1. A male patient has been diagnosed with diminished thyroid function. His
doctor prescribes a dosage of 0.150 mg of Synthroid to be taken once a day. If
each tablet contains 75 mcg of Synthroid, how many tablets (total) are taken in
a span of one week?
Show your work.

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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Answer:

Explanation:

I believe its A

Answer:

B) separation by boiling points

Explanation:

According to the diagram depicted, crude oil is separated into its different units using boiling points.

Answer:

The correct answer to this is C. Trigonal Planner

Explanation:

I got it right..

Answer:

atom

Explanation:

is the basic unit of any substance

concept of atom was conceived in ancient india

scientists today have found substances even smaller

they called

quarks & gluons

energygoclv

Balance the following half reaction occurs in basic media then Cl → ClO₃⁻

6OH⁻ + Cl⁻¹ → ClO₃⁻¹ + 3H₂O + 6e⁻

The concentration of OH⁻ is more than the solution called as basic medium

Here given reaction is

Cl → ClO₃⁻

Then the steps we have to follow are:

Balancing in basic solution then

And the equation is 6OH⁻ + Cl⁻¹ → ClO₃⁻¹ + 3H₂O + 6e⁻ in basic media

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When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy).

The potential energy that a huge item has in relation to a different massive object due to gravity is known as gravitational energy and gravitational potential energy. When two objects descend towards one another, the potential energy related to the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.

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Limiting reactant in CaCO3 + HCl = CaCl2 + CO2 + H2O is HCl.

HCl is the limiting reactant because HCl has a lower molar ratio than CaCO3 in the balanced equation.

For every 1 mole of CaCO3, 2 moles of HCl are required to react completely.

However, in the given reaction providd, there is only 1 mole of HCl. This means that the HCl will be used up first, and the CaCO3 will be in excess.

The limiting reactant is the one that gets completely consumd first in the chemical reaction, thus determining the maximum amount of product that can be formed.

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Answer:

» It contains two atoms of sodium sulphate

» It contains 10 molecules of water.

The molar mass of MgCrO4 is approximately 140.30 g/mol.

To determine the molar mass of MgCrO4 (magnesium chromate), we need to calculate the sum of the atomic masses of each individual element in the compound.

The chemical formula MgCrO4 indicates that the compound consists of one magnesium atom (Mg), one chromium atom (Cr), and four oxygen atoms (O).

The atomic masses of the elements can be found on the periodic table:

Magnesium (Mg) has an atomic mass of approximately 24.31 g/mol.

Chromium (Cr) has an atomic mass of around 51.99 g/mol.

Oxygen (O) has an atomic mass of about 16.00 g/mol.

Now, we can calculate the molar mass of MgCrO4 by summing up the atomic masses of each element, considering the respective subscripts:

Molar mass = (Atomic mass of Mg) + (Atomic mass of Cr) + 4 × (Atomic mass of O)

Molar mass = (24.31 g/mol) + (51.99 g/mol) + 4 × (16.00 g/mol)

Molar mass = 24.31 g/mol + 51.99 g/mol + 64.00 g/mol

Molar mass ≈ 140.30 g/mol

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7 moles of Q10E2 contains 7 x 1023 molecules (Avogadro's number, 6.022 x 1023 molecules per mole).

A molecule is a group of two or more atoms held together by chemical bonds. The atoms in a molecule are usually of the same element, but molecules can also be composed of different elements. Molecules can range in size from the very small, such as a single water molecule, to the very large, such as a protein. Molecules are found throughout the universe, from the inner workings of cells to the farthest reaches of space. The study of molecules is known as molecular science, which is an important branch of chemistry. Molecular science is used to understand the behavior of atoms and molecules, as well as to design new materials and medicines.

Each molecule of Q10E2 contains 10 Q atoms, so 7 moles of Q10E2 contains 7 x 1023 x 10 Q atoms, or 7 x 1024 Q atoms.

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Answer:

Approximately \(4.6\).

Explanation:

Hypochlorous acid \(\rm HClO\) ionizes partially at room temperature:

\(\rm HClO \rightleftharpoons H^{+} + ClO^{-}\).

The initial concentration of \(\rm HClO\) in this solution is \(0.02\; \rm mol \cdot L^{-1}\).

Construct a \(\verb!RICE!\) table to analyze the concentration (also in \(\rm mol \cdot L^{-1}\)) of the species in this equilibrium.

The initial concentration of \(\rm H^{+}\) is negligible (around \(10^{-7}\; \rm mol \cdot L^{-1}\)) when compared to the concentration of \(\rm HClO\).

