1. A compressor is running too first response is to A. Run it shower B. Raise the ambient temperature C. Add a lubricant D. Check the coolant 2. Which one of the following pipe fitting would
Answers
If a compressor is running too fast, the first response is to check the coolant.
This is because an inadequate amount of coolant may cause the compressor to run too fast and result in a burnout.
The other options are incorrect as running it slower, raising the ambient temperature, and adding a lubricant are not suitable solutions to the problem.
The following pipe fitting would have a cylindrical center section:
Elbow fittings.
Elbow fittings are pipe fittings that are used to join two pipes at an angle.
These fittings are used when a pipeline must be altered direction and allow for a smooth, long-lasting joint between pipes.
Elbow fittings come in a variety of styles and materials to suit a wide range of applications.
The shape of the center section of an elbow fitting is cylindrical, and the diameter is the same as that of the pipes being connected.
Thus, it can be concluded that Elbow fittings are the type of pipe fitting with a cylindrical center section.
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Related Questions
Which sentence from the passage uses passive voice?
Question 9 options:
a)
E-books also make reading easier for people with disabilities. (paragraph 12)
b)
M.K. sees it another way. (paragraph 16)
c)
In one year, e-reader production released 2350 million kilograms of carbon dioxide into the atmosphere. (paragraph 8)
d)
The Diamond Sutra was printed in China in 868 AD. (p
Answers
Answer:
"The Diamond Sutra was printed in China in 868 AD." (paragraph 4)
Explanation:
I took the test
Who is responsible for providing working conditions which are free from fall dangers?
Answers
Answer:
I am pretty confident it is the Employer!
Explanation:
They have the responsibility to provide a safe workplace that is free from serious hazards, according to the General Duty Clause of the OSH Act (OSHA Standards)
I hope this helped you!! :D
Answer:
Employers
Explanation:
OSHA requires employers to: Provide working conditions that are free of known dangers. Keep floors in work areas in a clean and, so far as possible, a dry condition. Select and provide required personal protective equipment at no cost to workers.
Technician A says that unibody vehicles are generally lighter and more fuel efficient than body-over-frame vehicles.Technician B says that full-size trucks always use body-over-frame construction.Who is correct?
Answers
Answer:
Both technicians are right.
Explanation:
Unibody vehicles have their body, floor plan, and chassis formed into a single structure. These vehicles are generally lighter and more rigid than body-over-frame vehicles. The fact that they are lighter than body-over-frame vehicles means that they have lesser weight to power ratio, which means compared to a body-over-frame vehicle, they will use a lesser amount of fuel to move through the same distance than the body-over-frame would use. This makes unibody vehicles more fuel efficient. Body-over-frame types of vehicles are made up of a separate body, mounted on a relatively rigid vehicle frame or chassis that carries the powertrain (the engine and drivetrain). This was the original method of building automobiles, is now used mainly for pickup trucks and SUVs.
how to attach swiffer wet jet pads
Answers
Answer:
Explanation:
To attach a Swiffer Wet Jet pad, you first need to make sure the device is turned off and the battery is removed. Then, locate the cleaning pad attachment on the bottom of the unit and push it forward until it clicks into place.
Next, take your Swiffer Wet Jet pad and align the edges with the Velcro strips on the cleaning pad attachment. Press down firmly on the pad until it is securely attached.
Once the pad is attached, you can turn the device back on and begin cleaning. Remember to replace the pad after each use or when it becomes too dirty to effectively clean your floors.
I hope that helps!
Which of the following is static characteristics of measurement?
Answers
Unwanted static traits in measurement systems include drift, static inaccuracy, dead zone, and non-linearity.
Which one of the following does not describe a measurement system's static characteristics?
Explanation:Sincerity is not a fixed quality.It is an element of an instrument's dynamic.In terms of measurements, fidelity relates to how accurate a number is when compared to a quantity that hasn't experienced any dynamic mistakes.
