the current passing through the resistor is 0.40 A and the resistance is 141 Ω, we can substitute these values into the formula:

P = (0.40 A)^2 * 141 Ω

P = 0.16 A^2 * 141 Ω

P = 0.064 W

Therefore, the power dissipated in the resistor is 0.064 W.

This calculation is based on the relationship between current, resistance, and power in an electrical circuit. The power dissipated in a resistor is directly proportional to the square of the current and the resistance.

In this case, the given values of current and resistance allow us to determine the power dissipated in the resistor as 0.064 W.

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Answer:

There are \(9.537\times 10^{-23}\) kilograms of radioactive material after 300 seconds.

Explanation:

From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:

\(\frac{dm}{dt} = -\lambda\cdot m\) (1)

Where:

\(\frac{dm}{dt}\) - Rate of change of the mass of the radioactive material, measured in kilograms per second.

\(m\) - Current mass of the radioactive material, measured in kilograms.

\(\lambda\) - Decay constant, measured in \(\frac{1}{s}\).

The solution of the differential equation is:

\(m(t) = m_{o}\cdot e^{-\lambda\cdot t}\) (2)

Where:

\(m_{o}\) - Initial mass of the radioactive material, measured in kilograms.

\(t\) - Time, measured in seconds.

If we know that \(m_{o} = 20\,kg\), \(\lambda = 0.179\,\frac{1}{s}\) and \(t = 300\,s\), then the initial mass of the radioactive material is:

\(m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}\)

\(m(t) \approx 9.537\times 10^{-23}\,kg\)

There are \(9.537\times 10^{-23}\) kilograms of radioactive material after 300 seconds.

The amplitude of the motion is 0.608.The amplitude of a particle is its maximum departure from its equilibrium position or mean position, and its direction is always in the opposite direction.

The amplitude of a particle is its maximum departure from its equilibrium position or mean position, and its direction is always in the opposite direction. Its dimensions are [L1M0 T0] and its S.I. unit is the meter.

It alludes to the greatest departure from equilibrium that an object in periodic motion can exhibit. As an illustration, consider how a pendulum moves through its equilibrium point (straight down) and then moves outward to its maximum distance.

The motion's angular frequency is

W=2\(\pi\)/T

  =2\(\pi\)/0.95

  =6.61

w=√k/m on a spring for a mass. Rearranging this formula results in

                                    k=wm²=0.165×6.61×6.61=7.209 N/m

A system performing simple harmonic motion has a total energy of

   E=a²k÷2 .Rearranging this formula results in

a=√2E÷k=√2×3.1÷7.209

   =0.608 m

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Answer:

qeyygrydfguygffsddtggfxccfufdrfff

Answer:

Physics is the natural science that studies matter its fundamental constituents, its motion and behavior through space and time, and the related entities of energy and force

Explanation:

Answer:

c: will expand and demonstrate the Charles's law

Answer:

\(\boxed {\tt 3.63636364 \ m/s}\)

Explanation:

Velocity can be found using the following formula:

\(v=\frac{p}{m}\)

where p is the momentum and m is the mass.

The woman has a mass of 55 kilograms and a momentum of 200 kilogram meters per second.

\(p= 200 \ kgm/s\\m=55 \ kg\)

Substitute the values into the formula.

\(v=\frac{200 \ kg m/s}{55 \ kg}\)

Divide. Note that the kilograms, or kg, will cancel each other out.

\(v=\frac{200 \ m/s}{55}\)

\(v= 3.63636364 \ m/s\)

The woman's velocity is 3.63636364 meters per second.

The expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by E = Y * e * ln(L) * A

The work done to stretch the wire can be calculated by integrating the force applied over the displacement. In this case, the force applied is the tension (T) in the wire, and the displacement is the change in length (ΔL) from the original length (L) to the stretched length (L + ΔL).

The tension in the wire is given by Hooke's law, which states that the tension is proportional to the extension of the wire:

T = Y * (ΔL / L)

where Y is the Young's modulus of the material of the wire.

Now, let's calculate the work done to stretch the wire:

dW = T * dL

Integrating this expression from L to L + ΔL:

W = ∫ T * dL = ∫ Y * (ΔL / L) * dL

W = Y * ΔL * ∫ (dL / L)

W = Y * ΔL * ln(L) + C

Here, C is the constant of integration. Since the energy stored in the wire is zero when it is unstretched (ΔL = 0), we can set C = 0.

Finally, the expression for the energy stored in the wire (E) is:

E = W = Y * ΔL * ln(L)

or, if we substitute the cross-sectional area (A) and strain (e) of the wire, where e = ΔL / L:

E = Y * e * ln(L) * A

Thus, the expression for the energy stored (E) in a stretched wire of original length (L), cross-sectional area (A), tension (T), and Young's modulus (Y) is given by:

E = Y * e * ln(L) * A

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Answer:

If the starting GPE is doubled than it's KE would also double.