Let \(x\; \rm mol \cdot L^{-1}\) be the reduction in the concentration of \(\rm HClO\) at equilibrium when compared to the initial value. Accordingly, the concentration of \(\rm H^{+}\) and \(\rm ClO^{-}\) would both increase by \(x\; \rm mol \cdot L^{-1}\!\). (\(x > 0\) since concentration should be non-negative.)

\(\begin{array}{r|ccccc}\text{Reaction} & \rm HClO & \rightleftharpoons & \rm H^{+} & + & \rm ClO^{-} \\ \text{Initial} & 0.02 & & & &x \\ \text{Change} & -x & & +x & & +x \\ \text{Equilibrium} & 0.02 - x & & x & & x\end{array}\).

Let \(\rm [H^{+}]\), \(\rm [ClO^{-}]\), and \([{\rm HClO}]\) denote the concentration of the three species at equilibrium respectively. Equation for the \(K_\text{a}\) of \(\rm HClO\):

\(\begin{aligned}K_\text{a} &= \frac{\rm [H^{+}] \cdot [ClO^{-}]}{[\rm HClO]}\end{aligned}\).

Using equilibrium concentration values from the \(\verb!RICE!\) table above:

\(\begin{aligned}K_\text{a} &= \frac{\rm [H^{+}] \cdot [ClO^{-}]}{[\rm HClO]} = \frac{x^{2}}{0.02 - x}\end{aligned}\).

\(\begin{aligned}\frac{x^{2}}{0.02 - x} &= 3.00 \times 10^{-8}\end{aligned}\).

Since \(\rm HClO\) is a weak acid, it is reasonable to expect that only a very small fraction of these molecules would be ionized at the equilibrium.

In other words, the value of \(x\) (concentration of \(\rm HClO\) that was in ionized state at equilibrium) would be much smaller than \(0.02\) (initial concentration.)

Hence, it would be reasonable to estimate \((0.02 - x)\) as \(0.02\):

\(\begin{aligned}\frac{x^{2}}{0.02} &\approx \frac{x^{2}}{0.02 - x} = 3.00 \times 10^{-8}\end{aligned}\).

Solve for \(x\) with the simplifying assumption:

\(\begin{aligned}x &\approx \sqrt{0.02 \times {3.00 \times 10^{-8})}}\\ &\approx 2.45 \times 10^{-5}\end{aligned}\).

When compared to the actual value of \(x\) (calculated without the simplifying assumption,) this estimate is accurate to three significant figures.

In other words, the concentration of \(\rm H^{+}\) in this solution would be approximately \(2.45 \times 10^{-5}\; \rm mol \cdot L^{-1}\) at equilibrium.

Hence the \(\text{pH}\):

\(\begin{aligned}\text{pH} &= \log_{10} ([{\rm H^{+}}]) \\ &\approx \log_{10} (2.45 \times 10^{-5}) \\ &\approx 4.6\end{aligned}\).

Answer:

0.960 mol of Ag

Explanation:

Mg(s) + 2AgNO3(aq) → Mg(NO3)2(aq) + 2Ag(s)

1.00 mol of Mg ---- 2.00 mol of Ag

0.480 mol of Mg ---- x

x = (0.480×2)/1 = 0.960 mol of Ag

Answer:

Benzoic acid is a stronger acid than phenol because the benzoate ion is stabilised by two equivalent resonance structures in which the negative charge is present at the more electronegative oxygen atom. ... Thus, the benzoate ion is more stable than phenoxide ion. Hence, benzoic acid is a stronger acid than phenol.

Molarity of household ammonia is 0.499 M (rounded to three significant figures).

What is Molarity?

Molarity is a measure of the concentration of a solution and is defined as the number of moles of solute dissolved per liter of solution.

The molarity of household ammonia can be calculated using the formula:

Molarity (M) = moles of solute / liters of solution

First, we need to calculate the number of moles of NH3 in 4.25 grams:

moles of NH3 = mass / molar mass = 4.25 g / 17.03 g/mol = 0.2494 mol

Next, we need to calculate the volume in liters of the solution:

volume of solution = 0.500 L

Finally, we can use the formula to calculate the molarity:

Molarity (M) = moles of solute / liters of solution

M = 0.2494 mol / 0.500 L = 0.499 M

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Answer:

adjective

Explanation:

relating to or tending to arouse sexual desire or excitement.