What qualities does measuring have?It offers a definition for each of the five key attributes of a measuring device: scale length, sensitivity, accuracy, "finesse," and response time.
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definition of ceramics
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Answer:
Ceramics are generally made by taking mixtures of clay, earthen elements, powders, and water and shaping them into desired forms. Once the ceramic has been shaped, it is fired in a high temperature oven known as a kiln. Often, ceramics are covered in decorative, waterproof, paint-like substances known as glazes.
Explanation:
Answer:
made essentially from a nonmetallic mineral (such as clay) by firing at a high temperature.
Explanation:
A horizontal poly crystalline solar panel module has to be investigated by natural cooling. For crystal silicon, the thermal coefficient approximately 0.0045/K is used. Investigate the effect of air velocity on the cooling performance of PV panels at 0-5 m/s air velocities, 25-40 ºC ambient temperatures, and 400-1000 W/ m2 solar radiation
Answers
Solution :
It is given that :
Thermal coefficient = 0.0045/K
Ambient temperature, \($T_a = 25 - 40^\circ$\)
air velocity, v = 0-5 m/s
Solar radiation, \($G= 400-100 \ W/m^2$\)
\($P=50 \ W$\)
Model calculations :
Cell temperature (\($T_c$\))
\($T_c = T_a + \left(\frac{0.25}{5.7+3.8 \ v_w}\right) G$\)
where \($ v_w - v_a = $\) wind speed / air speed
∴ \($T_c = 2 \pi + \left(\frac{0.25}{5.7+3.8 \times 1}\right) \times 400$\)
\($T_c = 35.526 ^\circ$\)
\($\Delta T = T_c -25$\)
= 35.526 - 25
= 10.526 K
Thermal coefficient = 0.0045 x 10.526
= 0.04737
Pv power = \($(1 -C_T) \times P \times \frac{G}{1000}$\)
\($=(1 -0.04737) \times 50 \times \frac{400}{1000}$\)
= 17.0526 W
help please thank you
Answers
The system is operated at a feed rate of 15 × 10^(-3) m^3/h with an initial glucose concentration of 10 kg/m^3.
How to explain the informationThe steady-state mass balance for the reactor can be written as:
F = QX + Qs
where F is the feed rate, QX is the volumetric flow rate of cells, and Qs is the volumetric flow rate of glucose.
At steady-state, QX and Qs are constant. Therefore, we can write:
QX = F - Qs
In this case, the system is operated at a feed rate of 15 × 10^(-3) m^3/h with an initial glucose concentration of 10 kg/m^3.
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Your new boss wants to know if they are compliant with the latest (2017) OWASP Top 10. Which of the following IS NOT one of the 2017 Top 10 Top Application Security Risks.?a) Cross Site Request Forgery b)Cross Site Scripting c)Injection d)Broken Authentication
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After gaining access to the user's account, the attacker can steal any sensitive information they desire or perform any action that the user is authorized to perform.
In 2017, the Open Web Application Security Project (OWASP) created a list of the Top 10 Application Security Risks. The list is as follows:
InjectionBroken Authentication and Session ManagementSensitive Data ExposureXML External Entities (XXE)Broken Access ControlSecurity MisconfigurationCross-Site Scripting (XSS)Insecure DeserializationUsing Components with Known VulnerabilitiesInsufficient Logging and MonitoringNow, the given alternatives include:
a) Cross Site Request Forgery
b) Cross Site Scripting
c) Injectiond)
Broken AuthenticationFrom the above alternatives, we can say that all of the options are part of OWASP Top 10, except Cross Site Request Forgery.
Therefore, the correct answer is (a) Cross Site Request Forgery.
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In example 21. 17 in the textbook, if the dielectric constant of the slab that is slid between the plates of the capacitor had been 5 rather than 3. 3, what would have been the final voltage across the capacitor?.
Answers
Example 21.17 shows that a 3.3 μF capacitor is charged to 300 V and is then connected to a 5.6 μF capacitor through a switch S. The charge sharing between the two capacitors and the final voltage are to be determined.The original voltage across the 3.3 μF capacitor isQ = CV = (3.3 × 10-6 F)(300 V) = 0.99 mCWhen S is closed, the charge on each capacitor will be equal and given byQ = CV1 = CV2where V1 and V2 are the voltages across the 3.3 μF and 5.6 μF capacitors, respectively.
The equivalent capacitance of the two capacitors in series is
Ceq = (C1C2)/(C1 + C2)
= (3.3 × 10-6 F)(5.6 × 10-6 F)/(3.3 × 10-6 F + 5.6 × 10-6 F)
= 2.105 × 10-6 F
The final voltage across the capacitors is then
V = Q/Ceq
= (0.99 mC)/(2.105 × 10-6 F)
= 471.54 V
If the dielectric constant of the slab that is slid between the plates of the capacitor had been 5 rather than 3.3, the capacitance of the 3.3 μF capacitor would have increased by a factor ofκ = 5/3.3 = 1.5151
The original capacitance isC1 = 3.3 μFThe new capacitance is
C1' = κC1
= (1.5151)(3.3 × 10-6 F)
= 4.9983 μF
The equivalent capacitance of the two capacitors in series is
Ceq' = (C1'C2)/(C1' + C2)
= (4.9983 × 10-6 F)(5.6 × 10-6 F)/(4.9983 × 10-6 F + 5.6 × 10-6 F)
= 2.4289 × 10-6 F
The final voltage across the capacitors is then
V' = Q/Ceq'
= (0.99 mC)/(2.4289 × 10-6 F)
= 407.73 V
Therefore, if the dielectric constant of the slab that is slid between the plates of the capacitor had been 5 rather than 3.3, the final voltage across the capacitor would have been 407.73 V instead of 471.54 V.
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is sampled at a rate of to produce the sampled vector and then quantized. Assume, as usual, the minimum voltage of the dynamic range is represented by all zeros and the maximum value with all ones. The numbers should increase in binary order from bottom to top. Find the bit combination used to store each sample when rounded to the nearest integer between and (clipping may occur). Note: A partially-correct answer will not be recognized. You must answer all three correctly on the same
Answers
Answer:
d[0] = 11111111
d[1] = 11011101
d[2] = 1111011
Explanation:
Assume that the number of bits is 8. The voltage range input is -8 to 7 volts. The range is thus 15V, and the resolution is 15/2^8 = 0.0586 volts. We will first add +8 to the input to convert it to a 0-15v signal. Then find the equivalent bit representation. For 7.8 volts, the binary signal will be all 1's, since the max input voltage for the ADC is 7 volts. For 4.95, we have 4.95+8 = 12.95 volts. Thus, N = 12.95/0.0586 = 221. The binary representation is 11011101. For -0.8, we have -0.8 + 8 = 7.2. Thus, N = 7.2/0.0586 = 123. The binary representation is 1111011.
Thus,
d[0] = 11111111
d[1] = 11011101
d[2] = 1111011
Give all the steps necessary to obtain 100 mL of a 1.9 X 10 -5 M solution using serial dilution. The required laboratory equipment and compound information are given:0.15 grams of a compound with a molar mass of 793 g/mol, deionized water, 1.0 mL pipette, 5.0 mL pipette, 10.0 mL pipette and two - 100.0 mL volumetric flasks
Answers
Answer:
Take 10.0mL of stock solution using 10.0mL pipette in a 100mL volumetric flask and make up the solution with deionized water up to the mark of the flask and we get 100mL of 1.9×10⁻⁵M solution.