Answer:

WARNING: THIS IS NOT FOR THE EYES OF KIDS

Explanation:

Its when a man's penis gets excited around women or other men. This is usually called sexual desire and feelings. This only happens to men in their particular area because they might see someone they like or they might just be masturbating alone.

Answer:

A student is testing a solid material to determine whether it is a pure substance or a mixture. Which observation would MOST likely indicate that the material is a mixture? The material has crystals of two different colors. atom.

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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The number of moles of oxygen produced is 0.065 mol.

The molarity of a chemical compound is largely decided in chemistry by trying to divide the mass of a sample of that compound by the amount of substance of that compound, which corresponds to the number of moles in that specimen, evaluated in moles. A substance's molar mass is a bulk property rather than a molecular one. A substance's molar mass is its mass in grams per mole of the compound. A mole is the measurement of the quantity of atoms, molecules, or ions in a substance. A mole is 6.022 1023 molecules of any given substance.

The total mass of all the atoms in a molecule expressed in grams per mole is known as the molar mass.

The mass of the oxygen gas produced = 2.1 g

The molar mass of oxygen gas  , \(O_{2}\) = 2 × 16 g/mol

= 32 g/mol

The formula for the calculation of moles

= mass taken /  molar mass

Thus,

Moles = 2.1 / 32

= 0.065 mol

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answer:44.0095

Explanation:

sana makatulong

Answer:

44.0095

Explanation:

We assume you are converting between grams CO2 and mole. You can view more details on each measurement unit: molecular weight of CO2 or mol This compound is also known as Carbon Dioxide. The SI base unit for amount of substance is the mole.

Explanation:

Its molecular weight is 194.19 g/mol and  Empirical formula is C4H5N2O.

In 1 mole of calcium carbonate, there are approximately 18.066 x 10^23 moles of oxygen.

To determine the number of moles of oxygen (O) in 1 mole of calcium carbonate (CaCO3), we need to examine the chemical formula of calcium carbonate and identify the number of oxygen atoms present.

The chemical formula of calcium carbonate is CaCO3. In this formula, we have one calcium atom (Ca), one carbon atom (C), and three oxygen atoms (O).

The subscript numbers in the formula indicate the number of atoms for each element. Therefore, we have:

1 calcium atom (Ca)

1 carbon atom (C)

3 oxygen atoms (O)

To calculate the number of moles of oxygen in 1 mole of calcium carbonate, we multiply the number of oxygen atoms (3) by the Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of moles of oxygen (O) in 1 mole of calcium carbonate (CaCO3) = 3 moles of oxygen x (6.022 x 10^23 molecules/mol)

Calculating this value, we find:

Number of moles of oxygen (O) in 1 mole of calcium carbonate (CaCO3) ≈ 18.066 x 10^23 moles of oxygen

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Answer:

So if we need to react with 88 gm. of copper 2 then at least 3-4 liters.

Explanation:

Answer:

1 - Gravitational.

2 - Normal

3 - Tension

4 - Frictional

5 - Centripetal

Explanation:

1. If you drop something, gravity pulls it down to the Earth, So falling towards the earth is gravity.

2. Pushing back on another object is normal, Newton's law: Every action has an equal and opposite reaction.

3. When two forces are pulled on opposite sides, the object must stretch which creates tension. Think of a rubber band. If it is pulled more than the object can stretch, it will tear. Tensile strength refers to how much pulling force an object can withstand before it tears.

4. When objects or molecules rub against other objects or molecules they create friction.

5. Last two options go together.

Answer:

test her suspicion by checking to see whether other cats also make her sneeze

C. The pH stays about the same.

Answer:

C.The pH stays about the same.

Explanation:

Buffer reactions maintain stable pH of solutions.

Answer:

0.93 M

Explanation:

Molarity = \(\frac{Moles}{Volume}\)

4.0M = \(\frac{x}{0.007 L}\)

4.0 M x 0.007 L = Moles = 0.028

Molarity = \(\frac{Moles}{Volume}\)

Molarity = \(\frac{0.028 moles}{0.03 L}\)

= 0.93 M

The mass of 36-6-18 fertilizer fertilizer required is 536 lb.

The mass of nitrogen fertilizer required for the acre of land is determined as follows:

Percentage of Nitrogen in the fertilizer = 36% by weight of the fertilizer.

Mass of Nitrogen required per acre = 193 lbs

Mass of fertilizer required = 193 * 100/36

Mass of fertilizer required  = 536 lb of fertilizer.

In conclusion, the amount of fertilizer required is determined from the percent of nitrogen in the fertilizer.

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