Explanation:
Molarity of stock solution, \(M = \frac{mass}{Molar mass} * \frac{1}{Volume (L)}\)
\(M = \frac{0.15g}{793mol^{-1}} * \frac{1}{1.0L} = 1.9*10^{-4}M\)
According to law of dilution MV = m'v'
Where, M = Molarity of stock solution = 1.9×10⁻⁴M
V = Volume of stock solution = ?
m' = Molarity of dilute solution = 1.9×10⁻⁵M
v' = Volume of dilute solution = 100 mL
Substituting the above parameters in the equation of dilution
\(V = \frac{m'v'}{M}\)
\(V = 10.0 mL\)
Why do drivers always yield to emergency vehicles with lights and sirens
Answers
Answer:
So The emergency vehicle can pass so they can get to where they need to go
Explanation:
What flow type occurs when the heat exchanger has multiple passes and baffles?
Cross flow
Laminar flow
Parallel flow
Hybrid flow
Answers
Can space debris take out a whole state
Answers
Scientists were surprised by which thing found in Ötzi the Iceman's stomach, and why?
Answers
Answer:
Scientists were surprised to find that Ötzi the Iceman's stomach contained remnants of red deer meat, as it had been previously assumed that his diet consisted primarily of plants. This finding provided new insights into the dietary habits of Copper Age Europeans and challenged previous assumptions about their reliance on agriculture. Additionally, the presence of the red deer meat in Ötzi's stomach suggested that he had eaten a last meal that was high in fat and protein, which may have provided him with the energy needed for his fateful journey through the Alps.
Answer:
Ötzi the Iceman was a well-preserved mummy found in the Italian Alps in 1991. One of the most interesting things about his remains was the discovery of his last meal. Analysis of his stomach contents showed that he had recently eaten a meal of ibex meat, a type of wild goat that lived in the region, and a type of ancient bread made from einkorn wheat. What surprised scientists was the presence of the ibex's stomach contents in Ötzi's stomach. They discovered that Ötzi had eaten the ibex meat raw, with no signs of cooking. This was surprising because it was previously believed that prehistoric humans only ate meat that had been cooked over fire. The discovery of the raw meat in Ötzi's stomach suggested that prehistoric humans may have eaten raw meat more often than previously thought and that cooking food may not have been as prevalent in ancient societies as previously believed.
A route for a proposed 8-m-wide highway crosses a region with a 4-m-thick saturated, soft, normally consolidated clay (CH) above impermeable rock. Groundwater level is 1 m below the surface. The geotechnical data available during the preliminary design stage consist of Atterberg limits (LL 5 68% and PL 5 32%) and the natural water content (w 5 56%). Based on experience, the geotechnical engineer estimated the coefficient of consolidation at 8 m2 per year. To limit settlement, a 4-m-high embankment will be constructed as a surcharge from fill of unit weight 16 kN/m3.
(a) Estimate the compression and recompression indices.
(b) Estimate the total primary consolidation settlement under the center of the embankment.
(c) Plot a time–settlement curve under the center of the embankment.
(d) How many years will it take for 50% consolidation to occur?
(e) Explain how you would speed up the consolidation.
(f) Estimate the rebound (heave) when the surcharge is removed.
Sketch a settlement profile along the base of the embankment. Would the settlement be uniform along the base? Explain your answer.A route for a proposed 8-m-wide highway crosses a
Answers
Avapor mixture containing 50.0 mole % benzene and 50.0 mole % toluene at 1 atm is cooled isobarically in a closed container from an initial temperature of 115°C. Use the Tsy diagram below to answer the following questions. 115 110 1400 1300 105 100 Vapor 1200 95 Temperature (°C) 90 Liquid 1100 1000 900 Pressure (mm Hg) Liquid 85 800 Vapor 80 700 75 70 600 500 0 1.0 65 0 10 0.2 0.4 0.6 0.8 Mole fraction henvene Polarm 0.2 0.4 0.6 0.8 Mole fraction benzene 7100 First Condensation Your answer is partially correct. At what temperature does the first drop of condensate form? 104 °C What is its composition? 0.20 mol benzene/mol
Last Condensate Your answer is partially correct. At what temperature does the last bubble of vapor condense? °C 98 What is its composition? 0.53 mol benzene/mol
Answers
Answer:
105°touch sensce what I could wathskb
In the following load-tracing problem, construct a series of FBDs and show the propagation of loads
through the various structural elements.
Determine the column loads (A1, A3, B2, C2, D1, and D3)
Assuming:
DL (decking, flooring, etc) = 10 psf
LL (occupancy) = 40 psf
Beam B-2 spans between girder G-3 and column B-2
Beam B-3 spans between girder G-3 and column C-2
Answers
Using the equations of statics, we can solve for the reaction forces and column loads. The final results are:
RD3 = 5150 lb
R = 6950 lb
RC2 = 8400 lb
VL = 1800 lb
Define reaction force.
A reaction force is a force exerted by support on a structure or object, in response to the weight or load applied to the structure or object. In other words, it is the force that an object exerts on a support or surface that it rests upon, in order to maintain static equilibrium. Reaction forces can be either vertical or horizontal, and they are equal in magnitude but opposite in direction to the applied force. These forces are essential to keep structures stable and in balance.
Here is the solution to the load-tracing problem:
1. Free-body diagram (FBD) for column D3:
Vertical load: 40 psf
Reaction force: RD3
2. FBD for girder G3:
Vertical load: 10 psf (dead load from beam B2) + 40 psf (live load from beam B2) + 10 psf (dead load from beam B3) + 40 psf (live load from beam B3) = 1800 lb
Horizontal load: 0 lb
Reaction force: R
3. FBD for column C2:
Vertical load: 10 psf (dead load from beam B3) + 40 psf (live load from beam B3) + 10 psf (dead load from girder G3) + 40 psf (live load from girder G3) = 3150 lb
Reaction force: RC2
4. FBD for beam B3:
Vertical load: 10 psf (dead load from beam B3) + 40 psf (live load from beam B3) = 500 lb
Horizontal load: 0 lb
Shear force: VL (vertical load from girder G3)
Moment: VL * L/2 (where L is the span of beam B3)
5. FBD for girder G2:
Vertical load: 10 psf (dead load from column B2) + 40 psf (live load from column B2) = 500 lb
Reaction force: RG2
6. FBD for column B2:
Vertical load: 10 psf (dead load from beam B2) + 40 psf (live load from beam B2) + 500 lb (vertical load from girder G2) = 2100 lb
Reaction force: RB2
7. FBD for beam B2:
Vertical load: 10 psf (dead load from beam B2) + 40 psf (live load from beam B2) = 500 lb
Horizontal load: 0 lb
Shear force: VR (vertical load from girder G3) + RB2 (vertical load from column B2)
Moment: VR * L/2 + RB2 * L/2 (where L is the span of beam B2)
8. FBD for girder G1:
Vertical load: 10 psf (dead load from column A1) + 40 psf (live load from column A1) = 500 lb
Reaction force: RG1
9. FBD for column A1:
Vertical load: 10 psf (dead load from beam A1) + 40 psf (live load from beam A1) + 500 lb (vertical load from girder G1) = 2100 lb
Reaction force: RA1
10. FBD for beam A1:
Vertical load: 10 psf (dead load from beam A1) + 40 psf (live load from beam A1) = 500 lb
Horizontal load: 0 lb
Shear force: RA1 (vertical load from column A1)
Moment: RA1 * L/2 (where L is the span of beam A1)
We can solve for the reaction forces and column loads. The final results are:
RD3 = 5150 lb
R = 6950 lb
RC2 = 8400 lb
VL = 1800 lb
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what is the role of product design?
Answers
Answer:
Product designers are in charge of the entire product creation process. They are ultimately responsible for discovering and defining a problem, and then empathically designing a solution. The skills that a product designer must have range from technical to human-centered design.
Explanation:
For proper function hydraulics systems need a reservoir of which of the following?
A.) Compressible fluid
B.) Non-compressible fluid C.) Non-compressible air
Answers
Think of brake fluid on a vehicle, compressed as one applies the break= pressure to expand brake cylinders in the wheels which compress the pads on the wheel brake rotors.
Release brake and fluid relaxes back into the reservoir/accumulator.
a metal tension specimen of initial diameter 0.505 inches fractures at a load of 5,000 lb with a fracture diameter of 0.325 inches. calculate the true stress at fracture
Answers
The true stress at fracture is 59,824.28 psi. True stress at fracture can be calculated by first calculating the true strain at fracture. After calculating the true strain at fracture, calculate the true stress using the given value of force at fracture and the cross-sectional area at fracture. Given data:
Diameter of tension specimen = 0.505 inches
Initial diameter of tension specimen = 0.505 inches
Fracture diameter of tension specimen = 0.325 inches
Load at fracture = 5000 lbs
Formula for true strain calculation:
True strain at fracture = ln (initial diameter / fracture diameter)
Formula for true stress calculation:
True stress at fracture = Force at fracture / Area at fracture
Calculation of true strain:
True strain at fracture = ln (initial diameter / fracture diameter)
= ln (0.505/0.325)= 0.4458
Calculation of area at fracture:
The area of the tension specimen is given by the following formula:
Area = π (diameter)2/4
The area at fracture can be calculated using the fracture diameter.
Area at fracture = π (0.325)2/4= 0.08353 sq inches
Calculation of true stress:
True stress at fracture = Force at fracture / Area at fracture
= 5000 / 0.08353= 59,824.28 psi
Therefore, the answer is 59,824.28 psi.
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All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:
Answers
Question:
All of the following are advantages of using a pressure transducer rather than a vacuum gauge EXCEPT:
A. greater accuracy.
B. easier identification of the cylinder.
C. measuring higher pressures.
D. ability to see the levels graphically
Answer:
The correct answer is D) ability to see the levels graphically
Explanation:
The above question derives from the Rudiments of Automotive Technology.
The function of the pressure transducer is to enable the diagnostic who is testing the engine vacuum to detect the cylinder with a faulty vacuum.
The pressure transducer does allow its user to see the vacuum graphically NOT the levels.
Cheers.
Can be used to eliminate rubbing friction of wheel touching frame. 1.Traction 2.Thrust washer
Answers
Answer:
thrust washer
can be used to eliminate rubbing friction of wheel touching frame
Consider the following data for 2008 in a small suburban community:
1. number of accidents: 360 fatal 10 injury 36 pdo 314
2. number of fatalities 15
3. area population: 50,000
4. registered vehicles 35,000
5. annual vmt: 12,000,000
6. average speed 30 mi/hr
compute all relevant exposure and population based accident and fatality rates for this data. compare these to national norms for the current year. (hint: use the internet to location current national norms)
Answers
Answer:
Motorcyclist Fatality and Injury Rates per Vehicle Miles Traveled, 1998-2008. 10. 9. Fatalities in School Transportation Related Crashes,. 1998-2008.
Explanation:
When an object is made of the plastic polyester (PET), it uses antimony as a catalyst. After production, antimony can leach into food and drink stored in PET containers. Usually, if stored correctly for a short amount of time, the amount of antimony found in liquids is well below the safety limits. However, there have been reports of as much as 44.7 micrograms per liter [µg/L] of antimony found in fruit juice concentrates. How much antimony, in units of moles [mol], could be found in one gallon [gal] of fruit juice concentrate at this level of contamination? The molecular mass of antimony is 121.76 grams per mole [g/mol].
Answers
Answer:
1.39 µmol
Explanation:
(1 gal) × (44.7 µg/L)/(121.76 g/mol)(3.785411784 L/gal) = 1.39 µmol
Highway safety engineer tests newly designed road signboards with the objective to increase the reflectivity so that the signboards will be more visible to drivers. Volunteers drive through a test course with new and old design signboards and they rate which design is more visible. Hypothesis testing is conducted and P-value of the difference between rate of visibility for new and old signboard sis found to be 0.04. i) Identify the possible parameter in the study. [1 Mark] ii) Is there enough evidence that the new improved design is helping in improving visibility? [5 Marks] iii) Identify the type of error in the study. Justify your answer.
Answers
The probability of making a Type 1 error is equal to the level of significance (α).The probability of making a Type 2 error is the probability of failing to reject the null hypothesis when it is false. In other words, it is a false negative result. The probability of making a Type 2 error is denoted by β.
i) Possible parameters in the studyThe possible parameter in the study is the rate of visibility of the signboards for drivers.ii) Is there enough evidence that the new improved design is helping in improving visibility?
The p-value obtained in the hypothesis test is 0.04, which means that the null hypothesis should be rejected. Since the level of significance is not given, we can assume that it is 0.05.
Since the p-value is less than the level of significance, there is enough evidence to conclude that the new improved design is helping in improving visibility.
iii) Identify the type of error in the study.Type 1 error is an error that occurs when we reject the null hypothesis when it is true. In other words, it is a false positive result.
The probability of making a Type 1 error is equal to the level of significance (α).The probability of making a Type 2 error is the probability of failing to reject the null hypothesis when it is false. In other words, it is a false negative result. The probability of making a Type 2 error is denoted by β.
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What is a flat bottom boat called?
Answers
Punts, originally used as freight and angling boats, are shallow-water craft with a flat bottom and a square-cut bow.
A flat-bottomed hull is what?Flat-bottomed hulls are made to float on the water's surface while moving very little. Due to the absence of resistance, flat-bottomed boats can travel pretty quickly, but if the sea is rough at all, the hulls will pound into each swell, making for an extremely unpleasant ride.
Is the bottom of a bass boat flat?Bass boat and flats boats are both stable, and whose hulls are made for a shallow draft; as a result, they are typically more flat than that of the wider hulls of boats built to cruise offshore, in choppy seas.
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need urgent help!!
Determine the point(s) P on the line e with equation x−6 = ( y−3)/4 = ( 1−z)/3
for which the line connecting P with Q(2, −6, 5) is perpendicular to e.
Answers
The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.
How are quartiles determined?In order to quartile a set of data with n items (numbers), we choose the n/4th, n/2nd, and n/4th items. Interpolation between the adjacent items is used if indexes n/4, n/2, or 3n/4 are not integers.For instance, the first quartile Q1 of ordered data is the 25th item, the second quartile Q2 is the 50th item, and the third quartile Q3 is the 75th item. The fourth quartile Q4 would be the highest item of data, and the zeroth quartile Q0 would be the minimum item; however, these extreme quartiles are referred to as the minimum and maximum of a set, respectively.Calculation:Statistical file: {2, -6, 5}
Quartile Q1: -6
Quartile Q2: 2
Quartile Q3: 5.
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Determine the enthalpy, volume and density of 1.0 kg of steam at a pressure of 0.5 MN/m2 and with a dryness fraction of 0.96
Answers
Answer:
Enthalpy, hsteam = 2663.7 kJ/kg
Volume, Vsteam = 0.3598613 m^3 / kg
Density = 2.67 kg/ m^3
Explanation:
Mass of steam, m = 1 kg
Pressure of the steam, P = 0.5 MN/m^2
Dryness fraction, x = 0.96
At P = 0.5 MPa:
Tsat = 151.831°C
Vf = 0.00109255 m^3 / kg
Vg = 0.37481 m^3 / kg
hf = 640.09 kJ/kg
hg = 2748.1 kJ/kg
hfg = 2108 kJ/kg
The enthalpy can be given by the formula:
hsteam = hf + x * hfg
hsteam = 640.09 + ( 0.96 * 2108)
hsteam = 2663.7 kJ/kg
The volume of the steam can be given as:
Vsteam = Vf + x(Vg - Vf)
Vsteam = 0.00109255 + 0.96(0.37481 - 640.09)
Vsteam = 0.3598613 m^3 / kg
From the steam table, the density of the steam at a pressure of 0.5 MPa is 2.67 kg/ m^3